please help me with this!!

The subset of real numbers √3 belong to is irrational numbers

What is a subset ?

If all of the items in a set A are also in a set B, then the sets A and B are subsets of one another. To put it another way, the set A is contained within the set B. A and B stand for the subset connection.

When all the components of Set A are also present in Set B, Set A is said to be a subset of Set B. Alternatively said, Set B contains Set A. Example: If set A contains X and Y and set B contains X, Y, and Z, then set A is a subset of set B because set B also contains X and Y.

As √3 is irrational number

∴it is a  subset of real numbers √3 belong to is irrational numbers

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After analysing the given data we conclude that the factorization of the given expression is 3(x³+24)(x³-9), under the condition that the given expression is 3x⁶+57x³-648.

The expression 3x⁶+57x³-648 could  be factored by first evaluating the greatest common factor (GCF) of the terms.  It means the largest number that divides two or more numbers without leaving a remainder. For instance , the GCF of 12 and 18 is 6 because 6 is the largest number that divides both 12 and 18 without leaving a remainder.
The GCF of 3x⁶, 57x³ and -648 is 3.
We can factor out 3 from each term to get:
3(x⁶+19x³-216)
The expression x⁶+19x³-216 could  be factored further applying the substitution u=x³:
u²+19u-216
This quadratic equation can be factored as:
(u+24)(u-9)
Staging  back x³ for u,
(x³+24)(x³-9)
Hence, the factored form of 3x⁶+57x³-648 is:
3(x³+24)(x³-9)
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The remaining keys are hashed and placed in the table using linear probing until all keys are placed.

The hash table that results from using the hash function h(k) = k mod 13 to hash the keys 2, 7, 4, 41, 15, 32, 25, 11, and 30, assuming collisions are handled by linear probing:
Index       Key
0      
1      
2             2
3             4
4             30
5             41
6             15
7             7
8             25
9             11
10    
11    
12            32
To fill in the table, we apply the hash function to each key and then check whether that index is already occupied.

If it is, we move to the next index and continue until we find an empty spot. In this case, we start with the key 2, which hashes to index 2.

This index is empty, so we insert the key there.

Next, we hash the key 7, which also goes to index 2.

Since that spot is already occupied, we move to the next index (3) and find that it's empty, so we insert 7 there.

We continue in this way for each key, resolving collisions by linear probing.
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Answer:

\(y = \frac{1}{3} x - \frac{16}{3} \)

Step-by-step explanation:

Write 3x + y - 4 = 0 in the form of y = mx + c ,

where m is is the gradient .

Thus, y = -3x + 4

Next use the formula,

m1 × m2 = -1

to find the gradient for the new equation.

-3 × m2 = -1

m2 = 1/3

Given the contacting point (1, -5), therefore

y-(-5) =1/3(x-1)

y+5=1/3(x) - 1/3

y = 1/3(x) -1/3 -5

y = 1/3 (x) -16/3

3y=x-16

What is slope in straight line?

Generally, the slope of a line gives the measure of its steepness and direction. The slope of a straight line between two points says (x1,y1) and (x2,y2) can be easily determined by finding the difference between the coordinates of the points. The slope is usually represented by the letter 'm'.

y-y1=m(x-x1)

mm1=-1

Given line,

3x+y=4

y=-3x+4

slope, m=-3

m*m1=-1

-3*m1=-1

m1 = 1/3

Since, the new line that passes through the point (1, −5) is perpendicular to the line 3x+y=4, the slope of the new line will be 1/3.

Therefore, slope of the new line will be m1= 1/3

Now, equation of line is

y-y1=m1(x-x1)

Putting the values,

y-(-5)=1/3(x-1)

y+5=1/3(x-1)

3y=x-16

therefore, our line equation is 3y=x-16

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The specific name of the quadrilateral is trapezoid

The measure of the missing angle is 55 degrees

To determine the measure of the angle, we need to know the following;

The properties of a trapezoid are listed as;

From the information given, we have that;

125 + x = 180

collect the like terms, we have;

x = 180 - 125

subtract the values, we get;

x = 55 degrees

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From the rigid transformation that takes ABC to EDF, the coinciding parts based on congruency; are matched below.

When we say two triangles are congruent to each other, it means that the corresponding sides and corresponding angles of both triangles are equal.

