PLEASE HELP PLEASE ALMOST DUE IN 27 MINUTES WILL MARK BRAINLIEST PICTURE ATTACHED

Answer:

exponential growth

Step-by-step explanation:

Answer: c.

Step-by-step explanation:

A= .5*b*h

A = .5* \(\sqrt{5} * \sqrt{10}\)

A = 3.5355339059

5/\(\sqrt{2}\) = 3.5355339059

The phrase r2h is one that can be utilised in order to provide an approximation of the cylinder's volume. In this expression, r stands for the radius of the base, h stands for the height of the cylinder, and stands for the mathematical constant pi.

The volume of a cylinder can be determined by multiplying the area of the base by the height of the cylinder. In this particular instance, the base of the cylinder is a circle. The mathematical expression for calculating the area of a circle is r2, where is approximately equal to 3.14159 and r is the circle's radius. Since we know the radius of the base to be 4 inches, the area of the cylinder's base can be calculated using the equation r2, where r is the radius of the base. The approximate volume of the cylinder can be calculated by taking this measurement and multiplying it by the height of the cylinder, which is stated to be 6 inches. Because of this, the phrase r2h can be utilised to calculate an approximation of the volume of the cylinder in the given circumstances.

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Answer:

Step-by-step explanation:

she had both on May 5

swimming lessons every 5th day

5,10,15,20

diving lessons every 3rd day...

3,6,9,12,15

so they both have a common multiple of 15

so fifteen days after May 5 = May 20 <==

A significance level of 0.10, we have enough evidence to conclude that the new copy machines have a significantly faster mean repair time compared to the older model.

To test if the new copy machines are faster to repair, we can set up the following null and alternative hypotheses:

Null Hypothesis (H₀): The mean repair time for the new copy machines is the same as the mean repair time for the older model.

Alternative Hypothesis (H₁): The mean repair time for the new copy machines is less than the mean repair time for the older model.

Let's perform a one-sample t-test to test these hypotheses. The test statistic is calculated as:

t = (sample mean - population mean) / (sample standard deviation / √(sample size))

Given:

Population mean (μ) = 93 minutes

Sample mean (\(\bar x\)) = 86.8 minutes

Sample standard deviation (s) = 14.6 minutes

Sample size (n) = 18

Significance level (α) = 0.10

Calculating the test statistic:

t = (86.8 - 93) / (14.6 / sqrt(18))

t = -6.2 / (14.6 / 4.24264)

t ≈ -2.677

The degrees of freedom for this test is n - 1 = 18 - 1 = 17.

Now, we need to determine the critical value for the t-distribution with 17 degrees of freedom and a one-tailed test at a significance level of 0.10. Consulting a t-table or using statistical software, the critical value is approximately -1.333.

Since the test statistic (t = -2.677) is less than the critical value (-1.333), we reject the null hypothesis.

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Answer:

The answer is 2

Step-by-step explanation:

5x + 7y = -11

y = -3

Now, put the value of y in the given equation we get,

5x + 7y = -11

5x + 7(-3) = -11

5x - 21 = -11

5x - 21 + 21 = 21 - 11

5x = 10

5x/5 = 10/5

x = 2

Thus, The value of x is 2

The diagram of the pentagon is missing, so i have attached it.

Answer:

|AE| = 130 m

|DE| = 150 m

Perimeter of pentagon = 720 m

Step-by-step explanation:

From the diagram, we can find AE from pythagoras theorem;

|AE| = √(|AA'|² + 50²)

Where AA' is the length from A to the perpendicular angle.

Now, AB = 150, and A'B is parallel to 30 m. Thus, A'B = 30

AA' = AB - A'B = 150 - 30

AA' = 120

Thus;

|AE| = √(120² + 50²)

|AE| = √(14400 + 2500)

|AE| = √16900

|AE| = 130

Similarly,

|DE| = √(|DD'|² + |ED'|²)

ED' = BC - 50

ED' = 140 - 50

ED' = 90

Also, DD' is parallel to AA' and is = 120

Thus;

|DE| = √(120² + 90²)

|DE| = √22500

|DE| = 150

Perimeter of pentagon = 150 + 130 + 150 + 150 + 140 = 720

The percentage that each expense has out of the total budgeted amount of $45,000  have been computed, where insurance has 8.00%, Utilities 7.00% and so on.

What is a percentage?

