Question No 1 (10 Marks)
a) Assume a high voltage pulse signal x(t)= 8 x 10^4 sinc(8 x 10^4 t) is fed to an analog to digital converter (ADC) that just samples x(t) at the Nyquist sampling rate of x(t). Draw the spectrum of the output signal x(T) from the ADC with proper labelling along the frequency axis.

b) Now assume that above x(t)= 8 x 10^4 sinc(8 x 10^4 t) is passed through an AWGN channel to give y(t) i.e. y(t) = x(t) +w(t)

Here w(t) is AWGN with a power spectral density (PSD) Sn(f) = 2. Will sampling y(t) by the above ADC that samples y(t) at the Nyquist sampling rate of x(t) cause aliasing ? justify.

c) Now assume that an antialiasing filter signal with H(t) = 2 pi (f/100 * 10^3) is applied to above y(t) to give z(t). Draw the spectrum Z(f) of the output of the antialiasing filter with proper labelling along the frequency & magnitude axis.

d) This z(t) is sampled by the ADC at the sampling rate of 120 X 10^3 Samples per second.Draw the Spectrum of ADC output z(t) with proper labelling along the frequency & magnitude axix.

Answer:Just multiply 90 by itself 46 times

Explanation:

do it

jrjrkeekkekekkwkkakkllalllalallalllalalaallalalaalalalalalallallallllallalalallaaallalallllllallllllllalaalalalaaaaalalaaaaaaalgjgiejxpwunfifjruritiririirieoeowowowowowowowowooeowowowoeeoeowowowowowowowoowowwowowowoozoeisiaokseekxidjdkdjfidjfjdjfjfjrifjrifjdirjdjrjfjrjfjrjfjrfuejwwuxmaneanfjkaosndjxieneamalhaqzeeshanvhorahfuensiwjakaksjdhfhfnfhfndjxnxmakaalalalwlwlwwow

Answer:

The meole fraction of acetone in the outlet liquid is \(x_1 = 0.0072\)

Explanation:

1.

The schematic diagram to represent this process is shown in the diagram attached below:

2.

the mole fraction of acetone in the outlet liquid is determined as follows:

solute from Basis Gas flow rate \(G_s = 10(1-0.012) =9.88 kmol/hr\)

Let the entering mole be :\(y_1 = 1.2\) % = 0.012

\(y_1 =(\dfrac{y_1}{1-y_1})\)

\(y_1 =(\dfrac{0.012}{1-0.012})\)

\(y_1 =0.012\)

Let the outlet gas concentration be \(y_2\) = 0.1% = 0.001

\(y_2 = 0.001\)

Thus; the mole fraction of acetone in the outlet liquid is:

\(G_s y_1 + L_s x_2 = y_2 L_y + L_s x_1\)

\(9.88(0.012-0.001)=15*x_1\)

\(9.88(0.011) = 15x_1\)

\(x_1 = \dfrac{0.10868}{15}\)

\(x_1 = 0.0072\)

The mole fraction of acetone in the outlet liquid is \(x_1 = 0.0072\)

Answer:

Explanation:

Step one:

given data

V1=0.25m^3

T1=290k

P1=100kPa

V2=0.5m^2

T2=405k

P2=? final pressure

Step two:

The combined gas equation is given as

P1V1/T1=P2V2/T2

Substituting we have

(100*0.25)/290=P2*0.05/405

25/290=0.5P2/405

0.086=0.05P2/405

cross multiply

0.086*405=0.05P2

34.9=0.05P2

divide both sides by 0.05

P2=34.9/0.05

P2=698.3Kpa

Therefore the new pressure is 698.3Kpa when the gas is compressed

Answer:

a)  \(Tb=1845.05K\)

b)  \(Q=1000.25KJ\)

c)  \(\mu=0.59\)

Explanation:

From the question we are told that:

Temperature x \(Tx=450c=>723K\)

Pressure x \(Px=2.5MPa\)

Temperature y \(Ty=600c=>873K\)