Thus, if triangle ABC is congruent to triangle EDF, then we can say that;

Angle A ≅ Angle E

Angle B ≅ Angle D

Angle C ≅ Angle F

Segment AB ≅ Segment ED

Segment AC ≅ Segment EF

Segment BC ≅ Segment DF

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(a) Rejection region: Reject H0 if the calculated test statistic falls below the lower critical value or above the upper critical value at α/2 = 0.025.

(b) Rejection region: Reject H0 if the calculated test statistic exceeds the upper critical value at α = 0.025.

(c) Rejection region: Reject H0 if the calculated test statistic falls below the lower critical value at α = 0.01.

We have,

To determine the rejection region for the Wilcoxon signed rank test, we need to consider the sample size (n), the alternative hypothesis (Ha), and the significance level (α).

The rejection region consists of the critical values that, if exceeded, would lead to the rejection of the null hypothesis (H0).

Here are the rejection regions for each set of hypotheses:

(a)

H0: M = 0 versus Ha: M ≠ 0, n = 19, α = 0.05:

The rejection region consists of the lower and upper critical values of the Wilcoxon signed rank test at significance level α/2 = 0.05/2 = 0.025.

(b)

H0: M ≤ 0 versus Ha: M > 0, n = 8, α = 0.025:

The rejection region consists of the upper critical value of the Wilcoxon signed rank test at significance level α = 0.025.

(c)

H0: M ≥ 0 versus Ha: M < 0, n = 14, α = 0.01:

The rejection region consists of the lower critical value of the Wilcoxon signed rank test at significance level α = 0.01.

Thus,

(a) Rejection region: Reject H0 if the calculated test statistic falls below the lower critical value or above the upper critical value at α/2 = 0.025.

(b) Rejection region: Reject H0 if the calculated test statistic exceeds the upper critical value at α = 0.025.

(c) Rejection region: Reject H0 if the calculated test statistic falls below the lower critical value at α = 0.01.

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Answer:

Dude wt,f? The answer is B. Obviously.

Step-by-step explanation:

COMMON SENSE

The solution of the inequality is x≥-13 and the graph c represents the inequality, option c is correct.

The given inequality is -1/4(12x+8)≤-2x+11.

Let us solve for x:

Apply distributive property:

-3x-2≤-2x+11

Add 2 on both sides of the inequality:

-3x+2x≤11+2

Combine the like terms:

-x≤13

x≥-13

Hence, the graph of c represents the solution of the inequality.

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Answer:

Step-by-step explanation:

First get y byitself to oneside

\(2x-y\leq 5\)

Subtract -2x to bothside

\(-y\leq 5-2x\)

Divide -1 to make y positive. Dividing or Multiplying changes direction.

\(y\geq 2x-5\)

y >= any value above the positive of the line.

Answer:

\(the \: equation \: of \: the \: statement \: is : \\ 5 {x}^{2} - 28x = 2500\)

Answer:

3x^2-8x+4

Step-by-step explanation:

We are 90% certain that the average number of  hamsters per litter is between 7.1077 and 8.3323.

A confidence interval is a range of values that includes a population value with a high degree of certainty. When a population mean falls between an upper and lower interval, it is frequently expressed as a percentage. The confidence level is the long-run proportion of corresponding CIs that contain the parameter's true value. For example, 95% of all intervals computed at the 95% level should contain the true value of the parameter.

Given, n=47

\(\bar{x}\)=7.72

s=2.5

c=90%=0.90

To find the t-value, look in the row that starts with degrees of freedom.

df=n-1

df=47-1

df=46>45 and in the column with c=90% in the table

=1.679

Now, the margin of error is then:

E=\(t_{\alpha/2}\times \dfrac{s}{\sqrt{n}}=1.679\times \dfrac{2.5}{\sqrt{47}}\approx 0.6123\)

The confidence interval's boundaries are thus:

\(\overline{x}-E\)=7.72-0.6123=7.1077

\(\overline{x}+E\)=7.72+0.6123= 8.3323

The average number of hamsters per litter is between 7.1077 and 8.3323, and we are 90% certain of this.

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Answer: 5

Step-by-step explanation:

The ratio of the size increase is:

1:5

Now, multiply 1 and 5 to get the similarity ratio (also know as the scale factor):

1 • 5 = 5

Hope this helps!

Answer:

22 yards

Step-by-step explanation:

Let x equal the number of yards of ribbon at $.07 per yard:

$18.46 + 0.07x = $20.00

Solve for x

Subtract $18.46 from both sides

0.07x = $1.54

Divide both sides by .07

x = 22

Answer:

Rotation 90 degrees counter clockwise, dilation of 6, translation down

Step-by-step explanation:

The probability that the It is purple or has an odd number is 1.045.

