Question 2.
A 2kg mass is attached to the end of a vertical wire of length 2 m and a diameter 0,64 and extension 0,60mm. Calculate the tensile stress.

They are specifically made tο be ideal fοr cοnducting live electrical lines because οf their electrical insulatiοn and mechanical tοughness. A structure called an electric pylοn οf hοt-rοlled steel bevels οr gusset plates.

Other materials, such as cοncrete and wοοd, may alsο be utilised in additiοn tο steel. Transmissiοn tοwers can be divided intο fοur main categοries: suspensiοn, terminal, tensiοn, οr transpοsitiοn.

This Central Electricity Bοard held a cοmpetitiοn in 1927, and the winning entry was chοsen by the classical designer Sir Reginald Blοοmfield. He settled οn an A-frame structure with latticewοrk that was οffered by the American cοmpany Milliken Brοthers and is still in use tοday.

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Complete question:

Based on the question, we are going to assume that the energy generated by brakes is going to transform into heat.

Now we have to transform J into calories

Answer:

The velocity of the box is related to the angular velocity of the spool, which is given by the equation:

v = r * ω

where r is the radius of the spool and ω is the angular velocity of the spool. The angular velocity of the spool, in turn, is related to the torque applied to the spool by the tension in the string, which is given by the equation:

τ = I * α

where τ is the torque, I is the moment of inertia of the spool, and α is the angular acceleration of the spool.

The tension in the string is equal to the weight of the box, which is given by:

T = m * g

Putting all of these equations together, we can solve for the time it takes for the box to reach the floor. Here's how:

First, we can find the angular acceleration of the spool using the torque equation:

τ = I * α

T = m * g = τ

m * g = I * α

α = (m * g) / I

α = (35.30 kg * 9.81 m/s^2) / 4.00 kg*m^2

α = 86.53 rad/s^2

Next, we can find the angular velocity of the spool using the kinematic equation:

ω^2 = ω_0^2 + 2 * α * θ

where ω_0 is the initial angular velocity (which is zero), θ is the angle through which the spool has turned (which is equal to the distance the box has fallen divided by the radius of the spool), and ω is the final angular velocity (which is what we want to find). Solving for ω, we get:

ω^2 = 2 * α * θ

ω = sqrt(2 * α * θ)

ω = sqrt(2 * 86.53 rad/s^2 * (3.50 m / 0.10 m))

ω = 166.6 rad/s

Finally, we can find the time it takes for the box to reach the floor using the equation:

v = r * ω

v = 0.10 m * 166.6 rad/s

v = 16.66 m/s

t = d / v

t = 3.50 m / 16.66 m/s

t = 0.21 s

The snowball travels a horizontal distance x and has height y at time t according to

x = vt

y = 0.9 m - 1/2 gt ²

where g = 9.8 m/s² is the magnitude of the acceleration due to gravity.

Set y = 0 and solve for t :

0 = 0.9 m - 1/2 gt ²

t ² = (1.8 m) / g

t ≈ 0.43 s

The target is 2 m away from where the snowball is thrown, so it was thrown with speed v such that

2 m = v (0.429 s)

v = (2 m) / (0.43 s)

v ≈ 4.7 m/s

Answer:

About 5

Explanation:

it’s about 5 because of the physical shape

Complete question is;

Assuming 100% efficient energy conversion how much water stored behind a 50 centimeter high hydroelectric dam would be required to charge the battery with power rating, 12 V, 50 Ampere-minutes.

Answer:

Amount of water required to charge the battery = 7.35 m³

Explanation:

The formula for Potential energy of the water at that height = mgh

Where;

m = mass of the water

g = acceleration due to gravity = 9.8 m/s²

h = height of water = 50 cm = 0.5 m

We know that in density, m = ρV

Where;

ρ = density of water = 1000 kg/m³

V = volume of water

So, potential energy is now given as;

Potential energy = ρVgH = 1000 × V × 9.8 × 0.5 = (4900V) J

Now, formula for energy of the battery is given as;

E = qV

We are given;

q = 50 A.min = 50 × 60 = 3,000 C

V = 12 V

Thus;

qV = 3,000 × 12 = 36,000 J

E = 36,000 J

At a 100% conversion rate, the energy of the water totally powers the battery.

Thus;

(4900V) = (36,000)

4900V = 36,000

V = 36,000/4900

V = 7.35 m³

Answer:

Explanation:

(a) Q=ap^n

Function of p and q:

p = q^(1/n)

(b) Q^m=ap^n

Function of p and q:

p = (q^(1/m))^(1/n)

The correct answer is option 3 i.e., 5.50 Kg and 120 N had lowest acceleration among all options given.

