pproximate The Zero(S) Of The Function. Use Newton's Method And Continue The Process Until Two Successive Approximations Differ By Less Than 0.001. Then Find The Zero(S) To Three Decimal Places Using A Graphing Utility And Compare The Results. F(X) = X3 + 9 Newton's Method: X= Graphing Utility: X=
Approximate the zero(s) of the function. Use Newton's Method and continue the process until two successive approximations differ by less than 0.001. Then find the zero(s) to three decimal places using a graphing utility and compare the results.
f(x) = x3 + 9
Newton's method: x=
Graphing utility: x=

Answers

Answer 1

To use Newton's Method, we need to start with an initial approximation, which we can choose as x=1. Then, we can use the formula: x1 = x0 - f(x0)/f'(x0)

where x0 is the initial approximation, f(x0) is the function evaluated at x0, and f'(x0) is the derivative of the function evaluated at x0. In this case, we have:

f(x) = x3 + 9
f'(x) = 3x2

So, we can plug in x0=1 and get:

x1 = 1 - (1^3 + 9)/(3(1^2))
x1 = 1 - 10/3
x1 = -7/3

Now, we can repeat the process using x1 as our new approximation:

x2 = x1 - f(x1)/f'(x1)
x2 = (-7/3) - [(-7/3)^3 + 9]/[3(-7/3)^2]
x2 = (-7/3) - (-754/81)
x2 = 175/81

We can continue this process until two successive approximations differ by less than 0.001:

x3 = 1709/567
x4 = 532082/178605
x5 = 328211562/109735763

Now, we can use a graphing utility to find the zeros to three decimal places. We can see from the graph that there is only one real zero, which is approximately -2.080. This is close to our last approximation using Newton's Method, which was x5 = 2.994. However, our approximation is not accurate to three decimal places, so we need to keep going with Newton's Method.

x6 = -2.082297225
x7 = -2.080083055
x8 = -2.080083823

Now, we have found an approximation that is accurate to three decimal places: -2.080. This is very close to the zero we found using the graphing utility.

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Related Questions

drag each expression to show whether it is equivalent to 3 time times 9 or to 2x3x9​

drag each expression to show whether it is equivalent to 3 time times 9 or to 2x3x9

Answers

The first and third one goes to the left box and the second and fourth one goes to the right box

what is the answer to this? what does a equal?−6(−4+5)=−30+6

Answers

Answer:

I guess it would be 36?

Step-by-step explanation:

help me i need it
!!!!!!!!!!!!!!!!!!!!!!!!!

help me i need it!!!!!!!!!!!!!!!!!!!!!!!!!

Answers

Answer:

S, BB, J

Step-by-step explanation:

Because you are going greatest (positive) to least (negative)

Highest to lowest

write a solution system for the inequality 3x-2>10

Answers

Answer:

x>4

Step-by-step explanation:

3x - 2 >10  add 2 to both sides

3x > 12  Divide both sides by 3

x >4

Answer:

\(x > \bf 4\)

Step-by-step explanation:

To find a solution to this inequality, we have to rearrange this equation to make \(x\) its subject:

\(3x - 2 > 10\)

⇒ \(3x - 2 + 2 > 10 + 2\)      [Add 2 to both sides]

⇒ \(3x > 12\)

⇒ \(\frac{3x}{3} > \frac{12}{3}\)                         [Divide both sides by 3]

⇒ \(x > \bf 4\)

At LaGuardia Airport for a certain nightly flight, the probability that it will rain is 0.11 and the probability that the flight will be delayed is 0.14. The probability that it will not rain and the flight will leave on time is 0.76. What is the probability that the flight would be delayed when it is raining? Round your answer to the nearest thousandth.

Answers

Since probabilities cannot be negative, we can conclude that the given probabilities are inconsistent or there might be an error in the information provided. Please verify the values and provide correct probabilities so that we can accurately calculate P(B|A), the probability of the flight being delayed when it is raining.

Let's denote the events as follows:

A: It will rain

B: The flight will be delayed

We are given the following probabilities:

P(A) = 0.11 (probability of rain)

P(B) = 0.14 (probability of flight delay)

P(A'∩B') = 0.76 (probability of no rain and on-time departure)

We can use the probability formula to calculate the probability of the flight being delayed when it is raining, P(B|A), which is the probability of B given A.

