please help. thank you.

Edna should leave at 2:07 PM in order to arrive at Jake's party by 2:30 PM

To determine the time Edna should leave, we need to subtract the travel time from the desired arrival time.

If Edna needs to be at Jake's party at 2:30 PM and it takes her 23 minutes to drive there, she should leave 23 minutes before 2:30 PM.

To calculate the departure time, we subtract 23 minutes from 2:30 PM:

2:30 PM - 23 minutes = 2:07 PM

Therefore, Edna should leave at 2:07 PM in order to arrive at Jake's party by 2:30 PM

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Answer:

1/6

Step-by-step explanation:

The centipede that Maria measured was 1 1/12 inches long. If you convert this to an improper fraction it is equal to 13/12 inches. Now to find how much longer Maria's centipede was than Jeromes, you just take 11/12 and minus it from 13/12 which is equal to 2/12 of an inch, which then simplifies to 1/6 of an inch.

The procedure which is deemed to be the type of sample in discuss is; representative sample are free of bias.

Representative sampling and random sampling are two techniques used to help ensure data is free of bias. A representative sample on the other hand is a group or set chosen from a larger statistical population according to specified characteristics. A random sample is a group or set chosen in a random manner from a larger population.

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Answer:

Step-by-step explanation:

v = l * w * h

v = x * 22 * 28

v = 616x

Using a linear function, we have that:

a) The costs are:

i. C(x) < $1.3.

ii. C(x) > $2.3.

b) The times are:

i. Less than 9 minutes.

ii. At least 16 minutes.

A linear function is modeled by:

y = mx + b

In which:

In this problem, the y-intercept is of 0.3, while the slope is of 0.2, hence the cost for a call of x minutes is:

C(x) = 0.3 + 0.2x.

For calls shorter than 5 minutes, the costs are:

C(x) < 0.3 + 0.2 x 5

C(x) < $1.3.

For calls longer than 10 minutes, the costs are:

C(x) > 0.3 + 0.2 x 10

C(x) > $2.3.

The cost is less than $2.10 for calls of less than x minutes, found as follows:

0.3 + 0.2x < 2.1

0.2x < 1.8

x < 9.

The cost is greater or equal to $3.50 for calls of at least x minutes, found as follows:

0.3 + 0.2x >= 3.5

0.2x >= 3.2

x >= 16.

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A p-value is a measure of the strength of evidence against the null hypothesis in a statistical hypothesis test. It represents the probability of obtaining the observed data or more extreme results, assuming that the null hypothesis is true.

In general, a smaller p-value provides stronger evidence against the null hypothesis. Therefore, in the given scenario, a p-value of 0.02 would provide stronger evidence against the null hypothesis compared to a p-value of 0.03.

A p-value of 0.02 indicates that there is a 2% chance of obtaining the observed data or more extreme results if the null hypothesis is true. This suggests that the observed data is relatively unlikely under the assumption of the null hypothesis, providing stronger evidence against it.

On the other hand, a p-value of 0.03 indicates that there is a 3% chance of obtaining the observed data or more extreme results if the null hypothesis is true. Although this still suggests that the observed data is unlikely under the null hypothesis, it is not as strong evidence as a p-value of 0.02.

In summary, a lower p-value indicates that the observed data is less likely to occur under the null hypothesis, providing stronger evidence against it. Therefore, a p-value of 0.02 would provide stronger evidence against the null hypothesis compared to a p-value of 0.03.

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One strategy to eliminate a variable is by multiplying the first equation by 5 and the second equation by 2 and then adding the resulting equations or by multiplying the first equation by 3 and the second equation by 7 and then adding the resulting equations

From the question, we are to determine the strategies that would eliminate a variable in the given system of equations

The given system of equations is

-7x + 2y = 5

3x - 5y = -5

We can eliminate the variable y multiplying the first equation by 5 and the second equation by 2

That is,

5 × [-7x + 2y = 5

2 × [3x - 5y = -5

--------------------------

-35x + 10y = 25

6x - 10y = -10

------------------------

-29x = 15

Also,

We can eliminate the variable x by multiplying the first equation by 3 and the second equation by 7

That is,

3 × [-7x + 2y = 5

7 × [3x - 5y = -5

-------------------------

-21x + 6y = 15

21x - 35y = -35

---------------------

-29y = -20

Hence, one strategy is by multiplying the first equation by 5 and the second equation by 2 and then simplify by adding

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Component 3 must be started on day 197 to meet the delivery date of day 200.

