please help me with this math problem

Domain: 8, 9, 10, 11.Range: -7, 7 This relation does not represent a function because the same x-value (8, 10, 11) is associated with more than one y-value (-7, 7).

Domain: 8, 9, 10, 11

Range: -7, 7

A function is a relation between a set of inputs and a set of outputs such that each input is associated with exactly one output. This particular relation fails to meet this condition because the domain value 8 is associated with two different range values (-7 and 7). In other words, the same input (8) is associated with two different outputs, which means the relation does not represent a function. The domain of the relation is 8, 9, 10, 11 and the range is -7 and 7. Therefore, this relation does not represent a function because it violates the condition that each input must have one and only one associated output.

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Answer:

Pretty sure it is B sorry if I am wrong :)

Answer:

Is number 4

Step-by-step explanation:

Answer:

d, 3 5/8

Step-by-step explanation:

A graph of the resulting triangle after a rotation of -180° about the origin is shown below.

In Mathematics and Geometry, the rotation of a point 180° about the origin in a clockwise or counterclockwise direction would produce a point that has these coordinates (-x, -y).

Furthermore, the mapping rule for the rotation of triangle TOP 180° counterclockwise or -180° about the origin is given by this mathematical expression:

(x, y)                                            →            (-x, -y)

Coordinates of point T (6, 0)  →  Coordinates of point T' = (-6, 0)

Coordinates of point O (-2, -5)  →  Coordinates of point O' = (2, 5)

Coordinates of point P (-2, 5)  →  Coordinates of point P' = (2, -5).

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

Answer:

PR= 8

ST=5

Step-by-step explanation:

PQ and PR are congruent so

2x=8

x=4

2*4=8

PR=8

ST and TU are congruent so

5z=2z+3

3z=3

z=1

5*1=5

ST=5

Answer:

PR=8

ST=5

Step-by-step explanation:

PR

QS=SR (marked)

a²=b²+c² (TRIANGLE PQS)

PQ²=PS²+QS²

8²=PS²+SR² (PQ=8, QS=SR)

64=PS²+SR²

a²=b²+c² (TRIANGLE PRS)

PR²=PS²+SR²

(2x)²=64

2x=8

x=4

PR=2x=2(4)=8

ST

a²=b²+c² (TRIANGLE VUT)

VT²=TU²+UV²

VT²=(2z+3)²+UV²

VT²=4z²+12z+9+UV²

a²=b²+c² (TRIANGLE VST)

VT²=VS²+ST²

VT²=VS²+25z²

4z²+12z+9+UV²=VS²+25z²

21z²-12z-9=0

7z²-4-3=0

(7z+3)(z-1)=0

z=-3/7 or z=1

cant be neg, z=1

ST=5(1)=5

Answer:

The ball is 3.86 meters from the wall when it stops rolling.

Step-by-step explanation:

Representation of the situation:

This situation can be represented by a right triangle:

The hypotenuse is the distance the ball traveled, of 6 meters.

The distance from the wall is the side opposite to the angle of 40º.

We have that:

Sine of an angle is the length of the opposite side divided by the hypotenuse. So, in this situation.

Sine of 40 degrees = Distance from the wall/6

Sine of 40 degrees is of 0.64278760968.

Distance = 6*0.64278760968 = 3.86.

The ball is 3.86 meters from the wall when it stops rolling.

Answer: (x+6)(x-3)

Step-by-step explanation:

y=x^2+3x-18

(x+6)(x-3 )

The Venn diagram for (D ⋃ E) ⋃ F will be the ovarlapped region of D,E and F.

To represent the sets D, E, and F in the Venn diagram, we first construct three overlapping circles. Then, beginning with the innermost operation and moving outward, we shade the regions corresponding to the set operations in the expression.

We shade the area where the circles for D and E overlap because the equation (D ⋃ E)  denotes the union of the sets D and E. All the elements in D, E, or both are represented by this area.

The union of (D ⋃ E) with F is the next step. This indicates that we darken the area where the circle for F crosses over into the area that we shaded earlier. All the components found in sets D, E, F, or any combination of these sets are represented in this region.

