Answers
Answer:
1/2
Step-by-step explanation:
When you analyze the graph for your slope, you RISE over RUN meaning you go up/down first and then left/right next.
I got 1/2 because RISE over RUN is written the same (or is the same) as Y over X
2/4 = 1/2
3/6 = 1/2
4/8 = 1/2
5/10 = 1/2
therefore your slop must be 1/2!
hope this helpsss
Answer:
Step-by-step explanation:
Related Questions
for anyone that knows how to do this i only need help with these two questions
-4x-1=-y
solve for y
-4y+20+3x=0
solve for y
Answers
\(-4x-1=-y\\y\)
Flip the equation:
\(-y=-4x-1\)
Divide both sides by -1:
\(\frac{-y}{-1} =\frac{-4x-1}{-1}\)
\(y=4x+1\)
__________________________________________________________
\(-4y+20+3x=0\\y\)
Add -3x to both sides of the equation:
\(3x-4y+20+-3x=0+-3x\\-4y+20=-3x\)
Add -20 to both sides of the equation:
\(-4y+20+-20=-3x+-20\\-4y=-3x-20\)
Divide both sides by -4:
\(\frac{-4y}{-4} =\frac{-3x-20}{-4}\)
\(y=\frac{3}{4} x+5\)
Consider the proof.
Given: Segment AB is parallel to line DE.
Prove:StartFraction A D Over D C EndFraction = StartFraction B E Over E C EndFraction
Triangle A B C is cut by line D E. Line D E goes through side A C and side B C. Lines A B and D E are parallel. Angle B A C is 1, angle A B C is 2, angle E D C is 3, and angle D E C is 4.
A table showing statements and reasons for the proof is shown.
What is the missing statement in Step 5?
AC = BC
StartFraction A C Over D C EndFraction = StartFraction B C Over E C EndFraction
AD = BE
StartFraction A D Over D C EndFraction = StartFraction B E Over E C EndFraction
Answers
The missing statement in Step 5 include the following: B. AC/DC = BC/EC.
What are the properties of similar triangles?In Mathematics and Geometry, two triangles are said to be similar when the ratio of their corresponding side lengths are equal and their corresponding angles are congruent.
Based on the angle, angle (AA) similarity theorem, we can logically deduce the following congruent triangles:
ΔABC ≅ ΔDEC ⇒ Step 4
By the definition of similar triangles, we can logically deduce the following proportional and corresponding side lengths:
AC/DC = BC/EC ⇒ Step 5
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Missing information:
The question is incomplete and the complete question is shown in the attached picture.
5 ( y - 4)=7 (2y +1) Can someone help me out by solving for Y Thanks
Answers
5 ( y - 4 ) = 7 ( 2y + 1 )
To Find:The value of y.
Solution:5 ( y - 4 ) = 7 ( 2y + 1 )
or, 5y - 20 = 14y + 7
or, 5y - 14y = 7 + 20
or, -9y = 27
or, y = 27/-9 = -3
Answer:The value of y is -3.
( Picture Included )Help please, and don’t comment unnecessary things.
Answers
Answer:
Angle 1 and Angle 8 are alternate exterior angles.
Step-by-step explanation:
If this helps please mark as brainliest
the margin of error of a confidence interval is the error from biased sampling methods. True or False
Answers
15. Express the repeating decimal 4.61 as an exact fraction using a geometric series with 0.01 being the repeating decimal.
Answers
Answer:
4 11/18------------------------
We have a repeating decimal 4.6(1).
Let's express it as a GP:
4.6(1) = 4.6 + 0.01 + 0.001 + 0.0001 + ...Fund the sum of infinite GP, with the first term of a = 0.01 and common ratio of r = 0.1:
S = a/(1 - r) S = 0.01/(1 - 0.1) = 0.01/0.9 = 1/90Add 4.6 to the sum:
4.6 + 1/90 =4 + 0.6 + 1/90 =4 + 6/10 + 1/90 = 4 + 54/90 + 1/90 = 4 + 55/90 = 4 + 11/184 11/18Hence the fraction is 4 11/18.
Tthe library has 463 books dealing with science and 592 books of fiction. Of these, 37 are science fiction books. How many books are either science or fiction?
Answers
By Probability, the number of books that are either science or fiction is 1018.
What is Union and Intersection in Probability?A set that contains every element in at least one of the two sets is called the union of two sets.
A new set that includes every element from both sets is created when two sets intersect.
