The answer is either a (33.3) or b (83.3), depending on the specific pulse width needed to generate the desired output signal.
Pulse width modulation is a technique used to modulate a signal by varying the pulse width of a periodic waveform. In this case, the duty cycle of the signal is being modulated to give a certain output. The duty cycle is the ratio of the pulse width to the period of the waveform.
Given that the input is 5 V DC and the duty cycle has a numerical value, we can use the formula for duty cycle to determine the answer.
Duty cycle = (pulse width / period) x 100%
We are given the input voltage, but not the period of the waveform. However, we can assume that the period is a fixed value for this problem. Therefore, we can simply use the given duty cycle value to determine the pulse width.
If the duty cycle has a numerical value of 33.3%, that means the pulse width is 33.3% of the period. Similarly, if the duty cycle is 83.3%, that means the pulse width is 83.3% of the period.
Using this logic, we can eliminate option d (500), as that is not a valid duty cycle value.
Therefore, the correct answer is either a (33.3) or b (83.3), depending on the specific pulse width needed to generate the desired output signal.
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Technician A states that about 33% of the heat energy created is wasted by being dumped straight out
of the exhaust to the atmosphere. Technician B states that 33% is wasted by internal friction and from
radiating off hot engine components straight to the atmosphere. Who is correct?
Select one:
A. Technician A
B. Technician B
C. Both A and B
D. Neither Anor B
Heat energy is the known to be a product of the movement of tiny particles called atoms, molecules or ions. The true statement is by Technician A.
Internal combustion engine is dependent on the heat of combustion so as to make torque to move the vehicle and power the system.
A lot of heat made during combustion is not often used productively and therefore need to be removed to avoid overheating of the engine.
The heat energy that is not used for is wasted in three ways: They are:
About 33% is wasted by being dumped straight out of the exhaust to the atmosphere. About 33% is wasted by the cooling system, which prevents overheating of the engine components. About 5% is wasted by internal friction and from radiating off of hot engine components straight to the atmosphere.Learn more from
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1025 steel wire is stretched with a stress of 70 MPa at room temperature 20 C. If th length is held constant, to what temperature in 'C and 'F must the wire be heated to reduce the stres to 17 MPa?
Check attached pictureCheck attached pictureCheck attached pictureCheck attached picture
Can someone help me please?
Avionics mechanics do which of the following tasks?
a. cargo inspection for safety
b. design improvements to the aircraft's engine
c. inspect the aircraft's interior
d. engine and landing gear maintenance and repair
Answer:
I think the answer is B. but I'm not 100% sure.
Answer:
engine and landing gear maintenance and repair
Explanation:
(a) Design a high-pass filter with a cutoff frequency of 40 kHz. Use0.01 uF capacitor and an appropriate resistor. B) Sketch and label the circuit. C) What is the gain of the filter at the cutoff frequency? Give your answer both as ratio (Vout/Vin) and in dB. D) What is the gain of the filter at a frequency of 55 kHz? Give your answer both as a ratio (Vout/Vin) and in dB.
Answer:
a) 397.89 ohm
b) attached below
c) 0.707 as a ratio
Gain in dB = 20 log 0.707 = -3 dB
d) 0.8087
Gain in dB = 20 log \(|\frac{Vout}{Vin}|\) = -1.844 dB
Explanation:
A) Find the appropriate resistor
c = 0.01 uf
fc = 40 kHz
cut-off frequency ; fo = \(\frac{1}{2\pi RC }\)
from the above equation R = \(\frac{1}{2\pi foC}\) = 397.89 ohm
B) sketch of the circuit is attached
C) The gain of the filter at the cutoff frequency
fc = 40 kHz,
C = 0.01 uF ⇒ \(\frac{-j}{2\pi foC }\) = -j 397.89
Vout = Vin * ( R / R- C )
Vout = Vin * ( 397.89 / (397.89 - j 397.89))
Vout = \(\frac{1}{\sqrt{2} }\) Vin ∠45⁰
therefore gain = |\(\frac{Vout}{Vin }\)| = \(\frac{1}{\sqrt{2} }\) = 0.707 as a ratio
Gain in dB = 20 log 0.707 = -3 dB
D) Gain of filter at 55 kHz
c = 0.01 uF = \(\frac{-J}{2\pi foC }\) = -j 289.373 ohms
Vout = Vin * \(\frac{R}{R-C}\)
= Vin * ( 397.89 / ( 397.89 - j 289.373))
Gain in ratio \(|\frac{Vout}{Vin}|\) = 0.8087 ∠ 36.03⁰
therefore gain in ratio = 0.8087
Gain in dB = 20 log \(|\frac{Vout}{Vin}|\) = -1.844 dB
Implement the following Matlab code:
x=zeros(10,128);
t1=[0:1/128:1-1/128];
z=cos(2*pi*2*t1);
x(1,:)=z;
x=reshape(x,1,1280);
figure(1);
plot(x)
Examine Figure 1 – what does it “look like”? Zoom in. Take the FFT of x and explain what you see.
