please help me with this​

Answer:

It is 20

Step-by-step explanation:

1+1= 2*20=40

40/2=20

Answer:

I believe it is 1+10x. hope this helps!!

9514 1404 393

Answer:

Step-by-step explanation:

1. The distributive property tells you the factor outside parentheses multiplies each of the term inside parentheses.

  7(3x -4y) = 7·3x -7·4y = 21x -28y

__

2. Time, speed, and distance are related by ...

  time = distance/speed

  time = (20 mi)/(40 mi/h) = 1/2 h = 30 minutes

The drive takes 30 minutes.

Answer:

5

Step-by-step explanation:

Both factors should be negative in order to multiply to give 14, but add to give -9. Hence, option C is the correct answer.

The polynomial equations of degree two in one variable of type f(x) = ax²+ bx + c = 0 and with a, b, c, and R R and a 0 are known as quadratic equations. It is a quadratic equation in its general form, where "a" stands for the leading coefficient and "c" for the absolute term of f. (x).

The standard form of the equation is:

f(x)=x² - 9x + 14

f(x) = x² - 2x - 7x + 14

f(x) = x(x - 2) - 7 (x - 2)

f(x) = (x - 7)(x - 2)

Hence, both factors should be negative in order to multiply to give 14, but add to give -9.

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Answer:

Step-by-step explanation:

The sampling distribution of the sample mean (x) is the probability distribution of all possible sample means of a given sample size, obtained from repeated sampling from a population. In this case, we have a normal distribution with a mean of 65 and a standard deviation of 18, and we are repeatedly drawing samples of size 9.

According to the Central Limit Theorem, as the sample size increases, the sampling distribution of the sample mean approaches a normal distribution, regardless of the shape of the population distribution, as long as the sample size is sufficiently large.

In this case, since the sample size is 9, which is smaller than 30, the sample mean x will not necessarily follow a normal distribution. However, if we take many samples of size 9 from the population and compute the sample mean for each sample, the distribution of these sample means will approach a normal distribution with mean μ = 65 and standard deviation σ/sqrt(n) = 18/sqrt(9) = 6.

Therefore, the sampling distribution of the sample mean x is approximately normal with mean μ = 65 and standard deviation σ/sqrt(n) = 6, where n = 9 is the sample size.

They bought a total of 160 pairs of shoes and boots

Variable is a value that can change, depending on conditions.

Let's start by defining some variables:

Let x be the number of pairs of shoes they bought.

Let y be the number of pairs of boots they bought.

From the problem, we know that:

The cost of a pair of shoes is 20 dollars.

The cost of a pair of boots is 60 dollars.

They spent a total of 8000 dollars,

so we have:

20x + 60y = 8000

They bought 3 times as many boots as shoes, so we have:

y = 3x

Now we can substitute y = 3x into the first equation and solve for x:

20x + 60(3x) = 8000

20x + 180x = 8000

200x = 8000

x = 40

So they bought 40 pairs of shoes. Using y = 3x, we find that they bought 120 pairs of boots.

Therefore, they bought a total of 40 + 120 = 160 pairs of shoes and boots.

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The growth formula for calculating the future value of an investment or loan, un = uo(1 + i)^n, can be expressed as un = uo[(1 + 1/a)^a]^rt. This equation relates the initial value (uo), the interest rate (r), the number of years (t), and the number of interest payments per year (N).

The growth formula for calculating the future value of an investment or loan is given by the equation un = uo(1 + i)^n. In this equation, r represents the annual interest rate as a percentage, t is the number of years, and N represents the number of interest payments made per year. To find the values of i and n in terms of r and t, we can use the formulas i = r/N and n = Nt.

Using the given formulas, we substitute i and n into the growth formula to get un = uo(1 + r/N)^(Nt). Simplifying further, we can rewrite the expression as un = uo[(1 + 1/N)^N]^t.

Now, to show that un = uo[(1 + 1/a)^a]^rt, we need to equate the expressions for N and a. By setting N = a^(-1), we can rewrite the formula as un = uo[(1 + 1/a)^a]^rt. This demonstrates that the growth formula un is equivalent to uo[(1 + 1/a)^a]^rt, given the relationship between N and a.