We know that:

P(B|A) = P(A∩B) / P(A)

To find P(A∩B), we can use the formula:

P(A∩B) = P(A) - P(A'∩B')

Substituting the given values:

P(A∩B) = P(A) - P(A'∩B')

P(A∩B) = 0.11 - 0.76

P(A∩B) = -0.65

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Multiply and simplify if possible - radical functions. Thank you!

Multiply and simplify if possible - radical functions. Thank you!

Answers

We want to simplify the following expression

\(\sqrt{7x}(\sqrt{x}+7\sqrt{7})\)

First, we can apply the distributive rule to rewrite this product

\(\sqrt{7x}(\sqrt{x}+7\sqrt{7})=(\sqrt{7x})(\sqrt{x})+(\sqrt{7x})(7\sqrt{7})\)

Then, using the following property

\(\sqrt{x}\cdot\sqrt{y}=\sqrt{x\cdot y}\)

we can rewrite our expression as

\((\sqrt{7x})(\sqrt{x})+(\sqrt{7x})(7\sqrt{7})=\sqrt{7x\cdot x}+7\sqrt{7x\cdot7}\)

We can remove the squared terms out of the root

\(\sqrt{7x\cdot x}+7\sqrt{7x\cdot7}=x\sqrt{7}+7\cdot7\sqrt{x}=x\sqrt{7}+49\sqrt{x}\)

and this is our answer.

\(\sqrt{7x}(\sqrt{x}+7\sqrt{7})=x\sqrt{7}+49\sqrt{x}\)

Minimize f(x)=2x2 1-2 x1 x 2+2x2-6 x 1 +6
Subject to: x1+x2-2=0
Using the Lagrange multipliers technique. Compute the optimal point values ​​for x1, x2, l y ll
In an optimization problem with equality constraints, what is the meaning of the values ​​of the Lagrange multipliers?

Answers

The optimal point values for x1, x2, λ, and μ (Lagrange multipliers) in the given problem are:

x1 = 1

x2 = 1

λ = -4

μ = 2

To solve the optimization problem using the Lagrange multipliers technique, we first construct the Lagrangian function L(x1, x2, λ) by incorporating the equality constraint:

L(x1, x2, λ) = f(x1, x2) - λ(g(x1, x2))

Where f(x1, x2) is the objective function, g(x1, x2) is the equality constraint, and λ is the Lagrange multiplier.

In this case, the objective function is f(x1, x2) = 2x1^2 - 2x1x2 + 2x2 - 6x1 + 6, and the equality constraint is g(x1, x2) = x1 + x2 - 2.

The Lagrangian function becomes:

L(x1, x2, λ) = 2x1^2 - 2x1x2 + 2x2 - 6x1 + 6 - λ(x1 + x2 - 2)

To find the optimal values, we need to find the critical points by taking partial derivatives of L with respect to x1, x2, and λ and setting them equal to zero. Solving these equations simultaneously, we get:

∂L/∂x1 = 4x1 - 2x2 - 6 - λ = 0

∂L/∂x2 = -2x1 + 2 + λ = 0

∂L/∂λ = -(x1 + x2 - 2) = 0

Solving these equations, we find x1 = 1, x2 = 1, and λ = -4. Substituting these values into the equality constraint, we can solve for μ:

x1 + x2 - 2 = 1 + 1 - 2 = 0

Therefore, μ = 2.

The optimal point values for the variables in the optimization problem are x1 = 1, x2 = 1, λ = -4, and μ = 2. The Lagrange multipliers λ and μ represent the rates of change of the objective function and the equality constraint, respectively, with respect to the variables. They provide insights into the sensitivity of the objective function to changes in the constraints and can indicate the impact of relaxing or tightening the constraints on the optimal solution. In this case, the Lagrange multiplier λ of -4 indicates that a small increase in the equality constraint (x1 + x2 - 2) would result in a decrease in the objective function value. The Lagrange multiplier μ of 2 indicates the shadow price or the marginal cost of satisfying the equality constraint.

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Kevin buys
A total of 350 raffle tickets are sold.
One of these tickets will win the raffle.
Each ticket has an equal chance of winning the raffle,
Write down the probability that
Kevin's ticket will win the raffle.

Answers

Answer:

1:350 i think

Step-by-step explanation:

i could be wrong

Answer:

1:350 or 1 out of 350. There are 350 tickets, he only bought 1.