Manipulate the FFT and perform the IFFT to create a signal which is a continuous (i.e. no interpolating zeroes) sinusoid in the “time” domain. Explain the amplitude of the sinusoid.
The amplitude of the sinusoid is 28384 *x soít cos.
What is amplitude?Amplitude is defined as the greatest deviation from equilibrium of a point on a vibrating body or wave in terms of displacement or distance traveled. In most cases, amplitude is calculated by looking at a wave graph and determining the height of the wave from rest. The strength or intensity of the wave is gauged by its amplitude.
Sinusoid is defined as a signal with sine wave characteristics. In the liver, spleen, and bone marrow, sinusoids and irregular tubules transport blood in place of venules and capillaries. The sine or cosine functions from trigonometry form the foundation of sinusoidal signals, which are periodic functions.
Thus the amplitude of the sinusoid is 28384 *x soít cos.
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What type of drum system is mostly to be found on the rear of a modern front wheel drive vehicle ?
Drum Brakes are mostly to be found on the rear of a modern front wheel drive vehicle.
What Is Drum Brake?
Drum brakes have been around since 1900 ,patented until 1902 by Louis Renault.
A drum brake is a brake that , causes friction caused by a set of shoes or pads that press outward against a rotating cylinder-shaped part called a brake drum.It rotates at the same speed as the wheel. The drum surrounds a set of brake shoes that are coated in materials that generate friction.Types of drum brakes
Leading/Trailing Shoe type. Twin-leading shoeDuo Servo.To know more about drum brakes from the given link
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Suppose you have a circuit you are working with, but you recognize that there is a really strong LaTeX: 60\text{Hz}60 Hz hum due to the AC power being provided to your system. You wish to reduce the effect of this humming but not any other frequency content in the signal. Which type of filter should you use to remove it
Answer:
A bandstop filter should be used to remove the 60 Hz humming component of the signal.
A bandstop filter basically allows all the frequencies above and below a specific frequency that is 60 Hz in this case.
Therefore, only the 60 Hz component of the signal will be attenuated and the rest of the frequency components in the signal will not be affected.
Explanation:
There is a really strong 60 Hz hum (noise) due to the AC power being provided to your system.
We wish to reduce the effect of this humming but not any other frequency content in the signal.
So we need a filter that can reject a particular frequency but allow any other frequencies present in the signal.
A bandstop filter would get the job done.
A bandstop filter basically allows all the frequencies above and below the specific frequency that is 60 Hz in this case.
Therefore, only the 60 Hz component of the signal will be attenuated and the rest of the frequency components in the signal will not be affected.
The notch frequency in this case is 60 Hz which is the frequency at which maximum attenuation occurs.
The typical frequency response of a bandstop filter is attached below.
Calculate the length of a half wave dipole antenna to be used to receive a 10MHz radio signal. Assume that the velocity of the electromagnetic waves on the antenna is 300000000 m/s
Using the frequency of the radio signal given, the length of the half-wave dipole antenna is 30m
What is the length of the half wave dipole antenna?The formula to calculate the length of a half-wave dipole antenna is:
Length (L) = (c / f) / 2
where:
L is the length of the antennac is the velocity of electromagnetic waves in the medium (in this case, air), which is approximately 300,000,000 m/sf is the frequency of the radio signal in Hertz (Hz)We are given that the frequency of the radio signal is 10 MHz (10,000,000 Hz). Substituting these values into the formula, we get:
L = 3 * 10⁸ / 10 * 10 * 10⁶
L = 30m
Therefore, the length of a half-wave dipole antenna to be used to receive a 10 MHz radio signal is 30 meters.
