Answer:
True
Explanation:
it is true because blabla bla
If 155 g of sugar can be dissolve in 100g of water at 20 degree than how much sugar will be dissolved in 300 g of water at same temperature if someone do I will make you brainly
Answer:
465 grams of sugar.
Explanation:
I'm not sure this is true: is the relationship linear?
If it is then 300 grams of water should be able told 3*155 grams of sugar
3 * 155 = 465 grams of sugar in 300 grams of water.
eporting results (1) Fifteen measurements of a resistance are quoted here based on approximately 10 repeat measurements. Only three of them obey the five golden rules. Identify the mistakes in the other results. (i) (99.8 ± 0.270) × 103 Ω, (ii) (100±0.3)× 103 Ω, (iii) (100.0±0.3)× 1039, (iv) (100.1 ±0.3) × 103, (v) 97.1 x 103-276Q, (vi) (99.8645 ± 0.2701) × 102 Ω, (vii) 98.6 x 103 ±3 × 10-Q,
The mistakes in the results include options (v) and (vii) which do not follow the five golden rules for reporting results.
What are the golden rules for reporting results?The five golden rules for reporting results are:
Always report the uncertainty in the measurement.Report the uncertainty to the same number of decimal places as the measured value.Use the correct units and prefixes.Avoid rounding until the final calculation.Report only the significant figures.Using these rules, identify the mistakes in the given results as:
(v) 97.1 × 10³ ± 276Ω - The uncertainty is reported to an inappropriate number of significant figures and the units are not consistent.
(vii) 98.6 × 10³ ± 3 × 10^(-Q) - The uncertainty is not reported to the same number of decimal places as the measured value, and the units are not consistent.
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the lanthanides and actinides belong to the
Answer:
Inner Transition Metals
Explanation:
The lanthanides and actinides belong to the inner transition metals.
Answer:
inner transition elements
Explanation:
In the periodic table to which the lanthanides and actinides metals belong to is inner transition elements because these elements are present in between transition elements.
Which of the following is not true about Triton, the large moon of Neptune? It is more reflective than Earth's Moon. It is larger than Earth's Moon. It is in a retrograde orbit. It has a thin atmosphere. It has nitrogen geysers.
Answer:
Triton is the largest of Neptune's 13 moons. It is unusual because it is the only large moon in our solar system that orbits in the opposite direction of its planet's rotation―a retrograde orbit. ... Like our own moon, Triton is locked in synchronous rotation with Neptune―one side faces the planet at all times.
A cart of mass 350 g is placed on a frictionless horizontal air track. A spring having a spring constant of 7.5 N/m is attached between the cart and the left end of the track. The cart is displaced 3.8 cm from its equilibrium position. (a) Find the period at which it oscillates. s (b) Find its maximum speed. m/s (c) Find its speed when it is located 2.0 cm from its equilibrium position.
Answer:
(a) T = 1.35 s
(b) vmax = 0.17 m/s
(c) v = 0.056 m/s
Explanation:
(a) In order to calculate the period of oscillation you use the following formula for the period in a simple harmonic motion:
\(T=2\pi\sqrt{\frac{m}{k}}\) (1)
m: mass of the cart = 350 g = 0.350kg
k: spring constant = 7.5 N/m
\(T=2\pi \sqrt{\frac{0.350kg}{7.5N/m}}=1.35s\)
The period of oscillation of the car is 1.35s
(b) The maximum speed of the car is given by the following formula:
\(v_{max}=\omega A\) (2)
w: angular frequency
A: amplitude of the motion = 3.8 cm = 0.038m
You calculate the angular frequency:
\(\omega=\frac{2\pi}{T}=\frac{2\pi}{1.35s}=4.65\frac{rad}{s}\)
Then, you use the result of w in the equation (2):
\(v_{max}=(4.65rad/s)(0.038m)=0.17\frac{m}{s}\)
The maximum speed if 0.17m/s
(c) To find the speed when the car is at x=2.0cm you first calculate the time t by using the following formula:
\(x=Acos(\omega t)\\\\t=\frac{1}{\omega}cos^{-1}(\frac{x}{A})\\\\t=\frac{1}{4.65rad/s}cos^{-1}(\frac{0.02}{0.038})=0.069s\)
The speed is the value of the following function for t = 0.069s
\(|v|=|\omega A sin(\omega t)|\\\\|v|=(4.65rad/s)(0.038m)sin(4.65rad/s (0.069s))=0.056\frac{m}{s}\)
The speed of the car is 0.056m/s
Why should you avoid bullying behavior? List 3 negative consequences from bullying behavior.
