pls help i dont understand im sped

Answer:

The correct value of z crit for this test is +1.645

Step-by-step explanation:

Answer:

iek

Step-by-step explanation:3283349

Answer: D \(10\sqrt{2}\)

Step-by-step explanation:

It says that the measure of angle B is 45 degrees. So if we were to put in 45 degrees  we could see that is is opposite AC and BC which we needs to find is the hypotenuse. So since we know the opposite of angle B  is 10 ft we can using that to find the length of BC.  Opposite hypotenuse is the sine function so we will use it to calculate the length of BC.

sin(45) = \(\frac{10}{BC}\)       multiply both sides by BC  

BC sin(45) = 10      divide both sides by sin(45)

BC = \(\frac{10}{sin(45)}\)

BC = \(10\sqrt{2}\)

Answer:

\(\huge\boxed{Option\ D : \ BC = 10\sqrt{2}\ ft }\)

Step-by-step explanation:

Since it's a right angled triangle, We'll use trigonometric rations.

Given that m∠B = 45°

So,

Sin B = opposite / hypotenuse

Where m∠B = 45°, opposite = 10 ft and hypotenuse = BC

Sin 45 = 10 / BC

\(\sf \frac{\sqrt{2} }{2} = \frac{10}{BC}\)

BC = 20 / √2

Multiplying and Dividing by √2

BC = 20√2 / √(2)²

BC = 20 √2 / 2

BC = 10√2 ft

Answer:

Where is the data ?

Step-by-step explanation:

Need the data set

The value of the 10% trimmed mean is approximately 1.3027. To calculate the 10% trimmed mean, we need to trim off the lowest and highest 10% of the data and then find the mean of the remaining values.

First, let's sort the data in ascending order:

0.2, 0.21, 0.26, 0.3, 0.33, 0.41, 0.54, 0.57, 1.41, 1.7, 1.84, 2.2, 2.26, 3.06, 3.24

Next, we calculate the number of values to trim from each end:

10% of 15 (total number of values) = 0.1 * 15 = 1.5

Since we can't remove half a value, we round up to the nearest whole number, which is 2.

Now, we remove the two lowest and two highest values:

0.26, 0.3, 0.33, 0.41, 0.54, 0.57, 1.41, 1.7, 1.84, 2.2, 2.26

Finally, we calculate the mean of the remaining values:

(0.26 + 0.3 + 0.33 + 0.41 + 0.54 + 0.57 + 1.41 + 1.7 + 1.84 + 2.2 + 2.26) / 11 = 14.33 / 11 ≈ 1.3027

Rounding to four decimal places, the value of the 10% trimmed mean is approximately 1.3027.

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To answer this question, we need to use the age frequency table given.

Part 1 of 4 (a) Over 20 and under 41:
To find the probability of selecting a CEO whose age is over 20 and under 41, we need to add the frequency of ages 21-30 and 31-40.
P(over 20 and under 41) = frequency of ages 21-30 + frequency of ages 31-40
= 1 + 8
= 9
Therefore, the probability of selecting a CEO whose age is over 20 and under 41 is 9/100 or 0.09.

Part 2 of 4 (b) Between 31 and 40:
To find the probability of selecting a CEO whose age is between 31 and 40, we just need to use the frequency of ages 31-40.
P(between 31 and 40) = frequency of ages 31-40
= 8
Therefore, the probability of selecting a CEO whose age is between 31 and 40 is 8/100 or 0.08.

Part 3 of 4 (c) Under 41 or over 50:
To find the probability of selecting a CEO whose age is under 41 or over 50, we need to add the frequency of ages 21-30, 31-40, and 51-60, 61-70, 71-up.
P(under 41 or over 50) = frequency of ages 21-30 + frequency of ages 31-40 + frequency of ages 51-60 + frequency of ages 61-70 + frequency of ages 71-up
= 1 + 8 + 29 + 24 + 11
= 73
Therefore, the probability of selecting a CEO whose age is under 41 or over 50 is 73/100 or 0.73.