What connection exists between force and mass of acceleration?

Mass times acceleration, or F=m x a, equals force. This means that in order to move an object at the same speed as an object with smaller mass, a stronger force is required. Newton's Second Law of Motion is this.

Acceleration = Force / Mass

Given, as per question in all the 4 options Force = 120 N same for all

So as per formula if we assume Force is constant

Then, if mass is increased then acceleration will be lowest as both are inversely proportional.

1. Acceleration= 120 / 4.25 = 28.23 m/s²

2. Acceleration= 120 / 3.25 = 34.28 m/s²

3. Acceleration= 120 / 5.50 = 21.81 m/s²

4. Acceleration= 120 / 4.50 = 26.66 m/s²

Hence answer is option number 3.

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Answer:

am not sure about the answer

Explanation:

you need to find out the amount of force it's going in for example 10n or 100n then you need to times it the distance then devide by the time

Answer:

920000

Explanation:

Each kg contains 1,000 grams

The water purification procedure, such as filtration, sedimentation, distillation, etc.

Analysis of the reduction in microbes that is enough to protect against the transmission of pathogens in water is debated below. Chlorination is the most widely used method for disinfecting water supplies in the United States.

The most efficient way to desalinize salt water is by using a method called distillation. This is where you boil the water and then assemble the condensation. The steam will provide fresh salt-less water for you to drink.

So we can conclude that Chlorination is the activity of adding chlorine to drinking water to kill parasites bacteria and viruses.

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The student measured the length of a wire four times and the total length from the reading is 18.55 m.

From the given,

The length of the wire measured by the student using a meter rule is :

l₁ = 18.6 m

l₂ = 18.5m

l₃ = 18.6m

l₄ = 18.5 m

The total length of the wire is obtained from the average values of length.

Total length (L) = (l₁ + l₂ + l₃ + l₄)/4

                     L  = (18.6 + 18.5 + 18.6 + 18.5) / 4

                         = 74.2 /4

                         = 18.55

Hence, the actual length of the wire = 18.6 m.

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a. A high-pitch wave is characterized by a high frequency and a short wavelength. The frequency determines the pitch of the sound, with higher frequencies corresponding to higher pitches.

The wavelength is the distance between two consecutive peaks or troughs of the wave and is inversely proportional to the frequency. Therefore, a high-pitch wave has a shorter wavelength.

The amplitude of the wave, which is the height of the peak or the depth of the trough, is not directly related to the pitch of the sound, but it does determine the volume or intensity of the sound.

b. A high-volume wave is characterized by a high amplitude and a relatively long wavelength. The amplitude determines the volume or intensity of the sound, with higher amplitudes corresponding to louder sounds.

The wavelength of the wave does not directly affect the volume of the sound, but it can affect how the sound is perceived in different environments.

In general, longer wavelengths are more effective at traveling through obstacles such as walls and are better at penetrating long distances, whereas shorter wavelengths are more easily scattered and attenuated in the atmosphere.

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Answer:

Explanation:

Sure, I'd be happy to help you with the question!

Let's denote the input as x. According to the function machine, the input is multiplied by 6 and then 80 is subtracted from the result to obtain the output.

So, the function can be written as:

Output = (6 * x) - 80

Now, the problem states that the input is the same as the output. Therefore, we can set up the equation:

x = (6 * x) - 80

Let's solve this equation to find the value of x:

x = 6x - 80

Subtracting 6x from both sides, we get:

x - 6x = -80

Combining like terms, we have:

-5x = -80

Dividing both sides by -5, we find:

x = (-80) / (-5)

Simplifying the expression, we have:

x = 16

Therefore, the input (x) that results in the input being the same as the output is 16.

To work out these types of questions, it's important to carefully read the instructions and understand the operations being performed in the function machine. Then, you can set up an equation with the input and output, and solve for the unknown value. Always double-check your solution to ensure it satisfies the given conditions of the problem.

Answer:

16

Explanation:

(x*6) - 80 = x

Multiply the parentheses

6x - 80 = x
Add 80 to each side to get
6x = x + 80
Subtract x from both sides to get
5x = 80
Divide both sides by 5
x = 16

Venus has days that are longer than a day or. Venus takes longer to complete one rotation of its axis than it does to complete an orbit around the Sun. Earth days are needed for one orbit around the Sun.

