pls help fast i'll give brainliest

Answer:

that would be ten dollars $10

Answer: $28

Step-by-step explanation:

regular price = 35

20% = 20/100 = 0.20

35(0.20) = 7

35 - 7 = 28

28

\(\quad \huge \quad \quad \boxed{ \tt \:Answer }\)

\(\qquad \tt \rightarrow \:x = 16 \)

____________________________________

\( \large \tt Solution \: : \)

If two polygons are similar, their corresponding sides ratios will be equal to each other.

\(\qquad \tt \rightarrow \: \cfrac{8}{16} = \cfrac{2x - 20}{24} \)

\(\qquad \tt \rightarrow \: \cfrac{1}{2} = \cfrac{2x - 20}{24} \)

\(\qquad \tt \rightarrow \: 2x - 20 = \cfrac{24}{2} \)

\(\qquad \tt \rightarrow \: 2x = 12 + 20\)

\(\qquad \tt \rightarrow \: 2x = 32\)

\(\qquad \tt \rightarrow \: x = 16\)

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Answer:

4.5

Step-by-step explanation:

15% of 30 is 4.5

30/100=0.3

0.3*15=4.5

Answer: 30 inches

Step-by-step explanation:

The sides of the square are equal and so if the area is 25 inch², each side can be acquired by square rooting that figure:

= √25

= 5 inch per side for the square

Each side of the triangle is twice as long as a side of the square:

= 5 * 2

= 10 inches

There are three sides to a triangle so the perimeter is:

= 10 * 3

= 30 inches

Verifying Identity with a calculator requires an individual to enter specific numerical values into a calculator and then solve a given equation. This can be used to prove the validity of an equation, or the accuracy of a given answer.

The equation is typically written in algebraic form and includes numerical values.Verifying Identity with a calculator requires an individual to enter specific numerical values into a calculator and then solve a given equation. This can be used to prove the validity of an equation, or the accuracy of a given answer. For example, if an individual is asked to verify the identity \(sin^2x + cos^2x\)= 1, they will be given numerical values to plug into the equation. For example, if they are given x = 60, they would enter\((sin60)^2 + (cos60)^2\) into the calculator and solve. This should result in an answer of 1, proving the equation is accurate.

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Using the normal distribution:

(a) 309 minutes after the doors open

(b) 172 minutes after the doors open.

In a normal distribution with mean μ and standard deviation σ, the z-score of a measure X is given by:

Z = ( X - μ ) / σ

It counts the number of standard deviations the value deviates from the mean.

We look at the z-score table after determining the z-score to determine the p-value, which is the percentile of X.

Now, we have

Mean of 3 hours and 48 minutes, therefore:

μ = 3(60) + 48 = 228 minutes

The standard deviation, σ = 52 minutes

(a) The doors open with 94% of the people who come to the Saturday show.

We look 94%, or 0.94, up in the cells of a z table.  The closest we can get to this value is 0.9406, which corresponds to a z score of 1.56:

Z = ( X - μ ) / σ

1.56 = ( X - 228 ) / 52

1.56 × 52 = X - 228

81.12 = X - 228

X = 309.12

X = 309 minutes

(b) We look 14%, or 0.14, up in the cells of a z table.  The closest we can get to this value is 0.1401, which corresponds to a z score of - 1.08:

- 1.08 = ( X - 228 )/ 52

- 1.08 × 52 = X - 228

- 56.16 = X - 228

X = 228 - 56.16

X = 171.84

X = 172 minutes

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Considering that y is between x and z, we have that:

We consider that y is between x and z, hence the length of the segment is given by:

xz = xy + yz

The separate lengths are given as follows:

Hence:

4k + 38 = 3k - 2 + 7k + 4.

4k + 38 = 10k + 2

6k = 36

k = 6.

Hence the length of yz is given by:

yz = 7k + 4 = 7(6) + 4 = 42 + 4 = 46 units.

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The probability that at least 4 buyers would prefer green is 0.9963.

The researcher wishes to conduct a study of the color preferences of new car buyers.

Suppose that 30% of this population prefers the color green.

If 16 buyers are randomly selected, the probability that at least 4 buyers would prefer green is 0.9963.