In summary, the growth formula for calculating the future value of an investment or loan, un = uo(1 + i)^n, can be expressed as un = uo[(1 + 1/a)^a]^rt. This equation relates the initial value (uo), the interest rate (r), the number of years (t), and the number of interest payments per year (N), showing the growth of an investment or loan over time.

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Answer:

Step-by-step explanation:

(a) Use Cos 2A = cos^2 A - sin^2 A.

So A = 2*37 = 74 degrees.

(b) B = 2*2x = 4x.

The line that intersects the curve at (8, p(8)) represents the secant line to the curve at that point. The statement is true.

A straight line that crosses a curve at two or more points is known as a secant line. The given point (8, p(8)) in this instance is on the curve and the line. As a result, the secant line to the curve at that point is the line that intersects the curve at (8, p(8)).

Let's think of an example to help further clarify this idea. Let's say we wish to locate the secant line to a curve at the point (8, p(8)) where the equation \(y = x^2\) defines the curve.

We must first determine the secant line's slope. The following formula determines the slope of a line via the points (x1, y1) and (x2, y2):

slope= (y2 - y1) / (x2 - x1).

The two points in this case are the curve's second point and (8, p(8)). We can select a different point on the curve, such as (4, p(4)), to get the slope.

slope = (p(4)-p(8)) / (4 - 8)

Next, we evaluate the function at these points:
\(p(4) = 4^2 = 16\\p(8) = 8^2 = 64\)

Substituting these values into the slope formula:
slope = (16 - 64) / (4 - 8)
     = -48 / -4
     = 12

Now that we have the slope, we can write the equation of the secant line using the point-slope form:
y - y1 = m(x - x1)

Substituting the values (8, p(8)) and slope = 12 into the equation:
y - p(8) = 12(x - 8)

Simplifying the equation:
y - p(8) = 12x - 96

This is the equation of the secant line to the curve at the point (8, p(8)).

In conclusion, the statement is true. The line that intersects the curve at (8, p(8)) represents the secant line to the curve at that point.

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Answer:

C

m= 7 LO= 14 MO= 14

Step-by-step explanation:

LO and NO are going to be the same length



m + 7 = 2m

to get the variable alone subtract m from both sides

7 = m)

plug 7 into both equations

7 + 7 = 14

2 x 7 = 14

Answer:

Step-by-step explanation:

The experimental probability of the cube landing on three is 1/10.

Answer:(

−1,3]

Step-by-step explanation:

Move all terms not containing

x

from the center section of the inequality.

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2

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2

x

≤

6

Divide each term in the inequality by

2

.

−

2

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2

x

2

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6

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Divide

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2

by

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2

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6

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Cancel the common factor of

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Tap for more steps...

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x

≤

6

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Divide

6

by

2

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−

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3

The result can be shown in multiple forms.

Inequality Form:

−

1

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x

≤

3

Interval Notation:

(

−

1

,

3

]

Let the number be x

ATQ

\(\\ \sf\longmapsto 3x+2=18\)

\(\\ \sf\longmapsto 3x=18-2\)

\(\\ \sf\longmapsto 3x=16\)

\(\\ \sf\longmapsto x=\dfrac{16}{3}\)

\(\\ \sf\longmapsto x=5.3\)

\(\\ \sf\longmapsto x\approx 5\)

Answer:

Square root of 27 units

Step-by-step explanation:

the square of hypotenuse is equal to sum of square length of the two legs

if we call the other leg x

x^2 + 3^2 = 6^2

x^2 + 9 = 36

x^2 = 27

Answer:

The answer is the square root of 27 units

Step-by-step explanation:

Answer:

146

Step-by-step explanation:

6 * 23 = 138

138 + 8 = 146

Answer:

146

Step-by-step explanation:

6x23 = 138

138+8= 148

Answer:

Mathematics Solutions Solutions for Class 8 Math Chapter 14 Construction Of Triangles are provided here with simple step-by-step explanations. These solutions for Construction Of Triangles are extremely popular among Class 8 students for Math Construction Of Triangles Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Mathematics Solutions Book of Class 8 Math Chapter 14 are provided here for you for free. You will also love the ad-free experience on Meritnation’s Mathematics Solutions Solutions. All Mathematics Solutions Solutions for class Class 8 Math are prepared by experts and are 100% accurate.

