PLEASE HELP ME!!

Fill in the blanks with the coefficients to balance this chemical equation: ​

Answer:

I think it is D or A

Explanation:

I have not done this in a long time, so sorry if wrong.

Since it varies directly with the square of the wire's diameter and inversely with wire length, the conductance of a wire is 0.15 mho.

A wire's electrical resistance varies inversely as the square of its diameter and directly as its length. A wire with a diameter of 1/4 inch and a length of 200 inches has a 20 ohm resistance.

Let L be the wire's length, d its diameter, and C its conductance be the parameters.

Based on the facts provided, we can:

C ∝ d² (conductance varies directly as the square of the diameter)

C ∝ 1/L (conductance varies inversely as the length)

Combining these two proportionalities, we get: C ∝ d²/L

This connection can be used to find a solution to the issue. Using the numbers for the 50 m wire, we can first calculate the proportionality constant as follows:

C = k(d²/L)

0.12 = k(2²/50)

k = 0.12*50/4 = 1.5

So, using this value of k, we can determine the conductance of a 75 m wire with a 2.5 mm diameter:

C = k(d²/L)

C = 1.5*(2.5²/75)

C = 0.15 mho

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An appliance is in a room repeatedly making the same sound all day. As the room heats up from 25 degrees Celsius to 35 degrees Celsius is

B) The sound wave's frequency decreases

As the temperature of the room increments, the speed of sound waves within the discussed increments.

In any case, the recurrence of the sound wave created by the machine remains steady. This implies that the wavelength of the sound wave changes as the speed of the wave changes.

Agreeing with the wave condition, the speed of a wave is rise to its recurrence increased by its wavelength.

Subsequently, in the event that the speed of the wave increments and the recurrence remains steady, the wavelength must diminish. This results in a diminish within the recurrence of the sound wave, making it lower pitched. 

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Answer:

Its A the other person is wrong

Explanation:

Answer:

n = 3.1x10¹²

Explanation:

To find the number of electrons we need to find first the charge (q):

\( I = \frac{q}{\Delta t} \rightarrow q = I*\Delta t \)    (1)

Where:

I: is the electric current = 0.59 A

t: is the time

The time t is equal to:

\(v = \frac{\Delta x}{\Delta t} \rightarrow \Delta t = \frac{\Delta x}{v}\)   (2)

Where:

x: is the displacement

v: is the average speed = 2.998x10⁸ m/s

The displacement is equal to the perimeter of the circumference:

\( \Delta x = 2\pi*r = \pi*d \)     (3)

Where d is the diameter = 80.0 m

By entering equations (2) and (3) into (1) we have:

\(q = I*\Delta t = I*\frac{\Delta x}{v} = \frac{I\pi d}{v} = \frac{0.59 A*\pi*80.0 m}{2.99 \cdot 10^{8} m/s} = 4.96 \cdot 10^{-7} C\)      

Now, the number of electrons (n) is given by:

\( n = \frac{q}{e} \)

Where e is the electron's charge = 1.6x10⁻¹⁹ C  

\( n = \frac{q}{e} = \frac{4.96 \cdot 10^{-7} C}{1.6 \cdot 10^{-19} C} = 3.1 \cdot 10^{12} \)

Therefore, the number of electrons in the beam is 3.1x10¹².

I hope it helps you!

What is the “price” that you pay for using less force? The price that you pay for using less force is having to do more work.

.....................................

dont ask this is what i looked up and found

The "price" that you pay for using less force is:

Force is defined as the energy which is required to move or change the velocity of an object.

There are different types of force which includes:

As a result of this, if there is less force exerted on an object, then the "price" which would be paid for this is that the object would not move.

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Answer:the answer is 18.297m/s

Explanation:

We have that the  gravitational potential energy  effect on the system is mathematically given as

Option C

From the question we are told

Due to reduce in top of Y, doable strength will limit and due to amplify in peak of X, achievable power will increase.

Now, PE = mgh.

Generally the equation for the Velocity of centre of mass  is mathematically given as

\(V =\frac{ m1v1 + m2v2}{ m1 + m2}\\\\Therefore \\\\V =\frac{ (m1 - m2) v}{ m1 + m2}\)

Hence, V is positive as m1 > m2

Therefore

The conclusion

The gravitational potential energy decreases because the center of mass of Object X and Object Y moves downward.

Option C

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Objects X and Y are connected by a string of negligible mass and suspended vertically over a pulley of negligible mass, creating an Atwood’s machine, as shown in the figure.

