PLEASE HELP (PSYCHOLOGY) John and Kate met two weeks ago, and they have been on four terrific dates. They each feel a very strong attraction toward the other, and they wish they could be around each other all the time. Their relationship is based only on having fun together, and does not include honestly sharing difficult aspects of life. Each of them has secretly thought they might be falling in love, but they have not yet been open about how they feel. Neither of them has told their friends or their families about their new relationship.
Explain these theories of love, and how John and Kate’s situation relates to each: (15 points)
Zick Rubin’s theory of attachment, caring, and intimacy;
Elaine Hatfield’s theory of passionate and companionate love;
Sternberg’s triangular theory.

The volume of matter is primarily due to its electrons and protons.

Correct option is C.

Electrons are an essential element of all atoms, and contribute significantly to the overall volume of all matter. Protons are also essential elements of all atoms, and contribute to the overall volume of matter as well. Responsibility for the majority of the volume of matter lies with the electrons.

Electrons are negatively charged particles that are much smaller than protons. While electrons occupy the space in the atoms, protons are responsible for maintaining the atoms stable due to their positive charge. As such, electrons and protons both play an important role in maintaining the overall volume of matter.

Moreover, neutrons, which are located within the nucleus of atoms, also contribute to the overall volume of matter as they are needed to balance the positive charge of protons. In conclusion, electrons and protons are responsible for the majority of the volume of matter, as they are the essential elements that constitute atoms.

Correct option is C.

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Correct question is :

the volume of matter is due mostly to its

a. electrons.

b. protons.

c. both of these

d, none

It would take 500 J of work to completely separate them. Option e is the answer.

Gravitational potential energy is the energy stored in the gravitational field between two objects. A negative value for gravitational potential energy indicates that work would need to be done to separate the objects to an infinite distance, meaning that the objects are attracted to each other. Therefore, in this scenario, it would take 500 J of work to completely separate the objects. Option e is correct choice.

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Answer:

940800π Nm

Explanation:

Given the following :

Radius of cylindrical tank(r) = 2m

Weight of water = 9800N/m^3

Volume of a cylindrical tank is given as:

πr^2h

Height of tank = Δy

Volume = π2^2Δy = 4πΔy

Weight of water layer = weight of arer × volume of cylindrical tank = 9800 × 4πΔy = 39200πΔy

Distance from any point from tank top

Height - y = 6 - y

1 metre below ground level

Distance = 6 - y + 1 = 7 - y

Δy = 7- y

Taking the integral:

See attached picture for final calculations

Answer:

12

Explanation:

12

a) The air to fuel ratio (AFR) for complete combustion of n-heptane is approximately 14.6:1.

b) The heat of combustion for n-heptane at 25°C and 1 atm is approximately 48.7 MJ/kg.

c) Assuming 120% excess air in the reaction, the AFR would be approximately 17.3:1.

d) The heat of combustion for n-heptane with 120% excess air at 25°C and 1 atm is approximately 48.7 MJ/kg.

The air to fuel ratio (AFR) is the ratio of the mass of air to the mass of fuel required for complete combustion. In the case of n-heptane, a hydrocarbon fuel, if complete combustion occurs, it means that all the fuel reacts with the available oxygen in the air without any side reactions.

a) To find the AFR for complete combustion, we need to consider the stoichiometry of the reaction. For n-heptane, the balanced chemical equation is \(C_7H_1_6 + 11O_2 \geq 7CO_2 + 8H_2O\). From this equation, we can see that 1 mole of n-heptane requires 11 moles of oxygen. Since air contains about 21% oxygen by volume, the AFR can be calculated as 1/(0.21*11) = approximately 14.6:1.

b) The heat of combustion is the amount of heat released when one unit mass of a substance undergoes complete combustion. The heat of combustion for n-heptane at 25°C and 1 atm is approximately 48.7 MJ/kg.

c) Assuming 120% excess air means providing 120% more air than the stoichiometric requirement. In this case, the AFR would be calculated as (1 + 1.2)/(0.21*11) = approximately 17.3:1.

d) The heat of combustion remains the same, regardless of the excess air. Therefore, the heat of combustion for n-heptane with 120% excess air at 25°C and 1 atm is approximately 48.7 MJ/kg.

