Problem #8: Let f(x, y,-) = yz/x. Find the value of the following partial derivatives. (a) f(3,4,4) (b) f,(4,4, 2) (C) (2,2,4) Problem #8(a): Enter your answer symbolically, as in these examples

Answers

Answer 1

The value of the partial derivatives are:

(a) f(3,4,4) = 16/3

(b) f,x(4,4,2) = -1/8

(c) f,y(2,2,4) = 2

Let's understand

(a) To find f(3,4,4), simply substitute x = 3, y = 4, and z = 4 into the formula for f(x,y,z):

f(3,4,4) = (4 * 4) / 3 = 16/3

(b) To find the partial derivative of f with respect to x at the point (4,4,2), we need to hold y and z constant and differentiate f(x,y,z) with respect to x:

f,x(4,4,2) = -4*(2/4²) = -1/8

(c) To find the partial derivative of f with respect to y at the point (2,2,4), we need to hold x and z constant and differentiate f(x,y,z) with respect to y:

f,y(2,2,4) = 4/2 = 2

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Related Questions

HELPPPPP
An expression that is equivalent to this expression 7(6 + y)

Answers

Answer:

42 + 7y

Step-by-step explanation:

Just multiply what's in the brackets by the outside number (PEMDAS).

Suppose that a deck of 52 cards contains 26 red cards and 26 black cards (and assume the red cards are numbered 1 to 26, and so are the black cards). Say we use the 52 cards to randomly distribute 13 cards each among two players (2 players receive 13 card each). a. How many ways are there to pass out 13 cards to each of the two players? b. What is the probability that player 1 will receive 13 cards of one color and player 2 receive 13 cards of the other color?

Answers

(A) the number of ways to pass out 13 cards to each of the two players is (52! / (13! × 13!)) × (39! / (26! × 13!)) (B) We can calculate probability by dividing the number of favorable outcomes by the total number of possible outcomes. (26! / (13! × 13!))²] / [(52! / (13! × 13!)) × (39! / (26! × 13!))]

A) To determine the number of ways to distribute 13 cards to each of the two players, we can use the concept of combinations. Since the order of distribution does not matter, we'll use the formula for combinations:

C(52, 13) × C(39, 13)

= (52! / (13! × (52 - 13)!)) × (39! / (13! × (39 - 13)!))

Simplifying this expression:

= (52! / (13! × 39!)) × (39! / (13! × 26!))

= (52! / (13! × 13! × 26!)) × (39! / (26! × 13!))

= (52! / (13! × 13! × 26!)) × (39! / (26! × 13!))

= (52! / (13! × 13!)) × (39! / (26! × 13!))

Therefore, the number of ways to pass out 13 cards to each of the two players is (52! / (13! × 13!)) × (39! / (26! × 13!)).
B) To calculate the probability that player 1 will receive 13 cards of one color and player 2 will receive 13 cards of the other color, we need to find the favorable outcomes and divide it by the total number of possible outcomes.
The favorable outcome is when player 1 receives 13 cards of one color and player 2 receives 13 cards of the other color.
For player 1 to receive 13 red cards, there are C(26, 13) ways, and for player 2 to receive 13 black cards, there are C(26, 13) ways.

Therefore, the number of favorable outcomes is C(26, 13) ×C(26, 13).
The total number of possible outcomes is the same as the answer to part A, which is C(52, 13) × C(39, 13).
Finally, we can calculate the probability by dividing the number of favorable outcomes by the total number of possible outcomes.

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There are approximately \(6.54 \times 10^{11}\) ways to distribute 13 cards to each of the two players, and the probability that player 1 will receive 13 cards of one color and player 2 will receive 13 cards of the other color is approximately 0.76%.

a. To determine the number of ways to pass out 13 cards to each of the two players, we can use the concept of combinations. We need to select 13 cards out of the total 52 cards for the first player, and then the remaining 13 cards will automatically go to the second player. The number of ways to choose 13 cards out of 52 is given by the combination formula: \(52_C_{13} = \frac{52!}{(13!(52-13)!)}\). Evaluating this expression, we find that there are approximately \(6.54 \times 10^{11}\) ways to distribute the cards.

b. The probability that player 1 will receive 13 cards of one color and player 2 will receive 13 cards of the other color depends on the specific color that each player receives. Let's consider the case where player 1 receives all red cards and player 2 receives all black cards. There are 26 red cards and 26 black cards, so the probability of player 1 receiving all red cards is given by: \(\frac{26_C_{13} \times 26_C_0}{52_C_{13}}\). Evaluating this expression, we find that the probability is approximately 0.0076, or 0.76%.