Answer:
you should avoid bullying behavior because it can physically, mentally, or emotionally harm someone else. Three consequences from bullying behavior can include: death , depression, and eventually it might get to the point where you go to jail
A Scientists want to place a 2600 kg satellite in orbit around Mars. They plan to have the satellite orbit a distance equal to 2.2 times the radius of Mars above the surface of the planet. Here is some information that will help solve this problem:
mmars = 6.4191 x 1023 kg
rmars = 3.397 x 106 m
G = 6.67428 x 10-11 N-m^2/kg^2
This What I found and calculated
time it take the satellite to complete one revolution = 9.2 hours The speed the satellite have to be in a perfectly circular orbit = 1985 m/s
Well the question I just can't get the right answer for.
What should the radius of the orbit be (measured from the center of Mars), if we want the satellite to take 8 times longer to complete one full revolution of its orbit?
The radius of the orbit, measured from the center of Mars, should be approximately 1.04 x 10^7 meters to make the satellite take 8 times longer to complete one revolution of its orbit.
What is Orbit?
In physics, an orbit refers to the path that an object takes around another object under the influence of gravity. The object being orbited can be a planet, a star, a moon, or any other massive object. The object in orbit is constantly pulled towards the center of the object being orbited, but also has a forward velocity that keeps it moving in a curved path around the object
We can start by using the formula for the period of an orbit:
T = 2π √(r^3/GM)
where T is the period, r is the radius of the orbit, G is the gravitational constant, and M is the mass of the planet.
We can solve for r:
r = [(GMT^2)/(4π^2)]^(1/3)
We know that the satellite currently takes 9.2 hours to complete one revolution, so its current period is:
T1 = 9.2 hours = 33,120 seconds
We also know that we want the satellite to take 8 times longer to complete one revolution, so its new period will be:
T2 = 8 x T1 = 265,000 seconds
We can now plug in the given values into the equation to solve for the new radius:
r = [(G x mmars x T2^2)/(4π^2)]^(1/3)
r = [(6.67428 x 10^-11 N-m^2/kg^2) x (6.4191 x 10^23 kg) x (265,000 s)^2 / (4π^2)]^(1/3)
r ≈ 1.38 x 10^7 meters
However, we were asked for the radius measured from the center of Mars, so we need to subtract the radius of Mars to find the altitude above the surface:
altitude = r - rmars = 1.38 x 10^7 meters - 3.397 x 10^6 meters ≈ 1.04 x 10^7 meters
Therefore, the radius of the orbit, measured from the center of Mars, should be approximately 1.04 x 10^7 meters to make the satellite take 8 times longer to complete one revolution of its orbit.
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An organism is prokaryotic, unicellular, and autotrophic, and it also causes disease. Which kingdom does it belong in
pls answr
Answer:
Eubacteria Kingdom :)
Explanation:
Answer: eubacteria
Explanation:
find $m\angle jkm$ . triangle j k l is shown. the measure of angle j is 3 x degrees. the measure of angle l is 41 degrees. the measure of external angle j k m is equal to 4 x plus 9 degrees.
The angle of ∠JKM is 148 degrees when given that the angle J is 3 times the angle JKL and the measure of angle L is 41degrees.
Given the angle J is = 3 x ∠JKL = 3x
Let the angle K = x degrees
The angle of ∠L = 41degrees
The measure of external angle ∠JKM = 4x+9 degrees
The measure of external angle is equal to the sum of angles opposite to that angle inside a triangle.
Then ∠JKM = ∠J + ∠L
The sum of all angles in a triangle = 180 degrees
3x + x + 41 = 180
x = 34.75degrees
Thus the angle JKM and J = 34.75degrees
So, we know that 4x+9 = 4 x 34.75 + 9 = 148degrees.
