Please help me to solve this question​

Please Help Me To Solve This Question

Answers

Answer 1

Answer:

(p+5)(p-2)

Step-by-step explanation:

We are looking for two numbers that multiply to -10 (the rightmost number) and sum to 3 (the middle number)

These are 5 and -2

So we write

(p ____)(p ____)

and fill in the blanks

(p+5)(p-2)

Check by FOILing:

p^2 -2p + 5p -10

And combine the two middle terms.

p^2 + 3p - 10


Related Questions

There is a mother-daughter tea that will be attended by 20 mother-daughter pairs, including the hosts. The rules of conduct are very strict; the host mother-daughter will greet everyone, all the guest mothers will greet everyone, and all the guest daughters will greet all the mothers only. How many greetings will there be?

Answers

In total, the number of greetings will be 1159.

Why do you use the term "numbers"?

Mathematical symbols used to represent quantities or values include numbers. They are employed in the measurement, comparison, addition, subtraction, multiplication, and division processes in mathematics. According to their qualities and properties, numbers can be categorized into a variety of groups, including natural numbers, whole numbers, integers, rational numbers, irrational numbers, real numbers, and complex numbers. There are specific properties and guidelines for mathematical operations for each group of numbers. Mathematics depends on numbers, which are also utilized in many other disciplines, including science, engineering, economics, and statistics.

The number of greetings exchanged between the host and the other mothers and daughters must be counted first. Since there is only one host, the number of mother-daughter pairs is 20 - 1 = 19. There are thus a total of 38 greetings, 19 between the host and the other moms, and 19 between the host and the other daughters.

The number of pleasantries exchanged between the guest mums and everyone else must next be tallied. The host, the other mothers, and the daughters must all be greeted, making a total of 20 - 1 = 19 guest mothers. Thus, each host mother must extend 1 + 19 + 20 = 40 greetings. There will be 760 greetings exchanged between the guest mothers and everyone, or 19 x 40.

The number of pleasantries exchanged between the mothers and the invited girls must also be tallied. Moreover, there are 20 guest girls, so 19 of them must welcome the mothers. As a result, there will be 361 pleasantries exchanged between the mothers and the guest daughters.

In total, the number of greetings will be 38 + 760 + 361 = 1159.

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Use the distributive property to remove the parentheses. -3(4v-2y-6)

Answers

-12v+6y+18

you multiply everything by -3, so -3×4v=-12v
-3×(-2y)=6y, since negative × negative=positive
-3×(-6)=18

i hope this helps :)

Use the number line below, where RS= 5y +5, ST = 4y + 8, and RT = 67.
a. What is the value of y?
b. Find RS and ST.
R
a. What is the value of y?
y = (Type an integer or a decimal.)

Answers

Answer:

y = 6RS = 35ST = 32

Step-by-step explanation:

The segment sum theorem tells you the whole is the sum of the parts. That can be used to write an equation for y.

Setup

  RS +ST = RT

  (5y +5) +(4y +8) = 67

Solution

Simplifying, we get ...

  9y +13 = 67

  9y = 54 . . . . . . . . subtract 13

  y = 6 . . . . . . . . . divide by 9

RS = 5y +5 = 5·6 +5 = 35

ST = 4y +8 = 4·6 +8 = 32

The values of interest are ...

y = 6RS = 35ST = 32

can someone please help me
50 points

can someone please help me50 points

Answers

Answer:.

Step-by-step explanation im not sure

Answer:

Step-by-step explanation:

47.)  sin20 = 6/b

b = 6(sin20) = 17.5

c = √6²+17.5² = 18.5

48.)  tan61 = y/18

y = 18(tan61) = 32.5

z = √18²+32.5² = 37.1

49.)  r = √25²+23² = 34

50).  d = √30²+7² = 30.8

51.)  sin71 = j/19

j = 19(sin71) = 18

k = √19²-18² = 6.2

52.)  y = √4²-1² = √7 = 2.6

53.)  sin49 = f/26

f = 26(sin49) = 19.6

h = √26²-19.6² = 17

54.)  t = √7²+4² = 8.1

Can anyone solve this.