In conclusion, there are approximately \(6.54 \times 10^{11}\) ways to distribute 13 cards to each of the two players, and the probability that player 1 will receive 13 cards of one color and player 2 will receive 13 cards of the other color is approximately 0.76%.

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a nations population could still decline rapidly even if there are no deaths. true or false

Answers

False. A nation's population cannot decline rapidly if there are no deaths.

The population of a nation is determined by the balance between births, deaths, and migration. If there are no deaths occurring within a population, the only factor that can lead to population decline are a decrease in birth rates or significant emigration.

Population decline occurs when the number of births is lower than the number of deaths or when a large number of individuals leave the country. In such cases, the population may experience a decline even without deaths. However, it is important to note that in natural circumstances, a declining population typically involves a combination of factors including low birth rates, high death rates, and/or significant emigration. Simply having no deaths is not sufficient to cause a rapid decline in a nation's population.

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You created a circle with a center at point E that passed through point A, then the length of the radius would also be equal to which segments? Select all that apply

Answers

If a circle with center E passes through point A, then the length of the radius would be equal to segments EA and AE.In a circle, the radius is a line segment that connects the center of the circle to any point on

the circle. In this case, the center of the circle is point E, and the circle passes through point A. Therefore, the line segments EA and AE would both be equal to the radius of the circle. Segment EA represents the line segment from point E to point A, while segment AE represents the line segment from point A to point E. Since both segments connect the center of the circle (point E) to a point on the circle (point A), they would have the same length as the radius. It's important to note that the length of the radius remains constant throughout the circle. Regardless of which point on the circle is chosen, the line segment connecting that point to the center will always be equal to the radius. This property holds true for any circle, not just the specific scenario mentioned in the question. Therefore, in the given scenario, the segments EA and AE would be equal in length and would both represent the radius of the circle.

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What is the sum of 1\2 + 1\6

Answers

the correct answer is 2/3

now, let's consider the effects of time dilation. how far would the pion actually travel before decaying?

Answers

To get the number of half-lives passed, we divide the time of flight from part a by the length of a half-life, as

given in the statement of the problem:

Number of half lives = 2×10−4

1.5×10−6 ≈ 133

The fraction of remaining muons will decrease by 1/2

every half life, so the fraction after a given number N of

half-lives will be:

1/2 × 1/2 × 1/2

· · · N times · · · × 1/2 = ( 1/2)N .

This makes the fraction remaining equal to 1/2 to the power 133:

fraction remaining = ( 1/2)

133 ≈ 10−40. That’s not very many muons

First-generation quarks are what make up pions, which are mesons with no spin. An anti-down quark and an up quark are described in the quark model. In addition to vector, rho, and omega mesons, the exchange of virtual pions also explains why there is still a strong interaction between nucleons. Pions are typically created in high-energy collisions between hadrons and are not created during radioactive decay. In some matter-antimatter annihilation processes, pions are also produced.

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Note that the full question is:

Ne of the many fundamental particles in nature is the muon mu. This particle acts very much like a "heavy electron." It has a mass of 106 MeV/c^2, compared to the electron's mass of just 0.511 MeV/c^2. (We are using E = mc^2 to obtain the mass in units of energy and the speed of light c).Unlike the electron, though, the muon has a finite lifetime, after which it decays into an electron and two very light particles called neutrinos (nu). We'll ignore the neutrinos throughout this problem.

If the muon is at rest, the characteristic time that it takes it to decay is about 2.2 microseconds. Most of the time, though, particles such as muons are not at rest and, if they are moving relativistically, their lifetimes are increased by time dilation. In this problem we will explore some of these relativistic effects.

Cosmic rays are constantly raining down on the earth from outer space. (Figure 1)The majority of these cosmic rays are protons, and when upper atmosphere, they can convert into particles called pions (), which subsequently decay into muons with a characteristic lifetime of T.

Suppose that a cosmic-ray proton crashes into a nitrogen molecule in the upper atmosphere. 45 km above the earth's surface, producing a pia a muon. Assume that the pion has a velocity of 99.99% the speed of light and decays into a muon, which, owing to kinematics, has a downward velocity of 99.9943% the speed of light.

now let’s consider the effect of time dilation how far would the pion actually travel before decaying?