To illustrate the backward schedule, we need to start from the delivery date (day 200) and work our way backward, taking into account the lead times and dependencies of each operation.

(a) Backward schedule:

Operation    |  Work Center  |  Time (hours)  |  Start Day

--------------------------------------------------------

Final Assembly |   Work Center 1  |        1       |     200

Sub-assembly 1 |   Work Center 2  |        2       |     199

Component 4     |   Work Center 3  |        3       |     197

Component 2     |   Work Center 4  |        4       |     196

Component 3     |   Work Center 5  |        3       |     ????

(b) To identify when component 3 must be started to meet the delivery date, we need to consider its dependencies and lead times.

From the backward schedule, we see that component 3 is required for sub-assembly 1, which is scheduled to start on day 199. The time required for sub-assembly 1 is 2 hours, which means it should be completed by the end of day 199.

Since component 3 is needed for sub-assembly 1, we can conclude that component 3 must be started at least 2 hours before the start of sub-assembly 1. Therefore, component 3 should be started on day 199 - 2 = 197 to ensure it is completed and ready for sub-assembly 1.

Hence, component 3 must be started on day 197 to meet the delivery date of day 200.

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One problem with the arithmetic mean is that it is influenced by outliers. Because with the presence of outliers , the arithmetic mean will be pulled towards the outlier. So, the correct option is A) it is influenced by outliers.

The arithmetic mean is calculated by summing up all the observations in a dataset and dividing by the number of observations. While it is a commonly used measure of central tendency, it has some limitations. One of the main problems with the arithmetic mean is that it can be strongly influenced by outliers.

An outlier is an observation that is very different from the other observations in the dataset. When outliers are present, the arithmetic mean can be pulled towards the outlier and may not be a good representation of the typical value in the dataset.  So, the answer is A) it is influenced by outliers.

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Answer:

  y = 4x

Step-by-step explanation:

You want an equation that represents the proportional relationship between ounces of chocolate (x) and ounces of almonds (y) when we know (x, y) = (2, 8).

A proportional relation can be written using the equation ...

  y = kx

where k is a constant.

The value of k can be found if a pair of values is known for x and y.

  k = y/x . . . divide by x

  k = 8/2 = 4 . . . . use (x, y) = (2, 8) from the table.

The equation for the relationship is ...

  y = 4x

The proportional relationship that accounts between the amount of dark chocolate and the amount of almonds is y = 4x.

What is ratio and proportion?
Majority of the explanations for ratio and proportion use fractions. A ratio is a fraction that is expressed as a:b, but a proportion says that two ratios are equal. In this case, a and b can be any two integers. An equation known as proportion shows that the two ratios presented are equal to one another. A ratio is the comparative or condensed form of two quantities of the same type. We may determine how many times one quantity is equal to another using this relationship. The ratio can be defined as the number that can be used to represent one quantity as a percentage of another.

Given, for 2 ounces of dark chocolate(x), 8 ounces of almonds(y) are put in.
Taking the ratio as y to x, we have:
y/x = 8/2 ⇒ y/x = 4 ⇒ y = 4x
Thus, the proportional relationship that accounts between the amount of dark chocolate and the amount of almonds in each package of Sweet and Salty trail mix is y = 4x.

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Answer:

3rd option

Step-by-step explanation:

the denominator cannot be zero as this would make the expression undefined.

equating the denominator to zero and solving gives the values that x cannot be.

x² - 7x - 18 = 0 ← in standard form

(x - 9)(x + 2) = 0 ← in factored form

equate each factor to zero and solve for x

x - 9 = 0 ⇒ x = 9

x + 2 = 0 ⇒ x = - 2

then

x = - 2, x = 9 ← are the excluded values

Answer:

\(\frac{27y^6}{8x^{12}}\)

Step-by-step explanation:

1) Use Product Rule: \(x^ax^b=x^{a+b}\).

