Please solve 7(-2x+4)=-4x

There are at least two times during the flight, such as takeoff, landing, or temporary slowdown/acceleration, when the speed of the plane could reach 200 miles per hour.

The speed of the plane can be calculated by dividing the total distance of the flight by the total time taken. In this case, the total distance is 1980 miles and the total time taken is 4.2 hours.

Therefore, the average speed of the plane during the flight is 1980/4.2 = 471.43 miles per hour.

To understand why there are at least two times during the flight when the speed of the plane is 200 miles per hour, we need to consider the concept of average speed.

The average speed is calculated over the entire duration of the flight, but it doesn't necessarily mean that the plane maintained the same speed throughout the entire journey.

During takeoff and landing, the plane's speed is relatively lower compared to cruising speed. It is possible that at some point during takeoff or landing, the plane's speed reaches 200 miles per hour.

Additionally, during any temporary slowdown or acceleration during the flight, the speed could also briefly reach 200 miles per hour.

In conclusion, the average speed of the plane during the flight is 471.43 miles per hour. However, there are at least two times during the flight, such as takeoff, landing, or temporary slowdown/acceleration, when the speed of the plane could reach 200 miles per hour.

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Let's start solving the expression using the product to sum formulae.

Here's the given expression,

\[\sin \frac{x}{3} \cos \frac{2 x}{3}+\cos \frac{x}{3} \sin \frac{2 x}{3}\]

Using the product-to-sum formula,

\[\sin A \cos B=\frac{1}{2}[\sin (A+B)+\sin (A-B)]\]

Applying the above formula in the first term,

\[\begin{aligned}\sin \frac{x}{3} \cos \frac{2 x}{3} &= \frac{1}{2} \left[\sin \left(\frac{x}{3}+\frac{2 x}{3}\right)+\sin \left(\frac{x}{3}-\frac{2 x}{3}\right)\right] \\&= \frac{1}{2} \left[\sin x+\sin \left(-\frac{x}{3}\right)\right]\end{aligned}\]

Using the product-to-sum formula,

\[\cos A \sin B=\frac{1}{2}[\sin (A+B)-\sin (A-B)]\]

Applying the above formula in the second term,

\[\begin{aligned}\cos \frac{x}{3} \sin \frac{2 x}{3}&= \frac{1}{2} \left[\sin \left(\frac{2 x}{3}+\frac{x}{3}\right)-\sin \left(\frac{2 x}{3}-\frac{x}{3}\right)\right] \\ &= \frac{1}{2} \left[\sin x-\sin \left(\frac{x}{3}\right)\right]\end{aligned}\]

Substituting these expressions back into the original expression,

we have\[\begin{aligned}\sin \frac{x}{3} \cos \frac{2 x}{3}+\cos \frac{x}{3} \sin \frac{2 x}{3} &= \frac{1}{2} \left[\sin x+\sin \left(-\frac{x}{3}\right)\right]+\frac{1}{2} \left[\sin x-\sin \left(\frac{x}{3}\right)\right] \\ &=\frac{1}{2} \sin x + \frac{1}{2} \sin x - \frac{1}{2} \sin \left(\frac{x}{3}\right)\\ &= \sin x - \frac{1}{2} \sin \left(\frac{x}{3}\right)\end{aligned}\]

Therefore, the given expression can be written in terms of a single trigonometric function as:

\boxed{\sin x - \frac{1}{2} \sin \left(\frac{x}{3}\right)}

Hence, the required expression is \sin x - \frac{1}{2} \sin \left(\frac{x}{3}\right). The solution is complete.

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Answer:

p = 40

Step-by-step explanation:

20/6 = p/12

20 × 12 = 6 × p

240 = 6p

p = 240/6

p = 40

Answer:

56.25π cm^2

Step-by-step explanation:

circumference = 15π

diameter*π = circumference

diameter = 15π/π

radius*2 = diameter

radius*2 = 15

radius = 7.5

area = π*radius^2

area = π*7.5^2

area = 56.25π

Answer:

A = 56.25π cm²

Step-by-step explanation:

the area (A) of a circle is calculated as

A = πr² ( r is the radius )

to find r use the circumference formula

C = 2πr

given C = 15π , then

2πr = 15π ( divide both sides by 2π )

r = 7.5 cm

then

A = π × 7.5² = 56.25π cm²

Answer:

0.4

Step-by-step explanation:

The question is not complete, the correct question is:

Two events, X and Y, are independent of each other. P(Y) = 5/6 and P(X and Y) = 1/3. What is P(X) written as a decimal? Round to the nearest tenth, if necessary

Answer: Two events (event X and event Y) are said to be independent if the probability of event X occurring does not affect the probability of event Y occurring and vice versa. If the probability of X = P(X) and the probability of Y = P(Y), therefore P(X and Y) = P(X) × P(Y).