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A hydrogenation catalyst is prepared by soaking alumina particles (100-150 mesh size) in aqueous NiNO3 solution. After drying and reduction, the particles contain about 7 wt% NiO. This catalyst is then made into large cylindrical pellets for rate studies. The gross measurements for one pellet are: Mass, g 3.15 Diameter, mm 25 Thickness, mm 6 Volume, cm3 3.22 The alumina particles contain micropores, and the pelleting process introduces macropores surrounding the particles. If the macropore volume of the pellet is 0.645 cm3 and the micropore volume is 0.40 cm3 /g of particles, determine: i] The density of the pellet ii] The macropore volume in cm3 /g iii] The macropore void fraction in the pellet iv] The micropore void fraction in the pellet v] The solid fraction vi] The density of the particles
i] The density of the pellet is 0.977 g/cm^{3}. ii] The macropore volume in cm^{3}/g is 0.205 cm^{3}/g. iii] The macropore void fraction in the pellet is 25.1%.iv] The micropore void fraction in the pellet is 49.0%. v] The solid fraction of the pellet is 25.9%. vi] The density of the particles is 1.222 g/cm^{3}.
i] To determine the density of the pellet, we can use the formula:
Density = Mass / Volume
Given that the mass of the pellet is 3.15 g and the volume is 3.22cm^{3}, we can calculate the density as follows:
Density = 3.15 g / 3.22 cm^{3}≈ 0.977 \(g/cm^{3\)
ii] The macropore volume in cm3/g can be calculated by dividing the macropore volume of the pellet (0.645 cm3) by the mass of the pellet (3.15 g):
Macropore volume = 0.645 cm^{3} / 3.15 g ≈ 0.205 \(cm^{3} /g\)
iii] The macropore void fraction in the pellet can be calculated using the formula:
Macropore void fraction = Macropore volume / Total volume of the pellet
Total volume of the pellet = Volume - Macropore volume = 3.22 cm^{3}- 0.645 cm^{3} = 2.575 cm^{3}
Macropore void fraction = 0.645 cm^{3} / 2.575 \(cm^{3}\)≈ 0.251 or 25.1%
iv] The micropore void fraction in the pellet can be calculated using the given micropore volume of the particles (0.40 cm^{3} /g) and the mass of the pellet (3.15 g):
Micropore volume in the pellet = Micropore volume/g x Mass
Micropore volume in the pellet = 0.40 \(cm^{3} /g\) x 3.15 g = 1.26 cm3
Micropore void fraction = Micropore volume in the pellet / Total volume of the pellet
Micropore void fraction = 1.26 \(cm^{3}\) / 2.575 \(cm^{3}\) ≈ 0.490 or 49.0%
v] The solid fraction of the pellet can be calculated by subtracting the sum of macropore and micropore void fractions from 1:
Solid fraction = 1 - (Macropore void fraction + Micropore void fraction)
Solid fraction = 1 - (0.251 + 0.490) ≈ 0.259 or 25.9%
vi] The density of the particles can be determined using the mass of the pellet (3.15 g) and the total volume of the particles:
Total volume of the particles = Volume - Macropore volume = 3.22 \(cm^{3}\)- 0.645 \(cm^{3}\) = 2.575\(cm^{3}\)
Density of the particles = Mass / Total volume of the particles
Density of the particles = 3.15 g / 2.575\(cm^{3}\) ≈ 1.222 \(g/cm^{3}\)
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8.28 Water is the working fluid in an ideal Rankine cycle with superheat and reheat. Steam enters the first-stage turbine at 1400 lbf/in.2 and 10008F, expands to a pressure of 350 lbf/in.2, and is reheated to 9008F before entering the secondstage turbine. The condenser pressure is 2 lbf/in.2 The net power output of the cycle is 1 3 109 Btu/h. Determine for the cycle (a) the mass flow rate of steam, in lb/h. (b) the rate of heat transfer, in Btu/h, to the working fluid passing through the steam generator. (c) the rate of heat transfer, in Btu/h, to the working fluid passing through the reheater. (d) the thermal efficiency.
Answer:
Betbtybrbytntrnyrnrynunjhjhnthnnhtnnthnhtnnhnhrnntnthhnhnhtnthn
Explanation:
Would like some help with this question please ?
Answer:
D
Explanation:
Because the Boat D engine looks fast
Which method of freezing preserves the quality and taste of food?
Answer:
commercial freezing
Explanation:
smaller ice crystals are formed this causes less damage to cell membranes so the quality is less effected
The input impedance for a 100 Ω lossless transmission line of length 1.162 λ is measured as 10 + j40Ω. What is the load impedance?
The load impedance for the given transmission line is 90 - j30 Ω.
What is the impedance of the load in a 100 Ω lossless transmission line of length 1.162?The load impedance can be calculated using the following equation:
ZL = Zin * conj(Z0^2/Zin)
Where conj() denotes the complex conjugate of the quantity inside the parenthesis.