Because Venus rotates in the opposite way from Earth and the majority of other planets, it is peculiar. Additionally, it rotates rather slowly. About 243 days to assess for the Earth to make one complete revolution.

The majority of astronomers believe that life could not possibly exist on Venus. Venus is an extremely unfriendly environment right now. The surface of this very dry planet shows no signs of water, and its environment is so dense that lead may melt on it.

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Answer:

(a) 4.334 × 10¹¹ joules are required to propel the rocket an unlimited distance away from Earth's surface, (b) The rocket has travelled 3999.865 miles from the Earth's surface with the half of the total work.

Explanation:

The complete statement is: "Use the weight of the rocket to answer the question. (Use 4000 miles as the radius of Earth and do not consider the effect of air resistance.) 7 metric ton rocket (a) How much work is required to propel the rocket an unlimited distance away from Earth's surface, (b) How far has the rocket traveled when half the total work has occurred?"

(a) The work required to propel the rocket is given by the change in gravitational potential energy, whose expression derives is described below:

\(U_{g, f} - U_{g, o} = -G\cdot M\cdot m \cdot \left[\frac{1}{r_{f}}-\frac{1}{r_{o}} \right]\)

Where:

\(U_{g,o}\), \(U_{g,f}\) - Initial and final gravitational potential energies, measured in joules.

\(m\), \(M\) - Masses of the rocket and planet Earth, measured in kilograms.

\(G\) - Universal gravitation constant, measured in newton-square meters per square kilogram.

\(r_{o}\), \(r_{f}\) - Initial and final distances of the rocket with respect to the center of the Earth, measured in meters.

The initial distance and rocket mass are converted to meters and kilograms, respectively:

\(r_{o} = (4000\,mi)\cdot \left(1609.34\,\frac{m}{mi} \right)\)

\(r_{o} = 6,437,360\,m\)

\(m = (7\,ton)\cdot \left(1000\,\frac{kg}{ton} \right)\)

\(m = 7000\,kg\)

Given that \(m = 7000\,kg\), \(M = 5.972\times 10^{24}\,kg\), \(G = 6.674\times 10^{-11}\,\frac{N\cdot m^{2}}{kg^{2}}\), \(r_{o} = 6,437,360\,m\) and \(r_{f} \rightarrow +\infty\), the work equation is reduced to this form:

\(U_{g,f} - U_{g,o} = \frac{G\cdot m \cdot M}{r_{o}}\)

\(U_{g,f} - U_{g,o} = \frac{\left(6.674\times 10^{-11}\,\frac{N\cdot m^{2}}{kg^{2}} \right)\cdot (7000\,kg)\cdot (5.972\times 10^{24}\,kg)}{6,437,360\,m}\)

\(U_{g,f} - U_{g,o} = 4.334\times 10^{11}\,J\)

4.334 × 10¹¹ joules are required to propel the rocket an unlimited distance away from Earth's surface.

(b) The needed change in gravitational potential energy is:

\(U_{g,f} - U_{g,o} = 2.167\times 10^{11}\,J\)

The expression for the change in gravitational potential energy is now modified by clearing the final distance with respect to the center of Earth:

\(U_{g, f} - U_{g, o} = -G\cdot M\cdot m \cdot \left[\frac{1}{r_{f}}-\frac{1}{r_{o}} \right]\)

\(\frac{U_{g,o}-U_{g,f}}{G\cdot M \cdot m} = \frac{1}{r_{f}} - \frac{1}{r_{o}}\)

\(\frac{1}{r_{f}} = \frac{1}{r_{o}} + \frac{U_{g,o}-U_{g,f}}{G\cdot M\cdot m}\)

\(r_{f} = \left(\frac{1}{r_{o}} + \frac{U_{g,o}-U_{g,f}}{G\cdot M\cdot m} \right)^{-1}\)

If \(m = 7000\,kg\), \(M = 5.972\times 10^{24}\,kg\), \(G = 6.674\times 10^{-11}\,\frac{N\cdot m^{2}}{kg^{2}}\), \(r_{o} = 6,437,360\,m\)  and \(U_{g,f} - U_{g,o} = 2.167\times 10^{11}\,J\), then:

\(r_{f} = \left[\frac{1}{6,437,360\,m}-\frac{2.167\times 10^{11}\,J}{\left(6.674\times 10^{-11}\,\frac{N\cdot m^{2}}{kg^{2}} \right)\cdot (7000\,kg)\cdot (5.972\times 10^{24}\,kg)} \right]^{-1}\)

\(r_{f} \approx 12,874,502.49\,m\)

The final distance with respect to the center of the Earth in miles is:

\(r_{f} = (12,874,502.49\,m)\cdot \left(\frac{1}{1609.34}\,\frac{mi}{m} \right)\)

\(r_{f} = 7999.865\,mi\)

The distance travelled by the rocket is: (\(r_{f} = 7999.865\,mi\), \(r_{o} = 4000\,mi\))

\(\Delta r = r_{f}-r_{o}\)

\(\Delta r = 7999.865\,mi - 4000\,mi\)

\(\Delta r = 3999.865\,mi\)

The rocket has travelled 3999.865 miles from the Earth's surface with the half of the total work.