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2. A wire 4.00 m long and 6.00 mm in diameter has a resistance of 15.0 mΩ. A potential difference of 23.0 V is applied between the end. a) What is the current in the wire? b) Calculate the resistivity of the wire material. c) Try to identify the material.
Answer:
Explanation:
a )
current in the wire = potential diff / resistance
= 23 / (15 x 10⁻³ )
= 1.533 x 10³ A .
b )
For resistance of a wire , the formula is
R = ρ L / S where ρ is specific resistance , L is length and S is cross sectional area of wire
putting the given values
15 x 10⁻³ = 4ρ / π x .003²
ρ = 106 x 10⁻⁹ ohm. m
= 10.6 x 10⁻⁸ ohm m
The metal wire appears to be platinum .
(a) The current in the wire is 1.533 x 10³ A
(b) The resistivity of the wire material is 10.6 x 10⁻⁸ Ωm
(c) The material of the wire is Platinum
Ohm's Law and resistivity:
(a) According to the Ohm's Law:
V = IR
where V is the potential difference
I is the current
and R is the resistance
So,
I = V/R
I = 23 / (15 x 10⁻³ )
I = 1.533 x 10³ A
(b) The resistance of a wire is expressed as:
R = ρ L / A
where ρ is the resistivity,
L is length
and A is the cross-sectional area
15 x 10⁻³ = 4ρ / π x .003²
ρ = 106 x 10⁻⁹ Ωm
ρ = 10.6 x 10⁻⁸ Ωm
The metal from which the wire is made is platinum.
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The largest identified asteroid is Ceres and is about three times the size of the Moon.
True
or
False
\(false\)
Hope it helps you
a force acting on a body of mass 24 kg produces an acceleration of 12ms ^-2 . what acceleration will the same force produce in a body of 10 kg
please give answers if they are right and you know how to do it
Answer: a = 28,8
Explanation:
\(F = ma\)
m = 24 , a = 12
\(F=ma\\\\F = 24 x12\\\\F=288\)
Same force :
m = 10
a = ?
F = 288
\(F = ma \\\\288 = 10xa \\\\28,8=a\)
A radio station broadcasts on afrequency of 103.7 MHz. What isthe energy of the radio wave?[?] × 10^[?] J
ANSWER:
6.87 *10^-26 J
STEP-BY-STEP EXPLANATION:
Given:
f = 103.7 MHz = 103.7 x 10^6 Hz
The energy of a radio wave is given by:
\(\begin{gathered} E=hf \\ \\ \text{ h is the planck constant } \\ \\ \text{ We replacing:} \\ \\ E=(6.626\cdot10^{-34})(103.7\cdot10^6) \\ \\ E=6.87\cdot10^{-26} \end{gathered}\)the energy of the radio wave is 6.87 *10^-26 J
What does it mean for a chemical equation to be balanced?
Answer:
The number of each type of atom is the same for both the reactants and products.I hope this helps
A 1500-kg car goes around a flat 25-m-radius circular track at 10 m/s (approximately 22 mph). What is the maximum speed this car can go without sliding, in m/s? The coefficients of friction between the tire and the road on a dry day are µs = 1.0 and µk= 0.80. Use g = 10 m/s2.
The maximum speed that the car can gο arοund the circular track withοut sliding is apprοximately 27.39 m/s.
What is a fοrce?Fοrce is a physical quantity that describes the interactiοn between twο οbjects οr between an οbject and its envirοnment. A fοrce can cause an οbject tο accelerate, change directiοn, οr defοrm. Fοrce is a vectοr quantity, meaning it has bοth magnitude and directiοn. It is measured in units οf Newtοns (N).
The fοrmula fοr fοrce is:
F = ma
where F is the fοrce, m is the mass οf the οbject, and a is the acceleratiοn οf the οbject. This fοrmula is knοwn as Newtοn's Secοnd Law οf Mοtiοn. It states that the fοrce acting οn an οbject is directly prοpοrtiοnal tο its mass and acceleratiοn.