Pressure y \(Py=0.45MPa\)

Let

Air atmospheric temperature be \(25c\)

Therefore

Temperature \(Ta=25+273=298k\)

Generally the equation for Otto cycle is mathematically given by

 \(\frac{Tb}{Tx}=\frac{Ty}{Ta}\)

 \(Tb=\frac{873*723}{298}\)

 \(Tb=2118.05\)

Therefore the peak cycle temperature (°C)

 \(Tb=2118.05k\)

 \(Tb=2118.05-273\)

 \(Tb=1845.05K\)

Generally the equation for Heat addition is mathematically given by

 \(Q=Cv(Tb-Tx)\)

 \(Q=Cv(2118.05-723)\)

 \(Q=1000.25KJ\)

Generally the equation for Thermal  efficiency is mathematically given by

 \(\mu=1-\frac{Ta}{Tx}\)

 \(\mu=1-\frac{298}{723}\)

 \(\mu=0.59\)

Answer:

Explanation:

do you have any other questions besides "tyuuyiopopiouyttrrtrffrlkl,k;;';'l.l"

Answer:

Magnitude of the velocity = 16.82 m/s

Angular direction, θ = 52.41°

Explanation:

As given ,

mass of bullet, m₁= 50g = 0.05 kg

speed of bullet , u₁ = 600 m/s

mass of the block , m₂ = 4 kg

speed of the block before collision , u₂ = 12 m/s

direction , θ = 30°

Now,

Assume that the combined velocity of bullet and block after collision = v

and the direction = θ

Now, from the conservation of momentum in x - direction :

m₁ u₁ + m₂ u₂ = ( m₁ + m₂ ) vₓ

where v = final velocity after collision

u₁ = initial velocity of bullet before collision = 0

m₁ = mass of the bullet before collision = 0.05 kg

u₂  = velocity of block before collision = 12 cos(30° )

m₂ = mass of block before collision

m₁ + m₂ = combined mass of bullet and block after collision = 0.05 + 4

∴ we get

0.05 (0) + 4(12 cos(30° ) ) = ( 0.05 + 4 ) vₓ

⇒ 0 + 4(6√3) = 4.05 vₓ

⇒24√3 = 4.05 vₓ

⇒vₓ = 10.26 m/s

Now, from the conservation of momentum in y - direction :

m₁ u₁ + m₂ u₂ = ( m₁ + m₂ ) \(v_{y}\)

where v = final velocity after collision

u₁= initial velocity of bullet before collision = 600

m₁ = mass of the bullet before collision = 0.05 kg

u₂  = velocity of block before collision = 12 sin(30° )

m₂= mass of block before collision

m₁+ m₂= combined mass of bullet and block after collision = 0.05 + 4

∴ we get

0.05 (600) + 4(12 sin(30° ) ) = ( 0.05 + 4 ) \(v_{y}\)

⇒ 30 + 4(6) = 4.05 \(v_{y}\)

⇒30 +24 = 4.05 \(v_{y}\)

⇒54 = 4.05 \(v_{y}\)

⇒\(v_{y}\) = 13.33 m/s

Now, the magnitude of the velocity = √vₓ² + \(v_{y}\)² = √(10.26)² + (13.33)²

                                                           = √105.26 + 177.68

                                                           = √282.95 = 16.82

The angular direction, θ =  \(tan^{-1}\)(\(\frac{v_{y} }{v_{x} }\)) =  \(tan^{-1}\)(\(\frac{13.33}{10.26}\)) = \(tan^{-1}\)(1.299) = 52.41°

The Pyramid for Enterprise Design in autonomous driving involves hardware, software, data collection, and dashboards for making informed business decisions.

Pyramid for Enterprise Design:

1. Hardware Needed: Autonomous driving technology requires various hardware components such as sensors, cameras, radars, GPS systems, processors, and actuators. These components enable the collection of real-time data and facilitate the functioning of the autonomous vehicle.