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Answer:

\(0.62\:\mathrm{s}\)

Explanation:

Since the universal SI unit for velocity is meters/second, let's convert ft/s to m/s:

\(10\:\mathrm{ft/s}=3.048\:\mathrm{m/s}\)

We can use the following kinematics equation to solve this question:

\(v_f=v_i+at\)

What we know:

Solving for \(t\):

\(-3.048=3.048+(-9.8t),\\-6.096=-9.8t,\\t=\frac{-6.096}{-9.8}\approx \boxed{0.62\:\mathrm{s}}\)

The energy absorbed by the retina is approximately 3.31 x \(10^-^1^7\) joules per second under ideal conditions.

Under ideal conditions, the human eye can detect light with a wavelength of 620 nm and an absorption rate of 100 photons/s.

To find the energy absorbed by the retina, we use the formula E = nhf, where E is energy, n is the number of photons, h is Planck's constant (6.63 x \(10^-^3^4\) Js), and f is the frequency.

First, we need to find the frequency using the formula f = c/λ, where c is the speed of light (3 x \(10^8\) m/s) and λ is the wavelength.

The frequency is approximately 4.84 x \(10^1^4\) Hz.

Now we can calculate the energy absorbed: E = (100 photons/s)(6.63 x \(10^-^3^4\) Js)(4.84 x \(10^1^4\) Hz) = 3.31 x \(10^-^1^7\) J/s.

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Under ideal conditions, the retina absorbs energy at a rate of approximately 3.21 x \(10^{-17}\) Joules/s when detecting light with a wavelength of 620 nm.

Under ideal conditions, the human eye can detect light with a wavelength of 620 nm when at least 100 photons/s are absorbed by the retina. To calculate the rate of energy absorbed by the retina, we first need to find the energy of a single photon using the formula: E = (hc) / λ. Where E is the energy of a photon, h is Planck's constant (6.63 x \(10^{-34}\) Js), c is the speed of light (3 x \(10^{8}\) m/s), and λ is the wavelength (620 x \(10^{-9}\) m). E = (6.63 x \(10^{-34}\) Js) x (3 x \(10^{8}\) m/s) / (620 x \(10^{-9}\)m). E ≈ 3.21 x \(10^{-19}\) Joules. Now, we know the energy of one photon, and the retina absorbs 100 photons/s. To find the rate of energy absorbed by the retina, we multiply the energy of a single photon by the number of photons absorbed per second: Rate of energy absorbed = Energy per photon x Number of photons/s. Rate of energy absorbed = (3.21 x 10^-19 Joules) x (100 photons/s). Rate of energy absorbed ≈ 3.21 x 10^-17 Joules/s

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To find the relative frequency distribution, you need to divide the frequency of each value by the total number of observations in the data set.

The relative frequency distribution is a way of showing the proportion or percentage of data values that fall into each category or interval. It is calculated by dividing the frequency of each value by the total number of observations in the data set. This gives you the proportion or percentage of data values that fall into each category or interval.

The relative frequency distribution can be displayed in a table or a graph, such as a histogram or a bar chart, to provide a visual representation of the data distribution.

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Answer:

22.777777777777 m/s

Explanation:

Since 1 kilometer is 1000 meters, then 82 km is 82000 meters. Since one hour is the same as 3600 seconds, then the answer is pretty simple: 82000/3600 or 820/36. That gets you 22.77777 or 22.78. Hope this helps

Answer:

is minimised.......

.........

The approximate image distance (di) of the passing moon when reflected off the highly reflective coating on the spherical convex mirror is approximately 0.0286 km, or 28.6 meters.

To determine the image distance of the passing moon when reflected off the highly reflective coating on the spherical convex mirror (the large moon with a diameter of 70.0 km), we can use the mirror equation:

1/f = 1/do + 1/di,

where f is the focal length, do is the object distance, and di is the image distance.

Since we are dealing with a convex mirror, the focal length (f) is positive. For a spherical convex mirror, the focal length is half the radius of curvature (R). However, the radius of curvature is not given in the information provided, so we cannot directly calculate the focal length.

However, we can make use of the fact that a convex mirror always produces a virtual image. In this case, the image distance (di) will be negative, indicating a virtual image formed behind the mirror.

Given:

Diameter of large moon = 70.0 km

Distance of passing moon = 1.00 × 10? km

Since the distance of the passing moon is much greater than the diameter of the large moon, we can approximate the object distance (do) as the distance of the passing moon (1.00 × 10? km).

Substituting these values into the mirror equation:

1/f = 1/do + 1/di,

we can rearrange the equation to solve for the image distance (di):

1/di = 1/f - 1/do.

Since a convex mirror has a positive focal length and we have a virtual image, the term 1/f will be positive and 1/do will be negative.

