The average study hours are the same for both groups, but the mode, median, and range differ between the two age groups.
Based on the provided responses, here is the comparison of the data for the two groups of teens:
1. The 13- to 15-year-olds spent an average of 14 hours studying last week, which is the same as the average for the 16- to 18-year-olds.
2. The mode for the hours spent studying last week for the 13- to 15-year-olds is less than the mode for the 16- to 18-year-olds, indicating that there was a higher concentration of hours for a specific value in the 16- to 18-year-old group.
3. The median value for the hours spent studying last week for the 13- to 15-year-olds is greater than the median value for the 16- to 18-year-olds, suggesting that the middle value of study hours is higher for the younger group.
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Which choice is equivalent to the fraction below when x is an appropriate value? Hint: Rationalize the denominator and simplify. 5/5+√10x
Answer:
The equivalent fraction is: \(\frac{5-\sqrt{10x} }{5-2x} }\)
which agrees with the second answer in the list of options
Step-by-step explanation:
Recall that in order to rationalize a denominator of this type (remove the square roots), we need to multiply numerator and denominator of the fraction we have by the conjugate of the binomial. That is, multiply top and bottom of the fraction by the expression:
\(5-\sqrt{10\,x}\)
Therefore we have:
\(\frac{5}{5+\sqrt{10\,x} } =\frac{5\,(5-\sqrt{10x} )}{(5+\sqrt{10\,x})\,(5-\sqrt{10x})} =\frac{5\,(5-\sqrt{10x} )}{(25-10x)} }=\frac{5\,(5-\sqrt{10x} )}{5\,(5-2x)} }=\frac{5-\sqrt{10x} }{5-2x} }\)
Then this is the equivalent rationalized expression:
\(\frac{5-\sqrt{10x} }{5-2x} }\)
Answer:
B.
Step-by-step explanation:
A P E X
You have bag filled with 6 red marbles, 4 blue marbles, and 8 yellow marbles. What is the probability of pulling out a red marble?
Step-by-step explanation:
Simple
Total no of marbles = 6 + 4 + 8 = 18
Probability of red marble = 6 / 18 = 1/ 3
which is true about confidence intervals? group of answer choices both are true. large sample produce small confidence intervals. small samples produce large confidence intervals.
Both of the following statements are true about confidence intervals: Small samples produce large confidence intervals. Large samples produce small confidence intervals.
Confidence intervals are statistical estimations used in hypothesis testing. They are calculated from a random sample taken from a population, and they help to measure the accuracy and variability of the population parameter being tested.
The confidence interval is calculated by using a sample mean and a margin of error. In general, the larger the sample size, the smaller the margin of error and the narrower the confidence interval. The confidence interval is larger if the sample size is small, indicating that the sample mean is less likely to accurately represent the population parameter.
Small samples will produce larger confidence intervals because of greater uncertainty in the sample estimates. In contrast, larger samples will produce smaller confidence intervals because they provide more accurate estimates of the population parameter.
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PLSSS HELP IF YOU TURLY KNOW THISS
Answer:
answer [-19]d + [4]p +[2]
Answer:
\(-9d-4p-6-10d+8=-19d-4p+2\)
Step-by-step explanation:
\(-9d-4p-6-10d+8\)
\(=-9d-10d-4p-6+8\)
\(=-19d-4p-6+8\)
\(=-19d-4p+2\)
So the answer would be -19d-4p+2
hopefully this helps you ~
im stuck whats the answer b3=1000
Answer:
b=0.003 happy to help ya:) and pls help me in my question if u dont mind
Step-by-step explanation:
Answer:
If its b cubed, then b = 10. If you meant to say 3b, then b = 333.333333
Which ordered pairs are solutions to the inequality y−4x≥−5?
Select each correct answer.
Responses
(−4,2)
begin ordered pair negative 4 comma 2 end ordered pair
(1,−1)
begin ordered pair 1 comma negative 1 end ordered pair
(5,−2)
begin ordered pair 5 comma negative 2 end ordered pair
(−2,1)
begin ordered pair negative 2 comma 1 end ordered pair
(4,0)
begin ordered pair 4 comma 0 end ordered pair
If we use the ordered pair (5, -2), then we have:
5 - 4*(-2) ≥ −5
5 + 8 ≥ −5
13 ≥ −5
This is true, so the ordered pair (5, -2) is a solution.
Which ordered pairs are solutions to the inequality y−4x ≥ −5?
An ordered pair will be a solution of an inequality only if it makes the statement true.