Substituting the given values, we get:
ZL = (10 + j40) * conj(\(100^2\)/(10 + j40))
= (10 + j40) * conj(1000 - j400)
= (10 + j40) * (1000 + j400)
= 4400 + j3600
= 90 - j30 Ω
Therefore, the load impedance that should be connected to the transmission line is 90 - j30 Ω for maximum power transfer.
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Equipment such as phones, fax machines, and computers are all examples of the_____ element of the business environment.
The equipment aspect of the corporate environment is exemplified by tools like phones, fax machines, and computers.
Equipment includes items like computers, vehicles, and processing equipment. They are tangible because they have a physical form, as opposed to intangible assets, which don't (such patents, trademarks, or copyrights), which are the things required for a specific activity or purpose. When we say "the set of goods you require for a certain function," we mean "the uncountable noun equipment," such as tools or clothing: New sleeping bags and a small refrigerator are among the camping supplies we've purchased. They are the most fundamental methods for employing leverage (or mechanical advantage) to increase force that are currently understood. Simple machines include the wheel and axle, inclined plane, lever, wedge, pulley, and screw basic machines
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assuming complementary inputs are available, the minimum number of transistors needed to realize a two input xor gate is:
Assuming complementary inputs are available, the minimum number of transistors needed to realize a two input xor gate is 4.
If two inputs work well together in the production process, they are said to be complements. Since the inputs are used in fixed proportions, if the price of one input lowers, more of it will be sought after, increasing the demand for the other input.
In this study, a model of anticompetitive exclusive contracts with complimentary inputs is built. A downstream company converts a variety of complementary inputs into finished goods. When complementary input providers hold a dominant position in a specific input market, upstream competition price within that market benefits both the downstream firm and the complementary inputs providers by driving up complementary input prices.
Thus, even when entry that is socially optimal is permitted, the downstream firm is unable to generate higher profits. Therefore, even in the absence of scale economies, downstream competition, and relationship-specific investment, the inefficient incumbent provider can prevent socially efficient entrance by employing exclusive contracts.
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You should always adjust the seat as ____ as possible, while staying comfortable.
A. high
B. even
C. low
D. close
Answer: A. High
Explanation:
In order to have an obstructed view from your seat, you should always adjust your seat as high as possible, while staying comfortable.
Answer:
A
Explanation:
I put high and got it right.
A gas in a piston-cylinder device is compressed, and as a result its temperature rises. is this a heat or work energy interaction?
Answer::
It is a work interaction as the compression process moves the piston by an external force.
Explanation:
what feature is not characteristic of the international style? geometric form. volume over mass. glass walls. applied ornament.
The feature that is not characteristic of the international style is applied ornament. This style is known for its minimalism and simplicity, often featuring geometric forms, glass walls, and prioritizing volume over mass. However, it does not typically incorporate decorative ornamentation in its design.
The feature that is not characteristic of the International Style is applied ornament. The International Style typically emphasizes geometric form, volume over mass, and glass walls, while avoiding ornate decorations or applied ornamentation.The feature that is not characteristic of the International Style is applied ornament. The International Style emerged in the early 20th century and was characterized by a focus on functionality, simplicity, and the use of modern materials and construction techniques. It emphasized a minimalist aesthetic that was devoid of unnecessary ornamentation or decoration.Geometric form, volume over mass, and glass walls are all key features of the International Style. Geometric form refers to the use of simple geometric shapes such as squares, rectangles, and circles in the design of buildings. Volume over mass refers to the use of lightweight materials and the creation of buildings with a sense of lightness and transparency. Glass walls were a key element of the International Style, allowing for greater transparency and connection between interior and exterior spaces. Applied ornament, on the other hand, was not characteristic of the International Style. Ornamentation was seen as unnecessary and superficial, and architects and designers sought to eliminate it in favor of a more functional and streamlined approach. This rejection of applied ornament was a defining characteristic of the International Style, and it has influenced architectural design to this day.
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The feature that is not characteristic of the international style is applied ornament.
The international style emphasizes simplicity, functionality, and the use of modern materials such as steel, concrete, and glass. It favors geometric forms and the use of volume over mass, as well as the incorporation of large expanses of glass walls. However, it rejects the use of decorative ornamentation, as it goes against the minimalist and rational principles of the style.
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Three common controls used in central electric heat applications are
A. capacitors, thermostats, and contactors.
B. thermostats, contactors and sequencers.
C. cool anticipators, relays, and contactors.
D. capacitors, cool anticipators, and sequencers.
Three common controls used in central electric heat applications are thermostats, contactors, and sequencers.The correct answer is option B.