Substituting the values and performing the calculations:

1/di = 1/f - 1/do

= 1/2f - 1/do

≈ 1/2f (assuming 1/do is negligible compared to 1/2f)

Now, we need to determine the approximate value of 1/2f. Since we don't have the radius of curvature or focal length information, we cannot calculate an exact value. However, we can make an estimation based on the given information.

Assuming the large moon is roughly spherical, we can consider its diameter of 70.0 km as the approximate diameter of its curvature. The radius of curvature (R) would be half the diameter, or 35.0 km.

Since the focal length (f) of a spherical convex mirror is half the radius of curvature, we can estimate the focal length as 17.5 km.

Substituting this estimated value into the equation:

1/di ≈ 1/2f

= 1/(2 * 17.5 km)

≈ 1/35.0 km^-1

= 0.0286 km^-1.

Therefore, the approximate image distance (di) of the passing moon when reflected off the highly reflective coating on the spherical convex mirror is approximately 0.0286 km, or 28.6 meters.

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Answer:

P = M0 V / (1 - (V / C)^2)^1/2

Let V / C = X       unless V is a close to the speed of light (10% or so)

(1 - x^2)^1/2    is a small quantity and can be ignored at small speeds.

(1 - [1 - (V/C)^2]^-1/2 = (V/C)^2     using the first terms of the binomial expansion

P2 / P1 = V2 / V1 * (X2 / X1)^2

For V<<C     the effect is small and the momentum is merely doubled

Answer:

429.3 m

Explanation:

Speed=Distance÷Time

⇒Speed×Time=Distance

In this case,

Distance=27×15.9

              =429.3m

Hope it helps.

Answer:

The element manganese has seven valence electrons. A tin atom has 50 electrons. Tin has 5 energy level because it is in the 5th row of the periodic table

Explanation:

because the internet said so

Speed of the bricks at the top of hill is 6.26 m/s. c.)speed of the bricks at the top of hill is 14.14 m/s. d)minimum compression of spring necessary to get to the top of hill is 6.26 m. e) speed of the bricks at the top of hill with 2 m of initial compression and 15% energy dissipation is 13.04 m/s.

The capacity or power to do work, such as the capacity to move an object by application of force is called energy.

Initial potential energy of compressed spring is:

Ep = 1/2 kx^2 = 1/2 * 500 N/m * (2 m)^2 = 1000 J

k is spring constant, x is compression of the spring, and J is unit of energy in joules.

Final potential energy of the bricks is:

Ep = mgh = 100 N * 9.81 m/s^2 * 2 m = 1962 J

Ep = Ep

1/2 kx^2 = mgh

v = sqrt(2gh) = sqrt(2 * 9.81 m/s^2 * 2 m) = 6.26 m/s

Therefore, the speed of the bricks at the top of the hill is 6.26 m/s.

c.  Initial potential energy of compressed spring is: 1000 J

Ek = Ep = 1000 J

Kinetic energy of the bricks is given by:

Ek = 1/2 mv^2

1000 J = 1/2 * 100 N * v^2

v = sqrt(200 / 1) = 14.14 m/s

Therefore, the speed of the bricks at the top of the hill is 14.14 m/s.

d.  As, Ep = m g h

where m is mass of the bricks, g is acceleration due to gravity, and h is  height of the hill.

Ep = 100 N * 9.81 m/s^2 * 2 m = 1962 J

Ep = 1/2 kx^2 = 1962 J

1/2 * 500 N/m * x^2 = 1962 J

x = sqrt(2 * 1962 J / 500 N/m) = 6.26 m

Therefore, the minimum compression of the spring necessary to get to the top of the hill is 6.26 m.

e. If 15% of the energy is dissipated through friction, final kinetic energy of the bricks at the top of the hill will be 85% of initial potential energy of the compressed spring. Therefore,

0.85 * 1000 J = 1/2 mv^2

v = sqrt(170 / 1) = 13.04 m/s

Therefore, the speed of the bricks at the top of the hill with 2 m of initial compression and 15% energy dissipation is 13.04 m/s.

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The magnitude and direction of the electric field at that location is 900 N/C and upward. This is based on the formula for the electric field at a certain location.

The relation between the electric field and electrostatic force is given by

E = F/q

Where

We have

At that location, find the magnitude and direction of the electric field!

The magnitude of the electric field can be find by the formula above.
E = F/q

E = (27 × 10⁻³)/(-30 × 10⁻⁶)

E = - 900 N/C
For a negative charge, the direction of electric field is inward. It is the same with the direction of electric force. So, in this case, the direction of electric field is upward.