At a sand and gravel plant, sand is falling off a conveyor and onto a conical pile at a rate of 12 cubic feet per minute. The diameter of the base of the cone is approximately 4 times the altitude. At what rate is the height of the pile changing when the pile is 18 feet high? Express your answer in terms of π (V=1/3 πr^2h)

Answers

The rate at which the height of the pile is changing when the pile is 18 feet high is given by dh/dt = [Answer] ft/min. sand is falling off the conveyor at a rate of 12 cubic feet per minute,

To find the rate at which the height of the pile is changing, we need to use related rates and the volume formula for a cone. The problem provides information about the rate at which sand is falling ,

off the conveyor, which corresponds to the rate of change of volume of the cone. We also know the relationship between the diameter and altitude of the cone.

Let's denote the height of the pile as h and the radius of the base as r. From the problem statement, we have the relationship r = h/4, since the diameter of the base is approximately 4 times the altitude.

The volume of a cone is given by the formula V = (1/3) * π * r^2 * h. We want to find dh/dt, the rate at which the height is changing, when h = 18 feet.

To solve this problem, we'll differentiate the volume formula with respect to time t, using the chain rule and related rates. We havedV/dt = (1/3) * π * (2rh * dr/dt + r^2 * dh/dt) Since sand is falling off the conveyor at a rate of 12 cubic feet per minute,

we know that dV/dt = 12 ft^3/min. Substituting the given values and the relationship between r and h, we can solve for dh/dt.

Plugging in the values, we have:

12 = (1/3) * π * [(2 * (h/4) * dr/dt) + ((h/4)^2 * dh/dt)]

Simplifying the equation and solving for dh/dt, we can determine the rate at which the height of the pile is changing.

Therefore, the rate at which the height of the pile is changing when the pile is 18 feet high is given by dh/dt = [Answer] ft/min.

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Tineka has a sack that contains 7/12 lb of jellybeans. If she splits the jellybeans into 2 piles of equal weight, how much will each pile weigh?

F 3/16
H 1 1/16
G 7/24
J Not here

Answers

The weight of each of the two piles Tineka split the jellybeans in the sack to is 7/24 lb.

What is the weight of each pile?

Division is when two numbers are grouped into equal parts using another number. The sign used to denote division is ÷.

In order to determine the weight of each pile, divide the weight of the sack by 2.

Weight of each sack = 7/12 ÷ 2

7/12 x 1/2 = 7/24

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a quality control expert at life batteries wants to test their new batteries. the design engineer claims they have a variance of 8100 with a mean life of 1192 minutes. if the claim is true, in a sample of 72 batteries, what is the probability that the mean battery life would be greater than 1173.8 minutes? round your answer to four decimal places.

Answers

For a sample of 72 batteries, the probability that the average battery life of the sample exceeds 1173.8 minutes is 0.9918.

It states a battery life variance of 8100 minutes and a median battery life of 1192 minutes.

In a sample of 72 batteries, find the probability that the average battery life (x) of the sample exceeds 1173.8 minutes.

Due to the large sample size (n = 72), we can use the central limit theorem to assume that the sample mean follows a normal distribution with mean μ = 1192 and standard deviation σ = sqrt(8100/72) = 30.

So the z-score for x= 1173.8 is

z = (x - μ) / (σ / sqrt(n))

= (1173.8 - 1192) / (30 / square(72))

= -2.4

You can use a standard normal distribution table or calculator to find the probability that a  standard normal random variable is greater than -2.4. This is 0.9918 (rounded to four decimal places).

Therefore, for a sample of 72 batteries, the probability that the average battery life of the sample exceeds 1173.8 minutes is 0.9918 (rounded to four decimal places) if the claim is correct. 

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There is a probablity of ____ that any individual at a random from
a population will fall (plus or minus) one standard deviation of
the mean.

Answers

Step-by-step explanation:

I hope this answer is helpful ):

There is a probablity of ____ that any individual at a random froma population will fall (plus or minus)

The critical value in a chi-square test for independence depends on Multiple Choice the normality of the data. the variance of the data. the number of categories. the expected frequencies.

Answers

The critical value in a chi-square test for independence depends on the number of categories and expected frequencies, and not on the normality or variance of the data.

The critical value in a chi-square test for independence is determined by the number of categories and expected frequencies in the data. This test is used to analyze the relationship between two categorical variables, and the expected frequencies are calculated based on the assumption of independence between these variables. The critical value is the minimum value of the test statistic that would result in rejecting the null hypothesis, which states that the two variables are independent.