Given that P(Y) = 5/6 and P(X and Y) = 1/3. Therefore:

P(X and Y) = P(X) × P(Y)

Making P(X) the subject of formula by dividing through by P(Y) gives:

\(P(X)=\frac{P(X\ and\ Y)}{P(Y)} \\Substituting\ values:\\P(X)=\frac{\frac{1}{3} }{\frac{5}{6} }=\frac{1}{3} *\frac{6}{5}=\frac{2}{5}=0.4\\ P(X)=0.4\)

Answer:

0.4

Step-by-step explanation:

edg 2021

The range at which Dan's car can go is 3.33 miles

A car's range is the distance it can travel with the current amount of fuel in the tank.

The vehicle calculates the range based on the amount of fuel, how the accelerator and brakes are used, and how quickly the car is travelling.

The range of a car can be measured in the unit of distance.

Therefore the range of a car can be calculated as;

R = distance per gallon/ number of gallon.

Dan's car is 40mpg and has 12 gallons in it's tank.

Therefore it's range = 40/12

= 3.33miles.

therefore the range of Dan's car is 3.33miles

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A Pearson correlation coefficient of +1.00 between two variables, X and Y, indicates a perfect positive correlation between them. This means that as the values of X increase, so do the values of Y, and vice versa.

In other words, the two variables are perfectly linearly related, and there is no variability in their relationship. A Pearson correlation coefficient of +1.00 is the strongest possible correlation coefficient, and it suggests that there is a direct and strong association between the two variables being measured.

For example, let's say we have data on the height and weight of a group of individuals. If we find a Pearson correlation coefficient of +1.00 between height and weight, it means that as a person's height increases, their weight will also increase perfectly in a linear fashion. This information can be useful in predicting weight based on height, or vice versa, and can help inform decisions related to health and fitness.

Overall, a Pearson correlation coefficient of +1.00 suggests that the two variables being measured have a strong and direct relationship, which can be useful in many different contexts.

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There are 3080 ways 3 men and 2 women can be chosen if they are equally considered, using the multiplication principle of counting

The multiplication principle states that if there are m ways to perform one task and n ways to perform another task, then there are m x n ways to perform both tasks together.

To find the number of ways to choose 3 men from the 12 men, we can use the formula for combination, which is: ⁿCᵣ = n! / (r! (n-r)!).

where n is the total number of men and r is the number of men chosen

so, the number of ways to choose 3 men from the 12 men = ¹²C₃ = 1.

Similarly, we evaluate the number of ways to choose 2 women from the 8 women

as = ⁸C₂ = 14

Now, using the multiplication principle, we can find the total number of ways 3 men and 2 women be chosen if they are equally considered.

220 x 14 = 3080

Therefore, there are 3080 ways 3 men and 2 women can be chosen if they are equally considered, using the multiplication principle of counting

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Step-by-step explanation:

they are the same length sooo what class is this???????

The measure of the angle is <B is 110 degrees

It is important to note that supplementary angles are described as angles that sum up to 180 degrees.

From the information given, we have that;

m<A = x + 26

m>B = 2x + 22

Equate the angles

m<A +m<B = 180

x + 26 + 2x + 22 = 180

collect the like terms

3x = 180 - 48

3x = 132

x = 44

the measure of <B = 2x + 22 = 2(44) + 22 = 88 + 22 = 110 degrees

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Working Model: Properties of Rational Numbers (Addition and Multiplication)

Using colored blocks, demonstrate how the closure, commutative, associative, and distributive properties hold true when performing addition and multiplication with rational numbers. Show visually and explain the properties through manipulations and examples.

Materials needed:

Colored blocks (preferably different colors to represent different rational numbers)

Paper or whiteboard to write down the operations and results

Closure Property of Addition

Start with two colored blocks, representing two rational numbers, such as 1/3 and 2/5.

Add the two blocks together by placing them side by side.

Explain that the sum of the two rational numbers is also a rational number.

Write down the addition operation and the result: 1/3 + 2/5 = 11/15.

Commutative Property of Addition

Take the same two colored blocks used in the previous step: 1/3 and 2/5.

Rearrange the blocks to demonstrate that the order of addition does not change the result.

Explain that the sum of the two rational numbers is the same regardless of the order.

Write down the addition operations and the results: 1/3 + 2/5 = 2/5 + 1/3 = 11/15.

