Please help me I’m so sad

The relational algebra operator that selects rows from a single table based on a specified condition is called the "selection" operator.

In relational algebra, the "selection" operator is used to filter rows from a single table based on a given condition or predicate. It is denoted by the Greek symbol sigma (σ). The selection operator allows us to retrieve a subset of rows that satisfy a particular condition specified in the query.

The selection operator takes a table as input and applies a condition to each row. If a row satisfies the specified condition, it is included in the output; otherwise, it is excluded. The condition can be any logical expression that evaluates to true or false. Commonly used comparison operators like equal to (=), not equal to (<>), less than (<), greater than (>), etc., can be used in the condition.

For example, consider a table called "Employees" with columns like "EmployeeID," "Name," and "Salary." To retrieve all employees with a salary greater than $50,000, we can use the selection operator as follows: σ(Salary > 50000)(Employees). This operation will return a new table containing only the rows that meet the specified condition.

Overall, the selection operator in relational algebra enables us to filter and extract specific rows from a table based on desired conditions, allowing for flexible and precise data retrieval.

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Answer:

19.25%

Step-by-step explanation:

If you are asking 35% of 55 then this is your answer.

Answer:

\(\frac{1}{233974}\) (1 out of 233974 chance of correctly guessing Alec’s password)

Step-by-step explanation:

First Part (letter in the password):

There are 26 letters in the alphabet, and there is only one letter in Alec’s password. So for that part, you have \(\frac{1}{26}\) chance in finding the letter in the password.

Second Part (4 digit number in the password):

For the next part, the problem says that it’s a four digit number. So, out of all the numbers there are, what place value has four digits? It would be the thousands. That means from 1,000 to 9,999 (not including 10,000 too because that’s 5 digits) is the range of all the possible 4 digit numbers. So, how many numbers are in the range of 1,000 through 9,999? Well, all you do is subtract 1,000 from 9,999 (can be written as 9,999 - 1,000) and that equals 8,999. This means that there are 8,999 possible 4 digit numbers that can be guessed in Alec’s password. So that means you will have a 1 out of 8,999 chance in finding the 4 digit number in Alec’s password. This can be written as \(\frac{1}{8999}\).

Final Part (solving it):

Finally, you need to multiply the two chances together (the chance in finding the letter times the change of finding the 4 digit number). This can be written as \(\frac{1}{26}\) × \(\frac{1}{8999}\), which equals \(\frac{1}{233974}\).

Answer: \(\frac{1}{233974}\) (1 out of 233974 chance of correctly guessing Alec’s password)

I hope you understand and that this helps with your question! :)

Answer:

5

Step-by-step explanation:

the norm of f2(x) on the interval [0, 1] with the value of c from part (a) is 8/5.

To determine the value of the constant c so that f1(x) = x and f2(x) = 8 - 10cx are orthogonal on the interval [0, 1], we need to find the inner product of the two functions and set it equal to 0.

The inner product of two functions f(x) and g(x) on the interval [a, b] is defined as:

⟨f(x), g(x)⟩ = ∫[a,b] f(x)g(x) dx

In this case, we have:

f1(x) = x

f2(x) = 8 - 10cx

To find the value of c, we will set the inner product of f1 and f2 to 0:

⟨f1(x), f2(x)⟩ = ∫[0,1] x(8 - 10cx) dx

Expanding the expression and integrating, we get:

∫[0,1] (8x - 10cx²) dx = 0

Applying the integral, we have:

[4x² - (10/3)cx³] evaluated from 0 to 1 = 0

(4 - (10/3)c) - (0 - 0) = 0

Simplifying, we get:

4 - (10/3)c = 0

Multiply both sides by 3:

12 - 10c = 0

-10c = -12

Divide both sides by -10:

c = 12/10

Simplifying further, we have:

c = 6/5

Therefore, the value of the constant c that makes f1(x) and f2(x) orthogonal on the interval [0, 1] is c = 6/5.