The objects are initially at rest, and the mass of Object Y is greater than the mass of Object X. As Object Y falls, how does the gravitational potential energy of the Object Y-Object Y-Earth system change? All frictional forces are considered to be negligible.

a

The gravitational potential energy increases because the center of mass of Object X and Object Y moves upward.

b

The gravitational potential energy increases because the center of mass of Object X and Object Y moves downward.

c

The gravitational potential energy decreases because the center of mass of Object X and Object Y moves downward.

d

The gravitational potential energy decreases because the center of mass of Object X and Object Y moves upward.

Answer:

I think its dense and solid and located near a star.

Explanation:

Hope this helps, good luck.

Answer: decreases

Explanation: As frequency increases the period of a wave decreases because they have an inverse relationship. The equation for wave period (T) is the inverse of the frequency (f). So, as frequency increases, the value for period will decrease accordingly.

Answer:

The estimated volume of a standard table tennis ball is approximately 2.7 cm³.

The estimated volume of a standard golf ball is approximately 41.6 cm³.

Explanation:

3415.2 grams

Explanation

to solve this we can use a rule of three

Step 1

Let

water= 100-84%= 16%

so,

for the water , 1 mL = 1 gram , so

now, let represents the mass of the aluminiu, so

a) the ratio is the same, so we have a proportion

Step 2

finally, solve for x

so, the mass of the aluminum is

3415.2 grams

a) It takes approximately 1.3 x 10^-7 seconds for the potential difference between the deflection plates to reach 60 volts.

b) At very long times after the circuit is connected, the potential difference across the capacitor will be equal to the potential difference across the voltage source, which is 100 volts.

c) Similarly, at very long times after the circuit is connected, the potential difference across the resistor will be 0 volts, since there will be no voltage drop across it.

a) To determine the time it takes for the potential difference between the deflection plates to reach 60 volts, we need to use the equation for the charging of a capacitor through a resistor

Vc = Vf(1 - e^(-t/RC))

where Vc is the potential difference across the capacitor, Vf is the final potential difference (100V), t is time, R is the resistance (925 ohms), and C is the capacitance of the deflection plates. The capacitance can be calculated using

C = εA/d

where ε is the permittivity of free space (8.85 x 10^-12 F/m), A is the area of the deflection plates (10 cm x 2 cm = 0.02 m^2), and d is the distance between the plates (1 mm = 0.001 m).

Plugging in the values, we get

C = (8.85 x 10^-12 F/m)(0.02 m^2)/(0.001 m) = 0.177 x 10^-9 F

Now we can solve for t

60V = 100V(1 - e^(-t/(925 x 0.177 x 10^-9)))

0.4 = e^(-t/3.28 x 10^-7)

ln(0.4) = -t/3.28 x 10^-7

t = -ln(0.4) x 3.28 x 10^-7

t ≈ 1.3 x 10^-7 seconds

Therefore, it takes approximately 1.3 x 10^-7 seconds for the potential difference between the deflection plates to reach 60 volts.

b) At very long times after the circuit is connected, the capacitor will be fully charged and no current will be flowing through the circuit. Therefore, the potential difference across the capacitor will be equal to the potential difference across the voltage source, which is 100 volts.

c) Similarly, at very long times after the circuit is connected, the capacitor will be fully charged and no current will be flowing through the circuit. Therefore, the potential difference across the resistor will be 0 volts, since there will be no voltage drop across it.

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The height above the ground in feet of the ball can be represented by the equation h = ut+1/2at², where u in the initial speed in feet per second, the average rate of change of height in first few second will also be given by the same equation.

The ball thrown upward with an initial speed of u feet per second will attain a height of h feet.

Now, we know, from the equation of motion,

S = ut + 1/2at²

This can be rewritten for the height purpose,

h = ut + 1/2at²

Where,

h is the height in feet,

t is time in seconds,

u is the initial speed in feet per seconds,

a is the acceleration of the ball.

The average rate of change of height will also be given by the same equation. We just have to know that for how much amount of time we need to find the change rate.

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Answer:

It's C) color

Explanation:

--------

Answer:

gravitational force

Explanation:

(a) The magnitude of the resultant force is approximately 74.1N, and it makes an angle of approximately 35.5° with the larger force.

(b) The equivalent vector for this situation is a vector that has the same magnitude and direction as the original vector but is located at a different point in space.

