Please Help me to solve this problem!!!!!!

Answer:

yes it is possible

Explanation:

if the body is travelling with uniform speed in a circular track its speed remains the same but the velocity is non-uniform as the direction of the body is changing every time.

eg: a body in uniform circular motion has constant speed but its velocity changes at every point during the course of motion. Whenever, the direction changes, velcoity changes.

Answer:

The vertical component of the velocity can be found using the formula:

V₀y = V₀ * sin(θ)

where V₀ is the initial velocity, θ is the angle of projection, and V₀y is the vertical component of the velocity.

Substituting the given values, we have:

V₀y = 48 * sin(53°)

Using a calculator, we can evaluate sin(53°) to be approximately 0.799:

V₀y = 48 * 0.799

V₀y ≈ 38.352

Therefore, the vertical component of the velocity with which the ball was launched is approximately 38 meters/second, which corresponds to option B.

Answer:

B.) 38 meters/second

Explanation:

Answer:

\(T_2=39.5N\)

Explanation:

From the question we are told that:

Mass \(m=5kg\)

Length \(L=0.67m\)

Tension \(T=88N\)

Generally the equation for Tension is mathematically given by

 \(T = m * ( g + v^2 /l)\)

Therefore

 \(T_1 = m * ( g + \frac{v^2}{l})\)

 \(88 = 5 * ( 9.8 + \frac{v^2}{0.67})\)

 \(v^2=5.2\)

 \(v=2.4m/s\)

The uniform velocity is

 \(v=2.4m/s\)

Therefore

The tension at the side of the circle halfway between the top and bottom is

 \(T_2=5*\frac{2.3^2}{0.67}\)

 \(T_2=39.5N\)

Answer:

A solid air freshener loses mass and volume as a result of sublimation, where solid particles skip the liquid state and change directly from a solid to a gas. Sublimation requires that the particles in the solid state gain enough energy to immediately become a gas.

Explanation:

Hope this helps.

The temperature of the boiler is 150.9°C, the thermal energy absorbed each hour is 1.62 x 10^9 joules, and the amount of thermal energy lost per hour is 1.61 x 10^9 joules.

The Carnot cycle is a theoretical thermodynamic cycle that consists of four reversible processes: isothermal expansion, adiabatic expansion, isothermal compression, and adiabatic compression. It is a highly efficient cycle that provides the maximum possible efficiency for a heat engine operating between two given temperatures.

18. The efficiency of a Carnot engine is given by the equation:

efficiency = 1 - (T_C / T_H)

where T_C is the temperature of the cold reservoir and T_H is the temperature of the hot reservoir. We can rearrange this equation to solve for T_H:

T_H = T_C / (1 - efficiency)

Substituting the given efficiency and waste heat temperature values, we get:

T_H = 36.3°C / (1 - 0.761) = 150.9°C

Therefore, the temperature of the boiler is 150.9°C.

19. The efficiency of a Carnot engine is given by the equation:

efficiency = 1 - (T_C / T_H)

where T_C is the temperature of the cold reservoir and T_H is the temperature of the hot reservoir. We can rearrange this equation to solve for the thermal energy absorbed each hour:

thermal energy absorbed per hour = power output / efficiency

Substituting the given values, we get:

thermal energy absorbed per hour = 115 kW / (1 - (13°C / 569°C)) = 1.62 x 10^9 J/h

Therefore, the thermal energy absorbed each hour is 1.62 x 10^9 joules.

20. In a Carnot engine, all the input energy must be converted either into work output or waste heat. Therefore, the amount of thermal energy lost per hour is equal to the difference between the thermal energy absorbed and the power output:

thermal energy lost per hour = thermal energy absorbed per hour - power output

Substituting the given values, we get:

thermal energy lost per hour = 1.62 x 10^9 J/h - 115 kW x 3600 s/h = 1.61 x 10^9 J/h

So, the amount of thermal energy lost per hour is 1.61 x 10^9 joules.

Hence, The boiler has a temperature of 150.9°C, absorbs 1.62 × 109 joules of thermal energy every hour, and loses 1.61 x 109 joules of thermal energy every hour.

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Answer:

See Below

Explanation:

I am not sure what you exact question is to know what direction it is but here is how you do it.

The direction of the net force is the direction of the largest force.

for example if you were to push a box forward with 100 newton's of force and someone pushed at the same time 50 newton's backwards on the box, the box would move forwards because the was a greater force on the box in a forward direction. hope this helps

Answer:

С . Molecules are made up of two or more  atoms.

Explanation:

The relationship between molecules and atoms is that molecules are made up of two or more atoms.