To find the norm of f2(x) on the interval [0, 1] using the value of c from part (a), we need to calculate the square root of the inner product of f2(x) with itself:

||f2(x)|| = sqrt(⟨f2(x), f2(x)⟩)

||f2(x)|| = sqrt(∫[0,1] (8 - 10cx)² dx)

Expanding and integrating, we get:

||f2(x)|| = sqrt(∫[0,1] (64 - 160cx + 100c²x²) dx)

= sqrt(64x - 80cx² + (100/3)c²x³) evaluated from 0 to 1

= sqrt(64 - 80c + (100/3)c²) - sqrt(0 - 0)

= sqrt(64 - 80c + (100/3)c²)

Substituting the value of c from part (a), we have:

||f2(x)|| = sqrt(64 - 80(6/5) + (100/3)(6/5)²)

= sqrt(64 - 96 + 144/25)

= sqrt(192/25)

= 8/5

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The sοlutiοn tο the given prοblem οf the triangle cοmes οut tο be triangle side lengths are multiples οf triangle side lengths is untrue.

A triangular is a pοlygοn because it has twο οr maybe mοre additiοnal sectiοns. It has a straightfοrward square fοrm. Only the edges A, B, but alsο C distinguishes a triangular frοm a parallelοgram. When the sides are nοt exactly cοllinear, Euclidean geοmetry prοduces a singular plane instead οf a cube. If a shape has three edges and three angles, it is said tο be triangular.

Here,

A cοllectiοn οf the three pοsitive integers a, b, and c knοwn as a Pythagοrean triple fulfill the fοrmula a² + b² = c², where c is the hypοtenuse length οf a right triangle οf legs οf length a and b.

Triangle has sides that are 6, 8, and 10 in length. The Pythagοrean Theοrem is satisfied by these three numbers:

6² + 8² = 36 + 64 = 100 = 10²

Triangle is a right triangle as a result, and its side lengths make a Pythagοrean triple.

Hence, The statement that triangle side lengths are multiples οf triangle side lengths is untrue.

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Answer:

x=10

Step-by-step explanation:

x^2-20x+100=0

x^2-20x=-100

x^2=-100+20x

x^2+100=20x

100=10x

x=10

Hope this helps plz hit the crown ;D

Answer:

THATS ONLY 35 points

Step-by-step explanation:

Answer:

its only 35 points but that's ok we all make mistakes

Step-by-step explanation:

Answer:

5x7=35

Step-by-step explanation:

A tenth of an inch of water container will be 35.

Answer:

x = 5

Step-by-step explanation:

4x + 17 = 12x - 23

23 + 17 = 12x - 4x

      40 = 8x

       8      8

       5  =  x

The value of x should be 5.

A parallelogram is a quadrilateral with opposite sides parallel (and therefore opposite angles equal).

As, to from the square using the dimension of parallelogram the value of x should be 5

as the side of square is equal.

4x + 17 = 12x - 23

23 + 17 = 12x - 4x

40 = 8x

5  =  x

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Answer:

50 km/hr

Step-by-step explanation:

speed = x + 75

distance = 250km

time = 2

250 = (x + 75) * 2

125 = x + 75

x = 50

Consequently, 15 is the third partial total of the sequence.

The area of mathematics known as arithmetic deals with the mathematical study of numbers and the numerous procedures that can be performed on them. Addition, subtraction, multiplication, and division are the fundamental mathematical processes. The icons listed above stand in for these processes.

The given series is an arithmetic series with first term a1 = 2 and common difference d = 3.

To find the third partial sum, we need to add the first three terms of the series:

S₃ = 2 + 5 + 8

S₃ = 15

Therefore, the third partial sum of the series is 15.

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The number of can of soups purchased is 10 and the number of frozen dinner purchased is 10.

What are the linear equations in two variables?

A linear equation in two variables is one that is written in the form ax + by + c=0, where a, b, and c are real numbers and the coefficients of x and y, i.e. a and b, are not equal to zero. For example, 10x+4y = 3 and -x+5y = 2 are two-variable linear equations.

Let 'x' number of cans of soup purchased and 'y' number of frozen dinners purchased.

