please help me!

A scientist is comparing the bacteria population on two surfaces t days after it is cleaned with bleach.

Bacteria on the kitchen counter is initially measured at 5 and doubles every 3 days.

Bacteria on the stove is initially measured at 10 and doubles every 4 days.

1. After how many days will the bacteria population on both surfaces be equal?
2. What is the bacteria population when both surfaces have an equal population?

The value of x is –2, 1, or 3 only.

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

To find the roots by the graph we have to look at the graph at which at the x-axis the curve of the graph touches.

Here, the curve touches at -2, 1 and 3.

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Answer:

11/4 and 33/8

Step-by-step explanation:

Answer to 1:

\(\frac{x^3}{2y^25}\)

First thing you want to do is combine like terms on the bottom. Since it's multiplication, all you have to do is add the exponents. So for x you'd get x raised to the -9 power and for y you'd get 2y raised to the power of 7

Second thing is the numerator of the fraction. Since this is raising what is inside the paranthesis to a power, you must multiply this power by the powers of x and y, respectively. You should get x raised to the power of -6 and y raised to the power of -18

Here's where it gets complicated. to rationalize the problem, you must add parts from the numerator and denominator or vice versa. You cannot have any negative exponents anywhere in the fraction.  So that means for x you have to add 9 to the x on the top to cancel out the -6 and rationalize the remaining x's. You should end up with x^3.

For y, you work the opposite way. Since the negatives are only on the top, you simply add 18 to the bottom y's and it remains rationalized.

If done correctly this should come out to x^3/2y^25

Answer to 2:

(x^20y^12)/256

First thing you can do on this one is to cancel out the x^0s. Anything to the power of 0 equals one so only the coefficients will remain. Multiply those together and you'll get 4.

Next you will rationalize the ys. Add the bottom 3 to the top to cancel out the denominator and you're left with y^-3. Leave it like this for now.

Now is the difficult part. You must take everything that is inside the parenthesis to the power of -4. That includes the coefficients and the exponents. 4^-4 = 1/256. This means that you now must move the coefficients to the bottom. You should currently have y^-3/(256x^5).

Now take the exponents to the power using the same rules as question 1. -3*-4 = 12 and 5*-4 = -20. You should now have y^12/(256x^-20)

Lastly, we must rationalize the denominator. To do so, move the x^-20 to the numerator and make the exponent positive. After doing this, you have the answer: (x^20y^12)/256

Answer:

answer is 15 and second one i dont know yet sorry am doing scoo

Step-by-step explanation:

If the cost for 10 ounce of organic blueberry is $2. 70, the cost of 30 ounce of organic blueberry is represented by the equation x = 20y + 2.70 where y is the cost in dollars for one ounce of organic blueberry.

As x is the cost in dollar for 30 ounce of organic blueberry. For y is the cost in dollars for one ounce of organic blueberry, then

x = 30y + c

where c is the fixed cost

We know for 10 ounce of organic blueberry it costs $2.70. That is

2.70 = 10y + c

c = 2.70 - 10y

So x = 30y + 2.70 - 10y

x = 20y + 2.70

-- The question is incomplete, the complete question is as follows--

"The cost for 10 ounce of organic blueberry is $2. 70 which equation can be used to determine x the cost in dollars, for 30 ounces of organic blueberries.?"

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Answer:

x=3

Step-by-step explanation:

1. Rearrange terms

1 - 6x = -17

-6x + 1 = -17

2. Subtract 1 from both sides of the equation (we want to get rid of 1)

3. Simplify

In the end, you should get x=3.

Answer:

Its the second one

Step-by-step explanation:

Answer:

the 2nd one

Step-by-step explanation:

Answer:

The values are calculated with the help of table.

Step-by-step explanation:

We are given the following information in the question:

A table is shown showing trees on two different plots of land which are tested for disease.

     Tree:        1           2           3           4          5           6          7        

      Plot:         A          A           B           B         B           A          B

Disease:        Y          N           Y           Y          Y          N         N

We have to find:

Calculating from the table, we can fill the values as:

                                              Plot A                Plot B

Disease Present                        1                          3

Disease not Present                2                          1

The length of the race was 30 meters.