Molecules are made up of atoms.

A molecule is the smallest particle of a substance element or compound capable of independent existence.

A molecule could be monoatomic, diatomic or polyatomic.

Monoatomic molecules are made up of one atom

Diatomic are made up of two different atoms

Polyatomic substances are made up of more than two kinds of atoms.

Explanation:

a.Object is in linear motion with constant velocity.

b.Object is moving at a constant speed.

c.Object is either at rest or it returns to the initial point.

d.Object is moving in a straight line without changing its direction.

hope it helps you

Answer:

34.24 %

Explanation:

Since I₀ is the intensity of the un-polarized light, the intensity I₁ of the light polarized by the 1st sheet is (by the one-half rule) I₁ = I₀/2.

The intensity of polarized light I from a polarized source I' is I = I'cos²Ф where Ф is the angle between the direction of I' and I. Since the second sheet has its transmission axis at 25° with respect °o the 1st sheet, the intensity of light I₂ from the second sheet is I₂ = I₁cos²25°.

Also, the 3rd sheet has its transmission axis 47° with respect to the 1st sheet. So, the angle between the transmission axis of the 2nd sheet and 3rd sheet is 47° - 25° = 22°. So, the intensity I₃ from the 3rd sheet is I₃ = I₂cos²22°

Finally, the 4th sheet has its transmission axis 10° with respect to the 3rd sheet. So, the intensity I₄ from the 4th sheet is I₄ = I₃cos²10°.

So,  I₄ = I₃cos²10°

I₄ = I₂cos²22°cos²10°

I₄ = I₁cos²25°cos²22°cos²10°

I₄ = (I₀/2)cos²25°cos²22°cos²10°

I₄/I₀ = cos²25°cos²22°cos²10°/2

I₄/I₀ = (cos25°cos22°cos10°)²/2

I₄/I₀ = (0.9063 × 0.9272 × 0.9848)²/2

I₄/I₀ = 0.8275²/2

I₄/I₀ = 0.6848/2

I₄/I₀ = 0.3424

So, as a percentage,

I₄/I₀ × 100% = 0.3424 × 100% = 34.24 %

A.  The motor's speed is approximately 1086 r/min if the field resistance is raised to 50 Ω.

B. The speed of this motor as a function of the field resistance RF is approximately 1086 r/min

A. According to the magnetization curve shown in Figure 8-9, the motor's speed can be calculated by using the following equation:

EA = kϕN, where EA is the back EMF, k is a constant, ϕ is the magnetic flux, and N is the motor speed.

Since the amount of armature current remains constant, the back EMF is also constant.

Therefore, the magnetic flux must also be constant. The magnetic flux is proportional to the field current IF, which can be calculated using Ohm's law:

IF = (250 V - EA)/(RF + R₁)

At the initial field resistance of 41.67 Ω, the field current is IF = (250 V - EA)/(41.67 Ω + 0.03 Ω) = (250 V - EA)/41.70 Ω.

If the field resistance is raised to 50 Ω, then the new field current is IF = (250 V - EA)/(50 Ω + 0.03 Ω) = (250 V - EA)/50.03 Ω.

Since the magnetic flux is constant, we can set the two expressions for IF equal to each other and solve for N:

kϕN/IF1 = kϕN/IF2

N = (IF2/IF1)N1 = (250 V - EA)/(50.03 Ω + 0.03 Ω) * 1103 r/min ≈ 1086 r/min

Therefore, the motor's speed is approximately 1086 r/min if the field resistance is raised to 50 Ω.

B. The speed of the motor as a function of the field resistance RF can be plotted using the same equation used in part A:

N = (250 V - EA)/(RF + R₁ + Radj) * 1103 r/min

where Radj is the resistance of any additional resistance in the circuit. Since the load current is constant, the current through the motor is also constant, so EA is also constant.

Therefore, the speed is inversely proportional to the total resistance in the circuit, which includes the field resistance RF, armature resistance R₁, and any additional resistance Radj.

A plot of the speed as a function of the field resistance is shown in Figure 8-10. As the field resistance increases, the speed of the motor decreases due to the increased total resistance in the circuit. This relationship is linear for this type of constant-current load.

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See the attached figure.

The black arrows represent the two given vectors. The dashed black arrows are these same vectors, but translated so that the end of one vector is aligned with the start of another.

The red vector is their sum.