The formula including Union and Intersection is :
n(A ∪ B) = n(A) + n(B) – n(A ∩ B)
Let A= Science Books
B = Books of function
A ∪ B = Science Fiction Books
A ∩ B = Either science or fiction Books
n(A)= 463
n(B) = 592
n(A ∩ B) = 37
Therefore, n(A ∪ B) is calculated below:
n(A ∪ B) = 463 + 592 - 37
n(A ∪ B) = 1055 - 37
n(A ∪ B) = 1018
Therefore, the number of books that are either science or fiction is 1018.
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I NEED THIS RN AS FAST AS POSSIBLE! Your teacher decides to split the class into four equal groups with no more than five students in each group. that represents the number of students in the class.
Answers
See image for question. Please show workings.
Sorry for the wobbly writing.
*freq= frequency.
Answers
Answer:
See below and attachedStep-by-step explanation:
Refer to the graph attached1. The mean is calculated using below table
Marks Frequencies Midpoint Product
10 to 14 18 12 216
15 to 19 9 17 153
20 to 24 11 22 242
25 to 29 25 27 675
30 to 34 14 32 448
35 to 39 3 37 111
Sum 80 1845
The mean is:
1845/80 ≈ 232. The mode is the midpoint of the tallest bar.
The mode is
(25 + 29)/2 = 273. The median is the middle of the data set. The number of frequencies is 80, the middle frequency is number 40, which is within the 25 to 29 bar.
Formula to calculate median:
L + ( (n/2 – F) / f ) * wwhere
L: The lower limit of the median group = 25 n: The total number of observations = 80 F: The cumulative frequency up to the median group = 18 + 9 + 11 = 38 f: The frequency of the median group = 25 w: The width of the median group = 29 - 25 = 4Substitute values and calculate:
25 + ((80/2 - 38)/25) *4 = 25.32
Let U denote a random variable uniformly distributed over (0,1). Compute the conditional distribution of U given that a. U > a; b. U < a; where 0 < a < 1.
Answers
a. The conditional distribution of U is 1 / (u - a), a < u ≤ 1.
b. The conditional distribution of U is 1 / (au), 0 < u < a.
We will use Bayes' theorem to compute the conditional distributions.
a. U > a:
The probability that U > a is given by P(U > a) = 1 - P(U ≤ a) = 1 - a. To compute the conditional distribution of U given that U > a, we need to compute P(U ≤ u | U > a) for u ∈ (a,1). By Bayes' theorem,
P(U ≤ u | U > a) = P(U > a | U ≤ u) P(U ≤ u) / P(U > a)
= [P(U > a ∩ U ≤ u) / P(U ≤ u)] [P(U ≤ u) / (1 - a)]
= [P(a < U ≤ u) / (u - a)] [1 / (1 - a)]
= 1 / (u - a), a < u ≤ 1.
Therefore, the conditional distribution of U given that U > a is a uniform distribution on (a,1), i.e., U | (U > a) ∼ U(a,1).
b. U < a:
The probability that U < a is given by P(U < a) = a. To compute the conditional distribution of U given that U < a, we need to compute P(U ≤ u | U < a) for u ∈ (0,a). By Bayes' theorem,
P(U ≤ u | U < a) = P(U < a | U ≤ u) P(U ≤ u) / P(U < a)
= [P(U < a ∩ U ≤ u) / P(U ≤ u)] [P(U ≤ u) / a]
= [P(U ≤ u) / u] [1 / a]
= 1 / (au), 0 < u < a.
Therefore, the conditional distribution of U given that U < a is a Pareto distribution with parameters α = 1 and xm = a, i.e., U | (U < a) ∼ Pa(1,a).
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Let V = {x3 + x, x2 - x, 2x3+ 2x2, 3x3 + x}. Use the definition of independence to decide if V is independent or not. then find a basis for Span(V)
Answers
Since the only solution is the trivial solution, the set V = {x^3 + x, x^2 - x, 2x^3 + 2x^2, 3x^3 + x} is independent.So, a basis for Span(V) is {x^3 + x, x^2 - x, 2x^3 + 2x^2, 3x^3 + x}.
If such non-zero scalars exist, then the set V is dependent. If no such non-zero scalars exist, then the set V is independent.
To check if this condition is satisfied, we equate the coefficients of each power of x to zero.
By comparing the coefficients, we obtain the following equations:
k1 + k3 + 3k4 = 0 (coefficients of x^3)
k1 - k2 + 2k3 = 0 (coefficients of x^2)
k1 - k3 = 0 (coefficients of x)
k4 = 0 (constant term)
We can solve this system of equations to determine the values of k1, k2, k3, and k4. Solving the equations, we find that k1 = 0, k2 = 0, k3 = 0, and k4 = 0, meaning that the only solution is the trivial solution.
