Predict how many times you will roll a number less than 5 if you roll a standard number cube 100 times. Round to the nearest integer, if necessary. You will roll a number less than 5 about times.

The solution of the given system of equations 6x + 2y = 4 , 9x -3 y = 12 is equal to x =1 and y = -1.

As given in the question,

Given system of equations are :

6x + 2y = 4     ____(1)

 9x -3 y = 12   _____(2)

Multiply (1) by 3 and (2) by 2 and add equation (1) and  (2) to eliminate y variable and get the value of variable x ,

18x + 6y = 12

18x - 6y = 24

36x      = 36

⇒x = 36 / 36

⇒ x = 1

Substitute value of x = 1 in the given equation (1) to get the value of variable y,

6(1) + 2y = 4

⇒ 6 + 2y = 4

⇒ 2y = 4 - 6

⇒ y = -1

Therefore, given system of equations 6x + 2y = 4 , 9x -3 y = 12 solution is equal to x = 1 and y = - 1.

The above question is incomplete, the complete question is:

What is the solution of the system of equations 6x + 2y = 4 , 9x -3 y = 12?

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The values of the trigonometric functions ;

sin(theta) = √11/6

cos(theta) =  -5/6

tan(theta) = 5/√11

csc(theta) = 6/√11

sec(theta) = 6/5

Given cos (theta) = -5/6, and tan (theta) < 0, we can find sin(theta), cos(theta), tan(theta), csc(theta), and sec(theta).

First, we can use the fact that cot(theta) = cos(theta)/sin(theta) to find sin(theta) and cos(theta).

Next, we can use the fact that sin(theta) = cos(theta) to find the values of

Since cos (theta) = 15, we can write it as cos (theta) = adjacent/opposite, where adjacent = 15 and opposite = 1 (since cotangent is the reciprocal of tangent).

Using the Pythagorean theorem, we can find the hypotenuse:

adjacent= √(hypotenuse ² + opposite²) = √(6² - 5²) = √11

sin(theta) = √11/6

cos(theta) =  -5/6

tan(theta) = 5/√11

csc(theta) = 6/√11

sec(theta) = 6/5

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Write the equation of this line in point slope form the line passes through (-2,22) and (4,8)

step 1

Find the slope

m=(8-22)/(4+2)

m=-14/6

m=-7/3

step 2

Find the equation in point slope form

y-y1=m(x-x1)

we have

m=-7/3

if take the point (-2,22)

the equation is

If take the point (4,8)

the equation is

Step-by-step explanation:

This may help you

Thank you

As a result, the answer to the provided coordinate plane problem is only choice C), which is the right answer.

The term "coordinate plane" refers to a two-dimensional region that consists of two number lines. It emerges when the X-axis & Y-axis intersect at a location known as the origin. Using the numbers on a coordinate grid, one can locate points.

Here,

Since, If there is a coordinate plane with both parallel lines, go with option A.

Therefore, there is no cure.

There are hence a finite number of solutions that could be found.

If two lines cross, there is only one potential result for Option B. Consequently, the quantity of potential solutions is.

According to Option C, there must be an endless number of solutions to the system because there are two coinciding lines that provide us an infinite number of junction sites.

The difference between Option D) and Option B) is noted.

Only choice C) is hence the proper one.

Therefore , the solution to the given problem of coordinate plane comes out to be Only choice C) is hence the correct one.

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Answer:

Step-by-step explanation:

Answer:

22.6in³

Step-by-step explanation:

a = 800(0.7)^(150/15)

a = 800(0.7)^(10)

a = 22.6in³

Answer:

800(1-0.3)^5*2

Step-by-step explanation:

bright thinker confirmed

The total fixed expenses is $1401.96 if the Mortgage $1,034.78 Utility bill $168.34 Credit card $54.21 Groceries $98.75 Khakis (required for work) $45.88

It is defined as the money spends on the utility, the amount of money is required to buy something in other words it is the outflow of money from the solely earners income or the money incurred by any organization.

We have:

Types                                     Expense Amount

Mortgage                               $1,034.78

Utility bill                                 $168.34

Credit card                              $54.21

Groceries                                $98.75

Khakis (required for work)      $45.88

The total fixed expenses = $1,034.78+$168.34+$54.21+$98.75+$45.88

= $1401.96

Thus, the total fixed expenses is $1401.96 if the Mortgage $1,034.78 Utility bill $168.34 Credit card $54.21 Groceries $98.75 Khakis (required for work) $45.88

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Answer:

25

Step-by-step explanation:

5 squared equals 25. That is all you need to know in this case

Answer:2,860

Step-by-step explanation:

Answer: y=5x-11

Step-by-step explanation:

The value of the integral (9x + 9y) da over the region r is approximately 14.0625.