In case you also need to find the magnitude and direction of the sum, we have

A = (120 N) (cos(30°) i + sin(30°) j) = (60√3 i + 60 j) N

B = (-100 N) (cos(90°) i + sin(90°) j) = (-100 j) N

⇒   A + B = (60√3 i - 40 j) N

⇒   ||A + B|| = √((60√3)² + (-40)²) N = 20√31 N

and its direction relative to the positive horizontal axis (rightward) is θ such that

tan(θ) = (-40) / (60√3) = -2/(3√3)

⇒   θ = arctan(-2/(3√3)) ≈ -21.05°

By separating actions that are motivated by obligation from those that are not, the first premise aids in the distinction between those actions that have moral value.

The first involves a salesman who, even though he is aware of the customer's inexperience, does not overcharge them because he does not want to risk damaging his reputation by being found out.

Because the salesman was not driven by a sense of obligation to treat the consumer fairly, Kant claims that this is not a moral issue.

The second claim is that "an action performed out of obligation has its moral significance not in the goal that it is intended to achieve.

Therefore, By separating actions that are motivated by obligation from those that are not, the first premise aids in the distinction between those actions that have moral value.

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Answer:

10m/s2

Explanation:

250/25=10

Answer:

the Answer is b

Explanation:

because the moon usually orbits around our solar system

As the moon continuously changing direction, it accelerates.

Option B. is correct.

The rate at which an object's velocity changes with respect to time is called acceleration. Accelerations are measured in terms of vectors. The orientation of the net force acting on an object determines the orientation of its acceleration.

The Moon is kept in orbit around us by the gravity of the Earth. It constantly shifting the Moon's velocity direction. This means that, despite its constant speed, gravity causes the Moon to accelerate all the time.

So, as the moon continuously changing direction, it accelerates.

Option B. is correct.

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250 Newton is net force .

mass= 50 kg

a= 5m/s²

force=ma

force=50×5

force=250 N

In mechanics, a force is any action that seeks to preserve, modify, or deform a body's motion. Isaac Newton's three principles of motion, which are outlined in his Principia Mathematica, are frequently used to illustrate the idea of force (1687).

Newton's first law states that unless a force is applied to a body, it will stay in either its resting or uniformly moving condition along a straight path. According to the second law, when an external force applies on a body, the body accelerates (changes velocity) in the force's direction.

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If the coefficient of kinetic friction between Josh's sled and the snow is 0.08, he slides 6.97 meter from the base of the hill.

To find how far from the base of the hill Josh's sled ends up, we need to first find the speed of the sled at the bottom of the hill using the conservation of energy principle,

mgh = (1/2)mv², plugging in the values given in the problem, we get,

m(9.81 m/s²)(3.5 m) = (1/2)mv²

Simplifying and solving for v, we get,

v = √(2gh)

v = √(2(9.81 m/s²)(3.5 m))

v = 8.29 m/s

Now we can use the kinematic equation,

d = vt - (1/2)at, to find how far the sled slides on the horizontal patch of snow before coming to a stop, where d is the distance traveled, v is the initial velocity (8.29 m/s), a is the acceleration due to friction (-μg), and t is the time it takes to come to a stop (which we can find by setting v = 0 and solving for t),

0 = 8.29 m/s - μg*t

t = 8.29 m/s / μg

Substituting this value of t back into the kinematic equation, we get,

d = (8.29)(8.29/μg) - (1/2)μg(8.29/μg)²

d = 6.97 m

Therefore, Josh's sled ends up 6.97 meters from the base of the hill.

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Machine 1 has the greatest mechanical advantage among the given machines. To determine the machine with the greatest mechanical advantage, we need to calculate the mechanical advantage for each machine.

Machine 1: Mechanical Advantage = Output Force / Input Force = 50 N / 5 N = 10

Machine 2: Mechanical Advantage = Output Force / Input Force = 50 N / 10 N = 5

Machine 3: Mechanical Advantage = Output Force / Input Force = 50 N / 25 N = 2

Machine 4: Mechanical Advantage = Output Force / Input Force = 50 N / 50 N = 1

Comparing the mechanical advantages, we can see that Machine 1 has the highest mechanical advantage of 10. This means that Machine 1 can multiply the input force by 10 to produce the output force. It provides the greatest amplification of force among the four machines.

Machine 2 has a mechanical advantage of 5, Machine 3 has a mechanical advantage of 2, and Machine 4 has a mechanical advantage of 1. Therefore, Machine 1 has the greatest mechanical advantage among the given machines.

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Answer:

292.31 m/s

Explanation:

If Distance (d) = 190m

Time (t) = 1.3s

Speed of sound in air (v) =?

then

2d=vt

v=2d/t

v= 2×190/1.3

v=292.31 m/s

The unit of measure of work is (d) Newton meter, which is commonly abbreviated or acronym as Nm or Joule (J). Option D is correct.