One-third of the students in Mrs. Hayko's class walk to school. Of the students who do not walk to school, four-fifths take the bus.

a.) What fraction of the students in Mrs. Hayko's class take the bus to school?

b.) How many students might be there in her class?​

Answers

Answer:

The possible number of students in Mrs. Hayko's class is limited to 15 or 30, as higher multiples of 15 would exceed the desired class size.

Step-by-step explanation:

a)

Let 'x' be the total number of students in Mrs. Hayko's class.

One-third of the students walk to school: (1/3)x.

The remaining students who do not walk to school: (2/3)x.

Four-fifths of the non-walking students take the bus: (4/5) * (2/3)x.

Simplify to find the fraction of students taking the bus: (8/15)x.

b)

Consider different values for 'x' to find a whole number of students taking the bus.

Start with a small number, such as x = 15.

Calculate the number of students taking the bus using (8/15)x.

If the result is a whole number, it's a possible class size.

Repeat with different values of 'x' until a whole number is obtained.

The possible number of students in Mrs. Hayko's class could be 15, 30, or any other multiple of 15.

In the Venn Diagram for an EIO - 2 Categorical Syllogism, there is an X in number 6.
Group of answer choices
True
False

Answers

The answer is True. In the Venn Diagram for an EIO - 2 Categorical Syllogism, X represents the area of the diagram where the subject of the conclusion statement (the term in the predicate of the minor premise) overlaps with the complement of the predicate of the major premise.

In a EIO syllogism, the conclusion statement is negative and particular, meaning that it denies the existence of some members of the subject class. This area of the diagram is represented by number 6. Therefore, there should be an X in number 6 of the Venn Diagram for an EIO - 2 Categorical Syllogism.


In the Venn Diagram for an EIO-2 Categorical Syllogism, there is an X in number 6. The statement is true. An EIO-2 Categorical Syllogism consists of a negative major premise, a negative minor premise, and a negative conclusion. In a Venn Diagram, an "X" represents an instance where the two categories overlap, and number 6 is the area where the two categories overlap negatively. So, in this case, the presence of an X in number 6 indicates the truth of the EIO-2 Categorical Syllogism.

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what is the product of 1.2 and 3.4?

Answers

Question

what is the product of 1.2 and 3.4?

Answer: 1.2 * 3.4

there fore answer is  4.08

mark me brainliest  and thanks

have a good day ahead...

: )

The senior classes at High School A and High School B planned separate trips to the local amusement park. The senior class at High School A rented and filled 13 vans and 5 buses with 370 students. High School B rented and filled 12 vans and 10 buses with 600 students. Every van had the same number of students in it as did the buses. Find the number of students in each van and in each bus.


please show you work

Answers

Answer:

10 students/van

48 students/bus

Step-by-step explanation:

(a) 13v+5b = 370

(b) 12v+10b = 600

(a) - (b)

v -5b = -230

v = 5b-230

12(5b-230) + 10b = 600

60b+10b -2760=600

70b=3360

7b=336

b=48

v = 5(48) - 230 = 10

v = 10

Let's check

12(10) +10(48) = 600

The first five terms of a pattern are shown.
3/100, 3/10, 3, 30, 300.........
Which expression can be used to find the nth term?
OA. (3/10)^n-3
OB. (3/100)^n
OC. 3(10)^n-3
OD. 3(10)^n

Answers

Answer:

C

Step-by-step explanation:

There is a common ratio between consecutive term in the sequence, that is

\(\frac{3}{10}\) ÷ \(\frac{3}{100}\) = 3 ÷ \(\frac{3}{10}\) = 30 ÷ 3 = 300 ÷ 30 = 10

This indicates the sequence is geometric with n th term

\(a_{n}\) = a\((r)^{n-1}\)

where a is the first term and r the common ratio

Here a = \(\frac{3}{100}\) and r = 10 , thus

\(a_{n}\) = \(\frac{3}{100}\) \((10)^{n-1}\)

    = \(\frac{3}{10^{2} }\) × \(10^{n-1}\)

    = 3 × \(10^{-2}\) × \(10^{n-1}\)

    = 3 × \(10^{n-3}\)

Thus

\(a_{n}\) = 3\((10)^{n-3}\) → C

Answer: C

I got it right !

Step-by-step explanation:

Find the area of the semi circle with a radius of 2 feet

Answers

Answer:

area of semi circle πr=π×2=44/7 feet²

Alfred delivers 10 to the power of 2 newspapers every week. How many does he deliver in 14 weeks?

Answers

Answer:

1400

Step-by-step explanation:

10² is 100 so 100*14 is 1400

What is the perimeter? 3 mi. Il mi.​

Answers

Perimeter = 2(3 mi + 1 mi) = 8 miles.

