i need help on this which is correct? plz help me its timed.
Answer:
Watershed should be your answer!
x = 3t2 - 18t . Find position when velocity is zero
x = at3+bt2+ct+d , Find dimensions of a,b,c,d. ( Where x is position and t is time)
(a) The position of the particle when velocity is zero is - 27 m.
(b) The dimensions of a, b, c, and d are LT⁻³, LT⁻², LT⁻¹ and L respectively.
Velocity of the particleThe velocity of the particle is change in position of the particle with time.
v = dx/dt
v = 6t - 18
when velocity = 0
0 = 6t - 18
6t = 18
t = 18/6
t = 3 seconds
Position of the particle at 3 secondsx = 3(3²) - 18(3)
x = -27 m
Dimensions of a, b, c, dx = at³ + bt² + ct + d
if t is in seconds and x is meters, the dimensions of a, b, c, and d is calculated as;
x(m) = at³(m/s³) + bt²(m/s²) + ct(m/s) + d(m)
Thus, the dimensions of a, b, c, and d are LT⁻³, LT⁻², LT⁻¹ and L respectively.
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What can you do to a parallel circuit to vary the amount of current that flows through each branch?
To vary the amount of current that flows through each branch of a parallel circuit, we can:
1. Adjust the resistance
2. Add or remove branches
3. Adjust the voltage
1. Adjust the resistance: The amount of current flowing through a branch depends on the resistance in that branch.
You can change the resistance of a branch by adding or removing resistors, or by adjusting the value of variable resistors (also known as potentiometers or rheostats).
As resistance increases, the current flowing through the branch decreases, and vice versa.
2. Add or remove branches: In a parallel circuit, the total current is divided among the individual branches.
By adding or removing branches, you can affect the current distribution among the remaining branches.
For example, if you add an additional branch with the same resistance as the other branches, the current in each branch will be reduced as the total current is now divided among more branches.
3. Adjust the voltage: The current flowing through a branch is directly proportional to the voltage applied to the circuit. By changing the voltage source (battery or power supply) or adjusting the voltage, you can affect the current distribution among the branches.
Increasing the voltage will increase the current in all branches, while decreasing the voltage will decrease the current in all branches.
Remember to always be cautious when working with electrical circuits.
Turn off the power before making any adjustments or changes to the circuit, and follow proper safety procedures.
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much like mass and energy, the amount of electric charge in the universe is constant and cannot be created or destroyed. in physics, what law governs such a relation? if the total electric charge remains constant in a closed system, how can some objects change their charges?
The law that governs the conservation of electric charge in a closed system is known as the law of conservation of charge.
According to this law, the total amount of electric charge in a closed system remains constant and cannot be created or destroyed. As for how objects can change their charges in a closed system, it is because the distribution of electric charge can change.
For example, when two objects with different electric charges are brought into contact, electrons can flow from one object to the other until both objects have the same electric potential. This transfer of electrons results in a change in the charge of each object, but the total charge remains the same.
Another way objects can change their charges is through the process of ionization, where an atom loses or gains electrons, resulting in a change in the electric charge of the atom. Again, the total charge remains constant, as the lost or gained electrons must go somewhere.
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1 A grandfather clock uses energy stored in raised weights. The weights transfer energy to the clock mechanism as they fall. One clock has a 4.5 kg weight that supplies energy to the chimes (which play a few notes every 15 minutes), and two 3.5 kg weights that power the clock and the mechanism that strikes the hours.
For all questions on this sheet,
use g = 10 N/kg
a Calculate how much energy is stored when all three of these weights are raised by 70 cm. b How far does the 4.5 kg weight have to be lifted to store 45 J of energy?
2 The water tank in a house can hold 200 litres of water. The mass of 1 litre of water is 1 kg. The tank is 2 m above the bathroom taps and 5 m above the kitchen taps. The kitchen taps are 1 m above the floor.
a
Calculate the gravitational potential energy (GPE stored in the water in the tank when it is full. State any assumptions made in your answer.
b Calculate the speed at which the water would come out of the bathroom taps and kitchen taps. You
may assume that no energy is transferred due to friction in the pipes.