Let X be the number of new car buyers who prefer the color green.

X follows a binomial distribution with n = 16 and p = 0.30.

The probability of at least 4 buyers preferring green is:

P(X ≥ 4) = P(X = 4) + P(X = 5) + P(X = 6) + ... + P(X = 16)

Using the binomial probability formula, P(X = k) = (n C k) pk qn-k

where q = 1 - p = 1 - 0.30 = 0.70

Then: P(X ≥ 4) = P(X = 4) + P(X = 5) + P(X = 6) + ... + P(X = 16)

P(X ≥ 4) = [16 C 4](0.30)4(0.70)12 + [16 C 5](0.30)5(0.70)11 + [16 C 6](0.30)6(0.70)10 + ... + [16 C 16](0.30)16(0.70)0= 0.9963

Therefore, the probability that at least 4 buyers would prefer green is 0.9963.

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Answer:B

Step-by-step explanation:

The exponential curve passes through the point (0, 70). Then the correct option is B.

Let a be the initial value and x be the power of the exponent function and b be the increasing factor.

The exponent is given as

y = a(b)ˣ

The table addresses a few focuses on the diagram of the outstanding capability that models the radioactive rot of an example of xenon-135.

At x = 4.6, the value of 'y' will be 49.5.

\(\rm 49.5 = ab^{4.6} \ \ \ \ \ \ \ ...1\\\)

At x = 9.2, the value of 'y' will be 35.

\(\rm 35= ab^{9.2} \ \ \ \ \ \ \ ...2\)

From equations 1 and 2, then we have

\(\rm \dfrac{b^{9.2}}{b^{4.6}} = \dfrac{35}{49.5}\\\\b^{4.6} = 0.707\\\\b = 0.927\\\)

Then the value of 'a' will be

\(\rm 49.5 = a (0.927)^{4.6}\\\\a = 70\)

Then the equation is given as,

y = 70 · (0.927)ˣ

The graph is given below.

The exponential curve passes through the point (0, 70). Then the correct option is B.

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The missing options are given below.

A) There is an asymptote at y = 70.

B) The y-intercept is located at (0, 70).

C) There is an asymptote at x = 0.

D) The x-intercept is located at (70, 0).

Answer:

40,000

Step-by-step explanation:

100,000 + 40,000 + 5,000 + 20 + 7 = 145,027

Present value of Loan payment 1 = \($1000 / (1 + (0.12/365))^{60\)

Present value of Loan payment 2 = \($1200 / (1 + (0.12/365))^{(-30)\)

The single payment required 90 days from now to pay off the two obligations would be the total present value calculated in Step 3.

To calculate the single payment required to pay off the two obligations with a 12% interest rate, we can use the concept of present value. Present value is the current worth of a future payment, taking into account the interest rate and time.

Let's break down the given information:

Loan payment 1: $1000 due 60 days ago

Loan payment 2: $1200 due in 30 days

To find the single payment required 90 days from now, we need to calculate the present value of each payment and then add them together.

Step 1: Calculate the present value of Loan payment 1.

The time period for Loan payment 1 is 60 days ago.

To bring it to the present, we need to calculate the interest accrued for 60 days at a 12% annual interest rate.

Step 2: Calculate the present value of Loan payment 2.

The time period for Loan payment 2 is 30 days in the future.

To bring it to the present, we need to calculate the interest accrued for 30 days at a 12% annual interest rate.

Step 3: Add the present values of Loan payment 1 and Loan payment 2.

Total present value = Present value of Loan payment 1 + Present value of Loan payment 2

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Answer:

180000

Step-by-step explanation:

Each kilometer = 100,000 cm

That means 1.8 * 100,000 = 180,000 cm.

Based on your question. That should be the answer

The minimal point does not have x = 0.

