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The Nernst equation can be used to calculate the potential of an electrochemical cell when not under standard conditions. It is also very useful to show how ion concentration affects cell potential and the cell potential is 0.09314 V.

At 298 K, the Nernst equation simplifies to - 0.0592 v protocol Q where Q is the reaction quotient and n is the coefficient of electrons transferred if the redox equations are balanced.

In this cell copper is reduced at the cathode and oxidized.

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Answer:

In chemistry and atomic physics, the main group is the group of elements whose lightest members are represented by helium, lithium, beryllium, boron, carbon, nitrogen, oxygen, and fluorine as arranged in the periodic table of the elements. The main group includes the elements in groups 1 and 2, and groups 13 to 18.

At 101 kpa and 293 k, the equilibrium mole fraction of oxygen in the water that is exposed to dry air is  5.22×10⁻⁶ mol O₂/mol solution.  The concentration of oxygen in the water corresponds to the equilibrium solution is 9.28 mg/l.

Henry's law is typically expressed as follows, assuming phase equilibrium at the gas-liquid interface: \(p_A=H_AC_A\) where pA is the partial pressure, CA is the liquid phase concentration, and HA is Henry's law constant.

In terms of mole fraction, this is written as, \(p_A=H_Ax_A\) where xA represents the equilibrium mole fraction of A.

a) The equilibrium mole fraction of oxygen in water is given as,

\(x_{\text{oxygen}}=\frac{p_{\text{oxygen}}}{H_\text{oxygen}}\)

The partial pressure for oxygen in water is calculated as,

\(\begin{aligned}p_{\text{oxygen}}&=y_{\text{oxygen}}P_T\\&=\mathrm{(0.21)(1.010\times10^5\;Pa)}\\&=\mathrm{2.12\times10^4\;Pa}\end{aligned}\)

Then,

\(\begin{aligned}x_{\text{oxygen}}&=\mathrm{\frac{2.12\times10^4\;Pa}{4.06\times10^9\;Pa(mol\;O_2/mol\;solution)}}\\&=5.22\times10^{-6}\;\mathrm{mol\;O_2/mol\;solution}\end{aligned}\)

b) The equilibrium concentration of oxygen in water is calculated as,

\(\begin{aligned}C_{\text{oxygen}}&=x_{\text{oxygen}}C_T\end{aligned}\) where CT represents the total moles of solution present in a given volume. This is calculated as,

\(\begin{aligned}C_T&=\mathrm{1000\;kg/m^3}\\&=\frac{\mathrm{1000\;kg/m^3}}{\mathrm{18\;kg/kmol}}\\&=\mathrm{55.56\;kmol/m^3}\end{aligned}\)

Then,

\(\begin{aligned}C_{\text{oxygen}}&=x_{\text{oxygen}}C_T\\&=\mathrm{(5.22\times10^{-6}\;mol\;O_2/mol\;solution)(55.56\;kmol/m^3)}\\&=\mathrm{0.290\;mol/m^3}\\&=\mathrm{0.290\times32\;gm/m^3}\\&=\mathrm{9.28\;gm/m^3}\\&=\mathrm{9.28\;mg/l}\end{aligned}\)

The required answers are 5.22×10⁻⁶ mol O₂/mol solution and 9.28 mg/l.

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Answer:8.334×10^-6 moles

Explanation:

a mole is 6.023×10^23

5.02×10^18 ÷ 6.023×10^23=8.33×10^-6

By dividing the sample's mass by its molar mass, one can determine the number of moles present in a sample. One mole, denoted by the symbol mol and written as molecular entities, known as Avogadro's number.

In addition, the molar mass of each element is determined by the weight of its atoms, which is calculated to be 6.022*10^23. (1 mole). The definition of a substance's molecular weight is the ratio of the mass of one mole to the given mass of that substance in any form of chemical reaction. It is best understood as the maximum number of moles that can be created from a given amount of the substance. Because a mole contains 6.023 10 23 atoms, or 6.023 mol, it is a very large unit. One mole is equivalent to the Avogadro number.

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Answer:

1. 34.25

2.716

3.0.02181

4.1,323.194921978313 round use calculator

5.9.89

6.90 or 91

7.0.0269

Explanation:

Round if you can

Radioactive dating measures the rate of decay of radioactive materials in rocks.