3 The Victoria Falls in Africa is one of the world's largest waterfalls. Just over 1000 m° of water pass over the falls every second and fall approximately 100 m. 1 m3 of water has a mass of 1000 kg. a What mass of water goes over the falls every second? Give your answer in standard form.
b
Calculate the GPE of 1 kg of water at the top of the falls.
c If all the GPE stored in 1 kg of water is transferred to kinetic energy, calculate the speed of the water as
it reaches the bottom.
d Suggest why the water will not be falling as fast as your answer to part c suggests. e What is the total energy transferred per second as the GP stored in the water falling in one second is
transferred to other energy stores.
f Suggest the ways in which this energy is finally stored.
4 A post driver is used to drive fence posts into the ground. It is a hollow tube with a closed top, and handles on the side. A person fits the driver over a fence post, then lifts it up and lets it drop.
post driver
50 cm
a A post driver has a mass of 10 kg. Calculate the change in GPE stored when the post driver is lifted by 50 cm above the post, as shown in the diagram.
b
Calculate the speed of the driver when the end hits the post.
C
Explain how much extra energy is stored if the post driver is
fence post
lifted by 1 metre instead of only 50 cm.
d Calculate the speed of the post driver after it falls for 1 m. e A new design of post driver has a mass of 15 kg. Suggest one advantage and one disadvantage of this new design.
Extra challenge
5 F The post driver in question 4a stops in
0.5 seconds when it hits the fence post.
a Calculate the force needed to bring the post driver to a stop. (Hint: use your answer to 4b.)
The momentum of a moving object is the product of its mass and its velocity. The force needed to stop a moving object depends on how fast its momentum changes.
force = change in momentum
=
mv - mu
time
t
b What provides this force?
c Explain how your answer might be different it the post were being sunk into very soft ground,
F = force (N)
u = initial velocity (m/s)
te time (s)
m = mass (kg)
v = final velocity (m/s)
1a) The total energy stored when all three weights are raised by 70 cm is 80.5 J.
1b) The height of the tank is 2 m.
2b) The potential energy is converted into kinetic energy when the water flows out of the taps 6.32 m/s.
3a) The mass of water that goes over the falls every second is 1 x 10⁶ kg.
3b) The gravitational potential energy of 1 kg of water at the top of the falls 1000 J.
3c) The speed of the water as it reaches the bottom if all the GPE stored in 1 kg of water is transferred to kinetic energy is 44.72 m/s.
3d) The water will not be falling as fast as the speed calculated in part c suggests because of the presence of air resistance and the fact that the water falls through a medium (air) which offers resistance to its motion.
3e) The energy transferred when the GPE stored in the water falling in one second is transferred to other energy stores is finally stored in thermal energy stores due to the heat generated by the water as it hits the bottom.
1a) To calculate the amount of energy stored in the three weights, we use the formula given below:
E = mgh
Where,E = Energy (Joules)
m = Mass (kg)
g = Gravity (10 N/kg)
h = Height (m)
For the 4.5 kg weight:
E = 4.5 x 10 x 0.7 = 31.5 J
For each of the 3.5 kg weight:
E = 3.5 x 10 x 0.7 = 24.5 J
Thus, the total energy stored when all three weights are raised by 70 cm is:
31.5 J + 24.5 J + 24.5 J = 80.5 J
1b) To calculate how far the 4.5 kg weight must be lifted to store 45 J of energy, we use the formula:
E = mghh = E/mg = 45 / (4.5 x 10) = 1 m2a)
To calculate the gravitational potential energy stored in the water in the tank when it is full, we use the formula given below:
E = mgh
Where,E = Energy (Joules)
m = Mass (kg)
g = Gravity (10 N/kg)
h = Height (m)
The mass of 1 litre of water is 1 kg and the tank can hold 200 litres of water. Therefore, the total mass of water in the tank is:
Mass = 200 kg
The height of the tank is 2 m.
Therefore, the gravitational potential energy stored in the water in the tank is:
E = mgh = 200 x 10 x 2 = 4000 J
Assumptions made in the answer:
We have assumed that the tank is full.
2b) To calculate the speed at which the water would come out of the bathroom and kitchen taps, we use the formula given below:
PE = KEPE = mghKE = 1/2mv²
Where,PE = Potential Energy (Joules)
KE = Kinetic Energy (Joules)
m = Mass (kg)
g = Gravity (10 N/kg)
h = Height (m)
v = Velocity (m/s)
Assuming that the potential energy of the water in the tank is converted into kinetic energy when the water flows out of the taps, the potential energy stored in the water in the tank is given by:
PE = mgh = 200 x 10 x 2 = 4000 J
The potential energy is converted into kinetic energy when the water flows out of the taps.