Step-by-step explanation:

Construct a triangle ABC in which AB = 5 cm and BC = 4.6 cm and AC = 3.7 cm.

ANSWER:Steps of construction:

ANSWER:Steps of construction:(1) Draw a sufficiently long line segment using a ruler.

ANSWER:Steps of construction:(1) Draw a sufficiently long line segment using a ruler.(2) Locate points A and B on it such that AB = 5 cm.

ANSWER:Steps of construction:(1) Draw a sufficiently long line segment using a ruler.(2) Locate points A and B on it such that AB = 5 cm.(3) With A as the centre and radius 3.7 cm, draw an arc.

ANSWER:Steps of construction:(1) Draw a sufficiently long line segment using a ruler.(2) Locate points A and B on it such that AB = 5 cm.(3) With A as the centre and radius 3.7 cm, draw an arc.(4) With B as the centre and radius 4.6 cm, draw another arc that cuts the previous arc at C.

ANSWER:Steps of construction:(1) Draw a sufficiently long line segment using a ruler.(2) Locate points A and B on it such that AB = 5 cm.(3) With A as the centre and radius 3.7 cm, draw an arc.(4) With B as the centre and radius 4.6 cm, draw another arc that cuts the previous arc at C.(5) Join AC and BC.

ANSWER:Steps of construction:(1) Draw a sufficiently long line segment using a ruler.(2) Locate points A and B on it such that AB = 5 cm.(3) With A as the centre and radius 3.7 cm, draw an arc.(4) With B as the centre and radius 4.6 cm, draw another arc that cuts the previous arc at C.(5) Join AC and BC.Then, ABC is the required triangle.

Answer:

C. 2.4 degrees Fahrenheit

Step-by-step explanation:

1.1 per hour for 7 hours

1.1 x 7 = 7.7

5.2 - 7.7= -2.5

-2.5 + 4.9 = 2.4

We get: u(xi, tj) = u(xi, tj-1) + a(Δt/h²)[u(xi+h, tj) - 2u(xi, tj) + u(xi-h, tj)]

The backward difference method is a numerical method used to approximate the partial derivative of a function with respect to time, given its values at discrete points in space and time. The formula for this method is:

∂u(xi, tj)/∂t ≈ [u(xi, tj) - u(xi, tj-1)]/Δt

where Δt is the time step size. To derive an approximation for the second derivative of u with respect to x using the backward difference method, we can use the difference formulas:

∂²u(xi, tj)/∂x² ≈ [u(xi+h, tj) - 2u(xi, tj) + u(xi-h, tj)]/h²

where h is the spacing between consecutive spatial grid points.

Combining these two formulas, we get:

∂u(xi, tj)/∂t ≈ [u(xi, tj) - u(xi, tj-1)]/Δt = a∂²u(xi, tj)/∂x²

Solving for u(xi, tj), we get:

u(xi, tj) = u(xi, tj-1) + a(Δt/h²)[u(xi+h, tj) - 2u(xi, tj) + u(xi-h, tj)]

This is the backward difference method formula for approximating the solution to the partial differential equation. We can use it iteratively to find approximations for the value of u at each point in space and time, starting from the initial condition u(x,0) = f(x) and advancing in time by steps of size Δt.

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The L1 norm of vector A is greater than or equal to the L1 norm of vector B.

Basically, if the L2 norm of vector A is greater than the L2 norm of vector B, it is indeed always true that the L1 norm of vector A is greater than or equal to the L1 norm of vector B. The Lp norm is defined as follows:

\(||x||_p = (|x_1|^p + |x_2|^p + ... + |x_n|^p)^(1/p),\)

where x = [x₁, x₂, ..., xₙ] is a vector.

