4. The box plot that represents the data is: D. box plot D.
5. The range for the data set is 30.
The interquartile range (IQR) for the data set is 28.
How to complete the five number summary of a data set?Based on the information provided about the number of dogs, we would use a graphical method (box plot) to determine the five-number summary for the given data set as follows:
Minimum (Min) = 30.First quartile (Q₁) = 39.5.Median (Med) = 53.5.Third quartile (Q₃) = 67.5.Maximum (Max) = 80.Question 5:
In Mathematics, the range of a data set can be calculated as follows;
Range = Highest number - Lowest number
Range = 80 - 50
Range = 30.
Mathematically, interquartile range (IQR) of a data set is typically calculated as the difference between the first quartile (Q₁) and third quartile (Q₃):
Interquartile range (IQR) of data set = Q₃ - Q₁
Interquartile range (IQR) of data set = 67.5 - 39.5
Interquartile range (IQR) of data set = 28.
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The percentage discount at a store is determined
using the table below.
Sale Discounts
Total Purchases
less than $50
$50 to $100
over $100
Discount
25%
30%
35%
Shamika bought 3 skirts that cost $25 each before the discount. What was her total after thediscount?
A. $45.00
B. $48.75
C. $52.50
D. $56.25
Answer:
The answer is C and please give me brainliet And a like!
Where the above parameters are given, Shamika's total after the discount is $56.25. (Option D)
How to compute the above resultAccording to the table, if the total purchases are less than $50, the discount is 25%.
Shamika bought 3 skirts at $25 each, so her total purchase amount is 3 * $25 = $75.
Since $75 is less than $50, she qualifies for a 25% discount.
To calculate the discount, we multiply the total purchase amount by the discount rate -
Discount = 25% of $75 = (25/100) * $75 = $18.75
To find her total after the discount, we subtract the discount from the total purchase amount -
Total after discount = Total purchase amount - Discount
Total after discount = $75 - $18.75 = $56.25
Therefore, Shamika's total after the discount is $56.25. (Option D)
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Let u=In(x) and v=ln(y), for x>0 and y>0.. Write In (x³ Wy) in terms of u and v. Find the domain, the x-intercept and asymptotes. Then sketch the graph for f(x)=In(x-3).
To find ln(x³y) in terms of u and v, we can use the properties of logarithms. ln(x³y) can be rewritten as ln(x³) + ln(y), and using the property ln(a^b) = bˣ ln(a), we have 3ln(x) + ln(y) = 3u + v.
How can ln(x³y) be written in terms of u and v, where u = ln(x) and v = ln(y)?To find ln(x³y) in terms of u and v, we can use the properties of logarithms. ln(x³y) can be rewritten as ln(x³) + ln(y), and using the property ln(a^b) = bˣ ln(a), we have 3ln(x) + ln(y) = 3u + v.
The domain of the function f(x) = ln(x-3) is x > 3, since the natural logarithm is undefined for non-positive values. The x-intercept occurs when f(x) = 0, so ln(x-3) = 0, which implies x - 3 = 1. Solving for x gives x = 4 as the x-intercept.
There are no vertical asymptotes for the function f(x) = ln(x-3) since the natural logarithm is defined for all positive values. However, the graph approaches negative infinity as x approaches 3 from the right, indicating a vertical asymptote at x = 3.
To sketch the graph of f(x) = ln(x-3), we start with the x-intercept at (4, 0). We can plot a few more points by choosing values of x greater than 4 and evaluating f(x) using a calculator.
As x approaches 3 from the right, the graph approaches the vertical asymptote at x = 3. The graph will have a horizontal shape, increasing slowly as x increases. Remember to label the axes and indicate the asymptote on the graph.
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The expression 17n+11 represents the perimeter of the triangle. What is the length of the third side? Please Answer as soon as posable. Thank you.
Answer:the answer is 8n hope that helps!
One fourth of a Number decreased by three is at least two.
Answer:
100
Step-by-step explanation:
1/4 of 100 is 25. 25-3=22, which is at least 2.
