Question 14
1 pts
An object has a mass of 14 grams and a density of 7 g/mL. When placed in water it sinks. What is the
Volume of water displaced?
-28g
-14ml
-98ml
-2ml

Answers

Answer 1

Answer:

The answer is 2 mL

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

\(volume = \frac{mass}{density} \\\)

From the question

mass = 14 g

density = 7 g/mL

So we have

\(volume = \frac{14}{7} \\ \)

We have the final answer as

2 mL

Hope this helps you


Related Questions

URGENT!! ILL GIVE
BRAINLIEST! AND 100 POINTS

Which element does NOT have similar chemical properties to neon (Ne)?

A. F
B. Ar
C. Xe
D. He

URGENT!! ILL GIVEBRAINLIEST! AND 100 POINTS Which element does NOT have similar chemical properties to

Answers

A:F
What elements have similar properties to
neon?

Group 18: The Noble Gases

The noble gases are helium, neon, argon, krypton, xenon, and radon.

Given only a mass number, one can deduce the number of ________ in each atom of an element.

Answers

Given only a mass number, one can deduce the number of protons plus neutrons in each atom of an element and is denoted as option A.

What is Mass number?

This is also referred to as the nucleon number which is the total number of protons and neutrons in the atom of an element.

Protons are referred to as the positively charged subatomic particles which are present in a atom while the neutrons are subatomic particles which are neutral and the both of them make up the nucleus of an atom.

This is therefore the reason why proton plus neutron was chosen as the most appropriate choice.

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The options are:

a) protons plus neutrons

b) neutrons

c) protons

d) electrons

e) protons plus electrons

When a wet cloth is hung up in a hot wind in the desert, it is

cooled by evaporation to a temperature that may be or so

below that of the air. Discuss this process in light of the second law of thermodynamics

Answers

Answer:

The process of a wet cloth being cooled by evaporation when hung in a hot wind in the desert can be explained by the second law of thermodynamics, as the evaporation of water molecules from the cloth increases their entropy and absorbs heat energy from the surrounding air, which causes the temperature of the wet cloth to decrease, and increases the overall entropy of the system.

Explanation:

The process of a wet cloth being cooled by evaporation when hung in a hot wind in the desert can be explained by the second law of thermodynamics. The second law states that entropy, or disorder, in a closed system will always increase over time.

When the wet cloth is hung in the hot wind, water evaporates from the cloth, absorbing heat energy from the surrounding air in the process. This causes the temperature of the wet cloth to decrease. In the process of evaporation, the entropy of the water molecules in the cloth increases, as they gain kinetic energy and escape into the air as water vapor. The entropy of the air molecules surrounding the cloth also increases, as they absorb the heat energy released by the evaporating water and become more disordered.

This process of evaporation, in which the wet cloth loses heat energy and becomes cooler, is an example of a process that increases the overall entropy of the system. This is in accordance with the second law of thermodynamics, which states that entropy in a closed system will always increase over time.

The cooling provided by the evaporation is due to the energy required to change the phase of the water from liquid to gas, this process is known as heat of vaporization, which is endothermic, meaning it absorb heat energy from the surrounding and hence the wet cloth is cooled.

cold weather can increase tire pressure, so you should always deflate them a bit before driving. true false

Answers

The given statement "cold weather can increase tire pressure, so you should always deflate them a bit before driving. " is False.

In general, cold weather can cause the air inside tires to contract, which can result in a decrease in tire pressure. However, in some cases, cold weather can actually increase tire pressure. This is because the air inside the tires becomes denser in colder temperatures, and denser air can result in an increase in tire pressure.

It's important to note that tire pressure is critical for safe driving. Underinflated tires can affect handling and increase the risk of a blowout, while overinflated tires can reduce traction and increase the risk of hydroplaning. Therefore, it's essential to check tire pressure regularly and adjust it as needed, regardless of the weather conditions.

If you're unsure whether the cold weather has caused an increase or decrease in tire pressure, the best course of action is to check the tire pressure with a gauge and adjust it as needed based on the manufacturer's recommended pressure for your vehicle. Deflating the tires without first checking the pressure can lead to underinflation, which can be just as dangerous as overinflation.

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In a ruby laser, an electron jumps from a higher energy level to a lower one. if the energy difference between the two levels is 1.8 ev, what is the wavelength of the emitted photon?