Can anyone solve this.

Answers

Answer:

x-1+5x+1=180, 6x=180, x=30

Step-by-step explanation:

If 2+sqrt(3) is a polynomial root, name another root of the polynomial, and explain how you know it must also be a root

Answers

Answer:

2 - √3

Step-by-step explanation:

Find other root. Use x as a substitute.

\(x = 2 + \sqrt{3}\\x - 2 = \sqrt{3}\\\left(x - 2\right)^2 = 3\\x^2 = 4 - 2 \times x \times 2 = 3\\x^2 - 4x + 1 = 0\)

Now, we must use the quadratic formula to find the rest of the solution.

\(x = \frac{-b\pm \sqrt{b^2-4ac} }{2a}\\x = \frac{4\pm \sqrt{\left(-4\right)^2-4 \times 1 \times 1} }{2}\\\frac{4 \pm \sqrt{12} }{2} = 2 \pm 3\)

If one root of this polynomial [root] is 2 - √3, the other will be 2 + √3. Inversing that rule, the answer is 2 - √3.

5 kilograms = ...... grams (Conversion factor: 1 kg = 1,000 g)

Answers

Answer:

5000 g

Step-by-step explanation:

1 kg = 1000 g

5 kg is 5 times 1 kg

5 * 1 kg = 5 * 1000 g

5 kg = 5000 g

How many website graphics can be created?

How many website graphics can be created?

Answers

I do not understand what do you mean

Which function represents a reflection of f(x) = 3/8 (4)^x across the y-axis?

Which function represents a reflection of f(x) = 3/8 (4)^x across the y-axis?

Answers

A function that represents a reflection of \(f(x) = \frac{3}{8} (4)^x\) across the y-axis include the following: D. \(g(x) = \frac{3}{8} (4)^{-x}\).

What is a reflection over the y-axis?

In Mathematics and Geometry, a reflection over or across the y-axis or line x = 0 is represented and modeled by this transformation rule (x, y) → (-x, y).

This ultimately implies that, a reflection over or across the y-axis or line x = 0 would maintain the same y-coordinate while the sign of the x-coordinate changes from positive to negative or negative to positive.

By applying a reflection over the y-axis to the parent exponential function, we would have the following transformed exponential function:

(x, y)                                              →                 (-x, y).

\(f(x) = \frac{3}{8} (4)^x\)                               →              \(g(x) = \frac{3}{8} (4)^{-x}\)

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Kyra is blocking off several rooms in a hotel for guests coming to her wedding. The hotel can reserve large rooms that can hold 8 people, and small rooms that can hold 6 people. Kyra reserved twice as many large rooms as small rooms, which altogether can accommodate 88 guests. Determine the number of small rooms reserved and the number of large rooms reserved.

Answers

The number of small rooms reserved is 4.

The number of large rooms reserved is 8.

What is an equation?

An equation is a mathematical statement that is made up of two expressions connected by an equal sign.

We have,

Small rooms are denoted as S.

Large rooms are denoted as L.

Now,

We will make two equations.
L = 2S _____(1)

8L + 6S = 88 ______(2)

Putting (1) in (2) we get,

8L + 6S = 88

8 x (2S) + 6S = 88

16S + 6S = 88

22S = 88

S = 88/22

S = 8/2

S = 4

Now,

Putting S = 4 in (1) we get,

L = 2 x 4

L = 8

Thus,

The number of small rooms and large rooms reserved is 4 and 8.

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When the scale factor is 1, what is the ratio of the side length of the side opposite ∠A and the length of the hypotenuse?

Answers

when the scale factor is 1, we have:

(side length of side opposite ∠A) / (length of hypotenuse) = sin A

When the scale factor is 1, the ratio of the side length of the side opposite ∠A to the length of the hypotenuse remains the same as in the original triangle. In a right triangle, the side opposite ∠A is referred to as the "opposite" side, and the hypotenuse is the longest side.

The ratio of the side length of the side opposite ∠A to the length of the hypotenuse is commonly known as the sine of angle A (sin A). So, when the scale factor is 1, the ratio of the side length of the side opposite ∠A to the length of the hypotenuse is equal to sin A.