Part 4 of 4 (d) Under 41:
To find the probability of selecting a CEO whose age is under 41, we need to add the frequency of ages 21-30 and 31-40. This is the same as part (a).
P(under 41) = frequency of ages 21-30 + frequency of ages 31-40
= 1 + 8
= 9
Therefore, the probability of selecting a CEO whose age is under 41 is 9/100 or 0.09.

Part 1 of 4 (a) Over 20 and under 41
P(over 20 and under 41) = P(21-30) + P(31-40) = (1 + 8) / 100 = 9/100 = 0.09

Part 2 of 4 (b) Between 31 and 40
P(between 31 and 40) = P(31-40) = 8/100 = 0.08

Part 3 of 4 (c) Under 41 or over 50
P(under 41 or over 50) = P(under 41) + P(over 50) = (P(21-30) + P(31-40)) + (P(51-60) + P(61-70) + P(71-up)) = (1+8+29+24+11)/100 = 73/100 = 0.73

Part 4 of 4 (d) Under 41
P(under 41) = P(21-30) + P(31-40) = (1 + 8) / 100 = 9/100 = 0.09

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No, Lydia's assertion that δSTU is a right triangle is not correct.

A right triangle is a triangle in which one of the angles measures 90 degrees (a right angle). To determine if δSTU is a right triangle, we need to examine the angles formed by the given coordinates.

Using the coordinates:

s (-3, 0)

t (0, -3)

u (3, -3)

We can calculate the slopes of the lines formed by connecting these points to see if any of them are perpendicular (indicating a right angle).

The slope of the line connecting points s and t is:

m(st) = (y₂ - y₁) / (x₂ - x₁) = (-3 - 0) / (0 - (-3)) = -3/3 = -1

The slope of the line connecting points s and u is:

m(su) = (y₂ - y₁) / (x₂ - x₁) = (-3 - 0) / (3 - (-3)) = -3/6 = -1/2

The slope of the line connecting points t and u is:

m(tu) = (y₂ - y₁) / (x₂ - x₁) = (-3 - (-3)) / (3 - 0) = 0/3 = 0

None of the slopes calculated are perpendicular to each other, meaning none of the angles formed by the given coordinates are 90 degrees. Therefore, δSTU is not a right triangle.

In summary, Lydia's assertion that δSTU is a right triangle is incorrect because the angles formed by the given coordinates do not include a 90-degree angle.

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Answer:

5

Step-by-step explanation:

w = c + ___

means that you add a number to the value of c to get the value of w.

Look at the first line: c = 5; w = 10

What do you add to 5 to get 10?

Answer: 5

5 also works for all the other lines.

6 + 5 = 11

7 + 5 = 12

8 + 5 = 13

The number added to c to get w is always 5.

w = c + 5

Answer: 5

Answer: 48

Step-by-step explanation: 48 is the highest mileages

The 95% confidence interval for population mean is (19.8, 22.2).

The confidence interval for population mean using the Student's t-distribution is:

CI = x ± \(t_{\frac{\alpha }{2}, (n -1) }\) \(\frac{s}{\sqrt{n} }\)

Given:

x = 22

s = 3

n = 27

α = n - 1 = 26

The critical value of t for α = 0.05 and degrees of freedom, (n - 1) = 19 is:

\(t_{\frac{\alpha }{2} , (n -1)}\) = \(t_{\frac{0.05}{2,19} }\)

            = 2.093

Compute the 95% confidence interval for population mean as follows:

   CI = X + \(t_{\frac{\alpha }{2}, (n -1) }\frac{s}{\sqrt{n} }\)

⇒ CI = 21± 2.093 × 3/√27

        = 21 ± 1.20

        = (22.2, 19.8)

Thus, the 95% confidence interval for population mean is (19.8, 22.2).

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Answer: 2/8 first answer, 6/2 second answer, 3/2 last answer

Step-by-step explanation: The slope should be the rise over the run, so the answer to the first question would be 2/8 which is rise/run which equals the slope the second answer would be 6/2=slope and the the answer to the last question is 3/2 you start from one point, rise until you get next to the other point on the graph, then you run until you get on that point, the you count your rise which will be the top number of your fraction and then you count your run which will be the bottom number of your fraction. I hope this helped if you could even make sense of all of this.