The maximum speed that the car can gο arοund the circular track withοut sliding can be calculated using the centripetal fοrce equatiοn:
Fc = mv² / r
where Fc is the centripetal fοrce required tο keep the car mοving in a circle οf radius r, m is the mass οf the car, v is the velοcity οf the car, and r is the radius οf the circular track.
Tο prevent sliding, the fοrce οf static frictiοn between the tires and the rοad must be greater than οr equal tο the maximum fοrce that can be exerted by static frictiοn, which is equal tο µs times the nοrmal fοrce (N = mg), where µs is the cοefficient οf static frictiοn and g is the acceleratiοn due tο gravity.
In this case, the centripetal fοrce required tο keep the car mοving in a circle οf radius 25 m is:
Fc = mv² / r = (1500 kg) x (10 m/s)² / (25 m) = 6000 N
The maximum fοrce οf static frictiοn that can be exerted between the tires and the rοad is:
Ff = µs x N = (1.0) x (1500 kg) x (10 m/s² ) = 15000 N
Tο find the maximum speed that the car can gο withοut sliding, we need tο find the velοcity that cοrrespοnds tο a centripetal fοrce οf 15000 N:
Fc = mv² / r = (1500 kg) x (vmax)² / (25 m) = 15000 N
Sοlving fοr vmax, we get:
vmax = sqrt(15000 N x 25 m / 1500 kg) = 27.39 m/s
Therefοre, the maximum speed that the car can gο arοund the circular track withοut sliding is apprοximately 27.39 m/s.
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Electric Forces need help will mark brainliest.
The net electric force on charge q1 is 15.47 N towards the left.
What is the net electric force on q1?The net electric force on charge q1 is calculated by applying Coulomb's law of electrostatic force.
F(net) = F(12) + F(13)
The force on q1 due to charge 2 is calculated as;
F(12) = (9 x 10⁹ x 8.99 x 10⁻⁶ x 5.16 x 10⁻⁶ )/(0.22²)
F(12) = 8.63 N
The force on q1 due to charge 3 is calculated as;
F(13) = -(9 x 10⁹ x 8.99 x 10⁻⁶ x 89.9 x 10⁻⁶ )/(0.55²)
F(13) = -24.1 N
The net force on q1 is calculated as;
F(net) = -24.1 N + 8.63 N = -15.47 N
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What is the magnitude of the gravitational force of attraction be-
tween two asteroids in space, each with a mass of 50,000 kg,
separated by a distance of 3800 m?
Question 4 (1 point)
Having the ability to play or stay active longer without getting tired explains which
Health-Related Fitness Component?
cardiovascular endurance :))
A mini copper of mass 1350kg is travelling at speed of 100km/hr and travel at a distance of 45 m before coming to rest . Determine the magnitude of the net force required to bring the machine to rest and state the direction with regards to initial velocity
Answer:
The net force required to bring the car to rest is 11,900 N. Since the car is slowing down, the direction of the net force must be opposite to the initial velocity. Therefore, the direction of the net force is opposite to the initial direction of the car's motion.
Explanation:
First, we need to convert the speed from km/h to m/s:
100 km/h * (1000 m/km) / (3600 s/h) = 27.78 m/s
The initial kinetic energy of the car is:
KE = (1/2) * m * v^2
KE = (1/2) * 1350 kg * (27.78 m/s)^2
KE = 535,500 J
To bring the car to a stop, the net force applied over the distance traveled must equal the initial kinetic energy. So:
work done = force * distance = KE
Rearranging this equation, we get:
force = KE / distance
Substituting the values we have, we get:
force = 535,500 J / 45 m
force = 11,900 N
The net force required to bring the car to rest is 11,900 N. Since the car is slowing down, the direction of the net force must be opposite to the initial velocity. Therefore, the direction of the net force is opposite to the initial direction of the car's motion.
why fan videos be streamed from the cloud to a computer with no lost quality
Videos can be streamed from the cloud to a computer with no loss in quality because Digital signals are used to transmit data to and from the cloud.
How do digital signals work?
An established or one that represents data as a step made up of discrete values is known as a digital signal. There is no noise produced by digital signals. Electronic signals sent as pulses are used to transmit digital signals to computers. These signals can be found in things like digital phones and computers.
