Propane (C3H8) is a fuel commonly burned for needs such as home heating and cooking food. When propane burns, it reacts with oxygen (O2). The products of the reaction are carbon dioxide (CO2) and water (H2O). If 44.1 g of propane react completely with 160.0 g of oxygen, 132.0 g of carbon dioxide are formed. What is the mass of the other product, water, formed in this reaction?

Adding ice to the liquid decreases the average kinetic energy of the particles of the liquid.

The temperature of a substance is defined as a measure of the average kinetic energy of the molecules of the substance. The average kinetic energy of the molecules of a substance is directly proportional to the temperature of the substance.

This implies that if I increase the temperature of a substance, the average kinetic energy of the molecules of the substance increases and vice versa.

Ice is at a lower temperature than water at room temperature. Thus, adding ice to water at room temperature decreases the temperature of the water and consequently decreases the average kinetic energy of its particles.

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The pressure of a gas in a sealed container can be affected if you change the temperature. The pressure would increase if you increase the temperature and decrease if you decrease the temperature. Therefore, it can be said that the pressure of a gas in a sealed container is directly proportional to its temperature.

The variables that must be kept constant while determining the functional relationship between pressure and temperature of a gas are as follows:

Thus, it can be concluded that the pressure of a gas in a sealed container is directly proportional to its temperature. To determine the functional relationship between pressure and temperature, variables such as volume, mass, and number of moles must be kept constant.

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The thermal conductivity of a substance affects its ability to heat or be heated by its surroundings because the higher the thermal conductivity of a substance, the more easily it can be heated or heat others.

Thermal conductivity of a substance refers to the ability of a substance to allow heat energy to easily flow through it.

The higher the thermal conductivity of a substance, the more easily it can be heated or heat its surroundings.

The thermal conductivity of a substance varies according to the nature of the substance. Metals generally have high thermal conductivities whereas non-metals usually have low thermal conductivity.

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The graph shows that as mass increases, kinetic energy increases exponentially. This means that as the mass of an object increases, the kinetic energy increases by a larger and larger amount.

This can be seen by the upward sloping line on the graph. This can be seen in the graph by the steepness of the line, which shows that the increase in kinetic energy is growing faster and faster as the mass increases. Additionally, the graph shows that the rate of increase in kinetic energy is greater for lower masses than for higher masses, which indicates an exponential increase. This can be seen by the upward sloping line on the graph.

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The pressure of the gas using the ideal gas equation and by using the van der Waals equation is 2.52 atm and 0.164 atm.

Ideal gas equation is defined as the state equation for a fictitious perfect gas. Although it has significant drawbacks, it is a decent approximation of the behavior of many gases under various conditions.

Given n = 3.21 moles

V = 5.22 L

T = 50 °C

R = 0.0821 L atm K-1 mol-1

a = 4.17 atm L2 mol-2

b = 0.0371 L mol-1

Ideal gas equation

PV = nRT

P = nRT / V

P = 3.21 x 0.0821 x 50.0 / 5.22

P = 2.52 atm

Van der Waals equation

P = RT / V - b - a / V²

P = 0.0821 x 50.0 / 5.22 - 0.0371 - 4.17 / ( 5.22 )²

P = 0.317 - 0.153

P = 0.164 atm

Thus, the pressure of the gas using the ideal gas equation and by using the van der Waals equation is 2.52 atm and 0.164 atm.

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Answer:

To prepare a 1.00 mol dm^-3 sodium chloride solution, we need to dissolve one mole of sodium chloride in one liter of solution (1000 cm^3).

However, we only need to prepare 100 cm^3 of the solution, which is 1/10 of a liter. So we need to dissolve:

1/10 * 1.00 mol = 0.100 mol

of sodium chloride in 100 cm^3 of solution.

The molar mass of sodium chloride is 58.5 g/mol. So to calculate the mass of sodium chloride required, we can use:

mass = number of moles x molar mass

mass = 0.100 mol x 58.5 g/mol

mass = 5.85 g

Therefore, we need 5.85 g of sodium chloride to prepare 100 cm^3 of 1.00 mol dm^-3 sodium chloride solution.

\(2Mg + 2HCl = MgCl_2 + H_2\)

The remaining mass has escaped the test tube, as hydrogen is in gaseous form.

The energy of light with a frequency of 3 × \(10^{9}\) Hz is equal to 1.988 x \(10^{-24}\) Joules.