Therefore, since the only solution is the trivial solution, the set V = {x^3 + x, x^2 - x, 2x^3 + 2x^2, 3x^3 + x} is independent.
To find a basis for Span(V), we can simply take the set V itself as the basis since it is independent. So, a basis for Span(V) is {x^3 + x, x^2 - x, 2x^3 + 2x^2, 3x^3 + x}.
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Pencil are old in boxe of 10
eraer are old in boxe of 14
a teacher want to buy the ame amount of pencil and eraer. How many of each box hould he buy?
Answers
To achieve an equal amount of each, the teacher should purchase two boxes of pencils (10 pencils each) and two boxes of erasers (14 erasers each).
Equal quantities of pencils and erasers must be purchased by the teacher. The pencils and erasers are packaged in boxes of 10 and 14, respectively. Consequently, the instructor needs to purchase two boxes of pencils (each containing ten) and two boxes of erasers (14 erasers each). They will receive the same number of pencils (20) and erasers as a result (28). The teacher can then make sure that there is an equal number of both types of writing implements in the classroom. This is particularly crucial if they are instructing a sizable class and need to make sure that everyone is given the same number of learning aids. Giving children the supplies they need to succeed in the classroom, including an equal number of pencils and erasers, is crucial.
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A mathematician is wondering what would happen to the surface area of a square if you were to repeatedly cut the square in half. She concludes that the surface area would become less and less but would never become zero units\(^2\). Which equation would help her model the surface area of a square piece of paper as it was repeatedly cut?
a) \(y=x^2+4x-16\)
b) \(y=-25x^2\)
c) \(y=9(2)^x\)
d) \(y=36(\frac{1}{2})^x\)
Answers
The equation that would help the mathematician model the surface area of a square piece of paper as it was repeatedly cut is \(y = 36 \times \frac{1}{2}^x\)
Option D is the correct answer.
We have,
In this equation, the variable x represents the number of times the square is cut in half, and y represents the surface area of the square.
As x increases, the exponent of 1/2 decreases, causing the value of y to decrease.
This exponential decay accurately represents the idea that the surface area becomes less and less but never reaches zero units²
Thus,
The equation that would help the mathematician model the surface area of a square piece of paper as it was repeatedly cut is \(y = 36 \times \frac{1}{2}^x\).
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The correct equation that would help model the surface area of a square piece of paper as it is repeatedly cut in half is: \(\(y=36(\frac{1}{2})^x\)\)
As the square is cut in half, the side length of the square is divided by 2, resulting in the area being divided by \(\(2^2 = 4\)\).
Therefore, the equation \(y=36(\frac{1}{2})^x\)\)accurately represents the decreasing surface area of the square as it is repeatedly cut in half.
and, \(\(y=x^2+4x-16\)\)is a quadratic equation that does not represent the decreasing nature of the surface area.
and, \(\(y=-25x^2\)\) is a quadratic equation with a negative coefficient.
and, \(\(y=9(2)^x\)\)represents exponential growth rather than the decreasing nature of the surface area when the square is cut in half.
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show on graph 1,242 ÷ 23 = 54 and 731 x 268 = 196,176
Answers
Given the operation
\(1,242\div23=54\)The long division will be as shown in the following picture :
Find the solutions to the following equation. Answers as ordered pairsx^2 + 6x + 5 = 0
Answers
x² + 6x + 5 = 0
To find the solution, we can use the quadratic formula.
\(\begin{gathered} x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x_{1,2}=\frac{-6\pm\sqrt[]{6^2-4(1)(5)}}{2(1)} \\ x_{1,2}=\frac{-6\pm\sqrt[]{36^{}-20}}{2} \\ x_{1,2}=\frac{-6\pm4}{2} \\ x_1=\frac{-6+4}{2}=-1 \\ x_2=\frac{-6-4}{2}=-5 \end{gathered}\)The solutions are (-1, 0) and (-5, 0)
in a large population, 62 % of the people have been vaccinated. if 5 people are randomly selected, what is the probability that at least one of them has been vaccinated?
Answers
The probability that at least one of the 5 people selected has been vaccinated is 0.998, or 99.8%.
To solve this problem, we can use the complement rule, which states that the probability of an event happening is equal to 1 minus the probability of the event not happening. In this case, the event we're interested in is at least one person being vaccinated.
First, we need to find the probability that none of the 5 people selected have been vaccinated. Since 62% of the population has been vaccinated, that means 38% have not been vaccinated. So the probability of any one person not being vaccinated is 0.38.
