Please Hurry!
Drag each relation to the correct location on the table.
Classify the relations according to whether or not they are functions.

Answer:

2, 3

Step-by-step explanation:

Answer:

148

Step-by-step explanation:

AP 200, 196, 192, ...

a14=?

---------

a1= 200

d= 196-200=192-196= -4

a14= a1+13d

a14= 200+13*(-4)= 200- 52= 148

The probability of drawing a 15 (of any suit) from a standard deck of 52 cards is approximately 7.69%.

To calculate the probability of drawing a 15 from a standard deck of 52 cards, we need to determine the number of favorable outcomes (i.e., the number of 15s) and divide it by the total number of possible outcomes (52 cards).

In a standard deck, there are four 15s, one in each suit (hearts, diamonds, clubs, and spades). Thus, the number of favorable outcomes is 4.

The total number of possible outcomes is 52 since there are 52 cards in the deck.

Therefore, the probability of drawing a 15 from the deck is calculated as:

Probability = Number of favorable outcomes / Total number of possible outcomes

= 4 / 52

= 1 / 13

≈ 0.0769 or 7.69%

So, the probability of drawing a 15 (of any suit) from a standard deck of 52 cards is approximately 7.69%.

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Door to door sampling is used when it is important to control where the sample is delivered and when the products are of a perishable nature.

The term sampling  selecting refers to the selection of a small proportion of the population extrapolating the results the results obtained from this small group to represent the characteristics of the entire population. This sample is chose in a manner as to reflect the properties the generality of the population.

Hence, door to door sampling is used when it is important to control where the sample is delivered and when the products are of a perishable nature.

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Answer:

24 cm²

Step-by-step explanation:

The area of a rhombus is half the product of its diagonals.

\(\boxed{\sf Area\;of\;a\;rhombus=\dfrac{diagonal\;1 \cdot diagonal\;2}{2}}\)

Therefore, to find the area of the rhombus, we need to find the lengths of the diagonals AC and BD.

The diagonals of a rhombus are perpendicular bisectors of each other.

The point of intersection of the diagonals of rhombus ABCD is point O.

We can use the given information to find the lengths of BO and OC, then  double these to find diagonals AC and BD.

The sides of a rhombus are equal in length. Therefore, if the perimeter of rhombus ABCD is 20 cm, each side length is 5 cm.

Therefore, the hypotenuse of right triangle BOC is BC = 5 cm.

If the ratio of AC : BD = 4 : 3, then the ratio of OC : BO = 2 : 1.5.

Let OC = 2x and BO = 1.5x.

Use Pythagoras Theorem to find the value of x.

\(\begin{aligned}BO^2+OC^2&=BC^2\\(1.5x)^2+(2x)^2&=5^2\\1.5^2x^2+2^2x^2&=25\\2.25x^2+4x^2&=25\\6.25x^2&=25\\x^2&=4\\\sqrt{x^2}&=\sqrt{4}\\x&=2\end{aligned}\)

Therefore, to find the lengths of OC and BO, substitute x = 2:

\(OC = 2x = 2(2) = 4\; \sf cm\)

\(BO = 1.5x = 1.5(2) = 3\; \sf cm\)

As the diagonals of a rhombus bisect each other:

\(AC = 2\cdot OC=2 \cdot 4 = 8\; \sf cm\)

\(BD = 2\cdot BO=2 \cdot 3 = 6\; \sf cm\)

Finally, substitute the lengths of the diagonals into the formula for the area of a rhombus:

\(\begin{aligned}\textsf{Area of rhombus $ABCD$}&=\sf \dfrac{diagonal\;1 \cdot diagonal\;2}{2}}\\\\&= \dfrac{AC \cdot BD}{2}\\\\&=\dfrac{8 \cdot 6}{2}\\\\&=\dfrac{48}{2}\\\\&=24\; \sf cm^2 \end{aligned}\)

Therefore, the area of rhombus ABCD is 24 cm².

The value of seaweed height that divides the bottom 30%  from the top 70% is 8.96 cm.

What is a Normal distribution in statistics?

Data in a normal distribution are symmetrically distributed and have no skew. The majority of values cluster around a central region, with values decreasing as one moves away from the center. In a normal distribution, the measures of central tendency (mean, mode, and median) are all the same.

Given data:

X: height of seaweed.

       X~N (μ;σ²)

       μ= 10 cm

       σ= 2 cm

We have to find the value of the variable X that separates the bottom 0.30 of the distribution from the top 0.70

              P(X ≤ x) = 0.30

              P(X ≥ x) = 0.70

Now by using the standard normal distribution,

we have to find the value of Z that separates the bottom 0.30 from the top 0.70 and then use the formula

        Z = (X - μ)/σ

translates the Z value to the corresponding X value.

           P(Z ≤ z) = 0.30

In the body of the table look for the probability of 0.30 and reach the margins to form the Z value. The mean of the distribution is "0" so below 50% of the distribution you'll find negative values.

                  z= -0.52

Now you have to clear the value of X:

        Z= (X - μ)/σ

        X= (Z * σ) + μ

       X = (-0.52 * 2) + 10

         = 8.96

hence, the value of seaweed height that divides the bottom 30%  from the top 70% is 8.96 cm.