Because digital signals are used to transport data to and from the cloud, it should be noted that videos are said to stream from the cloud to a computer without quality degradation.
Videos can be streamed from the cloud to a computer with no loss in quality because Digital signals are used to transmit data to and from the cloud.
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5. A tennis player hits a ball when it is at a height of 1.1 meters above the court, giving it a velocity of 12 m/s at an angle of 22° above the horizontal towards the net. The net is 1.81 meters high and stands 2.6 meters from the player.
a) Show that the ball will just pass over the net.
b) Find when and where the ball hits the ground.
According to the information, the ball will just pass over the net (question A); and the ball hits the ground approximately at 7.04 meters from the player and after a time of flight of approximately 1.31 seconds (question B).
How to determine if the ball will clear the net?To determine if the ball will clear the net, we compare the vertical displacement of the ball with the net height. The ball's initial height is 1.1 meters, and it reaches its highest point during flight. By calculating the trajectory, we can confirm that the ball's vertical displacement at its highest point will be higher than the net height of 1.81 meters, ensuring it clears the net.
How to find when and where the ball hits the ground?To find when and where the ball hits the ground, we need to calculate the time of flight and horizontal displacement. Using the given initial velocity and angle, we can determine the time it takes for the ball to reach the ground. By calculating the horizontal displacement based on the initial horizontal velocity and total time of flight, we find that the ball hits the ground approximately 7.04 meters from the player. The time of flight is approximately 1.31 seconds. The specific values may vary depending on the given initial conditions.
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an ideal gas is flowing in a constant diameter pipe at a constant temprature. what is the relation of average velocity to pressure
Answer:
V = mRT / (\(\frac{\pi }{4}\)d²)PM
Therefore, pressure decreases as velocity increases.
This is a hypothetical concept as the friction which causes the velocity to increases also makes the pressure decrease.
Explanation:
Given the data in the question;
we know that an ideal gas equation is;
\(_p\) = PM/RT --------------- let this be equation 1
P is pressure, M is molecular weight, R is universal gas constant and T is the absolute temperature.
The volumetric flow rate from the continuity equation is;
Q = AV
and A = \(\frac{\pi }{4}\)d²
so, Q = (\(\frac{\pi }{4}\)d²)V ---------let this be equation 2
Expression for mass m in flowrate is;
m = Q\(_p\) ------------------let this be equation 3
so, m = (\(\frac{\pi }{4}\)d²)V × PM/RT
solve for V
V = mRT / (\(\frac{\pi }{4}\)d²)PM
Therefore, pressure decreases as velocity increases.
This is a hypothetical concept as the friction which causes the velocity to increases also makes the pressure decrease.
1.) Consider the graph shown to the right. The two lines denote the motion of two different objects which move in the x direction only.
2.) Five vectors, A, B, C, D, E are shown at the right. Which of the combinations below has the largest magnitude ?
Graph is shown in the picture, please help!
The change in position of an object over time is known as velocity. The thing in question is traveling correctly. Vector c has the largest magnitude of all the vectors. And as demonstrated, a half-arrow can be used to represent this vector.
What are some types of objects?Everything that is readily apparent or palpable and has a stable form. An object of study in medicine is anything, anyone, or anything to which action or thinking is focused.
What is a kid-friendly object?A person or thing that the verb directs its action toward is called an object. A noun, pronoun, or noun phrase that is impacted by the action verb is referred to as an object. A sentence is also finished by it.
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What is the same about Jupiter and the earth ?
The characteristics that is same about Jupiter and Earth is as follows:
They are approximately sphericalThey revolve around the Sun and rotate around their own axisThey follow elliptical orbitsThey have irregular surfacesThey have an atmosphereWhat is Earth and Jupiter?Earth and Jupiter are part of the nine planets of the solar system.
Some of the differences between them are as follows:
Jupiter is a gas giant with no discernible solid surface, while Earth is a terrestrial planet. Jupiter's primary atmosphere consists of hydrogen and helium, while Earth's atmosphere is composed of a mix of oxygen and nitrogen and other chemicals.Jupiter has a mass more than 2.5 times the mass of all other planets in the solar system. Earth has life, but Jupiter doesn'tHowever, the little ways in which they are alike is as illustrated above in the main answer part.