A furniture store sold 33 tables for every 77 chairs last week. Assuming the ratio remains the same, how many tables were sold if 49 chairs were sold this week?
Answer:
21 tables
Step-by-step explanation:
First, let’s simplify the ratio by dividing both sides by 11.
Once we’ve done that, we're left with a ratio of 3 tables for every 7 chairs.
Because 49 is divisible by 7, we will divide seven and get a quotient of 7.
All that’s left is to multiply 7 by 3, and get our final answer of 21 tables sold.
if a random variable x has a mean 1 and a variance 4, then the average of the 50 samples of x has mean of a) 1/50 b) 2/50 c) 4/50 d) 1
Option (a) 1/50 The average of the 50 samples of x can be calculated as the sum of the values of x divided by the number of samples, which is 50 in this case.
Since x has a mean of 1, we know that the sum of the values of x is 50 times 1, which is 50. The variance of x is 4, which means that the standard deviation of x is 2. This means that the standard error of the mean of x, which is the standard deviation of the sample mean, is 2 divided by the square root of 50, which is approximately 0.283. Therefore, the 95% confidence interval for the mean of the 50 samples of x is [1 - 1.96(0.283), 1 + 1.96(0.283)] = [0.44, 1.56]. Since none of the answer choices fall within this interval, we cannot determine the correct answer without additional information.
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What is the equation of the line that passes through the point (-1,6) and has a y-intercept of -5
well, since the y-intercept is at -5, or namely when the line hits the y-axis is at -5, that's when x = 0, so the point is really (0 , -5), and we also know another point on the line, that is (-1 ,6), to get the equation of any straight line, we simply need two points off of it, so let's use those two
\(\stackrel{y-intercept}{(\stackrel{x_1}{0}~,~\stackrel{y_1}{-5})}\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{6}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{6}-\stackrel{y1}{(-5)}}}{\underset{run} {\underset{x_2}{-1}-\underset{x_1}{0}}} \implies \cfrac{6 +5}{-1} \implies \cfrac{ 11 }{ -1 } \implies - 11\)
\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-5)}=\stackrel{m}{- 11}(x-\stackrel{x_1}{0}) \implies y +5 = - 11 ( x -0) \\\\\\ y+5=-11x\implies {\Large \begin{array}{llll} y=-11x-5 \end{array}}\)
A data set includes the following numbers: eighteen over 5, two and four fifths, 97%, and 1.74.
Part A: What is the order of the numbers from least to greatest? Write your answer using the numbers in their original form.
Part B: Did you use estimation or rewrite the numbers in equivalent forms? Please explain your answer.
Help me pls!
Raj, Devi and Miko have managed their savings well. The sum of Raj and Devi's savings is $1181. Raj and Miko's savings sum up to $1797. The ratio of Devi to Miko's savings is 3 : 11. How much has Raj saved?
Answer:
it is easy it is 3833
Step-by-step explanation:
The money saved by Raj from the given conditions is $950.
Given that, Raj, Devi and Miko have managed their savings well.
What is the ratio?The ratio is defined as the comparison of two quantities of the same units that indicates how much of one quantity is present in the other quantity.
The ratio of Devi to Miko's savings is 3:11.
So, Devi's saving is 3x and Devi to Miko's savings is 11x.
The sum of Raj and Devi's savings is $1181. Raj and Miko's savings sum up to $1797.
Let y be the Raj's saving.
Now, y+3x=1181 --------(I) and y+11x=1797 --------(II)
From equation (I), y=1181-3x
Substitute y=1181-3x, in equation (II), we get
1181-3x+11x=1797
⇒ 8x=1797-1181
⇒ 8x=616
⇒ x=616/8
⇒ x=77
So, y=1181-3x=1181-231
=$950
Hence, the money saved by Raj from the given conditions is $950.
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Suppose 45% of the worlds population has type "O" blood type. A study was done to see if the percent differs for college students. 47% of the 1000 random selected college students have type O blood. conduct a hypothesis test to determine if the percent of college students with type o blood differs for college students?