2. Software Needed: The software layer consists of the operating system and the algorithms required for autonomous driving. This includes perception systems for object detection and recognition, decision-making algorithms, and control systems for navigation, acceleration, and braking.

3. Application Needed: The application layer involves the development of specialized software applications specifically designed for autonomous driving. These applications integrate the hardware and software components, enabling the vehicle to perform tasks like lane keeping, adaptive cruise control, and automated parking.

4. Data Collected: Autonomous vehicles generate vast amounts of data through their sensors and onboard systems. This data includes information about the vehicle's surroundings, such as road conditions, traffic patterns, and the behavior of other vehicles. It also includes internal vehicle data like speed, acceleration, and fuel consumption.

5. Dashboards or KPIs: Dashboards or Key Performance Indicators (KPIs) provide visual representations of the collected data. These dashboards enable users to monitor the performance of autonomous driving technology, track key metrics, and identify areas for improvement. Examples of KPIs in this context could be the number of successful autonomous trips, average reaction time, and fuel efficiency.

The data collected and analyzed from autonomous driving technology can be used to make various business decisions. For example, analyzing traffic patterns and congestion data can help businesses optimize delivery routes and reduce transportation costs. Additionally, data on driving behavior and vehicle performance can be utilized to improve safety measures, enhance maintenance protocols, and optimize fleet management. By leveraging the insights gained from the data, businesses can make informed decisions to improve the efficiency, reliability, and safety of autonomous driving technology.

To learn more about software  Click Here: brainly.com/question/32393976

#SPJ11

The frequency deviation of the modulating signal is given by: Frequency deviation, Δf = βVm = 5 x 1.2 = 6 kHz.

Assuming that an FM system has a frequency deviation of 10 kHz when the modulating signal has an amplitude of 4 volts and a frequency of 2 kHz, let us determine the frequency deviation if the modulating signal is given below.

Therefore, we can say that the modulating signal is given by 1.2sin(2πft), where f is the frequency of the modulating signal. Let us first find the modulator sensitivity (km/Volt). Given, amplitude of modulating signal, Vm = 4 V. Frequency of modulating signal, fm = 2 kHz Frequency deviation, Δf = 10 kHzWe know that Modulation index, β = Δf/fm = 10/2 = 5 km/Volt

From the given question, we are given that the modulator's sensitivity (km/volt) is 5 km/Volt. Therefore, the answer is 6 kHz.

Learn more about frequency deviation : https://brainly.com/question/26226551

#SPJ11

Answer:

The volume of the gas is 11.2 L.

Explanation:

Initially, we have:

V₁ = 700.0 L

P₁ = 760.0 mmHg = 1 atm

T₁ = 100.0 °C

When the gas is in the thank we have:

V₂ =?

P₂ = 20.0 atm

T₂ = 32.0 °C      

Now, we can find the volume of the gas in the thank by using the Ideal Gas Law:

\( PV = nRT \)

\(V_{2} = \frac{nRT_{2}}{P_{2}}\)    (1)

Where R is the gas constant

With the initials conditions we can find the number of moles:

\( n = \frac{P_{1}V_{1}}{RT_{1}} \)    (2)

By entering equation (2) into (1) we have:

\( V_{2} = \frac{P_{1}V_{1}}{RT_{1}}*\frac{RT_{2}}{P_{2}} = \frac{1 atm*700.0 L*32.0 ^{\circ}}{100.0 ^{\circ}*20.0 atm} = 11.2 L \)

Therefore, When the gas is placed into a tank the volume of the gas is 11.2 L.

I hope it helps you!                                                                                                                                                                                

Yes, when two fluid streams are mixed in a mixing chamber, the mixture temperature can be lower than the temperature of both streams.

This is due to the phenomenon of heat transfer that occurs during the mixing of fluids.

What is a fluid?

A fluid is a substance that flows and takes the shape of its container. Liquids and gases are examples of fluids. Fluids are used in various applications, including engineering, medicine, and science.

What is a chamber?