The normality and variance of the data do not affect the critical value in a chi-square test for independence. This test does not assume a normal distribution of the data, and the variance is not used to calculate the expected frequencies. Instead, the expected frequencies are determined by the marginal frequencies of the two variables, assuming that they are independent.

It is important to use the correct critical value in a chi-square test for independence, as using the wrong value could result in incorrect conclusions about the relationship between the two variables. The critical value can be found using a chi-square distribution table or calculator, based on the number of categories and the level of significance chosen for the test.

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A source supply produces 7.5 x 107 gallons of water per day. How many gallons of water will be produced in 37 days?

Answers

Answer: 29,692.5 gallons of water

Step-by-step explanation: first i multiplied 7.5 and 107 and got 802.5 and since it wanted to know about 37 days i multiplied 802.5 by 37 and got 29,692.5

How do you find the third side of an inequality of a triangle?

Answers

To find the third side of an inequality of a triangle, you must first use the Triangle Inequality Theorem.

This theorem states that for any triangle, the sum of any two sides of the triangle must be greater than the third side. This means that in order to find the length of the third side, you must subtract the sum of the two known sides from the smaller of the two sides, then the length of the third side will be equal to the difference between these two numbers. For example, if two sides of a triangle have lengths of 4 and 3, the third side must be greater than 1 (4 + 3 = 7 and 4 - 3 = 1). Therefore, the length of the third side must be greater than 1.

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[3 + 3 + 3 + 3 pts) In this exercise you will generalize the binomial distribution.
(a) Show that the number of possible ways in which a set A with cardinality |A| = n can be partitioned into r subsets A1,..., A, with cardinalities n1,..., nr such that ni +...+ nor = n is equal to n! / ni!...n!

Answers

The number of possible ways to partition a set A with cardinality n into r subsets with varying cardinalities is given by n! / (n1! * n2! * ... * nr!).

How can a set A be partitioned into subsets of different sizes?

Partitioning a set A into subsets of varying sizes involves calculating the number of possible ways to arrange the elements in the subsets. The formula n! / (n1! * n2! * ... * nr!) accounts for the total number of permutations while considering the specific sizes of each subset.

To understand why this formula works, let's break it down step by step.

Step 1: Counting permutations

The numerator n! represents the total number of permutations of the elements in set A. This is because when we partition a set, the order in which we choose the elements for each subset matters. So, we start with n choices for the first element, (n-1) choices for the second element, and so on, resulting in n! permutations.

Step 2: Accounting for subsets

However, in the numerator, we are overcounting because the order of elements within each subset doesn't matter. To correct for this, we divide by the factorials of the sizes of the subsets (n1!, n2!, ..., nr!). This ensures that each partition is counted only once, irrespective of the order in which the elements are chosen within each subset.

Step 3: Simplifying the formula

Dividing n! by the product of the factorials simplifies the formula, giving us the final result: n! / (n1! * n2! * ... * nr!).

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Fill in the blanks with the correct words:
An event that has probability O is said to be
An event that has probability 1 is said to be

Answers

Answer:

Impossible; certain to happen

Step-by-step explanation:

Probability = 0 applies to an event which cannot happen.  Example: roll a die and get a 7.

Probability = 1 applies to an even which is certain to occur.  Example: roll a die and get a number less than 8.

The volume of this cone is 140 cm3
Find the perpendicular height, c.
Give your answer rounded to 1 DP.
х
7 cm

The volume of this cone is 140 cm3Find the perpendicular height, c.Give your answer rounded to 1 DP.7

Answers

Answer:

x = 10.9 cm

Step-by-step explanation:

Formula for a cone

Volume (cone) = 1/3 × π × (radius)² × height

Here, we are given :

Diameter = 7 cmVolume = 140 cm³

Solving

140 = 1/3 × 22/7 × (7/2)² × (x)420 = 11 × 7/2 × (x)77x = 840x = 840/77x = 10.9 cm (1 DP)

Answer:

x ≈ 3.6 cm

Step-by-step explanation:

the volume (V) of a cone is calculated as

V = πr²h ( r is the radius and h the perpendicular height )

here diameter = 7 , so r = 7 ÷ 2 = 3.5 , V = 140 and h = x , then

π × 3.5² × x = 140

π × 12.25x = 140 ( divide both sides by 12.25π )

x = \(\frac{140}{12.25\pi }\) ≈ 3.6 cm ( to 1 dec. place )

Solve -6x +18> -30.
A. x < 2
B. x > 2
C. x > 8
D. x < 8

Answers

Answer: D, x < 8

Step-by-step explanation: Subtract 18 from both sides.