According to the statement

We have to find that the probability of the given condition.

So, For this purpose, we know that the

Probability is the ratio of the number of outcomes in an exhaustive set of equally likely outcomes that produce a given event to the total number of possible outcomes.

From the given information:

five yellow jerseys numbered one to five and three purple jerseys numbered one to three.

The probability that the It is purple or has an odd number.

Then

Probability = 3/8 + 2/3

Probability = 0.375 + 0.67

Probability = 1.045.

So, The probability that the It is purple or has an odd number is 1.045.

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The  value for n that would make the inequality true is 4.5

You should understand that a statement of an order relationship with greater than, greater than or equal to, less than, or less than or equal to between two numbers or algebraic expressions is inequality.

The given inequality is ⁿ⁄₉ > ½

This implies that 2(n) > 1(9)

Opening the brackets to have

2n > 9

Making n the subject of the relation by dividing both sides by 2

2n/2 > 9/2

Therefore n = 4.5

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Answer:

time = 70 minutes

Answer:

5

Step-by-step explanation:

Plug 1 into the x.

So 2(1)+3

2+3

5 is your final answer.

Answer:

53%

Step-by-step explanation:

Use percent decrease formula.

= 85-40/85

= 45/85

≈ 0.53

= 0.53 * 100%

= 53%

Best of Luck!

Answer:

I will assume that you mean solve for q.

q < -2

Step-by-step explanation:

-2q - 2 > 2

      +2  +2

Add 2 to both sides

2q > 4

/-2    /-2

Divide both sides by -2 (flip the sign if you multiply or divide by a negative number)

q < -2

The probability that X is greater than 1 is 19/18. However, this probability is greater than 1, which is not possible. Therefore, there must be an error in the calculations or in the statement of the problem.

To find the value of the constant c, we use the fact that the total area under the probability density function (pdf) must equal 1:

∫ f(x) dx = 1

∫ (-cx) dx = 1 (since the pdf is defined as -cx for -3 < x < 3)

-c/2 [x^2]_-3^3 = 1

-c/2 [(3)^2 - (-3)^2] = 1

-c/2 (18) = 1

c = -1/9

Now, we can find the cumulative distribution function (cdf) by integrating the pdf from negative infinity to x:

F(x) = ∫ f(t) dt = ∫_-∞^x (-1/9)t dt

F(x) = (-1/18) x^2, -3 < x < 3

To find P(X > 1), we can subtract the probability that X is less than or equal to 1 from 1:

P(X > 1) = 1 - P(X ≤ 1)

P(X > 1) = 1 - F(1)

P(X > 1) = 1 - (-1/18) (1)^2

P(X > 1) = 19/18

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The probability that there will be between 5.5 and 7 in. of rainfall during the project is 0.88.

The availability of rainfall in terms of inches during the project is known to be a random variable defined by a triangular distribution with a lower end point of 5.25 in., a mode of 6 in., and an upper end point of 7.5 in.

We know that the triangular distribution has the following formula for probability density function.

f(x) = {2*(x-a)}/{(b-a)*(c-a)} ; a ≤ x ≤ c

Given: a= 5.25, b= 7.5 and c= 6

Given: Lower limit (L)= 5.5 in. and Upper limit (U) = 7 in.

The required probability is:

P(5.5 ≤ x ≤ 7)

We can break this probability into two parts: P(5.5 ≤ x ≤ 6) and P(6 ≤ x ≤ 7)

Now, calculate these probabilities separately using the formula of triangular distribution.

For P(5.5 ≤ x ≤ 6):

P(5.5 ≤ x ≤ 6) = {2*(6-5.25)}/{(7.5-5.25)*(6-5.25)}= 0.48

For P(6 ≤ x ≤ 7):

P(6 ≤ x ≤ 7) = {2*(7-6)}/{(7.5-5.25)*(7-6)}= 0.4

Now,Add both the probabilities,P(5.5 ≤ x ≤ 7) = P(5.5 ≤ x ≤ 6) + P(6 ≤ x ≤ 7)= 0.48 + 0.4= 0.88

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For the function f(x) = cos(x) on the closed interval [a, b], Rolle's Theorem can be applied.