In this case, percentage refers to proportion of each expense from the total budgeted expense of $45,000, which means that in order to total budgeted expense of $45,000, which means that in order to compute the percentage of total budgeted for each expense category, we divide the expense by the total budgeted expense

Insurance=$3600/$45,000=8.00%

Utilities=$3150/$45,000=7.00%

Clothing=$2700/$45000=6.00%

Transportation=$1350/$45000=3.00%

Entertainment=$5400/$45000=12.00%

Savings=$4050/$45000=9.00%

Taxes=$7200/$45000=16.00%

Food=$7650/$45000=17.00%

Housing=$9900/$45000=22.00%

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Answer:

There are no solutions to this equation.

Step-by-step explanation:

Answer:

5.0714285714

Step-by-step explanation:

check the photo

:)

Answer:

2 : 1

12 : 6

30 : 15

Step-by-step explanation:

Look at the ratios one by one.  Starting with 6 : 3, we can see that it's of the form 2a : a.

2 : 1

12 : 6

30 : 15

These are all equivalent.

Answer:

Figure ABC is congruent to figure A′B′C′.

Step-by-step explanation:

I just did the test and got it right

D - Figure ABC is congruent to figure A′B′C′.

Step-by-step explanation

took the test

The mass of each object (a) A thin copper wire 1.75 feet long (starting at x= 0) with density function given byp (a)=3x² + 4 lb/ft.m = 12.44lb (b) A frisbee with radius 7 inches with density function given by p(x)=√2 kg/in.m =1.74 lb

(a) To find the mass of the copper wire, we need to integrate the density function over the length of the wire: m = ∫p(x)dx from 0 to 1.75 m = ∫(3x² + 4)dx from 0 to 1.75 m = [x³ + 4x] from 0 to 1.75 m = (1.75³ + 4(1.75)) - (0³ + 4(0)) m = 12.44 lb (rounded to two decimal places)

Therefore, the mass of the copper wire is 12.44 lb.

(b) To find the mass of the frisbee, we need to integrate the density function over the volume of the frisbee: m = ∫∫∫p(r,θ,z)rdrdθdz from 0 to 7 inches (radius)

Since the frisbee is symmetric around the z-axis, we can simplify this integral by using cylindrical coordinates:

m = ∫∫∫p(r,z)rdrdθdz from 0 to 7 inches (radius), 0 to 2π (angle), and -√(49-r²) to √(49-r²) (z) m = ∫0²⁷p(r,z)rdrdθdz (since p(x) is in kg/in and we want the mass in lb, we need to convert units)

m = ∫0²⁷(√2/39.37)πr(rdr)(√(49-r²) + √(49-r²))dθdz (conversion factor: 1 kg/in = √2/39.37 lb/in) m = ∫0²⁷(2πr(49-r²)/39.37)(√2/39.37)(dz)

m = (√2π/39.37)∫0²⁷(98r(49-r²)/39.37)dr m = (√2π/39.37)[(98/15)r⁵ - (98/3)r³] from 0 to 7 m = (√2π/39.37)[(98/15)(7⁵) - (98/3)(7³)] m = 1.74 lb (rounded to two decimal places) Therefore, the mass of the frisbee is 1.74 lb.

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When the height is 38 cm and the base is 32 cm, the rate at which the area of the triangle changes is 10 cm²/min.

The rate at which the area of a triangle changes can be found by multiplying the rate at which the base is shrinking by the rate at which the height is increasing.

Given:

Rate of shrinking of the base = -2 cm/min

Rate of increasing of the height = 3 cm/min

Height of the triangle = 38 cm

Base of the triangle = 32 cm

To find the rate at which the area of the triangle changes, we use the formula for the area of a triangle:

Area = (1/2) * base * height

Differentiating the area formula with respect to time gives us:

dA/dt = (1/2) * (db/dt) * height + (1/2) * base * (dh/dt)

Substituting the given values, we have:

dA/dt = (1/2) * (-2) * 38 + (1/2) * 32 * 3

Simplifying, we get:

dA/dt = -38 + 48

dA/dt = 10 cm²/min

Therefore, when the height is 38 cm and the base is 32 cm, the rate at which the area of the triangle changes is 10 cm²/min.

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Answer: 17.50

Step-by-step explanation:

Answer:

$18.50

Step-by-step explanation:

\(185 \times 6.10 = 1128.50\)

\(1128.50 \div 61 = 18.5\)

To be sure of getting at least one face card from a standard deck of 52 cards, you would need to pick a minimum of 4 cards.

