Answer:
20
Step-by-step explanation:
Kyala =x+24
ze=x
in 2 years=2 (x+24)=2x+48
x= 2x+48
x=48
48-28=20
I need help im stuck (image attach)
Answer:
∠e = 32°
∠d = 69°
∠f = 79°
Step-by-step explanation:
Angle e and 32° are vertical angles, so this means that ∠e = 32° because vertical angles are congruent.
Next, a straight line is equal to 180°, and angle e is equal to 32°, so we can write the following equation to solve for angle f:
69° + e + f = 180° ➜ 69° + 32° + f = 180° ➜ 101° + f = 180° ➜ f = 79°
Lastly, angle d and 69° are also vertical angles, so this means that ∠d = 69° because vertical angles are congruent.
20. The table shows the numberof days you keep a rented movie before returning it and the total cost of renting the
movie. Find the rate of change in cost with repect to time and interpret its meaning.
Time (days)
4
5
6
Cost (dollars)
6.00
8.25
10.50
Step-by-step explanation:
According to given table we have pairs of points:
(4, 6.00), (5, 8.25), (6, 10.50)The rate of change is:
(8.25 - 6.00)/(5 - 4) = 2.25or
(10.50 - 8.25)/(6 - 5) = 2.25It is 2.25 and the meaning is:
Rental per day is $2.25Assume that a particle is described by the wave function ψ(x)=(2πσ)−1/4exp[−x2/(4σ)]. (i) Confirm that this wave function is normalised. (ii) Calculate the expectation values ⟨x^2⟩ and ⟨p^2⟩ as a function of σ.
The expectation values ⟨x2⟩ and ⟨p2⟩ as a function of σ are given by,⟨x2⟩ = πσ and ⟨p2⟩ = π/2σ.
The given wave function is ψ(x) = \([2\pi \sigma](-1/4) e^{-x_2/(4\sigma)}\).
To confirm that this wave function is normalized, we need to perform the following steps:
i) ∫ψ(x)*ψ(x) dx from -infinity to +infinity.
ii) Solve the above integral and check if the result is equal to 1.
After performing the above steps, we get the following results
As per the given problem, the wave function is given by,ψ(x) = \([2\pi \sigma](-1/4) e^{-x_2/(4\sigma)}\).
We need to confirm that this wave function is normalized.
For that, we need to perform the following steps:
i) ∫ψ(x)*ψ(x) dx from -infinity to +infinity.
ii) Solve the above integral and check if the result is equal to 1.
Substituting the wave function, we get,
\(\int\limits^\infty_{-\infty} {2\pi\sigma(-1/4)e^{-x_2/4\sigma} \times 2\pi\sigma(-1/4)e^{-x_2/4\sigma} \, dx\)
Now, ∫exp[-x2/(2σ)]dx from -infinity to +infinity can be solved as follows:
Let y = x/(√2σ)
Substituting the limits, we get,
\(∫exp[-x2/(2σ)]dx from -infinity to +infinity = √(2σ) * ∫exp(-y2) dy from -infinity to +infinity\)
= √(2πσ).
∴ \(∫[2πσ](-1/4) exp[-x2/(4σ)]*[2πσ](-1/4) exp[-x2/(4σ)] dx from -infinity to +infinity = ∫[2πσ](-1/2) exp[-x2/(2σ)] dx from -infinity to +infinity= 1, which is equal to 1.\)
Hence, the given wave function is normalized.
Now, we need to calculate the expectation values ⟨x2⟩ and ⟨p2⟩ as a function of σ.
⟨x2⟩ = ∫x2 |ψ(x)|2 dx from -infinity to +infinity.
Substituting the wave function, we get,
⟨x2⟩ = ∫x2 [2πσ](-1/2) exp[-x2/(2σ)] dx from -infinity to +infinity.
Using the relation,
∫x2 exp(-ax2) dx = √(π/2a3)⟨x2⟩ = √(2σ) * ∫x2 exp[-x2/(2σ)] dx from -infinity to +infinity
= 1/2 * σ * √(2σ) * ∫[2σ](-3/2) exp(-u) du from -infinity to +infinity
= 1/2 * σ * √(2σ) * Γ(3/2), where Γ is the Gamma function.
Using the value of Γ(3/2) = √π, we get,⟨x2⟩ = (1/2) * (2σ) * π = πσ.