Therefore, KE = 1/2mv²v² = 2KE/mv² = 2(4000)/200 = 40 m²/s²v = √(40) = 6.32 m/s (speed of the water coming out of the taps)
3a) To calculate the mass of water that goes over the falls every second, we use the formula given below:
Mass = Volume x Density
Where,Volume = 1000 m³/s, Density = 1000 kg/m³, Mass = 1000 x 1000 = 1000000 kg = 1 x 10⁶ kg
3b) To calculate the gravitational potential energy of 1 kg of water at the top of the falls, we use the formula:
E = mgh
Where,m = 1 kg, g = 10 N/kg, h = 100 m, E = 1 x 10 x 100 = 1000 J
3c) To calculate the speed of the water as it reaches the bottom if all the GPE stored in 1 kg of water is transferred to kinetic energy, we use the formula given below:
PE = KEP
E = mgh
KE = 1/2mv²
Where,PE = Potential Energy (Joules)
KE = Kinetic Energy (Joules)
m = Mass (kg)
g = Gravity (10 N/kg)
h = Height (m)
v = Velocity (m/s)
Assuming that all the potential energy is converted into kinetic energy when the water reaches the bottom,
PE = KEKE = mghv² = 2mghv² = 2(1)(10)(100)v² = 2000v = √(2000) = 44.72 m/s
3d) The water will not be falling as fast as the speed calculated in part c suggests because of the presence of air resistance and the fact that the water falls through a medium (air) which offers resistance to its motion.
3e) To calculate the total energy transferred per second as the GPE stored in the water falling in one second is transferred to other energy stores, we use the formula given below:
Power = Energy / Time
Where,Power = 1 x 10⁶ x 10 x 100 = 1 x 10⁹ W = 1 GW (assuming that 1 m³ of water falls every second)3f)
The energy transferred when the GPE stored in the water falling in one second is transferred to other energy stores is finally stored in thermal energy stores due to the heat generated by the water as it hits the bottom.
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How do space probes make it past the asteroid belt without crashing into asteroids?
Answer:
The thing is space is really vast like really big so even though the asteroid belt looks really cramped it isn't. There's a lot of space between asteriods and using simple navigation and maneuvering, space probes can easily make it through without the threat of crashing.
Explanation:
Net force changes momentum, while net torque changes angular momentum.TrueFalse
ANSWER:
True
STEP-BY-STEP EXPLANATION:
Moment depends on force and angular momentum depends on torque. Which means that if the statement is fulfilled.
Which statement describes the endothermic reaction by this graph?
Answer:
B
endothermic: heat taking in
exothermic: heat given out
Answer:
I thin that the answer is d because the energy goes high and then it goes down a bit
Explanation:
What happens when a constant force is exerted on a cart that is initially at rest on an air track?
The equation states that when a constant force is applied to a cart that is initially at rest on an air track, the speed of the cart will grow linearly with time.
When a constant force is exerted on a cart that is initially at rest on an air track the speed of the cart will increase linearly with time, according to the equation
When a constant force is exerted on a cart that is initially at rest on an air track, the cart will start to accelerate in the direction of the force.
This is described by Newton's second law of motion, which states that the acceleration of an object is directly proportional to the force applied to it, and inversely proportional to its mass. Mathematically, we can express this as:
a = F/m
where a is the acceleration of the cart, F is the applied force, and m is the mass of the cart.
Assuming there is no friction or other resistive forces acting on the cart, it will continue to accelerate indefinitely under the influence of the constant force.