Associative Property of Addition

Take three colored blocks representing three rational numbers, such as 1/4, 2/5, and 3/8.

Group the blocks and perform addition in different ways to show that the grouping does not affect the result.

Explain that the sum of the rational numbers is the same regardless of how they are grouped.

Write down the addition operations and the results: (1/4 + 2/5) + 3/8 = 25/40 + 3/8 = 47/40 and 1/4 + (2/5 + 3/8) = 1/4 + 31/40 = 47/40.

Distributive Property

Take two colored blocks representing rational numbers, such as 2/3 and 4/5.

Introduce a third colored block, representing a different rational number, such as 1/2.

Demonstrate the distribution of multiplication over addition by multiplying the third block by the sum of the first two blocks.

Explain that the product of the rational numbers distributed over addition is the same as performing the multiplication separately.

Write down the multiplication and addition operations and the results: 1/2 * (2/3 + 4/5) = (1/2 * 2/3) + (1/2 * 4/5) = 2/6 + 4/10 = 4/6 + 2/5 = 22/30.

By using this working model, students can visually understand and grasp the concepts of closure, commutative, associative, and distributive properties of rational numbers through hands-on manipulation and observation.

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The minimum number of masthead lights for the given vessel is 2.

The ratio can be defined as the proportion of the fraction of one quantity towards others. e.g.- water in milk.

Here,
A towing vessel 35 meters in length, with a tow 100 meters astern,

Masthead lights = total length of the tow / total length of the vessel
                        = 100 / 35 = 2.85

So, the Number of Masthead lights for the given vessel is 2 ≤ x ≤ 3.
And a minimum number of masthead lights is 2.

Thus, the minimum number of masthead lights for the given vessel is 2.

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The absolute maximum of the function on the given interval is at x = 7, and the value is f(7) = 4^(3/4).

To determine the location and value of the absolute extreme values of the function f(x) = (x-3)^3/4 on the interval [-7, 7], follow these steps:

1. Find the critical points by taking the derivative of the function and setting it to zero.
2. Evaluate the function at the critical points and the endpoints of the interval.
3. Compare the function values to determine the absolute maximum and minimum.

Step 1: Find the critical points.
f(x) = (x-3)^(3/4)
f'(x) = (3/4)(x-3)^(-1/4)

Set f'(x) = 0
(3/4)(x-3)^(-1/4) = 0

There is no solution for x, so there are no critical points.

Step 2: Evaluate the function at the endpoints of the interval.
f(-7) = (-7-3)^(3/4) = (-10)^(3/4) = 10^(3/4) * (-1)^(3/4)
f(7) = (7-3)^(3/4) = 4^(3/4)

Step 3: Compare the function values.
f(-7) = 10^(3/4) * (-1)^(3/4)
f(7) = 4^(3/4)

Since (-1)^(3/4) is a complex number and f(7) is a real number, the absolute maximum occurs at x = 7.

The absolute maximum of the function on the given interval is at x = 7, and the value is f(7) = 4^(3/4).

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The area of the region outside the doghouse that skipper can reach is 3(pi)^2 yards.

This problem is based on the area of sectors. Now, we know that a sector is a pie-shaped part of a circle made of the arc along with its two radii.

The image which correctly explains the situation in the problem is attached.

From the figure, we can see that the spot can be located anywhere in the two sectors of 120  and  60 degrees each respectively. Now, these radii are respectively of 2 and 1 yards.

Area of one sector of 120 degrees = 120/360 π (2)^2 since radius is 2 yards.

So, area of two sectors is 2 x  120/360 π (2)^2 = 8π /3 square yards.

Similarly, Area of the two 60 degrees sectors is -

2 x  60/360 π (2)^2 = π /3 sq. yards.

Therefore , the total area that the skipper can reach outside the doghouse is given by the sum of all the four sectors i.e. π /3 + 8π /3 =

3π square yards.

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The area of the region outside the doghouse that the skipper can reach is \(3\pi ^2\) yards.

This problem is based on the area of sectors. Now, we know that a sector is a pie-shaped part of a circle made of an arc along with its two radii.

The image which correctly explains the situation in the problem is attached.

From the figure, we can see that the spot can be located anywhere in the two sectors of 120  and  60 degrees each respectively. Now, these radii are respectively 2 and 1 yards.

Area of one sector of 120 degrees \(=\frac{(\pi*2^2*120) }{360}\) since the radius is 2 yards.

So, the area of the two sectors is \(\frac{(2*120*2^2*\pi )}{360}=\frac{8\pi }{3}\) square yards.