In this case, it means that the left side is equal or larger than the right side.
So, what we need to do is evaluate the given points in the inequality, and see which one makes the inequality true.
If we use the ordered pair (5, -2), then we have:
5 - 4*(-2) ≥ −5
5 + 8 ≥ −5
13 ≥ −5
This is true, so the ordered pair (5, -2) is a solution.
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Answer: (5,1) and (4, -2)
Step-by-step explanation:
I had the same quiz with this question. :)
In a statistical study, it is desired to know the degree of satisfaction of engineering students with the facilities provided by a university. A sample of 50 students gave the following answers:
very satisfied satisfied regular dissatisfied very dissatisfied regular regular satisfied very satisfied regular very dissatisfied satisfied regular very dissatisfied very dissatisfied
satisfied satisfied dissatisfied regular very satisfied very satisfied satisfied regular dissatisfied very dissatisfied regular regular satisfied very satisfied regular
very dissatisfied satisfied regular very dissatisfied very dissatisfied satisfied satisfied dissatisfied regular very satisfied satisfied satisfied dissatisfied regular very satisfied
very satisfied satisfied regular dissatisfied very dissatisfied
Describe the statistical variable and obtain the frequency distribution. Then present the grouped data in bar charts and pie charts. Finally develop a brief commentary on the results of the survey.
2. In a hospital, the number of meters that each child walks without falling, the first day he or she begins to walk, has been recorded for a month. In a sample of 40 children the data are as follows:
1 2 1 2 2 2 2 2 5
6 6 6 7 7 3 3 3 3
3 5 5 5 3 3 3 3 4
4 4 4 4 3 5 5 5 5
5 5 8 8
Describe the survey variable and obtain the frequency distribution of the data. Then, make a stick graph showing the absolute and relative frequencies comparatively. Finally, develop a brief commentary.
The majority of the children can walk between 4.5 and 10 meters without falling.
1. The statistical variable in the case of the degree of satisfaction of engineering students with the facilities provided by a university is ordinal as it includes verbal responses that are not represented by numbers in the sense that they can be added, subtracted, or averaged.
The frequency distribution of the data is given as follows:
Rating Frequency
Very satisfied 6
Satisfied 10
Regular 13
Dissatisfied 4
Very dissatisfied 8
Grouped Data in Bar Chart
Pie Chart Comment on the results of the survey
The majority of the engineering students (6+10)/50=32/50, or 64%, are satisfied with the facilities provided by the university.2. The survey variable is quantitative as it involves recording the distance walked by the child and it can be represented by numbers.
Also, the variable is discrete as the data cannot be measured in fractions.
The frequency distribution of the data is given as follows:
Distance walked Frequency Relative Frequency Absolute frequency (f)Relative frequency (f/N)
0 < d ≤ 22.5
m3 0.0752.5 < d ≤ 44
0.1 4.5 < d ≤ 65
0.1256.5 < d ≤ 86
0.1508 < d ≤ 1030
0.375
Total40 1
The stick graph showing the absolute and relative frequencies comparatively is shown below:
Stick Graph Comment
The graph shows that the highest frequency (relative and absolute) is in the interval 8 < d ≤ 10 and the lowest frequency is in the interval 0 < d ≤ 2.5.
Also, the majority of the children can walk between 4.5 and 10 meters without falling.
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simplify the following expression. 5.3x − 8.14 3.6x 9.8 a. -2.84x − 1.66 b. 8.9x 1.66 c. -2.84x 17.94 d. 8.9x 17.94
The simplified expression is (-187.584x + 287.6672) / 6.8, which is equivalent to option A: -2.84x - 1.66.
To simplify the expression 5.3x - 8.14 / 3.6x - 9.8, we can first simplify the division by finding a common denominator for the fractions.
The common denominator for 3.6x and 9.8 is 3.6x * 9.8 = 35.28x.
Next, we can rewrite the expression using the common denominator:
5.3x * (35.28x/35.28x) - 8.14 * (35.28x/35.28x) / 3.6x * (35.28x/35.28x) - 9.8 * (35.28x/35.28x)
Simplifying further, we get:
(5.3 * 35.28x^2 - 8.14 * 35.28x) / (3.6 * 35.28x - 9.8 * 35.28x)
Now, we can simplify the numerator:
(187.584x^2 - 287.6672x) / (-6.8x)
Factoring out an x from the numerator, we have:
x(187.584x - 287.6672) / (-6.8x)
Finally, we can cancel out the x terms:
(187.584x - 287.6672) / -6.8
Therefore, the simplified expression is (-187.584x + 287.6672) / 6.8, which is equivalent to option A: -2.84x - 1.66.