Conversely, ⟨p2⟩ = ∫p2 |ψ(p)|2 dp from -infinity to +infinity.
Substituting the wave function, we get,
⟨p2⟩ = ∫[2πσ](-1/2) p2 \(e^{-p2\sigma/2}\) dp from -infinity to +infinity.
Integrating by parts twice, we get,
⟨p2⟩ = (2σ) *\(∫[2πσ](-1/2) exp[-p2σ/2] dp from -infinity to +infinity= (2σ) * √(π/(2σ3))\)= π/2σ.
Hence, the expectation values ⟨x2⟩ and ⟨p2⟩ as a function of σ are given by,⟨x2⟩ = πσ and ⟨p2⟩ = π/2σ.
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I=$200,p=$1000,r=4 years
Answer:
idt this is right..... sorry if this is wrong...
Step-by-step explanation:
I = $ 8,000.00
Equation:
I = Prt
Calculation:
First, converting R percent to r a decimal
r = R/100 = 200%/100 = 2 per year,
then, solving our equation
I = 1000 × 2 × 4 = 8000
I = $ 8,000.00
The simple interest accumulated
on a principal of $ 1,000.00
at a rate of 200% per year
for 4 years is $ 8,000.00.
Anyone one know the answers to this ?? HELP PLS.
ONLY ANSWER IF YOU KNOW, any other answers will be reported !
Each month we have to deposit 1389 of amount and we get interest of 30000
What is Percentage?percentage, a relative value indicating hundredth parts of any quantity.
Given 500000 to be in our account in retirement of 30 years.
We need to find how much we have to deposit each month.
We know that in a year there are 12 months.
For 30 years the number of months are 12×30=360
So Now divide 500000 by 360 to find each month deposit
500000/360=1388.8
So each month one has to deposit 1389 into account.
Now if account earns 6% of interest. We need to find how much amount we earned.
6% is converted to decimal by dividing 6 by 100
0.06
Now multiply with 500000
0.06×500000
30000
Hence, each month we have to deposit 1389 of amount and we get interest of 30000.
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what is 8+4=2(x-1) please help
Answer:
8+4=2(x-1)
8+4=2x-2
12=2x-2
14=2x
x=7
This was the answer I got but I am not sure it it is correct.
To find JL
We will first find the value of x
JK = KL
2(x+6) = 3x + 8
2x + 12 = 3x+ 8
subtract 2x from both-side of the equation
12 = 3x-2x + 8
12 = x+ 8
subtract 8 from both-side of the equation
12 - 8 = x+ 8 - 8
4 = x
x=4
JK = 2(x+ 6)
substitute x = 4 into the above
JK = 2(4+6)
JK=2(10)
JK=20
KL =3x+8
substitute x=4 into the above
KL = 3(4) + 8
KL = 12 + 8
KL=20
JL = JK + KL
= 20 + 20
= 40
JL = 40 units
(x-24)
296
29°
Show work
Answer:
x=59
Step-by-step explanation:
this is a full circle which is 360 degrees
We subtract 296 from 360 first
360-296=64
Then subtract 29 from 64
64-29=35
now we can set x-24 equal to 35
X-24=35
+24 +24
x=59
Hopes this helps please mark brainliest
true or false? finding a random sample with a mean this low in a population with mean 7 and standard deviation 2 is very unlikely.
It is false that " finding a random sample with a mean this low in a population with mean 7 and standard deviation 2 is very unlikely".
What is standard deviation?The term "standard deviation" (or "") refers to a measurement of the data's dispersion from the mean. A low standard deviation indicates that the data are grouped around the mean, whereas a high standard deviation shows that the data are more dispersed. The average degree of variability in your data set is represented by the standard deviation. It reveals the average deviation of each score from the mean. The standard deviation gauges how widely the data deviates from the mean. When comparing data sets that may have the same mean but a different range, it is helpful. The mean of the two numbers 15, 15, 15, 14, 16 and 2, 7, 14, 22, 30 for instance, is the same. The second, however, is obviously more dispersed.
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8 is 16% of what?
Complete the sentence
Answer:
50
Step-by-step explanation:
the answer is 50 becuz it is
What is the value of x? (NO LINKS)
Answer:
42 x is the answer of this question
can someone help me pls for 50 pts
Answer:
62 square units
Step-by-step explanation:
Area = 2(lb+lh+bh)
= 2(3×2+3×5+2×5)
= 62
The solid represented by the net is a rectangular prism.