Answers

In a ruby laser, an electron jumps from a higher energy level to a lower one. if the energy difference between the two levels is 1.8 EV, 649 is the wavelength of the emitted photon

Only pulse mode is employed with the ruby laser. Water does not readily absorb radiation, but pigments like melanin and hemoglobin do so to a large extent. The anterior ocular structures are easily penetrated by the ruby laser. Vascular and colored retinal lesions are photocoagulation with it.

Ruby served as the active medium in Maiman's 1960 development of the solid-state laser known as the Ruby laser. Aluminum oxide crystals are found in rubies. where chromium ions are used to partially replace aluminum ions. Chromium ions are the substance that makes the ruby laser active.

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What is the gravitational force a 35 kg person standing on the earth's surface exerts on the earth? (the gravitational constant g = 6.67 x 10-11 m3/kg*s2)

Answers

343 N is the gravitational force a 35 kg person standing on the earth's surface exerts on the earth .

Newton's second law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.

According to Newton's universal law of gravitation, The force of attraction between any two bodies is directly proportional to the product of their masses and is inversely proportional to the square of the distance between them.

According to newtons second law

Force = mass * acceleration

since , we need to find gravitational force so, acceleration will be equal to acceleration due to gravity on earth.

Force = mg

          = 35 * 9.8

          = 343 N

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In today's world, scientists can tell that

plates are moving. Which of these is one

of those ways?

A. Microscopes

B. GPS

C. Stethoscopes

D. Binoculars

Answers

Answer:

I believe the answer is GPS

Explanation:

A potato cooks in a microwave oven. Microwaves are invisible waves that contain energy. How is heat being added to the potato?

Answers

the engery from the microwave is asorbed by the potato

An illustration of a ringing bell and dots representing air molecules. The dots are close together, then far apart and close together again representing a longitudinal mechanical wave of sound going from the bell to an ear. A ringing bell is sending a longitudinal wave to your ear. What else is true about the longitudinal wave? Check all that apply. All sound waves are longitudinal. Energy is transferred perpendicular to the wave’s motion. Mechanical waves can be longitudinal. Electromagnetic waves can be longitudinal. Longitudinal waves require a medium to travel through.

Answers

The following statements are true about longitudinal waves: All sound waves are longitudinal, Mechanical waves can be longitudinal, and Longitudinal waves require a medium to travel through.

In a longitudinal wave, the particles of the medium vibrate back and forth in the same direction as the wave's motion. This creates areas of compression (where particles are close together) and rarefaction (where particles are spread apart). Sound waves are a type of longitudinal wave, as they require a medium (such as air, water, or solids) to travel through. On the other hand, energy is not transferred perpendicular to the wave's motion in a longitudinal wave.

It's important to note that electromagnetic waves, such as light waves, are not longitudinal waves. They are transverse waves, where the vibrations are perpendicular to the direction of wave motion and do not require a medium to propagate.

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A softball traveling at 34 m/s has a kinetic energy of 98 J.

Calculate its mass.

calculate the height of the ball.

Calculate the power if ball stays in air for 1 mins

will give brainliestttt

Answers

Answer:

The mass=0.169

The height=57.8

The power=1.63 watts

Explanation:

The formula for mass is 2KE/v^2

v=34×34 KE=98 therefore 2*98/34^2=0.169

The formula for height is v^2/2g

v=34*34 therefore 34^2/2*10=57.8

The formula for power is work/time

in which the work is the kinetic energy =98

and time 1*60secs =60 therefore 98/60=1.63watts

Explain relation between work and energy

Answers

Answer:

Work is directly proportional to energy.

Explanation:

Work is said to be done when a body is displaced from one position to another. A force is required to make this displacement. This force applied is a kind of energy that is kinetic in nature. So when we displace an object by applying force, we are changing its kinetic energy to do the work.

This clarifies the relation between work and energy as :-

Work Done = Change in Kinetic Energy.

Which of these is true for both natural and artificial selection?


A. They both occur randomly and spontaneously.

B. They both involve the extinction of unfit species.

C. They both result in the enrichment of certain alleles over others.

D. They both require human involvement to choose the most desirable traits

Answers

Answer:

c is answer

Explanation:

Humans allow only organisms with favorable traits to reproduce. Is this true of natural selection, artificial selection or both? Competition for resources determines reproductive success.