The final Venn diagram should include three overlapping circles, with (D ⋃ E) ⋃ F shaded in the area where all three circles overlap.

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The perimeter of the given shape as represented in the task content is; 29 cm.

It follows from the task content that the perimeter of the given shape on the centimeter grid as required is to be determined.

Since each grid line has 1cm as it's length;

The perimeter of the shape is the sum of all side lengths of the shape;

Perimeter, P = 6+2+3+2+2+1+3+2+2+2+2+1

P = 29 cm

Hence, the perimeter of the shape is; 29 cm.

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Answer:

Jerry would still be in debt by 7100

Step-by-step explanation:

Just subtract 8500 from 15600

The option that's not equivalent to 20% will be D. 4/16.

A percentage is a value or ratio that may be stated as a fraction of 100. If we need to calculate a percentage of a number, we should divide it's entirety and then multiply it by 100.

It was illustrated that after counting and sorting them, she realized that 20% of the jelly beans were red

It should be noted that 20% is also 0.2, 1:5 and 10/50. On the other hand, 4/16 will be;

= 4/16 × 100

= 1/4 × 100

= 25%

In conclusion, the correct option is D.

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the denominator will be zero when. \(x=-2\)or \(x=-7.\) Therefore, the domain of the expression is all real numbers except \(x=-2\) and \(x=-7\).

In mathematics, factoring refers to the process of finding the factors of a given number or expression. Factors are numbers or expressions that can be multiplied together to obtain the original number or expression. For example, the factors of 12 are 1, 2, 3, 4, 6, and 12, because these are the numbers that can be multiplied in pairs to obtain 12 (e.g. 2 x 6 = 12).

In algebra, factoring involves breaking down an algebraic expression into simpler expressions that can be multiplied together. This is done by finding common factors or using techniques such as difference of squares, perfect squares, or grouping. Factoring is an important tool in algebra, as it can help simplify complex expressions and solve equations.

To simplify a rational expression, follow these steps:

Step 1: Factor both the numerator and denominator if possible. For example, in the expression you provided, the numerator can be factored as\((2x+5)(x+4)\)and the denominator can be factored as \((2x+15)(x+2)\).

Step 2: Cancel out any common factors in the numerator and denominator. In this case, both the numerator and denominator have a common factor of (2x+5), which can be cancelled out.

Step 3: Simplify the remaining expression. After cancelling out the common factor, the simplified expression becomes:

\((2x+5)(x+4) / (2x+15)(x+2) = (x+4) / (x+2)(2x+15)\)

Domain restrictions occur when a value of x makes the denominator equal to zero, because division by zero is undefined. In this case, the denominator will be zero when x=-2 or x=-7. Therefore, the domain of the expression is all real numbers except x=-2 and x=-7.

It is important to identify any domain restrictions before simplifying a rational expression to ensure that the final expression is valid for all values of x in its domain.

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The Propositions are resulting

(a) ∀x∃y(x = y²) is False

(b) ∀x∃y(x² = y) is True.

(c) ∃x∀y(xy = 0) is True.

(d) ∀x∃y(x + y = 1) is True.

(a) ∀x∃y(x = y²)

This proposition states that for every x, there exists a y such that x is equal to y². To determine the truth value, we need to check if this statement holds true for every value of x.

If we take any positive value for x, we can find a corresponding value of y that satisfies the equation.

For example, if x = 4, then y = 2 satisfies the equation since 4 = 2². Similarly, if x = 9, then y = 3 satisfies the equation since 9 = 3².

Therefore, the proposition (a) is false.

(b) ∀x∃y(x² = y)

For any given positive or negative value of x, we can find a corresponding value of y that satisfies the equation.

For example, if x = 4, then y = 2 satisfies the equation since 4² = 2. Similarly, if x = -4, then y = -2 satisfies the equation since (-4)² = -2.

Therefore, the proposition (b) is true.

(c) ∃x∀y(xy = 0)

The equation xy = 0 can only be satisfied if x = 0, regardless of the value of y. Therefore, there exists an x (x = 0) that makes the equation true for every y.

Therefore, the proposition (c) is true.

