PLEASE THIS IS URGENT!!

1.) Write 2 points of difference between water molecule and hydrogen molecule.

2.) Differentiate between homogeneous and heterogeneous mixture.
​

The volume (in liters) at STP that is equivalent to 14.0 moles of carbon monoxide, CO gas is 313.6 liters

From Ideal gas law, we understood that at standard temperature and pressure, STP, one mole of a gas is given as shown below:

1 mole of gas = 22.4 L at STP

Thus,

1 mole of CO = 22.4 L at STP

With the above information, we can obtain the volume of 14.0 moles of CO at STP. Details below

1 mole of CO = 22.4 liters at STP

Therefore,

14 moles of CO = (14 mole × 22.4 liters) / 1 mole

14 moles of CO = 313.6 liters

Thus, we can conclude that the volume of CO is 313.6 liters

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To calculate the solubility product constant (Ksp) for Mn(OH)2, we need to first determine the concentration of Mn^2+ and OH^- ions in the saturated solution of Mn(OH)2.

The balanced chemical equation for the dissociation of Mn(OH)2 is:

Mn(OH)2(s) ⇌ Mn^2+(aq) + 2OH^-(aq)

From the equation, we can see that one mole of Mn(OH)2 produces one mole of Mn^2+ and two moles of OH^-.

Given the solubility of Mn(OH)2 in pure water as 7.18 × 10^(-1) g/L, we can convert this into moles per liter (M) by using the molar mass of Mn(OH)2.

Molar mass of Mn(OH)2:

M(Mn) = 54.94 g/mol

M(O) = 16.00 g/mol

M(H) = 1.01 g/mol

Molar mass of Mn(OH)2 = M(Mn) + 2 * (M(O) + M(H))

= 54.94 + 2 * (16.00 + 1.01)

= 54.94 + 2 * 17.01

= 54.94 + 34.02

= 88.96 g/mol

Now, we can calculate the concentration of Mn^2+ ions in the saturated solution:

Concentration of Mn^2+ = solubility of Mn(OH)2 / molar mass of Mn(OH)2

= (7.18 × 10^(-1) g/L) / (88.96 g/mol)

= 8.07 × 10^(-3) mol/L

Since the concentration of Mn^2+ ions is equal to the concentration of OH^- ions (according to the stoichiometry of the equation), we can say:

[OH^-] = 8.07 × 10^(-3) mol/L

Finally, we can calculate the Ksp for Mn(OH)2 by multiplying the concentrations of Mn^2+ and OH^- ions:

Ksp = [Mn^2+][OH^-]

= (8.07 × 10^(-3) mol/L)(8.07 × 10^(-3) mol/L)

= 6.51 × 10^(-5) mol^2/L^2

Therefore, the Ksp for Mn(OH)2 is 6.51 × 10^(-5) mol^2/L^2.

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As per the balanced reaction, 2 moles of NaOH  reacts with 1 mole of Li₂S. Then, 18.7 g or 0.4 moles of lithium sulphide needs 0.8 moles of NaOH. But 23.4 g of NaOH is only 0.5 moles. Hence, NaOH is the limiting reactant.

A limiting reactant in a reaction is the reactant which is fewer in amount or consume early without complete reaction with other reactants. Hence, as soon as this reactant is consume, the reaction stops.

In the given reaction, 2 moles of NaOH  reacts with 1 mole of Li₂S. Then, 18.7 g or 0.4 moles of lithium sulphide needs 0.8 moles of NaOH.

Molar mass of NaOH = 40 g

Molar mass of LiOH = 23 g.

80 g of NaOH gives 46 g of LiOH. Then, the mass of LiOH produced from 23.4 g of NaOH is:

(23.4 ×46)/80 = 13.4 g

Therefore, the mass of LiOH produced will be 13.4 g.

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Answer:

what do you need help with .

Explanation:

?

Answer:

Based on stoichiometry HNO3 to H2O is 6:2

Use 9 grams to find the moles of HNO3

9 grams/63g/mol=0.143 moles of HNO3

HNO3:H2O

6:2

0.143*2/6=0.048

H2O moles is 0.048moles

Mass of water =0.048moles*18g/mol=0.864g

To the nearest tenth=0.9grams

( sorry if its not right)

Answer:

See explanation

Explanation:

The reaction of NaOH and KHP is a neutralization reaction. The molarity of KHP is often calculated from the mass of KHP used to prepare the standard solution.