Answer:
We accept H₀, with CI = 90 %, porcentage of O blood type in college students does not differ from the world population porcentage
Step-by-step explanation:
The test is a proportion two-tail test ( note: differs)
p₀ = 45 % or p₀ = 0,45
n = 1000
p = 47 % or p = 0,47
Test Hypothesis
Null hypothesis H₀ p = p₀
Alternative hypothesis Hₐ p ≠ p₀
CI we assume 90 % then α = 10 % α = 0,1 α/2 = 0,05
z score from z-table z(c) = 1,64
To calculate z(s) = ( p - p₀ ) / √ p₀q₀/ n
z(s) = ( 0,47 - 0,45 )/ √( 0,45)*(0,55)/1000
z(s) = 0,02/√( 0,2475)/1000
z(s) = 0,02/0,01573
z(s) = 1,2714
Now we compare z(s) and z(c)
z(s) < z(c) 1,2714 < 1,64
Then z(s) is in the acceptance region we accept H₀
Meera purchases 400 beads for $80.00. Which answer is the unit rate for her purchase?
When Meera purchases 400 beads for $80.00, the unit rate is $0.2 per bead.
How to calculate the unit rate?The unit rate is the denominator of a ratio of two different units. For instance, kilometer/hour, meter/sec, mile/hour, salary/month, and so on. Arithmetic is the most fundamental and ancient branch of mathematics, and it is widely used in everyday life.
When expressed as a fraction, a unit rate has a denominator of one unit. To write a rate as a unit rate, divide the rate's numerator and denominator by the rate's denominator.
Since Meera purchases 400 beads for $80.00, the unit rate will be:
= Price / Number of beads
= $80 / 400
= $0.2 per bead.
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A bag of skittles contains 4 red skittles, 3 green skittles, 2 orange skittles, and 1 purple skittle. What is the probability that you randomly choose a skittle that is green, do not replace it, and then draw a purple skittle?
Answer:1/30
Step-by-step explanation:
green: 3/10
purple don't replace: 1/9
3/10*1/9=1/30
a child enters a carousel that takes one minute to revolve once around. the child enters at the point (0,1) , that is, on the due north position. assume the carousel revolves counterclockwise. what are the coordinates of the child after 30 seconds?
the coordinates of the child after 30 seconds are (0,-1). A carousel is a rotating platform that can be found in amusement parks or other recreational areas. When a child enters a carousel, the position of the child changes as the carousel revolves.
To determine the position of a child on a carousel, it is necessary to consider the speed and direction of the rotation, as well as the starting point of the child.
If a carousel takes one minute to revolve once around and the child enters at the point (0,1) on the due north position,
after 30 seconds the child will have rotated 30/60 = 1/2 of the way around the carousel.
Since the carousel revolves counterclockwise, the child's new position can be found by rotating the starting position (0,1) by 1/2 of a full revolution,
which is equal to 180 degrees.
The rotation can be performed using trigonometric functions, such as sine and cosine. The coordinates of the child after 30 seconds would be (-sin(180), cos(180)) = (0,-1).
This means that the child would be located on the due south position, which is the opposite direction from their starting position on the due north position.
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21) What are the coordinates of the image of segment CV with endpoints C(3, 2) and V (1,-6) after a dilation with scale factor 3/2 and the origin as the center of dilation?
Answer:
The coordinates of the image of segment CV after the dilation are:
C' = (9/2, 3)
V' = (3/2, -9)
Step-by-step explanation:
To perform a dilation with center of dilation at the origin and scale factor 3/2, we need to multiply the coordinates of each point by 3/2. The coordinates of point C(3, 2) become:
C' = (3 * 3/2, 2 * 3/2) = (9/2, 3)
Similarly, the coordinates of point V(1, -6) become:
V' = (1 * 3/2, -6 * 3/2) = (3/2, -9)
Therefore, the image of segment CV with endpoints C(3, 2) and V(1, -6) after the dilation with center of dilation at the origin and scale factor 3/2 is a segment with endpoints C'(9/2, 3) and V'(3/2, -9).
sigma factors are necessary in which phase of transcription?