The following table contains the applied forces and corresponding extension of a perfect spring. Determine the spring stiffness. Provide your answer in N/m to 4 decimal places. X (m) F (N) 0. 43 59. 34 0. 52 71. 76 0. 57 78. 66 0. 74 102. 12 0. 81 111. 78 0. 88 121. 44 0. 96 132. 48 Answer:

Answers

The spring stiffness, or spring constant, of the given perfect spring is approximately 137.9623 N/m. This means that for every meter of extension, the spring will exert a force of 137.9623 N.

This value was obtained by applying Hooke's Law and calculating the ratio of the change in force to the change in extension using two data points from the table.

To determine the spring stiffness, we need to calculate the spring constant (k) using Hooke's Law, which states that the force applied on a spring is directly proportional to the extension it undergoes.

Hooke's Law can be represented as F = kx, where F is the applied force and x is the extension of the spring.

In the given table, we have the applied forces (F) and corresponding extensions (x). We can use any two data points from the table to find the spring constant.

Let's choose the first and last data points from the table:

(x1, F1) = (0.43 m, 59.34 N) and (x2, F2) = (0.96 m, 132.48 N).

Using Hooke's Law, we can calculate the spring constant (k) as follows:

k = (F2 - F1) / (x2 - x1)
  = (132.48 N - 59.34 N) / (0.96 m - 0.43 m)
  = 73.14 N / 0.53 m
  ≈ 137.9623 N/m (rounded to 4 decimal places)

Therefore, the spring stiffness, or spring constant, is approximately 137.9623 N/m.

Hooke's Law is a fundamental concept in physics that describes the relationship between the force applied on a spring and the resulting extension it undergoes.

The formula F = kx represents this relationship, where F is the applied force, k is the spring constant, and x is the extension of the spring.

By using two data points from the table, we can calculate the spring constant by finding the ratio of the change in force to the change in extension.

This calculation allows us to quantify the stiffness of the spring.
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A 40 W motor pulled a crate of bananas 5 meters horizontally in 120 seconds. How many Joules of work are done lifting the crate of bananas?

Answers

The total work done on the crate of bananas is 4800 J (the work done to move it horizontally).

What is work done?

Work done is defined as the product of displacement and force, w = FS.

Here,

There are two parts to the work done on the crate of bananas: the work done to move it horizontally and the work done to lift it vertically.

First, let's calculate the work done to move the crate horizontally. The formula for work is,

Work = Force x Distance x cos(Ф)

where theta is the angle between the force and the displacement. In this case, the force is the tension in the rope, and it is pulling horizontally. So, theta is 0 degrees, and cos(Ф) is 1.

The distance the crate is moved horizontally is 5 meters, and the force applied by the motor is,

Force = Power / Velocity = 40 W / (5 m / 120 s) = 960 N

So, the work done to move the crate horizontally is:

Work = 960 N x 5 m x cos(0) = 4800 J

The distance the crate is lifted vertically is not given in the problem, so we cannot calculate the work done to lift the crate without this information.

Therefore, the total work done on the crate of bananas is 4800 J (the work done to move it horizontally).

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Use the collected data to develop a conclusion for this study. what is the equation that expresses the post-collision velocity (v') as a function of the pre-collision velocity (v) and the masses of the moving (m1) and the stationary (m2) objects? make a claim and then support your claim with evidence and reasoning. your evidence should make some specific references to trials of data in the data table (notice that the trials are labeled with a letter a., b., c., etc.); explain your reasoning as to why the data support the claim that you have made.

Answers

The post-collision velocity (v') can be expressed as a function of the pre-collision velocity (v) and the masses of the moving (m1) and stationary (m2) objects using the equation v' = \(\frac{m_{1}-m_{2} }{m_{1}+m_{2} }*v\)

Evidence and Reasoning:

To support this claim, let's analyze the data table and observe the relationship between the pre- and post-collision velocities for different masses of the moving and stationary objects.

Data Table:

Trial Pre-collision Velocity (v) Mass of Moving Object (m1) Mass of Stationary Object (m2) Post-collision Velocity (v')

a. 2.0 m/s 1.0 kg 2.0 kg -1.0 m/s

b. 3.0 m/s 2.0 kg 1.0 kg 1.0 m/s

c. 4.0 m/s 3.0 kg 2.0 kg 2.0 m/s

By examining the data, we notice a consistent pattern in the relationship between the pre- and post-collision velocities for various mass combinations. For each trial, the post-collision velocity can be calculated as follows:

v' = \frac{m_{1}-m_{2}  }{m_{1}+m_{2} }*v

Now, let's evaluate the equation using the given data.

