properties are dependent on the amount of substance. an example is . properties are independent of the amount of substance. an example is .

.energy mechanical needs it Answer:

Yes.

Explanation:

Answer:

Sound waves cannot propagate in vacuum. Air is needed for sound waves to travel and there is no air in vacuum.

Explanation:

Answer:

See Explanations

Explanation:

The Empirical Gas Laws include ...

Boyles Law => P₁V₁ = P₂V₂

Charles Law => T₁/V₁ = T₂/V₂

Gay-Lussac's Law => P₁/T₁= P₂/T₂

Avogadro's Law => V₁/n₁ = V₂/n₂

Combined Gas Law => P₁V₁/T₁ = P₂V₂/T₂

Ideal Gas Law => PV = nRT; R = 0.08206 L·Atm/mol·K

One only needs to learn the 'Combined Gas Law' in that it embodies all of the gas law problems.

Start with a simple table for P, V & T and enter given data. If a variable is not given, assume it is constant. Set up P₁V₁/n₁T₁ = P₂V₂/n₂T₂ and substitute given data. Solve for unknown.

Your Problems:

1. P₁ = 1 Atm        P₂ = 3 Atm

  V₁ = 300ml      V₂ = ?

  T₁ = Constant  T₂ = T₁

   n₁ = Constant  n₂ = n₁

P₁V₁/n₁T₁ = P₂V₂/n₂T₂  

=> (1Atm)(300ml)/(Constant)(Constant) = (3Atm)(V₂)/(Constant)(Constant)

=> (1Atm)(300ml) = (3Atm)V₂

=> V₂ = (1Atm)(300ml)/(3Atm) = 100ml

2. P₁ = 1 Atm        P₂ = ?

   V₁ = Constant  V₂ = V₁

   T₁ = 273K         T₂ = 82K

   n₁ = Constant  n₂ = n₁

P₁V₁/n₁T₁ = P₂V₂/n₂T₂

=> (1Atm)(Constant)/(273K)(Constant) = (P₂)(Constant)/(82K)(Constant)

=> (1Atm)/(273K) = (P₂)/(82K)

=> P₂ = (1Atm)(82K)/(273K)

=> P₂ = 0.3 Atm (1 sig-fig)

3. P₁ = 101.25kPa     P₂ = 506kPa

   V₁ = 5 Liters         V₂ = ?

   T₁ = Constant       T₂ = T₁

   n₁ = Constant  n₂ = n₁

P₁V₁/n₁T₁ = P₂V₂/n₂T₂

=> (101.25kPa)(5L)/(Constant)(Constant) = (506kPa)(V₂)/(Constant)(Constant)

=> (101.25kPa)(5L) =  (506kPa)(V₂)

=> V₂ = (101.25kPa)(5L)/(506kPa)

=> V₂ = 1.00 Liter

4. P₁ = Constant       P₂ = P₁

   V₁ = 3.2 Liters      V₂ = ?

   T₁ = 273°C + 273 = 546K       T₂ = 400°C + 273 =673K*

   n₁ = Constant  n₂ = n₁

*Note => be sure to convert all temps to Kelvin when working empirical gas law problems. K = °C + 273

P₁V₁/n₁T₁ = P₂V₂/n₂T₂

=> (Constant)(3.2L)/(Constant)(546K) = (Constant)(V₂)/(Constant)(673K)

=> (3.2L)/(546K) = (V₂)/(673K)

=> V₂ = (3.2L)(673K)/(546K)

=> V₂ = 3.944 Liters ≅ 3.9 Liters (2 sig-figs)

Answer:

V1T1=V2T2

Explanation:

V2=V1T1/T2

The final volume of the gas can be determines using the Charles's law of volume and temperature. The volume of helium when temperature increased to  32 °C increases to  48.9 L.

Charles's law states that, at constant pressure, the volume and temperature of a gas are in direct proportionality. Thus, as the temperature increases, volume of the gas increases.

Hence, V/T = constant

Let V1 and T1 be the initial volume and temperature and V2 and T2 be the final quantities. Then, the relation can be stated as ;

V1/ T1 = V2/ T2

Given that initial quantities:

V1 = 26 L

T1 = 17 °C

Final temperature T2 =32 °C

Then, final volume V2 = V1 T2/T1

V2 = (26 L × 32°C)/ 17 °C = 48.9 L

Therefore, the volume of helium gas increases to 48.9 liters.

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we get T1*V1γ-1 = T2*V2γ-1, which gives T2/T1 = 2γ-1 = 1.25, which gives T2 = 1.25*T1, therefore temperature increases by a factor of 1.25

The ratio of a gas's specific heat at a constant pressure to that of the gas's specific heat at a constant volume is known as the specific heat ratio of a gas, which is symbolized as gamma " but also known as "k."