Answer:

x= 83y−17 and y= 83x+17

​

hope it helps

Answer:

-9

Step-by-step explanation:

Plug 5 into the equation in place of the x:

- x - 4 becomes -(5) - 4.

-5 - 4 = -9

:)

Answer:

X < 7/2

Step-by-step explanation:

Move the variable to the left, separate into possible cases , solve, find the intersections, find the union, and then you get your solution.

Step-by-step explanation:

Given that:

|2x-7| = 7-2x

⇛2x-7 = 7-2x or -(7-2x)

since |x| = a ⇛ x = a or x = -a

⇛2x-7 = 7-2x or 2x-7 = 2x-7

Shift all variables on LHS and constant on RHS, changing it's sign.

⇛2x+2x = 7+7

Add the values on LHS and RHS.

⇛4x = 14

Shift the number 4 from LHS to RHS.

⇛x = 14/4

Write the fraction in lowest form by cancelling method.

⇛ x = {(14÷2)/(4÷2)}

⇛x = 7/2

There is no solution for negative value

x = 7/2

Please let me know if you have any other questions.

The BMI of an 118-lb adult who is 5 feet 4 inches tall is approximately 20.25.

BMI stands for Body Mass Index.

It's a measure of body fat based on height and weight that applies to both adult men and women.

BMI is an easy-to-perform screening tool for body fat levels that can help identify individuals who have health risks linked with excess body fatness.

It's important to keep in mind that the BMI measurement should not be used as a diagnostic tool for health conditions and is only one component in an overall evaluation of a person's health status.

Using the formula below, we can calculate the BMI of an 118-lb adult who is 5 feet 4 inches tall: BMI = (weight in pounds / (height in inches x height in inches)) x 703

First, we need to convert the height into inches:5 feet 4 inches = 64 inches

Next, we plug the values into the formula and solve for the BMI:

BMI = (118 / (64 x 64)) x 703BMI = (118 / 4,096) x 703BMI = 0.0288 x 703BMI = 20.2464

Therefore, the BMI of an 118-lb adult who is 5 feet 4 inches tall is approximately 20.25.

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The range of the dataset obtained from the difference between the maximum and minimum value is 5.

The range of a distribution or dataset is obtained by subtracting the maximum and minimum values in the distribution.

Range = Maximum - Minimum

From the dataset :

Maximum number of messages sent = 15

Minimum number of messages sent = 10

Range = 15 - 10 = 5

The value of the range in the dataset is 5

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The range of the set {10, 11, 11, 11, 13, 15, 15} is R = 5.

For a set of numbers {x₁, x₂, ..., xₙ}

The range is defined as the difference between the largest value and the smallest value.

In this case, we have the set:

{10, 11, 11, 11, 13, 15, 15}

The largest value is 15, and the smallest value is 10, then the range of this set will be:

Range = 15 - 10

Range = 5

The range of the set is 5 units.

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Answer:

B

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

because i just know

Answer: One abutment

Step-by-step explanation: When a fixed bridge is created, there must be at least one abutment of the bridge.

In a shortest path problem, the right-hand side (RHS) value for the starting node has a value of 0. This indicates that the shortest path from the starting node to itself has a cost of 0.

In summary, the RHS value for the starting node in a shortest path problem is 0, indicating that the shortest path from the starting node to itself has a cost of 0.

The RHS value is used in the context of the Dijkstra's algorithm, which is commonly used to solve shortest path problems. In this algorithm, a priority queue is used to store the nodes that have not yet been visited, sorted based on their tentative distances from the starting node. Initially, the starting node is assigned a tentative distance of 0, indicating that it is the source node for the shortest path. The RHS value is used to update the tentative distance of a node when a shorter path is discovered. When a node is added to the priority queue, its tentative distance is compared to its RHS value, and the smaller of the two values is used as the node's priority in the queue. By setting the RHS value of the starting node to 0, we ensure that the starting node always has the highest priority in the queue and is processed first by the algorithm.