The formula to calculate the energy is - E = h × f

where,

E = energy

h =  Planck's constant (6.626 × \(10^{-34}\) J-sec)

f  = frequency of the light

Put the given values of 'f' and 'h' in the above equation -

E = 6.626 × \(10^{-34}\) × 3 × \(10^{9}\)

  = 19.88 × \(10^{-25}\)

  = 1.988 × \(10^{-24}\) J

So, a light wave with 3 x \(10^{9}\) Hz has an energy of 1.988 x \(10^{-24}\) J.

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i think it is D

ffffffffffffffffffffffffffffffffffffffuuuuuuuuuuuuuuuuuuuuuuuuuunnnnnnnnnnnn

Nuclear magnetic resonance spectroscopy (NMR) is used to study the electronic environment of atoms and the bonding nature of a compound.

The number of different signals observed in the 1H NMR spectra of the given compounds are as follows: Compound A: 10 signals, Compound B: 6 signals ,Compound C: 4 signals Compound D: 6 signals ,Compound E: 9 signals, Compound F: 3 signals

In proton nuclear magnetic resonance spectroscopy (1H NMR), the magnetic field strength and electronic environment of the protons influence the chemical shifts. The shielding effect or deshielding effect of the nearby atoms, bond length, and bond angle, among other factors, all influence the chemical shifts. There are five different types of proton environments, which correspond to five different chemical shifts, in this case: Type 1: Hydrogen atoms that are covalently bonded to sp3 hybridized carbons. Type 2: Hydrogen atoms that are covalently bonded to sp2 hybridized carbons. Type 3: Hydrogen atoms that are covalently bonded to sp hybridized carbons. Type 4: Hydrogen atoms that are covalently bonded to aromatic carbons. Type 5: Hydrogen atoms that are directly bonded to electronegative elements such as nitrogen, oxygen, or halogens.

Here, to determine the number of signals expected in the 1H NMR of the compounds. Compound A: 10 different proton environments => 10 signals. Compound B: 6 different proton environments => 6 signals. Compound C: 4 different proton environments => 4 signals. Compound D: 6 different proton environments => 6 signals. Compound E: 9 different proton environments => 9 signals. Compound F: 3 different proton environments => 3 signals.

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Answer:

I and Ii it is the answer the correct one

Answer: \(Fe^{2+}(aq)+2e^-\rightarrow Fe(s)\)

Explanation:

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance increases.

 Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced.

\(Mg(s)+Fe^{2+}(aq)\rightarrow Fe(s)+Mg^{2+}(aq)\)

The oxidation half reaction is:

\(Mg(s)\rightarrow Mg^{2+}(aq)+2e^-\)

The reduction half reaction is:

\(Fe^{2+}(aq)+2e^-\rightarrow Fe(s)\)

Answer:

A

Explanation:

edge

The question is incomplete, the complete question is:

Standardization of a Borax solution (Na2B4O7). A student titrates a 20.00 mL sample of an aqueous borax solution with 1.044 M H2SO4. It takes 2.63 mL of acid to reach the equivalence point. Knowing it takes 1 H2SO4 to neutralize 2 Na2B4O7, what was the concentration of this Borax solution?

Answer: The concentration of borax solution is 0.069 M.

Explanation:

To calculate the concentration of borax solution, the formula used is:

\(n_1C_1V_1=n_2C_2V_2\) ....(1)

where,

\(n_1, C_1\text{ and }V_1\) are the n-factor, concentration and volume of sulfuric acid

\(n_2,C_2\text{ and }V_2\) are the n-factor, concentration and volume of borax solution.

We are given:

\(n_1=1\\C_1=1.044M\\V_1=2.63mL\\n_2=2\\C_2=?M\\V_2=20mL\)

Putting values in equation 1, we get:

\(1\times 1.044\times 2.63=2\times C_2\times 20\\\\C_2=\frac{1\times 1.044\times 2.63}{2\times 20}\\\\C_2=0.069M\)

Hence, the concentration of borax solution is 0.069 M.

Answer:

The velocity of the bb when it reaches a height of 203 m can be determined using the laws of projectile motion. Since the bb is moving vertically upwards, its velocity at that height will be zero.

brainlest?

Answer: v = 83.96 m/s

Assuming the acceleration due to gravity is approximately 9.8 m/s^2, we can use the principles of projectile motion and energy conservation.

