Answers
Answer:
\( \frac{468}{14.4} = \frac{d}{16.8} \)
\(32.5 = \frac{d}{16.8} \)
\(d = 546\)
Wyatt can drive 546 miles on a full tank (16.8 gallons) of gas.
Related Questions
What is the value of | 3 | (PLEASE HELPP!!)
Answers
Scale Factor: 2; Center: (-2, 1)
Answers
Answer:
Brhaaliarwoiagsajaidgsiuaaidywlx
6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
Answers
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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PLS HELP ME
Number 1
Answers
the answer is 6 because theres need to be a total of 9 and they put 3 cups so 9 minus 3 equals 6
In 5 years, Nicole will
be old enough to vote in an election. The minimum age
for voting is at least 18 years. What can you say about
how old she is now? Write and solve an inequality to
show how old Nicole is now. Let a represent Nicole's
age now.
Answers
Answer:
Nicole is 13 years old because x + 5 = 18
Step-by-step explanation:
What should be done to solve the following equation? d - 5 = 3
Answers
Answer:
d=8
Step-by-step explanation:
Firstly you need to get d by itself. To get d by itself you need to get 5 onto the other side. To do that you need to add 5 to 3 (because adding is the opposite of addition). Therefore you will get 8! So d = 8
Answer:
add 5 both sides making it
d=5+3
solve 5+3
=8
d=8!!!Kate and Clare went for a bike ride through a park. They started their ride near the pond at 12:31 P.M. They finished near the basketball court at 1:30 P.M. How long did Kate and Clare ride their bikes?
Answers
Answer: 59 minutes.
Step-by-step explanation:
12:31-1:30 is 59 minutes
If the zeros of a quadratic functions are -2 and 4, which graph could represent the function? A. A parabola declines from (negative 3 point 1, 10) through (negative 3, 8), (negative 2, 0), (negative 1, negative 4), (1, negative) and rises through (2, negative 8), (3, negative 4), (4, 0), (5, negative 6), and (5 point 5, 10). B. A parabola declines from (negative 5 point 8, 10), (negative 5, 7), (negative 4, 0), (negative 8, negative 2), (negative 1, negative 8 point 4) and rises through (2, 0), (3, negative 6) and (3 point 9, 10). C. A downward open parabola rises from (negative 6 point 2, negative 10), (negative 5 point 2, negative 6), (negative 4, 0), (negative 3, 1) and declines through (negative 1 point 4, negative 2), (1, negative 4), (0, negative 8), and (0 point 5, 10). D. A downward open parabola rises from (negative 0 point 5, negative 10), (0, negative 8), (1, negative 4), (2, 0), (3, 1), and declines through (5, negative 4), (6, negative 8), and (6 point 5, negative 10) on the x y coordinate plane.
Answers
Option A. The only graph that could represent the function with the zeros of -2 and 4 is the graph is : A parabola declines from (negative 3 point 1, 10) through (negative 3, 8), (negative 2, 0), (negative 1, negative 4), (1, negative) and rises through (2, negative 8), (3, negative 4), (4, 0), (5, negative 6), and (5 point 5, 10).
How to determine the graphThe zeros of a quadratic function are the x-values where the function equals zero (where it crosses the x-axis). In this case, you mentioned that the zeros of the function are -2 and 4.
Looking at the provided options:
A. This graph crosses the x-axis at (-2, 0) and (4, 0), which are indeed the zeros of the function. Therefore, this could be a possible representation of the function.
B. This graph crosses the x-axis at (-4, 0) and (2, 0). These are not the zeros given for the function (-2 and 4), so this graph is not a possible representation of the function.
C. This graph crosses the x-axis at (-4, 0), but it never crosses at x=4. Instead, it crosses at x=2. Therefore, this is not a possible representation of the function.
D. This graph crosses the x-axis at (2, 0), but does not cross the x-axis at x=-2. Therefore, this is not a possible representation of the function.
So, the only graph that could represent the function with the zeros of -2 and 4 is the graph provided in Option A.
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b. Triangle ABC is similar to triangle EBD. Find the lengths of segments BD and BE. Show all your work.
Answers
Answer:
BD=4/3 BE=5/3
Step-by-step explanation:
by pythag theorem we can see that AC=3 and because CPCTC
AC/DE=AB/EB=CB/DB we can see that CB/DB=3/1 and CB is 4 therefore DB = 4/3 do same with BE and we get solution above.
u = 63 cm, t = 34 cm and ∠T=158°. Find all possible values of ∠U, to the nearest 10th of a degree.
Answers
Answer:
{}
Step-by-step explanation:
Thats actually the answer believe it or not :)
In a survey based on a random sample of high school seniors at Roosevelt High School,
60% of those surveyed said they do more than 2.5 hours of homework per day. Based on this
data which of the following conclusions are valid? (Choose 2)
A) Less than 60% of all seniors at Roosevelt do more than 2.5 hours of homework per day.