Thermostats play a crucial role in controlling the temperature in a central electric heating system. They detect the ambient temperature and send signals to the heating system to turn on or off accordingly.
Thermostats allow users to set their desired temperature and maintain it within a specific range, ensuring comfort and energy efficiency.
Contactors are electrical switches that control the flow of electricity to the heating elements. They are responsible for connecting or disconnecting the power supply to the heating system based on the signals received from the thermostat.
Contactors are essential for ensuring the safe and efficient operation of the electric heat system.
Sequencers are used to control the sequencing or timing of the electric heating elements. They ensure that the heating elements turn on and off in a specific order to prevent excessive power consumption and ensure even heating.
Sequencers also help protect the electrical system from overload conditions by controlling the activation of heating elements in a coordinated manner.
In conclusion, the correct answer is B. Thermostats, contactors, and sequencers are the three common controls used in central electric heat applications.
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You have been allocated a club instance to conduct pic for a customer.what steps do you need to follow before initiating the pic ?
Explanation:
1. Verify the scope of work: Make sure you understand the scope of work and requirements for the customer's club instance. Confirm with the customer if any specific settings or customizations are required.
2. Schedule the PIC: Coordinate with the customer to schedule a suitable time and date for the PIC. Ensure that all necessary stakeholders are available and informed.
3. Review the customer's club instance: Review the customer's club instance to identify any potential issues or conflicts that need to be addressed during the PIC. Check the instance for any configuration, integration, or data issues.
4. Prepare for the PIC: Prepare a checklist and any necessary tools or documentation for the PIC. Make sure you have access to the customer's club instance, including any necessary login credentials or permissions.
5. Initiate the PIC: Once you have completed the above steps, initiate the PIC by going through the checklist and verifying that the customer's club instance is set up correctly and meets their requirements. Identify any issues or gaps that need to be addressed and work with the customer to resolve them.
6. Follow up: Once the PIC is complete, provide the customer with a report or summary of the findings. Follow up with any necessary actions or next steps, and confirm that the customer is satisfied with the results
Many of the problems applied scientists address are multidisciplinary issues and therefore require the collaboration of scientists with a variety of skills and knowledge. Explain which types of scientists might be involved in studying global warming.
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Bridge collapses have hit the news recently with more frequency. Do some research online and state two possible reasons for these collapses. How might those employed in the Health, Safety, & Environmental Management pathway help prevent these collapses and keep us safe?
Answer:
The main reason for bridges collapses is: earthquakes (natural disasters) and construction incidents. Whenever a natural disaster occur, it makes the bridge collapse. An example is hurricanes. Hurricanes come with a great wind and that might lead to the bridge collapsing. Construction incidents means the bridge falls during construction. Those who are employed in health, safety and environmental management need to make sure that during the construction, they have examined the material and made sure it is strong. Working with economists, they should seek better understanding of the methods for minimizing the costs during the life of the bridge. In case for natural disasters, like flooding, they should make the bridge in a lever where the water won't reach the bridge. And they should have a limit for weight in the bridges because that is another reason it collapses, because the bridge does not support extra weight.
Explanation:
hope this helps
Q/For the circuit showm bellow:
a) find the mathematical expression for the transient behavior of ve and ic after closing the switeh,
b) sketch vc and ic.
Answer:
hello your question is incomplete attached is the complete question
A) Vc = 15 ( 1 -\(e^{-t/0.15s}\) ) , ic = \(1.5 mAe^{-t/0.15s}\)
B) attached is the relevant sketch
Explanation:
applying Thevenin's theorem to find the mathematical expression for the transient behavior of Vc and ic after closing the switch
\(R_{th}\) = 8 k ohms || 24 k ohms = 6 k ohms
\(E_{th}\) = \(\frac{20 k ohms(20 v)}{24 k ohms + 8 k ohms}\) = 15 v
t = RC = (10 k ohms( 15 uF) = 0.15 s
Also; Vc = \(E( 1 - e^{-t/t} )\)
hence Vc = 15 ( 1 - \(e^{-t/0.15}\) )
ic = \(\frac{E}{R} e^{-t/t}\) = \(\frac{15}{10} e^{-t/t}\) = \(1.5 mAe^{-t/0.15s}\)
attached
When you hover over an edge or point, you are activating ____________ in SketchUp?
