please help me right away! it’s timed!

The correct correlation between the heights of husbands and wives in the U.S. is around -0.3. The correlation between the heights of husbands and wives in the U.S. is not as strong as some might assume. It is about -0.3.

This is not a strong negative correlation, but it is still a negative one, indicating that as the height of one partner increases, the height of the other partner decreases. This relationship may be seen in married partners of all ages. It's important to note that the correlation may not be consistent among various populations, and it may vary in different places. The correlation between husbands and wives' heights is -0.3, which is a weak negative correlation.

It indicates that as the height of one partner increases, the height of the other partner decreases. When there is a weak negative correlation, the two variables are inversely related. That is, when one variable increases, the other variable decreases, albeit only slightly. The correlation is not consistent across all populations, and it may differ depending on where you are. Nonetheless, when compared to other correlations, such as a correlation of -0.9 or 0.9, the correlation between husbands and wives' heights is a weak negative one.

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The answer should be option C.

For a second order differential equation t²y'' - 4ty' + 6y = 0, general solution is of the form y(t) = c₁t² + c₂t³, so another solution other than y₁(t) = t² is y₂(t) = t³.

Given solution to t²y'' - 4ty' + 6y = 0 is

y₁(t) = t²

Using the method of reduction of order, let us assume, y₂(t) = v(t)y₁(t) is a solution to t²y'' - 4ty' + 6y = 0 for suitable choice of v(t). So,

y₂ = vt²

y₂' = 2vt + t²v'

y₂'' = 2v + 2tv' + 2tv' + t²v''

y₂'' = 2v + 4tv' + t²v''

Substituting this

t²×( 2v + 4tv' + t²v'') - 4t×(2vt + t²v') + 6×(vt²) = 0

t⁴v'' = 0

v'' = 0

v' = c, c is a constant

v = ct

Therefore, y₂(t) = ct×t²

y₂ (t) = ct³

Therefore general solution will be y(t) = c₁t² + c₂t³

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Answer:

58

Step-by-step explanation:

Lmk if its correct :)

To solve the following equation

We have a coefficient equals to zero, then this term is going to vanish. We stay with the following equation:

If we subtract 2 from both sides, we're going to get the value for 'x'.

And this is the solution for the equation. x = 1.

To solve the initial value problem x²y" + 19xy' + 106y = 0, y(1) = 4, y'(1) = 1:

First, we assume a solution of the form y(x) = x^r, where r is a constant to be determined.

Taking the first and second derivatives of y(x), we have:

y' = rx^(r-1)

y" = r(r-1)x^(r-2)

Substituting these expressions into the given differential equation, we get:

x²(r(r-1)x^(r-2)) + 19x(rx^(r-1)) + 106x^r = 0

Simplifying the equation, we have:

r(r-1)x^r + 19rx^r + 106x^r = 0

Factor out x^r:

x^r(r(r-1) + 19r + 106) = 0

For a nontrivial solution, we set the expression inside the parentheses equal to zero:

r(r-1) + 19r + 106 = 0

Solving this quadratic equation, we find two values for r: r = -2 and r = -7.

Therefore, the general solution to the differential equation is:

y(x) = C₁x^(-2) + C₂x^(-7)

Using the initial conditions, we can solve for the constants C₁ and C₂:

y(1) = C₁(1)^(-2) + C₂(1)^(-7) = 4

C₁ + C₂ = 4

y'(x) = -2C₁x^(-3) - 7C₂x^(-8)

y'(1) = -2C₁(1)^(-3) - 7C₂(1)^(-8) = 1

-2C₁ - 7C₂ = 1

Solving the system of equations, we find C₁ = -17/15 and C₂ = 119/15.

Therefore, the solution to the initial value problem is:

y(x) = (-17/15)x^(-2) + (119/15)x^(-7)

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Step-by-step explanation:

the graph is like a rough movie of what the water balloon does :

first it goes up a little bit, then it stays a little bit more of less at the same height, and then it drops.

to answer the questions we really only follow the explicit meaning of the graph line :

A

during the interval of 0 and 2 seconds.

B

during the interval of 2 and 4 seconds.