Similarly, the Area of the two 60 degrees sectors is -

\(\frac{(2*60*\pi *2^2)}{360} =\frac{\pi }{3}\) sq. yards.

Therefore, the total area that the skipper can reach outside the doghouse is given by the sum of all the four sectors i.e. \(\frac{\pi }{3} +\frac{8\pi }{3} =3\pi\)square yards.

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The equation for the hyperbola with foci (0,±5) and asymptotes y=± 3/4 x is:

y^2 / 25 - x^2 / a^2 = 1

where a is the distance from the center to a vertex and is related to the slope of the asymptotes by a = 5 / (3/4) = 20/3.

Thus, the equation for the hyperbola is:

y^2 / 25 - x^2 / (400/9) = 1

or

9y^2 - 400x^2 = 900

The center of the hyperbola is at the origin, since the foci have y-coordinates of ±5 and the asymptotes have y-intercepts of 0.

To graph the hyperbola, we can plot the foci at (0,±5) and draw the asymptotes y=± 3/4 x. Then, we can sketch the branches of the hyperbola by drawing a rectangle with sides of length 2a and centered at the origin. The vertices of the hyperbola will lie on the corners of this rectangle. Finally, we can sketch the hyperbola by drawing the two branches that pass through the vertices and are tangent to the asymptotes.

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Answer and work down below. Let me know if you have any questions

The power series representation for the function f(x) = ln(5 - x) centered at x = 0 is given by ln(5) - Σ((-1)^(n-1)/n) * x^n, where the summation goes from n = 1 to infinity. The radius of convergence, R, is 5.

To find the power series representation, we start with the known power series expansion of ln(1 + x) centered at x = 0, which is Σ((-1)^(n-1)/n) * x^n. By substituting x with (5 - x), we obtain ln(5 - x) = Σ((-1)^(n-1)/n) * (5 - x)^n.

Since ln(5) is a constant term, we can separate it from the series representation, giving us f(x) = ln(5) - Σ((-1)^(n-1)/n) * (5 - x)^n, where the summation goes from n = 1 to infinity.

The radius of convergence, R, is the distance between the center of the power series (x = 0) and the nearest singularity of the function. In this case, the function ln(5 - x) is singular at x = 5. Therefore, the radius of convergence, R, is 5.


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Answer:

Let's start by assigning variables to the unknowns in the problem. Let x be the number of $100 notes, y be the number of $50 notes, and z be the number of $10 notes.

We know that the ratio of these notes is 2:3:5, so we can write:

x:y:z = 2:3:5

This means that we can write x as 2k, y as 3k, and z as 5k, where k is some constant.

We also know that the total amount of money is $200,000, so we can write:

100x + 50y + 10z = 200000

Substituting our expressions for x, y, and z in terms of k, we get:

100(2k) + 50(3k) + 10(5k) = 200000

Simplifying and solving for k, we get:

20k = 2000

k = 100

So we know that x = 2k = 200, y = 3k = 300, and z = 5k = 500.

Therefore, there are 200 $100 notes, 300 $50 notes, and 500 $10 notes.

The given statement states that the parametrization of both the tangent line there at designated position is 7x - 4y = 3.

Finding parametric equations of a curve, a surface, or, more generally, a manifold or a variety, specified by an implicit equation, is the process of parametrization (or parameterization; see parameterization, parametrization). Implicitization is the term for the opposite process.  The parametrization consists of one function of multiple real variables for each coordinate since the state of the system is typically controlled by a finite set of coordinates. The system's degree of freedom is equal to the number of parameters.

r(t) = cos(6t), sin(3t) , t = 4

= -6sin6t, 3cosjt , 1

The parameter of Tangent live is

L(t) = γ(t₀) + tr'(t₀)

therefore

γ(t₀) = γ(ππ₄)

= (0 , 1/√2 , π/4)γ (+0)  =  γ(π/4)

= ( 6, -3/√2 , 1)

putting in the formula we get:

L(t) = γ(t₀) + tr'(t₀)

L(t) = (0 , 1/√2 , π/4) + t( 6, -3/√2 , 1)

= \(\left(6 t-\frac{1}{\sqrt{2}}-\frac{3}{\sqrt{2}} t, \frac{\pi}{4}+t\right)$$\)

= 2.

