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Approximately 766.08 grams of oxygen are required to completely react with 240g of C₂H₆.

To determine the amount of oxygen required to completely react with 240g of C₂H₆ (ethane), we need to set up a balanced chemical equation for the combustion of ethane.

The balanced equation for the combustion of ethane is as follows:

C₂H₆ + O₂ → CO₂ + H₂O

From the balanced equation, we can see that the stoichiometric ratio between C₂H₆ and O₂ is 1:3. This means that for every one mole of C₂H₆, three moles of O₂ are required for complete combustion.

To calculate the amount of oxygen required, we need to convert the given mass of C₂H₆ to moles using its molar mass, and then use the stoichiometric ratio to determine the moles of O₂ required. Finally, we can convert the moles of O₂ back to grams using the molar mass of oxygen.

The molar mass of C₂H₆ is calculated as follows:

(2 x atomic mass of carbon) + (6 x atomic mass of hydrogen)

(2 x 12.01 g/mol) + (6 x 1.01 g/mol) = 30.07 g/mol

Now, we can proceed with the calculation:

Calculate the moles of C₂H₆:

moles of C₂H₆ = mass of C₂H₆ / molar mass of C₂H₆

moles of C₂H₆ = 240 g / 30.07 g/mol ≈ 7.98 mol

Determine the moles of O₂ using the stoichiometric ratio:

moles of O₂ = moles of C₂H₆ x (3 moles of O₂ / 1 mole of C₂H₆)

moles of O₂ = 7.98 mol x 3 ≈ 23.94 mol

Convert moles of O₂ to grams:

mass of O₂ = moles of O₂ x molar mass of O₂

mass of O₂ = 23.94 mol x 32.00 g/mol = 766.08 g

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The total kilojoules in two tablespoons is  836.8 kJ.

To determine the total kilojoules in two tablespoons of a substance, we need to know the specific substance and its energy content per tablespoon. Different substances have different energy values, so without this information, it is not possible to provide an accurate calculation.

The energy content of food or substances is typically measured in kilocalories (kcal) or kilojoules (kJ). 1 kilocalorie is equal to 4.184 kilojoules. The energy content of a substance is often listed on food labels or in nutritional databases.

For example, if we have the energy content of a substance as 100 kilocalories (kcal) per tablespoon, we can convert it to kilojoules by multiplying it by 4.184:

100 kcal * 4.184 kJ/kcal = 418.4 kJ

So, if we have two tablespoons of this substance, the total energy would be:

418.4 kJ/tablespoon * 2 tablespoons = 836.8 kJ

It's important to note that the energy content of a substance can vary depending on its composition, density, and other factors. Therefore, it is always recommended to refer to reliable sources such as food labels, nutritional databases, or consult a qualified professional to obtain accurate information regarding the energy content of specific substances.

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(a) Because acid is caustic, dolphins can perish from exposure to it. Acids are compounds that give other things protons (H+). Acid can react with the proteins and lipids in dolphins' skin when they come into touch with it, leading to chemical burns and damage to the underlying tissue. Systemic consequences from this include death.

(b) Because chlorine is a potent oxidizer, it interacts with red-hot iron powder to produce Iron(III) chloride (FeCl3) rather than Iron(II) chloride (FeCl2). FeCl3 is created when chlorine at high temperatures rapidly accepts electrons from iron atoms. Contrarily, iron interacts with HCl, a less potent oxidizer than chlorine, to produce FeCl2.

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The number of moles of the gas is 0.016 moles

The airbag reaction is the nitrogen gas obtained by the decomposition of sodium azide and the reaction is

2NaN₃ → 2Na + 3N₂

Then it is under ideal condition

P = 1atm

V = 1L

T =  495°C or 768 K

n = ?

We have to calculate moles of nitrogen = ?