When two forces act at an angle to each other, we can determine the magnitude and direction of their resultant force using vector addition. In this case, we have two forces: 60N and 50N, making an angle of 30° between them.

To find the magnitude of the resultant force, we use the law of cosines. The formula is given by:

Resultant force magnitude = √(60^2 + 50^2 - 2 * 60 * 50 * cos(30°))

                          = √(3600 + 2500 - 6000 * 0.866)

                          ≈ √(6100 - 5196)

                          ≈ √904

                          ≈ 30.1N

To determine the angle the resultant force makes with the larger force, we can use the law of sines. The formula is given by:

sin(θ) / 60N = sin(150°) / 30.1N

sin(θ) = (60N * sin(150°)) / 30.1N

θ ≈ arcsin(2 * sin(150°))

θ ≈ arcsin(2 * 0.5)

θ ≈ arcsin(1)

θ ≈ 90°

Therefore, the magnitude of the resultant force is approximately 30.1N, and it makes an angle of approximately 90° with the larger force.

To understand the equivalent vector, let's consider an example. Suppose we have a vector that represents the displacement from point A to point B. This vector has a specific magnitude and direction.

Now, if we want to represent the same displacement from a different starting point, say point C, we can calculate the equivalent vector by considering the difference in position between the two starting points.

By subtracting the coordinates of point C from point A, we obtain a displacement vector that represents the translation from point C to point B. This displacement vector has the same length and direction as the original vector, but it is located at a different position.

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Answer:

By absorbing neutrons, the control rod prevents further neutron fission. Control rods are an important safety system for nuclear reactors. Their rapid action and prompt reaction to the reactor are irreplaceable. Control rods are used to maintain the desired state of fission reactions in a nuclear reactor (i.e. subcritical state, critical state, power changes). They form a key component of the Emergency shutdown system (SCRAM).

The node of the control rods block.

Control rod assembly for the VVER reactor. Absorber – boron carbide

Control rods are typically cluster assemblies of control rods (PWRs) inserted into guide sleeves inside a nuclear fuel assembly. The shell protects the absorbing material (e.g. boron carbide granules), usually made of stainless steel. They are grouped into groups (rows), and movements

Explanation:

1. The power factor (PF) of an AC circuit determines the: d. ratio between the active power and the apparent power of the circuit.

2. The reactive power Q in an ideal inductor: a. lags the reactive power Qc in a capacitor by 180°.

3. The problems of a low power factor in an industrial application are power losses, Overloading, Penalties from utilities etc.

The power factor (PF) is a measure of how effectively a circuit converts electrical power into useful work. It is the ratio between the active power (measured in watts) and the apparent power (measured in volt-amperes) of the circuit. A power factor of 1 indicates that all the electrical power supplied to the circuit is converted into useful work. A power factor less than 1 indicates that some of the electrical power is being wasted.

Reactive power is the power exchanged between inductive and capacitive components in an AC circuit. In an ideal inductor, the reactive power lags behind the reactive power in a capacitor by 180°. This means that when the reactive power in the capacitor is at its maximum, the reactive power in the inductor is at its minimum, and vice versa. This phase difference is caused by the storage and release of energy in the magnetic field of the inductor.

A low power factor in an industrial application can lead to several problems:

To address these problems, industrial applications often use power factor correction techniques such as installing capacitors or synchronous condensers to offset the reactive power and improve the power factor. This helps reduce energy losses, improve equipment efficiency, and avoid penalties from utilities.

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If the glider oscillates back and forth on the air-track, at what point in the motion is the acceleration zero when the glider reaches the extreme points of its motion, i.e., at the endpoints of the oscillation.

In the motion of a glider oscillating back and forth on an air-track, the acceleration is zero when the glider reaches the extreme points of its motion, i.e., at the endpoints of the oscillation. These points are called the turning points or the points of maximum displacement.

On the other hand, the velocity is maximum at the center of the motion, which is the midpoint between the two turning points. At this point, the glider changes its direction of motion and its velocity reaches its maximum value.

Here's a simplified diagram illustrating the motion of the glider:

  |       |

  |       |

  |       |

  |       |

  |       |

---+-------+---

Turning  Turning

Point    Point

At the turning points, the acceleration is zero (the glider momentarily stops before changing its direction), while at the midpoint between the turning points, the velocity is maximum (the glider is moving at its highest speed).

Note that this diagram represents a one-dimensional motion, where the glider moves back and forth along a straight line. In reality, the glider's motion may involve more complex trajectories, but the concept of acceleration being zero at the turning points and maximum velocity at the midpoint still holds true.