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Answer: Movement in which all positions of both the waves rotate around the directions at right angles to the axis of the wave's movement.

Explanation: Hope this help

Answer:

mass

gravitational pull

Answer:

F = 30 N

Explanation:

Given that,

Mass of a toy train, m = 1.5 kg

The acceleration of the toy-train, a = 20 m/s²

We need to find the force acting on it. We know that, net force acting on an object is given by :

F = ma

Substitute all the values,

F = 1.5 × 20

F = 30 N

Hence, the net force acting on the toy train is equal to 30 N.

No, a unit-wise analysis cannot tell about the equation constant. A unit-wise analysis involves checking the consistency of the units on both sides of an equation.

An evaluation of the consistency of the units employed in an equation or formula is known as a unit-wise analysis. Making ensuring that the units of each term on both sides of the equation are compatible with one another entails doing this.

A unit-wise analysis is used to check sure the equation makes sense in terms of dimensions. There is a unit of measurement that corresponds to every physical quantity, such as meters (m) for length, kilograms (kg) for mass, and seconds (s) for time. It is important to ensure that the units of the result and the original quantities match when performing mathematical operations on physical quantities.

It helps to ensure that the units of the quantities being compared in the equation match. However, the equation constant is a numerical value that is independent of the units used.

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Given data

*The given mass of the van is m = 402.89 kg

*The initial speed of the van is u_1 = 20.54 m/s

*The given mass of the compact car is M = 704.44 kg

*The initial speed of the compact car is u_2 = 26.62 m/s

The formula for the new speed of both the vehicles is given by the conservation of momentum as

Substitute the known values in the above expression as

Hence, the new speed of both the vehicles when they stick together is v = 24.40 m/s

Answer:

Physics Net Force

Explanation:

Physics Net Force

The net force is the combined force of all individual forces acting on an object. Newton's First Law can be seen to be the special case in the Second Law when F, the net force, is zero. When that happens, the acceleration a must also be zero.

Hope this helped you!!

The statement that best explains why the system looses energy is; the Collison of the molecules of hydrogen with the wall of the can carries off energy to the environment.

We know that energy is defined as the rate of doing work. Now the temperature of a gas is measure of the kinetic energy of the molecules of the body. In this case, the temperature of the hydrogen in the cannister has to do with how fast the molecules of the hydrogen are moving.

The higher the temperature, the faster the molecules of the hydrogen move. The lower the temperature, the slower the molecules of the hydrogen moves.

As such, the molecules collide with the walls of the canister, causing the canister molecules to vibrate and carry energy from the canister to the canister’s surroundings.

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Answer:

One atom will give electrons to another atom to fill its shell, this is an ionic bond. The atom giving away electrons becomes positive and the one recieving electrons becomes negative.

Explanation:

Answer: One atom will give electrons to another atom to fill its shell, this is an ionic bond. The atom giving away electrons becomes positive, and the one receiving electron becomes negative.

Explanation:

I did the Gizmo.

laws of reflection

I = r

angle of incident = angle of reflection

35 = 35

Answer:

(a) electrical energy or chemical energy

(b) sound energy, potential energy, light energy.

(c) Work (J) = Force (N) * Distance (m)

                   = 80 * 15

                   = 1200 Joules.

First find time period

\(\\ \bull\tt\longrightarrow Frequency=\dfrac{1}{Time\:Period}\)

\(\\ \bull\tt\longrightarrow Time\:Period=\dfrac{1}{Frequency}\)

\(\\ \bull\tt\longrightarrow Time\:Period=\dfrac{1}{256}=0.003s\)

Now

\(\\ \bull\tt\longrightarrow No\:of\:times\:it\:vibrate=5(0.003)=0.015times\)

Out of 150 approved mortgage applications, a random sample may have variable or interest-only mortgages.

we are given that a random sample of 150 approved mortgage applications is either variable or interest-only mortgages. A variable mortgage, also known as an adjustable-rate mortgage (ARM), is a type of mortgage in which the interest rate fluctuates based on market conditions. An interest-only mortgage is a type of mortgage in which the borrower only pays interest on the loan for a certain period of time before beginning to make principal payments.To determine what percentage of the sample is variable or interest-only mortgages, we would need more information on the breakdown of the sample. However, we know that these are two different types of mortgages that borrowers can choose from when applying for a mortgage.

A home loan application is a report submitted to a bank when you apply for a home loan to buy land. The application is extensive and includes information about the borrower's employment history, financial situation, and the property being considered for purchase, among other things.

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