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According to the article Alien Antimatter Crashes into Earth e: More than 60 years ago, future Nobel laureate Sheldon Glashow predicted that if an antineutrino - the antimatter answer to the nearly massless neutrino - collided with an electron, it could produce a cascade of other particles. The "Glashow resonance e" phenomenon is hard to detect, in large part because the antineutrino needs about 1,000 times more energy than what's produced in the most powerful colliders on Earth. Let's compare this event to an ordinary baseball with a mass of 146 g. Please use three significant figures in your calculations. Question 1 2 pts What is the threshold antineutrino energy for the Glashow resonance in peta electronvolts (PeV)? Question 2 2 pts What is this threshold energy in units of joules? dance Question 3 2 pts Now consider a baseball with the same kinetic energy as that of the Glashow resonance. What speed in m/s would correspond to this energy? Question 4 2 pts What is this rate in units of inches/second? Question 5 3 pts Compare and contrast IceCube e to Ice Cube e. How are they the same? How are they different? Edit View Insert Format Tools Table 12pt Paragraph BIU A ev T²v
FULL SOLUTION BELOW THE PIC.
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2-24 a reinforcing rod can be driven about 30 cm into sand soil estimate the soils strength and describe it's condition
The soil strength is estimated to be low, as the reinforcing rod can only penetrate 30 cm into the sand soil. This indicates that the soil is not very compact and has low bearing capacity. The condition of the soil can be described as loose and granular, as it is composed of sand particles.
What is soil strength?Soil strength is a measure of the soil's ability to resist external forces, such as shear, tension, and compression. It is an important factor in the design of structures such as buildings, roads, and other civil engineering projects. Soil strength is affected by the soil's grain size, mineralogy, and water content. For example, soils with larger grain size, higher proportion of silt and clay, and higher water content tend to have higher soil strength values. Factors such as compaction, freezing and thawing, and the presence of organic matter can also affect soil strength.
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PLS HELPPP! Why are ions harmful and why are they not harmful?
Answer:
This is because we are surrounded by positive ions from electromagnetic fields generated by computers, cell phones, and other electronic devices which can impair brain function and suppress the immune system causing symptoms such as: anxiety, breathing difficulty, fatigue, headaches, irritability, lack of energy, poor concentration, nausea, and vertigo,
Explanation:
Answer:
Ions can be harmful because ions can produce dangerous indoor ozone and can waste space and electricity. Hours of negative ion exposure can produce symptoms of depression. On the other hand, ions can help improve our immune systems by strengthening our immune cells. Ions can also speed up the production of antibiotics.
When earth catches up to a slower-moving outer planet and passes it in its orbit, in the same way that a faster runner overtakes a slower runner in an outside lane, the outer planet.
When earth catches up to a slower-moving outer planet and passes it in its orbit, in the same way that a faster runner overtakes a slower runner in an outside lane, the outer planet exhibits a retrograde motion
When a planet is far from another planet and observed from it, it rotates at a slower rate, making it appear that it is "retrograding" with regard to the other planet.
Early astronomers were perplexed when they observed motion in the sky because they attempted to explain it in terms of the geocentric idea.
Due to their commitment to the geocentrical paradigm, which stated the Earth was the center of the solar system, early astronomers were perplexed and unable to explain the phenomena.
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________________ is energy in motion. __________________ is stored energy and _________ cannot be measured. _______________ can be measured.
Energy is a very essential aspect of our daily life, which refers to the capacity to do work. It is the ability to bring about a change in some physical body or the other. Energy takes various forms, and they can be classified into two main groups, i.e., kinetic and potential energy.
Energy is commonly defined as the ability to do work. Work is a force acting over a distance, so energy is always related to work. Energy is expressed in units of work, such as joules (J), which are the same as newton-meters (N·m).Kinetic energy is energy in motion. Potential energy is stored energy, and neither of them can be measured. There are various types of energy, such as heat energy, light energy, sound energy, electrical energy, mechanical energy, nuclear energy, and chemical energy. Heat energy is the energy of moving particles in matter. It flows from hotter objects to colder objects and can be measured in joules. Light energy is the energy that travels in waves and can be seen by the eye. It is also measured in joules.
Sound energy is the energy of vibrating matter and can be heard by the ear. It is measured in decibels (dB).Electrical energy is the energy of moving charges and is used in electronics, lighting, and motors. It is measured in kilowatt-hours (kWh). Mechanical energy is the energy of moving objects, such as gears and pulleys, and is measured in joules. Nuclear energy is the energy stored in the nucleus of an atom and can be released in nuclear reactions. It is measured in electron volts (eV). Chemical energy is the energy stored in chemical bonds and is released in chemical reactions. It is measured in joules (J).