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Answer:

9:16

Step-by-step explanation:

In a similar rectangle , the ratio of lengths should be equal to ratio of widths.

Ratio of lengths =

\( \frac{length \: of \: rectangle \: 1}{length \: of \: rectangle \: 2} = \frac{3}{4} \)

Hence , Ratio of widths =

\( \frac{width \: of \: rectangle \: 1}{width \: of \: rectangle \: 2} = \frac{3}{4} \)

Area of rectangle 1 = Length 1 × Width 1 = 3×3 = 9

Area of rectangle 2= Length 2 × Width 2= 4×4= 16

Ratio of areas of both rectangles =

\( \frac{area \: of \: rectangle \: 1}{area \: of \: rectangle \: 2 \: } = \: \frac{9}{16} \)

The value of the missing variables in the congruent triangles are; a = 6 and b = 16.5

We are told that ΔWXY ≅ ΔMNO

Now, we are not told the exact congruency postulate that is being used but by careful observation of the two triangles, we can deduce that it is ASA Congruency which is Angle - Side - Angle Congruency Postulate.

Now, what this implies is that;

∠X = ∠M and ∠O = ∠Y

This gives us;

4b + 8 = 74

4b = 74 - 8

4b = 66

b = 66/4

b = 16.5

Similarly, we have;

7a - 4 = 38°

7a = 42°

a = 42/7

a = 6

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Answer:

83.3=width

30÷18=k

k=1.66666

k·50=83.3

w=83.3

The answer is 845.31 rounded is 345.31

Answer:

D

Step-by-step explanation:

Anything saying left is incorrect. Numbers going to the left are smaller than - 3.

The dot is not filled in. To have a closed dot you would need ≥

The answer is D

Answer:

I think its A

Step-by-step explanation:

I eliminated C and D but am not 100% sure between a and b i think its right im not sure sorry

A word is put between to and the verb while splitting an  infinitive. In terms of grammar, splitting an infinitive is acceptable.

In other cases, it might even be more logical to do so. An infinitive is a verb's to form, such as "to go" or "to be."

When it is said that infinitives should never be split, it means an adverb should never come before the verb in the sentence "to confidently proceed."

As we know  split infinitive is one in which the word "to" and the verb in the base (infinitive) form of the verb are separated by one or more words.

Adverbs are the words that split infinitives the most frequently.

Example,

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1/4 will be the scale factor of dilation.

The ratio used to depict the relationship between the dimensions of a model or scaled figure and the corresponding dimensions of the real figure or object is called the scale. On the other hand, a scale factor is a value that is used to multiply all of an object's parts in order to produce an expanded or decreased figure.

Given, A circle with an area of 100 square centimeters is dilated so that its image has an area of 25 square centimeters.

From the general formula of scale factor:

Scale factor = Dimension of the new shape ÷ Dimension of the original shape.

In our case,

Dimensions of the new shape = 25 Square centimeters

Dimension of the original shape = 100 Square centimeters

Ths,

Scale factor = 25/100

Scale factor = 1/4

Therefore, the scale factor of the dilation will be 1/4.

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Answer:

Rate me 1 star if wrong but its answer A

Step-by-step explanation:

it equals -8.

4k + 13 = 3k + 5

4k + 13 - 13 = 3k + 5 - 13

4k = 3k - 8

4 k  −  3 k  = 3k - 8 - 3k

k = -8

An equation that mode the relationship between thee two variable is y=2x+3 .

Let x represent the number of 6-month period worked

Let y represent the total number of paid vacation day

According to the question,

When he started work, he was given three paid day of vacation. For each six-month period he pay at the job, his vacation is increased by two day.

Each year has 2 six-month periods. After 4.4 years Roberto will have worked 8.8 six-month periods. He will have been given vacation days for each of the 8 whole working periods he has completed. x=8 y=2*8+3 y=19

An equation that mode the relationship between thee two variable is y=2x+3 (Total vacation time equals 2 days times x plus the 3 days he was given at the start).

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Answer:

x = 4.3

Step-by-step explanation:

1.2x = 5.16

x = 4.3

Answer:

x = 5.16 / 1.2

x= 4.3

GOOD LUCK FOR THE FUTURE! :)

The probability of flipping 3 coins and getting either all heads or all tails is 2/8 = 1/4 = 0.25, or 25%.

Let's calculate the probability of flipping 3 coins and getting either all heads or all tails correctly.

When flipping a fair coin, the probability of getting a head (H) or a tail (T) is 0.5 each. Now, let's calculate the probability of getting either all heads or all tails when flipping 3 coins.

Total number of outcomes when flipping 3 coins: Each coin has 2 possible outcomes (H or T), so the total number of outcomes when flipping 3 coins is 2 × 2 × 2 = 8.

Number of favorable outcomes (either all heads or all tails): There are 2 favorable outcomes: HHH (all heads) and TTT (all tails) out of the 8 total outcomes.

Therefore, the probability of flipping 3 coins and getting either all heads or all tails is 2/8 = 1/4 = 0.25, or 25%.