(d) ∀x∃y(x + y = 1)

To determine the truth value, we need to check if this statement holds true for every value of x.

If we take any value of x, we can find a corresponding value of y that satisfies the equation.

For example, if x = 2, then y = -1 satisfies the equation since 2 + (-1) = 1. Similarly, if x = 0, then y = 1 satisfies the equation since 0 + 1 = 1.

Therefore, the proposition (d) is true.

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The required probability is 3 √7 / 32.

Given, a square with sides of length 4 units and a red-shaded triangle with sides 3 units, 3 units and 4 units. We need to find the probability that a randomly selected point within the square falls in the red-shaded triangle.To find the probability, we need to divide the area of the red-shaded triangle by the area of the square. So, Area of square = 4 × 4 = 16 square units. Area of triangle = 1/2 × base × height.

Using Pythagorean theorem, the height of the triangle is found as: h = √(4² − 3²) = √7

The area of the triangle is: A = 1/2 × base × height= 1/2 × 3 × √7= 3/2 √7 square units. So, the probability that a randomly selected point within the square falls in the red-shaded triangle is:  P = Area of triangle/Area of square= (3/2 √7) / 16= 3 √7 / 32.

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Answer:

The answer is D. Cone

Step-by-step explanation:

Answer:

1. (x - 1) × (x + 3)

2. x = 3 and y = -2

Step-by-step explanation:

rewrite the equation:

y = 3x - 11; 2x + 3y = 0

solve y = 3x - 11 for the y:

y = 3x - 11

substitute 3x - 11 for y in 2x + 3y = 0;

2x + 3y = 0;

2x + 3y = 0

2x + 3 (3x - 11) = 0

11x - 33 = 0 (simplify both sides of the equation)

11x - 33 + 33 = 0 + 33 (add 33 to both sides)

11x = 33

11x/11 = 33/11 (divide both sides by 11)

x = 3

subtitute 3 for x in y = 3x - 11

y = 3x - 11

y = (3)×(3) - 11

y = -2  

I showed one equation because the other is self explanatory, hope this helps.

Answer:

together they are 124.5 milligrams

Step-by-step explanation:

together they are 124 + 0.5 = 124.5 milligrams

The 68-95-99.7 Rule Example

Figure 1 illustrates how to apply the 68-95-99.7 Rule to the distribution of IQ scores. In this example, the population mean is 100 and the standard deviation is 15. Based on the 68-95-99.7 Rule, approximately 68% of the individuals in the population have an IQ between 85 and 115.

Answer:

x = -3 2/3

have a great day

Answer:

x = -3 2/3

Step-by-step explanation:

The number of elements in the Q complement set, n(Q') is 7

From the question, we are to determine the number of elements that are in the given set.

To find n(Q'),

First, we will determine the elements in Q'

NOTE: Q' means Q complement, that is, the elements that are present in the universal set but not in Q

The universal set is

ξ = {numbers between 3 and 19}

That is,

ξ = {3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19}

From the given information,

Q = {3, 5, 6, 7, 9, 10, 12, 13, 17, 18}

Therefore,

Q' = {4, 8, 11, 14, 15, 16, 19}

The value of n(Q') is the number of elements in the q' set

That is,

n(Q') = 7

Hence, n(Q') = 7

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The equation in slope-point form is:

A. The change in "y" is represented by "y - y1". The function shifts "y1" units down.

B. The change in "x" is represented by "x -x1". The function shifts "x1" units right.

What is a Right Angle Triangle?

A Right Angle Triangle is a triangle where one of the angles is equal to 90 degrees.

To calculate the values using SOHCAHTOA

 SOHCAHTOA calculate the angles and sides of the right triangle, using trigonometric function sine, cosine, and tangent. There are two triangles in which the adjacent and opposite changes based on which angle is in question, the hypotenuse always stays the same.

Where Sin A = Opposite/ Hypotenuse

            Cos A = Adjacent / Hypotenuse

   And  Tan A = Opposite / Adjacent

For question 1,

If Opposite = PR

Adjacent = PQ

Hypotenuse = QR

Sin A = 14/50

Cos A = 48/50

Tan A = 14/48

For question 2,

If Opposite = PQ

Adjacent = PR

Hypotenuse = QR

Sin A = 48/50

Cos A = 14/50

Tan A = 48/14

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Answer:

Pretty sure its E sorry if I'm wrong I learned this like 2 years aho

A value of a that would make the expression 5 1/3 ÷ 4/a equivalent to a whole number include the following: C. 9.