In mathematical terms, when the scale factor is 1, we have:

(side length of side opposite ∠A) / (length of hypotenuse) = sin A

It's important to note that this ratio holds true for any right triangle, regardless of its size or dimensions, as long as the angle A remains the same.

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Find the tangent line and the normal line to the curve at the given point.

Find the tangent line and the normal line to the curve at the given point.

Answers

The equation of the normal line to the curve x^2y^2 = 4 at the point (-1,-2) is y = x - 1.

To find the tangent line and normal line to the curve x^2y^2 = 4 at the point (-1,-2), we need to determine the derivative of the curve equation with respect to x and evaluate it at the given point.

First, let's differentiate the equation x^2y^2 = 4 implicitly with respect to x using the chain rule:

2x * (y^2) + 2y * (2xy * dy/dx) = 0

Simplifying the equation, we have:

2xy^2 + 4xy(dy/dx) = 0

Now, let's find the value of dy/dx at the point (-1,-2). Substitute x = -1 and y = -2 into the equation:

2*(-1)(-2)^2 + 4(-1)*(-2)(dy/dx) = 0

Simplifying further:

8 + 8(dy/dx) = 0

8(dy/dx) = -8

dy/dx = -1

We have found the derivative dy/dx at the point (-1,-2), which is -1. This represents the slope of the tangent line to the curve at that point.

Using the point-slope form of a line, we can write the equation of the tangent line as:

y - y₁ = m(x - x₁)

Substituting the values of (-1,-2) and dy/dx = -1 into the equation, we have:

y - (-2) = -1(x - (-1))

y + 2 = -1(x + 1)

y + 2 = -x - 1

y = -x - 3

Therefore, the equation of the tangent line to the curve x^2y^2 = 4 at the point (-1,-2) is y = -x - 3.

To find the normal line, we know that the slope of the normal line is the negative reciprocal of the slope of the tangent line. Therefore, the slope of the normal line is 1.

Using the point-slope form of a line again, we can write the equation of the normal line as:

y - y₁ = m'(x - x₁)

Substituting the values of (-1,-2) and m' = 1 into the equation, we have:

y - (-2) = 1(x - (-1))

y + 2 = x + 1

y = x - 1

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i really do need help with this geometry questions please hlep

i really do need help with this geometry questions please hlep

Answers

the coordinate of X is at 8 units of P and at 4 units to the left of Q

So the coordinate of X is: -5 + 8 = 3

How to find the coordinates of point x?

We know that point X is between points P and Q, in such a way that the ratio between the lengths of the segments PX and XQ is 2:1

First, we can length of the segment PQ is equal to the difference between their coordinates, so we get:

L = 7 - (-5) = 12

Then the length of segment PQ is 12 units, if we divide that in 3 we will get:

12/3 = 4 units.

So the segment PQ can be divided into 3 segments of 4 units each.

If the ratio PX to XQ is 2:1

Then the segment PQ must be divided into 3 parts, such that PX takes two of these parts and XQ is the remaining one.

Then the coordinate of X is at 8 units of P and at 4 units to the left of Q

So the coordinate of X is: -5 + 8 = 3

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PLEASE I NEED HELP IN THIS
HERE IS THE PICTURE IS JUST ONE QUESTION

PLEASE I NEED HELP IN THISHERE IS THE PICTURE IS JUST ONE QUESTION

Answers

Answer:

f(x) = -5/9x - 11/9

Step-by-step explanation:

Consider f(x) = y

so if x = -4 => y = 1 and x = 5 => y = -4

so (-4,1) and (5,-4) should be on the same linear equation

Slope m = (y2 - y1)/(x2 - x1)

m = (-4 - 1)/(5 -  -4) = (-5)/(9) = -5/9

y = mx + b

given m = -5/9, x = -4, y = 1

1 = -5/9(-4) + b

b = 1 - 20/9

b = 9/9 - 20/9 = -11/9

so y = -5/9x - 11/9

or f(x) = -5/9x - 11/9

What is an equation of the line that passes through the points (3,6) and (1,−2)?