To summarize, when flipping 3 coins, the probability of getting either all heads or all tails is 25%.

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The smallest value within the class is the lower class limit, and the largest value within the class is the upper class limit.

A class limit is a set of boundary values in the form of a range that describes the lowest and highest data values that a class can contain. The lower class limit refers to the smallest data value in a class, whereas the upper class limit refers to the largest data value in a class. The width of a class is determined by the difference between the upper and lower class limits. Here are a few examples to give you a better understanding of how this works:

Class:              5-9 5 9

Lower Limit:    10-14 10 14

Upper Limit:    15-19 15 19

This shows class limits for three different classes.

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Answer:

-5 and -2

Step-by-step explanation:

if \($a \neq b$\),\($f(n)$\)and \($g(n)$\) will not have the same growth rate. It is not true that \($\forall a, b \in \mathbb{N}, f(n) = a^n, g(n) = b^n$ implies $f \in \Theta(g)$\).

To determine whether $f(n) = a^n$ and $g(n) = b^n$ satisfy $f \in \Theta(g)$, we need to evaluate their growth rates and see if there exist constants $c_1$, $c_2$, and $n_0$ such that $c_1 \cdot g(n) \leq f(n) \leq c_2 \cdot g(n)$ for all $n \geq n_0$.

Let's analyze the growth rates of $f(n)$ and $g(n)$ separately:

1. $f(n) = a^n$:

  - When $a > 1$, $f(n)$ grows exponentially with $n$. For example, if $a = 2$, $f(n)$ doubles with each increment of $n$.

  - When $a = 1$, $f(n)$ is constant and does not grow with $n$.

  - When $0 < a < 1$, $f(n)$ converges to 0 as $n$ increases. For example, if $a = 0.5$, $f(n)$ halves with each increment of $n$.

2. $g(n) = b^n$:

  - When $b > 1$, $g(n)$ also grows exponentially with $n$.

  - When $b = 1$, $g(n)$ is constant.

  - When $0 < b < 1$, $g(n)$ converges to 0 as $n$ increases.

In general, if $a \neq b$, $f(n)$ and $g(n)$ will not have the same growth rate. Therefore, we cannot conclude that $f \in \Theta(g)$ for arbitrary $a$ and $b$.

Thus, it is not true that $\forall a, b \in \mathbb{N}, f(n) = a^n, g(n) = b^n$ implies $f \in \Theta(g)$.

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Answer:

yes, because it can be written as 23/100.

since the price is decreasing, you will substract a precentage.

you could find the 40% of 499 like this

after having this substract it from the original price

the new price will be $299.4

The jogger is 3 km away from the starting point and is located at an angle of 45 degrees counter-clockwise from the east axis.

To calculate the distance from the starting point, we can use the Pythagorean theorem. The jogger first runs 5 km east, then 6 km northwest, and finally 3 km south.

The distance traveled east and west cancels out, as they are in opposite directions. So we only need to consider the north-south distance.

The north-south distance is the sum of the distances traveled north (0 km) and south (3 km), which gives us a total distance of 3 km.

Therefore, the jogger is 3 km away from the starting point.

To determine the direction from the starting point, we can use trigonometry. We can consider the east direction as 0 degrees, and measure angles counter-clockwise from the east axis.

Since the jogger traveled northwest, which is halfway between north and west, the angle from the east axis would be 45 degrees (45°).

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10 procent

Step-by-step explanation:

150 / 150 = 10

Answer:10%

Step-by-step explanation:

The distance to the top of the building changing when they are 60 feet from the base of the building is 2.19 ft/s.

In the given question we have to find how fast is the distance to the top of the building changing when they are 60 feet from the base of the building.

A family is walking toward their home, which is in an apartment building 123 feet tall.

They are walking at a rate of 5 ft/sec.

So according to the given statement diagram is

In the diagram x represent base and s represent the distance.

Using the Pythagorean theorem to find the value of s.

So the equation should be

\(s^2=x^2+(123)^2\)........................(1)

From the question, x=60 feet

Now putting the value

\(s^2=(60)^2+(123)^2\)

\(s^2\) = 3600+15129

\(s^2\) = 18729

s = 136.85

Differentiate equation 1 with respect to t using the power rule then solve the expression for ds/dt

2s ds/dt=2x dx/dt+0

2s ds/dt= 2x dx/dt

Divide by 2s on both side, we get

ds/dt= x/s dx/dt.......................(2)

They are walking at a rate of 5 ft/sec.

So dx/dt=5

Putting the value in the equation 2

ds/dt=60/136.85 ×5

ds/dt=0.438×5

ds/dt=2.19 ft/s

The distance to the top of the building changing when they are 60 feet from the base of the building is 2.19 ft/s.

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Step-by-step explanation:

angle 2 = 2x + 10 deg (corresponding angles) or 180 - 4x + 46 deg (angles on a straight line are supplementary)

therefore,

2x + 10 = 226 - 4x

6x = 216

x = 36

hence,

angle 2 = 2(36) + 10 = 82deg

Topic: Angles

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