Simplify the expression

Subtract the numbers

Subtract the numbers

Divide both sides by the same factor, and flip the relation because the factor is negative

Cancel terms that are in both the numerator and denominator

Divide the numbers

−6x+18−18>−30−18=

=x<8

What is the area of this kite?
8 m
12 m
12 m
30 m
38 m

Answers

What kite? Where’s the image

Write a real word situation involving multiplication comparison that may be represented by the equations shown 24=4times6;24=6 times 2. 45=9 times 5; 45 = 5 times 9 3. 36= 3 times12; 36 =12 times 3 4. 60 =12 times 5; 60 = 5times 12

Write a real word situation involving multiplication comparison that may be represented by the equations

Answers

1. 24=4times6;24=6 times 4 is represented by  apple orchard

2. 45=9 times 5; 45 = 5 times 9 is represented by  classroom of students

3.  36= 3 times12; 36 =12 times 3  is represented by A construction site

4. 60 =12 times 5; 60 = 5times 12 is represented by A grocery store

How write the real word situation

1. An apple orchard is comparing the productivity of two of its workers in terms of the number of baskets of apples picked. Worker A picked 4 baskets in 6 hours, while Worker B picked 6 baskets in 2 hours.

The situation can be represented by the equations 24 = 4 x 6 and 24 = 6 x 2, where 24 represents the total number of baskets picked.

2. Another example is a classroom of students comparing the number of pencils each student has. In one row, there are 9 students and each student has 5 pencils. In another row, there are 5 students and each student has 9 pencils. This situation can be represented by the equations 45 = 9 x 5 and 45 = 5 x 9, where 45 represents the total number of pencils in each row.

3. A construction site is comparing the efficiency of two workers in terms of the number of bricks they can lay in a certain amount of time. Worker A can lay 3 bricks in 12 minutes, while Worker B can lay 12 bricks in 3 minutes. The situation can be represented by the equations 36 = 3 x 12 and 36 = 12 x 3, where 36 represents the total number of bricks laid.

4. A grocery store is comparing the size of two crates of oranges. Crate A contains 12 rows of oranges, with 5 oranges in each row. Crate B contains 5 rows of oranges, with 12 oranges in each row. This situation can be represented by the equations 60 = 12 x 5 and 60 = 5 x 12, where 60 represents the total number of oranges in each crate.

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Cynthia's older cousin sold her his collection of Pokemon cards. She paid him $9.50 and he charged her $0.10 per card. How many Pokemon cards did she buy?

Answers

95 because 10 cards is 1 dollar and so if she paid 9.50, the 9 dollars is 90cards and the 50¢ is 5cards so 95cards

Answer:

95$

Step-by-step explanation:

Choose one answer is math

Choose one answer is math

Answers

The correct answer is D

the answer is d which is x=.5x=-4

Create ABC by drawing AC. AC represents the foreman’s line of sight to the top of the landfill. What is m

Answers

Where the above is given, the required angle m∠BAC = 45°.

In triangle ABC. AC represents the foreman’s line of sight to the top of the landfill. Landfill height is BC

What is triangle?

The triangle is geometric shape which includes 3 sides and sum of interior angle should not grater than 180°

According to conditions angle b = 90°

The sum of angles of a triangle= 180°

That is a + b + c = 180

Therefore, c = a

       a = (180 - b)/2

          = (180 - 90) / 2

          = 90 / 2

          = 45°

Hence, the required angle m∠BAC = 45°

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Full Question:

Although part of your question is missing, you might be referring to this full question:

Question 1 Create Triangle ABC by drawing AC. Segment AC represents the foreman’s line of sight to the top of the landfill. What is Angle m BAC?

Alex is feeling stressed this morning. He did not get enough sleep because a dog barked most of the night. The dog barked from 11;41p.m. until 12:09 a.m.Then it started barking again at 3:35 a.m. and didn’t stop until 4:10 a.m.How long did the dog bark in all?

Answers

Answer:

Poor Alex, I know how they feel, I got a dog myself.

The amount of time between

11:41 pm to 12:09 am is

19 minutes (to 12 am, 60 minutes to next hour) + 9

which is 28 minutes for the first dog barking session

the second time is 35 minutes,

using same method as before.

adding the two separte barking sessions we get

35+28= 63 minutes

which is equivelant to 1 hour and 3 minutes.