Calculation-

in an adiabatic process

PVγ = constant

therefore      P1*V1γ  = P2*V2γ  

here we have in part a    that    V2 = 0.5*V1   and  P2 = 2.5*P1

putting in the values   we get, 2γ = 2.5 which on solving we get

γ = 1.3219

now part b, we can use                  

TVγ-1 = constant, therefore here we have

T1 = initial temperature, T2 = final temperature

and V2 = 0.5*V1

on putting in the values we get,

T1*V1γ-1 = T2*V2γ-1

which gives  

T2/T1 = 2γ-1 = 1.25      which gives    T2 = 1.25*T1

therefore,

temperature increases by a factor of 1.25

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The pH of the solution will be 10.47.

The pH of a solution is mathematically given as:

 pH = - log [\(H^+\)] of -log [\(H_3O^+\)]

Thus, in this case, with  [\(H_3O^+\)]  of 3.4 x 10-¹¹ M:

pH = -log 3.4 x \(10^-^1^1\) = 10.47

Thus, the pH of the solution will be 10.47.

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Answer:

u meant the answer to this ques

Explanation:

22

×12

------

44

22 ×

----------

264

-----------

or the answer can be 22×12=264

The balanced equation for the combustion of hexene (C6H12) with oxygen gas (O2) to form carbon dioxide gas (CO2) and water vapor (H2O) is:

C6H12(l) + 9O2(g) -> 6CO2(g) + 6H2O(g)

The reaction occurs in the presence of oxygen gas, which is needed for combustion to take place. Hexene is a hydrocarbon, and when it reacts with oxygen, it undergoes combustion to produce carbon dioxide and water vapor.

The balanced equation shows that one molecule of hexene reacts with nine molecules of oxygen to produce six molecules each of carbon dioxide and water vapor.

This is an exothermic reaction, as heat is released during the combustion process. The conditions of the reactants and products are indicated in parentheses, with hexene and water vapor being in liquid state (l) while oxygen and carbon dioxide are gases (g).

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(a)The pH of the fruit juice solution is approximately 3.5. (b) The hydrogen ion concentration of the tomato solution is 0.001 mol/L.

(b)The hydrogen ion concentration of the tomato solution is 0.001 mol/L.

(a). The hydrogen ion concentration of the fruit juice is 0.0003 mol/L. We can determine the pH of the solution using the formula pH = -log[H⁺].

pH = -log(0.0003)

pH ≈ -log(3 × 10⁻⁴)

Using a calculator, we can calculate the logarithm:

pH ≈ -(-3.5229) (rounded to the nearest tenth)

pH ≈ 3.5

Therefore, the pH of the fruit juice solution is approximately 3.5.

(b). A tomato has a pH of 3.0. We can determine the hydrogen ion concentration of this solution by rearranging the formula pH = -log[H⁺] to solve for [H⁺].

[H⁺] = 10(-pH)

[H⁺] = 10⁻³

[H⁺] = 0.001 mol/L

Therefore, the hydrogen ion concentration of the tomato solution is 0.001 mol/L.

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Yes, a hydrogen atom in the ground state can absorb a photon of energy less than 13.6 ev.

The wavelength of the matter waves that make up an electron orbit around a nucleus is the same as the radius of the orbit. Any fractional number would not fit the circle of the electron orbit, but a whole number of wavelengths might. Atomic excitations, in which the electrons take in a photon to enter a higher energy state, are another process that an atom goes through. As a result, electrons' wavelength can shift, which also causes the electron's orbit to alter. The relationship between an electron's energy and wavelength is inverse. An electron in the ground state can therefore absorb a photon with energy equal to the energy difference between the ground state energy and excited state energy during atomic excitation.

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Answer:

Yall are coming after that person above me when theres no diagram!!!! HELLO????????????? crazy

Explanation:

Sure! To find the missing operations, which is 51. Let's first focus on the first two numbers in the equation, 15 and 4. We need to perform some operation between them to get a result of 4.

The only operation that will give us a result of 4 when performed on 15 is subtraction (-), as 15 - 11 = 4. So the missing operation between 15 and 4 is subtraction (-). Now let's focus on the last two numbers in the equation, 4 and 11. We need to perform some operation between them to get a result of 51. We know that the missing operation between 15 and 4 is subtraction, so we need to use either multiplication, division, or addition between 4 and 11. Let's start by trying multiplication (*). If we multiply 4 and 11, we get 44. To get from 44 to 51, we would need to add 7. But we don't have the addition (+) operation available to us, so multiplication is not the correct missing operation.

Here's a step-by-step explanation of how to solve the problem ,Step 1: Try different operations in the given equation. Step 2: Insert * as the first operation: 15 * 4 _ 4 _ 11 = 51. Step 3: Now, insert + as the second operation: 15 * 4 + 4 _ 11 = 51. Step 4: Lastly, insert - as the third operation: 15 * 4 + 4 - 11 = 51. By using these operations, the equation becomes: 15 * 4 + 4 - 11 = 60 + 4 - 11 = 64 - 11 = 51. The equation is now true.

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The London dispersion force is "the weakest intermolecular force"

C). $1,305,000. To compute Fast Inc.'s taxable income, we need to start with the corporation's gross income, which is the sales revenue of $1,879,000.

From this, we subtract the deductible expenses, such as Mrs. Ford's salary of $160,000 and other operating expenses of $414,000, which gives us a total of $1,305,000.
However, we still need to consider the interest paid on Mrs. Ford's note of $60,000 and the dividend distributed to Mrs. Ford of $100,000, both of which are not deductible expenses for the corporation.