B) About 60% of seniors at Roosevelt do more than 2.5 hours of homework per day.
C) About 40% of all seniors at Roosevelt do less than 2.5 hours of homework per day.
D) 40% of seniors at Whitney do no homework.
Answers
-1/4(d+1)<2
HELP ME PLEASE
Answers
Answer: u suck at math just dont do it duh
Step-by-step explanation: its five
Work out the volume of the prism height of 12 4 and five
Answers
The calculated volume of the prism is 702 cubic cm
Finding the volume of the prismFrom the question, we have the following parameters that can be used in our computation
The trapezoidal prism (see attachment)
The formula of the volume of a trapezoidal prism is
Volume = Base area * Height
Where we have
Base area = 1/2 * (8 + 10) * 6
Evaluate the sum of 8 and 10
Base area = 1/2 * 18 * 6
Evaluate the products of 1/2, 18 and 6
Base area = 54
Also, we have
Height = 13
So, the volume is calculated as
volume = 13 * 54
Evaluate
volume = 702
Hence, the volume of the prism is 702 cubic cm
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!!PLEASE HELP WILL GIVE BRAINLIST!!
Determine whether the numbers can represent the side lengths of a triangle. If they can, classify the triangle as right, acute, or obtuse.
Answers
The side lengths will all make up a triangle, each can be classified as:
6. Isosceles triangle 7. Obtuse triangle 8. Scalene triangle
How to Classify a Triangle?To determine whether the given numbers can represent the side lengths of a triangle or not, we need to check if the sum of the two smaller sides is greater than the largest side.
If this condition is satisfied for all three pairs of sides, then the numbers can represent the side lengths of a triangle.
6. The numbers 4, 5, and 5 can represent the side lengths of a triangle because 4 + 5 > 5, 5 + 4 > 5, and 5 + 4 > 5. This triangle is isosceles because two sides have the same length.
7. The numbers 10, 17, and 26 can represent the side lengths of a triangle because 10 + 17 > 26, 17 + 26 > 10, and 26 + 10 > 17. This triangle is obtuse because the square of the longest side (26^2 = 676) is greater than the sum of the squares of the other two sides (10^2 + 17^2 = 369).
8. The numbers 2, 10, and 12 can represent the side lengths of a triangle because 2 + 10 > 12, 10 + 12 > 2, and 12 + 2 > 10. This triangle is scalene because all three sides have different lengths.
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Magdalena buys a lawnmower that costs $122.50. The
sales tax in her town is 8%. Write an equation of the
form y=kx to represent the amount of tax on an item
that costs x dollars. Use the equation to find the
amount of tax on the lawnmower. SHOW YOUR WORK. i need help asap!
Answers
Answer:
Here u go :3
Step-by-step explanation:
p = price
p=122.50x
x = 8%
122.50 * 0.08 = 9.80
The amount of sales tax on the lawnmower is $9.80.
A sales tax is a form of tax that is levied on the purchase of goods and services. Taxes increase the cost of a good or service. The amount of tax paid can bee determined by multiplying the tax rate by the cost of the lawnmower.
The amount of tax paid = cost of the lawnmower x sales tax
= $122.50 x 0.08
= $9.80
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Hi my name is Shila I'm Mimi's mom can you help me with this problem
Answers
Answer:
\(\begin{gathered} 27\times52=(20+7)\times(50+2)=(20+7)\times50+(20+7)\times2 \\ =(20\times50)+(7\times50)+(20\times2)+(7\times2) \end{gathered}\)\(=1000+350+40+14\)Explanation:
Given the expression;
\(27\times52\)We can rewrite it as;
\(\begin{gathered} 27\times52=(20+7)\times(50+2)=(20+7)\times50+(20+7)\times2 \\ =(20\times50)+(7\times50)+(20\times2)+(7\times2) \end{gathered}\)\(=1000+350+40+14\)I need help with these 2 questions
Answers
Answer:
use this formula 2 pie r square
Please help me it's very hard
Answers
B. No Solution
Select the statement that best justifies the conclusion based on the given information. If x + 5 = 15, then x = 10.
Answers
The Subtraction property of equality justifies the conclusion based on the given information.
Subtraction Property of Equality Definition:The subtraction property of equality states that when the same number is subtracted from both sides of an equality, then the two sides of the equation still remain equal. In simple words, we can say that when a number is subtracted from one side of an equation, the same number must be subtracted from the other side of the equality.
if a = b
then;
a-c = b-c
We have:
If x + 5 = 15
By subtraction property of equality:
Subtract 5 from both sides we have;
x = 10
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using monitoring the gfture 2017 data, we examline whther a relationshiop exists bewteeen the race/thnicity of a studetn and how the studetn rates the impoiratnace being a community
Answers
Community colleges in the United States play an important role in higher education. In United States, everyone monitors they community colleges are primarily her two-year institutions of higher education that focus on teaching and learning and workforce preparation.