In conclusion the dog barks for 1 hour and 3 minutes in total.

PROBLEM 3​: ​Sales tax in a certain community is 7%. If the sales tax on a new car was $1400, what was the selling price of the car? ​Rephrase: ​$1400 is 7% of what number?

Answers

Answer:

$20,000

Step-by-step explanation:

Let the new car price before tax be p.  If the sales tax was $1400, then the following is true:  0.07p = $1400, and p = $20,000

$1400 is 7% of the before-tax new car price, which is $20,000

2a2 + cb; a = 5, b = 11, and c = 3

Answers

Answer
53

Explanation

Calculate the product
20+3•11

Multiply the numbers
20+30

Add the numbers
53

Answer:

83 is the answer

Step-by-step explanation:

2*5^2+33

2*25+33

50+33=83

Which is more, 8 pints or 13 cups?

Answers

Answer:

8 pints

Step-by-step explanation:

A pint is 16 ounces = 2 cups

8 pints is then 16 cups

what would the method be???

what would the method be???

Answers

Answer:

The AA method

Step-by-step explanation:

The AA method states that if 2 of a triangle's angles are congruent to that of another triangle's 2 angles, then those triangles are similar.

AA because if 2 angles in one triangle are congruent to the other 2 angles in the second triangle, the triangle the third angle of both triangles must be equal because all angles in a triangle add up to be 180.

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The mass of a substance varies directly as the volume of the substance. If a mass of 30 kg of a substance has a volume of 6 liters, what is the volume of 65 kg of the substance?

Answers

Answer:

The volume of 65 kg of the substance is 13 liters.

Step-by-step explanation:

If a substance's mass varies directly from its volume, it means that the ratio of mass to volume remains constant. In this case, we can calculate the continuous ratio and then use it to find the volume.

Given:

Mass1 = 30 kg

Volume1 = 6 liters

Let's denote the constant ratio as k.

Mass1 / Volume1 = k

30 kg / 6 liters = k

k = 5 kg/liter

Now, we can find the volume2 for a mass of 65 kg using the constant ratio:

Mass2 = 65 kg

Volume2 = ?

Mass2 / Volume2 = k

65 kg / Volume2 = 5 kg/liter

To find Volume2, we can cross multiply:

65 kg = 5 kg/liter * Volume2

Volume2 = 65 kg / 5 kg/liter

Volume2 = 13 liters

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HELPP PLSS! its about US History What mass of sodium chloride is produced when chlorine gas reacts with 0.29 grams of sodium iodide? how do you write it out as a formula with Conversion factors? let their number of sides of a regular polygon is 6 in its radius is 5,then find the length of the side. Goal: Practice of software modeling using UML Consider the following use case specification for a use case called "Search Student" Search student Brief description: The actor receives results of students Actors: Participant Preconditions: The actor is a registered student Basic flow of events: 1. The actor logs into the system 2. The system authenticates the actor and starts a session 3. The actor chooses to search for student 4. The actor is guided by the system to fill the required criteria's to search for student 5. The actor receives results for student 6. The actor leaves the system Extensions: 1a. The system fails to authenticate the actor. The system informs the actor and doesn't allow the actor to proceed 3a. The system fails to search The system informs the actor Post-conditions: The system outputs results for the search of student Special requirements: Actor is connected to Internet and uses a Java enabled Mobile phone 1. Draw a class diagram for this use case (5 marks) 2. Draw a sequence diagram for this use case (5 marks) A video game club's members are asked to play three new games and order them from what they believe to be the best to the worst game scaling types most likely used are _____. (select all that apply.) Arrange the steps in order to describe what happens to a gas when it cools. The particles of gas move slower. The gas changes to a liquid. The gas loses thermal energy. The space between the gas particles decreases. What are the themes of the play a sunny morning? without secretin, enzymes that catalyze the breakdown of carbohydrates are active. T/F? helena cares deeply about hector, but does not feel any sexual attraction. hector, on the other hand, has feelings of great longing accompanied by physical arousal whenever helena is near. in this situation, helena is feeling love for hector, whereas hector, is feeling love for helena. group of answer choices fatuous; consummate companionate; passionate passionate; companionate consummate; companionate Aeuphemism is a figure of speech.ooTrueO False which of the following is not an example of cui cyber awareness challenge 1 Introduction In practicals you have implemented and learned about a number of algorithms and ADTs and will be implementing more of these in the remaining practicals. In this assignment, you will be making use of this knowledge to implement a system to explore and compare a variety of ADT implementations. Feel free to re-use the generic ADTs from your practicals. However, remember to self-cite; if you submit work that you have already submitted for a previous assessment (in this unit or any other) you have to specifically state this. Do not use the Python implementations of ADTs if in doubt, ask.2 The Problem This assignment requires the extension of your graph code to apply it to determining a preferred path through an area. In the example case, we will be looking at journeys across a university campus. The area will be represented as a weighted, directed graph, with nodes for locations and edges for the various ways to move between locations. For example, a preferred route may no longer be possible due to construction, a need to avoid stairs, or insufficient security access (affected by time of day). Your task is to build a representation of the world and explore the possible routes through the world and rank them. Sample input files will be available with various scenarios in terms of size and modifiers. Your program should be called whereNow.py, and have three starting options: No command line arguments : provides usage information "-i" : interactive testing environment (python whereNow[.py] i) "-s" : silent mode (python whereNow[.py] s infile journey savefile) When the program starts in interactive mode, it should show the following main menu:1 Introduction In practicals you have implemented and learned about a number of algorithms and ADTs and will be implementing more of these in the remaining practicals. In this assignment, you will be making use of this knowledge to implement a system to explore and compare a variety of ADT implementations. Feel free to re-use the generic ADTs from your practicals. However, remember to self-cite; if you submit work that you have already submitted for a previous assessment (in this unit or any other) you have to specifically state this. Do not use the Python implementations of ADTs if in doubt, ask.2 The Problem This assignment requires the extension of your graph code to apply it to determining a preferred path through an area. In the example case, we will be looking at journeys across a university campus. The area will be represented as a weighted, directed graph, with nodes for locations and edges for the various ways to move between locations. For example, a preferred route may no longer be possible due to construction, a need to avoid stairs, or insufficient security access (affected by time of day). Your task is to build a representation of the world and explore the possible routes through the world and rank them. Sample input files will be available with various scenarios in terms of size and modifiers. Your program should be called whereNow.py, and have three starting options: No command line arguments : provides usage information "-i" : interactive testing environment (python whereNow[.py] i) "-s" : silent mode (python whereNow[.py] s infile journey savefile) When the program starts in interactive mode, it should show the following main menu:then output the ranked paths to a file. Once you have a working program, you will showcase your program, and reflect on its performance. This investigation will be written up as The Report. Which situation can be represented by the equation x + 6 = 13?A. Two friends played 13 games of chess. One friend won 6 games.What is x, the number of games the other friend won?B. Ryder has 13 herb plants and 6 tomato plants in his garden. Whatis x, the total number of plants in Ryder's garden?C. Dorina ran 6 laps around the track at practice on Tuesday. OnThursday, she ran 13 laps. What is x, the total number of laps thatDorina ran?D. Zoltan spent $13 on a shirt and $6 on sunglasses. What is x, thetotal amount that he spent?SUBMIT f(X)=X^3 + 4 X^2-10=0 (between X=1 , X=2) Bisection methodplease fast :ARE X AND Y PROPORTIONAL? HOWDO YOU KNOW? EXPLAIN.A.B.3536 | 912302512341201510500 1 2 3 4 5 6 7 x question 3 question a student is setting up a model to study the carbon cycle and natural sources of carbon dioxide. they create a microenvironment that contains soil, leaf debris, an earthworm, heterotrophic bacteria, and a sun lamp. what natural source of carbon dioxide and major metabolic process was left out of the model? responses Point B is on line segment AC. Given BC =7 and AC = 11, determine the length AB Please help! What is the probability a customer ordered a small, given that he or she ordered a hot drink? answer has to be rounded to the nearest percentage. Please look at this photo A tent is set up for an outdoor market. One side of the tent is 9 feet tall. A rope of length p is attached to the top edge of the tent and is secured to the ground. The rope forms a 55 angle with the groundsin 550.82cos 550.57tan 551.432019 StrongMind Created using GeoGebraWhat is the approximate value of p, the length of the rope?O 10.9 feet7.3 feetO 7.4 feetO 11.0 feet559 ft. in the early romantic period, paris, france often featured __________ in which elements of an operatic production were meant to be spectacular and crowd pleasing. these operas would often contain large crowd scenes, amazing staging, ballet, etc. and were meant to impress.