KHP is a slightly acidic substance. It is used as a primary standard for acid-base titrations because the solid is stable in air hence it is easy to weigh accurately. Also, the solid is neither hygroscopic nor deliquescent.

If student A recorded the amount of KHP used for the titration as 0.10g instead of 0.15g, then the molarity of NaOH calculated will be less than the actual the actual molarity of the NaOH.

Answer:

Ammonia

Explanation:

I believe that ammonia is the correct answer to this question.

You should weigh 3.038 g of lead (1) chromate on the scale. There are 0.079 moles of Br in 6.40 g.

1. To determine the amount of lead (1) chromate needed, you need to know its molar mass. Lead (1) chromate has a molar mass of 303.80 g/mol. To calculate the weight, multiply the moles by the molar mass:

0.0100 mole * 303.80 g/mol = 3.038 g

2. To find the number of moles of a substance, you need to divide the mass by its molar mass. To convert 6.40 g of Br to moles, divide the mass by the molar mass of Br:

6.40 g / 80.9 g/mol = 0.079 moles

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Answer: 391 g

Explanation:

For this problem, we need to know that molarity is. Molarity is moles of solute/liters of solution. it is also denoted as M=n/V, which is also mol/L. We are given that the molarity is 3.0 M and the liter is 1.5 L. All we have to do is plug in 3.0 and 1.5 into our formula and solve for moles.

\(3.0M=\frac{n}{1.5L}\)

\(n=4.5 mols\)

Now that we have moles, we can convert moles to grms by using the molar mass of LiBr.

\(4.5 mols*\frac{86.844 g}{1 mol} =391g\)

Answer:

In the cells.

Explanation:

Moles are the unit of measurement that estimates the amount of the substance in a sample. It directly compares the amounts of substances. Thus, option c is correct.

Moles are said to be the SI unit to estimate the number of substances like atoms, molecules, ions, etc., in a sample. It is used to measure the elementary entities that are small in size.

It is abbreviated as mol and is equivalent to 6.02214076 × 10²³ particles (Avogadro number). It can be calculated by mass and the molar mass of the substance and is shown as,

Moles (n) = mass ÷ molar mass

Where mass is given in grams and molar mass in grams/ mol.

The moles are used to estimate the molarity and are also used in the ideal gas equation. The moles will be more in the substance with less molar mass and vice versa.

Therefore, option c. moles directly compares the amounts of substances.

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Alkanes are the simplest family of hydrocarbons, compounds containing only carbon and hydrogen, and only carbon-hydrogen bonds and carbon-carbon single bonds. Alkanes are less reactive and have little biological activity. All alkanes are colorless and odorless.

What are the applications of 3-hexanol?

n-Hexanol is a colorless liquid with a fruity smell. It is used in the production of flavoring additives, pesticides, leather processing, preservatives, perfumes, plasticizers and other chemicals. n-Hexanol is included on the Hazardous Materials List as cited by the DOT and NFPA.

What are alkanes?

In organic chemistry, alkanes or paraffins are saturated acyclic hydrocarbons. In other words, alkanes are composed of hydrogen and carbon atoms arranged in a tree structure in which all carbon-carbon bonds are single. Alkane has the general chemical formula CₙH₂ₙ₊₂

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Based on the phase of matter and our knowledge of elements, the elements that is clearly not a metal would be helium (He).

Depending on the temperature and pressure, an element can exist in many phases of matter. The solid, liquid, and gas states are the three fundamental types of matter.

Particles are closely packed and vibrate in situ while having a fixed shape and volume in the solid phase of an element. Examples are carbon (C) in the form of diamond and iron (Fe) in the form of a solid metal.

The volume of the elements in the liquid phase is fixed, but they take the shape of their container. Because they are not tightly packed, the particles can move. Mercury (Hg) and bromine (Br) are two examples.

Elements lack both a defined shape and volume in the gas phase. The particles travel freely and are spaced far apart. Examples include the gases hydrogen (H2) and oxygen (O2).

Helium is a noble gas and is in the gaseous phase at room temperature, which is different from most metals that are solid at room temperature. Additionally, helium's chemical properties, such as being non-reactive and a poor conductor of heat and electricity, further differentiate it from metals.

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Alright, let's take it step by step!