In a standard deck of 52 cards, there are 12 face cards (4 jacks, 4 queens, and 4 kings). To ensure that you have at least one face card, you would need to consider the worst-case scenario, which is that the first three cards you pick are not face cards. In this case, the fourth card you pick is guaranteed to be a face card, as there are 12 face cards remaining in the deck.

To understand why you need a minimum of 4 cards, consider the possibilities:

If you pick 3 non-face cards consecutively, the next card must be a face card. The probability of picking a non-face card is
(40/52) * (39/51) * (38/50) = 0.4026.

Therefore, the probability of picking at least one face card in the first 3 cards is 1 - 0.4026 = 0.5974.

However, to be absolutely sure of getting at least one face card, you need to consider the worst-case scenario, where the first 3 cards are non-face cards. Therefore, you would need to pick the fourth card to guarantee a face card.

Hence, to be sure of getting at least one face card, you need to pick a minimum of 4 cards from a standard deck of 52 cards.

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0.023...

hope it helps...!!!

Answer:

y, (3y + 1), and (y + 5).

i might be wrong but what is OBJ?

Step-by-step explanation:

Answer:

x^2 -10x+2

Step-by-step explanation:

(3x^2 - 11x - 4) – (x – 2) (2x + 3)

FOIL

(3x^2 - 11x - 4) – (2x^2-4x+3x-6)

Combine like terms

(3x^2 - 11x - 4) – (2x^2 -x-6)

Distribute the minus sign

3x^2 - 11x - 4 – 2x^2 +x+6

Combine like terms

x^2 -10x+2

Given: Inclination angle of the ground below = θ = 52°

Elevation angle of the plane at B = α = 53.2°

Distance BC = 3500 ft

The angular coverage of the camera lens = φ = 73′

The required distance AB = it

Let us form a diagram of the given information: From the given diagram,

we can see that, In right Δ ABC,

We have, tan(α) = BC/AB  

= 3500/ABAB

= 3500/tan(α)AB

= 3500/tan(53.2°) ... (i)

Also,In right Δ ABD,

We have, tan(φ/2) = BD/ABBD

= AB × tan(φ/2)BD

= [3500/tan(53.2°)] × tan(73′/2)BD

= 3379.8 ft (approx)

Now,In right Δ ACD,

We have, cos(θ) = CD/ADCD

= AD × cos(θ)AD

= CD/cos(θ)AD

= BD/sin(θ)AD

= (3379.8) / sin(52°)AD

= 2645.5 ft (approx)

Therefore, the ground distance AB (to the nearest foot) that will appear in the picture is 2646 feet.

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The probability that more than 150 soldiers were killed by horse kicks in 1872 is 0.015.

The probability of more than 150 soldiers being killed by horse kicks in 1872 is determined by Poisson's distribution. This distribution is used to find the probability of a given number of events within a fixed time period, given the known average rate of events that occur in a given period of time.

The calculation is as follows:

P(X> 150) = 1 - P(X <= 150)

P(X <= 150) = Σx=0 to x=150 \

P(X ≤ 150) = (182/365)

P(X ≤ 150) = 0.985

P(X> 150) = 1 - 0.985

P(X> 150) = 0.015

Therefore, the probability that more than 150 soldiers were killed by horse kicks in 1872 is 0.015.

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Answer:

-3k + 10

Step-by-step explanation:

-3k-(-8)+2 = -3k + 8 + 2 = -3k +10

Answer:

-3k + 10

Step-by-step explanation:

-3k + 8 + 2 =

-3k + 10

Hope that helps!

Answer:

see explanation

Step-by-step explanation:

Since the marked angles are congruent, let them be x

(6)

The sum of the interior angles of a quadrilateral = 360°

Sum the angles and equate to 360

x + x + 120 + 90 = 360

2x + 210 = 360 ( subtract 210 from both sides )

2x = 150 ( divide both sides by 2 )

x = 75

Then ∠ X = ∠ Y = 75°

---------------------------------------------------------------------

(7)

The sum of the interior angles of a hexagon = 720°

Sum the angles and equate to 720

x + x + 108 + 103 + 149 + 90 = 720

2x + 450 = 720 ( subtract 450 from both sides )

2x = 270 ( divide both sides by 2 )

x = 135

Then ∠ X = ∠ Y = 135°

Answer:

Step-by-step explanation:

Sum of the interior angles of a regular polygon:

Quadrilateral has sum of angles:

Sum the given angles and consider x = y as marked congruent:

Hexagon has sum of angles:

Sum the given angles and consider x = y as marked congruent:

The angle x of the triangle is 68 degrees and the side y is 7.5 units.