Community colleges are open access institutions that offer economically affordable entry into higher education. About half of first-time college-going students enroll in community colleges, which serve as her transition route to four-year colleges (Beach, 2011). However, despite the important role and primary focus of community colleges, students may view community college instruction as inferior and undesirable to her four-year college (Dougherty, Lahr, & Morest, 2017; Twombly, 2001; Twombly & Townsend, 2008). This general dissatisfied view of community college instruction has much to do with the historical legacy of community colleges, where most two-year schools are either officially called "junior colleges" or "junior colleges." is called Community colleges have reason to brag about progress. It tends to have a higher proportion of female and minority teachers compared to traditional her four-year colleges (Antonio, 2002; Marcotte, Bailey, Borkowski, & Kientz, 2005; Turner, 2001). While the high recruitment rate of minority teachers is laudable, most higher education institutions are still predominantly white and male dominated (with the exception of those serving minorities). Overall, despite the high proportion of women and minority teachers, empirical studies show that such teachers experience high levels of stress and frustration with the way students are treated in the classroom. (Allen et al., 2002; Pittman, 2010). For many teachers and teachers of color, the classroom environment serves as a reminder of the unfortunate social ills that plague our society (Harlow, 2003; Seo & Hinton, 2009).
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What is the graph of the inequality y < (x+1)^3?
Answers
Answer:
Simplify
(
x
+
1
)
3
.
y
<
x
3
+
3
x
2
+
3
x
+
1
Step-by-step explanation:
Find the area of the trapezoid. TOP 11ft, RIGHT4√3ft , BOTTOM 15ft ,LEFT 8ft
Answers
Answer:
\(52\sqrt{3} ft^{2}\)
Step-by-step explanation:
Please refer to the attached picture.
First we will find the area of rectangle BCDE.
Area of Rectangle = Length x Breadth = DE x CD
= 11 x \(4\sqrt{3}\)
\(=44\sqrt{3} ft^{2}\)
Next we will find Area of Triangle ABE.
Area of Triangle = 0.5 x Base x Height
\(0.5*4*4\sqrt{3} \\=8\sqrt{3} ft^{2}\)
Area of Trapezoid = Area of Rectangle + Area of Triangle
\(=44\sqrt{3} +8\sqrt{3} \\=52\sqrt{3} ft^{2}\)
Answer:
A = 52\(\sqrt{3}\) ft² ≈ 90.1 ft²
Step-by-step explanation:
the area (A) of a trapezoid is calculated as
A = \(\frac{1}{2}\) h (b₁ + b₂ )
where h is the perpendicular height and b₁ , b₂ the parallel bases
here h = 4\(\sqrt{3}\) , b₁ = 15 , b₂ = 11 , then
A = \(\frac{1}{2}\) × 4\(\sqrt{3}\) × (15 + 11)
= 2\(\sqrt{3}\) × 26
= 52\(\sqrt{3}\) ft²
≈ 90.1 ft² ( to the nearest tenth )
Math Homework: Unit 3 Assignment
Answers
Solve the inequality for y.
y-5<-14
Answers
negative 9 remember that
Move the constant to the right-hand side and change its sign and calculate
A two-child family is selected at random. Let B denote the event that at least one child is a boy, and let D denote the event that
the genders of the two children differ. Find the union of B and D. (1 point)
The union is (bb, gg); the first letter denotes the gender of the firstborn child, and the second letter denotes the gender of the
second child.
The union is (bg. gb); the first letter denotes the gender of the firstborn child, and the second letter denotes the gender of the
second child.
The union is {bb, bg, gb, gg); the first letter denotes the gender of the firstborn child, and the second letter denotes the gender of
the second child.
The union is (bb, bg. gb); the first letter denotes the gender of the firstborn child, and the second letter denotes the gender of the
second child.
Answers
With the help of probability we can say that, DUM={GG,BB,GB,BG).
What is Probability?Probability is the concept that describes the likelihood of an event occurring.
In real life, we frequently have to make predictions about how things will turn out.
We may be aware of the result of an occurrence or not.
When this occurs, we state that there is a possibility that the event will occur.
In general, probability has many excellent applications in games, commerce, and this newly growing area of artificial intelligence
The chance of an event can be calculated using the probability formula by only dividing the favourable number of possibilities by the total number of potential outcomes.
hence, DUM={GG,BB,GB,BG)
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Sadie and Connor both play soccer. Connor scored 2 times as many goals as Sadie. Together they scored 9 goals. Could Sadie have scored 4 goals? Why or why not?
Answers
Answer:
No.