Answer:

Fault is the correct answer

Explanation:

The rest are incorrect.

We can use the formula:

average velocity = displacement / time

Here, the displacement is the distance travelled, which is 9 km, and the time taken is 5 minutes, or 5/60 = 1/12 hours (since there are 60 minutes in an hour). Therefore:

average velocity = 9 km / (1/12 hours)

= 108 km/h

So the average velocity of the businessman is 108 km/h.

The root-mean-square speed of propane gas molecules at a temperature of  \(280\) K is approximately  \(489.6 m/s\) .

To calculate the root-mean-square (rms) speed of propane gas molecules, we can use the following equation:

rms speed \(= \sqrt(3kT/m)\)

Where \(k\) is the Boltzmann constant \((1.38 \times 10^-23 J/K)\) , T is the temperature in Kelvin, and m is the molar mass of propane.

The molar mass of propane  \((C_3H_8)\) can be calculated as follows:

\(m(C_3H_8) = 3m(C) + 8m(H)\)

Where m(C) is the atomic mass of carbon and m(H) is the atomic mass of hydrogen. Using the atomic masses from the periodic table, we get:

\(m(C) = 12.01 g/mol\)

\(m(H) = 1.01 g/mol\)

\(m(C_3H_8) = 3(12.01 g/mol) + 8(1.01 g/mol) = 44.11 g/mol\)

Now we can plug in the values into the equation:

rms speed \(= \sqrt(3kT/m)\)

= \(\sqrt{[(3 \times 1.38 \times 10^-23 J/K \times 280 K) / (44.11 g/mol \times 0.001 kg/g)]}\)

= 489.6 m/s

Therefore, the root-mean-square speed of propane gas molecules at a temperature of   \(280 K\) is approximately \(489.6 m/s\)  .

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In hydrogen atom the electronic transition from n= ∞ to n=1 corresponds to largest energy emission.

Electronic transition is the jump of an electron from one energy level to another energy level .

E = hc/λ

h= plank constant =6.62*10^(-34)

c=speed of light

λ= wavelength of emited electron .

Thus , we can conclude that the electronic transition from infinity to n=1 (ground state) corresponds to largest energy emission .

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Answer:

Pluto & Mercury

Explanation:

Pluto's eccentricity is 0.248

Mercury's eccentricity is 0.206

Answer:

(mv^2/R)/(mg)=1/2

v^2=R/2g

The expression for the speed of the mass is \(v = \sqrt{\frac{gL}{3} }\)

The given parameters;

mass of the string, = m

length of the string, = L

speed of the string, = v

The tension of the string at the top of the circle;

\(T_{top} = \frac{mv_t^2}{r} - mg\)

The tension of the string at the bottom of the string;

\(T_{bottom} = \frac{mv_b^2}{r} + mg\)

The ratio of the two force is given as;

\(\frac{T_{top}}{T_{bottom}} = \frac{mg - \frac{mv_t^2}{r} }{mg + \frac{mv_b^2}{r}} = 0.5\\\\0.5(mg + \frac{mv_b^2}{r}) = mg - \frac{mv_t^2}{r}\\\\mg + \frac{mv_b^2}{r} = 2(mg - \frac{mv_t^2}{r})\\\\mg + \frac{mv_b^2}{r} = 2mg - 2\frac{mv_t^2}{r}\\\\2\frac{mv_t^2}{r} + \frac{mv_b^2}{r} = 2mg - mg\\\\2\frac{mv_t^2}{r} + \frac{mv_b^2}{r} = mg\\\\assuming \ v_t = v_b\\\\3\frac{mv^2}{r}= mg\\\\\frac{v^2}{r} = \frac{g}{3} \\\\v^2 = \frac{rg}{3} \\\\v = \sqrt{\frac{rg}{3}}\)

\(v = \sqrt{\frac{gL}{3} }\)

Thus, the expression for the speed of the mass is \(v = \sqrt{\frac{gL}{3} }\)

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An electromagnet consists of a conductive wire wrapped around a magnetic core, creating a magnetic field when an electrical current is passed through it.