If you have an area A and a width w, you can calculate the length w using the formula h = A/w. The formula h = P/2w can be used to determine the length if you know the perimeter P and the width w.

Let's use "L" for the race's length and "t" for their running times. Ms must sprint L + 10 metres to tie Mr since she gives Mr a 10-meter head start.

The following equation can be created:

Ms distance = Mr distance + 10 meters

3t = 2t + 10

Simplifying this equation, we get:

t = 10

As a result, after 10 seconds, they were tied. We may enter "t" into either Ms. or Mr.'s distance formula to determine how long the race will be:

Ms distance = 3t = 3 × 10 = 30 meters

Mr distance = 2t + 10 = 2 × 10 + 10 = 30 meters

So, the length of the race was 30 meters.

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Answer:

A = 5

I hope you have an amazing day!

To show that cov(Xr - X, X) = 0 for r = 1, 2, ..., n, we need to demonstrate that the covariance between the differences of each individual observation and the sample mean, and the sample mean itself, is zero.

Let's begin by calculating the covariance using the definition:

cov(Xr - X, X) = E[(Xr - X)(X - E[X])]

Since X is the sample mean, we can rewrite it as:

X = (X1 + X2 + ... + Xn) / n

Now, let's expand the expression:

cov(Xr - X, X) = E[(Xr - X)(X - E[X])]

                = E[(Xr - X)(X - (X1 + X2 + ... + Xn) / n)]

Next, we distribute and simplify:

cov(Xr - X, X) = E[XrX - X^2 - (X1 + X2 + ... + Xn)X / n + X^2 / n]

Now, we can rearrange the terms:

cov(Xr - X, X) = E[XrX - (X1 + X2 + ... + Xn)X / n]

                = E[XrX] - E[(X1 + X2 + ... + Xn)X] / n

At this point, notice that Xr and X are independent since Xr is one of the observations in the sample, and X is a function of all the observations. Therefore, E[XrX] = E[Xr]E[X].

Also, we know that E[X1 + X2 + ... + Xn] = E[X1] + E[X2] + ... + E[Xn] = nE[X].

Plugging these values back into the expression:

cov(Xr - X, X) = E[Xr]E[X] - (nE[X])E[X] / n

                = E[Xr]E[X] - E[X]^2

Now, let's simplify further:

cov(Xr - X, X) = E[Xr]E[X] - E[X]^2

                = E[Xr] * nE[Xr] / n - (E[Xr])^2

                = (E[Xr])^2 - (E[Xr])^2

                = 0

Hence, we have shown that cov(Xr - X, X) = 0 for r = 1, 2, ..., n.

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The function that models the horizontal displacement as a function of time in seconds is y = 5cos(2π/3 x)

The given parameters are:

Start by calculating the amplitude, A using:

A = h/2

This gives

A = 10/2

A = 5

Next, we calculate the period using:

B = π/t

This gives

B = π/1.5

Evaluate

B = 2π/3

The pendulum is at the middle.

So, it has no vertical displacement

The function is then represented as:

y = Acos(Bx)

This gives

y = 5cos(2π/3 x)

Hence, the function that models the horizontal displacement as a function of time in seconds is y = 5cos(2π/3 x)

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a) The number of page faults for the First In First Out (FIFO), Least Recently Used (LRU), and Optimal page replacement (OPT) algorithms with 4 frames in physical memory are compared for the given page reference string. , b) The effect on the page fault rate is discussed when the number of frames is reduced to 3 frames in each algorithm.

a) To compare the number of page faults for the FIFO, LRU, and OPT algorithms with 4 frames, we simulate each algorithm using the given page reference string. FIFO replaces the oldest page in memory, LRU replaces the least recently used page, and OPT replaces the page that will not be used for the longest time. By counting the number of page faults in each algorithm, we can determine which algorithm performs better in terms of minimizing page faults.

b) When the number of frames is reduced to 3 in each algorithm, the page fault rate is expected to increase. With fewer frames available, the algorithms have less space to keep the frequently accessed pages in memory, leading to more page faults. The reduction in frames restricts the algorithms' ability to retain the necessary pages, causing more page replacements and an overall higher page fault rate. The specific impact on each algorithm may vary, but in general, reducing the number of frames decreases the efficiency of the page replacement algorithms and results in a higher rate of page faults.