A. Zoom Focus
B. Inference Tools
C. Drawing Tools
D. Selection Filters
A rocket is launched from rest with a constant upwards acceleration of 18 m/s2. Determine its velocity after 25 seconds
Answer:
The final velocity of the rocket is 450 m/s.
Explanation:
Given;
initial velocity of the rocket, u = 0
constant upward acceleration of the rocket, a = 18 m/s²
time of motion of the rocket, t = 25 s
The final velocity of the rocket is calculated with the following kinematic equation;
v = u + at
where;
v is the final velocity of the rocket after 25 s
Substitute the given values in the equation above;
v = 0 + 18 x 25
v = 450 m/s
Therefore, the final velocity of the rocket is 450 m/s.
A project ha following time chedule: Activity Time in Week Activity Time in Week 1-2 4 5-7 8 1-3 1 6-8 1 2-4 1 7-8 2 3-4 1 8-9 1 3-5 6 8-10 8 4-9 5 9-10 7 5-6 4 Contruct the network and compute: (1) TE and TL for each event (2) Float for each activity (3) Critical path and it duration
(1) TE and TL for each event
Event 1: TE=0, TL=0
Event 2: TE=4, TL=4
Event 3: TE=1, TL=5
Event 4: TE=2, TL=6
Event 5: TE=6, TL=12
Event 6: TE=1, TL=2
Event 7: TE=8, TL=16
Event 8: TE=9, TL=17
Event 9: TE=8, TL=18
Event 10: TE=16, TL=23
(2) Float for each activity
Activity 1-2: Float=0
Activity 1-3: Float=3
Activity 2-4: Float=2
Activity 3-4: Float=1
Activity 3-5: Float=0
Activity 4-9: Float=0
Activity 5-6: Float=0
Activity 5-7: Float=0
Activity 6-8: Float=7
Activity 7-8: Float=6
Activity 8-9: Float=5
Activity 8-10: Float=0
Activity 9-10: Float=0
(3) The critical path for this project is: 3-4, 4-9, 5-7, 7-8, 8-10, 9-10, with a total duration of 23 weeks.
THE SOLUTIONTo construct the network and compute the requested information, we first need to create a list of events and activities.From the given schedule, we can identify the following events and activities:Events:1, 2, 3, 4, 5, 6, 7, 8, 9, 10
Activities:1-2: 4 weeks
1-3: 1 week
2-4: 1 week
3-4: 1 week
3-5: 6 weeks
4-9: 5 weeks
5-6: 4 weeks
5-7: 8 weeks
6-8: 1 week
7-8: 2 weeks
8-9: 1 week
8-10: 8 weeks
9-10: 7 weeks
Now we can compute the TE (time when an event is expected to start) and TL (time when an event is expected to be completed) for each event, as well as the float (amount of time that an activity can be delayed without delaying the project completion) for each activity.TE and TL for each event:Event 1: TE=0, TL=0
Event 2: TE=4, TL=4
Event 3: TE=1, TL=5
Event 4: TE=2, TL=6
Event 5: TE=6, TL=12
Event 6: TE=1, TL=2
Event 7: TE=8, TL=16
Event 8: TE=9, TL=17
Event 9: TE=8, TL=18
Event 10: TE=16, TL=23
Float for each activity:Activity 1-2: Float=0
Activity 1-3: Float=3
Activity 2-4: Float=2
Activity 3-4: Float=1
Activity 3-5: Float=0
Activity 4-9: Float=0
Activity 5-6: Float=0
Activity 5-7: Float=0
Activity 6-8: Float=7
Activity 7-8: Float=6
Activity 8-9: Float=5
Activity 8-10: Float=0
Activity 9-10: Float=0
The critical path is the sequence of activities that have zero float, meaning they cannot be delayed without delaying the project completion. The critical path for this project is: 3-4, 4-9, 5-7, 7-8, 8-10, 9-10, with a total duration of 23 weeks.Learn more about Construct Network here:
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A circular tube AB is fixed at one end and free at the other end. The tube is subjected to concentrated torques as shown in the figure. If the outer radius of the tube is 1.5in. and the thickness is 3/4in. , calculate the strain energy stored in the tube. Let G = 11800ksi.
Which of the following would zoning ordinances not address?
how tall a skyscraper can be
how much revenue a restaurant must make
how far from a school a power plant must be
how many parking spots a mall must have
look told you i made it a meme
Answer:
Dam they be thinking we racist
Explanation:
Answer:
XDDDD
Explanation:
XD I LOVE THIS MEME IM SAVING THIS TO MY GALLERY XD