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1. A complete fitness and exercise program should incorporate three basic components: Endurance (Aerobic), Flexibility, and Strength. Each of these components has specific guidelines, which govern their effectiveness

Answer:

The correct answer is C) Force. If the total force on an object is not zero, its motion will change according to the second law of motion by Isaac Newton.

The new planet has the radius of only 1/4th of earth and mass of half that of earth. Then , the gravity on the surface of the new planet will be8 times higher than that of earth.

The gravitational force is the force by which an object attracts other object into its center of mass. Earth attracts every objects on ots surface to the ground by gravitation.

The force of gravitation is directly proportional to the mass and inversely proportional to the distance or radius of the planet.

g =  G m/r²

Where G is the universal gravitational constant.

The new planet has the mass half of that of earth (me) and radius 1/4th of earth.

gn = G me/2 (re/4)²

  = G 16 me/2

  = 8 ge

Where ge is the gravity by earth and gn that of new planet. The gravitational force of the new planet will be 8 times greater than that of earth.

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The work done by the steam when the piston moves 0.800 m is 1.75×10⁵ J and the amount of work by calculating the force exerted times the distance traveled is 1.85×10⁵ J. From this, the work done by the second part is more than the initial one. So they are not the same.

The work produced by the compression or expansion of fluid is known as pressure-volume work. Gas molecules gain kinetic energy when energy is added, which causes the gas to expand and affect its surroundings. The work is calculated using the formula W=pΔV where p is pressure, W is work done and ΔV is the change in the volume.

Given the gauge pressure (Pg) of the steam locomotive is  1.75×10⁶ N/m², the radium of piston r is 0.200 m, and the distance moved by the piston l is 0.800 m.

a) First, calculate the ΔV.

ΔV = area×distance

ΔV = πr²×l

ΔV = π×(0.20)²×0.80

ΔV = 0.1 m³

Then, the work done will be,

W = 1.75×10⁶× 0.1

W = 1.75×10⁵ J

The required answer is 1.75×10⁵ J.

b) The absolute pressure is given by the sum of gauge pressure and the atmospheric pressure, i.e., P=P₀+Pg. Then,

P = 1.01×10⁵ +  1.75×10⁶

P = 18.5×10⁵ Pa.

The force is calculated as,

F = P×A

F = 18.5×10⁵×π×(0.20)²

F = 232477 N

The work done by the piston is calculated as,

W = Force×distance

W = 232477×0.80

W = 1.85×10⁵ J

The required answer is 1.85×10⁵ J.

The answer for the first and second parts are not the same.

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The net electric force on charge q2 is 28.7 N.

The net electric force on charge q2 is calculated by applying Coulomb's law of electrostatic force.

F(net) = F(12) + F(23)

The force on q2 due to charge 1 is calculated as;

F(12) = -(9 x 10⁹ x 8 x 10⁻⁶ x 3.5 x 10⁻⁶ )/(0.1²)

F(12) = 25.2 N

The force on q2 due to charge 3 is calculated as;

F(23) = (9 x 10⁹ x 2.5 x 10⁻⁶ x 3.5 x 10⁻⁶ )/(0.15²)

F(23) = 3.5 N

The net force on q2 is calculated as;

F(net) = 25.2 N + 3.5 N = 28.7 N

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Answer:

The is: Although it is possible to have more than one state, it is also possible to have only one state.

Explanation:

Hope this helps! ;-)

Answer:

Although it is possible to have more than one state, it is also possible to have only one state.

Explanation:

The speed of the mass at the time the tension is measured is 6.12m/s

centripetal force - It is a force which makes a body follow a curved path.

It is directed inward towards center of rotation.

for example - gravitational force of sun is a centripetal force that keeps earth rotating around it.

the centripetal force on the swinging mass

Fc = mv²/r

where Fc is the centripetal force

m is the mass of body

v is the velocity

r is the radius

m = 1.5

r = 2.3 m

F = 24.5 N

To calculate the speed we put values in above equation

Fc = mv²/r

v = sqrt(Fc x r / m)

v = \(\sqrt[]{\frac{F *m}{r} }\)

\(v = \sqrt[]{\frac{24.5*1.5}{2.3} }\)

v = 6.12m/s

The speed of the mass at the time the tension is measured is 6.12m/s

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