Answers

Answer:

y = 4x - 6

Step-by-step explanation:

Hi there!

We are given the points (3,6) and (1, -2), and that a line passes through these 2 points

We want to find the equation of said line

There are 3 ways to write the equation of the line:

Slope-intercept form, which is y=mx+b, where m is the slope and b is the y interceptStandard form, which is ax+by=c, where a, b, and c are integer coefficients but a and b cannot be equal to 0, and a cannot be negative Slope-point form, which is \(y-y_1=m(x-x_1)\), where m is the slope and \((x_1, y_1)\) is a point

The  most common way is slope-intercept form, so let's write the equation of the line this way

First, we need to find the slope

The slope (m)  can be found using the formula \(\frac{y_2-y_1}{x_2-x_1}\), where \((x_1, y_1)\) & \((x_2, y_2)\) are points

Before we calculate, let's label the values of the points.

\(x_1=3\\y_1=6\\x_2=1\\y_2=-2\)

Now substitute into the formula

m=\(\frac{y_2-y_1}{x_2-x_1}\)

m=\(\frac{-2-6}{1-3}\)

Subtract

m=\(\frac{-8}{-2}\)

Divide

m= 4

The slope of the line is 4

Substitute 4 as m in y=mx+b:

y = 4x + b

Now to find b

Since the equation passes through both (3,6) and (1, -2), we can use either point to help solve for b.

Taking (3,6) for example:

Substitute 3 as x and 6 as y.

6 = 4(3) + b

Multiply

6 = 12 + b

Subtract 12 from both sides

-6 = b

Substitute -6 as b into the equation

y = 4x - 6

Hope this helps!

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What is the value of -4.4+ (5-2)(-6)?

Answers

Answer:

Step-by-step explanation:

-4.4 + (5-2)(-6) = -4.4 + (3)(-6) = -4.4 + (-18) = - 22.4

The answer is 22.4
Hope this helps

2x^4y^3(5x) simplify fully

Answers

Answer:

the answer is (2•5x5y3)

Step-by-step explanation:

1.  (2x4 • y3) • 5x

Multiplying exponential expressions

2. x4 multiplied by x1 = x(4 + 1) = x5

Final result :

(2•5x5y3)

Sorry if I'm wrong

Answer:

10 x ^5 y^ 3

Step-by-step explanation:

2x-1=y
3x-1=y

Consider the system of equations above. Which of the following statements about this system is true?

2x-1=y 3x-1=yConsider the system of equations above. Which of the following statements about this system

Answers

Answer:

B; There is only one (x,y) solution and y is negative

Step-by-step explanation:

First, I graphed the two equations. Attached is an image of the equations graphed. Next, I looked for overlapping points. Wherever the two points overlap, there is a solution. When looking at the graph, we can see the lines overlap at only one point, (0,-1). Since y is negative, the answer must be B; there is only one (x,y) solution and y is negative.

If this answer helped you, please leave a thanks!

Have a GREAT day!!!

2x-1=y 3x-1=yConsider the system of equations above. Which of the following statements about this system

PLEASE HELP AS SOON AS POSSIBLE

PLEASE HELP AS SOON AS POSSIBLE

Answers

Answer:

B

Step-by-step explanation:

Yes, because for each input there is exactly one output. You can have two of the same x values but you cannot have 2 of the same y values. if you have two of the same y values, it is not a function as it doesn't pass the vertical line test.

A recipe for 1 batch of muffins calls for 3/4 cups of almond milk. Rose has 6 cups of almond milk. How many batches of muffins could she make​

Answers

Answer:

8

Step-by-step explanation:

3/4 cup leaves 1/4 cup from each cup

1/4+1/4+1/4=3/4

so it would be 3/4+3/4+3/4+3/4+3/4+3/4+3/4+3/4=8 cups

Identity theft is one of the most costly types of crime committed in the United States, the targets. The following charts show types of identity theft fraud reported in 2015 as well as percentage of victims by age.