And, The surface area of the solid is , 62.
What is mean by Rectangle?A rectangle is a two dimension figure with 4 sides, 4 corners and 4 right angles. The opposite sides of the rectangle are equal and parallel to each other.
We have to given that;
The solid represented by the net.
Here, We know that;
A rectangular prism is a three-dimensional solid shape with six faces that including rectangular bases.
Hence, The solid represented by the net is a rectangular prism.
Here, The length of the rectangular prism (l) = 5
The width of the rectangular prism (w) = 2
The height of the rectangular prism (h) = 3
We know that;
The surface area of the rectangular prism = 2 (wl + hl + hw)
Substitute all the values, we get;
The surface area of the rectangular prism = 2 (2×5 + 3×5 + 3×2)
The surface area of the rectangular prism = 2 (10 + 15 + 6)
The surface area of the rectangular prism = 2 × 31
The surface area of the rectangular prism = 62
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Please help! My assignment is due today! Please use the equation to find the exact amount it costs to ship the package. P.S. don't put it in a file, as I cannot reach it.
how do i do this, im very confjseddd
Find the nth term: 8, 18, 28, 38, 48....
Answer:
The ninth term? That would be 98.
Step-by-step explanation:
Notice how the numbers add 10 every time. If we keep doing that pattern until we get the ninth number, then we get this:
8, 18, 28, 38, 48, 58, 68, 78, 88, 98
Therefore, the answer is 98.
Please help me. Only answer if you know the answer. In circle O, PA and PB are tangents. The figure is not drawn to scale.
a. Prove that APO is congruent to BPO.
b. Find BOD for AOP = 64. Explain your reasoning.
Answer:
a. See down below
b. 116 degrees
Step-by-step explanation:
a. Since PA and PB are both tangents to the circle, they both form right angles with the radius of the circle. Also, since they originate from a common point, they have equal length when they reach the circle. Finally, they share side PO. Therefore, by SSA congruence, they are congruent triangles.
b. Since PD bisects the circle, it is divided into two 180 degree sections. If AOP=64, then so is POB. Since all of the remaining half of the circle is BOD, you can find its angle measure by subtracting the angle measure of AOP from 180. 180-64=116 degrees. Hope this helps!
HURRY! 30 POINTS! The prism below has a volume of 21 cubic units. The base is a right triangle with legs that have lengths of 2 units and 3 units. Find the height of the prism.
A.) 7 units
B.) 3.5 units
C.) 21 units
D.) 11.5 units
Answer:
A)
7 units
hope it helps you :D .
Answer:
A.) 7 units
Step-by-step explanation:
hope You Enjoy
Which number is rational, an integer, and a real number?
A. 1.5
B.
C. There is no such nurnber.
D. -5
Answer please :) thanks.
Please answer correctly !!!!!!! Will mark 50 points !!!!!!!!!!!!!!!!
Answer:
Hope it helps
Step-by-step explanation:
I think the answer to this question is 0
After an alcoholic beverage is consumed, the concentration of alcohol in the bloodstream (blood alcohol concentration, or BAC) surges as the alcohol is absorbed, followed by a gradual decline as the alcohol is metabolized. The function C(t)=0.135 t e^{-2.802 t}C(t)=0.135te −2.802t models the average BAC, measured in g/dL, of a group of eight male subjects t hours after rapid consumption of 15 mL of ethanol (corresponding to one alcoholic drink) What is the maximum average BAC during the first 3 hours? When does it occur?
It gradually decreases as alcohol is metabolized. The function C(t)=0.135 t e^{-2.802 t}models the mean BAC measured in g/mL.
The maximum average BAC during 3 hours is 0.0001358 g/mL.
f(t) = α t e−βt --(1)
Let's rewrite this in a simple form:
f(t)= α eˡⁿ ᵗ e⁻βt = αe^(ln t −βt)
Since e^x is strictly increasing and it will be maximized exactly when its argument is maximized, so we can maximize instead:
g(t)=ln t −βt
differentiating with respect to t , and g'(t) = 0
g′(t)=1/t − β = 0
=> t =1/β
we have given a function
C(t)=0.135 t e⁻²·⁸⁰²ᵗ
if we compare it with (1) we get
β = 2.802, 0.135 = α
For it's maximized we need to check the second order condition, and that of g will differentiate again , g′′(t)= −1/t² < 0
We have to compute the derivative of C(t):
C′(t) = 0.135 t⋅(−2.802)e⁻²·⁸⁰²ᵗ + 1.35e⁻²·⁸⁰²ᵗ
For optimum at t₀ if C′(t₀)=0 and C′′(t₀)≠0. Here, we have
C′(t₀) = 0.135t₀⋅(−2.802)e⁻²·⁸⁰²ᵗ₀+ 0.135e⁻²·⁸⁰²ᵗ₀ =e⁻²·⁸⁰²ᵗ₀(−0.135* 2.802t₀+ 0.135)=0
It is clear that e⁻²·⁸⁰²ᵗ₀ not equal to zero for all t₀∈R, so that
=> −0.135* 2.802t₀+0.135=0
=> t₀ = 1/2.802 ≈0.36
let us consider t is in hours, so that it makes t₀ =0.36h≈21.41min. This is the only optimum and one should verify it is indeed a maximum, i.e. C′′(t₀)<0.
Now, easily compute the maximum average BAC, which is C(t₀)=C(0.36) = 0.135 (0.36)e⁻²·⁸⁰²⁽⁰·³⁶⁾
= 0.0486(0.3678) = 0.01787508
Hence, the maximum average BAC, is 0.017 g/dL.
Maximum average BAC during the first 3 hours,
t = 3 , C(t)=C(3) = 0.135 (3)e⁻²·⁸⁰²⁽³⁾ = 0.0001358 g/mL
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In ARST, RS – TR and mZT = 15°. Find mZS.
Answer:
54
Step-by-step explanation:
D²y(t) + 12 Dy(t) + 36y(t) = 2 e-5t y(0) = 1, Dy(0)=0 Solve the differemtial equation using Classical Method (30pts) and Laplace Transform Method(30pts)
The solution to the differential equation D²y(t) + 12 Dy(t) + 36y(t) = 2 \(e^{(-5t)}\), with initial conditions y(0) = 1 and Dy(0) = 0, is \(y(t) = (1 + 6t) e^{(-6t)}\).
To solve the given differential equation using the classical method, we can assume a solution of the form \(y(t) = e^{(rt)}\) and find the values of r that satisfy the equation. We then use these values of r to construct the general solution.
Using the classical method:
Substitute the assumed solution \(y(t) = e^{(rt)}\) into the differential equation:
D²y(t) + 12 Dy(t) + 36y(t) = \(2 e^{(-5t)}\)
This gives the characteristic equation r² + 12r + 36 = 0.
Solve the characteristic equation for r by factoring or using the quadratic formula:
r² + 12r + 36 = (r + 6)(r + 6)
= 0
The repeated root is r = -6.
Since we have a repeated root, the general solution is y(t) = (c₁ + c₂t) \(e^{(-6t)}\)
Taking the first derivative, we get Dy(t) = c₂ \(e^{(-6t)}\)- 6(c₁ + c₂t) e^(-6t).\(e^{(-6t)}\)
Using the initial conditions y(0) = 1 and Dy(0) = 0, we can solve for c₁ and c₂:
y(0) = c₁ = 1
Dy(0) = c₂ - 6c₁ = 0
c₂ - 6(1) = 0
c₂ = 6
The particular solution is y(t) = (1 + 6t) e^(-6t).
Using the Laplace transform method:
Take the Laplace transform of both sides of the differential equation:
L{D²y(t)} + 12L{Dy(t)} + 36L{y(t)} = 2L{e^(-5t)}
s²Y(s) - sy(0) - Dy(0) + 12sY(s) - y(0) + 36Y(s) = 2/(s + 5)
Substitute the initial conditions y(0) = 1 and Dy(0) = 0:
s²Y(s) - s - 0 + 12sY(s) - 1 + 36Y(s) = 2/(s + 5)
Rearrange the equation and solve for Y(s):
(s² + 12s + 36)Y(s) = s + 1 + 2/(s + 5)
Y(s) = (s + 1 + 2/(s + 5))/(s² + 12s + 36)
Perform partial fraction decomposition on Y(s) and find the inverse Laplace transform to obtain y(t):
\(y(t) = L^{(-1)}{Y(s)}\)
Simplifying further, the solution is:
\(y(t) = (1 + 6t) e^{(-6t)\)
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The triangles shown below must be congruent.