Using the equation for the vertical displacement of an object in free fall:

Δy = (v₀² - v²) / (2g)

Δy = vertical displacement (203m)

v₀ = initial velocity (105 m/s)

v = final velocity (not known yet)

g = accerlation due to gravity (9.8 m/s^2)

Lets rearrange the equation to solve for the final velocity:

v = v = √(v₀² - 2gΔy)

Substituting the given values:

v = √(105² - 2 * 9.8 * 203)

v ≈ √(11025 - 3979.6)

v ≈ √(7054.4)

v ≈ 83.96 m/s

Therefore, when the BB pellet is at the height of 203m, its velocity will be approximately 83.96 m/s.

In the context of atomic orbital (AO) wavefunctions, the terms "radial node" and "nodal plane" refer to different aspects of the wavefunction's behavior.

A radial node is a region in the AO wavefunction where the probability of finding an electron is zero along the radial direction. In other words, it represents a spherical shell where the electron is unlikely to be found. The number of radial nodes is determined by the principal quantum number (n) of the orbital. For example, the 2s orbital has one radial node, while the 2p orbital has no radial nodes.

On the other hand, a nodal plane is a flat plane within the AO wavefunction where the probability of finding an electron is zero along a particular direction. It represents a surface that divides the orbital into two regions of opposite phases. The number of nodal planes is determined by the angular quantum numbers (l and m) of the orbital. For example, the 2s orbital has no nodal planes, while the 2p orbital has one nodal plane (the xz or yz plane).

Radial nodes arise from the radial part of the wavefunction because they depend on the distance from the nucleus. The radial part determines the distribution of the electron density as a function of distance, and the nodes correspond to regions where the density drops to zero.

On the other hand, nodal planes arise from the angular part of the wavefunction because they depend on the orientation and shape of the orbital. The angular part describes the angular distribution of the electron density around the nucleus, and the nodal planes correspond to regions where the phase of the wavefunction changes sign.

In summary, radial nodes are related to the distance from the nucleus and arise from the radial part of the wavefunction, while nodal planes are related to the orientation and shape of the orbital and arise from the angular part of the wavefunction. The 2s orbital has one radial node and no nodal planes, while the 2p orbital has no radial nodes and one nodal plane.

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Answer:

C

Explanation:

Mitochondria provides energy (ATP) for cells to use

Nucleus provides genetic code (DNA)

Ribosomes assemble amino acids chains based on the DNA from nucleus to form proteins

Answer:

c

Explanation:

Answer:

Mass of copper deposited = 31.75 g

Explanation:

According to Faraday's second law of electrolysis, when the same quantity of electricity is passed through different electrolytes, the relative number of moles of the elements deposited are inversely proportional to the charges on the ions of the elements.

From this law, it can be seen that the higher the charge, the lower the number of moles of a given element deposited.

Number of moles of aluminium in 9 g of aluminium = mass / molar mass

Molar mass of aluminium = 27 g

Number of moles of aluminium = 9/27 = 1/3 moles

Charge on aluminium ion = +3

3 moles of electrons will discharge 1 mole of aluminium,

1 mole of electrons will discharge 1/3 moles of aluminium

Number of moles of electrons involved = 1 mole of electrons

Charge on copper ion = +2

1 mole of electrons will discharge 1/2 moles of copper.

Mass of 1/2 moles of copper = number of moles × molar mass of copper

Molar mass of copper = 63.5 g

Mass of copper deposited = 1/2 × 63.5 = 31.75 g

The correct formula for a compound formed from the elements Al and O is Al₂O₃.

Correct option is C.

Aluminum oxide is an oxide of aluminum with the chemical formula Al₂O₃ which is primarily composed of two chemically bonded aluminum and oxygen atoms. Aluminum oxide chemical compounds exist in various forms, with the most common being alpha, gamma, and theta.

The solid compound is an odorless, white powder which is insoluble in water and is a major component of the Earth's crust. It occurs naturally as corundum, bauxite, and cryolite and can be synthetically produced through burning aluminum metal or dissolving alumina tri-hydrate.

Aluminum oxide is widely used in a variety of applications due to its unique properties such as hardness, thermal conductivity, electrical conductivity, optical properties, and chemical inertness.

Correct option is C.

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The pH of the solution is 5.4.

This is a basic buffer problem. The reaction in the buffer is:

C6H5NH3+ (aq) + H2O (l) ↔ C6H5NH2 (aq) + H3O+ (aq)

The Kb expression for the weak base C6H5NH2 is:

Kb = [C6H5NH2][H3O+] / [C6H5NH3+]

We can assume that the initial concentration of C6H5NH3+ and C6H5NH2 is equal to their original concentrations. Let x be the amount of H3O+ formed by the reaction. Then the new concentration of C6H5NH3+ is (0.100 - x) mol/L and the new concentration of C6H5NH2 is (0.500 + x) mol/L.

