Please someone help me with this im giving brainliest!!

The measure of angle APB in the intersecting chords is 10⁰.

The measure of angle APB is calculated by applying intersecting chord theorem which that the angle at tangent is half of the arc angle of the two intersecting chords.

The value of m∠APB is calculated as follows;

m∠APB = ¹/₂ (arc AC - arc AB ) ( exterior intersecting secants)

The value of arc angle AC = 80⁰

The value of arc angle AB = 60⁰

Now substitute and solve for the value of angle APB as follows;

m∠APB = ¹/₂ (80 - 60 )

m∠APB = ¹/₂ ( 20 )

m∠APB = 10⁰

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The complete question is below:

In the accompanying diagram, tangent PA and secant PBC are drawn to circle O from point P. If mAC=80 and mAB=60, what is the measure of angle APB.

The price of the Haswell Enterprises' bond is $1,124.61.

Step 1: To calculate the bond price  we need to use the present value formula, which takes into account the future cash flows discounted by the market interest rate.

Step 2: First, we need to calculate the number of periods, since the bond pays a semiannual coupon and has a 10-year maturity. There are 20 semiannual periods (10 years \(\times\) 2 semiannual periods per year).

Step 3: Next, we need to calculate the semiannual coupon payment. The coupon rate is 6.25%, which means the bond pays a semiannual coupon of:

Coupon payment = Coupon rate \(\times\) Par value / 2

Coupon payment = 6.25% \(\times\)$1,000 / 2

Coupon payment = $31.25

Using the present value formula, the bond price can be calculated as:

Price of bond = (Coupon payment / (1 + Market interest rate/2\()^1\)) + (Coupon payment / (1 + Market interest rate/2\()^2\)) + ... + (Coupon payment + Par value / (1 + Market interest rate/2\()^{20}\))

where:

Market interest rate is 4.75% (semiannual)

Coupon payment is $31.25

Par value is $1,000

Plugging in the values, we get:

Bond price = ($31.25 / (1 + 4.75%/2\()^1\)) + ($31.25 / (1 + 4.75%/2\()^2\)) + ... + ($31.25 + $1,000 / (1 + 4.75%/2\()^{20}\))

Price of bond = $1,124.61

Therefore, the price of the Haswell Enterprises' bond is $1,124.61.

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A certain plane is described by 2x+3y+4z=16. Find the unit vector normal to the surface in the direction away from the origin.Firstly, we will obtain the coefficients of the x, y and z variables from the equation of the plane:2x + 3y + 4z = 16The coefficients are 2, 3, and 4 respectively.

Now, we will calculate the magnitude of the normal vector, ||N||, using the formula:||N|| = √(a² + b² + c²)where a, b, and c are the coefficients of the x, y, and z variables respectively.||N|| = √(2² + 3² + 4²)= √(4 + 9 + 16)= √29Therefore, the unit normal vector in the direction away from the origin is given by:N = (2/√29) i + (3/√29) j + (4/√29) k. Given the equation of a plane as 2x + 3y + 4z = 16, we have to find the unit vector normal to the surface in the direction away from the origin. Here's how we can do it:To find the unit vector normal to the surface, we first need to find the coefficients of the x, y, and z variables from the equation of the plane. In this case, the coefficients are 2, 3, and 4 respectively.Next, we can use the formula ||N|| = √(a² + b² + c²) to calculate the magnitude of the normal vector, where a, b, and c are the coefficients of the x, y, and z variables respectively. In this case, ||N|| = √(2² + 3² + 4²) = √29.Finally, we can find the unit normal vector in the direction away from the origin by dividing each coefficient by the magnitude of the normal vector, ||N||. Thus, the unit normal vector is:N = (2/√29) i + (3/√29) j + (4/√29) k

Therefore, the unit vector normal to the surface in the direction away from the origin is (2/√29) i + (3/√29) j + (4/√29) k.

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Answer:

21.7

Step-by-step explanation:

XZ=XY+YZ=6.9+14.8=21.7

Hope, this helps you.

The area of the semi-circle with a diameter of 18 cm will be 127.17 square cm.

It is the close curve of an equidistant point drawn from the center. The radius of a circle is the distance between the center and the circumference.

Let 'd' be the diameter of the circle. Then the area of the circle will be

A = (π/4)d² square units

The diameter is 18 cm. Then the area of the circle is given as,

A = (π/4) x 18²

A = (3.14 / 4) x 324

A = 254.34 square cm

Then the area of the semicircle is the area of the half of the circle, then we have

Semicircle area = 254.34 / 2

Semicircle area = 127.17 square cm

The area of the semi-circle with a diameter of 18 cm will be 127.17 square cm.