C

the height of the water balloon decreases the fastest during the interval of 4 and 6 seconds (it decreases by almost 40 ft in 2 seconds).

in the intervals between 6 and 8 seconds and 8 and 10 seconds it only decreases by 20 ft in 2 seconds.

D

after 10 seconds the water balloon hits the ground (height 0 ft). from there on it will stay on the ground (0 ft). therefore, at 16 seconds it will be on the ground (0 ft).

FYI - at least on Earth this will not happen in real life : there will never be a period of time > 0 seconds where the balloon will stay flat in the air (unless something is holding it up). and any falling object (except an object with a large air resistance like a feather) will speed up during the fall and not slow down.

Answer:

To prove that cosA/sinA -sinA/cosA=2cos^2A-1/sinA cosA, we can start by multiplying both sides of the equation by sinA cosA:

cosA/sinA -sinA/cosAsinA cosA = (2cos^2A-1)/sinA cosAsinA cosA

Now we can simplify the left side of the equation by using the identity sin^2A + cos^2A = 1:

cosAcosA -sinAsinA = (2cos^2A-1)cosAsinA

Now we can simplify the right side of the equation by using the identity cos^2A = 1 - sin^2A:

cosAcosA -sinAsinA = (2(1 - sin^2A)-1)cosAsinA

Finally, we can simplify the right side of the equation by using the identity sinAcosA = (sinAcosA)/(sinA*cosA):

cosAcosA -sinAsinA = (2(1 - sin^2A)-1)(sinAcosA)/(sinA*cosA)

Since both sides of the equation are equal, we can conclude that the statement is true.

Answer:

Let's call the length of the hypotenuse SD as x.

Since the altitude from T to SD divides SD into two parts, let the length of the shorter part be y. Then the length of the longer part is x-y.

Using similar triangles, we have:

TU/TS = ST/TD

Substituting the values we have:

TU/(3√5) = √5/UD

TU = (3/5)UD

Using the Pythagorean theorem in triangle TUS, we have:

TU² + (3√5)² = TS²

(3/5 UD)² + 45 = ST²

9/25 UD² + 45 = ST²

Using the Pythagorean theorem in triangle TUD, we have:

TU² + UD² = TD²

(3/5 UD)² + UD² = x²

9/25 UD² + UD² = x²

34/25 UD² = x²

UD² = (25/34)x²

Substituting the value of UD² in the equation ST² = 9/25 UD² + 45, we get:

ST² = 9/25 (25/34)x² + 45

ST² = 45/34 x² + 45

Since y = x-y-1, we have y = (x-1)/2.

Using the Pythagorean theorem in triangle TUD, we have:

(1/4) (x-1)² + UD² = x²

(1/4) (x² - 2x + 1) + (25/34)x² = x²

(1/4)(x²) + (25/34)x² - (1/2)x + (1/4) = 0

(59/68)x² - (1/2)x + (1/4) = 0

Using the quadratic formula, we get:

x = [1/2 ± √(1/4 - 4(59/68)(1/4))]/(2(59/68))

x = [1/2 ± (3√34)/17]/(59/34)

x = 17/59 ± 6√34/59

Since x is the hypotenuse SD, we have:

UD² = (25/34) x²

UD² = (25/34) [(17/59 ± 6√34/59)²]

UD² = 136/59 ± 204√34/295

Therefore, the exact lengths of the two parts of the hypotenuse are:

SD = x = 17/59 ± 6√34/59

SU = x-y = (x-1)/2 = 8/59 ± 3√34/59

UD = y = (x-1)/2 = 8/59 ± 3√34/59

TU = (3/5) UD = (3/5) [8/59 ± 3√34/59] = 24/295 ± 9√34/295

ST² = 45/34 x² + 45 = 45/34 [(17/59 ± 6√34/59)²] + 45

ST = √[45/34 [(17/59 ± 6√34/59)²] + 45]

Answer:

1 acre is equal to 43,560 square feet.

Step-by-step explanation:

Hope it helped!

Answer:

slope-intercept form: y=5x-3 point-slope form: y-7=5*(x-2)

Step-by-step explanation:

Y-y1=m(x-x1)

plug in the values and you get y=5x-3

\(\huge\boxed{\mathcal{HELLO!:)}}\)

Since we are given the slope of the line and a point that it passes through, we can easily determine the equation of the line.