A chamber is a container or enclosed space used for a specific purpose. Chambers are used in various applications, including science, engineering, and medicine.

What is temperature?

Temperature is the measure of the average kinetic energy of the particles in a substance. The SI unit of temperature is Kelvin (K). The temperature of a substance determines its thermal state.

What happens when two fluids are mixed in a mixing chamber?

When two fluids are mixed in a mixing chamber, heat transfer occurs. Heat is transferred from the fluid with a higher temperature to the fluid with a lower temperature. This process continues until the temperatures of the fluids are equalized. The mixture temperature depends on various factors, including the flow rates of the fluids, the specific heat capacity of the fluids, and the temperature difference between the fluids. The mixture temperature can be lower than the temperature of both streams if the flow rate and specific heat capacity of the fluid with the lower temperature are significantly higher than that of the fluid with the higher temperature.

https://brainly.com/question/3031257. #SPJ11

Answer:

Explanation:

"Safety helmet" redirects here. It is not to be confused with hard hat.

Drug Enforcement Administration (DEA) agents wearing Level B hazmat suits

Personal protective equipment (PPE) is protective clothing, helmets, goggles, or other garments or equipment designed to protect the wearer's body from injury or infection. The hazards addressed by protective equipment include physical, electrical, heat, chemicals, biohazards, and airborne particulate matter. Protective equipment may be worn for job-related occupational safety and health purposes, as well as for sports and other recreational activities. "Protective clothing" is applied to traditional categories of clothing, and "protective gear" applies to items such as pads, guards, shields, or masks, and others. PPE suits can be similar in appearance to a cleanroom suit.

The purpose of personal protective equipment is to reduce employee exposure to hazards when engineering controls and administrative controls are not feasible or effective to reduce these risks to acceptable levels. PPE is needed when there are hazards present. PPE has the serious limitation that it does not eliminate the hazard at the source and may result in employees being exposed to the hazard if the equipment fails.[1]

Any item of PPE imposes a barrier between the wearer/user and the working environment. This can create additional strains on the wearer; impair their ability to carry out their work and create significant levels of discomfort. Any of these can discourage wearers from using PPE correctly, therefore placing them at risk of injury, ill-health or, under extreme circumstances, death. Good ergonomic design can help to minimise these barriers and can therefore help to ensure safe and healthy working conditions through the correct use of PPE.

Practices of occupational safety and health can use hazard controls and interventions to mitigate workplace hazards, which pose a threat to the safety and quality of life of workers. The hierarchy of hazard controls provides a policy framework which ranks the types of hazard controls in terms of absolute risk reduction. At the top of the hierarchy are elimination and substitution, which remove the hazard entirely or replace the hazard with a safer alternative. If elimination or substitution measures cannot apply, engineering controls and administrative controls, which seek to design safer mechanisms and coach safer human behavior, are implemented. Personal protective equipment ranks last on the hierarchy of controls, as the workers are regularly exposed to the hazard, with a barrier of protection. The hierarchy of controls is important in acknowledging that, while personal protective equipment has tremendous utility, it is not the desired mechanism of control in terms of worker safety.rly PPE such as body armor, boots and gloves focused on protecting the wearer's body from physical injury. The plague doctors of sixteenth-century Europe also wore protective uniforms consisting of a full-length gown, helmet, glass eye coverings, gloves and boots (see Plague doctor costume) to prevent contagion when dealing with plague victims. These were made of thick material which was then covered in wax to make it water-resistant. A mask with a beak-like structure which was filled with pleasant-smelling flowers, herbs and spices to prevent the spread of miasma, the prescientific belief of bad smells which spread disease through the air.[2] In more recent years, scientific personal protective equipment is generally believed to have begun with the cloth facemasks promoted by Wu Lien-teh in the 1910–11 Manchurian pneumonic plague outbreak, although many Western medics doubted the efficacy of facemasks in preventing the spread of disease.[3]