\((\frac{3x^{-5+2}{y^3}}{2z^0yx}) ^3\)

2) Use Negative Power Rule: \(x^{-a}=\frac{1}{x^a}\).

\((\frac{3\times\frac{1}{x^3} y^3}{2x^0yx} )^3\)

3) Use Rule of Zero: \(x^0=1\).

\((\frac{\frac{3y^3}{x^3} }{2\times1\times yx} )^3\)

4) use Product Rule: \(x^ax^b=x^{a+b}\).

\((\frac{3y^3}{2x^{3+1}y} )^3\)

5) Use Quotient Rule: \(\frac{x^a}{x^b} =x^{a-b}\).

\((\frac{3y^{3-1}x^{-4}}{2} )^3\)

6) Use Negative Power Rule: \(x^{-a}=\frac{1}{x^a}\).

\((\frac{3y^2\times\frac{1}{x^4} }{2} )^3\)

7) Use Division Distributive Property: \((\frac{x}{y} )^a=\frac{x^a}{y^a}\).

\(\frac{(3y^2)^3}{2x^4}\)

8) Use Multiplication Distributive Property:  \((xy)^a=x^ay^a\).

\(\frac{(3^3(y^2)^3}{(2x^4)^3}\)

9) Use Power Rule: \((x^a)^b=x^{ab}\).

\(\frac{27y^6}{(2x^4)^3}\)

10)  Use Multiplication Distributive Property:  \((xy)^a=x^ay^a\).

\(\frac{26y^6}{(2^3)(x^4)^3}\)

11) Use Power Rule: \((x^a)^b=x^{ab}\).

\(\frac{27y^6}{8x^12}\)

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Answer:

\(\displaystyle \frac{27y^{6}}{8x^{12}}\)

Step-by-step explanation:

\(\displaystyle \biggr(\frac{3x^{-5}y^3x^2}{2z^0yx}\biggr)^3\\\\=\biggr(\frac{3x^{-5}y^2x}{2}\biggr)^3\\\\=\frac{(3x^{-5}y^2x)^3}{2^3}\\\\=\frac{3^3x^{-5*3}y^{2*3}x^3}{8}\\\\=\frac{27x^{-15}y^{6}x^3}{8}\\\\=\frac{27y^{6}x^3}{8x^{15}}\\\\=\frac{27y^{6}}{8x^{12}}\)

Notes:

1) Make sure when raising a variable with an exponent to an exponent that the exponents get multiplied

2) Variables with negative exponents in the numerator become positive and go in the denominator (like with \(x^{-15}\))

3) When raising a fraction to an exponent, it applies to BOTH the numerator and denominator

Hope this helped!

True, The statement 5^7 = k is equivalent to log7 (5) = k, and the value of k is given by k = 5·log7(5)/log7(7)

The statement log7 (5) = k is equivalent to 5 = 7k, so k = log7(5)/log7(7). The equivalent form is k = log5/log7, where both the numerator and denominator are written in the same base log.

This can be seen by using the change of base formula which is a rule that simplifies writing logarithms with a base other than 10 or e.

This formula states that a logarithm with a base b can be converted to a logarithm with a base a using the following formula: loga(x) = logb(x) / logb(a).

For the case given in the question, we have:5·log7(5) = k·log7(7)Which can be rearranged to:log7(5^5) = log7(7^k). Then, using the fact that loga(x) = loga(y) if and only if x = y, we get:5^5 = 7^k

This means that k = log7(5^5)/log7(7), which simplifies to k = 5·log7(5)/log7(7).

Therefore, the statement 5^7 = k is equivalent to log7 (5) = k, and the value of k is given by k = 5·log7(5)/log7(7)

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Answer:

98%.

Step-by-step explanation:

The following data were obtained from the question:

Test 1 (T₁) = 83%

Test 2 (T₂) = 91%

Test 3 (T₃) = 88%

Test 4 (T₄) =?

AVERAGE = 90%

We can obtain the score of 4th test by doing the following:

AVERAGE = (T₁ + T₂ + T₃ + T₄) /4

90 = (83 + 91 + 88 + T₄) /4

90 = (262 + T₄) /4

Cross multiply

90 × 4 = 262 + T₄

360 = 262 + T₄

Collect like terms

360 – 262 = T₄

T₄ = 98%

Therefore, Sam need to score 98% in the 4th test in order to have an average score of 90%.