Now, we can set up the Kb expression and solve for x:

4.3 × 10-10 = [(0.500 + x)(x)] / (0.100 - x)

Solving this equation gives x = 3.76 × 10-6 M.

This means that the new concentration of H3O+ is 3.76 × 10-6 M, and the new pH is:

pH = -log[H3O+] = -log(3.76 × 10-6) ≈ 5.4

Therefore, the resulting pH when 0.040 mol of solid NaOH is added to the buffer is approximately 5.4.

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Answer:

chemical reactions which proceed with the release of heat energy are called exothermic reactions

Answer:

2 Al + 3 O2 → 2 Al2O3

I hope this helps a little bit.

Answer:

2 moles of NO₂ contain 12.044 × 10²³ molecules  of NO₂

Explanation:

Given data:

Number of moles of NO₂ = 2.00 mol

Number of molecules of NO₂ = ?

Solution:

It will be solve through Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

2.00 mole NO₂  × 6.022 × 10²³ molecules  of NO₂  / 1 mol of NO₂

12.044 × 10²³ molecules  of NO₂

Thus, 2 moles of NO₂  contain 12.044 × 10²³ molecules  of NO₂ .

Answer:

V = 25.7 L.  

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to solve for the volume of hydrogen, by firstly calculating the moles of this gas produced by 37.6 g of magnesium, according to the 1:1 mole ratio between them:

\(n_{H_2}=37.6gMg*\frac{1molMg}{24.305gMg}*\frac{1molH_2}{1molMg}=1.55molH_2\)

Now, we use the ideal gas equation:

\(PV=nRT\)

To solve for the volume, and obtain:

\(V=\frac{nRT}{P}\\\\V=\frac{1.55mol*0.08206\frac{atm*L}{mol*K}*293.15K}{1.45atm}\\\\V=25.7L\)

Regards!

Answer:

You can tell by looking at the reaction. If it stops bubbling or steaming it is finished. It s going to react and start bubbling. When it stops bubbling and fizzing, the reaction will be over.

Answer:

4.70 grams of NH4Cl is needed to prepare 350 mL of a 0.25 M ammonium chloride solution.

We need approximately 4.68 grams of NH4Cl to prepare a 0.25 M ammonium chloride solution with a volume of 350 mL.

To determine the mass of NH4Cl needed to prepare the solution, we us use the formula:

m=M x V x MM ... (i)

where,

m= mass in grams

M=molarity of solution

MM= molar mass of compound

V= volume in litres

The number of moles of NH4Cl needed can be calculated using:

  Moles = Molarity x Volume ...(ii)

  Moles = 0.25 mol/L x 0.350 L

  Moles = 0.0875 mol

Hence we can replace M x V with number of moles in equation i.

The molar mass of NH4Cl is :

  Molar mass of NH4Cl = (1 x 14.01 g/mol) + (4 x 1.01 g/mol) + (1 x 35.45 g/mol)

  Molar mass of NH4Cl = 53.49 g/mol

We have all the variables

Putting them in equation i.

Hence,

  Mass (g) = Moles x Molar mass

  Mass (g) = 0.0875 mol x 53.49 g/mol

  Mass (g) = 4.68 g

Therefore, you would need approximately 4.68 grams of NH4Cl to prepare a 0.25 M ammonium chloride solution with a volume of 350 mL.

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Metallic elements exist in a solid-state and they are opaque, have a shiny surface, good conductors of electricity and heat, malleable and ductile, and are dense. The structure of metals is formed by atoms that are held together by metallic bonds. These atoms have loosely bound valence electrons that can be shared between the neighboring atoms.

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Answer:

A: Because her drawing does not accurately represent what really happens, she should make a new version of it that better predicts what she actually experienced in the dark room.

A chemical equation is a statement using chemical formulas that express both the identities and the relative quantity of the reactants and products involved in a chemical or physical change.

The chemical equation is said to be balanced if there are no inequalities.

The relative quantity is generally an absolute quantity divided by some other quantity. For example, in the previous excel file, one could calculate the percent of the adult population infected with HIV by dividing the number of adults with HIV by the total adult population of the country.

The main four types of reactions are direct combination, analysis reaction, single displacement, and double displacement.

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Answer:

See below ↓

Explanation:

Answer:

hope it helps you

\( 172c{m}^{2} \)