Types

Personal protective equipment can be categorized by the area of the body protected, by the types of hazard, and by the type of garment or accessory. A single item, for example boots, may provide multiple forms of protection: a steel toe cap and steel insoles for protection of the feet from crushing or puncture injuries, impervious rubber and lining for protection from water and chemicals, high reflectivity and heat resistance for protection from radiant heat, and high electrical resistivity for protection from electric shock. The protective attributes of each piece of equipment must be compared with the hazards expected to be found in the workplace. More breathable types of personal protective equipment may not lead to more contamination but do result in greater user satisfaction.[4]

The use of a faulty PPE could be just as dangerous as not using any PPE at all because the user is still exposed to potential hazards and harm.

PPE is an acronym for personal protective equipment and it can be defined as a terminology that is used to denote any piece of equipment which offer protection to different parts of the body while working in a potentially hazardous environment.

Some examples of personal protective equipment (PPE) used to protect the different parts of the body are:

According to OSHA, the use of a faulty PPE could be just as dangerous as not using any PPE at all because the user is offered little or no protection at all.

Read more on PPE here: https://brainly.com/question/19131588

In the radio communication system, multipath is the propagation phenomenon that causes diffusion or reflection in multiple different directions of a signal.

Multipath is a propagation mechanism that impacts the propagation of signals in radio communication. Multipath results in the transmission of data to the receiving antenna by two or more paths. Diffusion and reflection are the causes that create multiple paths for the signal to be delivered.

Diffraction occurs when a signal bends around sharp corners; while reflection occurs when a signal impinges on a smooth object. When a signal is received through more than one path because of the diffraction or reflection, it creates phase shifting and interference of the signal.

You can learn more about signal propagation at

https://brainly.com/question/14452898

#SPJ4

For 304-annealed stainless steel, the tensile strength ranges 515 MPa (75,000 psi) and 1035 MPa (150,000 psi) and yield strength around 205 MPa (30,000 psi) to 515 MPa (75,000 psi).

The tensile and yield strengths you provided for the 304-annealed stainless steel are 515 MPa and 205 MPa, respectively. These values indicate the material's mechanical properties under tensile loading.

Tensile strength refers to the maximum stress a material can withstand before it fails or breaks.

Yield strength, on the other hand, is the stress at which a material begins to exhibit plastic deformation.

For 304-annealed stainless steel, the tensile strength typically ranges between 515 MPa (75,000 psi) and 1035 MPa (150,000 psi). This means that the material can withstand a maximum tensile stress in this range before experiencing failure.

and, the yield strength of 304-annealed stainless steel is generally around 205 MPa (30,000 psi) to 515 MPa (75,000 psi).

Learn more about Stress and Strain here:

https://brainly.com/question/13261407

#SPJ4

In any mechanical project, calculating the measurements of the equipment is an essential task.

As a result, it is paramount to reference the numerical details outlined in either the drawings or specifications related to that endeavor.

Fundamentally, these documents comprise height, width, and length. If precise dimensions are not available, collaborating with mechanical engineers or equipment manufacturers could be beneficial.

Moreover, guarantee that the measurements harmonize with the conception and capacity of the project to keep away from probable superfluous installation or usefulness snags.

Read more about mechanical equipments here:

https://brainly.com/question/30387012

#SPJ1

The capacitance-to-neutral in F/m is 8.742 × 10⁻¹²  F/m

The admittance-to-neutral in S/km is j3.296 × 10⁻⁶  S/km

The line charging current in kA/phase if the line is 110 km in length and is operated at 230 kV, I\(_{chg}\) = 4.814 × 10⁻¹²  kA/ Phase

A component or circuit's capacitance is its capacity to accumulate and store energy in the form of an electrical charge. The ratio of the electric charge on each conductor to the potential difference, or voltage, between them is used to express capacitance.

Farads (F), which bear the name of English physicist Michael Faraday, are the units used to measure the capacitance value of a capacitor (1791–1867).

A farad is a huge amount of capacitance. Most household electrical appliances contain capacitors that produce only a tiny amount of electricity, often a thousandth of a farad (or microfarad, or F), or as little as a picofarad (a trillionth, pF).