What is coefficient?

A coefficient is a numerical factor that is multiplied by a variable or a term in an algebraic expression. In mathematics, coefficients are commonly used in polynomial functions, where they determine the degree of the polynomial and the specific values of the function.

For example, in the polynomial function \(f(x) = 3x^2 + 2x - 1\), the coefficients are 3, 2, and -1. The coefficient 3 is multiplied by the variable \(x^2\), the coefficient 2 is multiplied by the variable x, and the coefficient -1 is the constant term.

by the question.

If you are referring to a rectangle, then the perimeter would be:

Perimeter = 2(length + width)

Assuming the 3 mi and 1 mi are the length and width respectively, then the perimeter would be:

Perimeter = 1 mile + 1 mile + unknown length of the third side

Perimeter = 2(3 mi + 1 mi) = 8 miles

perimeter = 8 mi.

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Complete question -

Find the perimeter of following -

3 mi. 1l mi.​

3 3/4÷3/4
pls I need this for my tuition in 5 min

Answers

Step-by-step explanation:

15/4÷3/4

15/4×4/3 (2 reciprocal of 3 upon 4)

5/1

or 4 1/1 Answer

4,4 will be cancelled 15 will be cancelled by 3

(x-5)^2-1=0
tìm x giúp mik vs

Answers

X= 6 and X=4 ☺️, have a good day
(x-5)^2-1=0tm x gip mik vs

Write the formula for finding the
area of a parallelogram.

Answers

Answer:

A = B * H 

Step-by-step explanation:

B is the base, H is the height, and * means multiply

you are testing h0: μ=10 against ha: μ≠10 based on an srs of 15 observations from a normal population. what values of the t statistic are statistically significant at the α=0.005 level?

Answers

The values of the t statistic that are statistically significant at the α=0.005 level are t < -2.977 or t > 2.977.

To determine the values of the t statistic that are statistically significant at the α=0.005 level, we need to find the critical values of the t-distribution with 14 degrees of freedom (df = n - 1 = 15 - 1 = 14).

Using a t-table or a calculator, we can find that the critical values for a two-tailed test with α=0.005 are -2.977 and 2.977. This means that any t statistic less than -2.977 or greater than 2.977 would be considered statistically significant at the α=0.005 level.

In other words, if the calculated t statistic falls within the range of -2.977 to 2.977, we would fail to reject the null hypothesis (H0: μ=10) and conclude that there is not enough evidence to suggest that the population mean is different from 10. However, if the calculated t statistic falls outside of this range, we would reject the null hypothesis and conclude that there is evidence to suggest that the population mean is different from 10.

So, the values of the t statistic that are statistically significant at the α=0.005 level are t < -2.977 or t > 2.977.

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I need some explanation on how to do piece wise functions? Where do I even start with this equation, can you explain this step by step? Including breaking down the graphing of absolute functions?

I need some explanation on how to do piece wise functions? Where do I even start with this equation,
I need some explanation on how to do piece wise functions? Where do I even start with this equation,
I need some explanation on how to do piece wise functions? Where do I even start with this equation,

Answers

A piecewise function is basically a function that behaves differently at different domain intervals.

The given piecewise function is

\(\begin{cases}2x\quad \quad \quad \quad \quad \quad x\le3 \\ \frac{1}{3}x^2-2x+9\quad x>3\end{cases}\)

As you can see, the function has a different expression for the interval x is less than or equal to 3 and a different expression for the interval x is greater than 3.

The easiest way to determine which graph corresponds to the given piecewise function is to evaluate the piecewise function at different values of x and graph it.

Evaluate the piecewise function for the interval x is less than or equal to 3.

\(\begin{gathered} 2x \\ x=1\rightarrow2(1)=2 \\ x=2\rightarrow2(2)=4 \\ x=3\rightarrow2(3)=6 \end{gathered}\)

Evaluate the piecewise function for the interval x is greater than 3.

\(\begin{gathered} \frac{1}{3}x^2-2x+9 \\ x=4\rightarrow\frac{1}{3}(4)^2-2(4)+9=6.33 \\ x=6\rightarrow\frac{1}{3}(6)^2-2(6)+9=9 \\ x=8\rightarrow\frac{1}{3}(8)^2-2(8)+9=14.33 \end{gathered}\)

Now, let us graph these points

As you can see from the graph, it matches with the graph of the 2nd option.

Therefore, the correct graph of the given piecewise function is the 2nd graph.