The triangle ABC is a right angle triangle because it has one angle as 90 degrees. The sum of the angles in the triangle is 180 degrees.

The angle ECD is congruent to angle ACB(vertically opposite angles).

Therefore,

∠ECD ≅ ∠ACB

Hence,

x = 180 - 90 - 22

x = 68 degrees.

using trigonometric ratios, let's find y

cos 22 = adjacent / hypotenuse

sin 22 = 2y - 1 / 15

cross multiply

15 cos 22 = 2y - 1

2y - 1 = 13.9077578185

2y = 13.9077578185 + 1

2y = 14.9077578185

divide both sides by 2

y = 14.9077578185 / 2

y = 7.45387890925

Therefore,

y = 7.5 units

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Respuesta:

x = 5.656854249

Explicación paso a paso:

[NOTA: Solo quería disculparme de antemano por cualquier mala gramática, ya que estoy usando un traductor para esto.]

x/Sen30°= 8/Sen45° [Multiplica ambos lados por Sen30°]

x = (8/Sen45°) * Sen30° [Resuelve usando una calculadora]

x = 5.656854249

Answer:

x is greater than or equal to -4 but less than or equal to 4

Step-by-step explanation:

The "domain" is all of the x values on the line. But there are an infinite amount of x-values there, so it must be written as that.

Answer:

See below.

Step-by-step explanation:

The domain is simply the range of x-values the graph encompasses. From the given graph, we can see that the graph stretches from x=-4 to x=+4.

However, note that the graph does not include -4 since the point is an open circle. However, it does include +4 since the point is a closed circle. Therefore, the domain of this graph is:

In interval notation:

\((-4,4]\)

(Parenthesis on the left because -4 is not included. Brackets on the right because +4 is included.)

The two triangles n = (75 + 3) / 5 = 18. The measure of angle q is 18 degrees.

1. First, find the value of n by using the equation 5(n - 3) = 75 + 3

2. Next, add 75 and 3 together and divide by 5. This gives us a value of 18 for n.

3. Finally, use the equation 5(n - 3) to determine the measure of angle q in triangle qrs. This equals 5(18 - 3) = 5(15) = 75 degrees.

The two triangles qrs and xyz are similar, meaning they have the same angle measures. In order to find the measure of angle q in triangle qrs, we must first find the value of n. The measure of angle x in triangle xyz is 75 degrees and the measure of angle q in triangle qrs is equal to 5(n - 3) degrees. We can use this equation to solve for the value of n. To do this, we add 75 and 3, then divide by 5. This gives us a value of 18 for n. Therefore, the measure of angle q in triangle qrs is 18 degrees.

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Convert ange in radian.

So answer is 4.51 radians.

To determine if the bolts vary by more than the required variance, we can conduct a hypothesis test. The null hypothesis (H₀) states that the variance of the bolts is equal to or less than the required variance (σ² ≤ 0.025), while the alternative hypothesis (H₁) states that the variance is greater than the required variance (σ² > 0.025).

Next, we need to determine the critical value(s) of the test statistic. Since we are testing for variance, we will use the chi-square distribution. For a one-tailed test with α = 0.01 and 14 degrees of freedom (n-1), the critical value is 27.488.

Now, we can compare the test statistic to the critical value. The test statistic is calculated as (n-1) * s² / σ², where n is the sample size (15), s² is the sample variance (0.1587²), and σ² is the required variance (0.025).

If the test statistic is greater than the critical value, we reject the null hypothesis and conclude that the bolts vary by more than the required variance. Otherwise, we fail to reject the null hypothesis.

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To determine if the bolts vary by more than the required variance, we can conduct a hypothesis test. The null hypothesis (H₀) states that the variance of the bolts is equal to or less than the required variance (σ² ≤ 0.025), while the alternative hypothesis (H₁) states that the variance is greater than the required variance (σ² > 0.025).

Next, we need to determine the critical value(s) of the test statistic. Since we are testing for variance, we will use the chi-square distribution. For a one-tailed test with α = 0.01 and 14 degrees of freedom (n-1), the critical value is 27.488.

Now, we can compare the test statistic to the critical value. The test statistic is calculated as (n-1) * s² / σ², where n is the sample size (15), s² is the sample variance (0.1587²), and σ² is the required variance (0.025).

If the test statistic is greater than the critical value, we reject the null hypothesis and conclude that the bolts vary by more than the required variance. Otherwise, we fail to reject the null hypothesis.

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