First of all, we need to write it in Point-Slope Form:

\(\huge\boxed{\boxed{\rm{y-y1=m(x-x1)}}}\)

Where y1 is the y-coordinate of the point, m is the slope, and x is the x-coordinate of the point.

Plug in the values and solve:

\(\huge\rm{y-7=5(x-2)\)

\(\rm{y-7=5x-10\)

\(\rm{y=5x-10+7}\\\rm{y=5x-3\)

\(\huge\boxed{\mathbb{ANSWER:{\boxed{\bold{y=5x-3}}}}}\)

\(\bigstar\star\) Hope it helps! Enjoy your day!

\(\rm{FabulousKingdom:)\)

The solid line on the graph has a positive slope that will be 2y - 3x ≥ 7. Then the correct option is C.

Let the equation of the line pass through (x₁, y₁) and (x₂, y₂).

Then the equation of the line is given as,

\rm (y - y_2) = \left (\dfrac{y_2 - y_1}{x_2 - x_1} \right ) (x - x_2)

The points that are on the line are given below.

(-9, -10), (-3, -1), and (3, 8)

The inequality of the line is given as,

(y - 8) ≥ [(8 + 1) / (3 + 3)] (x - 3)

y - 8 ≥ (3/2)(x - 3)

2y - 16 ≥ 3x - 9

2y - 3x ≥ 7

The solid line on the graph has a positive slope that will be 2y - 3x ≥ 7. Then the correct option is C.

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Answer: c

Step-by-step explanation:

we have

A(x)= x^2-5x for x>0



find A(6) and solve A(x)=36

Part 1

Find A(6)

that means

The value of A(x) when the value of x=6

For x=6

substitute

A(6)= 6^2-5(6)

A(6)=36-30

A(6)=6 in^2

Part 2

A(x)=36

Solve for x

substitute

A(x)= x^2-5x

36= x^2-5x

x^2-5x-36=0

Solve using the quadratic formula

we have

a=1

b=-5

c=-36

substitute

therefore

the solutions for x are

x=9 and x=-4

the solution is x=9 in (because the value of x can not be negative)

Answer:

i think its A im not sure tho i hope it helps

Step-by-step explanation:

The 99% confidence interval for the population mean time spent on the internet, in minutes, is given as follows:

(48.9, 59.5).

The t-distribution is used when the standard deviation for the population is not known, and the bounds of the confidence interval are given according to the equation presented as follows:

\(\overline{x} \pm t\frac{s}{\sqrt{n}}\)

The variables of the equation are listed as follows:

The critical value, using a t-distribution calculator, for a two-tailed 99% confidence interval, with 50 - 1 = 49 df, is t = 2.68.

The parameter values are given as follows:

\(\overline{x} = 54.2, s = 14, n = 50\)

Then the lower bound of the interval is given as follows:

\(54.2 - 2.68\frac{14}{\sqrt{50}} = 48.9\)

The upper bound of the interval is given as follows:

\(54.2 + 2.68\frac{14}{\sqrt{50}} = 59.5\)

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The value of y in the parallelogram is 120^o.

A parallelogram is a plane figure which has opposite sides to be equal. Some of its properties are:

i. Opposite sides are equal in length

ii. It has two diagonals

iii. Sum of adjacent angles is 180^o

The value of y in the diagram can be determined as;

m<ADC + m<DCB = 180^o              (sum of adjacent angles is 180^o)

(x + 8) + 3x = 180

4x = 180 - 8

    = 172

x = 172/ 4

  = 43

x = 43^o

So that;

m<ADC = x + 8

             = 43 + 8

             = 51^o

Therefore,

m<ADC + m<DAB = 180^o

51^o + (y + 9) = 180^o

y + 60 = 180

y = 180 - 60

 = 120

y = 120^o

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Given:

Cost of an item with VAT = Rs 1,356

Cost of that item without VAT = Rs 1,200.

To find:

The VAT.

Solution:

We have,

Cost of an item with VAT = Rs 1,356

Cost of that item without VAT = Rs 1,200.

We know that,

VAT = Cost of an item with VAT - Cost of that item without VAT

       = 1356 - 1200

       = 156

Therefore, the value of VAT is $156.