Given

f(x, y ) = in(7x² - 4y²)

at the point(1, 1)

Δ f (m, y) = (fn , f4)

= \(\frac{14 x}{7 n^2-4 y^2}, \frac{-8 y}{7 x^2-4 y^2}\\\\\)

Δ f (1, 1)

= \(\left\langle\frac{14}{3}, \frac{-8}{3}\right\rangle\)

= (a ,b)

The equation of the tangent plane is

a(x - x₀) + 6dy - y₀ = 0

(14/3)(x - 1)- (8/3)(y -1 ) = 0

14x - 14 - 8y + 8 = 0

14x - 8y = 6

7x - 4y = 3

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Answer:

19.63mm² should be the answer

Answer:

19.63 mm²

Step-by-step explanation:

Hope this helps can i get brainliest im trying to get to the Virtuoso rank i would really Appreciate it

Answer:

The answer would be C.48%

Answer:

100,000=10^5,  and 1/100,000= 1/10^5=10^-5

so this is your answer

10^5 x 10^-5

Step-by-step explanation:

Sample answer from Edmentum.

The exponential value of  1,00,000 and 1/1,00,000 is 10⁵ and 10⁻⁵.

The formula for an exponential function is f (x) = axe, where x is a variable and an is a constant that serves as the function's base and must be bigger than 0. The transcendental number e, or roughly 2.71828, is the most often used exponential function basis.

Given numbers 1,00,000 and 1/1,00,000

factors of 1,00,000 = 10 x 10 x 10 x 10 x 10

1,00,000 in exponential form is 10⁵ because 10 is multiplying continuously 5 times.

and 1/1,00,000 = 1/(10⁵)

using formula 1/aⁿ = a⁻ⁿ

so  1/(10⁵) = 10⁻⁵

Hence exponential for numbers is  10⁵ and  10⁻⁵.

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20 is not a solution of the inequality as the value is greater than 400 rather being less than 400.

We have the inequality

26g < 400

Now, for g = 20

26g

=26(20)

= 520 > 400

So, 20 is not a solution of the inequality as the value is greater than 400 rather being less than 400.

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The 99% confidence interval for the expected proportion of the vote is approximately (0.531, 0.629).

To

Next, find the critical value corresponding to a 99% confidence level. For a two-tailed test, the critical value is the z-score that leaves 0.5% in each tail. From the standard normal distribution table, the critical value is approximately 2.576.

Now, substitute the values into the formula:

\(CI = 0.58 ± 2.576 * √((0.58 * (1-0.58)) / 800)\)

Calculating the standard error:

\(SE = √((0.58 * (1-0.58)) / 800) ≈ 0.019\)

Calculating the margin of error:

\(ME = 2.576 * 0.019 ≈ 0.049\)

Finally, calculate the confidence interval:

\(CI = 0.58 ± 0.049\)

\(CI = 0.58 ± 0.049\)

The 99% confidence interval for the expected proportion of the vote is approximately (0.531, 0.629).

Interpretation: We are 99% confident that the true proportion of people who would vote for the candidate in a two-person race is between 53.1% and 62.9%.

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Answer:

3

Step-by-step explanation:

Answer:

1.7 m/s

Step-by-step explanation:

1/3 mile = 536 m

1/12 hour = 5 minutes = 300 second

volecity = s/t = 536 / 300 = 1.7 m/s

9514 1404 393

Answer:

  4 miles per hour

Step-by-step explanation:

Speed is the ratio of distance to time:

  speed = miles/hours = (1/3)/(1/12) = (4/12)/(1/12) = 4/1 = 4

Mr. M's walking speed is 4 miles per hour.

A recent report estimates that four out of every five dentists recommend a brand of toothpaste situation involves Inferential statistics.

Inferential statistics are widely employed to compare the differences between the treatment groups. Inferential statistics compare the treatment groups and make generalizations about the subject population using data from the experiment's sample of subjects. To offer answers for a situation or phenomena, inferential statistics is helpful. It differs fundamentally from descriptive statistics, which do not allow for result extrapolations and merely report the data that has already been measured.

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Answer:

232 cars

Step-by-step explanation:

Let's say the number of cars that entered is c.

At 9:00 am, there are a total of 24 + c cars and 64 trucks. We know that this value of 64 represents 1/5 of the total number of vehicles. The total number of vehicles is (24 + c) + 64 = 88 + c. So, we have:

64/(88 + c) = 1/5

Cross-multiply:

88 + c = 64 * 5 = 320

c = 320 - 88 = 232

Thus, the answer is 232 cars.

Note: as 232 doesn't show up in the answer choices, it's possible that the problem was copied correctly.

~ an aesthetics lover

Answer:

232 cars entered between 8 and 9

Step-by-step explanation:

at 9 am there are 64 x 5 vehicles total = 320

320 - 64 - 24 = 232