Radiometric dating, radioactive dating, or radioisotope dating is a technique used to date things such as rocks or carbon that included trace radioactive contaminants when they were produced. Radioactive dating is a technique for dating rocks and minerals that makes use of radioactive isotopes. This approach is appropriate for igneous and metamorphic rocks that cannot be dated using the sedimentary stratigraphic correlation method. There are around 300 naturally occuring isotopes known. The underlying idea behind radiometric dating is that you can compute the age of a sample by comparing the presence of a radioactive isotope within it to its known abundance on Earth and its known half-life (rate of decay).

Here,

Radioactive dating determines the rate at which radioactive elements in rocks decay.

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Answer:

For all atoms with no charge, the number of electrons is equal to the number of protons. The mass number, 40, is the sum of the protons and the neutrons. To find the number of neutrons, subtract the number of protons from the mass number.

Explanation:

Answer:

Letter C. Subtract the atomic number from the atomic mass

Answer:

v = 78.5 km/h

Explanation:

It is given that, the distance between one city to another is 314 km. The overall trip takes 4 hours. We need ton find average velocity. It is equal to the total displacement divided by total time taken. So,

\(v=\dfrac{d}{t}\\\\v=\dfrac{314\ km}{4\ h}\\\\v=78.5\ km/h\)

So, average velocity is 78.5 km/h.

Answer:

cystic fibrosis

Explanation:

The cells that make mucus, perspiration, and digestive fluids are impacted by cystic fibrosis. These fluids start to thicken and cling together as a result. They then block off all of the tubes, ducts, and passages.

Answer:

Both objects are in physical contact with each other

Explanation:

Conduction refers to the flow of heat from one object to another when the both objects are in contact with each other.

Hence, before heat can flow from one object to another, the two objects must be in contact with each other. This is a key requirement before conduction can take place.

Answer:

This reaction is characteristic to metal carbonates, which decompose when heated to form the oxide of the metal and carbon dioxide gas.

Explanation:

Just did it...

Answer:

If the temperature is sufficiently above the decomposition temperature, the mass of the mass will reach a steady level.  When this occurs, the decomposition is complete.  

Explanation:

If you have money and a mass spectrometer, you might consider monitoring the gas space above the zinc carbonate sample for CO2.  Once the sample stops emitting CO2, above the decomposition temperature, you may conclude the reaction has gone to completion.

The enthalpy change, ΔH, for the reaction, given that 5 grams of octane, C₈H₁₈ is burned in the calorimeter containing 1200 g of water is 450 Kcal/mol

First, we shall determine the mole of 5 grams of octane, C₈H₁₈. Details below:

Mole = mass / molar mass

Mole of C₈H₁₈ = 5 / 114

Mole of C₈H₁₈ = 0.044 mole

Next, we shall obtain the heat absorbed by the water. Details below:

Q = MCΔT

Q = 1200 × 1 × 16.5

Q = 19800 cal

Finally, we shall determine the enthalpy change, ΔH, for the reaction. Details below:

ΔH = Q / n

ΔH = 19.8 /  0.044

ΔH = 450 Kcal/mol

Thus, the enthalpy change, ΔH for the reaction is 450 Kcal/mol

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Answer:

UF6

Explanation:

Answer:

Some of the chemicals used to preserve food and give it color are sodium nitrate, sodium benzoate, and propionate

Explanation:

slate is the correct answer i PROMISE

(. ^ ᴗ ^.)

Answer:

Fluorine has seven valence electrons and usually forms the F – ion because it gains one electron to satisfy the octet rule.

Explanation:

Answer:

Because it gains one electron to meet the octet rule, fluorine possesses seven valence electrons and normally forms the F – ion.

Explanation:

The formula for the edge length of the face-centered cubic unit cell based on the radius (r) of the atom is: a = (6r) / \(\sqrt{2}\). In a face-centered cubic (FCC) unit cell, atoms are located at the corners and the centers of each face of the cubic unit cell. To find the formula for the edge length of an FCC unit cell based on the radius (r) of the atom:

1.   Consider a diagonal across the face of the cubic unit cell, which includes the following atoms: one corner atom, one face-centered atom, and another corner atom.
2.   In an FCC unit cell, the face-centered atom touches the two corner atoms, so the diagonal across the face can be expressed as the sum of the diameters of these three atoms (2r each).
3.   The diagonal across the face can also be expressed using the Pythagorean theorem: the square of the diagonal equals the sum of the squares of the edge length (a) and the height of the triangular face formed by the edge length and the diagonal (also a, as the face is a square). So, the diagonal equals \(\sqrt{(a^2 + a^2)}\) or a\(\sqrt{2}\).
4.   Set the sum of the three atom diameters equal to the diagonal across the face: 2r + 2r + 2r = a\(\sqrt{2}\).
5.   Simplify the equation: 6r = a\(\sqrt{2}\).
6.   Solve for the edge length (a): a = (6r) / \(\sqrt{2}\).