Answer: 12

Step-by-step explanation: Finding area of triangles. To find a triangle's area, use the formula area = 1/2 * base * height. Choose a side to use for the base, and find the height of the triangle from that base. Then, plug in the measurements you have for the base and height into the formula.

Answer:

Distribute 1.2 to 6.3 and -7x

Combine 3.5 and 7.56

suhtract 11.06 from both sides

Answer: 17/4

Step-by-step explanation:

multiply the 4's together then add the numerator of the fraction.

Train a total of 200 miles each week. 160 miles I bike, 32 miles I run, 8 miles I swim.

What do you mean by Simultaneous linear equations?

A system of simultaneous linear equations is any pair of linear equations or more that have the same unknown variables in common. To solve such a system, one must identify values for the unknown variables that simultaneously satisfy each of the equations. A system of simultaneous linear equations is any pair or group of linear equations where each equation has the same unknown variables. Finding values for the unknown variables that simultaneously satisfy each equation in such a system is the first step in its solution.

according to the question,

you bike five times as far as I run and you run four times as far as iswim. you train a total of 200 miles each week.

let, I swim x miles then I run 4x times and I bike 20x miles.

so, 4x+x+20x=200

by solving linear equations,

we get, x=8

hence,160 miles I bike.

32 miles I run.

8 miles I swim.

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Answer:

12, Brian rides 12 miles in all in 3 days.

Step-by-step explanation:

We know that each day Brian rides his bike for 4 miles, we need to figure out how many miles he rides in 3 days.

4 miles times 3 days = Total number of miles that Brian rides

Brian rides 12 miles in 3 days

To determine if a function crosses the horizontal asymptote, analyse the behavior of the function as it approaches the asymptote and on either side of it.

1. Identify the horizontal asymptote of the function. The horizontal asymptote is a horizontal line that the function approaches as the independent variable (usually denoted as x) goes to positive or negative infinity. It is often denoted by a horizontal line y = a, where "a" is a constant.

2. Examine the behavior of the function as x approaches positive infinity. Evaluate the limit of the function as x goes to positive infinity. If the limit is equal to the value of the horizontal asymptote, then the function does not cross the asymptote. However, if the limit does not equal the asymptote, move to the next step.

3. Examine the behavior of the function as x approaches negative infinity. Evaluate the limit of the function as x goes to negative infinity. If the limit is equal to the value of the horizontal asymptote, then the function does not cross the asymptote. If the limit does not equal the asymptote, proceed to the next step.

4. Investigate the behavior of the function around critical points or points where the function changes its behavior. These points may include the x-intercepts or vertical asymptotes. Determine if the function crosses the asymptote around these points by analyzing the behavior of the function in their vicinity.

If, at any point in this process, the function crosses the horizontal asymptote, then it does not have a true horizontal asymptote. However, if the function approaches the asymptote and does not cross it at any point, then it has a horizontal asymptote.

It's important to note that some functions may have multiple horizontal asymptotes or no horizontal asymptote at all. The steps outlined above are a general guideline, but the specific behavior of the function needs to be analyzed to make a conclusive determination.

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It depends on the rotational speed of the wheel. To calculate this speed, we need to know the angular velocity of the wheel.

The maximum speed of a point on the outside of the wheel, 15 cm from the axle, if we assume that the wheel is rotating at a constant rate, we can use the formula v = rω, where v is the speed of the point on the outside of the wheel, r is the radius of the wheel (15 cm in this case), and ω is the angular velocity of the wheel. Therefore, the maximum speed of a point on the outside of the wheel would be directly proportional to the angular velocity of the wheel.
The formula to calculate the maximum linear speed (v) is:
v = ω × r
where v is the linear speed, ω is the angular velocity in radians per second, and r is the distance from the axle (15 cm, or 0.15 meters in this case).
Once you have the angular velocity (ω) of the wheel, you can plug it into the formula and find the maximum speed of a point on the outside of the wheel.