By the given condition, we can prepare the equations,

              x + y = 15 --------(I)

       200x + 500y = 4500 -----(II)

now from (I), y = 15 - x

Substitute the value of 'y' in the equation (II), we get

              200x + 500(15 - x) = 4500

              200x + 7500 - 500x = 4500

               300x = 3000

                    x = 3000/300

                    x = 10

Put x = 10 in equation (I), we get

                  y = 5

Hence, the number of can of soups purchased is 10 and the number of frozen dinner purchased is 10.

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Answer:

He is incorrect.Because if they are irrational they are the opposite.

Step-by-step explanation:

Answer:

30

Step-by-step explanation:

Because it is an isosceles triangle, then only two sides of the triangle are of the same length and since it said one angle of the triangle is 120° there are still 60° left, so split that into two, and it equals 30° for both equal sides

By the definition of the polynomials, the expression  \(3.9x^3 - 4.1x^2 + 7.3\) is the only polynomials.

Polynomials are those algebraic expressions that consist of variables, coefficients, and constants. The standard form of polynomials has mathematical operations such as addition, subtraction, and multiplication.

a. \(\pi x -\sqrt{3} +5y\)

This expression consists of 2 variables so this is not a polynomial.

b. \(x^{2} y^{2} -4xy^{3} +12y\)

This expression consists of 2 variables so this is not a polynomial.

c. \(\frac{4}{x} -4x^{2}\)

Here variable x is in the denominator in term 4/x so this is not a polynomial.

d. \(3.9x^3 - 4.1x^2 + 7.3\)

This expression satisfies all conditions of being a polynomial hence this is a polynomial.

e. \(\sqrt{x} -16\)

Here the power of variable x is not an integer so it's not a polynomial.

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Answer:

A B E

Step-by-step explanation:

cuz i know

Answer:

The volume of the hemisphere is 496741.6 m³

Step-by-step explanation:

The volume of an sphere is given by:

In which  and r is the radius.

An hemisphere is half of an sphere, so it's volume is half the sphere's volume. So

In this question:

. So

The volume of the hemisphere is 496741.6 m³

The researcher is not conducting non-random sampling.

Random sampling is a sampling technique in which every individual or element of the population of interest has an equal opportunity of being selected for the sample. Each member of the population has an equal chance of being selected for the sample. Random sampling helps to ensure that the sample is representative of the population.

Non-random sampling, on the other hand, is a sampling technique in which the individuals or elements of the population of interest are not randomly selected. In other words, not every member of the population has an equal chance of being selected. This sampling method is biased and can lead to an unrepresentative sample.

The researcher is not conducting a non-random sampling technique because she is observing every child in the population of interest. The population of interest, in this case, is the children on the playground.

The researcher is not conducting non-random sampling because random sampling is a sampling technique in which every individual or element of the population of interest has an equal opportunity of being selected for the sample.

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Answer: Thomas spent .15 less

Step-by-step explanation:

Dan: 2.50/2=1.25

Thomas: 3.30/3=1.1

1.25-1.1=.15

Answer:

C

Step-by-step explanation:

Each cone they bought was 1.10 each and 1.25 each

1.10<1.25

1.25-1.10=0.15

Answer:

Step-by-step explanation:(3,-1)

Answer:

(3,0) and (-1,0)

Step-by-step explanation:

just find the points on the graph

After factoring out the common term of xy from the numerator and denominator, the given algebraic fraction simplifies to \((x^2 - 2xy) / [(2y - x) y]\).

The given algebraic fraction is:

\((x^3y - 2x^2y^2) / (2xy^3 - x2y2)\)

To simplify the expression, we can factor out the common term of xy from both the numerator and denominator:

\((xy) (x^2 - 2xy) / (xy^2) (2y - x)\)

Now we can simplify further by canceling out the common factor of xy in the numerator and denominator:

\((x^2 - 2xy) / (2y - x) y\)

So the simplified form of the algebraic fraction is:

\((x^2 - 2xy) / (2y - x) y\)

To simplify an algebraic fraction, we want to find a way to write it in a form that is easier to work with. One common method is to factor out common terms in both the numerator and denominator. In this case, we can factor out xy from both the numerator and denominator, since it is a common factor in both.