(a) When you mix water with different temperatures, the final temperature is like a weighted average. Imagine you have `v` liters of water at temperature `T` and `u` liters of water at temperature `S`. The amount of thermal energy in the first batch is `v*T` and in the second batch it's `u*S`. When you combine them, the total thermal energy is `v*T + u*S`. Since the total volume is now `v + u`, the average energy per liter (which is the final temperature) is `(v*T + u*S) / (v + u)`.

In equation form:

Final Temperature, F = (v*T + u*S) / (v + u).

(b) Now let's move to the changing volumes and temperatures. Let `v(t)` be the volume at time `t`, and `T(t)` the temperature at time `t`. Let's say that in `Gt` seconds, `Gu` gallons of water are added at temperature `S`. We’ll assume that 1 gallon is the same as 1 liter for simplicity, though in reality they are slightly different.

The new volume after `Gt` seconds is `v(t) + Gu`, and the total thermal energy is `v(t)*T(t) + Gu*S`. The new average temperature is:

T(t+Gt) = (v(t)*T(t) + Gu*S) / (v(t) + Gu).

Now, T(t+Gt) - T(t) = [(v(t)*T(t) + Gu*S) / (v(t) + Gu)] - T(t).

Now, let's think about water pouring at a constant rate. Let's use the limit definition of the derivative. Instead of `Gu` gallons in `Gt` seconds, let's say a tiny amount of water `du` is added in a tiny amount of time `dt`. So, `du/dt` is the rate at which water is poured into the urn.

Using the limit definition:

dT/dt = lim (dt -> 0) [(v(t)*T(t) + du*S) / (v(t) + du) - T(t)] / dt

     = [(v(t)*T(t) + du*S) / (v(t) + du) - T(t)]' (derivative with respect to t)

     = [v'(t)*T(t) + v(t)*T'(t) + du/dt*S - v'(t)*T(t) - v(t)*T'(t)] / (v(t) + du) (using product rule)

     = (du/dt*S) / (v(t) + du).

As dt approaches 0, du becomes very small, and thus we can ignore it in comparison to v(t), so:

dT/dt ≈ (du/dt*S) / v(t).

This is the rate of change of temperature with respect to time, in terms of the rate at which water is poured, the temperature at which it is poured, and the volume of water already in the urn.

The maximum liters per minute (lpm) flow for administering oxygen via a nasal cannula typically ranges from 1 to 6 lpm. The specific flow rate is determined by the healthcare provider based on the patient's needs and the oxygen saturation levels.

Lower flow rates, such as 1-2 lpm, are often used for patients requiring low levels of supplemental oxygen. Higher flow rates, ranging from 4-6 lpm, are utilized for patients who need a higher concentration of oxygen.

It's important to note that the maximum lpm flow may vary depending on the specific guidelines and protocols of different healthcare facilities. Therefore, it's always recommended to consult with a healthcare professional to determine the appropriate oxygen flow rate for a specific patient.

The maximum liters per minute (lpm) flow for administering oxygen via a nasal cannula typically ranges from 1 to 6 lpm.

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Explanation:

To find the isotope that is expected to be radioactive we have to compare the given isotopes with the ones that we find the in the periodic table.

(A) Ti:

Isotope ----> atomic mass = 48 atomic number = 22

Periodic table ---> average atomic mass = 47.9 atomic number = 22

(B) Sr:

Isotope ----> atomic mass = 88 atomic number = 38

Periodic table ---> average atomic mass = 87.6 atomic number = 38

(C) Os:

Isotope ----> atomic mass = 192 atomic number = 76

Periodic table ---> average atomic mass = 190.2 atomic number = 76

(D) Pu:

Isotope ----> atomic mass = 244 atomic number = 94

Periodic table ---> average atomic mass = 244 atomic number = 94

If we take a look at them we will see that the only one that is different is osmium. The atomic mass of the isotope is 192 amu, that means that this isotope has 2 more neutrons than the average atom of the element. So we can expect that it could be radioactive.

Answer: C. Os

Answer:

So, sodium oxide + water = sodium hydroxide + hydrogen is written Na2O+H2O-->NaOH+H.

To balance the equation it should read NaO+H2O-->2NaOH

Explanation:

Na2O+H2O-->2NaOH+0H2.......the 0H2 is dropped because there is no value

The correct balance of equation will be

Na2O + H2O - - > 2NaOH

A chemical equation where the number of atoms on both the reactant side and the product side of the reaction are equal is called a balanced chemical equation.