Learn more about capacitance

https://brainly.com/question/27393410

#SPJ4

Answer:

the answer is A

Explanation:

any saved date you have for example a video you take can be put on a hard drive and you can save it to your computer well if you save data on a computer it goes on the hardrive

Answer:

the answer is A - RAM / Hard Drive

Explanation:

ROM Contains certain information that are required to start and operate a machine or hardware, RAM used when you're working with some software or the OS itself but RAM is volatile so it'll be erased after power gone, Hard disk used for long term permanent data storage. So your answer is while you're using a file or some data it become stored in RAM but after you finish making changes to that file or data it'll be saved in hard disk.

A concurrent schedule is made up of two or more separate schedules that are presented at the same time and lead to different reinforcers.

Parallel schedule A reinforcement process where the participant can select their response from one of two or more accessible simple reinforcement schedules at once. The assessment of choice between straightforward schedule alternatives is possible with concurrent schedules.

The reinforcement schedules that are in place when two or more behaviors are reinforced simultaneously on various schedules. An illustration would be watching TV while on the phone and browsing the internet.

Two stimuli are pitted against one another in a concurrent schedule of reinforcer assessment to see which will result in a larger increase in responding when presented as a reward for responding. The reinforcer with more responses is the more potent one.

To know more about concurrent schedule click here:

https://brainly.com/question/28447316

#SPJ4

The first thing to do if your vehicle leaves the roadway is to take your foot off the accelerator.

It's crucial to maintain composure and refrain from making quick or hostile motions when your car leaves the road.

Stepping off the gas pedal allows you to gently slow down the car and regain control. It enables you to concentrate on analysing the circumstance and selecting the most appropriate line of action.

You should retain a tight grip on the steering wheel and steer softly after removing your foot from the pedal to keep the car under control.

Thus, if it is safe to do so, it is crucial to maintain your composure and move the car back onto the road with calm, controlled motions.

For more details regarding vehicles, visit:

https://brainly.com/question/32347244

#SPJ4

Answer:

defining the need

Explanation:

Of course, since the first stage of the engineering design phase involves defining the need of the design, it is at this stage that the researcher/engineer should determine the criteria and constraints.

This stage involves asking such questions as:

Using the formula of shear stress, the minimum required diameter is 0.81mm

Shear stress is a force that causes two objects to slide past each other in opposite directions. It is the force per unit area of the surface on which the force is applied. Shear stress is often caused by two objects rubbing against each other, such as a car tire sliding on the road. It can also be caused by wind, gravity, or other forces.

The shear stress on the shaft can be calculated using the formula:

τ(allow) = P/(2*π*d*J)

where P is the total power transferred by the shaft, d is the diameter of the shaft, and J is the polar moment of inertia.

J = π*d⁴/32

Substituting the given values,

τ(allow) = (15 + 6 + 4 + 5)/(2*π*d*π*d⁴/32)

d = √[32*(15 + 6 + 4 + 5)/(τ(allow)*2*π²)]

d = √[32*(30)/(75*2*π²)]

d = 0.81mm

The minimum required diameter of the shaft is 0.81 mm to the nearest millimeter.

Learn more shear stress here;

https://brainly.com/question/13670232

#SPJ1

Answer:

i) 3750 veh/hr/ln

ii) 100 veh/mi/In

iii) 37.5 mph

Explanation:

number of lanes = 3

sf for both directions = 75 mph  ( free mean speed )

Dj for both directions = 200 veh/mi/In

Calculate the value of  S0, D0 (veh/mi/ln) and maximum Vm (veh/hr)

For either direction we will consider the total volume = 3 lanes

value of Dj = 3 lanes * 200 = 600 veh/mi/

i) value of SO

=  ( Dj * sf ) / 4 = ( 600 * 75 ) / 4 = 11250 veh/hr  = 3750 veh/hr/lane

ii) Value of DO

DO = Dj / 2 = 200 /2 = 100 veh/mi/In

iii) Value of Vm

= sf /2 = 75 / 2 = 37.5 mph

Mathematically, it is given as:the COP for cooling of the vapor compression cooling machine is 4.