(a) Kuhn-Tucker conditions for the minimal value of fThe Kuhn-Tucker conditions are a set of necessary conditions for a point x* to be a minimum of a constrained optimization problem subject to inequality constraints. These conditions provide a way to find the optimal values of x1, x2, ..., xn that maximize or minimize a function f subject to a set of constraints. Let's first write down the Lagrangian: L(x, y, λ1, λ2, λ3) = f(x, y) - λ1(x+y-1) - λ2(xy-3) - λ3x - λ4y Where λ1, λ2, λ3, and λ4 are the Kuhn-Tucker multipliers associated with the constraints. Taking partial derivatives of L with respect to x, y, λ1, λ2, λ3, and λ4 and setting them equal to 0, we get the following set of equations: 4x - 2y - λ1 - λ2y - λ3 = 0 2y - 2x - λ1 - λ2x - λ4 = 0 x + y - 1 ≤ 0 xy - 3 ≤ 0 λ1 ≥ 0 λ2 ≥ 0 λ3 ≥ 0 λ4 ≥ 0 λ1(x + y - 1) = 0 λ2(xy - 3) = 0 From the complementary slackness condition, λ1(x + y - 1) = 0 and λ2(xy - 3) = 0. This implies that either λ1 = 0 or x + y - 1 = 0, and either λ2 = 0 or xy - 3 = 0. If λ1 > 0 and λ2 > 0, then x + y - 1 = 0 and xy - 3 = 0. If λ1 > 0 and λ2 = 0, then x + y - 1 = 0. If λ1 = 0 and λ2 > 0, then xy - 3 = 0. We now consider each case separately. Case 1: λ1 > 0 and λ2 > 0From λ1(x + y - 1) = 0 and λ2(xy - 3) = 0, we have the following possibilities: x + y - 1 = 0, xy - 3 ≤ 0 (i.e., xy = 3), λ1 > 0, λ2 > 0 x + y - 1 ≤ 0, xy - 3 = 0 (i.e., x = 3/y), λ1 > 0, λ2 > 0 x + y - 1 = 0, xy - 3 = 0 (i.e., x = y = √3), λ1 > 0, λ2 > 0 We can exclude the second case because it violates the constraint x, y ≥ 0. The first and third cases satisfy all the Kuhn-Tucker conditions, and we can check that they correspond to local minima of f subject to the constraints. For the first case, we have x = y = √3/2 and f(x, y) = -1/2. For the third case, we have x = y = √3 and f(x, y) = -2. Case 2: λ1 > 0 and λ2 = 0From λ1(x + y - 1) = 0, we have x + y - 1 = 0 (because λ1 > 0). From the first Kuhn-Tucker condition, we have 4x - 2y - λ1 = λ1y. Since λ1 > 0, we can solve for y to get y = (4x - λ1)/(2 + λ1). Substituting this into the constraint x + y - 1 = 0, we get x + (4x - λ1)/(2 + λ1) - 1 = 0. Solving for x, we get x = (1 + λ1 + √(λ1^2 + 10λ1 + 1))/4. We can check that this satisfies all the Kuhn-Tucker conditions for λ1 > 0, and we can also check that it corresponds to a local minimum of f subject to the constraints. For this value of x, we have y = (4x - λ1)/(2 + λ1), and we can compute f(x, y) = -3/4 + (5λ1^2 + 4λ1 + 1)/(2(2 + λ1)^2). Case 3: λ1 = 0 and λ2 > 0From λ2(xy - 3) = 0, we have xy - 3 = 0 (because λ2 > 0). Substituting this into the constraint x + y - 1 ≥ 0, we get x + (3/x) - 1 ≥ 0. This implies that x^2 + (3 - x) - x ≥ 0, or equivalently, x^2 - x + 3 ≥ 0. The discriminant of this quadratic is negative, so it has no real roots. Therefore, there are no feasible solutions in this case. Case 4: λ1 = 0 and λ2 = 0From λ1(x + y - 1) = 0 and λ2(xy - 3) = 0, we have x + y - 1 ≤ 0 and xy - 3 ≤ 0. This implies that x, y > 0, and we can use the first and second Kuhn-Tucker conditions to get 4x - 2y = 0 2y - 2x = 0 x + y - 1 = 0 xy - 3 = 0 Solving these equations, we get x = y = √3 and f(x, y) = -2. (b) Show that the minimal point does not have x=0.To show that the minimal point does not have x=0, we need to find the optimal value of x that minimizes f subject to the constraints and show that x > 0. From the Kuhn-Tucker conditions, we know that the optimal value of x satisfies one of the following conditions: x = y = √3/2 (λ1 > 0, λ2 > 0) x = √3 (λ1 > 0, λ2 > 0) x = (1 + λ1 + √(λ1^2 + 10λ1 + 1))/4 (λ1 > 0, λ2 = 0) If x = y = √3/2, then x > 0. If x = √3, then x > 0. If x = (1 + λ1 + √(λ1^2 + 10λ1 + 1))/4, then x > 0 because λ1 ≥ 0.