Sigma factors are necessary in the initiation phase of transcription. This phase requires a complex called RNA polymerase to locate the DNA's start site and begin the synthesis of a new RNA strand.
RNA polymerase recognizes promoters, which are DNA sequences adjacent to the transcription start sites that define the start site for RNA synthesis. Sigma factors are subunits of RNA polymerase that help it recognize promoters.Sigma factors regulate the initiation of RNA synthesis by RNA polymerase.
The sigma factor is a DNA-binding protein that recognizes specific promoter sequences and recruits RNA polymerase to the DNA molecule at the appropriate location. When the sigma factor binds to a promoter, RNA polymerase becomes anchored and initiates transcription. There are several sigma factors, each of which recognizes a different promoter sequence.
They are required for transcription of different sets of genes in response to environmental cues or other cellular stimuli.It is worth noting that the promoter sequence that sigma factors bind to can vary in terms of its similarity to the consensus sequence recognized by the sigma factor.
Sigma factors can also recognize alternative promoter sequences that bind to the RNA polymerase core enzyme with lower affinity than the consensus sequence. In general, a promoter with a perfect match to the consensus sequence is more effective than one with a non-perfect match in initiating transcription.
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What is the LCM of 9 and 18
Answer:
18
Step-by-step explanation:
product of prime factors
9=3^2
18=2*3^2
LCM of 9 and 18 = 2*3^2
=18
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Take the expression and translate it into words.
Answer:
The ratio of 2 times x minus three to 5
Step-by-step explanation:
Fractions can be represented as ratios: for instance, X/Y can be represented as x : y
suppose the magnitude (absolute value) of f′′is small on a given δ-interval with center a. are the slopes of the tangent lines changing slowly or quickly as x increases over the δ-interval?
When the magnitude of f′′ is small on a given δ-interval with center a, the slopes of the tangent lines change slowly as x increases over the δ-interval.
The magnitude of f′′ is small on a given δ-interval with center a. In this case, the slopes of the tangent lines are changing slowly as x increases over the δ-interval.
This can be explained by understanding that the second derivative, f′′, represents the rate of change of the first derivative, f′, which in turn represents the slope of the tangent lines to the function, f.
A small magnitude of f′′ means that the curvature of the function is minimal, and therefore, the change in the slopes of the tangent lines is minimal as well.
When the second derivative is small, the function behaves more like a straight line within the δ-interval, so the slopes of the tangent lines do not change much. This implies that the function is relatively stable and has less curvature in that interval.
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A _____________ is a line that provides an approximation of the relationship between the variables.
Answer:
srat
Step-by-step explanation:hehe i really dont know
What is the power for the function?
Answer choices:
.5
-2
Answer:
0.5
Step-by-step explanation:
The square root of x can be rewritten as \(x^{0.5}\).
Therefore f(x) can now be written as
f(x)=4\(x^{0.5}\), and so the power of the function is 0.5
What is an
i equation of the line that passes through the points (8, -1) and (4, -1)?
Answer:
I hope this is what you're looking for. Good luck.
Step-by-step explanation:
find the area of the part of the plane 5x + 3y + z = 15 that lies in the first octant.
The area of the part of the plane 5x + 3y + z = 15 that lies in the first octant is 15x^3/6 + 45x^2y/2.
What is area?Area is a measure of the size of a surface or the amount of space it takes up. It can be measured in square units such as square feet, square meters, or acres. Area is used to describe the size of a two-dimensional object or shape, and is often used when discussing the size of a plot of land, a room, or other geographical area.
The first octant is defined as the area in the three-dimensional Cartesian coordinate system where all the coordinates are positive. In this case, the equation 5x + 3y + z = 15 can be rearranged to solve for z: z = 15 - 5x - 3y. This new equation can then be used to find the area of the plane that lies in the first octant by integrating the equation over the area of the octant.