Step-by-step explanation:
Sadie goals = s
that means
2s+ s = 9 (2s is Connor's goals. Twice Sadie's)
3s=9
s=3
Sadie scored 3 goals
A paint mixer wants to mix paint that is 30% gloss with paint that is 15% gloss to make 3.75 gallons of paint that is 20% gloss. How many gallons of each paint should the paint mixer mix together?
Answers
Answer:
1.25 gallons of 30% gloss and 2.5 gallons of 15% glossStep-by-step explanation:
Gloss content is same at the input and output.
Let 30% gloss is x gallons, then 15% gloss is (3.75 - x) gallons.
We have the following equation:
0.3x + 0.15(3.75 - x) = 0.2*3.750.3x + 0.5625 - 0.15x = 0.750.15x = 0.75 - 0.56250.15x = 0.1875x = 0.1875/0.15x = 1.25 gallonsAmount of 15% gloss:
3.75 - 1.25 = 2.5 gallons30% gloss is 1.25 gallons and 15% gloss is 2.5 gallons
Mrs. Hensley , the P.E teacher, is pairing off students to race against each other. Eli can run 7 yards per second , and Aaron can run 8 yards per second, Mrs. Hensley decides to give Eli a head start of 5 yards since he runs more slowly . Once the students start running, Aaron will quickly catch up to Eli. How long will that take?
Answers
Answer:
5 Seconds
Step-by-step explanation:
Aaron is able to run one yard per second faster than Eli
So if Eli gets a head start of 5 yards it will take Aaron 5 seconds to catch up to him.
Mr. Woods is buying ice cream for two of his students, Moses and Gaby. They each get one scoop of ice cream. Gaby wants ice cream in a cone, but she is a slow eater. Moses wants a cup because he is a bit messy and doesn’t want to drip any ice cream. Each scoop is a perfect sphere and has a radius of 5 cm. The height of the cup and cone are both 12 cm. and the radius of each container is the same as each scoop of ice cream.
Answers
the volume of one scoop of ice cream is 523.6 cc. The cup can hold a volume of 942.5 cc, which is more than one scoop of ice cream. Therefore, Moses's cup can hold one scoop of ice cream without overflowing or spilling.
let's break down the problem step by step.
First, we need to calculate the volume of one scoop of ice cream. Since each scoop is a perfect sphere with a radius of 5 cm, we can use the formula for the volume of a sphere, which is:
V = (4/3)πr³
where V is the volume and r are the radius. Substituting r = 5 cm, we get:
V = (4/3)π(5³) = 523.6 cubic centimeters (cc)
So, the volume of one scoop of ice cream is 523.6 cc.
Next, we need to calculate the volume of the cup and the cone. Since both have the same radius as the scoop of ice cream, we can use the formula for the volume of a cylinder and a cone, respectively, with height 12 cm and radius 5 cm:
For the cup:
\(V_{cup}\)= πr²h = π(5²) (12) = 942.5 cc
For the cone:
\(V_{cone}\) = (1/3)πr²h = (1/3)π(5²)(12) = 314.2 cc
So, the volume of the cup is 942.5 cc, and the volume of the cone is 314.2 cc.
Now, we can determine how much ice cream each container can hold. Since each person gets one scoop of ice cream, we need to compare the volume of one scoop of ice cream to the volume of each container.
For Gaby's cone:
We know that the volume of one scoop of ice cream is 523.6 cc. The cone can hold a volume of 314.2 cc, which is less than one scoop of ice cream. Therefore, Gaby's cone can only hold one scoop of ice cream.
For Moses's cup:
Again, the volume of one scoop of ice cream is 523.6 cc. The cup can hold a volume of 942.5 cc, which is more than one scoop of ice cream. Therefore, Moses's cup can hold one scoop of ice cream without overflowing or spilling.
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The complete question: What is the volume of ice cream in each scoop and what is the total volume of ice cream that Mr. Woods needs to buy for Moses and Gaby? Also, what is the total surface area of the ice cream exposed to the air in each container (cone and cup)?
Eliana loves music, especially 80's punk rock. Eliana looked at the number of songs in her itunes account and she has 6 less than 4 times her best friend. Eliana's classmate David has 3 more than double her best friend. When talking to her Social Studies teacher, Eliana found out social study teacher has 7 more than two times the number of songs in his library than Eliana. Define a variable, then write and solve an equation. If the total number of songs is 382, how many songs does Eliana, her best friend, David and her social study teacher have?
Answers
Answer
Step by step explantion:
bsf= 26
Eliana:98
SS teacher=203
David=55
Step-by-step explanation:
m= music
bsf: m
eliana:4m-6
David:2m+3
SS teacher: 2(4m-6)+7
m+4m-6+2m+3+8m-12+7
382=15m-7
7+ +7
389=15m
/15m /15m
m=26
multiply 26 to each one of them