Use this information for Questions 3-4. Percentage of Victims by Age Types of Identity Theft Fraud Reported in 2015

Loan fraud 3,5%

Bank fraud 5.9%

Employment frand 3.3%

Utilities/ phone fraud 9.9% Other 19.2%

Credit card fraud 15.8%

Government documents/benefits 49.2%

AAAA22 35 30 25 20 15 10 0 16 20 Under 20 20-29 30-39 40-49 50-59 60 & over

3. Using roster notation, list the set of types of identity fraud that made up less than 20% of all reported cases.

4. Write the set of identity theft types that made up more than 50% of all reported claims.

Identity theft is one of the most costly types of crime committed in the United States, the targets.

Answers

In roster notation, the set can be represented as:

{Loan fraud, Bank fraud, Employment fraud, Utilities/phone fraud, Other}

To write the set of identity theft types that made up more than 50% of all reported claims, we can examine the percentages provided.

The type of identity theft fraud that made up more than 50% of all reported claims is:

Government documents/benefits fraud (49.2%)

In roster notation, the set can be represented as:

{Government documents/benefits fraud}

To list the set of types of identity fraud that made up less than 20% of all reported cases, we can examine the percentages provided for each type of identity theft fraud.

The types of identity theft fraud that made up less than 20% of all reported cases are:

Loan fraud (3.5%)

Bank fraud (5.9%)

Employment fraud (3.3%)

Utilities/phone fraud (9.9%)

Other (19.2%)

In roster notation, the set can be represented as:

{Loan fraud, Bank fraud, Employment fraud, Utilities/phone fraud, Other}

To write the set of identity theft types that made up more than 50% of all reported claims, we can examine the percentages provided.

The type of identity theft fraud that made up more than 50% of all reported claims is:

Government documents/benefits fraud (49.2%)

In roster notation, the set can be represented as:

{Government documents/benefits fraud}

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A firm can produce only 2500 units per month. The monthly total cost is given by C(x) = 400 + 200x dollars, where x is the number produced. If the total revenue is given by R(x) = 350x − 1 100 x2 dollars, how many items, x, should the firm produce for maximum profit?

Answers

Answer:

2500

Step-by-step explanation:

Monthly total cost, C(x) = 400 + 200x dollars

Monthly total revenue, R(x) = \(350x -\dfrac{1}{100}x^2\) dollars

Profit = Revenue - Cost

\(=R(x)-C(x)\\=(350x -\dfrac{1}{100}x^2)-(400 + 200x)\\=350x -\dfrac{1}{100}x^2-400 - 200x\\P(x)=150x-\dfrac{1}{100}x^2-400\)

To determine how many items, x, the firm should produce for maximum profit, we maximize P(x) by taking its derivative and solving for its critical points.

\(P(x)=150x-\dfrac{1}{100}x^2-400\\P'(x)=150-\dfrac{x}{50}\\\\$Set $ P'(x)=0\\150-\dfrac{x}{50}=0\\150=\dfrac{x}{50}\\$Cross multiply\\x=150*50\\x=7500\)

Next, we check if the point x=7500 is a maxima or a minima.

To do this, we find the second derivative of P(x).

\(P''(x)=-\dfrac{1}{50} $ which is negative\)

Hence, the point x=7500 is a point of maxima. However, since the firm can only produce 2500 units per month.

Therefore, the company needs to produce 2500 units to maximize profit.

How would you graph the solutions to the inequality on a number line? k > 5

Answers

To graph the inequality k > 5 on a number line, mark an open circle at 5 and shade the region to the right.

To graph the solutions to the inequality k > 5 on a number line, follow these steps:

Draw a horizontal line and mark a point for the number 5 on the line.

-------------------|---|---|---|---|---|---|---|---|---|---|

0 1 2 3 4 5 6 7 8 9 10

Since the inequality is k > 5, the solution includes all values greater than 5. Therefore, draw an open circle (○) at the number 5 to represent that 5 itself is not included in the solution.

-------------------|---|---|---|---○---|---|---|---|---|---|

0 1 2 3 4 5 6 7 8 9 10

Shade the region to the right of the open circle. This shading represents all values that are greater than 5 and satisfy the inequality k > 5.