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The particular solution is: \(y_p\)(x) = e^(-x) * cos(3x). To solve the given differential equation using the method of undetermined coefficients, we assume a particular solution of the form:

y_p(x) = Ae^(λx) * cos(3x) + Be^(λx) * sin(3x)

where A and B are undetermined coefficients, and λ is the constant we need to determine.

We start by finding the derivatives of y_p(x):

y_p'(x) = Aλe^(λx) * cos(3x) - 3Ae^(λx) * sin(3x) + Bλe^(λx) * sin(3x) + 3Be^(λx) * cos(3x)

y_p''(x) = Aλ^2e^(λx) * cos(3x) - 6Aλe^(λx) * sin(3x) - 3Ae^(λx) * sin(3x) - 3Bλe^(λx) * sin(3x) + Bλ^2e^(λx) * sin(3x) + 3Be^(λx) * cos(3x)

Now, we substitute y_p(x), y_p'(x), and y_p''(x) into the original differential equation:

[Aλ^2e^(λx) * cos(3x) - 6Aλe^(λx) * sin(3x) - 3Ae^(λx) * sin(3x) - 3Bλe^(λx) * sin(3x) + Bλ^2e^(λx) * sin(3x) + 3Be^(λx) * cos(3x)]

4[Aλe^(λx) * cos(3x) - 3Ae^(λx) * sin(3x) + Bλe^(λx) * sin(3x) + 3Be^(λx) * cos(3x)]

4[Ae^(λx) * cos(3x) + Be^(λx) * sin(3x)]

= e^(2x) * cos(3x)

Now, we can simplify the equation:

[Aλ^2 + 4Aλ + 4A] * e^(λx) * cos(3x) + [Bλ^2 + 4Bλ + 4B] * e^(λx) * sin(3x)

= e^(2x) * cos(3x)

For the equation to hold true for all values of x, the coefficients of each term must be equal:

Aλ^2 + 4Aλ + 4A = 1

Bλ^2 + 4Bλ + 4B = 0

Solving the first equation, we have:

λ^2 + 4λ + 4 = 1

λ^2 + 4λ + 3 = 0

This is a quadratic equation that can be factored:

(λ + 1)(λ + 3) = 0

λ = -1 or λ = -3

Now, let's solve the second equation for λ = -1 and λ = -3:

For λ = -1:

B*(-1)^2 + 4B*(-1) + 4B = 0

B - 4B + 4B = 0

B = 0

For λ = -3:

B*(-3)^2 + 4B*(-3) + 4B = 0

9B - 12B + 4B = 0

B = 0

Therefore, for both values of λ, B = 0.

Now, we can find the value of A:

Aλ^2 + 4Aλ + 4A = 1

For λ = -1:

A*(-1)^2 + 4A*(-1) + 4A = 1

A - 4A + 4A = 1

A = 1

For λ = -3:

A*(-3)^2 + 4A*(-3) + 4A = 1

9A - 12A + 4A = 1

A = 1/5

Therefore, for λ = -1, A = 1, and for λ = -3, A = 1/5.

The particular solution is:

\(y_p\)(x) = e^(-x) * cos(3x)

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Answer:

Kate is 3 years old, Jane is 9 years old

Step-by-step explanation:

1.) First, assign variables to all of their ages. If we say Kate's age is x, Jane's age is 3 times this, which can be written as j, is 3x.

2.) Jane's age is also 2 less than twice of Kate's in 5 years. This means that her age is also 2(x+5) - 2 = j + 5. With a little simplification, you get that 2x + 8 = j + 5.

3.) Since j, Jane's age, is also 3x, we can substitute 3x in for j in the second equation. If you do this, you get 2x + 8 = 3x + 5.

4.) By moving the x onto one side and the numbers onto another, you get x = 3. X was Kate's age, meaning that Kate is 3 years old.

5.) Finally, since Jane's age is 3 times Kate's age, Jane's age is 3 * 3, which is 9. Jane is 9 years old.

Jane is 9 years old and Kate is 3 years old.To solve the problem, let's first establish variables for Jane and Kate's ages.