Thus, we can say that energy is the capacity to do work. It takes various forms such as heat energy, light energy, sound energy, electrical energy, mechanical energy, nuclear energy, and chemical energy. Kinetic energy is energy in motion. Potential energy is stored energy, and neither of them can be measured.
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In addition to displacement, which of the following must be used for a more complete description of the average velocity of an object?
acceleration
O change in time
O Distance
O speed
Answer:
Option: 3 Speed √
is the right answer
S) a dam has the cross-section of a square with side length of 10m. find the force due to hydrostatic pressure on the dam when the water is 75% of the way up the wall.
The force due to hydrostatic pressure on the dam when the water is 75% of the way up the wall is 735,750 N
The force due to hydrostatic pressure on the dam can be calculated using the formula
P = ρghA
where P is the force, ρ is the density of the water, g is the acceleration due to gravity, h is the height of the water column, and A is the cross-sectional area of the dam.
In this case, the cross-sectional area of the dam is 100 m2 and the height of the water column is 7.5 m (since the water is 75% of the way up the wall, which is a 10m tall wall). Therefore, the force due to hydrostatic pressure on the dam is
P = 1000 kg/m3 x 9.81 m/s2 x 7.5 m x 100 m2
= 735,750 N
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A horizontal platform in the shape of a circular disk rotates on a frictionless bearing about a vertical axle through the center of the disk. The platform has a mass of 150 kg, a radius of 2.0 m, and a rotational inertia of 300 kg·m2 about the axis of rotation. A 60 kg student walks slowly from the rim of the platform toward the center. If the angular speed of the system is 1.4 rad/s when the student starts at the rim, what is the angular speed when she is 0.70 m from the center?
Answer: \(2.29\ rad/s\)
Explanation:
Given
Mass of Platform M=150 kg
the radius of Platform R=2 m
Moment of inertia of Platform \(I=300\ kg.m^2\)
Mass of student \(m=60\ kg\)
The initial angular speed of the student is \(\omega _1=1.4\ rad/s\)
Initially, the moment of inertia of platform and student is
\(I_1=\dfrac{1}{2}MR^2+mR^2\\\\I_1=300+60\times 4=540\ kg.m^2\)
The final moment of inertia
\(I_2=\dfrac{1}{2}MR^2+mr^2\\\\I_2=300+60\times 0.7^2=329.4\ kg.m^2\)
Conserving angular momentum
\(I_1\omega_1=I_2\omega _2\\\\540\times 1.4=329.4\times \omega_2\\\\\omega_2=\dfrac{756}{329.4}=2.29\ rad/s\)
Lab: Kinetic Energy What is the purpose of the lab, the importance of the topic, and the question you are trying to answer? What is your hypothesis (or hypotheses) for this experiment? What methods are you using to test this (or each) hypothesis? Section II: Data and Observations Locate the data and observations collected in your lab guide. What are the key results? How would you best summarize the data to relate your findings? Do you have quantitative data (numerical results or calculations)? Do you have qualitative data (written observations and descriptions)? How can you organize this date for your report? Section III: Analysis and Discussion What do the key results indicate? If you constructed graphs, what trends do they indicate in your data? Were there any problems with the experiment or the methods? Did you have any surprising results? Section IV: Conclusions What do the results tell you about your hypothesis(es)? How do the data support your claim above? If you could repeat the experiment and make it better, what would you do differently and why?
Pls hurry!!!!!!!! Worth 100 pts!
write the value of g on the moon and Jupiter
Answer:
The value of g on the moon is 1.625 m/s2 and the value of the g on the jupiter is 2.528g.
Jupiter's surface gravity is 24.79/s or 2.528 g .
The acceleration due to gravity on the surface of the moon is approximately 1.625m/s .
hope this helps you
mrk me braniliest plzz
Can frictional forces ever increase an object’s kinetic energy?
Explanation:
friction opposes the relative motion between two bodies,hence it decreases the kinetic energy but, in the view that friction supplies the force that accelerates the object , for example friction helps in walking we can say that friction causes an increase in kinetic energy
Answer:
In most situations, frictional forces tend to reduce the kinetic energy of an object. However, frictional forces can sometimes increase an object's kinetic energy.
1. Re-arrange the Ohm’s Law equation to solve the following:I = Type your answers here.R = Type your answers here.2. Power is equal to voltage multiplied by current. Add the missing information in each of the following power equations.P = V Type your answers here.P = R Type your answers here.P = V2 Type your answers here.