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PLEASE HELP ME I DONT UNDERSTAND THIS
Answer:
A) compression B) rarefaction C) wavelength
Explanation:
What is the acceleration of a car that starts at rest and achieves a final velocity of 33.5 m/s in a time of 12 seconds?
Variables we are given and that we know:
vi: initial velocity; vi = 0 m/s
vf: final velocity; vf = 33.5 m/s
t: time; t = 12 s
We need to find a: acceleration
We can use the formula:
vf = vi + a*t
Let's substitute the values we know:
33.5 = 0 + a*12
33.5 = 12a
Let's solve for a:
a = 33.5/12
a = 2.7917 m/s^2
How many minutes would be required for a 300.0 W (i.e., power=energy per second=300 J/s)
immersion heater to heat 0.25 kg of water from 20.0°C to 100.0°C? (Note: The specific heat of water
is 4184 J/kg°C)
Hence, the time required is approximately equal to 4 minutes and 39 seconds.
Given, Power, P = 300 W= 300J/s
Power= Energy per second
Mass, m= 0.25 kg
Initial Temperature= 20.0°C
Final Temperature= 100.0°C
Temperature difference, T =( 100-20)°C= 80.0°C
Specific heat of water, S= 4184 J/kg°C
Energy can be represented as
E=mST
where E is the energy, m is the mass, S is the specific heat of water and T is the temperature difference.
As Energy can be written as the product of time and power, E=Pt
Pt=mST
So,
t=(msT)/P
t=(0.25×4184×80)/300
Time, t = 278.934 seconds= 4 minutes and 39 seconds.
Hence, 4 minutes and 39 seconds will be required for a 300.0 W immersion heater to heat 0.25 kg of water from 20.0°C to 100.0°C.
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Help pls. Edge 2021- Motion in space
Collaboration is critical to successful product design, and with Solid Edge, OEMs and suppliers can improve and manage collaboration across design teams, regardless of location. By reducing design revisions and communication delays, our customers enjoy quicker time-to-market and increased profitability.
Controlling the amount of current in a circuit by opposing the flow of charge
is a function of which circuit component?
A. Battery
B. Transistor
C. Resistor
D. Capacitor
Answer:
Resistor provides resistance to the flow of electric current in a circuit. It controls the amount of current in a circuit by acting as a barrier to the flow of electric charges
Explanation:
Keyana and Sam are testing the law of conservation of energy. They use the same ball and release it from the same vertical height. Keyana is using a frictionless track, while Sam's track has friction. They discover Keyana's ball had more kinetic energy than Sam's when it reached the bottom. Which statement best explains why this happened if energy is conserved? Sam's ball lost mass as it traveled along the track. Sam's ball interacting with the track converted energy into heat. Keyana's ball was able to gain momentum. Keyana's ball had more potential energy.
The true statement is "Sam's ball interacting with the track converted energy into heat." The correct option is B.
The law of conservation of energy states that energy cannot be created or destroyed, only transferred or converted from one form to another. This means that the total amount of energy in a closed system remains constant.
The friction between Sam's ball and the track caused some of the energy to be lost as heat, while Keyana's ball experienced no such loss due to the absence of friction in her experiment. Therefore, Keyana's ball retained more of its initial potential energy as kinetic energy, resulting in a greater velocity and hence more kinetic energy at the bottom.
Option A (Sam's ball lost mass as it traveled along the track) is not true because it is not possible for the ball to lose mass during the experiment. The mass of the ball is a constant value and is not affected by the experiment.
Option C (Keyana's ball was able to gain momentum) is not the best explanation because momentum is not conserved in this scenario since external forces like friction are acting on the ball. The ball is only gaining kinetic energy.
Option D (Keyana's ball had more potential energy) is not true because both Keyana and Sam released the ball from the same vertical height. Therefore, both balls had the same initial potential energy. The difference in their kinetic energies at the bottom can be explained by the difference in their conservation of energy due to friction.
Therefore, The correct statement that best explains why Keyana's ball had more kinetic energy than Sam's when it reached the bottom, even though energy is conserved, is: Sam's ball interacting with the track converted energy into heat.
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