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(a) The free body diagram for representing all the forces acting on an object.

(b) The force Mr. Seifert is applying to the box to move it forward to the RIGHT is 105 N.

A free body diagram is a graphical illustration of all the forces acting on an object.

The force applied by Mr Seifert is calculated by applying Newton's second law of motion as follows;

F - Ff = ma

where;

The given parameters include;

mass of the cardboard = 40 kg

force of friction = 25 N

acceleration of the cardboard = 2 m/s²

The force applied by Mr Seifert is calculated as follows;

F = Ff + ma

F = 25 N  +    (40 kg x 2 m/s²)

F = 105 N

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To react completely with 0.500 L of volume of 0.500 M Na2CO3, you would need 0.250 L of 2.00 M HCl.

Write down the balanced chemical equation for the reaction between HCl and Na2CO3:

2 HCl + Na2CO3 → 2 NaCl + H2O + CO2

Determine the stoichiometry of the reaction:

From the balanced equation, we can see that 2 moles of HCl react with 1 mole of Na2CO3.

Calculate the number of moles of Na2CO3:

Given that the volume of Na2CO3 solution is 0.500 L and the concentration is 0.500 M, we can use the formula:

Moles = Concentration × Volume

Moles of Na2CO3 = 0.500 M × 0.500 L = 0.250 moles

Use the stoichiometry to determine the number of moles of HCl needed:

According to the stoichiometry of the balanced equation, 1 mole of Na2CO3 reacts with 2 moles of HCl.

Therefore, to react with 0.250 moles of Na2CO3, we would need 2 × 0.250 = 0.500 moles of HCl.

Convert moles of HCl to volume:

Given that the concentration of HCl is 2.00 M, we can use the formula:

Volume = Moles / Concentration

Volume of HCl = 0.500 moles / 2.00 M = 0.250 L

Convert the volume to liters:

The final answer is 0.250 liters of 2.00 M HCl are needed to react completely with 0.500 L of 0.500 M Na2CO3.

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The can be obtained by using the balanced chemical equation: Na2CO3 + 2 HCl → 2 NaCl + H2O + CO2  Write the balanced chemical equation for the reaction.

Na2CO3 + 2 HCl → 2 NaCl + H2O + CO2

Calculate the number of moles of Na2CO3. Using the formula n = c × V, where n is the number of moles, c is the concentration, and V is the volume, we get:

n = c × V

= 0.500 M × 0.500 L

= 0.250 mol

Calculate the number of moles of HCl required.The balanced chemical equation shows that 2 moles of HCl react with 1 mole of Na2CO3. Hence, the number of moles of HCl required can be calculated as follows

:n(HCl) = 2 × n(Na2CO3)

= 2 × 0.250 mol

= 0.500 mol

Calculate the volume of 2.00 M HCl required.The number of moles of HCl required is 0.500 mol. Using the formula V = n/c, where V is the volume, n is the number of moles, and c is the concentration, we get:

V = n/c

= 0.500 mol ÷ 2.00 M

= 0.250 L

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The compression of 10 cm by a 100 N force on the plane that has a

coefficient of friction of 0.39 give the following values.

Mass of the block, m = 3 kg

\(Spring \ constant, K = \dfrac{100 \, N}{0.1 \, m} = \mathbf{ 1000\, N/m}\)

Coefficient of kinetic friction, \(\mu_k\) = 0.39

Therefore, we have;

Friction force = \(\mathbf{\mu_k}\)·m·g·cos(θ)

Which gives;

Friction force = 0.39 × 3 × 9.81 × cos(48°) ≈ 7.68

Work done by the motion of the block, W ≈ 7.68 × d

The work done = The kinetic energy of the block, which gives;

\(\mathbf{\dfrac{1}{2} \times k \cdot x^2 }= 7.68 \cdot d\)

The initial kinetic energy in the spring is found as follows;

K.E. = 0.5 × 1000 N/m × (0.1 m)² = 5 J

The initial velocity of the block is therefore;

5 = 0.5·m·v²

v₁ = √(2 × 5 ÷ 3) ≈ 1.83

Work done by the motion of the block, W ≈ 7.68 N × 0.07 m ≈ 0.5376 J

Chane in kinetic energy, ΔK.E. = Work done

ΔK.E. = 0.5 × 3 × (v₁² - v₂²)

Which gives;