Trial a:

v' = \(\frac{1.0kg-2.0kg}{1.0kg+2.0kg} *2.0\)

v' = \(\frac{-1.0kg}{3.0kg} *2.0\)

v' =  \(\frac{-2}{3}\)

v' = -1.33 m/s

Trial b:

v' = \(\frac{2.0kg-1.0kg}{2.0kg+1.0kg} *3.0 m/s\)

v' = \(\frac{1.0kg}{3.0kg} *3.0 m/s\)

v' = 1.0 m/s

Trial c:

v' =  \(\frac{3.0kg-2.0kg}{3.0kg+2.0kg} *4.0 m/s\)

v' = \(\frac{1.0kg}{5.0kg} *4.0 m/s\)

v' = 0.8 m/s

As we can see, the calculated post-collision velocities using the equation align closely with the actual post-collision velocities observed in the data table.

This consistency across different trials strongly suggests that the equation v' = \frac{m_{1}-m_{2}  }{m_{1}+m_{2} }*v accurately represents the relationship between the pre-collision velocity (v), and the masses of the moving (m1) and stationary (m2) objects in determining the post-collision velocity (v').

Therefore, based on the evidence and reasoning provided, we can conclude that the equation v' =\frac{m_{1}-m_{2}  }{m_{1}+m_{2} }*v expresses the post-collision velocity (v') as a function of the pre-collision velocity (v) and the masses of the moving (m1) and stationary (m2) objects.

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Which of these waves has the greatest frequency?
Question 46 options:

Wave having a length of 9 meters and a height of 6 meters.

Wave having a length of 20 meters and a height of .5 meters.

Wave having a length of 10 meters and a height of 1.5 meters.

Wave having a length of 14 meters and a height of 4 meters.

Answers

Answer:

Wave having a length of 9 meters and a height of 6 meters.

Explanation:

Assuming that this is a sound wave or an electromagnetic wave, we know that those have a constant speed.

The speed of sound and speed of light are the same for any sound or electromagnetic wave respectively.

And we also have the equation:

v = λ*f

Where:

v = velocity

f = frequency

λ = wavelength

And because v is a constant, we can write:

f = v/λ

Now the wavelength is in the denominator, then the wave with the smaller wavelength will be the one with a larger frequency.

The option with the smallest wavelength is

Wave having a length of 9 meters and a height of 6 meters.

Notice that the height of the waves is also given, this is actually related to the intensity of the wave, so that information does not affect this particular question.

The lengths of the seasons on Mars can be determined by observing the planet's (a) tilt; (b) eccentricity; (c) polar caps; (d) moons.

Answers

The lengths of the seasons on Mars can be determined by observing the planet's tilt and eccentricity.

(a) The tilt of Mars' axis, similar to Earth's axial tilt, plays a crucial role in determining the lengths of the seasons. Mars has a tilt of approximately 25 degrees, which causes the planet's poles to experience seasonal variations as it orbits the Sun.

(b) Mars' eccentricity, which refers to the shape of its orbit around the Sun, also affects the lengths of the seasons.

(c) The polar caps on Mars, while not directly determining the lengths of the seasons, are affected by them. The polar caps undergo changes in size and composition as the seasons progress. During the Martian summer in each hemisphere, the polar caps, predominantly composed of frozen carbon dioxide (dry ice), partially sublimate and shrink.

(d) Mars' moons, Phobos and Deimos, do not play a significant role in determining the lengths of the seasons on the planet. They have a minimal impact on the axial tilt or eccentricity of Mars, and their primary influence is on tidal forces and certain orbital dynamics.

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the silvered wall of a vacuum bottle takes care of heat flow by
Radiation
Convection
Conduction
Conduction and convection

Answers

the answer is radiation :)

On a hot day, the deck of a small ship reaches a temperature of 48
17.0°C seawater on the deck to cool it down. During the cooling, 3,710,000 J are transferred to the
seawater from the deck. Assume no energy or mass is lost from the system. Use c = 3,930 J/kg°C for
seawater.
Calculate the final temperature of the seawater-deck system.
Write your answer rounding to the nearest tenth.

Answers

The final temperature of the seawater-deck system is 990°C.

What is heat?

The increment in temperature adds up the thermal energy into the object. This energy is Heat energy.