To solve for the area, we must first find the boundaries of the octant. Since all coordinates must be positive, the boundaries of the octant are x = 0, y = 0, and z = 0. The area of the plane that lies in the first octant is then computed using the triple integral:
Area = ∫∫∫ 0 0 0 15-5x-3y dzdydx
= ∫∫ 0 0 (15x + 45y)dydx
= ∫ 0 (15x^2/2 + 45xy)dx
= 15x^3/6 + 45x^2y/2
Therefore, the area of the part of the plane 5x + 3y + z = 15 that lies in the first octant is 15x^3/6 + 45x^2y/2.
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use the kkt
Use the method of steepest ascent to approximate the solution to max z = -(x₁ - 3)² - (x₂ - 2)² s. t. (x₁, x₂) E R²
To approximate the solution and maximize the given objective function we need to find the steepest ascent direction and iteratively update the values of x₁ and x₂ to approach the maximum value of z.
The method of steepest ascent involves finding the direction that leads to the maximum increase in the objective function and updating the values of the decision variables accordingly. In this case, we aim to maximize the objective function z = -(x₁ - 3)² - (x₂ - 2)².
To find the steepest ascent direction, we can take the gradient of the objective function with respect to x₁ and x₂. The gradient represents the direction of the steepest increase in the objective function. In this case, the gradient is given by (∂z/∂x₁, ∂z/∂x₂) = (-2(x₁ - 3), -2(x₂ - 2)).
Starting with initial values for x₁ and x₂, we can update their values iteratively by adding a fraction of the gradient to each variable. The fraction determines the step size or learning rate and should be chosen carefully to ensure convergence to the maximum value of z.
By repeatedly updating the values of x₁ and x₂ in the direction of steepest ascent, we can approach the solution that maximizes the objective function z. The process continues until convergence is achieved or a predefined stopping criterion is met.
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In a random sample of twelve people, the mean driving distance to work was 20.2 miles and the standard deviation was 7.1 miles. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 90% confidence interval for the population mean μ. Interpret the results. Identify the margin of error.
Interpreting the results: We are 90% confident that the true population mean driving distance to work falls within the range of 20.2 miles plus or minus 4.091 miles.
To construct a confidence interval for the population mean μ, we can use the formula:
Confidence interval = sample mean ± margin of error
where the margin of error is given by:
Margin of error = t * (standard deviation / √n)
In this case, the sample mean is 20.2 miles, the standard deviation is 7.1 miles, and the sample size is 12. We need to find the appropriate value of t for a 90% confidence level with (n-1) degrees of freedom.
The degrees of freedom for a sample size of 12 is (n-1) = 12-1 = 11.
Using a t-table or calculator, the t-value for a 90% confidence level and 11 degrees of freedom is approximately 1.796.
Substituting the values into the formula, we have:
Margin of error = 1.796 * (7.1 / √12)
Calculating this value, we find the margin of error to be approximately 4.091 miles.
Therefore, the 90% confidence interval for the population mean μ is:
20.2 ± 4.091
Interpreting the results: We are 90% confident that the true population mean driving distance to work falls within the range of 20.2 miles plus or minus 4.091 miles.
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THE PROBLEM:
Kip had to renew his license and while sitting at the DMV he surveyed everyone else there, asking them their age. The data turned out to have normal distribution, the mean age was 41, and the standard deviation was 5.
1. On paper, make a bell curve with the appropriate values listed on the axis below. Show your teacher.
2. What % of people were below 31 years old?
3. What % of people were above 31 years old?
4. What % of people were between 41 and 46?
5. About what % of people were older than Kip (he's 38 years old)?
Answer:
1. To make a bell curve (a normal distribution) with a mean of 41 and a standard deviation of 5, we can use the following values on the x-axis:
x = 21, 26, 31, 36, 41, 46, 51, 56, 61
These values are symmetric around the mean of 41, and each value is one standard deviation away from the mean.
On the y-axis, we can mark the percentage of people in each interval, which is calculated using the area under the curve. The total area under the curve is 100%.