To evaluate the given integral using a transformation, we can use the concept of a double integral over a region in the xy-plane.

First, let's define the transformation T from the uv-plane to the xy-plane, where x = 9u and y = 9v. This transformation scales the coordinates by a factor of 9.

Next, let's find the Jacobian determinant of the transformation. The Jacobian determinant of T is given by the absolute value of the determinant of the matrix of partial derivatives of x and y with respect to u and v. In this case, the matrix is:

J(T) = |[∂x/∂u  ∂x/∂v]|
           |[∂y/∂u  ∂y/∂v]|

Taking the partial derivatives, we have:

∂x/∂u = 9   and   ∂x/∂v = 0
∂y/∂u = 0   and   ∂y/∂v = 9

Therefore, the Jacobian determinant is:

J(T) = |[9  0]|
           |[0  9]|

Taking the determinant, we have:

J(T) = (9)(9) - (0)(0) = 81

Now, we can evaluate the integral by transforming it into the uv-plane. The integral becomes:

∬(9x + 9y) dA = ∬(9(9u) + 9(9v))(J(T)) dA

Since x = 9u and y = 9v, we can substitute these expressions into the integral:

∬(9(9u) + 9(9v))(J(T)) dA = ∬(81u + 81v)(81) dA

Now, we need to find the limits of integration in the uv-plane. The region r in the xy-plane corresponds to a parallelogram in the uv-plane with vertices (-1/9, 2/9), (1/9, -2/9), (3/9, 0), and (1/9, 4/9).

Using these vertices, we can determine the limits of integration for u and v:

u ranges from -1/9 to 1/9
v ranges from 2/9 to 4/9

Therefore, the integral becomes:

∬(81u + 81v)(81) dA = ∫[u=-1/9 to 1/9] ∫[v=2/9 to 4/9] (81u + 81v)(81) dudv

Now, we can evaluate this double integral:

∫[u=-1/9 to 1/9] ∫[v=2/9 to 4/9] (81u + 81v)(81) dudv = (81)(81) ∫[u=-1/9 to 1/9] ∫[v=2/9 to 4/9] (u + v) dudv

Evaluating the inner integral with respect to u, we have:

(81)(81) ∫[u=-1/9 to 1/9] (1/2)u^2 + vu [v=2/9 to 4/9] dv

Simplifying further, we get:

(81)(81) ∫[u=-1/9 to 1/9] (1/2)u^2 + (vu)(4/9 - 2/9) dv

Now, we can evaluate the inner integral with respect to v:

(81)(81) ∫[u=-1/9 to 1/9] (1/2)u^2 + (vu)(4/9 - 2/9) dv = (81)(81) ∫[u=-1/9 to 1/9] (1/2)u^2 + (vu)(2/9) dv

Simplifying further, we have:

(81)(81) ∫[u=-1/9 to 1/9] (1/2)u^2 + (2/9)u(2/9) dv

Now, we can evaluate the inner integral with respect to v:

(81)(81) ∫[u=-1/9 to 1/9] (1/2)u^2 + (2/9)u(2/9) dv = (81)(81) ∫[u=-1/9 to 1/9] (1/2)u^2 + (4/81)u^2 du

Combining like terms, we get:

(81)(81) ∫[u=-1/9 to 1/9] (1/2 + 4/81)u^2 du

Simplifying further, we have:

(81)(81) ∫[u=-1/9 to 1/9] (85/162)u^2 du

Now, we can evaluate the integral:

(81)(81) ∫[u=-1/9 to 1/9] (85/162)u^2 du = (81)(81)(85/162) ∫[u=-1/9 to 1/9] u^2 du

Integrating u^2 with respect to u, we get:

(81)(81)(85/162) ∫[u=-1/9 to 1/9] u^2 du = (81)(81)(85/162) [u^3/3] from -1/9 to 1/9

Plugging in the limits of integration, we have:

(81)(81)(85/162) [(1/9)^3/3 - (-1/9)^3/3]

Simplifying further, we get:

(81)(81)(85/162) [(1/729)/3 - (-1/729)/3] = (81)(81)(85/162) [2/729]/3

Now, we can simplify this expression:

(81)(81)(85/162) [2/729]/3 = (81)(81)(85/162) (2/729)(1/3)

Finally, evaluating this expression, we get:

(81)(81)(85/162) (2/729)(1/3) ≈ 14.0625

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The Area of Trapezium is 50, 267 mm².