R = 0.082 atm LK⁻¹mol⁻¹

So the formula is

PV =nRT

n = PV/RT

n = 1 atm×1L/0.082 atm LK⁻¹mol⁻¹×768 K

n = 0.016 moles

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Answer:

C. A Spring Scale

Explanation:

Using process of elimination, we can quickly decide that a stopwatch and a ruler will not be useful in measuring the force. This leaves us with either the spring scale or a balance scale. A balance scale is used to compare two weights, so this is eliminated. That leaves us with a spring scale. This is because we can attached the spring scale to the car and when we let it go, we can record the force. I hope this helps!

Answer:

Electronegativity is a measure of the tendency of an atom to attract electrons (or electron density) towards itself. It determines how the shared electrons are distributed between the two atoms in a bond. The more strongly an atom attracts the electrons in its bonds, the larger its electronegativity.

Explanation:

Hi there! :)

\(\large\boxed{x = 2.49 L}\)

Use the proportion for Charles' Law where:

\(\frac{v_{1}}{t_{1}}= \frac{v_{2}}{t_{2}}\)

v1 = initial volume

t1 = initial temperature

v2 = final volume

v2 = final temperature

Substitute in the given values into the proportion:

v1 = 4.39 L

t1 = 44° C

t2 = 25°C

v2 = x L

Set up the proportion:

\(\frac{4.39}{44} = \frac{x}{25}\)

Cross multiply:

\(25 * 4.39 = 44x\\\\109.75 = 44x\\\\x = 2.49 L\)

Answer:

The new volume will be approximately 2.49 L.

Explanation:

We are given that a gas sample occupies 4.39 L at 44° C.

We are also given that we are going decrease the temperature to 25° C.

Charles' Law has a formula which shows the relationship between the volumes of a samples and the temperatures of the samples.

The proportion is shown as:

\(\displaystyle \bullet \ \ \ \frac{V_1}{T_1} = \frac{V_2}{T_2}\),

where V₁ and V₂ are the initial and final volume respectively and T₁ and T₂ are the initial and final temperature respectively.

This proportion can be used to determine what our unknown is. We need to know the final volume.

\(\displaystyle \frac{4.39 \ \text{L}}{44 \ \text{C}} = \frac{\text{x}}{25 \ \text{C}}\\\\\\\frac{4.39}{44} = \frac{x}{25}\\\\\\4.39 \times 25 = 44 \times x\\\\\\44x = 109.75\\\\\\\frac{44x}{44}=\frac{109.75}{44}\\\\\\x = 2.49432 \approx \boxed{2.49 \ \text{L}}\)

Therefore, if we reduce the temperature to 25 °C, we will be reducing the volume of the substance to 2.49 L.

P Ar = 1.5

P Xe = 0.5

P tot = 2 atm

Dalton's law of partial pressures states that the total pressure of a mixture of gases is equal to the sum of the partial pressures of the component gases  

Can be formulated:  

P tot = P1 + P2 + P3 ....  

The partial pressure is the pressure of each gas in a mixture  

3 L Argon , P = 1 atm and 1 L Xe, P=1 atm⇒assume T = 273 K

mol Argon :

\(\tt n_{Ar}=\dfrac{PV}{RT}=\dfrac{1\times 3}{0.082\times 273}=0.134\)

mol Xenon :

\(\tt n_{Xe}=\dfrac{1\times 1}{0.082\times 273}=0.045\)

\(\tt P_{Ar}=\dfrac{nRT}{V}=\dfrac{0.134.0.082.273}{2}=1.5\)

\(\tt P_{Xe}=\dfrac{nRT}{V}=\dfrac{0.045.0.082.273}{2}=0.5\)

P tot = 1.5 + 0.5 = 2 atm

Answer:

They all contain switches

Answer: D. they all contain resonators.

Explanation:

This question is based on Boyle's law as temperature is constant. Boyle's law is derived from ideal gas equation only at constant temperature. Therefore, the new volume is 9.375L.

Boyle's law is a law which states that at constant temperature, the pressure that is exerted by an ideal gas on the walls of the container is inversely proportional to the volume occupied that gas.

Ideal gas is a gas where there is no forces of attraction or forces of repulsion between the particles . The volume of container is equal to the volume occupied by the gas.