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Answer:

0.5 OR 1/2

Step-by-step explanation:

Since the two points are (6,4) and (12,7) you would find the distance in x and y.

Slope = change in y/ change in x

Change in y: the y coordinates are 4 and 7, so 4 + 3 = 7. +3 is the change.

Change in x: the x coordinates are 6 and 12, so 6 + 6 = 12. +6 is the change.

Slope = 3/6 = 1/2 = 0.5 = 50%

Hope this helps :D

Answer:

C

Step-by-step explanation:

200g + 4g = C. 204 g

Mass is the quantity of matter present in a substance. Density is the ratio of mass to volume. It is given by:

Density = mass/ volume

Given that a 4g salt is dissolved in 200 g of water. Hence:

Final mass of mixture = mass of salt + mass of water

Final mass of mixture = 4g + 200g = 204g

The final mass of  this mixture is 204g

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In the above question, (image attached) The option that shows the segments that are parallel, if any, if ∠EDA≅∠HCB is option A: None of these.

Note that by examining the the image if ∠EDA≅∠HCB, the two lines can never intersect even if they go a longer distance.

The reason why is that there are no parallel lines on it and as such, they cannot intercept.

Hence, In the above question, (image attached) The option that shows the segments that are parallel, if any, if ∠EDA≅∠HCB is option A: None of these.

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The amount of storage required to represent a simple graph with n vertices and m edges can vary depending on the chosen representation. Here's the storage requirement for each representation:

a) Adjacency lists:

In an adjacency list representation, we typically use an array of size n to store the vertices, and for each vertex, we maintain a linked list or an array to store its adjacent vertices. The space complexity of this representation is O(n + m), where n is the number of vertices and m is the number of edges.

Each vertex requires constant space, and each edge is represented by a link or entry in the adjacency list.

b) Adjacency matrix:

In an adjacency matrix representation, we use a 2D matrix of size n x n to represent the graph. Each entry (i, j) in the matrix represents whether there is an edge between vertices i and j. The space complexity of this representation is O(n^2), as we need to store n^2 entries for the complete matrix. However, if the graph is sparse (few edges compared to vertices), the space complexity can be reduced to O(n + m) by only storing the entries corresponding to the existing edges.

c) Incidence matrix:

In an incidence matrix representation, we use a 2D matrix of size n x m, where n is the number of vertices and m is the number of edges. Each entry (i, j) in the matrix represents whether vertex i is incident to edge j. The space complexity of this representation is O(n * m), as we need to store n * m entries for the matrix.

Similar to the adjacency matrix, if the graph is sparse, the space complexity can be reduced to O(n + m) by storing only the entries corresponding to the existing edges.

In summary:

a) Adjacency lists: O(n + m)

b) Adjacency matrix: O(n^2) or O(n + m) for sparse graphs

c) Incidence matrix: O(n * m) or O(n + m) for sparse graphs

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Answer:

BCE= 115    ECD=65

Step-by-step explanation:

(5x+10)+(3x+2)=180

8x+12=180

8x=168

x=21

5(21)+10=115

3(21)+2=65

Answer:

<BCE=115°

<ECD=65°

And their sum is 180°

Step-by-step explanation:

< BCE + <ECD =180° ( Being sum of supplementary angle which is formed in the given diagram is 180°)

(5x + 10)° + (3x + 2)°= 180°

5x + 10 + 3x + 2 = 180°

5x + 3x + 10 +2 = 180°

8x + 12= 180°

8x = 180°-12°

8x = 168

x= 168/8

x=21°

Now,

<BCE = 5x+10

= 5*21+10

=105+10

=115

<ECD

= 3x+2

= 3*21+2

=65

Answer:

Variable B is the area of triangular base.

B = 38.5 \(in^{2}\).

Variable h is the height of pyramid.

In the given prism, h is 9 inches.

The volume of prism is 346.5 \(in^{3}\).

Step-by-step explanation:

Please refer to the attached image for the detailed labeling of all the sides.

\(\triangle ABC\) is the triangular base of the prism.

BC is the base of triangular base of the prism.

AP is the height of triangular base.

Area of triangular base is represented by B and is calculated by following formula of area of a triangle.

\(Area = \dfrac{1}{2} \times \text{Base}\times \text{Height}\)

\(\Rightarrow \dfrac{1}{2} \times 11 \times 7\\\Rightarrow 38.5\ in^{2}\)

Hence, B = 38.5 \(in^{2}\).

Height of prism, h = 9 in

h is represented as side BE in the attached image.