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A nutrition researcher wants to determine the mean fat content of hen's eggs. She collects a sample of 40 eggs. She calculates a mean fat content of 23 grams with a sample standard deviation of 8 grams. From these statistics, she calculates a 90% confidence interval of 20.9 grams to 25.1 grams. What can the researcher do to decrease the width of the confidence interval?
a. increase the confidence level
b. decrease the confidence level
c. decrease the sample size
d. none of the above
To decrease the width of the confidence interval, the researcher can take the following steps:
1. Decrease the confidence level: The confidence interval width is inversely proportional to the confidence level. By decreasing the confidence level, the researcher can have a narrower interval. However, it is important to note that decreasing the confidence level also increases the chance of the interval not capturing the true population mean.
2. Increase the sample size: The sample size affects the precision of the estimate. Increasing the sample size reduces the standard error, which leads to a narrower confidence interval. This is because a larger sample provides more information about the population.
Therefore, the researcher can decrease the width of the confidence interval by either decreasing the confidence level or increasing the sample size. Both approaches will result in a narrower interval, providing a more precise estimate of the mean fat content of hen's eggs.
The researcher can decrease the width of the confidence interval by either decreasing the confidence level or increasing the sample size. Both approaches will result in a more precise estimate of the mean fat content of hen's eggs.
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Check all of the expressions that are equal to the one below. (-8). (4 + 6) O A. (6 + 4) • (8) B. (-8) • 4 + (-8) - 6 O C. (4+6) • (-8) O D. (-8) • 4-(8) • 6
Answer:
1 is, 2 is, 3 isn't, 4 isn't
Step-by-step explanation:
Some answers may not add up the same way!
how many people have to be in a room in order that the probability that at least two of them celebrate their birthday in the same month is at least assume that all possible monthly outcomes are equally likely.
The people having to be in a room in order that the probability that at least two of them celebrate their birthday in the same month is at least 1/2 is 5.
X = No of people having same month birth day
We need, P(X 2) ≥ 1/2
= 1-P(X ≤1) ≥ 1/2
1-P(No one having same month birth day) ≥ 1/2
P(No one having same month birth day)≤ 1/2..........................(1)
Now, k = Minimum no of people required to satisfy (1)
P(No one having same month birth day) =
\(\frac{11*10*9......*(12-k+1)}{12*12*12......*12}\)
for k= 4
P(No one having same month birth day) =
\(\frac{11.10.9}{12.12.12} = 0.572 \geq 0.5\)
for k= 5
P(No one having same month birth day) =
\(\frac{11.10.9.8}{12.12.12.12} = 0.38 \leq 0.5\)
Therefore , the people having to be in a room in order that the probability that at least two of them celebrate their birthday in the same month is at least 1/2 is 5.
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George reads 692 pages in a month. Lisa reads twice as many pages as George. Wade reads 45 fewer pages than Lisa. How many pages did the three friends read altogether?
please help
Answer:
The answer is 2471 I think
Answer:
the answer is 2723
Step-by-step explanation:
you add 692 + lizas, which is double the amount, 1384, then you subtract 45 from that and get 1339, then you add them
a sequence is given by the rule 4n - 5. what is the 20th term in the sequence?
Answer:
a₂₀ = 75
Step-by-step explanation:
Substitute n = 20 into the n th term rule , that is
a₂₀ = 4(20) - 5 = 80 - 5 = 75
Multiple-Choice Tests Professor Easy's final examination has 14 true-false questions followed by 2 multiple-choice questions. In each of the multiple-choice questions, you must select the correct answer from a list of four. How many answer sheets are possible
Numerous-Choice Exams 14 true-false and two multiple-choice questions make up Professor Easy's final exam. There are 65,536 possible answer sheets.
For each true-false question, there are two possible answers (true or false), so there are \(2^{14\) possible answer sheets for the true-false questions.
For each multiple-choice question, there are 4 possible answers. Since there are 2 multiple-choice questions, there are \(4^2 = 16\) possible answer sheets for the multiple-choice questions.
To find the total number of possible answer sheets, we need to multiply the number of possible answer sheets for the true-false questions by the number of possible answer sheets for the multiple-choice questions. Therefore, the total number of possible answer sheets is:
\(2^{14} \times 16 = 65,536\)
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solve for x. please please i need help help me please
Select all the correct answers. What is 221,000,000,000,000,000,000 expressed in scientific notation? 2. 21 × 1021 2. 21E20 2. 21E21 2. 21E-20 2. 21 × 10-21 2. 21 × 10-20 2. 21 × 1020 2. 2.10E-20.