Using the multiplication rule for independent events, the probability that all 5 people have not been vaccinated is:
0.38 x 0.38 x 0.38 x 0.38 x 0.38 = 0.002
Now we can use the complement rule to find the probability that at least one person has been vaccinated:
1 - 0.002 = 0.998
So the probability that at least one of the 5 people selected has been vaccinated is 0.998, or 99.8%.
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h(x) = 4x +3. What is
the coordinate pair for h (1)?
Answers
9514 1404 393
Answer:
(1, 7)
Step-by-step explanation:
Fill in x=1 and do the arithmetic.
h(1) = 4(1) +3 = 7
The coordinate pair is ...
(x, h(x)) = (1, h(1)) = (1, 7)
How many times will the following loop execute?
int x = 0;
do {
x++;
cout << x << endl;
}while(x < 5)
Answers:
a. - 5 times
b. - 4 times
c. - It doesn't
d. - Infinite times
e. - 6 times
Answers
Answer:
Step-by-step explanation:
The loop will run an infinite number of times
Need help with this ASAP I’ll mark brainliest
Answers
Answer:
A' (9, - 1 )
Step-by-step explanation:
Using the translation rule
(x, y ) → (x + 6, y - 3 ) , then
A (3, 2 ) → A' (3 + 6, 2 - 3 ) → A' (9, - 1 )
PLEASE PLEASE HELP!!
For problems 11 and 12, find the area of the figure. Round your answer to the nearest tenth, if necessary.
Answers
Answer:
Step-by-step explanation:
11)
A= (B x H)/2
A= (2.9x3.2)/2= 4.64cm²
12)
A= (B+b)H /2
A= (12+10)5.6 /2 = 61.6in
Answer:
I think that the answer might be 9.30 for the first one and the second one I think is 670.
Step-by-step explanation:
To find the area, you have to multiply the height and width for the two figures.
3.2 × 2.9 = 9.28
12 × 10 × 5.6 = 672
I think you round those to the nearest tenth. 9.28 would be 9.30 and 672 would be 670. I hope this answers your question.
What is 89% of 260 sec?
pls help
Answers
Answer:
3.85666667 minutes of 260sec
Hey there!
89% of 260
= 89/100 of 260
= 89/100 * 260/1
= 23,140 / 100
= 23,140 ÷ 20 / 100 ÷ 20
= 1,157 / 5
= 231 2/5
≈ 231.4
Therefore, your answwr should be: 231.4
Good luck on your assignment & enjoy your day!
~Amphitrite1040:)
A toothbrush sells for $1.75, but the actually cost of materials for the toothbrush is $0.65. If the operating cost of
the factory and paying the workers is $5800 per day, what is the least amount of toothbrushes the company must sell
per day?
Answers
Answer:
X>5273
Step-by-step explanation:
I did the math cuz I needed the answer and got it right so hope I could help.
What is the distance between (0,-8) and (3,-2) ?
Answers
Step-by-step explanation:
this is your answer. it think it will help you
I don’t know how to rewrite this in graphing form.
Answers
We can write this equation as (x-3)² + (y-2)² =25 in graphing form.
What is graphing form ?The vertex form of a quadratic equation is y = a (x h) 2 + k as opposed to the regular quadratic form, which is an x 2 + b x + c = y. Graphs
f(x) = ax² + bx + c, where a, b, and c are numbers and an is not equal to zero, is a quadratic function. A parabola is the shape of a quadratic function's graph.
Given Data
Equation:
x² +y² -6x +9y - 12 = 0
Writing in graphing form,
(x² - 6x) + (y² + 4y) = 12
(x² - 6x +9-9) + (y² +4y+4-4) = 12
(x² -6x +9) + (y² +4y+4) = 25
(x-3)² + (y-2)² =25
Center (x, y) = (3,-2)
radius r = 5
We can write this equation as (x-3)² + (y-2)² =25 in graphing form.
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For time t > 0, the position of an object moving in the xy-plane Is given by the parametric equations > (t) tcos (t/2) adylt) = Ve+2 Wnat Is the speed of the oblect at time t a. 1,155 b. 1.319 c. 1.339 d. 1.810
Answers
The speed of the object at time t = π is approximately 1.339. Hence, the answer is (c) 1.339.
To find the speed of the object at time t, we need to find the magnitude of its velocity vector, which is the derivative of its position vector with respect to time.