It is know that volume of prism is given as :

V = Bh

Putting values of B and h:

\(V = 38.5 \times 9\\\Rightarrow V = 346.5\ in^{3}\)

Answer:

The formula for volume of a prism is V = Bh.

The variable B stands for the ✔ area of the base.

In this prism, B equals ✔ 38.5  in.².

The variable h stands for ✔ height.

In this prism, h is ✔ 9 in.

The volume of the prism is ✔ 346.5  in.³.

Explanation:

The answer above mine is correct. I hope this helps!

Answer:

True, there is a y-intercept at (0,2)

Answer:

3

Step-by-step explanation:

multiplication rule of exponents is to multiply the bases (sq rt 3) and add the exponents

(sq rt 3)^2 = 3

add exponents and power of 1

For a result to be considered significant, the chances of its occurring as a result of random error are often less than 5 percent.

A coincidental discrepancy between the observed and true values of anything is known as a random error (e.g., a researcher misreading a weighing scale records an incorrect measurement).

It's not always a mistake when there is random error; rather, it happens when measurements are made. Even when you measure the same item repeatedly, there will always be some variation in your results because to changes in the environment, the instrument, or your own perceptions.

Your measurements are equally likely to be greater or lower than the genuine values due to random error, which has unexpected effects.

According to the given data,

For a result to be considered significant, the chances of its occurring as a result of random error are often less than 5 percent.

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(a) The game tree for n = 4 cards can be represented as follows:

markdown

       Alice

      /  |  |  \

     1   3  4   5

    /     |     \

  Bob     |     Dave

  / \     |     / \

 3   4    5    1   3

b here is a bijection between the set of valid games for n cards and a particular subset of subgraphs of K4.n.

In this game tree, each level represents a player's turn, starting with Alice at the top. The numbers on the edges represent the cards played by each player. At each level, the player has multiple choices depending on the available cards. The game tree branches out as each player makes their move, and the game continues until all cards have been played or no valid moves are left.

(b) To prove the bijection between the set of valid games for n cards and a subset of subgraphs of K4.n, we can associate each player's move in the game with an edge in the bipartite graph. Let's consider a specific example with n = 4.

In the game, each player chooses a card from their hand that hasn't been played before. We can represent this choice by connecting the corresponding vertices of the bipartite graph. For example, if Alice plays card 2, we draw an edge between the vertex representing Alice and the vertex representing card 2. Similarly, Bob's move connects his vertex to the chosen card, and so on.

By following this process for each player's move, we create a subgraph of K4.n that represents a valid game. The set of all possible valid games for n cards corresponds to a subset of subgraphs of K4.n.

Therefore, there is a bijection between the set of valid games for n cards and a particular subset of subgraphs of K4.n.

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The orthogonal decomposition of v with respect to w is [1, -1].

To find the orthogonal decomposition of v with respect to w, we need to find the orthogonal projection of v onto w, and the projection of v onto the orthogonal complement of w.

First, let's find the orthogonal projection of v onto w. The formula for the orthogonal projection of v onto w is:

\(\proj w(v) = ((v \cdot w)/||w||^2) * w\)

where · represents the dot product and ||w|| represents the magnitude of w.

We have:

v = [1, -1]

w = [2, 2]

The dot product of v and w is:

v · w = 1*2 + (-1)*2 = 0

The magnitude of w is:

\(||w|| = \sqrt(2^2 + 2^2) = 2\sqrt(2)\)

Therefore, the orthogonal projection of v onto w is:

\(\proj w(v) = ((v \cdot w)/||w||^2) * w = (0/(2\sqrt(2))^2) * [2, 2] = [0, 0]\)

Next, let's find the projection of v onto the orthogonal complement of w. The orthogonal complement of w is the set of all vectors that are orthogonal to w.

We can find a basis for the orthogonal complement of w by solving the equation:

w · x = 0

where x is a vector in the orthogonal complement. This equation represents the condition that x is orthogonal to w.

We have:

w · x = [2, 2] · [x1, x2] = 2x1 + 2x2 = 0

Solving this equation for x2, we get:

x2 = -x1

So any vector of the form [x1, -x1] is in the orthogonal complement of w. Let's choose [1, -1] as a basis vector for the orthogonal complement.