Let J represent Jane's age and K represent Kate's age.
According to the student question, Jane is 3 times as old as Kate, which can be represented as:
J = 3K
In 5 years, Jane's age will be 2 less than twice Kate's age, which can be represented as:
J + 5 = 2(K + 5) - 2
Now we can solve the equations step by step:

Substitute the first equation into the second equation to eliminate one of the variables:
3K + 5 = 2(K + 5) - 2
Distribute the 2 on the right side of the equation:
3K + 5 = 2K + 10 - 2
Simplify the equation by combining like terms:
3K + 5 = 2K + 8
Move the 2K term to the left side of the equation:
K = 3
now we know that Kate is currently 3 years old.
Substitute K's value back into the first equation to find Jane's age:
J = 3K
J = 3(3)
Simplify to find Jane's age:
J = 9
So, Jane is currently 9 years old.
Jane is 9 years old and Kate is 3 years old.

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Answer:

Step-by-step explanation:

since ΔABC is ≅ to ΔEDC

where ∠A = 40°

∠E = 40° because ∠A ≅ ∠E

Answer:

I believe it is x=−b2a

Step-by-step explanation:

Looked it up

Answer:

  100.5 cm

Step-by-step explanation:

The circumference of a circle is given by the formula ...

  C = 2πr

Using the given values, we find ...

  C = 2(3.14)(16 cm) ≈ 100.5 cm . . . circumference of the circle

Answer:

it A  

x + y = 29, 5x + 2y = 100

Step-by-step explanation:

Answer:

A, x + y = 29, 5x + 2y = 100

Step-by-step explanation:

just finished the assignment on edg 2020

Answer:

n = 3200

Step-by-step explanation:

200 = 1000 - \(\frac{n}{4}\) ( subtract 1000 from both sides )

- 800 = - \(\frac{n}{4}\) ( multiply both sides by 4 to clear the fraction )

- 3200 = - n ( multiply both sides by - 1 )

n = 3200

The speed of the asteroid at the final time is infinity.

Given, the velocity as a function of time for an asteroid in the asteroid belt is given by: v(t) = v0 * e^(-t/t0) + 2t * v0

Here, v0 and t0 are constants.

Now, let's find the velocity at final time by substituting the given values:

v(t) = v0 * e^(-t/t0) + 2t * v0v(t) = 2 * e^(-t/336) + 2t * 2m/s

t(t0 = 336 seconds and v0 = 2 m/s)

Now, let's find the velocity at the final time i.e v(ff)

v(ff) = v(∞) = 2 * e^(-∞/336) + 2 * ∞ * 2 m/s = 0 + ∞ = ∞

Thus, the speed of the asteroid at the final time is infinity.

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By mathematical induction, we have proved that for any positive integer n, 4 evenly divides 11n - 7n.

WHat is Divisibility?

Divisibility is a mathematical property that describes whether one number can be divided evenly by another number without leaving a remainder. If a number is divisible by another number, it means that the division process results in a whole number without any remainder. For example, 15 is divisible by 3

To prove that 4 evenly divides 11n - 7n for any positive integer n, we can use mathematical induction.

Base Case:

When n = 1, 11n - 7n = 11(1) - 7(1) = 4, which is divisible by 4.

Inductive Step:

Assume that 4 evenly divides 11n - 7n for some positive integer k, i.e., 11k - 7k is divisible by 4.

We need to prove that 4 evenly divides 11(k+1) - 7(k+1), which is (11k + 11) - (7k + 7) = (11k - 7k) + (11 - 7) = 4k + 4.

Since 4 evenly divides 4k, and 4 evenly divides 4, it follows that 4 evenly divides 4k + 4.

By mathematical induction, we have proved that for any positive integer n, 4 evenly divides 11n - 7n.

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The requried features of the given function has been shown below.

The function f(x) = -(1/3)^x +5 has the following features:

Domain: The domain of the function is all real numbers.

Range: The range of the function is y ≤ 5. In other words, the function has a maximum value of 5, which is approached but never reached as x approaches negative infinity.

x-intercept: The x-intercept is where the graph of the function intersects the x-axis. The x-intercept is approximately -3.96.

y-intercept: The y-intercept is where the graph of the function intersects the y-axis. The y-intercept is (0, 4).

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