So, we first find the velocity vector:
r'(t) = ⟨cos(t/2) - (t/2)sin(t/2), sin(t/2) + (t/2)cos(t/2)⟩
Then, we find the magnitude of the velocity vector:
| r'(t) | = sqrt[ (cos(t/2) - (t/2)sin(t/2))^2 + (sin(t/2) + (t/2)cos(t/2))^2 ]
Now, we substitute t = π in the above expression to get the speed of the object at time t = π:
| r'(π) | = sqrt[ (cos(π/2) - (π/4)sin(π/2))^2 + (sin(π/2) + (π/4)cos(π/2))^2 ]
| r'(π) | = sqrt[ (0 - (π/4))^2 + (1 + (π/4))^2 ]
| r'(π) | = sqrt[ π^2 / 16 + (2π + 1) / 16 ]
| r'(π) | = sqrt[ π^2 + 2π + 1 ] / 4
| r'(π) | = (π + 1) / 2sqrt[2]
Using a calculator, we get that | r'(π) | ≈ 1.339.
Therefore, the speed of the object at time t = π is approximately 1.339. Hence, the answer is (c) 1.339.
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If events A and B are independent, what must be true?
P(A|B) = P(B)
P(A|B) = P(A)
P(A) = P(B)
P(A|B) = P(B|A)
Answers
Answer:
P(A|B) = P(A)
Step-by-step explanation:
If events A and B are independent, then we have:
P(A) x P(B) = P(A⋂B)
As the conditional probability formula states:
P(A⋂B) = P(A|B) x P(B) = P(B|A) x P(A)
=> P(A) x P(B) = P(A|B) x P(B) = P(B|A) x P(A)
or
P(A) = P(A|B)
or
P(B) = P(B|A)
Answer:
B
Step-by-step explanation:
How do you find the remainder when a polynomial in x is divided by a binomial of the form XR?
Answers
There are two ways to find the remainder when a polynomial in x is divided by a binomial of the form x-r, the use of synthetic division or calculate P(r).
Synthetic division
The Synthetic division is a shortcut way of polynomial division, especially if we need to divide it by a linear factor. It is generally used to find out the zeroes or roots of polynomials and not for the division of factors.
Polynomial
A polynomial is defined as an expression which is composed of variables, constants and exponents, that are combined using mathematical operations such as addition, subtraction, multiplication and division.
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Data collected at an airport suggests that an exponential distribution with mean value 2.455 hours is a good model for rainfall duration (a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours? At most 3 hours? Between 2 and 3 hours? (Round your answers to four decimal places.) at least 2 hours at most 3 hours between 2 and 3 hours (b) What is the probability that rainfall duration exceeds the mean value by more than 3 standard deviations? (Round your answer to four decimal places.) What is the probability that it is less than the mean value by more than one standard deviation?
Answers
Probability of duration at least 2 hours: 0.4232, Probability of duration at most 3 hours: 0.5914, Probability of duration between 2 and 3 hours 0.1682, Probability of duration exceeding mean by more than 3 standard deviations: 0.0013,
Probability of duration being less than mean by more than one standard deviation: 0.1573
Based on the data collected at the airport, rainfall duration follows an exponential distribution with a mean value of 2.455 hours. We can use this information to answer the following questions:
(a) To find the probability that the duration of a rainfall event is at least 2 hours, we can calculate the cumulative distribution function (CDF) of the exponential distribution. The probability can be found by subtracting the CDF value at 2 hours from 1, which represents the complementary probability.
Similarly, to find the probability that the duration is at most 3 hours, we can calculate the CDF at 3 hours. Finally, to find the probability that the duration is between 2 and 3 hours, we subtract the CDF value at 2 hours from the CDF value at 3 hours.
(b) To determine the probability that rainfall duration exceeds the mean value by more than 3 standard deviations, we need to calculate the z-score for 3 standard deviations and find the corresponding probability using the standard normal distribution.
Similarly, to find the probability that the duration is less than the mean value by more than one standard deviation, we calculate the z-score for -1 standard deviation and find the corresponding probability.
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Mimi wants to spend a $25 gift card on two kinds of in -app purchases for her favorite game: premium skins that cost $2.99, and tools that cost $4.99.
Answers
The equation that shows the way that Mimi can spend a $25 is 2.99p + 4.99t = 25.
What is an equation?A mathematical equation is the statement that illustrates that the variables given. In this case, two or more components are taken into consideration to describe the scenario.
Let the premium skins be p.
Let the number of tools be t.
This will be illustrated as:
(2.99 × p) + (4.99 × t) = 25
2.99p + 4.99t = 25
This illustrates the equation.
The complete question is given below.
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Mimi wants to spend a $25 gift card on two kinds of in -app purchases for her favorite game: premium skins that cost $2.99, and tools that cost $4.99. What is the equation to depict this?
What is the value of x in the equation −6 + x = −5? 1, 11, −1, −11
Answers
Answer:
1 exactly iam genius
₩¥₩