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Answer:

A: 6x⁸y⁵

B: 4x⁵z⁸

C: 48a¹²b⁵

D: 6s⁹t³

Step-by-step explanation:

When you multiply 2 exponents together, you add them. When you power an exponent, you multiply the 2 exponents together,

3x²2y⁴(2x⁶y)

6x⁸y⁵

xz³(4x⁴z⁵)

4x⁵z⁸

(4a³)²(3a⁶b⁵)

16a⁶(3a⁶b⁵)

48a¹²b⁵

6s⁵t(s⁴t²)

6s⁹t³

To evaluate the flux integral ∬s F·dA over the surface S of a sphere with radius a = 2, we can use the Divergence Theorem. The final result of the evaluation is 256π.

The Divergence Theorem states that the flux integral ∬s F·dA over a closed surface S can be evaluated as the triple integral of the divergence of F over the region enclosed by S. In this case, the surface S is a sphere with radius a = 2, centered at the origin.

First, we need to calculate the divergence of the vector field F. The divergence of a vector field F = (F₁, F₂, F₃) is given by div(F) = ∂F₁/∂x + ∂F₂/∂y + ∂F₃/∂z. By evaluating the partial derivatives, we obtain:

div(F) = 4xy³z + 1 - 6x²y³z².

Next, we consider the outward unit normal vector dA. For a sphere centered at the origin, the unit normal vector points outward and is given by dA = (x/r, y/r, z/r), where r represents the distance from the origin. In this case, r = 2, so dA = (x/2, y/2, z/2).

Applying the Divergence Theorem, the flux integral over the sphere S becomes a volume integral:

∬s F·dA = ∭v div(F) dV,

where v represents the volume enclosed by S. Since S is a sphere, the volume integral can be evaluated using spherical coordinates.

Performing the necessary calculations, the final result is ∬s F·dA = 256π.

Therefore, the flux integral over the surface of the sphere is 256π.

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Answer:

Step-by-step explanation:

Given the equation x + 5 = 1, to get the solution to the equation, we need to find the value of x

Step 1: Subtract 5 from both sides of the equation

x+5-5 = 1-5

x = 1-5

Step 2: Find the value of the unknown variable x

x = -4

The solution to the equation is x = -4

Statistics expert daniel yankelovich believes that middle-class values give Americans a certain amount of self-esteem and a fairly clear idea of who they are.

This is the title that is used to refer to the people that have being trained in such a way that they are able  to apply statistical approaches and methods to the real life problems that exists in the environment.

They are known to be able to get the solutions to problems by the use of models of statistics and analyzing them as well.

Hence we can say that Statistics expert daniel yankelovich believes that middle-class values give Americans a certain amount of self-esteem and a fairly clear idea of who they are

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The distance of AX, A(-4, 5), X(1, -2) is 8.6

The distance formula is used to find the distance (shortest path) between two points.

The distance formula is

\(d = \sqrt{(x_2 - x_1)^{2} + (y_2 - y_1)^{2} } \\d = \sqrt{(-4 - 1)^{2} + (5 - (-2))^{2} } \\d = \sqrt{(-5)^{2} + (7)^{2} } \\d = \sqrt{25 + 49}\\ d = \sqrt{74}\)

d = 8.6

Therefore, the distance of AX, A(-4, 5), X(1, -2) is 8.6

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Answer:

game c

Step-by-step explanation:

because the slope went up more on level 2 during game c then any other game

predicted value of the slope , A regression model called simple linear regression uses a straight line to calculate the association between one independent variable and one dependent variable.

When modeling the relationship between a scalar answer and one or more explanatory variables in statistics, linear regression is a linear method. Simple linear regression is used when there is only one explanatory variable, and multiple linear regression is used when there are numerous variables.

A regression model called simple linear regression uses a straight line to calculate the association between one independent variable and one dependent variable. Both variables ought to have numerical values.

When the parameters are linear, a regression equation (or function) is said to be linear in statistics. Although the predictor variables can be transformed in ways that result in curvature, the equation must be linear in the parameters.

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in linear regression, the fitted value is the:  predicted value of the dependent variable

When you enter the values of the predictors, factor levels, and other inputs into a statistical model, the predicted mean response value is known as the fitted value.

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Answer:

if both the shorter ends are as long as or longer than the longer end when combined.

Step-by-step explanation: