please hurry write the symbol that completes the following nuclear equation
88 ^ 21 Rn : 2 He+?
15 ^ 29P +1 ^ 0 e+ ?
Answers
The symbols that completes the given nuclear equation are written as follows:
²²⁶Ra₈₈ ----> ²²²Rn₈₆ + ⁴He₂²⁹P₁₅ e ----> ⁰⁻e₁⁺ + ²⁹Si₁₄What is an alpha decay?An alpha decay can be defined as a type of radioactive decay in which the atomic nucleus of a radioactive element emits an alpha particle, thereby, producing chemical elements with a different atomic nucleus.
During an alpha decay, the radioactive element has a mass number that is decreased by four (4) and an atomic number that is decreased by two (2), which is typically an atom of Helium (⁴He₂).
What is a beta particle?A beta particle can be defined as an isotope which typically undergoes radioactive decay through the emission of a radiation with a -1 charge. This ultimately implies that, an atom of neutron becomes a proton and an electron (₀e⁻¹) and an atom of proton also becomes a neutron and a positron (⁰⁻e₁⁺) during beta decay.
In conclusion, the symbols that completes the given nuclear equation are written as follows:
²²⁶Ra₈₈ ----> ²²²Rn₈₆ + ⁴He₂²⁹P₁₅ e ----> ⁰⁻e₁⁺ + ²⁹Si₁₄Read more on alpha decay here: https://brainly.com/question/23303931
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Related Questions
When work is done by a system, does the internal energy of the system increase or decrease?
Answers
Decrease
Explanation:The mathematical relationship between heat, internal energy and work done by the system is given as:
△U = Q + W
where △U is the change in the internal energy
W is the workdone by the system
Q is the heat energy in the system
Since the workdone by the system is negative, when a system does work, there is a depletion in the amount of energy possessed by the system.
Due to this loss of energy by the system as a result of the workdone, the internal energy decreases.
Which statements explain current theories about dark energy and dark matter? Check all that apply. Space that appears empty actually contains dark energy and dark matter. Dark matter does not emit electromagnetic radiation. Scientists believe dark energy will cause the universe to collapse inward to a single point. Scientists theorize that dark energy is causing the expansion of the universe to accelerate. Dark matter includes all of the dust, ice, and debris that scientists observe in black holes.
Answers
The correct statements which describes current theories about dark energy and dark matter among the choices above are given below:
Space that appears empty actually contains dark energy and dark matter.Dark matter does not emit electromagnetic radiation.Scientists theorize that dark energy is causing the expansion of the universe to accelerate.The answers are options a, b, and d.
What meant by dark energy ?Dark energy refers to that energy which acts against gravity, thereby resulting in the expansion of the universe. It's major constituent is current characterized with vacuum fluctuation. It is on this premise that dark energy was theorized to be causing the expansion of the universe to accelerate and itself including dark matter is filled in empty space.
So therefore, from the simple note above, it can be deduced that this type of energy does not produce electromagnetic radiation.
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Answer:
a b d
Explanation:
Which statements explain current theories about dark energy and dark matter? Check all that apply.
Space that appears empty actually contains dark energy and dark matter.
Dark matter does not emit electromagnetic radiation.
Scientists believe dark energy will cause the universe to collapse inward to a single point.
Scientists theorize that dark energy is causing the expansion of the universe to accelerate.
Dark matter includes all of the dust, ice, and debris that scientists observe in black holes.
PLS HELP RN
A stone is thrown horizontally from the top of a 31.2 m tall cliff. The stone lands at a distance
of 21.4 m from the edge of the cliff. What is the initial horizontal velocity of the stone?
Answers
When a stone is hurled horizontally from the top of a 31.2 m tall cliff, its horizontal initial velocity is 39.25 m/s.
What is the initial horizontal velocity formula?By measuring the ball's diameter d and dividing it by the time t it takes for it to cross the photogate, one can also calculate the ball's starting horizontal velocity. Therefore, Vo = d/t. The kinematics equations of motion can be used to calculate the horizontal velocity of a projectile motion made by a person or an item.
Calculation:Height of cliff is 31.2 m
distance is 21.4
t = √2h/g
t = √2×31.4/9.8
t = √62.8/9.8
t = 0.80
The stone's first motion:V = 31.4/0.08
V = 39.25 m/s.
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20 POINTS:
Why does the initial hill of a roller coaster need to be steep?
Answers
Answer: A roller coaster does not have an engine to generate energy. The climb up the first hill is accomplished by a lift or cable that pulls the train up. This builds up a supply of potential energy that will be used to go down the hill as the train is pulled by gravity
Hope this helps! Good luck with future homework and exams!
A high surface tension results from _____.
Answers
Answer:
Capillary Action.
Explanation:
Capillary action is the ability of a liquid to flow in narrow spaces without the assistance of, or even in opposition to, external forces like gravity.
Read the following scenario and decide if it is a hypothesis, theory or law.
John is an amateur astronomer who is in his second semester of high school physics.
Accordingly, he knows that objects in motion remain in motion and move at constant
velocity in a straight line until some force acts on them. John observes that all of the
planets in this solar system orbit the sun in approximately circular orbits. In addition,
the farther a planet is from the sun, the longer it takes for that planet to complete one
orbit. John discusses his observations with like-minded friends, who also observe and
verify what John has seen. Based on these consistent observations from many different
people, John concludes that there is gravity in outer space. Is this conclusion a
hypothesis, theory or law?
Hypothesis
Theory
Law
Answers
Answer:
this questions is capable of being answered by submitting law
If m=120kg and a=15m/s2, what is the force
Answers
Answer:
F= 1800N
Explanation:
the equation for force is F= ma
so plug in the numbers: F= (120)(15)
solve this to get F= 1800N
tip: don't forget to add the units when writing your answer :)
Oxygen is needed for the reactions that cause artifacts to decay in the ocean.
Some ancient shipwrecks have been well-preserved deep in the ocean.
Review the information in the data table. Which statement about the
relationship between rates of reaction and concentration of reactants is true?
Object
Location
Decay time
Average
concentration of
oxygen
Wooden ship
Deep ocean
Very low
1,000 years
Wooden rowboat Shallow beach
High
1 to 2 years
O A. Reactions are faster when there is a lower concentration of
reactants.
Answers
Answer: The answer is C.
Explanation:Just took the quiz
The statement about the relationship between rates of reaction and concentration of reactants true is reactions are slower when there is lower concentration of reactants.
What is chemical reaction?The chemical reaction is the reaction between two reactants which led to the formation of products.
The products are substances which forms after reaction. The reactants are the substances which are original materials.
Oxygen is needed for the reactions that cause artifacts to decay in the ocean.
Some ancient shipwrecks have been well-preserved deep in the ocean.
Reviewing the information in the data table, we conclude that reactions are slower when there is lower concentration of reactants.
Thus, the correct option is C.
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ACELLUS PHYSICS HELP!!
A 6.93*10-4 C charge has a potential energy U = -3.09 J at a point in space. What is the electric potential V at that point? Include the sign, + or - . (Unit = V)
Answers
Answer:
Potential difference, V = -0.000224 Volts
Explanation:
Given the following data;
Quantity of charge = 6.93*10-4 C
Energy = -3.09 J
To find the electric potential V at that point?
Mathematically, the energy transferred per unit of charge is given by the formula;
E = QV
Where:
E is the energy
Q is the quantity of charge
V is the potential difference.
Substituting into the formula, we have;
\( -3.09 = 6.93*10^{-4} * V \)
\( V = \frac {6.93*10^{-4}}{-3.09} \)
Potential difference, V = -0.000224 Volts
Question 63 Marks: 1 Sounds with a frequency of 30 hertz (Hz) are considered very low pitch.Choose one answer. a. True b. False
Answers
a. True. Sounds with a frequency of 30 hertz (Hz) are considered very low pitch.
This is because low frequency sounds produce low pitch tones, and 30 Hz falls within the lower end of the human hearing range, which is typically between 20 Hz to 20,000 Hz. These lower frequencies are usually associated with bass notes, such as those in bass guitars and synthesizers.Low-pitched sounds are generally associated with bass sounds and have a slower frequency than higher-pitched sounds. Low-frequency sound waves travel farther than higher frequency sound waves and can be heard even when there is background noise.
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3volt,0.25,r1,4ohms,r2,2ohms,r3,0.5a,r4,3ohms,0.25volt, calculate the value read by the voltmeter across the r2, calculate the value of r3, calculate the total resistance
Answers
To calculate the value read by the voltmeter across R2, we need to use Ohm's Law, which states that voltage (V) is equal to the current (I) multiplied by the resistance (R).
Given the values provided, we have a voltage of 3 volts and a current of 0.25 amperes. The resistance across R2 is given as 2 ohms. Plugging these values into Ohm's Law, we can calculate the voltage across R2:
V = I * R
V2 = 0.25 A * 2 Ω
V2 = 0.5 volts
So, the value read by the voltmeter across R2 is 0.5 volts.
To calculate the value of R3, we can use Ohm's Law again. This time, we are given a voltage of 0.25 volts and a current of 0.5 amperes. Plugging these values into Ohm's Law, we can find the resistance of R3:
V = I * R
0.25 V = 0.5 A * R3
R3 = 0.25 V / 0.5 A
R3 = 0.5 ohms
So, the value of R3 is 0.5 ohms.
To calculate the total resistance, we need to consider the resistances in parallel (R1 and R2) and in series (R3 and R4).
The resistances R1 and R2 are in parallel, so we can use the formula:
1/Rt = 1/R1 + 1/R2
1/Rt = 1/4 Ω + 1/2 Ω
1/Rt = (2 + 4) / (4 * 2) Ω
1/Rt = 6 / 8 Ω
1/Rt = 0.75 Ω
Rt = 1 / 0.75 Ω
Rt = 1.333 Ω
The resistances R3 and R4 are in series, so we can simply add them:
Rt = R3 + R4
Rt = 0.5 Ω + 3 Ω
Rt = 3.5 Ω
Therefore, the total resistance is 3.5 ohms.
- The value read by the voltmeter across R2 is 0.5 volts.
- The value of R3 is 0.5 ohms.
- The total resistance is 3.5 ohms.
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according to product categorization, vehicles can be placed under the _____.
Answers
According to product categorization, vehicles can be placed under various categories based on their type, size, purpose, and other features.
Some of the most common categories include:
Passenger cars: This category includes all types of cars, SUVs, and hatchbacks designed for carrying passengers.
Light commercial vehicles: This category includes small trucks, vans, and pickup trucks that are used for carrying goods and equipment.
Heavy commercial vehicles: This category includes large trucks, buses, and other vehicles that are used for transporting goods over long distances.
Two-wheelers: This category includes motorcycles, scooters, and other small, lightweight vehicles designed for individual transportation.
Off-road vehicles: This category includes vehicles designed for off-road driving, such as SUVs, ATVs, and dirt bikes.
Electric vehicles: This category includes vehicles powered by electric motors, such as electric cars, buses, and motorcycles.
Hybrid vehicles: This category includes vehicles that use both electric and internal combustion engines, such as hybrid cars and SUVs.
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If the surface s is parameterized by r(u, v) = , find an equation o f the tangent plane to s at the point (pi, 1, 0)
Answers
To find the equation of the tangent plane to the surface parametrized by r(u, v) at the point (pi, 1, 0), we need to compute the normal vector to the surface at that point.
First, let's find the partial derivatives of r(u, v) with respect to u and v. Then, evaluate these derivatives at (pi, 1, 0). Let's denote the partial derivatives as ru and rv, respectively. Next, compute the cross product of ru and rv. This will give us the normal vector to the surface at the point (pi, 1, 0). Let's denote the cross product as N.
Finally, using the point-normal form of a plane equation, we can write the equation of the tangent plane to the surface at the point (pi, 1, 0) as: N · (x - pi, y - 1, z - 0) = 0 where · denotes the dot product. This will give us the normal vector to the surface at the point (pi, 1, 0). Let's denote the cross product as N. Please provide the specific parameterization of the surface r(u, v) for a more detailed answer.
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5. Which of the following is NOT correct walking technique?
O Looking at the ground
Standing tall
Pushing off your toes
Bending your arms
Answers
bending your arms
good luck bro
A fan operating at 260V with a current being supplied at 13A. What is the effective resistance at which it is being operated?
Answers
Answer:
20 ohms
Explanation:
Resistance=Potential difference÷Electric current
X=260÷13
X=20
Two large parallel conducting plates carry charges of equal magnitude and opposite charge. When you place a point charge q = +3.60 nC between the plates, the force on the point charge is 22.0 μN. What is the magnitude of the surface charge density on either plate? Express your answer with the appropriate units.
Answers
Answer:
The magnitude of the surface charge density on either plate is approximately 5.41 × 10⁻⁸ C/(m²)
Explanation:
The magnitude of the charge on each of the conducting plates = Equal
The orientation of the charges on each plate = Opposite charges
The magnitude of the point charge placed between the plates = +3.60 nC
The force acting on the point charge, q = 22.0 μN
Therefore, we have;
F = E × q
E = F/q = 22.0 μN/+3.60nC = 6,111.1111 V/m
We have;
\(E = \dfrac{\rho }{\epsilon_0}\)
Where;
ρ = The surface charge density
ε₀ = Absolute permittivity ≈ 8.85 × 10⁻¹² C²/(N·m²)
Therefore, we have;
ρ = E × ε₀ = 6,111.1111 V/m × 8.85 × 10⁻¹² C²/(N·m²) = 5.40833332 × 10⁻⁸ C/(m²)
∴ The magnitude of the surface charge density on either plate, ρ ≈ 5.41 × 10⁻⁸ C/(m²).
How can you separate chalk from
chalky water?
Answers
Answer:
Yes
Explanation:
Because the call can evaporate from the water.
Answer:
A centrifuge is utilized to isolated little sums of strong held in suspension from the fluid. For case, chalk from water. The centrifuge contains test-tubes that are spun around at tall speed that causes the strong to sink to the foot of the tube. The fluid is the tapped (poured off) clearing out the strong behind.
An object that is falling has the following type(s) of energy. Ignore air resistance.
Kinetic Energy
Potential Energy
Electrical Energy
Thermal Energy
Answers
The magnetic field around current carrying wire is blank proportional to the currant and blank proportional in the distance tot he wire
Answers
The magnetic field around a current-carrying wire is directly proportional to the current and inversely proportional to the distance from the wire.
The magnetic field strength generated by a current-carrying wire follows the right-hand rule. As the current increases, the magnetic field strength also increases. This relationship is described by Ampere's law.
Additionally, the magnetic field strength decreases as the distance from the wire increases, following an inverse square law. This means that doubling the current will double the magnetic field strength, while doubling the distance from the wire will reduce the field strength to one-fourth of its original value. Therefore, the magnetic field around a current-carrying wire is directly proportional to the current and inversely proportional to the distance from the wire.
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Help me please ()- :))
Answers
Answer:
A pardon
Explanation:
Hope this helps
Answer:
that would probably be a A.Pardon
According to Newton's third law, two objects interacting under a force (such as gravity) both feel the same force. If the planets pull on the Sun as much as the Sun pulls on the planets, why are we able to approximate the Sun as a fixed position when studying the planetary orbits?
Answers
Explanation:
That's because the Sun's acceleration is much smaller
A sound wave passes through regions of the ocean with varying density. How do the varying wavelengths correspond to the density of the water
Answers
Sound moves faster in the denser regions of the ocean than in the less dense regions of the ocean.
Speed of soundWe know that sound is a wave whose medium of propagation isthrough matter. Hence, sound move faster in a dense object than in a less dense object.
As such, sound moves faster in the denser regions of the ocean than in the less dense regions of the ocean.
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the magnitude of the magnetic field at point p for a certain electromagnetic wave is 2.12 μt. what is the magnitude of the electric field for that wave at p?
Answers
To find the magnitude of the electric field at point P for a certain electromagnetic wave with a magnetic field of 2.12 μT, you can use the equation:
E = c * B
where E is the electric field, B is the magnetic field (2.12 μT), and c is the speed of light in a vacuum (approximately 3 x 10^8 m/s).
Step 1: Convert the magnetic field B to Tesla (T) by multiplying it by 10^-6:
\(B = 2.12 μT * 10^-6 = 2.12 x 10^-6 T\)
Step 2: Plug the values into the equation:
\(E = (3 x 10^8 m/s) * (2.12 x 10^-6 T)\)
Step 3: Calculate the result:
E ≈ 636 N/C
The magnitude of the electric field for that wave at point P is approximately 636 N/C.
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If a 1 kg book has 46 Joules of gravitational potential energy how high is the shelf it is on?
g = 9.8 m/s^2 KE = ½ mv^2 PE = mgh
Answers
Answer:
4.7m
Explanation:
Given parameters:
Mass of the book = 1kg
Gravitational potential energy = 46J
Unknown:
Height of the shelf = ?
Solution:
The potential energy is due to the position of a body above the ground.
Gravitational potential energy = mgh
m is the mass,
g is the acceleration due gravity = 9.8m/s²
h is the height which is unknown
46 = 1 x 9.8 x h
h = 4.7m
A 10 kg-shopping cart is being pushed with a net force of 18 N, what is the acceleration
of the cart?
Answers
Answer:
180m/s²
Explanation:
A = Fm
A = 18(10)
A = 180m/s²
HELP ASAP !
Which of the following situations would result in no work done by the force indicated?
a
The object undergoes only a slight displacement while the force is acting on it.
b
The force is perpendicular to the displacement of the object.
c
The force is not completely parallel to the displacement of the object
d
All of the above result in no work done by the force indicated.
Answers
Answer:
b The force is perpendicular to the displacement of the object.
Explanation:
Work is done when a force is applied on a body causing it to move in a particular direction.
Work done = Force x displacement
For work to be done, a force must applied on a body to move it through a specific distance in direction.
When force is perpendicular to the displacement of the object, the component vector resolution is 0 and the work done is 0.
the force f between two charges q^(1) and q^(2) in a vacuum is proportional to the product of the charges and is inversely proportional to the square of the distance d between the two charges solve the formula for k
Answers
From the formula for coulomb's, the formula for k would be k = Fd²/q1q2.
How to determine the formula for K when using Coulomb's Law?Here, we are required to solve for k from the Coulomb's formula, F=kq1q2/d².
Solving the formula for k, we obtain;
k = Fd²/q1q2
To solve the formula for k, we need to make k the subject of the formula;
F = kq1q2/d²
Then, F × d² = kq1q2
Therefore, to make k the subject of the formula; we divide both sides of the equation by q1q2.
Therefore, k = Fd²/q1q2.
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Complete question
Coulomb's Law is given by the formula
F=kq1q2/d2
The force F between two charges q1 and q2 in a vacuum is proportional to the product of the charges, and is inversely proportional to the square of the distance d between the two charges. Solve the formula for k.
Two cylinders contain the same ideal gas and have the same volume. If the gas molecules in cylinder B have twice the average kinetic energy as those in cylinder A how does the internal energy, U, of cylinder B compare to that of cylinder A
Answers
Hence, internal energy in cylinder B is twice than that in A.
It is given that two cylinders contain the same ideal gas and have the same volume. If the gas molecules in cylinder B have twice the average kinetic energy as those in cylinder, we need to compare internal energy.
As kinetic energy is directly proportional to temperature, internal energy is also proportional to temperature.
We can say that more the average kinetic energy, more is the internal energy.
Hence, internal energy in cylinder B is twice than that in A.
The ratio in A:B is 1:2.
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A spring of k=500 N/m that is initially compressed 2m is used to launch a 100N load of bricks up a 2 m tall
hill. Find the speed of the bricks at the top of the hill.
a. Qualitatively complete the energy flow diagram and the energy bar graphs.
c. Determine the speed
e. What would the speed at the top of the hill be with 2m of initial compression if 15% of the energy is
dissipated through friction?
d. What is the minimum compression of the spring necessary to get to the top of the hill? (v=0 at top, no
friction)
Answers
Speed of the bricks at the top of hill is 6.26 m/s. c.)speed of the bricks at the top of hill is 14.14 m/s. d)minimum compression of spring necessary to get to the top of hill is 6.26 m. e) speed of the bricks at the top of hill with 2 m of initial compression and 15% energy dissipation is 13.04 m/s.
What is energy?The capacity or power to do work, such as the capacity to move an object by application of force is called energy.
Initial potential energy of compressed spring is:
Ep = 1/2 kx^2 = 1/2 * 500 N/m * (2 m)^2 = 1000 J
k is spring constant, x is compression of the spring, and J is unit of energy in joules.
Final potential energy of the bricks is:
Ep = mgh = 100 N * 9.81 m/s^2 * 2 m = 1962 J
Ep = Ep
1/2 kx^2 = mgh
v = sqrt(2gh) = sqrt(2 * 9.81 m/s^2 * 2 m) = 6.26 m/s
Therefore, the speed of the bricks at the top of the hill is 6.26 m/s.
c. Initial potential energy of compressed spring is: 1000 J
Ek = Ep = 1000 J
Kinetic energy of the bricks is given by:
Ek = 1/2 mv^2
1000 J = 1/2 * 100 N * v^2
v = sqrt(200 / 1) = 14.14 m/s
Therefore, the speed of the bricks at the top of the hill is 14.14 m/s.
d. As, Ep = m g h
where m is mass of the bricks, g is acceleration due to gravity, and h is height of the hill.
Ep = 100 N * 9.81 m/s^2 * 2 m = 1962 J
Ep = 1/2 kx^2 = 1962 J
1/2 * 500 N/m * x^2 = 1962 J
x = sqrt(2 * 1962 J / 500 N/m) = 6.26 m
Therefore, the minimum compression of the spring necessary to get to the top of the hill is 6.26 m.
e. If 15% of the energy is dissipated through friction, final kinetic energy of the bricks at the top of the hill will be 85% of initial potential energy of the compressed spring. Therefore,
0.85 * 1000 J = 1/2 mv^2
v = sqrt(170 / 1) = 13.04 m/s
Therefore, the speed of the bricks at the top of the hill with 2 m of initial compression and 15% energy dissipation is 13.04 m/s.
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A rocket of mass 5kg is travelling horizontally with a speed of 200m/s when it explodes into two parts.
one part of mass 3kg continues in the original direction with a speed of 100m/s and the other part continues in the same direction.
*Calculate the unknown speed of the other part*
(please solve with steps + explanation)
Answers
Answer:
350 m/s
Explanation:
Before the explosion, the rocket's momentum is given by:
p = m*v where
p = momentum
m = mass of the rocket
v = velocity of the rocket
Given that the mass of the rocket is 5 kg and its velocity is 200 m/s, we can calculate the momentum as:
p = m*v = 5 kg * 200 m/s = 1000 kg·m/s
After the explosion, the momentum is conserved, which means the total momentum of the two parts is still 1000 kg·m/s. We can use this principle to solve for the velocity of the second part.
Let v1 be the velocity of the 3 kg part, and v2 be the velocity of the other part. Since they are both moving in the same direction, we can write:
p = m1v1 + m2v2
where m1 = 3 kg is the mass of the first part, and m2 is the mass of the second part.
Substituting the known values, we get:
1000 kg·m/s = 3 kg * 100 m/s + m2 * v2
Solving for v2, we get:
v2 = (1000 kg·m/s - 300 kg·m/s) / m2
v2 = 700 kg·m/s / m2
We still need to find the mass of the second part. Since the rocket initially had a mass of 5 kg, and one part has a mass of 3 kg, the other part must have a mass of:
m2 = 5 kg - 3 kg = 2 kg
Substituting this into the equation for v2, we get:
v2 = 700 kg·m/s / 2 kg
v2 = 350 m/s
Therefore, the unknown speed of the other part is 350 m/s.