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Answer:

The slope of the model represents the amount of snow(in inches) added to the ground per hour

the y-intercept represents the beginning amount of snow already on the ground

Step-by-step explanation:

The value of x that makes this equation (X-2)/2= (X+4)/4  to be true is 8.

An equation ca be described as the mathematical terms which can contains different digits as well we a as alphabet and it can simplified so that a particular expression or term can be found, in the given equation we were told to find the value of x by simplify the equation which is done below.

(X-2)/2= (X+4)/4

Then if we cross multiply we will have

(4x - 8) =(2x+8)

then we can simplify further and collect the like terms which is

2x=16

x=8

There, the correct option is B

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The interval of time between Beacon frame transmissions is an important parameter for client devices to synchronize their clocks and to determine the optimal time to listen for the next Beacon frame.

The interval of time between the transmissions of the beacon frames is contained in the Beacon frame itself in the "Beacon Interval" field. This field is a 2-byte (16-bit) value that specifies the number of Time Units (TUs) between the transmissions of consecutive beacon frames. One TU is equivalent to 1024 microseconds (µs).

For example, if the Beacon Interval field in a Beacon frame is set to a value of 100, it means that the access point will transmit a Beacon frame every 100 TUs or 102,400 µs (100 x 1024 µs). This interval of time is used by the wireless client devices to synchronize their clocks and to determine the optimal time to listen for the next Beacon frame.

The Beacon frame is part of the management frame in the IEEE 802.11 wireless LAN standard and is transmitted periodically by an access point to advertise its presence and provide information about the network to the wireless client devices.

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This can be done by finding the CPI or another price index for the same period. Once you have the GDP deflator, you can use the formula above to calculate the real GDP.

If you only know the nominal GDP, you cannot determine the real GDP. In order to determine the real GDP, you need to take into account inflation. This is done by adjusting the nominal GDP for inflation using a price index, such as the Consumer Price Index (CPI).The formula for calculating real GDP is:Real GDP = Nominal GDP / GDP DeflatorThe GDP deflator is a measure of inflation that takes into account changes in the prices of all goods and services produced in an economy. It is calculated by dividing nominal GDP by real GDP and multiplying by 100. This gives us a ratio of the current price level to the base year price level.

The base year price level is assigned a value of 100.Using this formula, we can see that if we know the nominal GDP and the GDP deflator, we can calculate the real GDP. For example, if the nominal GDP is $10 trillion and the GDP deflator is 120, the real GDP would be:Real GDP = $10 trillion / 1.2 = $8.33 trillionTherefore, in order to determine the real GDP if you only know the nominal GDP, you need to obtain the GDP deflator.

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Answer:

false. example: 6 x 10. 6 is an integer, but 6 x 10 = 60, not 0. hope this helps

Step-by-step explanation:

- Zombie

Among the given equations, only y = 1/15x represents a direct variation. The other equations do not represent direct variations.

In a direct variation, the equation takes the form y = kx, where k is a constant. Let's analyze each equation to determine if it represents a direct variation.

1. y = 4x + 1:

This equation is not in the form of y = kx. It includes a constant term (+1) in addition to the multiple of x, which indicates that it does not represent a direct variation. Therefore, the answer is "No."

2. y + 7.5x:

This equation does not have an equal sign and is not in the form of y = kx. It is an expression rather than an equation. Hence, it does not represent a direct variation. The answer is "No."

3. y = 1/15x:

This equation is in the form of y = kx, where k = 1/15. It satisfies the criteria for a direct variation, as the dependent variable y is directly proportional to the independent variable x. Thus, the answer is "Yes."

4. y = 6/x:

This equation does not have the form of y = kx. The variable x is in the denominator, indicating an inverse relationship rather than a direct variation. Hence, the answer is "No."