Answer:

0.5

Step-by-step explanation:

Hopefully u got it right

Step-by-step explanation:

If you meant 50 divided by 100

\(\frac{50}{100} = \frac{1}{2}\)

or just .5

If you meant 500 divided by 100

\(\frac{500}{100} = 5\\\)

Answer:

B

Step-by-step explanation:

Standard form of a polynomial is when the terms are order from highest exponential power to lowest exponential power. The choice you chose has the highest exponential power of 1, and a leading coefficient of 1. You are incorrect. The correct answer would be the second choice of:

\(5 {x}^{2} + 6x - 7\)

This polynomial is in standard form, and has a leading coefficient of positive 5.

The required probability for three numbers rolled on the dice are the sides of a triangle is 31/36.

The area of mathematics known as probability studies potential outcomes of events as well as their relative probabilities and distributions. It is based on the likelihood that something will occur. The justification for probability serves as the main foundation for theoretical probability.

Here,

When three dice are rolled, there are 63=216 possible outcomes, or triplets (x, y, z).

Once more, in a triangle, any two sides added together are larger than the third side, or (x+y)>z.

As a result, 186 outcomes or triplets are possible and satisfy this property.

Hence, the required probability is 186/216=31/36.

The required probability is 31/36 for three dice rolls to produce triangle sides.

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Answer:

\(\frac{36}{g}\)=9

Answer:

I could be wrong, but if a function says f(x)=#, than the domain (the x values) range from negative infinity to infinity, where for every x value, the y value is always #, so in this case, the value of d (or x) would be negative infinity to infinity, written as a domain, surrounded by parentheses.

Step-by-step explanation:

Answer: yes

Step-by-step explanation:

Answer: 666

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

So first you’ll have to find the total or the sum of collected.

$90+$60= $150

Because you’re finding the percent of the total collected by girl scouts, divide the amount collected from the girl scouts by the total.

$90/$150= .6

Multiply that by 100 to get %60.

Answer:

3 lb. 6 oz.

Step-by-step explanation:

4 - 1 = 3

8 - 2 = 6

3lb. 6oz.

Option C is the correct choice - It is not appropriate to estimate beyond the scale at all. (i.e 2.3 cm)

The scale has two divisions, one for centimeters and the other for millimeters, so it can only measure between 2 (cm) and 3 (mm) and no more.

A measuring device is used to compare the unknown quantity to a standard, and the comparison is then expressed as a number to ascertain the magnitude of the quantity. To properly convey the measurement, a number expressing the magnitude must also have a unit associated with it. For instance, it makes no sense to simply record someone's height as 64. It must be measured at 64 inches. Thus, a number and unit must be assigned to each measurement.

Because the scale has two divisions—centimeter and millimeter—it can only measure up to three centimeters (2.3).
Therefore, option C is the correct choice which states that Any estimate made outside of the scale is entirely inappropriate. (i.e 2.3 cm)

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COMPLETE QUESTION:

According to Professor Dave, how far beyond the scale reported is it appropriate to estimate a measurement? (i.e. If the ruler below has cm labeled and lines for mm, what is an appropriate estimate?) 0 1 2 3 4 5 6 7 8 9 10 cm

a) It is appropriate to estimate 1 digit beyond the scale (.e. 2.33cm)

b) It is appropriate to estimate 2 digits beyond the scale (.e. 2.333cm)

c) It is not appropriate to estimate beyond the scale at all. (.e 2.3 cm)

d) There are no guidelines. Students should do whatever they feel most comfortable doing.

The area of the region that lies inside the first curve and outside the second curve is 2π/3 - 2.

The first step is to find the intersection points of the two curves. The intersection points are at θ = 0, π/2, and 2π.

The next step is to use the polar coordinate formula for area to find the area of each curve. The area of a polar curve is given by the formula A = 1/2 ∫ θ1 θ2 r(θ)^2 dθ.

The area of the first curve is A1 = 1/2 ∫ 0 π/2 (1 cos(θ))^2 dθ = π/3.

The area of the second curve is A2 = 1/2 ∫ 0 π/2 (2 - cos(θ))^2 dθ = 2 - π/3.

The area of the region that lies inside the first curve and outside the second curve is A = A1 - A2 = 2π/3 - 2.

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