2)
\(\begin{gathered} P=VI \\ P=RI^2 \\ P=\frac{V^2}{R} \end{gathered}\)Explanation
Step 1
Ohm's law states that the strength of a direct current is directly proportional to the potential difference and inversely proportional to the resistance of the circuit.
\(I=\frac{V}{R}\)so
a)
\(I=\frac{V}{R}\)b)
\(\begin{gathered} I=\frac{V}{R} \\ \text{Multiply both sides by R} \\ I\cdot R=R\cdot\frac{V}{R} \\ IR=V \\ \text{divide both sides by I} \\ \frac{RI}{I}=\frac{V}{I} \\ R=\frac{V}{I} \end{gathered}\)Step 2
2
let
Power is equal to voltage multiplied by current.
so
\(P=VI\rightarrow(1)\)also, replacing
\(\begin{gathered} P=VI \\ P=(IR)I \\ P=RI^2\rightarrow(2) \\ \end{gathered}\)also
\(\begin{gathered} V^2=I^2R^2 \\ \text{hece} \\ I^2=\frac{V^2}{R^2} \\ \\ \text{therefore, } \\ P=RI^2\rightarrow(2) \\ P=\frac{V^2}{R^2}\cdot R \\ P=\frac{V^2}{R} \end{gathered}\)I hope this helps you
ASAP HELP!! Showing the entire question for information I only need the data and conclusion. Please hurry!
Electromagnetic Spectrum Lab Report
Instructions: In this virtual lab, you will use a virtual spectrometer to analyze astronomical bodies in space. Record your hypothesis and spectrometric results in the lab report below. You will submit your completed report to your instructor.
Procedure:
Using your summary questions at the end of your virtual lab activity, please clearly define the dependent and independent variables of the experiment.
Data:
Record the elements present in each unknown astronomical object. Be sure to indicate “yes” or “no” for each element.
Hydrogen Helium Lithium Sodium Carbon Nitrogen
Moon One
Moon Two
Planet One
Planet Two
Conclusion:
Your conclusion will include a summary of the lab results and an interpretation of the results. Please answer all questions in complete sentences using your own words.
Using two to three sentences, summarize what you investigated and observed in this lab.
Astronomers use a wide variety of technology to explore space and the electromagnetic spectrum; why do you believe it is essential to use many types of equipment when studying space?
If carbon was the most common element found in the moons and planets, what element is missing that would make them similar to Earth? Explain why. (Hint: Think about the carbon cycle.)
We know that the electromagnetic spectrum uses wavelengths and frequencies to determine a lot about outer space. How does it help us find out the make-up of stars?
Why might it be useful to determine the elements that a planet or moon is made up of?
Answer:
In this lab, we used a virtual spectrometer to analyze the elements present in unknown astronomical objects. We observed that Moon One had hydrogen, helium, and carbon present, while Moon Two had hydrogen, helium, lithium, sodium, carbon, and nitrogen present. Planet One had hydrogen, helium, lithium, sodium, and carbon present, while Planet Two had hydrogen, helium, lithium, sodium, carbon, and nitrogen present.
It is essential to use many types of equipment when studying space because the electromagnetic spectrum is made up of many different wavelengths and frequencies, and each one provides different information. If carbon was the most common element found in the moons and planets, oxygen would be missing, which is necessary for the carbon cycle to occur. The electromagnetic spectrum helps us find out the make-up of stars by allowing us to detect the different wavelengths and frequencies of light they emit, which can tell us the elements they are composed of.
It is useful to determine the elements that a planet or moon is made up of because it can provide insight into the planet's atmosphere, climate, and potential for life. Knowing the elements present can also help us understand the history of the planet or moon, such as how it was formed and how it has evolved over time.
Squall lines most often form ahead of a: a. cold front. b. warm front. c. cold-type occluded front. d. warm-type occluded front.
Squall lines most often form ahead of a cold front. A squall line is a narrow band of thunderstorms that form along or ahead of a cold front.
As the cold front moves into a warm, moist air mass, it causes the warm air to rise rapidly and triggers the development of thunderstorms. These storms can produce strong winds, heavy rain, and lightning, and can sometimes develop into severe thunderstorms that produce tornadoes. Squall lines are often associated with the development of severe weather, and it is important to monitor weather forecasts and take appropriate safety precautions when a squall line is expected.