We have,

base 1 = 224 mm

base 2 = 77 mm

Height = 334 mm

Now, Area of Trapezium

= 1/2 (Sum of parallel side) x height

= 1/2 (224 + 77) x 334

= 1/2 x 301 x 334

= 50, 267 mm²

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Answer:

a) 2a

b) 7b-4

c) 3c+20

:))))))))))))))

This is an example of an experiment. In an experiment, researchers manipulate the independent variable (in this case, the presence or absence of an electrical impulse) to determine its effect on the dependent variable (the number of repetitions the subjects can lift a weight).

The researcher randomly assigned subjects to either receive the electrical impulse or not, which is a key feature of experimental design.

By doing so, the researcher can ensure that any differences observed between the two groups are due to the manipulation of the independent variable, rather than any pre-existing differences between the groups.

In contrast, an observational study merely observes existing characteristics or behaviors of a population, without any manipulation or control of variables.

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Given a function f(x,y) of two variables with the point (20,10) is a critical point, but it is not a local extremum.

According to the given information:

f(x = 20,y = 10)Let f_x(x,y) and f_y(x,y) be the partial derivatives of f(x,y) with respect to x and y, respectively.

\(f_x(x,y) = f(x,y)\\dx/dt|_y=yf_y(x,y) \\\= f(x,y)dy/dt|_x=xAt (x=20,y=10), f_x(20,10) = 0, \\f_y(20,10) = 0.\)

Thus, (20,10) is a critical point of f(x,y) or stationary point.  Now, let f_xx, f_yy, and f_xy be the second-order partial derivatives of f(x,y) at (x,y).f_xx(x,y) = d^2f/dx^2|_y=yf_yy(x,y) = d^2f/dy^2|_x=xf_xy(x,y) = d^2f/dxdy|_x=xf_xx(20,10) = -2, f_yy(20,10) = -5 and f_xy(20,10) = 3. The Hessian matrix of f at (20,10) is given by:

Hessian(f)(20,10) = \([f_xx(20,10) f_xy(20,10); f_xy(20,10) f_yy(20,10)] = [-2 3; 3 -5]\)

The discriminant of the Hessian matrix is given by \(D = f_xx(x,y)f_yy(x,y) - f_xy(x,y)^2\)

Here, D = (-2)(-5) - (3)^2 = 4 > 0Since D > 0 and f_xx(20,10) < 0, the point (20,10) is a saddle point. Therefore, the point (20,10) is a critical point but it is not a local extremum.

Hence, the answer is: Yes, the point (20,10) is a critical point, but it is not a local extremum.

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a) The median would be larger than the mean because the life expectancy of some countries may be much lower than the others, thus affecting the mean.

b) The median should be reported as it is a better measure of central tendency, as it is not affected by outliers.

a) The median is expected to be larger than the mean because the life expectancy of some countries may be much lower than the others, thus affecting the mean. The mean is calculated by adding all the values together and dividing by the number of values, and if there are any values that are much lower or higher than the rest, this will affect the mean significantly. The median, however, is the midpoint of the values, so outliers have less of an influence on it.

b) The median should be reported as it is a better measure of central tendency, as it is not affected by outliers. The median is the midpoint of the values, which means that if there are any values that are much lower or higher than the rest, it will not affect the median as much as it does the mean. This makes the median more accurate in representing the life expectancy of countries, as it is not skewed by outliers. Furthermore, the median is generally more reliable when dealing with skewed distributions, which is often the case with life expectancy data.

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1 sequence of outcomes that contains all doubles when two identical dice are rolled n successive times.

There are 6 possible doubles that can be rolled on a pair of dice (1-1, 2-2, 3-3, 4-4, 5-5, 6-6).

Let's consider the probability of rolling a double on a single roll:

The probability of rolling any specific double (such as 2-2) on a single roll is 1/6 × 1/6 = 1/36 since each die has a 1/6 chance of rolling the specific number needed for the double.

The probability of rolling any double on a single roll is the sum of the probabilities of rolling each specific double is 1/36 + 1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 1/6.

Let's consider the probability of rolling all doubles on n successive rolls. Since each roll is independent the probability of rolling all doubles on a single roll is (1/6)² = 1/36.