Rolle's Theorem states that if a function is continuous on a closed interval [a, b] and differentiable on the open interval (a, b), and if f(a) = f(b), then there exists at least one value c in the open interval (a, b) such that f'(c) = 0.

In this case, the function f(x) = cos(x) is continuous on the closed interval [a, b] and differentiable on the open interval (a, b). Additionally, f(a) = f(b) since cos(a) = cos(b).

Therefore, Rolle's Theorem can be applied to f on the closed interval [a, b].

To find the values of c in the open interval (a, b) such that f'(c) = 0, we need to find the values of x where the derivative of cos(x) equals zero.

Taking the derivative of f(x) = cos(x), we have:

f'(x) = -sin(x)

Setting f'(x) = 0, we solve for x:

-sin(x) = 0

The sine function equals zero at x = 0, π, 2π, ...

Therefore, the values of c in the open interval (a, b) such that f'(c) = 0 are c = πn, where n is an integer, and πn is within the interval (a, b).

So, c = πn, where n is an integer and a < πn < b.

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Answer:

\(x\geq 6\)

Step-by-step explanation:

Assuming you meant the equation was \(y=2\sqrt{x-6}\)

The x-value must be greater than or equal to 6 because you cannot have an imaginary(negative) number underneath the square root.

Option D is correct, the domain of the function is x≥6, or in interval notation, [6, ∞) or 6≤x<∞, Option D is correct.

A relation is a function if it has only One y-value for each x-value.

The domain of the function y=2√(x-6) is the set of all values of x for which the function is defined.

Since the only restriction on x in this function is that the expression inside the square root (x-6) must be non-negative, we have:

x-6 ≥ 0

Solving for x, we get x greater than or equal to six.

x ≥ 6

Therefore, the domain of the function is x≥6, or in interval notation, [6, ∞)., Option D is correct.

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Answer:

not simplified:12/14

reduced/simplified:6/7

Step-by-step explanation:

1/2 ÷ 7/12 =1/2×12/7=

1×12

-- -- = 12/14

2×7

and if simplified then you just do

12÷2=6

----

14÷2=7

According to the given statement The faster computer will take 2 minutes to send out the company's email on its own.

To solve this problem, let's assign variables to the given information. Let "x" represent the time it takes the slower computer to send out the company's email on its own, and let "y" represent the time it takes both computers working together to send out the email.

According to the problem, it takes two computers "y" minutes to send out the email, and it takes the slower computer "x" minutes to do the job on its own.

Since the two computers are working together, we can set up the following equation: 1/x + 1/y = 1/t, where "t" represents the time it takes the faster computer to do the job on its own.

Substituting the given values into the equation, we have: 1/x + 1/y = 1/2y

To find the value of "t", we need to solve for "y" in terms of "x". Multiply both sides of the equation by 2xy to eliminate the denominators:

2y + 2x = xy

Rearranging the equation, we get:

xy - 2y - 2x = 0

Now, let's factor the equation:

y(x - 2) - 2(x - 2) = 0

Simplifying further:

(x - 2)(y - 2) = 0

Since we are looking for the time it takes the faster computer to do the job on its own, we disregard the solution (y - 2) = 0, which gives us y = 2.

Therefore, the faster computer will take 2 minutes to send out the company's email on its own.

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A 11.544 acre-feet of this ice field will melt from the beginning of day 1 (t = 0) to the beginning of day 4 (t = 3). So, correct option is C.

To solve the problem, we need to integrate the given rate of melting with respect to time over the interval [0,3] to find the total amount of ice that melts during this time.

First, we can simplify the given rate of melting by using the identity: sin³(t) = (3sin(t) - sin(3t))/4

So, M(t) = 4 - (3sin(t) - sin(3t))/4 = 16/4 - 3sin(t)/4 + sin(3t)/4 = 4 - 0.75sin(t) + 0.25sin(3t)

Integrating this expression with respect to t over the interval [0,3], we get:

\(\int\limits^3_0\) M(t) dt = \(\int\limits^3_0\) (4 - 0.75sin(t) + 0.25sin(3t)) dt

= [4t + 0.75cos(t) - (1/3)cos(3t)]|[0,3]

= (12 + 0.75cos(3) - (1/3)cos(9)) - (0 + 0.75cos(0) - (1/3)cos(0))

= 11.544

Therefore, the answer is (C) 11.544.

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Answer:

9

Step-by-step explanation:

4-x = 5(16-x)

44-x = 80-5x

4x = 36

x = 9