For the L2 norm (p = 2), the formula is:

\(||x||_2 = \sqrt(|x_1|^2 + |x_2|^2 + ... + |x_n|^2).\)

For the L1 norm (p = 1), the formula is:

\(||x||₁ = |x_1| + |x_2| + ... + |x_n|.\)

If ||A||₂ > ||B||₂, it implies that:

\(\sqrt(|A_1|^2 + |A_2|^2 + ... + |A_n|^2) > \sqrt(|B_1|^2 + |B_2|^2 + ... + |B_n|^2).\)

Squaring both sides of the inequality, we get:

\(|A_1|^2 + |A_2|^2 + ... + |A_n|^2 > |B_1|^2 + |B_2|^2 + ... + |B_n|^2.\)

Since the squares of the magnitudes are positive, we can conclude that:

\(|A_1| + |A_2| + ... + |A_n| > |B_1| + |B_2| + ... + |B_n|.\)

Therefore, the L1 norm of vector A is greater than or equal to the L1 norm of vector B.

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Answer:

-65

Step-by-step explanation:

hope this helps

The product of rational numbers can always be expressed as the ratio of two integers, where the denominator is not zero.

The product of rational numbers can always be written as a rational number. A rational number is defined as the quotient of two integers, where the denominator is not zero. When we multiply two rational numbers, we are essentially multiplying the numerators and denominators separately.

Let's consider two rational numbers, a/b and c/d, where a, b, c, and d are integers and b, d are not equal to zero. The product of these rational numbers is (a/b) * (c/d), which can be simplified as (a * c) / (b * d). Since multiplication of integers results in another integer, both the numerator and denominator are integers.

Furthermore, as long as the denominators b and d are not zero, the product remains a valid rational number.

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Answer:

Step-by-step explanation:

A

The value of x from the given expression is 5 and the property used are addition and division property

Given the equation below

2x - 30 = -20

Add 30 to both sides (Addition property)

2x - 30 + 30 = -20 + 30

2x = -20 + 30

2x = 10

Divide both sides by 2

2x/2 = 10/2

x = 5

Hence the value of x from the given expression is 5 and the property used are addition and division property

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An expression with a square root is referred to as a radical expression.

Radical simplification:

Cube root simplification:

Rational radical simplification :

                 \(\frac{2}{\sqrt{5} -1} \\\\=\frac{2}{\sqrt{5} -1} *\frac{\sqrt{5}+1}{\sqrt{5}+1} \\\\=\frac{2(\sqrt{5} +1) }{4} \\\\=\frac{\sqrt{5} +1 }{2}\)

Exponential radical simplification :

           \((5^{2} )^{3} \\=(5^{2} ) (5^{2} )(5^{2} )\\=25 *25*25\\=15625\)

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Answer:

Step-by-step explanation:

\(y=-3(x^2+10x+25)-1\\ \\ y=-3x^2-30x-76\\ \\ dy=-6x-30\\ \\ d^2y=-6\\ \\ \text{Since the second derivative is always negative, when the first derivative is equal to zero the function will be at a global maximum.}\\ \\ dy=0=-6x-30\\ \\ x=-5\\ \\ f(-5)=-1\\ \\ \text{So the global maximum occurs at the point (-5,-1)\)

Answer:

C. aₙ = 7 + (n-1)(-4)

Step-by-step explanation:

a₁ =7     a₂ = 7-4 = 3       a₃ = 3 - 4 = 7-4 -4 = 7- 4* ( 3-1) = -1

aₙ = 7 + (n-1)(-4)

Answer:

(x^2+4)+10

Step-by-step explanation:

i think

Answer:

B

Step-by-step explanation:

I graphed the equation, and the highest point was at 3.7 feet in the air, 4 seconds into the flight. See the graph below. Hope this helps!

Answer: C complete reversal

Step-by-step explanation:

When there is a complete reversal error which is also known as an " error of complete reversal entry", the debit entry is switched with the credit entry. This is one of the more difficult errors to pick up because the Trial balance remains balanced when this happens as the debits and the credits would still be equal.

When rent is received from a tenant. The correct entries are to debit it to cash which is an asset and so will be debited when it increases.

Then credit it to Rent Receivable because this is a revenue account and these are credited when they increase.

The entries were therefore reversed.