Mathematically, Boyle's law can be written as

P₁V₁ = P₂V₂

P₁=initial pressure=750 torr

P₂=final pressure=80 torr

V₁ = initial volume= 1.00 L

V₂=final volume=?

V₂ = P₁V₁/P₂

V₂ = (750  × 1.00)/80

V₂ = 9.375L

Therefore, the new volume is 9.375L.

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The value of the equilibrium constant shows the relative amounts or concentrations of the reactants and products.

Answer:

(C) releases energy

Explanation:

From Bohr's model of the atom, we can understand the energy transitions involved when an electron moves from one energy level to another.

(C) releases energy

From Bohr's model of the atom:

We can understand the energy transitions involved when an electron moves from one energy level to another.

Therefore, option C is correct.

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From the stoichiometry of the reaction, the volume of the steam produced is 82.9 L

The term combustion is the term that is used to describe the kind of reaction that occurs when a substance is being burnt in oxygen. It is an oxidation reaction and the octane is burnt to produce carbon dioxide and steam.

We can try to write down the equation of the reaction as follows;

2C8H18(g) + 25O2(g) ------> 16CO2(g) + 18H2O(g)

Now 1 mole of octane gas occupies 22.4 L

x moles of octane gas occupies 9.1 L

x = 9.1 L  *  1 mole /22.4 L

x = 0.41 moles

Now;

2 mole of octane gas produces 18 moles of steam

0.41 moles of octane gas produces  0.41 moles  * 18 moles/2 mole

= 3.7 moles

1 mole of steam occupies 22.4 L

3.7 moles of steam occupies 3.7 moles *  22.4 L/1 mole

= 82.9 L

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The bulk density at 20 percent moisture, given that the soil dries to 20 percent by weight is 1.4 g/cm³

First, we shall obtain the initial volume of the soil. Details below:

Volume = mass / density

Initial volume of soil = 100 / 1.3

Initial volume of soil = 76.93 cm³

Next, we shall obtain the volume after the soil dries to 20 percent by weight. Details below:

We were told that the soil shrinks by an amount equal to the water loss, thus we have

Initial mass of water = 40% = 40 g

Water lost = 20% = 20 g

New mass of water = 40 - 20 = 20 g

Thus,

Volume = Equal value of mass of water lost = 20 cm³

Finally, we shall obtain the bulk density at 20 percent moisture. Details below:

Bulk density at 20 percent moisture = Total mass / new volume

Bulk density at 20 percent moisture = 80 /  5.93

Bulk density at 20 percent moisture = 1.4 g/cm³

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Answer:

d

Explanation:

Answer:C is the answer

Explanation:

Answer:

Explanation:

To determine the molar volume of the gas according to the equation at stp;

1 mole = 22.4 dm³

2 moles = 44.8 dm³

To determine the mass of NaN₃ inflated according to the equation

2NaN₃ (where Na = 23g and N = 14) = (2 × 23) + 2(14 × 3)

= 130 g

Hence, if 130g of NaN₃ is required to inflate 44.8 dm³ airbag upon impact

what mass of NaN₃ is required to fully inflate the air bag upon impact;

130g ⇒ 44.8 dm³

? ⇒ 11.9 dm³ (dm³ is same as L)

? = 130 × 11.9/44.8

? = 34.5g

34.5g of NaN₃ is required to fully inflate 11.9 L of air bag upon impact

Bromothymol blue mixed with water continues as a single phase, hence this mixture is an example of a given hobb-mogeneous mixture.

We know that a hom-bnbogeneous mixture is one that contains the substances that are not chemically combined yet they consist of a single phase. This implies that the substances that are in the mixture do not separate into layers. The are continuous through out the system.

We need to remind ourselves that the components in a mixture do not in anyway interact chemically and this is why the components of a mixture could be separated by the use of any of the physical methods. A het---er---ogenous is one in which the components of the mixture does separate into different phases

Given the fact that the bromothymol blue mixed with water continues as a single phase, this mixture is an example of a hom---ogeneous mixture.

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Answer:

a) The balanced chemical equation including states of matter:

NaOH(aq) + H2SO4(aq) → Na2SO4(aq) + 2H2O(l)

HCl(aq) + KOH(aq) → KCl(aq) + H2O(l)

NH3(aq) + H2SO4(aq) → (NH4)2SO4(aq)

CH3COOH(aq) + NaOH(aq) → CH3COONa(aq) + H2O(l)

NH3(aq) + CH3COOH(aq) → CH3COONH4(aq)

b) The total ionic equation:

Na+(aq) + OH-(aq) + H+(aq) + SO4^(2-)(aq) → Na+(aq) + SO4^(2-)(aq) + 2H2O(l)

H+(aq) + Cl-(aq) + K+(aq) + OH-(aq) → K+(aq) + Cl-(aq) + 2H2O(l)

NH3(aq) + 2H+(aq) + SO4^(2-)(aq) → (NH4)2SO4(aq)

CH3COO-(aq) + Na+(aq) + H+(aq) + OH-(aq) → CH3COO-(aq) + Na+(aq) + H2O(l)

NH3(aq) + CH3COOH(aq) → CH3COO-(aq) + NH4+(aq)

c) The net ionic equation:

OH-(aq) + H+(aq) → H2O(l)

H+(aq) + OH-(aq) → 2H2O(l)

NH3(aq) + H+(aq) → NH4+(aq)

CH3COO-(aq) + H+(aq) → CH3COOH(aq)

NH3(aq) + H+(aq) → NH4+(aq)

Brainliest for the effort please

Two key criteria that engineers must prioritize are efficiency and safety. By emphasizing efficiency and safety during process development, engineers can create robust and reliable processes that not only maximize productivity but also prioritize the well-being of personnel and the environment.

When developing a process, engineers need to consider several important criteria. Two key criteria that engineers must prioritize are efficiency and safety.

Efficiency is crucial in process development to ensure optimal use of resources, time, and energy. Engineers strive to design processes that maximize productivity, minimize waste, and reduce costs. This involves optimizing reaction conditions, streamlining workflow, and implementing automation where possible. Efficiency considerations also extend to energy consumption, raw material utilization, and overall process sustainability.

Safety is another critical aspect that engineers must prioritize. They need to identify and mitigate potential hazards associated with the process, ensuring the safety of both personnel and the environment. This involves conducting thorough risk assessments, implementing safety protocols, and designing equipment and systems with safety features. Engineers must also consider the safe handling and storage of materials, as well as potential risks during transportation and disposal.

By emphasizing efficiency and safety during process development, engineers can create robust and reliable processes that not only maximize productivity but also prioritize the well-being of personnel and the environment.

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Since there is excess hydrogen, that means that the concentration of hydrogen is not limiting.

According to the balanced chemical equation:

every mole of N2 and every 3 moles of H2 we obtain 2 moles of NH3. Since we have the amount of N2 and excess of hydrogen, we only need to work with the amount of N2.

1 mol of N2 will produce 2 moles of NH3

so now we can get a conversation tool :

moles of N2 * (2 moles of NH3/ 1 mole of N2) = moles of NH3

(2.22 mol of N2 x 2) ÷ 1 = 4.44 mol of NH3

The half-life of the carbon-14 obtained from the graphical representation of radioactive material remaining in a sample versus time is 5730 years.

The half-life a radioactive material is the time taken for half the material to decay or disintegrate.

For example, if the initial mass of a material is 10 g and the material becomes 5 g after 2 days. Then, we can say that the half-life of the material is 2 days.

With the above information in mind, we can obtain the half-life of the carbon-14 as illustrated below:

From the graph, we obtain:

Now, we shall obtain the time for 1/2 in the graph.

The time for 1/2 in the graph is 5730 years.

Thus, we can conclude that the half-life of the carbon-14 is 5730 years.

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Taking into account the definition of sensible heat, the energy required to raise the temperature of 4.2 mol of graphite by 25.0°C is 895.3455 J.

Sensible heat is defined as the amount of heat that a body absorbs or releases without changes in its physical state (phase change). In other words, when a system absorbs (or gives up) a certain amount of heat, it can happen that it experiences a change in its temperature without a phase change occurring, which implies sensible heat.

The expression that allows to calculate heat exchanges is:

Q = c× m× ΔT

where:

In this case, you know:

Replacing in the definition of sensible heat:

Q = 0.71 J/gC× 50.442 g× 25 C

Solving:

Q= 895.3455 J

In summary, the energy required is 895.3455 J.

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Where the above conditions are given, the dissociation degrees of KNO3, CaCl2, and Al2(SO4)3 are 0.6, 0.75, and 1.6, respectively.

The dissociation degree, α, of an electrolyte can be calculated using the formula:

α = (I - 1) / (n - 1)

where I is the ionic strength of the electrolyte and n is the number of ions produced per formula unit of the electrolyte when it dissociates.

Using the provided values of ionic strength (I), we can calculate the dissociation degree of each electrolyte as follows:

For KNO3:

α = (I - 1) / (n - 1)

α = (1.6 - 1) / (2 - 1)

α = 0.6

For CaCl2:

α = (I - 1) / (n - 1)

α = (2.5 - 1) / (3 - 1)

α = 0.75

For Al2(SO4)3:

α = (I - 1) / (n - 1)

α = (4.2 - 1) / (3 - 1)

α = 1.6

Therefore, the dissociation degrees of KNO3, CaCl2, and Al2(SO4)3 are 0.6, 0.75, and 1.6, respectively.

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Answer: chlorine 17Cl35 has 18 neutrons, and 17Cl37 has 20 neutrons

Explanation: 17 is the atomic number of chlorine which tells us what is the number of protons in chlorine nucleus. 35 and 37 is the mass number of two isotopes of chlorine, it tells us what is the total number of protons and neutrons in atomic nucleus of two chlorine isotopes .

Now to know how many neutrons are in both isotopes we have to substract the number of protons from the mass number of each isotope

For 17Cl35 it will be 35- 17 what makes 18 and for 17 Cl 37 it will be 20 neutrons

Subaquatic soil can be classified as sediment or soil based on its geological properties and formation processes.

Sediment refers to any material that is transported and deposited by water, wind, ice, or gravity. Sediments can be composed of various materials, such as minerals, rocks, organic matter, and even human-made debris.

Sediments can accumulate in different environments, such as rivers, lakes, oceans, and deserts, and can be deposited in layers over time.

Subaquatic soil can be classified as sediment or soil based on its geological properties and formation processes. If it has primarily formed through sediment deposition, it is more appropriate to classify it as sediment.

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Answer:

D

Explanation:

The unit used to measure atomic mass is the atomic mass unit (amu). A single amu is equivalent to 1/12 the mass of an atom from the carbon-12 isotopIsotopes with different numbers of protons and neutrons will have an actual mass slightly different from the atomic mass calculated in atomic mass units.

Li₃PO₄ + 3 Zn(NO₃)₂ → 3 LiNO₃ + Zn₃(PO₄)₂. In this balanced equation, one of the products is Zn₃(PO₄)₂. To ensure that the equation is balanced, we need 3 moles of Zn(NO₃)₂ for every 1 mole of Li₃PO₄.

In a chemical reaction, a product is a substance that is formed as a result of the chemical reaction. It is the end result of a chemical reaction, and it is produced by the rearrangement of atoms and/or ions of the reactants.

In the given equation, we end up with 1 mole of Zn₃(PO₄)₂ for every 3 moles of Zn₃(PO₄)₂. This means that the molar ratio of Zn₃(PO₄)₂ to Zn₃(PO₄)₂ is 1:3, indicating that we need three times as much Zn₃(PO₄)₂ as Zn₃(PO₄)₂ to balance the equation. Therefore, one of the products, Zn₃(PO₄)₂, must be produced in a smaller quantity than the other product, LiNO₃.

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