To solve the problem we must know about Scientific notations.
Scientific notationsThe way through which a very small or a very large number can be written in shorthand. In scientific notations when a number between 1 and 10s is multiplied by a power of 10.
For example, 6,500,000,000,000 can be written as 6.5e+12.
The number of 221,000,000,000,000,000,000 can be represented as 2.21e+21.
ExplanationGiven to us
221,000,000,000,000,000,000The above number can be written as 2.21e+21.
As in scientific notations, the number between 1 and 10 can only be represented, therefore, the number can be only 2.21e+21.
Hence, the number of 221,000,000,000,000,000,000 can be represented as 2.21e+21.
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Consider the like segment PQ with endpoints P(-3,-4) and Q(2,1). which point divides the line segment directed from Q to P in the ratio of 2:3?
The point that divides the line segment PQ in the ratio of 2:3 is R(0, -1).
To find the point that divides the line segment PQ in the ratio of 2:3, we can use the section formula.
Let the point that divides PQ in the given ratio be denoted by R. Then, the coordinates of R can be found using the following formula:
R = [(3Q + 2P) / 5]
Here, 3Q refers to the point Q taken thrice and 2P refers to the point P taken twice. We can substitute the values of P and Q in this formula to get the coordinates of R.
R = [(3 x (2, 1) + 2 x (-3, -4)) / 5] = [(6, 3) + (-6, -8)] / 5 = (0, -1)
Therefore, the point that divides the line segment PQ in the ratio of 2:3 is R(0, -1).
In summary, we can find the point that divides a line segment in a given ratio by using the section formula.
This formula involves the coordinates of the endpoints of the line segment and the ratio in which the point divides the segment.
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Sarah is trying to run a certain number of miles by the end of the month. If Sarah is 80% of the way to achieving her goal and she has already run 40 miles, how many miles is she trying to run by the end of the month?
Answer: 50 miles
Step-by-step explanation:
Let the miles that she is trying to run by the end of the month be denoted by x.
Since she is 80% of the way to achieving her goal and she has already run 40 miles. This can be expressed as:
80% of x = 40
80/100 × x = 40
0.8x = 40
x = 40/0.8
x = 50
The miles that she is trying to run by the end of the month is 50 miles.
II. Truth Table. 1. \( [\sim p \leftrightarrow(\sim q \wedge \sim r)] \vee \sim[q \wedge(p \rightarrow \sim p)] \)
The truth value of the expression [~P ↔ (~Q ∧ ~R)] ∨ ~[Q ∧ (P → ~P)] is 1 for all combinations of truth values.
To create a truth table for the expression [~P ↔ (~Q ∧ ~R)] ∨ ~[Q ∧ (P → ~P)], we need to consider all possible combinations of truth values for the variables P, Q, and R.
Let's analyze the expression step by step:
1. Define the variables:
P, Q, R
2. Evaluate the subexpressions:
~P: The negation of P
~Q: The negation of Q
~R: The negation of R
~[Q ∧ (P → ~P)]: The negation of the conjunction of Q and (P → ~P)
3. Construct the truth table:
| P | Q | R | ~P | ~Q | ~R | (Q ∧ ~R) | (P → ~P) | ~[Q ∧ (P → ~P)] | ~P ↔ (~Q ∧ ~R) | [~P ↔ (~Q ∧ ~R)] ∨ ~[Q ∧ (P → ~P)] |
|---|---|---|----|----|----|----------|----------|----------------|-----------------|---------------------------------|
| 0 | 0 | 0 | 1 | 1 | 1 | 0 | 1 | 1 | 0 | 1 |
| 0 | 0 | 1 | 1 | 1 | 0 | 0 | 1 | 1 | 0 | 1 |
| 0 | 1 | 0 | 1 | 0 | 1 | 0 | 1 | 1 | 0 | 1 |
| 0 | 1 | 1 | 1 | 0 | 0 | 0 | 1 | 1 | 0 | 1 |
| 1 | 0 | 0 | 0 | 1 | 1 | 1 | 0 | 0 | 1 | 0 |
| 1 | 0 | 1 | 0 | 1 | 0 | 0 | 0 | 1 | 0 | 1 |
| 1 | 1 | 0 | 0 | 0 | 1 | 0 | 0 | 1 | 0 | 1 |
| 1 | 1 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 1 |
In the truth table above, each row represents a unique combination of truth values for the variables P, Q, and R. The last column represents the final truth value of the expression [~P ↔ (~Q ∧ ~R)] ∨ ~[Q ∧ (P → ~P)] for each combination of truth values.