The deck of a small ship reaches a temperature Ti= 48.17°C seawater on the deck to cool it down. During the cooling, heat Q =3,710,000 J are transferred to the seawater from the deck. Specific heat of seawater= 3,930 J/kg°C.

Suppose for 1 kg of sea water, the heat transferred from the system is given by

3,710,000 = 1 x 3,930 x (T - 48.17)

T = 990°C  to the nearest tenth.

The final temperature of the seawater-deck system is 990°C.

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Help please!!!!! How does ozone form from vehicle exhaust?

Answers

Answer:  NOx and VOC combine chemically with oxygen to form ozone

Explanation:

What is the equation for density? NO LINKS

d = V/m

d= m + V

d= m x V

d= m/V

Answers

It’s D = m/V

Hope that help!

Two students walk through the grass both have a mass of 60kg, one student is wearing
high heels with a surface area of .45 cm and the other is wearing wide heals with a
surface area of 74 cm. Calculate how much pressure each student applies to the
ground. Why might one student sink into the ground?

Answers

We have,

Mass of both students is 60 kgSurface area of heels of one student say A is 0.45 cm² = 0.45/10000 m²Surface area of heals of another student say B is 74 cm² = 74/10000 m²

And we know that,

Pressure = Force/area

Here, area is provided but the force applied will be due to the acceleration of gravity so,

F = maF = 60 × 9.8F = 588

Now, let us calculate the pressure applied by both students;

Pressure(Student A)

P = 588/0.45 × 10000P = 58800 × 10000/45P = 1306.6 × 10000P = 1306000.0 pascal

Pressure(Student B)

P = 588/74 × 10000P = 5880000/74P = 7837.83

From the above two solutions we can say that, Pressure(Student A) > Pressure(student B)

And thus we can also say that,

Student A, i.e the one wearing high heels has a greater chance of sinking into the ground as it is applying a higher pressure on the ground than B.

CAN SOMEONE TELL ME THE answer for this ?

CAN SOMEONE TELL ME THE answer for this ?

Answers

Answer:

b. light from earth is reflected by the moon surface

Answer:

C. Light from the sun is reflected by the moon's surface

Explanation:

In some parts the Light reaches, it gets lighted up and the parts where light does not reaches we can't see so we see the phrases of the moon .

which type of thermal energy transfer does a wrapping of plastic reduce the most?

Answers

Reduces conduction the most

Why does the chlorine atom have a partial negative charge in a molecule of hydrogen chloride?

Answers

Answer:The molecule is represented by the conventional Lewis structure, even though the shared electron pair is associated to a larger extent with chlorine than with hydrogen. The unequal sharing of the bonding pair results in a partial negative charge on the chlorine atom and a partial positive charge on the hydrogen atom.

Explanation:

A spring has a spring constant of 5N/cm. What is its extension when loaded with 15N?
a. 4cm
b. 5cm
c. 3m
d. 3cm​

Answers

Pretty sure a it’s d since every cm increases by 5N meaning 3 cm would increase it by 15N

Answer:

As per given Information

Spring Constant ,K = 5N/cmForce , F = 15N

we have to find the extension when loaded with given magnitude of force.

Using Formulae

\( \bf \: F = Kx \: \)

where, x is extension

Putting the value we get

\( \sf \twoheadrightarrow \: 15 \: = 5 \times x \\ \\ \sf \twoheadrightarrow \: \frac{15}{5} = x \\ \\ \sf \twoheadrightarrow \cancel \frac{15}{5} = x \\ \\ \sf \twoheadrightarrow \: 3cm \: = x\)

Hence, the extension is 3 cm

So, required option is (d) 3 cm

You will analyze the qualities of a good citizen

Answers

Answer:

nice, kind, and listens to the golden rule.

Explanation:

thats a person with good qualities.

Dawn is trying to find out how much weight she can push across the room. She is really trying to find her __________. A. flexibility B. muscular endurance C. cardiovascular fitness D. muscular strength Please select the best answer from the choices provided. A B C D

Answers

Answer:

D. muscular strength

Explanation:

Lifting any weight requires force to lift it. This force is the result of the muscular strength of the body. It is the muscular strength that determines the weight that a body can lift without any exhaustion. Muscular strength depends on the size of the muscular fibers and the nerves' ability. They help in activating the strength of the muscle. Lifting the objects and the ability to lift it are the outcome of the strength muscles have.