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Answer: -17, 17, -3, 3, -7, 7,

Step-by-step explanation:

Find all Factors of -18, (got -18 from multiplying 6 and -3)

Add the factors together. (+/- 6 and +/- 3), (+/-9 and +/-2), (+/-18 and +./-1)

Answer:

\(2x + 9 = y \\ - 4x - 3 = y \\ so \: both \: equation \: is \: equal \\ 2x + 9 = - 4x - 3 \\ 2x + 4x = - 3 - 9 \\ 6x = - 12 \\ x = \frac{ - 12}{6} \\ x = - 2\)

The Domain is 0 ≤ x ≤ 4 and Range is 0 ≤ y ≤ 80.

The range of values that we are permitted to enter into our function is known as the domain of a function.  A function's range is the collection of values it can take as input. After we enter an x value, the function outputs this sequence of values.

Given:

We know that the domain of a function is the set of values that we are allowed to plug into our function.

From the Graph the x values ranges from 0 to 4.

So, domain is 0 ≤ x ≤ 4.

and, the range is the corresponding output for the input

From the Graph the y values ranges from 0 to 80.

So, Range is 0 ≤ y ≤ 80.

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The expression represents the time she spent driving is       \(\frac{228.95}{x}\)

The expression represent the time she spent driving can be calculated as follows:

We know that

Time = \(\frac{distance}{ speed}\)

Let x be her speed on the first half of the trip.

Then for first half , the tiime she takes is

T1= \(\frac{150}{x}\)

while in a second half the time taken by her is

T2= \(\frac{150}{1.9x}\)

T2= \(\frac{78.95}{x}\)

the total time she spent on driving is

T1 + T2 =    \(\frac{150}{x}\) + \(\frac{78.95}{x}\) =    \(\frac{228.95}{x}\)

Hence, the expression represents the time she spent driving is       \(\frac{228.95}{x}\)

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Answer:

might be 44inches but not sure

Answer:

10% means the boy is 50 inches taller

Answer:

yes 1/6 is a rational number.

..........................

Answer:

this is a correct answer 5√6/2

Answer:

x = 8 cm

Step-by-step explanation:

Given that,

In a square PQRS, PQ = 2x +3 cm and QR = 3x – 5 cm.

We need to find the value of x.

In a square, all the sides are equal. So,

PQ = QR

2x +3 = 3x – 5

3+5 = 3x - 2x

x = 8

So, the value of x is equal to 8 cm.

Lowes Depot uses a (Q, R) policy to manage its stock levels for a popular mini drill with a replacement lead time of 14 weeks. Historical demand during the replacement lead time is normally distributed with a mean of 90.4616 and a standard deviation of 14.3795. Each drill costs $6, and backorders result in a loss of goodwill of $10. The supplier charges $15 per order, and holding costs are based on a 30% annual interest rate.

To determine the optimal order quantity Q and reorder point R, we need to use the (Q, R) policy. The policy specifies that when the inventory level reaches the reorder point R, an order of size Q is placed. We need to determine Q and R such that the total annual cost is minimized.

The total annual cost consists of three components: ordering costs, holding costs, and shortage costs. Ordering costs are the costs associated with placing an order, which is given by (number of orders per year) x (ordering cost per order). The number of orders per year is the annual demand divided by the order quantity, which is Q. The ordering cost per order is $15. Therefore, the ordering cost is 15 X (Demand rate/Q).

Holding costs are the costs associated with holding inventory, which is given by (inventory level) x (holding cost per unit per year). The holding cost per unit per year is 30% of the unit cost, which is 0.3 x $6 = $1.8.