-------------------|---|---|---|---○===================>

0 1 2 3 4 5 6 7 8 9 10

The resulting number line graph illustrates that any value to the right of the open circle (excluding 5 itself) satisfies the inequality k > 5.

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How would you graph the solutions to the inequality on a number line? k > 5

PLS HELP

During a 90-minute school play, the main character was on stage 80% of the time.
What amount of time in minutes was the main character on stage?
88.9 minutes
112.5 minutes
80 minutes
72 minutes

PLS HELP During a 90-minute school play, the main character was on stage 80% of the time.What amount

Answers

Answer:

72 minutes

Step-by-step explanation:

you convert the 80% to decimal form so its now 0.80.

then you multiply how long the school play was (90) times the 'percentage' of how long the main character was on the stage (0.80).

90 times .80 is 72.

hope this helped:)

Helppppp plsssss I will do anything I need to pass this text

Helppppp plsssss I will do anything I need to pass this text

Answers

Answer:

(1,1) is the answer

Explanation:

Both lines cross at (1,1)

Activityin this activity you will apply the converse of the Pythagorean Theorem to determine whether triangle BCD is a right triangle.B046.emDQuestion 1The first step is to find the missing side length in the diagramPart AAccording to the diagram, which triangle is a right triangle

Activityin this activity you will apply the converse of the Pythagorean Theorem to determine whether

Answers

Given:

The figure with some sides measurements.

Required:

What is missing side length and which triangle is a right triangle?

Explanation:

Converse of Pythagoras theorem:

\(\begin{gathered} \text{ If the length of a triangle is }a,b\text{ and }c\text{ and }c^2=a^2+b^2,\text{ then the triangle} \\ \text{ is a right angle triangle.} \end{gathered}\)

So, take BAD right triangle,

\(\begin{gathered} BA^2+AD^2=BD^2 \\ 4^2+4^2=BD^2 \\ BD^2=16+16 \\ BD^2=32 \\ BD=4\sqrt{2} \end{gathered}\)

Now,

\(\begin{gathered} \text{ In }\Delta CBD, \\ BC^2+BD^2=CD^2 \\ 2^2+(4\sqrt{2})^2=6^2 \\ 4+32=36 \\ 36=36 \end{gathered}\)

Answer:

\(\begin{gathered} \text{ In diagram missing length equals }4\sqrt{2}\text{ and }\Delta BAD\text{ and }\Delta CBD\text{ are right} \\ triangles. \end{gathered}\)

Activityin this activity you will apply the converse of the Pythagorean Theorem to determine whether

Answer:

Step-by-step explanation:

Angle A is marked as a right angle. Therefore, triangle ABD is a right triangle.

To pay for a home improvement project that totals $20,000, a homeowner is choosing between two different credit card loans with an interest rate of 9%. The first credit card compounds interest quarterly, while the second credit card compounds monthly. The homeowner plans to pay off the loan in 10 years.

Part A: Determine the total value of the loan with the quarterly compounded interest. Show all work and round your answer to the nearest hundredth. (4 points)

Part B: Determine the total value of the loan with the monthly compounded interest. Show all work and round your answer to the nearest hundredth. (4 points)

Part C: What is the difference between the total interest accrued on each loan? Explain your answer in complete sentences. (2 points)



Please only responded if you know how to do it, will give the brainiest to however answers it correctly

Answers

The total value of the loan with quarterly compounded interest is approximately $45,288.38, while the total value of the loan with monthly compounded interest is approximately $45,634.84. The difference in total interest accrued is approximately $346.46.

Part A: To determine the total value of the loan with quarterly compounded interest, we can use the formula for compound interest:

A = P(1 + r/n)^(nt),

where:

A is the total value of the loan,

P is the principal amount (initial loan amount),

r is the interest rate (in decimal form),

n is the number of times interest is compounded per year,

and t is the number of years.

Given:

P = $20,000,

r = 9% or 0.09,

n = 4 (quarterly compounding),

t = 10 years.