2. To find the percentage of people who were below 31 years old, we need to calculate the area under the curve to the left of x = 31. Using a standard normal distribution table or calculator, we can find this area to be approximately 0.0228, or 2.28%.
So, about 2.28% of people were below 31 years old.
3. To find the percentage of people who were above 31 years old, we can subtract the percentage of people below 31 years old from 100%.
100% - 2.28% = 97.72%
So, about 97.72% of people were above 31 years old.
4. To find the percentage of people between 41 and 46 years old, we need to calculate the area under the curve between x = 41 and x = 46. Using a standard normal distribution table or calculator, we can find this area to be approximately 0.3413, or 34.13%.
So, about 34.13% of people were between 41 and 46 years old.
5. To find the percentage of people older than Kip (who is 38 years old), we need to calculate the area under the curve to the right of x = 38. Using a standard normal distribution table or calculator, we can find this area to be approximately 0.6306, or 63.06%.
So, about 63.06% of people were older than Kip.
Step-by-step explanation:
Which best represents the expression
5
x
−
4
?
Algebraic expressions can be represented with words and vice versa.
The statement that can represent 5x - 4 is: 4 less than the product of 5 and a number
The expression is given as: 5x - 4
By analysis, we have:
5x represents the product of 5 and a number (x)-4 represents 4 less than.Hence, a statement that can represent the expression 5x - 4 is: 4 less than the product of 5 and a number
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Ms. Truman has always provided her statistics students with a small index card for each exam. The students are permitted to write whatever they want on the index card and use it on the exam. She decides to conduct an experiment to investigate if the distribution of grades will be different if she provides students with a large index card. She has 80 students in her statistics classes this year. She randomly assigns 40 students to receive the typical small index card and 40 students to receive a large index card to use on the upcoming exam. The results of the exam are displayed in the table.
What are the appropriate hypotheses to determine if the distribution of grades would differ for all students like these under these two treatments?
H0: There is no association between index card size and grade.
Ha: There is an association between index card size and grade.
H0: There is an association between index card size card and grade.
Ha: There is no association between index card size card and grade.
H0: There is a difference in the distribution of grades for all students like these who use a small or large index card.
Ha: There is no difference in the distribution of grades for all students like these who use a small or large index card.
H0: There is no difference in the distribution of grades for all students like these who use a small or large index card.
Ha: There is a difference in the distribution of grades for all students like these who use a small or large index card.
The appropriate hypotheses to determine if the distribution of grades would differ for all students under these two treatments are:
H0: There is no difference in the distribution of grades for all students like these who use a small or large index card.Ha: There is a difference in the distribution of grades for all students like these who use a small or large index card.How to explain the hypothesisIn hypothesis testing, we have a null hypothesis (H0) and an alternative hypothesis (Ha). The null hypothesis represents the assumption of no effect or no difference, while the alternative hypothesis represents the claim we are trying to gather evidence for.
In this scenario, the null hypothesis (H0) states that there is no difference in the distribution of grades for all students who use a small or large index card. It suggests that the size of the index card does not have any association with the grades.
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Can someone tell me why is nobody helping me with my question I be POSTING 4 TIMES PLEASE YALL Help me please
Answer:
x = 4
y = 5
Step-by-step explanation:
4x = x + 12
^(subtract x from both sides)^
3x = 12
^(divide both sides by 3)^
x = 4
3y = 15
(divide both sides by 3)
y = 5
solve for x: 1/5(x+2/5)=-3/25
Answer:
x=-1
Step-by-step explanation:
Answer:
x=-1
Step-by-step explanation:
Move Constant to the right
carculate the difference
-59_________-60
<
>
=
Answer:
>
Step-by-step explanation:
-59 is bigger than -60. If you think about it on a number line, it is bigger.
By the way, can you follow me on Brainly?
Thanks!
Answer:
-59 > -60
Step-by-step explanation:
in negatives, the less the number is, the more it is.(kind of confusing)