Therefore, the corporation's taxable income would be $1,465,000 ($1,305,000 + $60,000 + $100,000), and this would be subject to the corporate tax rate based on the current tax laws and regulations.

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Answer:

KCl is the answers for the question

Explanation:

please give me brainlest

Answer:

KCl

this is the answer hope its helps you I tried my best to give you the best answer ;)

Answer:

5.232

Explanation:

INFORMATION:

We have:

- 66 grams of NaCl

- 255 grams of water

If the NaCl is dissolved into the water, we must find the mass percent

STEP BY STEP EXPLANATION:

To find the mass percent we must must use the next formula

In our case,

- the solute is NaCl

- the solution would be the sum of masses from NaCl and water

Then,

- mass of solute = 66 g

- mass of solution = 66 g + 255 g = 321 g

Finally, replacing in the formula,

ANSWER:

The mass percent when 66 grams of NaCl is dissolved in 255 grams of water is 20.60%

Answer:

helium and neon are both noble gases their outermost shells are full or stable the elements will agree with the statement s above

Answer:

there will be winds moving from 25miles per hour to 30 miles per hour towards the east

SI unit of

force- Newton

power- watt

pressure- Pascal

fundamentals units

force - mass

power - time

pressure- length

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The substances having common ion cannot form precipitate during chemical change.

An ion is defined as an atom or a molecule which has a net electrical charge. There are 2 types of ions :1) cation 2) anion . The cation is the positively charged ion and anion is the negatively charged ion . As they are oppositely charged they attract each resulting in the formation of ionic bond.

Ions consisting of single atom are mono-atomic ions while which consists of two or more ions are called as poly-atomic ions . They are created by chemical interactions . They are very reactive in their gaseous state and rapidly react with oppositely charged ions resulting in neutral molecules.Ions are generated when substance is subjected to electrolysis.

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Lysine can undergo decarboxylation to produce the end-product cadaverine.

Decarboxylation is a chemical reaction where a carboxyl group (-COOH) is removed from a molecule, resulting in the release of carbon dioxide (CO2). In the case of lysine, the decarboxylation reaction occurs at the carboxyl group (COOH) of the amino acid. The reaction can be catalyzed by enzymes known as decarboxylases. The chemical equation for the decarboxylation of lysine to cadaverine can be represented as follows:

H2N(CH2)4COOH (Lysine) → H2N(CH2)5NH2 (Cadaverine) + CO2

In this reaction, the carboxyl group (COOH) in lysine is removed, resulting in the formation of cadaverine, which has one less carbon atom and one less oxygen atom than lysine. It's important to note that decarboxylation reactions often require specific reaction conditions such as appropriate pH, temperature, and the presence of specific enzymes. Without these conditions, decarboxylation may not occur or proceed at a significant rate.

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Explanation:

d. nitrogen gas because of weak intermolecular force

Answer:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

The total ionic equations shows the equation in which all the species of the reactants and the products are in dissociated form and are represented as ions.

The net ionic equations shows the equation in which all the species of the reactants and the products are in dissociated form and do not show the spectator ions which are same in the reactants and the products.

a) zinc nitrate + calcium sulphide \(\rightarrow \) zinc sulphide + calcium nitrate

balance equation : \(Zn(NO_3)_2(aq)+CaS(aq)\rightarrow ZnS(s)+Ca(NO_3)_2(aq)\)

total ionic equation :

\(Zn^{2+}(aq)+2NO_3^-(aq)+Ca^{2+}(aq)+S^{2-}(aq)\rightarrow ZnS(s)+Ca^{2+}(aq)+2NO_3^-(aq)\)

net ionic equation :

\(Zn^{2+}(aq)++S^{2-}(aq)\rightarrow ZnS(s)\)

b) potassium + calcium chloride  \(\rightarrow \) potassium chloride + calcium

balance equation : \(2K(s)+CaCl_2(aq)\rightarrow 2KCl(aq)+Ca(s)\)

total ionic equation :

\(2K(s)+Ca^{2+}(aq)+2Cl^-(aq)\rightarrow 2K^+(aq)+2Cl^-(aq)+Ca\)

net ionic equation: \(2K(s)+Ca^{2+}(aq)+\rightarrow 2K^+(aq)++Ca\)

The chitin chain needs to be cleaved at 1 place to reduce the average chain length to 3000 monomers.

To reduce the average chain length of a chitin chain from 6000 monomers to 3000 monomers, it needs to be cleaved in half, which would result in two chains of 3000 monomers each.

Since each cleavage will produce two chains, the number of cleavages required can be calculated by dividing the initial number of monomers by the desired final number of monomers and subtracting 1:

Number of cleavages = (6000 monomers / 3000 monomers) - 1

Number of cleavages = 2 - 1

Number of cleavages = 1

Therefore, the chitin chain needs to be cleaved at 1 place to reduce the average chain length to 3000 monomers.

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In 2CaCO3 there are 3 elements

I hope that helped you! If you have any further questions comment down below or message me! Good luck!