O A. True
OB. False
Answer:
true
Step-by-step explanation:
they look alike
Step-by-step explanation:
it is true by the procress AASPLEASE ANSWER THIS QUICK AND RIGHT!! 50 POINTS
DETERMINE THE PERIOD
The period of the given trigonometric function is: 20.
What is the period of the trigonometric graph?The distance between the repetition of any function is called the period of the function. For a trigonometric function, the length of one complete cycle is called a period.
Sine and cosine functions start repeating the same pattern of y-axis values after every 2(pi). The period is defined as just the distance on the x-axis before the pattern repeats.
Now, looking at the trigonometric graph, we see that the x-interval for which the graph repeats itself is 20
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If the n×n matrix A is invertible, then the reduced row echelon form of A is the
n×n identity matrix. True or false ? Explain.
False. The reduced row echelon form of an invertible n×n matrix A is not always the n×n identity matrix.
The reduced row echelon form of a matrix is obtained by performing a sequence of row operations to transform the matrix into a specific form. These operations include row swaps, scaling rows, and adding multiples of rows to other rows.
When an n×n matrix A is invertible, it means that it has an inverse matrix A^-1 such that AA^-1 = A^-1A = I, where I is the n×n identity matrix. In other words, A and A^-1 are inverses of each other.
While the reduced row echelon form of A may have some properties that resemble the identity matrix, it is not guaranteed to be the exact same as the identity matrix. The row operations performed to obtain the reduced row echelon form may introduce additional non-zero entries or alter the diagonal entries of the matrix.
Therefore, the statement that the reduced row echelon form of an invertible n×n matrix A is the n×n identity matrix is false.
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In ΔQRS, r = 380 cm, s = 390 cm and ∠Q=48°. Find the length of q, to the nearest centimeter.
Step-by-step explanation:
Using Cosine rule, we have:
q² = r² + s² - 2(r)(s)(cosQ)
= 380² + 390² - 2(380)(390)(cos48°)
= 98169.688cm²
Hence q = 313cm. (nearest centimeter)
The required value of side q is 313 cm for the triangle ΔQRS.
What is a triangle?A triangle is a geometric figure with three edges, three angles and three vertices. It is a basic figure in geometry.
The sum of the angles of a triangle is always 180°
Given that,
In triangle QRS side r = 380 cm, side s = 390 cm and angle Q = 48°.
To find the length of the side q,
Use cosine rule,
\(cos Q = \frac{(r^2 + s^2 - q^2)}{(2\times r \times s)}\)
Substitute the values here,
\(cos 48 = \frac{(380)^2 + (390)^2- q^2}{2\times380 \times390} \\\)
\(0.67 = \frac{144400 + 152100 - q^2}{296400}\)
198,588 = 296500 - q²
q² = 97912
q = 312.90
q = 313 cm
The value of side q is 313 cm.
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Slope intercept form (pls help, friday is the end of the grading period and i have an f in algebra)
Answer:
yes, just ask away.
slope intercept form looks like this:
y = mX + b
Step-by-step explanation:
good luck
Mookie can polish 240 square feet of floor in 2
hours. How many square feet can he polish in 7
hours?
Answer:
840 square feet
Step-by-step explanation:
240 divided by 2 = 120 times 7 = 840
1. a right cone has a base with diameter 10 units. the volume of the cone is cubic units. what is the length of a segment drawn from the apex to the edge of the circular base?
For the given cone, the length of a segment drawn from the apex to the edge of the circular base is 13 units.
What is a cone?
A cone is a three-dimensional geometric form with a flat base and a smooth tapering apex or vertex. A cone is made up of a collection of line segments, half-lines, or lines that connect the apex—the common point—to every point on a base that is in a plane other than the apex. The height of the cone is determined by measuring the distance between its vertex and base. The radius of the circular base has been measured. The slant height is the distance along the cone's circumference from any point on the peak to the base.
Given,
The base diameter of the cone = 10 units
The volume of the cone = 100π cubic units.
We are asked to find the length of a segment drawn from the apex to the edge of the circular base of the cone.
Now the volume of a cone is given by,
V = πr² * h/3
where,
r = radius
h = height
for the given cone,
r = 10/2 = 5 units
So,
100π = π * 5*5 * h/3
4 = h/3
h = 12 units
Now we are asked to find the slant height(l) of the cone.
l² = h² + r² = 12² + 5² = 169
l = 13 units.
Therefore, for the given cone, the length of a segment drawn from the apex to the edge of the circular base is 13 units.
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