Once we factor out xy, we can rewrite the algebraic fraction as:

\((xy) (x^2 - 2xy) / (xy^2) (2y - x)\)

Next, we can simplify further by canceling out the common factor of xy in the numerator and denominator. This leaves us with:

\((x^2 - 2xy) / (2y - x) y\)

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Answer:

Rounded Answer - 47.01

Exact Answer - 47.00935

Step-by-step explanation:

see attached image below!!!

PLZZ give me brainliest

Answer:

77.00

Step-by-step explanation:

the price is going by 1.50 a year so it would be 77.00 in 2020

Answer:

10

Step-by-step explanation:

2+2+6

Answer:

10

Step-by-step explanation:

The right side of the graph shows the sum of the cars. 2 black Impala's + 6 white Impala's + 2 red Impala's = 10 total Impala's (that is, if all of the Impala's are one solid color)

It appears that the system dynamics can be manipulated through the control input u to minimize the time required for convergence to the origin (0,0).

Here, we have,

given that,

min t_i

x₁ = x₂-u

x₂ = u

-1 ≤ u ≤ 1, (x₁, x₂) are arbitrary starting point.

and origin  (0,0) be the begging of the coordinate.

also given that, (x₁, x₂)→ (0,0)

so, min t_i at origin (0,0) = t

Therefore, the generality condition of the situation does not met.

so, we get,

The given system can be represented by the following equations:

x₁' = x₂ - u

x₂' = u

To analyze the behavior of the system, we can examine the dynamics of each variable separately.

For x₁:

x₁' = x₂ - u

The equation implies that the rate of change of x₁ is dependent on x₂ and the input u. The term (-u) acts as a control input that can affect the dynamics of x₁. If we choose an appropriate control input u, we can manipulate the rate of change of x₁ and potentially minimize the time required to reach the origin.

For x₂:

x₂' = u

The equation for x₂ indicates that the rate of change of x₂ is solely determined by the input u. The variable x₂ can be directly controlled by the input u, allowing us to influence its behavior and potentially expedite convergence.

Based on the given equations, it appears that the system dynamics can be manipulated through the control input u to minimize the time required for convergence to the origin (0,0).

By carefully selecting the control input, it is possible to achieve the shortest time to reach the origin from any arbitrary starting point (x₁, x₂).

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Answer:

Rectangle

Step-by-step explanation:

Plz Mark Brainliest Thanks

When interpreting the expression as \((tanx)^{(sinx)\), the limit using L'Hospital's Rule is -∞ as x approaches 0+. However, when interpreting the expression as\(tan(x^{sinx})\), the limit is not well-defined due to the indeterminate form of 0^0.

To calculate the limit using L'Hospital's Rule, let's consider both interpretations of the expression and find the limits for each case:

Case 1: lim\((tanx)^{(sinx)\) as x approaches 0+

Taking the natural logarithm of the expression, we have:

\(ln[(tanx)^{(sinx)}] = sinx * ln(tanx)\)

Now, we can rewrite the expression as:

\(lim [sinx * ln(tanx)]\)as x approaches 0+

Applying L'Hospital's Rule, we differentiate the numerator and denominator:

\(lim [(cosx * ln(tanx)) + (sinx * sec^{2}(x))] / (1 / tanx)\) as x approaches 0+

Simplifying the expression:

\(lim [cosx * ln(tanx) + sinx * sec^{2}(x)] * tanx\) as x approaches 0+

\(lim [cosx * ln(tanx) + sinx * sec^{2}(x)] * (sinx / cosx)\) as x approaches 0+

\(lim [(cosx * ln(tanx) + sinx * sec^{2}(x)) / cosx] * sinx\) as x approaches 0+

\(lim [ln(tanx) + (sinx / cosx) * sec^{2}(x)] * sinx\) as x approaches 0+

\(lim [ln(tanx) + tanx * sec^{2}(x)] * sinx\) as x approaches 0+

Since lim ln(tanx) as x approaches 0+ = -∞ and\(lim (tanx * sec^{2}(x))\) as x approaches 0+ = 0, we have:

\(lim [ln(tanx) + tanx * sec^{2}(x)] * sinx\) as x approaches 0+ = -∞

Therefore, the limit of \((tanx)^{(sinx)\) as x approaches 0+ using L'Hospital's Rule is -∞.