In order to use the given expressions to determine the value of a (a-value) that makes the expression equivalent to a whole number, we would have to substitute the values of a (a-value or domain) into each of the expressions and then evaluate as follows;

First of all, we would re-write the mixed fraction as an improper fraction and then evaluate the given expression;

16/3 ÷ 4/a

16/3 × a/4

When a = 5, we have the following:

16/3 × a/4

16/3 × 5/4 = 20/3 (not a whole number).

When a = 7, we have the following:

16/3 × a/4

16/3 × 7/4 = 28/3 (not a whole number).

When a = 5, we have the following:

16/3 × a/4

16/3 × 9/4 = 36/3

36/3 = 12 (a whole number).

When a = 11, we have the following:

16/3 × a/4

16/3 × 11/4 = 44/3 (not a whole number).

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Complete Question:

Which value of a would make the expression 5 1/3 ÷ 4/a equivalent to a whole number?

5

7

9

11

Answer:

26000

Step-by-step explanation:

Chris' gross pay for the week after selling computer equipment worth $17,000 is $2,600.

The gross pay is the addition of the base pay and the sales commission.

The sales commission is graduated and computed as follows:

Chris' base pay = $300

Sales Commissions:

First $5,000 = 10%

Above $5,000 = 15%

Last week's sales = $17,000

10% Commission = $500 ($5,000 x 10%)

15% Commission = $1,800 ($17,000 - $5,000 x 15%)

Total Commission = $2,300

Gross pay = Base Pay + Commission

= $2,600 ($300 + $2,300)

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(a) f(x) =  \(log_2(x)\) is a logarithmic function

(b) g(x) = ∜x is a root function

(c) h(x) = \(2x^3/(1 - x^2)\) is a rational function

(d) u(t) = 1 - 1.1t + \(2.54t^2\) is a polynomial of degree 2

(e) v(t) = \(5^t\)is an exponential function

(f) w(θ) = sin θ \(cos^{2}\theta\) is a trigonometric function.

(a) f(x) = \(log_2(x)\) is a logarithmic function. Logarithmic functions have the logarithm of the independent variable as the output. Here, the logarithm base is 2.

(b) g(x) = ∜x is a root function. Root functions have the square root or higher roots of the independent variable as the output. Here, the root is a cube root.

(c) h(x) = \(2x^3/(1 - x^2)\) is a rational function. Rational functions are functions that are expressed as the quotient of two polynomials. Here, the numerator is a cubic polynomial and the denominator is a quadratic polynomial.

(d) u(t) = 1 - 1.1t + \(2.54t^2\) is a polynomial of degree 2. Polynomials are functions that are expressed as a sum of powers of the independent variable, with coefficients. The degree of a polynomial is the highest power of the independent variable.

(e) v(t) = \(5^t\) is an exponential function. Exponential functions have the independent variable as the exponent. Here, the base is 5.

(f) w(θ) = sin θ \(cos^{2}\theta\) is an algebraic function and a trigonometric function. Algebraic functions are functions that can be expressed using arithmetic operations and algebraic expressions. Trigonometric functions are functions that involve the ratios of the sides of a right triangle. Here, the function is a combination of sine and cosine functions.

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The complete question is -

Classify each function as a power function, root function, polynomial (state its degree), rational function, algebraic function, trigonometric function, exponential function, or logarithmic function.

(a) f(x) =  \(log_2(x)\)    

(b) g(x) = ∜x    

(c) h(x) = \(2x^3/(1 - x^2)\)    

(d) u(t) = 1 - 1.1t + \(2.54t^2\)                    

(e) v(t) = \(5^t\)    

(f) w(θ) = sin θ \(cos^{2}\theta\)

Answer:

Step-by-step explanation:

18 * 10 - 8 * 4    (remember pemdas)

180 - 32 =

148 cm²