Shortage costs are the costs associated with backordering, which is given by (expected shortage per year) x (shortage cost per unit). The expected shortage per year is the probability of a stockout during the lead time multiplied by the expected demand

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We have to calculate the estimated standard error and means of the two samples before calculating  the test statistic for a two sample test of means with population variances equal but unknown.

In the given question, we have to explain steps that are necessary before you can calculate the test statistic for a two sample test of means with population variances equal but unknown.

The test statistic for a two-sample independent t-test is derived by dividing the difference between the means of the two samples by the estimated standard error, either pooled or unpooled. The total amount of variation in both groups is gauged by the anticipated standard error.

So we have to calculate the estimated standard error and means of the two samples before calculating  the test statistic for a two sample test of means with population variances equal but unknown.

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Answer:See below and attached

Step-by-step explanation:

Given numbers

4.2×10^-6, 2.1×10^-3, 3.1×10^-2, 3.2×10^-5, 3.5×10^-4, 5.8×10^-3, 5.2×10^-4

Greater than 3.1×10^-3

3.1×10^-2, 5.8×10^-3

Between 3.1 × 10^-3  and 4.3 × 10^-5

2.1×10 ^-3, 3.5×10^-4, 5.2×10^-4

Less than 4.3 × 10^-5

4.2×10^-6, 3.2×10^-5

Step-by-step explanation

:

Based on the given information, the estimated current stock price for Full Boat Manufacturing is $13.11. This is calculated using the discounted cash flow model, taking into account the projected future cash flows, growth rates, and required rate of return.

To calculate the current stock price, we need to estimate the free cash flows and discount them at the required rate of return.

First, we calculate the free cash flow to the firm (FCFF) for next year as follows

FCFF = Sales - Costs - Net Investment*(1-t)

= $115 million - $67 million - $12 million*(1-0.21)

= $31.02 million

Next, we calculate the expected growth rate in FCFF using the formula:

g = (FCFF Year 2 / FCFF Year 1) - 1

where FCFF Year 2 = FCFF Year 1 * (1 + g)

Using the given information, we get

g = (FCFF Year 2 / FCFF Year 1) - 1

= (FCFF Year 1 * (1 + 0.14) * (1 - 0.02) / FCFF Year 1) - 1

= 0.12

We can now use the Gordon growth model to estimate the current stock price

Current stock price = FCFF Year 1 * (1 + g) / (r - g)

where r is the required rate of return.

Substituting the values, we get

Current stock price = $31.02 million * (1 + 0.12) / (0.13 - 0.12)

= $72.13 million

Finally, we divide the current stock price by the number of shares outstanding to get the estimate of the current stock price per share:

Current stock price per share = $72.13 million / 5.5 million

= $13.11 per share

Therefore, the estimate of the current stock price is $13.11 per share.

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--The given question is incomplete, the complete question is given

"  Full Boat Manufacturing has projected sales of $115 million next year. Costs are expected to be $67 million and net investment is expected to be $12 million. Each of these values is expected to grow at 14 percent the following year, with the growth rate declining by 2 percent per year until the growth rate reaches 6 percent, where it is expected to remain indefinitely. There are 5.5million shares of stock outstanding and investors require a return of 13 percent on the company’s stock. The corporate tax rate is 21 percent.

What is your estimate of the current stock price?

So now you just need to use LaGrange multipliers to minimize the function of a unit sphere (a compact set) and work out for which values of p the minimum is non-negative.

2a²b+9b²c+12c²a≥pabc

for a,b,c≥0.Letting a=3k,b=2m,c=n yields

36(k²m+m²n+n²k)≥(6p)kmn

k²m+m²n+n²k≥(p6/5)kmn

We now use AM-GM on k2m,m2n,n2k to get that

k²m+m²n+n²k/3 ≥ (k³m³n³)∧13

k2m+m2n+n2k≥3kmn

So we know that this applies to all p18. Furthermore, taking k=m=n turns the inequality into equality, therefore any p>18 fails. As a result, p=18 is the maximum.

Call that function f, and keep in mind that f(x,y,z)=(x,y,z) for all >0 and x,y,zR. So all you have to do is ensure that f is non-negative on the unit sphere.

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