So, the formula for the edge length of the face-centered cubic unit cell based on the radius (r) of the atom is: a = (6r) / \(\sqrt{2}\).

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Answer:

B

CuO

H2

Explanation:

hydrogen will oxidized to form water

Copper(II) oxide reacts with hydrogen.

\(CuO + H_2\) → \(Cu + H_2O\)

Oxidising agent - \(Cuo\)

Reducing agent - \(H_2\)

A chemical reaction that takes place between an oxidizing substance and a reducing substance.

The oxidizing substance loses electrons in the reaction, and the reducing substance gains electrons.

In the reaction  \(CuO + H_2\) → \(Cu + H_2O\)  

\(Cuo\) is the oxidising agent and  \(H_2\) is the reducing agent because \(Cuo\)  is oxidising  \(H_2\) and \(H_2\) is the reducing agent because it is removing oxygen from \(Cuo\).

Hence, option B is correct.

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The answer is Electronegativity.

The reduction of an alkyne to a trans alkene involves several steps. The correct order of these steps, starting from the top, is as follows:

Addition of hydrogen gas (H2) in the presence of a metal catalyst.

Formation of a cis-alkene intermediate.

Isomerization of the cis-alkene to a trans-alkene.

Removal of the metal catalyst and purification of the trans-alkene product.

The reduction of an alkyne to a trans alkene proceeds through a series of chemical reactions. The first step involves the addition of hydrogen gas (H2) in the presence of a metal catalyst, such as palladium (Pd) or platinum (Pt). The metal catalyst facilitates the breaking of the triple bond in the alkyne, resulting in the formation of a cis-alkene intermediate.

In the next step, the cis-alkene undergoes isomerization, converting it into a trans-alkene. This isomerization occurs through a rearrangement of the carbon-carbon double bond. The exact mechanism of this isomerization may vary depending on the reaction conditions and the specific alkynes involved.

After the desired trans-alkene is formed, the next step involves the removal of the metal catalyst. This can be achieved through various methods, such as filtration or extraction. The purified trans-alkene product is then obtained and can be further used in various chemical reactions or applications.

In summary, the reduction of an alkyne to a trans alkene involves four key steps: addition of hydrogen gas in the presence of a metal catalyst, formation of a cis-alkene intermediate, isomerization of the cis-alkene to a trans-alkene, and removal of the metal catalyst followed by purification of the trans-alkene product.

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The answer is "1.2". The balanced equation for the reaction is as follows: P4O10(s) + 6H2O(l) → 4H3PO4(aq)

To determine the number of moles of phosphoric acid that will be formed upon the complete reaction of 32.3 grams of diphosphorus pentoxide with excess water, we need to use stoichiometry.

Stoichiometry is a branch of chemistry that deals with the calculation of relative quantities of reactants and products in chemical reactions.

The mass of one mole of substance is known as its molar mass.

The number of particles in one mole of substance is known as Avogadro's number and is equal to 6.022 x 1023.

In the given reaction:

Mass of diphosphorus pentoxide, P4O10 = 32.3 g

Number of moles of P4O10 = mass/molar mass= 32.3 g/(30.97 g/mol + 4 × 15.99 g/mol)= 0.3 mol

According to the balanced chemical equation:1 mol of P4O10 will give 4 mol of H3PO4

Therefore, 0.3 mol of P4O10 will give = 0.3 mol × 4 mol H3PO4/1 mol P4O10= 1.2 mol H3PO4

So, 1.2 moles of phosphoric acid will be formed upon the complete reaction of 32.3 grams of diphosphorus pentoxide with excess water.

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Answer:

A. AgNO₃ + NaCl —> AgCl + NaNO₃

B. Mg(NO₃)₂ + 2KOH —> 2KNO₃ + Mg(OH)₂

C. 3LiOH + Fe(NO₃)₃ —> Fe(OH)₃ + 3LiNO₃

Explanation:

The equation given in the question above can be balanced as follow.