COP for cooling = Cooling output / Energy input

In this case, the cooling output is 4 kW and the energy input is 1 kW. Therefore, the COP for cooling can be calculated as:

COP for cooling = 4 kW / 1 kW = 4  The Coefficient of Performance (COP) for cooling of a vapor compression cooling machine is defined as the ratio of the cooling output to the energy input.

To learn more about machine click the link below:

brainly.com/question/15002511

#SPJ11

ANSWER :

325

Explanation:

313 + 12 = 325

Answer:

are you wht

didn't understand the question

Answer:

Yes/No

Explanation:

NANI?!

This statement is generally true. In most cases, waste piping is designed to connect to drain piping on the outlet side of traps or at other designated locations in drainage piping.

Traps are important components of plumbing systems that are designed to prevent the flow of sewer gases, insects, and other pests from entering a building through the plumbing system. They are typically installed in waste piping near the fixture that they serve, such as a sink, toilet, or shower.

The waste piping that connects to these fixtures typically leads to the inlet side of the trap, which is designed to hold a small amount of water that forms a seal to prevent sewer gases from entering the building. From there, the drain piping usually connects to the outlet side of the trap, allowing waste water to flow out of the building and into the sewer or septic system.

There may be some exceptions to this general rule, depending on the specific design of the plumbing system and local building codes. In some cases, for example, a waste line may be connected directly to a building's vent stack to improve drainage and prevent the buildup of gases. However, these types of configurations are typically designed and installed by licensed plumbers or other qualified professionals who are familiar with local plumbing codes and best practices.

In summary, while there may be some variations in the design and configuration of waste and drain piping in different plumbing systems, it is generally true that waste piping connects to drain piping on the outlet side of traps or at other designated locations in drainage piping.

To know more about drainage: https://brainly.com/question/29432940

#SPJ4

The py thon program that reads a list of scores and then assigns grades based on the given scheme is; As written below

The program steps when written in Py-thon is;

Enter scores: 40 55 70 58

Student 0 score is 40 and grade is C

Student 1 score is 55 and grade is B

Student 2 score is 70 and grade is A

"""

def get_grade(points):

   score = 70 - points

   grades = [(40, 'D'), (30, 'C'), (20, 'B'), (10, 'A')]

   result = ''

   for grade in grades:

       if score <= grade[0]:

           result = grade[1]

   return result

def scorer(points):

   results = []

   for point in points:

       results.append(get_grade(point))

   return results

if __name__ == "__main__":

   user_input = input('Enter scores: ')

   points = [int(n) for n in user_input.split(' ')]

   points = [ int(n) for n in user_input.split(' ')]

    scores = scorer(points)

   for n in range(len(points)):

       m sg = 'Student {} score is {} and grade is {}'.format(

           n, points[n], scores[n]

       )

       print(m sg)

Read more about Py-thon Program at; https://brainly.com/question/26497128

#SPJ1

With regard to open water diving, it is to be noted that I should have cylinders filled at a dive center I trust, not use air that tastes or smells bad, nor use air from a compressor designed to fill car tires. This is important to Reduce the risk of breathing contaminated air.

Open water in underwater diving refers to unrestricted water, such as a sea, lake, or flooded quarry. It is the polar opposite of restricted water (often a swimming pool) where diver training occurs. Open water also implies that the diver has direct vertical access to the ocean's surface, which is in contact with the Earth's atmosphere.

Open Water Divers can plan and perform dives to a maximum depth of 18 meters/60 feet with the assistance of a trained buddy or dive professional. Scuba Divers may only dive to a maximum depth of 12 meters/40 feet under the direct supervision of a PADI Professional (an Instructor).

Learn more about open water diving:
https://brainly.com/question/28153852

#SPJ1