To find the projection of v onto [1, -1], we can use the formula:

\(\proj u(v) = ((v \cdot u)/||u||^2) * u\)

where u is a unit vector in the direction of [1, -1]. We can normalize [1, -1] to obtain:

\(u = [1, -1]/||[1, -1]|| = [1/\sqrt(2), -1/\sqrt(2)]\)

The dot product of v and u is:

\(v \cdot u = 1*(1/\sqrt(2)) - 1*(-1/\sqrt(2)) = \sqrt(2)\)

The magnitude of u is:

\(||u|| = \sqrt((1/\sqrt(2))^2 + (-1/\sqrt(2))^2) = 1\)

Therefore, the projection of v onto [1, -1] is:

\(\proj u(v) = ((v \cdot u)/||u||^2) * u = (\sqrt(2)/1^2) * [1/\sqrt(2), -1/\sqrt(2)] = [1, -1]\)

Finally, the orthogonal decomposition of v with respect to w is:

v =\(\proj w(v) + \proj u(v)\) = [0, 0] + [1, -1] = [1, -1]

Therefore, the orthogonal decomposition of v with respect to w is [1, -1].

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Answer:

Explanation:

Given;

Surface area of the figure = 432 cm^2

Length of the square base(l) = 8cm

Height of the prism = 3 times height of the pyramid

We'll use the below formula for the surface area(SA) of the figure to determine the height of the pyramid;

Answer:

angle 4

its on the outside and it is alternate

Answer:

d

Step-by-step explanation:

The solution of the quadratic equation is x=5±√35 .

A quadratic equation is given by the equation which can be written in the form ax²+bx +c.

the given quadratic equation is :

x²-10x+25=35

Simplifying the equation we get:

or, x²-10x+25-35=0

or, x²-10x-10=0

Now we will solve the equation by completion squares method:

x²-10x-10=0

or, x²-2×x×5+5²-5²-10=0

or, (x-5)²=35

or, x-5=±√35

or, x= 5±√35

Therefore the solution of the quadratic equation is 5+√35 and 5-√35 .

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Using the circumference of the circle, it is found that:

About 7.1 feet of railing needs to be replaced.

The circumference of a circle of radius r is given by:

\(C = 2\pi r\)

It is equivalent to 360º.

In this problem, the diameter is of 30 feet, hence the radius is 15 feet, so:

\(C = 2\pi (15) = 30\pi\)

Then, considering that the circumference is equivalent to 360º, the length to be replaced is given by:

\(L = \frac{27}{360} \times 30\pi = 7.1\)

About 7.1 feet of railing needs to be replaced.

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Answer: 7.1

Step-by-step explanation: ANSWER ON EDMENTUM/PLUTO

Answer:

$88.3

Step-by-step explanation:

Here 42% of annual health premium($5450)=*5450

                                                                     =$2289

This amount is being paid by the company means it is deducted amount in one year.

One year has 26 paychecks so above amount divided by 26 is rebate amount in each paycheck.

Deducted amount=

                              =$88.30

Answer:

A.  y = x + 25

    x + y = 75

B.  25 minutes

C.  50 minutes

Step-by-step explanation:

Define the variables:

If Jackie dances 25 minutes more than she runs:

\(\implies y=x+25\)

If Jackie runs and dances for 75 minutes:

\(\implies x+y=75\)

Substitute the first equation into the second equation and solve for x:

\(\implies x+(x+25)=75\)

\(\implies 2x+25=75\)

\(\implies 2x+25-25=75-25\)

\(\implies 2x=50\)

\(\implies 2x\div 2=50 \div 2\)

\(\implies x=25\)

Therefore, Jackie spends 25 minutes running everyday.

Substitute the found value of x into the first equation and solve for y:

\(\implies y=25+25\)

\(\implies y=50\)

Therefore, the greatest amount of time Jackie could spend dancing every day, given she will take a run, is 50 minutes.

Answer:

C.) 5 * 4^n-1

Step-by-step explanation:

Use the given method you use for finding the sequence with the terms.

Also K12 moment.

If it's wrong, please forgive me, I'm in the middle of the test as well.
I checked and I'm 99% sure this is the answer

Hope this helped despite being a little late!

Answer:

5/6

Step-by-step explanation:

See attached Venn diagram

Given they passed the test is 12

    then 10 of these completed the assignment    10 /12 = 5/6

its  7.5 im pretty sure

Solution

Step 1

To convert seconds to hours, divide the seconds by 3600.

Step 2

1 million seconds = 1000000 seconds

A set of points equidistant from a fixed point in a plane figure is called a circle where the distance between each of the set of the points and the fixed point forms the radius of the circle.

A point is said to be equidistant from a set of objects if the distances between that point and each object in the set are equal.

In two-dimensional Euclidean geometry, the locus of points equidistant from two given (different) points is their perpendicular bisector. In three dimensions, the locus of points equidistant from two given points is a plane, and generalising further, in n-dimensional space the locus of points equidistant from two points in n-space is an (n−1)-space.

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