A. AgNO₃ + NaCl —> AgCl + NaNO₃

The above equation is already balanced.

B. Mg(NO₃)₂ + KOH —> KNO₃ + Mg(OH)₂

There are 2 atoms of H on the right side and 1 atom on the left side. It can be balance by writing 2 before KOH as shown below:

Mg(NO₃)₂ + 2KOH —> KNO₃ + Mg(OH)₂

There are 2 atoms of K on the left side and 1 atom on the right side. It can be balance by writing 2 before KNO₃ as shown below:

Mg(NO₃)₂ + 2KOH —> 2KNO₃ + Mg(OH)₂

Thus, the equation is balanced.

C. LiOH + Fe(NO₃)₃ —> Fe(OH)₃ + LiNO₃

There are 3 atoms of H on the right side and 1 atom on the left side. It can be balance by writing 3 before LiOH as shown below:

3LiOH + Fe(NO₃)₃ —> Fe(OH)₃ + LiNO₃

There are 3 atoms of Li on the left side and 1 atom on the right side. It can be balance by writing 3 before LiNO₃ as shown below:

3LiOH + Fe(NO₃)₃ —> Fe(OH)₃ + 3LiNO₃

Thus, the equation is balanced.

The type of reaction that occurs when you squeeze a cold pack is an exothermic reaction. An exothermic reaction is a chemical reaction that releases energy in the form of heat or light. In this case, the reaction between the chemicals inside the cold pack releases heat, which is transferred to your skin when you apply the pack.

The heat transfer between the cold pack and your skin occurs through conduction. Conduction is the transfer of heat between objects that are in direct contact with each other. When you apply the cold pack to your skin, the heat from your skin is transferred to the cold pack through conduction. As the heat is transferred, the cold pack gets warmer and your skin gets cooler.

The law of conservation of energy applies to this system because energy cannot be created or destroyed, only transferred from one form to another. In this case, the chemical reaction inside the cold pack releases energy in the form of heat, which is transferred to your skin through conduction. As the heat is transferred, the temperature of the cold pack decreases, while the temperature of your skin decreases. However, the total amount of energy in the system remains constant.

In summary, when you apply a cold pack to a twisted ankle, the chemical reaction that occurs is an exothermic reaction. The heat transfer between the cold pack and your skin occurs through conduction, and the law of conservation of energy applies to the system as the total amount of energy remains constant.

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For the first question, to bring about the conversion of OH, OH to NO₂, NO₂, the reagents/catalysts would be:

Step 1: HNO₃, H₂SO₄
Step 2: NaNO₂, HCl
The overall reaction would be:
OH, OH + HNO₃, H₂SO₄ -> NO₂, NO₂
For the second question, to bring about the conversion of OH, OH, OH to NO₂, NO₂, the reagents/catalysts would be:
Step 1: NaNO₂, HCl
Step 2: H₃PO₂
The overall reaction would be:
OH, OH, OH + NaNO₂, HCl -> NO₂, NO₂, OH
NO₂, NO₂, OH + H₃PO₂ -> NO₂, NO₂
For the third question, the reagent/catalyst to bring about the conversion of СН₃СН₂Сl to СН₃СН₂ l would be:
NaI in acetone
The overall reaction would be:
СН₃СН₂Сl + NaI ->СН₃СН₂ l + NaCl
For the fourth question, the structural formula of the ortho-substituted product when CH is treated with H2804 and HNO₃ would be:
NO₂
|
CH
|
NO₂
For the fifth question, the structural formula for the single-substitution product when CH is treated with H₂SO₄ would be:
SO₃H
|
CH
|
H
For the sixth question, the structural formula of the para-substituted product when CH is treated with Cl₂ and FeCl₃ would be:
Cl
|
CH
|
NO₂

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Answer:

Summer

Explanation:

Assuming you are in the northern hemisphere, it would be summer.

Asia is in the southern hemisphere and because of the Earth's axis of 23 degrees, it causes seasons to be inversed in the other hemisphere.

Hope that helps

Answer:

19.79%

Explanation:

mass % = (mass solute / total mass) * 100

total mass = 129.54 + 525 = 654.54

solute = C6H12O6

(129.54/654.54) = .1979

.1979 * 100 = 19.79%