While squall lines can form ahead of other types of fronts, they are most commonly associated with cold fronts. In contrast, warm fronts tend to produce more widespread, light to moderate precipitation and are less likely to produce severe weather.
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23. What is the total resistance of the combination of two resistors in the diagram?
A. 0.03
B. 0.15
C. 6.67
D. 30
One glass microscope slide is placed on top of another with their left edges in con- tact and a human hair under the right edge of the upper slide. As a result, a wedge of air exists between the slides. An interference pattern results when monochromatic light is incident on the wedge. What is observed at the left edge of the slides? a. A dark fringe b. A bright fringe c. Impossible to determine
Answer:
A dark fringe
If you free the cork in a highly pressurized champagne bottle, the resulting launch of the cork will, in principle, cause the bottle to recoil. A filled champagne bottle has a mass of 1. 8 kg. The cork has a mass of 7. 5 g and is launched at 22 m/s.
The speed of the bottle when recoiling if it could move freely is 0.092 m/s.
The problem isn't complete. A similar problem is in the attachment. When we free the cork from the bottle, the cork and the bottle have a collision. According to the law of conservation of momentum, the momentum before and after the collision is the same.
p = p'
m₁ v₁ + m₂ v₂ = m₁ v₁' + m₂ v₂'
m₁ = the mass of the cork = 7.5 grams = 0.0075 kgm₂ = the mass of the bottle = 1.8 kgv₁ = the speed of the cork before collision = 22 m/sv₁' = the speed of the cork after collision = 0m₁ v₁ + m₂ v₂ = m₁ v₁' + m₂ v₂'
(0.0075 × 22) + (1.8 × 0) = (0.0075 × 0) + (1.8 × v₂')
0.165 + 0 = 0 + 1.8v₂'
1.8v₂' = 0.165
v₂' = 0.165 ÷ 1.8
v₂' = 0.092 m/s
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A ball of mass of 0.5kg is dropped from a height of 2m.
Assuming that all of the GPE is transferred to KE, what
will be the velocity of the ball when it hits the ground?
Answer:
6.3m/s
Explanation:
Given parameters:
Mass of the ball = 0.5kg
Height = 2m
Unknown:
Velocity when the ball hits the ground = ?
Solution:
Since the potential energy is transformed into kinetic energy;
P.E = K.E
mgh = \(\frac{1}{2}\) m v²
cancelling m;
gh = \(\frac{1}{2}\) v²
v² = 2gh
v = √2gh
Insert the parameters and solve;
v = √2gh = √ 2 x 9.8 x 2 = 6.3m/s
A proton and an electron are placed in an electric field. Which undergoes the lesser acceleration?.
An Electron will undergoes the lesser acceleration
What is Proton and Electron ?An electron is a negatively charged particle of equivalent magnitude to a proton, which is positively charged. Therefore, they will feel the same amount of electric force when exposed to an electric field. As a result, the relationship between acceleration and mass will be inverse. An electron will accelerate more quickly than a proton because an electron has a lower mass.
Due to their opposite polarity, an electron and a proton are attracted to one another by an electrical force of equal strength when they are placed in an electric field. However, because of their opposing charges, the force will act in the opposite direction.
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Which statements describe surface waves? select three options. they arrive before s waves. they travel slower than p waves. they result in much ground motion. they are produced by p and s waves. they travel deep below earth’s surface.
how much electric potential energy was initially given to each culoumb of charge by the power supply
The amount of electric potential energy initially given to each Coulomb of charge by the power supply can be determined by calculating the potential difference of the power supply.
The electric potential energy is defined as the energy a charged particle possesses due to its position in an electric field.
The potential energy of a charged particle is equivalent to the amount of work done in moving the charge against the electric field from one position to another.
This can be expressed mathematically using the formula; Potential energy = Charge × Potential difference.
In order to determine the electric potential energy given to each Coulomb of charge by the power supply,
we need to use the equation;
Potential difference = Electric potential energy / Charge
Thus, Electric potential energy = Charge × Potential difference
Therefore, the amount of electric potential energy initially given to each Coulomb of charge by the power supply can be determined by calculating the potential difference of the power supply.
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