I need some explanation on how to do piece wise functions? Where do I even start with this equation,
I need some explanation on how to do piece wise functions? Where do I even start with this equation,

where Eſe|X] = 0. (a) What is Var(e|X)? (b) What is the asymptotic variance of your OLS estimator of ß? (c) How will you estimate this variance?

Answers

To estimate this variance, we can use the formula Var(ß) = MSE(X'X)^(-1) where MSE is the mean squared error obtained from the OLS regression.

If E[e|X] = 0, then we know that the OLS estimator of ß is unbiased.

The variance of e|X is denoted as Var(e|X) and is equal to σ² where σ is the standard deviation of the error term.

The asymptotic variance of the OLS estimator of ß is denoted as Var(ß) and is given by the formula Var(ß) = σ²(X'X)^(-1) where X is the matrix of predictors and (X'X)^(-1) is the inverse of the matrix X'X.

 Alternatively, we can use the residual standard error (RSE) to estimate σ and then use the formula Var(ß) = RSE²(X'X)^(-1).

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How many hex digits are required to represent decimal numbers up to 1,999? how many bits are required?

Answers

To determine the number of hex digits required to represent decimal numbers up to 1,999, we need to find the largest decimal number within that range and convert it to hexadecimal representation.

The largest decimal number within the range is 1,999. To convert it to hexadecimal, we divide it by 16 repeatedly until the quotient is 0, and then concatenate the remainders in reverse order.

1,999 divided by 16 gives a quotient of 124 and a remainder of 15 (F in hexadecimal representation).

124 divided by 16 gives a quotient of 7 and a remainder of 12 (C in hexadecimal representation).

7 divided by 16 gives a quotient of 0 and a remainder of 7 (7 in hexadecimal representation).

Thus, 1,999 in hexadecimal representation is 7CF. It requires three hex digits (7, C, F) to represent 1,999.

To calculate the number of bits required, we need to know the number of bits in one hex digit. Since each hex digit represents 4 bits, three hex digits would represent 3 * 4 = 12 bits.

Therefore, to represent decimal numbers up to 1,999, three hex digits are required, and it would take 12 bits.

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Solve y3 = −8. Please help im desperate

Answers

Answer:

-2

Step-by-step explanation:

y^3=-8.

y=cube root of -8 = -2

Which of the following represents The linear equation 3x+y=2 in slope-intercept form

Select one:
A. y−2=−3x
B. y=−13x−2
C. y=−3x+2
D. y=3x+2

Answers

C, see explanation in the picture attached below.
Which of the following represents The linear equation 3x+y=2 in slope-intercept formSelect one:A. y2=3xB.

Which linear relationship can be described as a function with direct variation?

Which linear relationship can be described as a function with direct variation?

Answers

Answer:

A, B , C and D

Step-by-step explanation:

Answer:

the answer is b

Step-by-step explanation:

(6) Let A be an n x n matrix and consider the linear homogeneous system Ar = 0. If the linear system has only the trivial solution state whether the following statements are true or false. (a) 0 is an eigenvalue of A (b) All columns of A are basic columns. (c) Rank of A is n. [1]

Answers

The statements are:

(a) False, (b) True, (c) True.

(a) False.

If the linear homogeneous system Ar = 0 has only the trivial solution, it means that the only solution is r = 0. This implies that the matrix A does not have a non-zero eigenvector associated with the eigenvalue 0. Therefore, 0 is not an eigenvalue of A.

(b) True.

If the linear homogeneous system Ar = 0 has only the trivial solution, it implies that the columns of A are linearly independent. Linearly independent columns are considered basic columns in the context of matrices. Therefore, all columns of A are basic columns.

(c) True.

If the linear homogeneous system Ar = 0 has only the trivial solution, it implies that the rank of the matrix A is equal to the number of columns, which is n. The rank of a matrix is the maximum number of linearly independent rows or columns in the matrix. Since all columns of A are linearly independent in this case, the rank of A is n.

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12)50 students took a quiz with five questions. The frequency table below shows the results of the quiz. Use the frequency table to answer the following questions. ValueFrequencyRelative FrequencyCumulative Frequency040.084180.1612260.1218320.04204150.3355150.350a)How many students answered exactly 3 questions correctly?Number of students answered exactly three questions = 2b)How many students answered less than 3 questions correctly?c)What proportion (percent) of students answered exactly 4 questions correctly?

12)50 students took a quiz with five questions. The frequency table below shows the results of the quiz.