In conclusion, only the equation y = 1/15x represents a direct variation among the given equations.

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Answer: 20cm

Step-by-step explanation:

First, add up the 3 sides you already know.

6+6+3 = 15.

Now you have to find the length of the semi circle which is half the circumference of a circle.

The equation for the circumference is 2πr.

The diameter of the circle is 3 meaning the radius is 1.5.

Plug this into the equation.

2 * π * 1.5 and you get approximately 9.42
Since it is only have a circle, you have to divide this by 2 to get half the circumference.

When you do this, you get 4.71

Add up 15 and 4.71 and you get 19.71 which rounds up to 20.

Answer:

31-12=-2m -m

19=m

or

m=19

Step-by-step explanation:

Answer:

43.98

Step-by-step explanation:

did some quick maths

c=2

\(c = 2 \times \pi \times r\)

The quadratic equation for the area of the new park is (x+30)(x+40) = 1824.

Quadratic equation for the area of the new park is:

(x+30)(x+40) = 1824

The equation in Standard Form is:

x^2 + 70x - 384 = 0

The equation in Factored Form is:

(x - 8)(x + 78) = 0

The solutions are:

x = -78 or x = 8

The negative solution is not valid in this context, so x = 8.

The dimensions of the new park are 48 feet by 38 feet.

The area of the new park is:

48 * 38 = 1824 square feet (as required)

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Answer:

y =2

Step-by-step explanation:

Inverse variation is of the form

xy = k

3*6 = k

18 = k

xy = 18

Now when x = 9, find y

9*y = 18

Divide by 9

y = 18/9

y =2

When x =9, y =2

Answer:

y = 2

Step-by-step explanation:

y = 6   ⇔  x= 3

y = ?   ⇔   x = 9

y = 6*3/9

y = 2

Answer:

19

Step-by-step explanation:

If it takes 5 cups to make each cake Henry can make 19 cakes.

Answer:

We're given a least-squares regression equation that we can use to predict weight (in kilograms) from a given length (in centimeters). The question asks to predict the weight of a fish that is 70cm long, so let's plug in 70 for "length" and solve for the predicted weight: logweight = 3.08  (log length) -5.07

(logweight) 3.08 (log 70) - 5.07

(logweight) ≈ 3.08 (1.84) - 5.07

log weight ≈ 0.613

Next, we use the fact that these are base 10 logarithms and the definition of a logarithm to solve for the predicted weight:

log₁₀ (weight) ≈ 0.613

Taking logarithms on both sides

weight ≈ 10₀.₆₁₃

weight ≈ 4.1

According to this model, the predicted weight for a 70 cm long Florida bass is about 4.1kg.

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The differential equation that models the rate of change of the sum S(t) with respect to time t is given by dS/dt = k * e^(0.05t).  The formula for the sum S(t) is S(t) = (k/0.05) * e^(0.05t) + C. It is not possible to determine the exact value of k that will result in $3,500,000 in 41 years.

(a) The differential equation that models the rate of change of the sum S(t) with respect to time t is given by dS/dt = k * e^(0.05t), where k represents the annual investment amount and e^(0.05t) represents the continuous compounding growth factor.

(b) To determine a formula for the sum S(t), we need to integrate the rate of change equation from part (a). Integrating both sides with respect to t, we have ∫dS = ∫k * e^(0.05t) dt. Integrating the left side gives S(t), and integrating the right side gives (k/0.05) * e^(0.05t) + C, where C is the constant of integration. Thus, the formula for the sum S(t) is S(t) = (k/0.05) * e^(0.05t) + C.

(c) In order to find the value of k that will provide $3,500,000 in 41 years, we can use the formula derived in part (b) and substitute the given values. The equation becomes 3500000 = (k/0.05) * e^(0.05*41) + C. To determine the value of k, we need to know the constant of integration C or have additional information about the initial conditions. Without this information, it is not possible to determine the exact value of k that will result in $3,500,000 in 41 years. However, with the given equation, you can solve for the value of k by rearranging the equation and solving numerically using methods such as iteration or numerical approximation techniques.

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