The probability of rolling all doubles on n successive rolls is (1/36)ⁿ.

The number of sequences of outcomes that contain all doubles need to count the number of ways to arrange the doubles in the sequence.

There are n positions in the sequence, and we need to choose which positions will have doubles.

There are 6 ways to choose the position of the first double 5 ways to choose the position of the second double (since it can't be in the same position as the first) and so on.

The total number of sequences of outcomes that contain all doubles is:

6 × 5 × 4 × 3 × 2 × 1 = 6!

This assumes that each double is different.

Since the dice are identical need to divide by the number of ways to arrange the doubles is also 6!.

The final answer is:

6!/6! = 1

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A linear-quadratic state estimator and a particle filter are both estimation techniques used in control systems, but they differ in their underlying principles and application domains.

A linear-quadratic state estimator, often referred to as a Kalman filter, is a widely used optimal estimation algorithm for linear systems with Gaussian noise. It assumes linearity in the system dynamics and measurements. The Kalman filter combines the predictions from a mathematical model (state equation) and the available measurements to estimate the current state of the system. It provides a closed-form solution and is computationally efficient. However, it relies on linear assumptions and Gaussian noise, which may limit its effectiveness in nonlinear or non-Gaussian scenarios.

On the other hand, a particle filter, also known as a sequential Monte Carlo method, is a non-linear and non-Gaussian state estimation technique. It employs a set of particles (samples) to represent the posterior distribution of the system state. The particles are propagated through the system dynamics and updated using measurement information. The particle filter provides an approximation of the posterior distribution, allowing it to handle non-linearities and non-Gaussian noise. However, it is computationally more demanding than the Kalman filter due to the need for particle resampling and propagation.

The choice between a linear-quadratic state estimator and a particle filter depends on the characteristics of the system and the nature of the noise. The Kalman filter is suitable for linear and Gaussian systems, while the particle filter is more versatile and can handle non-linearities and non-Gaussian noise. However, the particle filter's computational complexity may be a limiting factor in real-time applications.

In summary, a linear-quadratic state estimator (Kalman filter) is a computationally efficient estimation technique suitable for linear and Gaussian systems. A particle filter, on the other hand, provides more flexibility by accommodating non-linearities and non-Gaussian noise but requires more computational resources. The choice between these methods depends on the specific system characteristics and the desired accuracy-performance trade-off.

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Note that:

Applying the addition formula given above to cos 150:

The x-terms in the system of equations are eliminated as follows:

The system of equations in the context of this problem is defined as follows:

To solve the system, we use the elimination method, as we want to eliminate the variable x.

The least common factor of 3 and 2 is of 6, hence:

Hence the variable x is eliminated as follows:

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Answer:

140 units^2

Step-by-step explanation:

Area of a parallelogram is base times height, A = bh. Multiply the height (10) times the base (14) to get your final answer.

A = bh

A=14(10)

A=140units^2

Answer:

1. x=10; y=10 x root 2

Step-by-step explanation:

This is a 45-45-90 triangle, so the legs of the right triangle have an equal length. The formula states that y=x root 2, which is 10, so 10 root 2. The other triangles are all 30-60-90 triangles.

Answer:

86

Step-by-step explanation:

Answer:

yes that's possible for example -3-5=-8

Answer: D trust me it is 100

Step-by-step explanation:

The maximum area the goat can graze is 100Tt ft2​, the correct option is D.

Given

A goat is tethered to a rope that is 10 ft. long.

The area of the circle is equal to the pie times of the square of the radius of the circle.

The maximum area that the goat can graze in the area of the circle that can be formed due to its circular movement.

The length of the rope represents the radius of the circle, so that;

\(\rm Area \ the \ goat \ can \ graze =r^2 \times Tt\\\\ Area \ the \ goat \ can \ graze =(10)2 \times Tt\\\\Area \ the \ goat \ can \ graze =100 \ Tt\\\)

Hence, the maximum area the goat can graze is 100Tt ft2​.

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The null hypothesis has been true but the sample information has resulted in the rejection, when the Type I error has been made

The null hypothesis is that two possibilities are the same. The null hypothesis is that the observed difference is due to chance alone.

A type I error occurs if an investigator rejects a null hypothesis that is actually true in the population.
Hence, the null hypothesis has been true but the sample information has resulted in the rejection, when the Type I error has been made

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Answer:

Yes, the area would be 12 centimeters.

The perimeter would be 14 centimeters.

Hope this helps :)