Answers

Explanation

From the table, we have:

• The first column (Value),: indicates the # of correct answers,

,

• The second column (Frequency),: indicates the # of students that answer the # of correct answers to the left in the table,

,

• The third column (Relative Frequency),: indicates the proportion of the # of students to the total,

,

• The fourth column (Cumulative Frequency),: gives the sum of the previous frequencies up to that row.

Using these data, we answer the questions:

a) Looking at the column Frequency for Value = 3, we find that 2 students answered exactly 3 answers correct.

b) Looking at the column Cumulative Frequency for Value = 2 (the previous value to 3), we find that 18 students answered less than 3 questions correctly.

c) Looking at the column Relative Frequency for Value = 4, we find that 0.3 = 0.3 * 100% = 30% of the students answered exactly 4 questions correctly.

Answer

a) 2

b) 18

c) 30%

Frank was trying to simplify the following expression 43+3. Sarah said to add 3 to both the top and the bottom of the fraction. Gwen said to
just add three to the top of the fraction. Which person is correct? What is the value of the expression?
cor
correct. The value of the expression is
V

Answers

Gwen is correct. The expression 43 + 3 can be written as 43/1 + 3/1

What is an Algebraic Expression?

In most cases, something is said to be equivalent if two of them are the same. Similar to this, analogous expressions in mathematics are those that, despite their differences in appearance, have the same meaning. The two expressions, however, produce the identical outcome when the values are inserted into them.

Gwen is correct. The expression 43 + 3 can be written as 43/1 + 3/1. To simplify, you can add the numerators (43 + 3) and keep the denominator the same (1). So the simplified expression is 46/1, which is equal to 46.

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has mean 20.2 years and standard deviation 1.60 years. of all of those enrolled in the course, 54 percent are men and 46 percent are women. what is the mean age of the combined distribution of both men and women in the course?

Answers

The mean age of the combined distribution of both men and women in the course is 20.47 years

What is average/mean ?

The middle number, which is determined by dividing the sum of all the numbers by the total number of numbers, is the average value in mathematics. When determining the average for a set of data, we add up all the values and divide this sum by the total number of values.

Mean age of men , M = 20.7 years

Mean age of Women , W = 20.2 years

Percentage of Men = 54%

Percentage of Women = 46%

Recall, :

Mean, μ = np

The mean age of men in the distribution = (20.7 × 54%) = 11.178 years

The mean age of women in the distribution = (20.2 × 46%) = 9.292 years

The mean age of the combined distribution is :

11.178 + 9.292 = 20.47 years

Therefore, the mean age of the combined distribution is 20.47 years

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An isosceles triangle in which the two equal sides, labeled a, are longer than the base, labeled b.
This isosceles triangle has two sides of equal length, a, that are longer than the length of the base, b. The perimeter of the triangle is 15.7 centimeters. The equation can be used to find the side lengths.

If one of the longer sides is 6.3 centimeters, what is the length of the base?

cm

Answers

If one of the longer sides of the Isosceles triangle is 6.3 centimeters, the length of the base is 3.1 centimeters.

Let's solve the problem step by step:

1. Identify the given information:

  - The triangle is isosceles, meaning it has two equal sides.

  - The two equal sides, labeled "a," are longer than the base, labeled "b."

  - The perimeter of the triangle is 15.7 centimeters.

  - One of the longer sides is 6.3 centimeters.

2. Set up the equation based on the given information:

  Since the triangle is isosceles, the sum of the lengths of the two equal sides is twice the length of the base. Therefore, we can write the equation:

  2a + b = 15.7

3. Substitute the known value into the equation:

  One of the longer sides is given as 6.3 centimeters, so we can substitute it into the equation:

  2(6.3) + b = 15.7

4. Simplify and solve the equation:

  12.6 + b = 15.7

  Subtract 12.6 from both sides:

  b = 15.7 - 12.6

  b = 3.1

5. Interpret the result:

  The length of the base, labeled "b," is found to be 3.1 centimeters.

Therefore, if one of the longer sides of the isosceles triangle is 6.3 centimeters, the length of the base is 3.1 centimeters.

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PLEASE HELP MARKING BRAINLEIST JUST ANSWER ASAP

PLEASE HELP MARKING BRAINLEIST JUST ANSWER ASAP

Answers

Answer:

The perimeter is the sum of all the sides of the rectangle. So, adding up all the given sides, we get:

Perimeter = 2u + u + 10 + u + 10 + 8u

Simplifying the expression by combining like terms, we get:

Perimeter = 12u + 20

Therefore, the simplified answer for the perimeter is 12u + 20.

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