In a balanced chemical equation, not only the number of atoms but the charge and the mass is the same on both sides of the equation.

A chemical equation needs to be balanced to validate the law of conservation of mass. The law of conservation of mass states that the 'mass can neither be created nor destroyed in a chemical reaction'.

If the chemical equation is not balanced, it will go against the fundamental law of law of conservation of mass.

Thus, the chemical equations need to be balanced.

Therefore to balanced the given chemical equation, we equate the number of atoms on both the reactant and the product side of the reaction.

It will be written as

Na2O + H2O - - > 2NaOH

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Answer:

The  pressure is \(P_f = 0.93 \ atm\)

Explanation:

From the question we are told that

   The  volume of  Ne  is  \(V_N = 2.50 \ L\)

    The volume  of  CO is  \(V_C = 2.00 \ L\)

    The  pressure of  \(Ne\) is  \(P_N = 1.09 \ atm\)

      The  pressure of  CO is \(P_C = 0.773 \ atm\)

The  number of  moles of  Ne present is evaluated using the ideal gas equation as

      \(n_N = \frac{P_N * V_N}{R T}\)

=>   \(n_N = \frac{1.09 * 2.50 }{R T} = \frac{2.725}{RT}\)

The  number of  moles of  CO present is evaluated using the ideal gas equation as

      \(n_N = \frac{P_C * V_C}{R T}\)

=>   \(n_N = \frac{0.73 * 2.00 }{R T} = \frac{1.46}{RT}\)

The  total number of moles of gas present is evaluated as

        \(n_T = n_N + n_C\)

        \(n_T = \frac{2.725}{RT} + \frac{1.46}{RT}\)

      \(n_T = \frac{4.185}{RT}\)

The  total volume of gas present when valve is opened is  mathematically represented as

                \(V_T = V_N + V_C\)

    =>        \(V_T = 2.50 + 2.00 = 4.50 \ L\)

So

  From the ideal gas equation the final pressure inside the system  is mathematically represented as

         \(P_f = \frac{n_T * RT }{ V_T}\)

=>      \(P_f = \frac{[\frac{4.185}{RT} ] * RT }{ 4.50}\)

=>       \(P_f = 0.93 \ atm\)

The theoretical yield of the product, Cu(C₇H₄SO₃N)₂(H₂O)₄·2H₂O(s), is 10.189 g.

Molar Mass of Copper(II) acetate monohydrate = 199.65 g/mol

Molar Mass of Sodium saccharinate monohydrate = 223.18 g/mol

Molar Mass of product = 535.59 g/mol

The balanced chemical equation for the reaction is:

Cu(C₂H₃O₂)₂·H₂O(aq) + 2NaC₇H₄SO₃N·H₂O(aq) → Cu(C₇H₄SO₃N)₂(H₂O)₄·2H₂O(s) + 2NaC₂H₃O₂(aq)

Moles of Cu(C2H3O2)2·H2O used = Mass / Molar mass

= 3.80 g / 199.65 g/mol

= 0.01902 mol

Moles of NaC₇H₄SO₃N·H₂O used = Mass / Molar mass

= 8.60 g / 223.18 g/mol

= 0.03853 mol

Since the ratio of Cu(C₂H₃O₂)₂·H₂O to Cu(C₇H₄SO₃N)₂(H₂O)₄·2H₂O is 1:1, therefore, the number of moles of (Cu(C₇H₄SO₃N)₂(H₂O)₄·2H₂O produced would also be 0.01902 mol (i.e., equal to the number of moles of Cu(C₂H₃O₂)₂·H₂O  used).

Mass of product = Number of moles of product × Molar mass

= 0.01902 mol × 535.59 g/mol

= 10.189 g

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Answer:

A the first 1

Explanation:

Explanation:

We have a 63.9 g sample of calcium hydroxide. First we have to convert those grams into moles. To do that we have to use the molar mass of calcium hydroxide.

Calcium hydroxide = Ca(OH)₂

molar mass of Ca = 40.08 g/mol

molar mass of O = 16.00 g/mol

molar mass of H = 1.01 g/mol

molar mass of Ca(OH)₂ = 1 * 40.08 g/mol + 2 * 16.00 g/mol + 2 * 1.01 g/mol

molar mass of Ca(OH)₂ = 74.10 g/mol

mass of Ca(OH)₂ = 63.9 g

moles of Ca(OH)₂ = 63.9 g /(74.10 g/mol)

moles of Ca(OH)₂ = 0.862 moles

In 1 molecule of Ca we have 2 atoms of O. So in 1 mol of Ca(OH)₂ we will have 2 moles of O atoms.