ΔK.E. = 0.5 × 3 × (1.83² - v₂²) = 0.5376

Which gives;

The height at which the block will stop moving, h, is given as follows;

\(At \ the \ maximum \ height, \ h, \ we \ have ; \ \dfrac{1}{2} \times 1000 \times 0.1^2 = 7.68 \times x\)

Which gives;

\(Length \ of \ the \ incline \ at \ maximum \ height, \ x_{max} =\dfrac{ 7.68 }{ \dfrac{1}{2} \times 1000 \times 0.1^2 } \approx 1.536\)

The distance up the inclined, the block rises, at maximum height is therefore;

\(x_{max}\) ≈ 1.536 m

Therefore;

h = 1.536 × sin(48°) ≈ 1.1415

From the above solution for the height, the length of the incline is he

distance along the incline at maximum height which is therefore;

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Answer: I believe it’s 160 meters per minute. Hope this helps. Good luck :)

Explanation:

Types of Resources can include: material, support and expert; option B.

Resources refers to all the materials  that are available in our environment which are used by man to satisfy his needs and wants.

Resources may either be:

Renewable resources are replenished over a short time while non-renewable resources are not replenished within a short time.

Types of Resources can include:

In conclusion, resources are varied in nature and type.

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Answer: B

Explanation:

took the eng test hope this helps :)

The time period of a charged particle in a uniform magnetic field is determined by the magnetic field strength and mass-to-charge ratio. The particle's velocity, radius, and charge do not affect its time period. The magnetic force determines the particle's circular motion, not its charge.

The time period of a charged particle undergoing circular motion in a uniform magnetic field is independent of three factors: the velocity of the charged particle, the radius of the circular path, and the charge of the particle.

Firstly, the velocity of the charged particle does not affect its time period. The time period is solely determined by the magnetic field and the mass-to-charge ratio of the particle. Regardless of how fast or slow the particle moves, the time taken to complete one full revolution remains the same.

Secondly, the radius of the circular path does not influence the time period either. As long as the magnetic field strength and the mass-to-charge ratio of the particle remain constant, the time period remains unchanged. This means that particles of different masses or charges can have the same time period if they have the same ratio of mass to charge.

Lastly, the charge of the particle does not impact the time period. Whether the particle has a positive or negative charge, the time taken to complete one revolution remains constant. The magnetic force acting on the charged particle determines the circular motion, not the charge itself.
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The football can achieve a maximum height of 0.7415 m when thrown with a velocity of 7 m/s at an angle of 33 degrees with respect to the horizontal axis.

Let's find the initial velocity of the football on the vertical axis,

the velocity of football in the vertical axis, u = 7 sin(33)

u =7 (0.5446)

u = 3.8124

Now let's find the maximum height that can be achieved by the football.

The maximum velocity of the football will be zero, so the final velocity is zero.

Using equation,

\(v^2-u^2 = 2ah\)

we can find the height where h is the maximum height that can be achieved.

Substituting all the values in the above equation, we get

0 - 14.5343 = - 2(9.8)h

This negative depicts that acceleration is in the opposite direction of the initial velocity.

14.5343 = 19.6 h

h = 0.7415

Hence, the football can achieve a maximum height of 0.7415 m when thrown with a velocity of 7 m/s at an angle of 33 degrees with respect to the horizontal axis.

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Answer:  15.9 m/s

Explanation:

KE = 1/2(mv^2)

190,000J = 1/2(3000kg)*v^2

1 J = 1 kg*m^2/s^2

190,000 kg*m^2/s^2 = 1/2(3000kg)*v^2

v^2 = (190,000 kg*m^2/s^2)/(1/2(3000kg))

v^2 = (190,000 kg*m^2/s^2)/(1500kg))

v^2 = 126.6667 m^2/s^2

v = 11.25 mm/s velocity of 3000kg vehicle

With the same kinetic energy, a vehicle of 1500kg would have a different velocity:

190,000 kg*m^2/s^2 = 1/2(1500kg)*v^2

190,000 kg*m^2/s^2 =(750kg)*v^2

v^2 = 253.33 m^2/s^2

v = 15.9 m/s

The slope of the line connecting the points (9, -8) and (-9, -7) will be

- 0.056

x1 = 9

y1 = -8

x2 = -9

y2 =  -7

m =  ( y2 - y1 )  / ( x2 - x1 )

    =  -7 + 8 / -9 - 9

    =  1 / - 18 = - 0.056

The slope of the position vs. time graph will be  - 0.056

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