Substituting the values into the formula, we have:

A = 20000(1 + 0.09/4)^(4*10).

Calculating this value, we find:

A ≈ $45,288.38.

Therefore, the total value of the loan with quarterly compounded interest is approximately $45,288.38.

Part B: To determine the total value of the loan with monthly compounded interest, we follow the same formula but with a different value for n:

n = 12 (monthly compounding).

Substituting the values into the formula, we have:

A = 20000(1 + 0.09/12)^(12*10).

Calculating this value, we find:

A ≈ $45,634.84.

Therefore, the total value of the loan with monthly compounded interest is approximately $45,634.84.

Part C: The difference between the total interest accrued on each loan can be calculated by subtracting the principal amount from the total value of each loan.

For the loan with quarterly compounding:

Total interest = Total value - Principal

Total interest = $45,288.38 - $20,000

Total interest ≈ $25,288.38.

For the loan with monthly compounding:

Total interest = Total value - Principal

Total interest = $45,634.84 - $20,000

Total interest ≈ $25,634.84.

The difference between the total interest accrued on each loan is approximately $346.46.

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Does this appear to be a regular polygon? Explain.

Does this appear to be a regular polygon? Explain.

Answers

No, it is not a regular polygon.

What is a convex hexagon?

A hexagon is a six sided polygon. And a convex hexagon means, the hexagon's vertices are pointed outwards.

And no interior angle has an angle measure more than 180°.

Given:

A polygon.

To be a regular polygon:

Given Hexagon,

should have equal sides and equal angles.

We have no information about the angles and sides.

Therefore, it is not a regular polygon.

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Which is the graph of f(x)=3^x

Which is the graph of f(x)=3^x

Answers

The third graph from the figure represents the exponential function f(x) = 3ˣ, since the function contains the point (x, y) = (5, 243) on the cartesian plane.

How to determine the graph associated with a given function

In this question we must compare a given exponential function with a set formed by four functions. As the function is crescent and monotonous, then  we can choose the correct graph by a evaluating the function for a given x-value and find the graph that matches with such finding:

f(5) = 3⁵

f(5) = 243

The third graph from the figure represents the exponential function f(x) = 3ˣ, since the function contains the point (x, y) = (5, 243) on the cartesian plane.

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The number of 6th graders in RSM summer camp to that of 7th graders was 4 to 11, while the number of 5th graders to that of the 6th graders was 13 to 9. By what percent did the number of 7th graders exceed that of the number of 5th and 6th graders taken together ?

Answers

Answer:

The number of 7th graders exceed that of the number of 5th and 6th graders taken together by 5.88%.

Step-by-step explanation:

I am going to say that:

x is the proportion of 5th graders.

y is the proportion of 6th graders.

z is the proportion of 7th graders.

The number of 6th graders in RSM summer camp to that of 7th graders was 4 to 11

This means that:

\(\frac{y}{z} = \frac{4}{11}\)

So

\(11y = 4z\)

\(y = \frac{4z}{11}\)

The number of 5th graders to that of the 6th graders was 13 to 9.

This means that:

\(\frac{x}{y} = \frac{13}{9}\)

\(9x = 13y\)

\(x = \frac{13y}{9}\)

All of them is 100%

This means that:

\(x + y + z = 1\)

We need to find z.

\(y = \frac{4z}{11}\)

\(x = \frac{13y}{9} = \frac{13*4z}{9*11} = \frac{52z}{99}\)

Then

\(x + y + z = 1\)

\(\frac{52z}{99} + \frac{4z}{11} + z = 1\)

The lcm(least common multiple) between 11 and 99 is 99. Then

\(\frac{52z + 9*4z + 99z}{99} = 1\)

\(187z = 99\)

\(z = \frac{99}{187}\)

\(z = 0.5294\)

By what percent did the number of 7th graders exceed that of the number of 5th and 6th graders taken together ?

z(7th graders) is 52.94%.

x + y(5th and 6th graders) is 100 - 52.94 = 47.06%

52.94 - 47.06 = 5.88

The number of 7th graders exceed that of the number of 5th and 6th graders taken together by 5.88%.

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