Case 2: lim\(tan(x^{sinx})\)as x approaches 0+

We can rewrite the expression as:

lim\(tan(x^{(sinx)})\) as x approaches 0+

This expression does not have an indeterminate form of \(0^0\), so we do not need to use L'Hospital's Rule. Instead, we can substitute x = 0 directly into the expression:

lim \(tan(0^{(sin0)})\) as x approaches 0+

lim\(tan(0^0)\)as x approaches 0+

The value of \(0^0\) is considered an indeterminate form, so we cannot determine its value directly. The limit in this case is not well-defined.

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In the first function have vertical compression by 1/2, in second function have horizontal compresion by 1/4, in third compression have Vertical reflection and in fourth function have Horizontal reflection and horizontal compression by 1/2.

In the given question we have to find the transformations that map the function y = \(8^x\) onto each function.

Since we have to find the transformation, so we know that in a transformation;

The transformation from the first equation to the second one can be found by finding a, h and k for each equation.

\(y=ab^{x-h}+k\)

The horizontal is define by the value of h. The horizontal shift is defined as:

g(x)=f(x+h) - The graph is shifted to the left h units.

g(x)=f(x−h) - The graph is shifted to the right h units.

Horizontal Shift: None

The vertical shift define on the value of k. The vertical shift is defined as:

g(x)=f(x)+k - The graph is shifted up k units.

g(x)=f(x)−k - The graph is shifted down k units.

Vertical Shift: None

The value of a describes the vertical stretch or compression of the graph.

a>1 is a vertical stretch

0<a<1 is a vertical compression.

(a) The given first function is \((\frac{1}{2})8^{x}\).

y = \(8^x\)

Combine \(8^x\) and 1/2.

y = \(8^x\)/2

Assume that

y = \(8^x\)  is f(x)=\(8^x\) and y= \((\frac{1}{2})8^{x}\) is g(x)= \((\frac{1}{2})8^{x}\).

On comparing the equation \(y=ab^{x-h}+k\)

The value of a, h, and k for f(x)=\(8^x\).

a=1, h=0, k=0

The value of a, h and k for g(x)=\((\frac{1}{2})8^{x}\).

a=1/2, h=0, k=0

Since the value of h and k so tnere is no horizontal and vertical shift.

SInce the value of a changes from 1 to 1/2 and 1/2 is greater that 0 but less than 1 so there is vertical compression by 1/2.

(b) The given second function is \(8^{4x}\).

y= \(8^{4x}\) is g(x)= \(8^{4x}\).

On comparing the equation \(y=ab^{x-h}+k\)

The value of a, h and k for g(x)=\(8^{4x}\).

a=1/4, h=0, k=0

Parent Function: f(x)=8^x

So, Horizontal Shift: None, Vertical Shift: None, Reflection about the x-axis: None, Vertical Compression or Stretch: None, horizontal compresion by 1/4.

(c) The given third function is \(-8^{x}\).

y= \(-8^{x}\) is g(x)= \(-8^{x}\).

The value of a, h and k for g(x)=\(-8^{x}\).

a=-1, h=0, k=0

Parent Function: f(x)=8^x

So, Horizontal Shift: None, Vertical Shift: None, Reflection about the x-axis: Reflected, Vertical Compression or Stretch: None.

Vertical reflection

(d) The given fourth function is \(8^{-2x}\).

y= \(8^{-2x}\) is g(x)= \(8^{-2x}\).

The value of a, h and k for g(x)=\(8^{-2x}\).

a=-1/2, h=0, k=0

Parent Function: f(x)=8^x

So, Horizontal Shift: None, Vertical Shift: None, Reflection about the x-axis: Reflected, Vertical Compression or Stretch: None.

Horizontal reflection and horizontal compression by 1/2.

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