The quantity of energy transferred by a force operating via a displacement is referred to as work. It is computed by dividing the amount of force applied in the displacement direction by the length of the force's application. The mathematical formula for work (W) is

W=f×d×cosФ

Theta is the angle between the force vector and the displacement vector. F is the force, d is the displacement, and d is the displacement.

The unit of work, also known as the Newton meter (Nm) or Joule (J), is created by multiplying the force, measured in Newtons, by the distance, measured in meters. In many branches of research and engineering, the Joule is the unit of labor and energy that is most frequently employed.

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No

because that is a light

The light travel faster in fresh water as compare to sea water.

Hence, the light travel faster in fresh water as compare to sea water.

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Answer:

Dalton’s atomic theory was a scientific theory on the nature of matter put forward by the English physicist and chemist John Dalton in the year 1808. It stated that all matter was made up of small, indivisible particles known as ‘atoms’.

Explanation:

Atoms can be divided into their subatomic particles.

The statement that is part of Dalton's atomic theory is as follows: Matter is composed of small particles called atoms.

John Dalton is a scientist that first stated the theory of chemical combination in 1803.

The components of these theory are as follows:

Therefore, according to this question, the statement that is part of Dalton's atomic theory is as follows: Matter is composed of small particles called atoms.

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Answer:

Se mas clara

Explanation:

Answer:

(a) 0.748 J

(b) 2.245 J

(c) 3.74 J

(d) 4.482 W

Explanation:

(a) Work done  W = Force × distance

W = F×d,

Where d = 1/2(at²)

Therefore,

W =1/2(F×at²)................ Equation 1

Where a = acceleration, t = time.

But,

a = F/m...................... Equation 2

Where m = mass.

Substitute equation 1 into equation 2

W = 1/2(F²t²/m)................. Equation 3

Given: F = 6.7 N, t = 1 s, m = 30 kg

Substitute into equation 3

W₁ = 1/2(6.7²×1²/30)

W = 0.748 J.

(b) Similarly,

The work done in the second seconds is

Where t₂ = 2 s

W₂ = 1/2(F²t₂²/m)- W₁

W = 1/2(6.7²×2²/30)-0.748

W = 2.245 J

(c) The work done in the third seconds is

Where t₃ = 3 s

W₃ = 1/2(F²t₃²/m)-(W₂+W₃)

W = 1/2(6.7²×3²/30)-(2.993)

W = 3.74 J.

(d) P = Fv ............... Equation 4

Where v = velocity.

and,

v = at..................... Equation 5

Substitute equation 5 into equation 4

P = Fat................... Equation 6

Given: F = 6.7 N, a = 6.7/30 = 0.223 m/s², t = 3 s

Substitute into equation 6

P = 6.7×0.223×3

P = 4.482 W.

The two molecules that best complete the reactants' side of the equation\(CO_2\) + 2\(H_2O\) are \(O_2\) and CO.

The correct answer would be \(O_2\) and CO.

Based on the partial chemical equation provided, \(CO_2\) + 2\(H_2O\), we need to select two molecules that complete the reactants' side of the equation while also considering the conservation of mass. Let's evaluate the given options:

1. \(NaCl_3\): This compound, sodium trichloride, does not contain carbon (C) or oxygen (O) atoms, which are required to balance the equation. Therefore, \(NaCl_3\) is not a suitable choice.

2. \(HS_4\): This compound, hydrogen tetrasulfide, also does not contain carbon (C) or oxygen (O) atoms necessary to balance the equation. Hence, \(HS_4\) is not the correct choice.

3. \(CH_4\): This molecule, methane, consists of one carbon atom (C) and four hydrogen atoms (H). It contains carbon but lacks oxygen atoms required for balancing the equation. Thus, \(CH_4\) does not complete the reactants' side.

4. \(O_2\): Oxygen gas (diatomic oxygen) is represented by\(O_2\). It contains two oxygen atoms, which helps balance the equation since there are two oxygen atoms on the product side (2\(H_2O\)). \(O_2\) is a valid choice for completing the reactants' side.

Considering the conservation of mass, we still need a molecule that contains carbon. Among the given options, CO is the only molecule that consists of one carbon atom (C) and one oxygen atom (O). By adding CO to the reactants' side, we balance both carbon and oxygen atoms in the equation.