1 mol of Ca(OH)₂ = 2 moles of O atoms

moles of O atoms = 0.862 moles of Ca(OH)₂ * 2 moles of O /1 mol of Ca(OH)₂

moles of O atoms = 1.724 moles

One mol is similar to a dozen. When we say that we need a dozen eggs we know that we need 12 eggs. If we want a mol of eggs, we want 6.022*10^23 eggs. So one mol of something is 6.022 * 10^23 of that.

1 mol of O atoms = 6.022 * 10^23 atoms

n° of O atoms = 1.724 moles * 6.022 * 10^23 atoms/1 mol

n° of O atoms = 1.04 * 10^24 atoms

Answer: In a 63.9 g sample of Ca(OH)₂ we have 1.04 *10^24 atoms of oxygen.

Answer:

4.2 moles Cl2 ( 2 Cl / 1 Cl2 ) = 8.4 mol Cl atoms.

Explanation:

Hope this helps.

The empirical formula of the compound is K2O.

We need to determine the ratio of atoms in the compound. Here, we are given the masses of potassium and oxygen that are produced by decomposing the compound.

From the given information, we know that

Mass of K = 19.55 g

Mass of O = 4.00 g

We can use these masses to determine the number of moles of each element:

Moles of K = 19.55 g / 39.10 g/mol (molar mass of K) = 0.500 mol

Moles of O = 4.00 g / 16.00 g/mol (molar mass of O) = 0.250 mol

Next, we need to find the simplest whole number ratio of K to O. To do this, we divide each number of moles by the smaller number of moles (in this case, 0.250 mol):

Moles of K / Moles of O = 0.500 mol / 0.250 mol = 2.00

This means that the ratio of K to O in the compound is 2:1.

Therefore, the empirical formula of the compound is K2O.

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Answer:

67.5 gm H2O

Explanation:

2 H2   = 4 gm

O2 = 32 gm

2 H20 = 36 gm

so   32 gm O2   results in 36 gm H20

32/36  = 60/x     x = 67.5 gm

Answer:

its a  hammer falling off a table

Explanation:

i think its cause the gravitational energy gets converted to kinetic energy when its falling down

The correct answer is a hammer falling off a table.

When the hammer falls off a table, the potential energy contained in the hammer is transferred to kinetic energy.

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1.27×10^−11 m​ is the de Broglie wavelength of an alpha particle moving at a velocity of 1. 75 × 10⁷ meter per second.

De Broglie wavelengths is the wavelength () that is connected to an item in relation to its speed and mass. Typically, a particle's force is inverse to its de Broglie wavelength. Louis de Broglie demonstrated that a particle's frequency is proportional to Planck's frequency divided by its mass times its velocity.

The de-Broglie equation can be used to determine an electron's wavelength.

λ= h/mv

=  6.626×10^−34 Js / 9.11×10 ^−31 kg× 1. 75 × 10⁷ m/s

=1.27×10^−11 m​

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Answer:

5.09 x 10⁶ s⁻¹ = 5.09 x 10⁶ Hz

Explanation:

The relation between frequency (ν) and wavelength (λ) is given by:

λ = c/ν

where c is the speed of light (2.998 m/s) and it is a constant.

So, we first convert the wavelength from nanometers (nm) to meters (m) (1 nm = 1 x 10⁻⁹):

λ= 589 nm x (10⁻⁹ nm/1 m) = 5.89 x 10⁻⁷ m

Then, we calculate the frequency from the equation:

λ = c/ν ⇒ ν = c/λ = (2.998 m/s)/(5.89 x 10⁻⁷ m) = 5.09 x 10⁶s⁻¹ = 5.09 x 10⁶ Hz

There are total three laws of newtons, first law of newtons, second law of newton and third law of newton. Therefore, for every action there is an equal and opposite reaction.

Newton's first law is also called law of inertia. An object at rest remains at rest, and an object in motion remains in motion at constant speed and in a straight line unless acted on by an unbalanced force.

Third law of newton states  that for every action there is an equal and opposite reaction.

Therefore, for every action there is an equal and opposite reaction.

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Explanation:

You divide mass/volume to get density. 1.2/35 is 0.034

Answer:

Doctorate

Explanation:

Answer for PLATO