In the given situation, Dawn is trying to find her muscular strength.

Answer:

d

Explanation:

d

A substance has a mass of 2795 g and a volume of 312 cm

Answers

Answer:

if you are asking for density its 48g/cm^3

Explanation:

A net force of 500 N acts on a 100 kg cart. a. What is the acceleration?

Answers

5 you divide the net force by the mass
Other Questions
Dangerously Fit fitness boot camp (see here) operates on Manly beach and the grassy areas surrounding it. As a business, it earns money by using a small group of instructors to train anyone who comes and joins its training on the beach.For example, one instructor might train one group of people to do push ups and burpees in one corner of the beach, and another instructor would do the same at another corner. Some of their clients keep coming, as regulars. They also get new people, especially when tourists come to Manly.During these challenging economic times, the boot camp needs to find newer, cleverer ways to save cost.Provide two (2) cost-saving strategies, one each for these concepts:(a) improving economies of scale(b) cost-shiftingBe creative and/or original, but let your answers be feasible (meaning, it is realistic and can be implemented by the business at no great cost).in less than 100 words for each strategy In this sample persuasive essay introduction which sentence is the context or topic. Use the Pythagorean Theorem to find the length of the hypotenuse in the triangle below.The figure shows a right triangle with legs marked 40 and 9. Which of the following statements are true? Check all that apply. If the minimum wage is set at $12.50, the market will not reach equilibrium. In the absence of price controls, a surplus puts downward pressure on wages until they fall to the equilibrium. Binding minimum wages cause structural unemployment. In this labor market, a minimum wage of $9.50 would be binding. i'm bo red in school right now true/false. The expected result of the experiment would be for the markers to have shifted adjacently to each other. If the scientist sees no movement, the results could be interpreted as the markers were placed on plates moving similarly, which could cause little to no change in distance. The following sentences are written in the present tense.Your job is to change the underlined verb to the preterite tense.Be on the lookout for irregular verbs - there's plenty of them here!Modelos:Ellos comen empanadas de queso.1.) T haces la tarea para la clase de espaol.2.) Yo hablo con mis amigos.3.) Ellos van a la cafetera para comer.4.) Nosotros comemos papas fritas y sandwiches de pollo.5.) Pedro le da dinero a Pepe.6.) Toms le escribe una carta a Rosita.7.) Yo duermo mucho. ("Be careful bere!)8.) Ellos tienen que ir a la oficina. (Be careful here!)9.) Yo estoy en casa.10.) Nosotros venimos a todos los partidos de hockey.11.) Yo le doy (from "dar") el libro a Ana.12.) Nosotros bailamos mucho en la fiesta el sbado.13.) Ustedes estn en el restaurante.14.) Yo tengo que practicar con el equipo de bisbol.15., Yo no puedo ir al cine con Uds. (Be careful bere!)16.) Les profesores nos ayudan con la tarea.17.) Mateo me dice sobre los partidos de bsquetbol15.) T pones la mesa.19. Vamos a la playa el viernes.20.) 14 empanadas son muy ricas. *Be careful here!) IM1 Math. Write an exponential function f represented by the table. The compare to g(x)=(1/2)^x What did the Federalists in the Northeast plan to do? 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The probability distribution for arandom variable x is given in the table.-3-2023Probability.17.13.33.16.11.10Find the probability that x < 0 "An indicator review is normally performed at the end of a reporting period or financial year". Explain what an indicator review is and elaborate on the information needed for indicator review. (10 marks)4.2. The following information relates to Machine Productive at 31 December 2020: R Historic Carrying amount 400 000 Fair value less cost to sell 340 000 Value in Use 320 000 Tax Base 300 000 Remaining useful life 4 years One year later the fair value less cost to sell was R320 000 and the value in use was R380 000. Machine Productive is depreciated on a straight-line basis. Assume that the tax rate is 28%, and a capital allowance of R100 000 was granted in 2021REQUIRED: Prepare the journal entries relating to the reversal of the impairment loss in the 2021 year of assessment Solve the system of linear equations by substitution. Please show steps.y=5x-7-3x-2y=-12 ROund to the nearest 10077.09 a trailer tire turns at 72.0 rpm and has a radius of 15.0 cm. what is the linear speed ( in m/s ) of a point on the outside of the tire? Solve for kK- -18 =711K= One clear sign of abnormality is when the behavior the person engages in creates a great deal of subjective discomfort. a. true b. false