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Explanation:

Mass of carte 1 is 110 kg and that of crate 2 is 230 kg

Force required to lift crates is equal to its crate i.e. W = mg

On Moon, a = 1.625 m/s²

Weight of crate 1, W = 110 kg × 1.625 m/s²  = 178.75 N

Weight of crate 2, W = 230 kg × 1.625 m/s²  = 373.75 N

On Earth, g = 9.8 m/s²

Weight of crate 1, W = 110 kg × 9.8 m/s²  = 1078 N

Weight of crate 2, W = 230 kg × 9.8 m/s²  = 2254 N

Hence, this is the required solution.

The forces required to lift the crates straight up on the Moon is lesser than the forces required to lift them on Earth.

Given the following data:

Scientific data:

Mathematically, the weight of an object is given by the formula;

\(Weight = mg\)

Where;

\(Weight \;A= 110 \times 1.6\)

Weight A = 176 Newton.

\(Weight \;B=230 \times 1.6\)

Weight B = 368 Newton.

\(Weight \;A= 110 \times 9.8\)

Weight A = 1,078 Newton.

\(Weight \;B=230 \times 9.8\)

Weight B = 2,254 Newton.

In conclusion, the forces required to lift the crates straight up on the Moon is lesser than the forces required to lift them on Earth.

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(a) When m₂ is released, its acceleration will be approximately -3.27 m/s².

(b) The tension in the string is approximately -13.08 N.

To determine the acceleration of m₂ when it is released and the tension in the string, we need to consider the forces acting on the system.

(a) Acceleration of m₂:

Since the pulley is assumed to be frictionless, the tension in the string is the same on both sides of the pulley. We can consider the system consisting of m₁ and m₂ as one body. The net force acting on this system is the difference between the weight of m₁ and the weight of m₂:

Net force = m₁g - m₂g

Applying Newton's second law, F = ma, where F is the net force and a is the acceleration, we have:

m₁g - m₂g = (m₁ + m₂)a

Rearranging the equation to solve for the acceleration, we get:

a = (m₁g - m₂g) / (m₁ + m₂)

Substituting the given values, m₁ = 2.00 kg and m₂ = 4.00 kg, and the acceleration due to gravity, g = 9.8 m/s², we can calculate the acceleration:

a = ((2.00 kg)(9.8 m/s²) - (4.00 kg)(9.8 m/s²)) / (2.00 kg + 4.00 kg)

a = (19.6 N - 39.2 N) / 6.00 kg

a = -19.6 N / 6.00 kg

a = -3.27 m/s²

Therefore, when m₂ is released, its acceleration will be approximately -3.27 m/s². The negative sign indicates that the acceleration is in the opposite direction of the gravitational force.

(b) Tension in the string:

The tension in the string can be determined by considering the forces acting on m₂. The net force on m₂ is equal to its mass multiplied by its acceleration:

Net force = m₂a

Substituting the given values, m₂ = 4.00 kg and a = -3.27 m/s², we can calculate the tension:

Tension = (4.00 kg)(-3.27 m/s²)

Tension = -13.08 N

Therefore, the tension in the string is approximately -13.08 N. The negative sign indicates that the tension acts in the opposite direction of the weight of m₂.

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The particle’s acceleration is 0.268 m/s².

The initial velocity of the particle before 13.3 seconds is 3.56 m/s.

The time when the particle is at rest is 32.68 seconds.

The acceleration of the particle is calculated as follows;

a = Δv/Δt

a = (7.95 m/s - 4.38 m/s) / 13.3 s

a = 0.268 m/s²

u = at

u = 0.268 m/s² x 13.3 s

u = 3.56 m/s

s = ut + ¹/₂at²

0 = -4.38t + ¹/₂(0.268)t²

0.134t² = 4.38t

0.134t = 4.38

t = 32.68 seconds

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Answer:

The object in motion is deaccelerating in the negative direction.

Explanation:

Interpret the given position-time graph.

Observing the graph we can determine the slope is negative and is gradually flattening out. Thus, we can conclude the object in motion is deaccelerating in the negative direction.

Answer:

air pressure

:::::::::::::::::

The balloon hits the ground right before the professor gets there.

The balloon picks up speed due to gravity and we can calculate the time taken for it to fall to the ground as follows:

Gravity (g) = 9.81 m/s²

Height or distance (s) = 11 meters

Initial Speed (u) = 0 m/s

using equation of motion

\(s = ut + \frac{1}{2}at^{2}\)

where s = height

u = initial speed

a = acceleration due to gravity

t = time taken

then using above values we get

11 = 0 x 2 + 0.5 x (9.8 x t²)

t = 1.4975

So we can see that the balloon takes 1.4975 seconds to fall to the ground, and since the professor takes 2 seconds to get to that place.

The balloon hits the ground right before the professor gets there.

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