Therefore, the truth table for the expression is as follows:
| [~P ↔ (~Q ∧ ~R)] ∨ ~[Q ∧ (P → ~P)] |
|-----------------------------------|
| 1 |
| 1 |
| 1 |
| 1 |
| 0 |
| 1 |
| 1 |
| 1 |
The truth value of the expression [~P ↔ (~Q ∧ ~R)] ∨ ~[Q ∧ (P → ~P)] is 1 for all combinations of truth values.
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Complete question is below
Truth Table. 1. [~P↔(~Q∧~R)]∨~[Q∧(P→~P)]
The sum of the squared deviation scores is ss = 20 for a population of n = 5 scores. what is the variance for this population?
When the sum of the squared deviation scores is SS=20 for a population n=5 scores, then the variance for this population is 4
Given,
The sum of the squared deviation scores SS= 20
Population of n= 5
Then the variance = SS/n
Substitute the values in the equation
The variance = \(\frac{20}{5}\)
=4
Hence, when the sum of the squared deviation scores is SS=20 for a population n=5 scores, then the variance for this population is 4
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1) megan is making a quilt from squares of material. the quilt has 9 rows of 6 squares. the
corner squares and the two center squares in the middle row are white. each square sharing a
side with a white square is gold. of the remaining squares, half are blue and half are pink.
a)
how many squares are gold?
how many squares are blue?
b)
The total number of gold and blue squares are 18 and 13 respectively.
Here, we are given that Megan is making a quilt from squares of material.
The quilt has 9 rows and each row has 6 squares.
There are 4 corner squares in the quilt which will be white. Around 1 corner square there will be 3 squares that share a side with the white square.
Thus, there will be a total of 12 gold square around the 4 corner squares.
Further, there are two center squares in the middle row that are white.
Around these 2 center white squares there will be 6 squares that share a side with them. Hence, these 6 square will also be gold.
Therefore, the total number of gold squares will be-
6 + 12
= 18
Now, the white squares = 4 + 6 = 10
and gold squares = 18
and the total number of squares = 9 × 6 = 54
Thus, the number of remaining squares = 54 - 18 - 10
= 26
Out of these remaining 26 squares half will be blue and half pink.
Thus, the number of blue squares will be-
26/2
= 13
Hence, we find that the total number of gold and blue squares are 18 and 13 respectively.
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Can someone help me plsss!! As soon as possible!
Which statement is true?
Answer:
this probably isn't right, but with an educated guess it's probably the third answer.
Step-by-step explanation:
What is 3 1/5 * 2 1/4
To multiply two mixed numbers, one way to do it is to convert them into pure fractions and then multiply them:
\(3\text{ 1/5}\cdot2\text{ 1/4}=(3+\frac{1}{5})\cdot(2+\frac{1}{4})=(\frac{15+1}{5})\cdot(\frac{8+1}{4})=\frac{16}{5}\cdot\frac{9}{4}=\frac{144}{20}=\frac{36}{5}\)The product is 36/5, that can be expressed as mixed number as:
\(\frac{36}{5}=\frac{35+1}{5}=7+\frac{1}{5}\)Answer: The product (3 1/5 * 2 1/4) is 36/5 or 7 1/5.
find the first 5 terms in 3n^2/2
Help please, If your mom is making a garden and she wants it it be 5 yards how much cm is that
Answer:
it would be 457.2 cm or if you want it simplified then it would be 457 cm
hope this helped :)
Control questions:: 1. The organization of educational process at the department: staffing, textbooks, individual scientific work and so on. 2. Biochemical laboratory - safety rules 3. Determination of biochemistry as a science. Biochemistry objects and tasks 4. Biochemistry sections, achievements and perspectives 5. Role of biochemistry in the study of molecular genetics mechanisms of diseases 6. Amino acids - classification, structure, physico-chemical properties 7. Features of the chemical composition of living organisms 8. Simple and complex proteins: structure, classification, biological significance 9. Physico-chemical properties of proteins. Protein denaturation 10. Levels of structural organization of the protein molecule
The topics covered include the organization of educational processes, biochemical laboratory safety rules, defining biochemistry as a science, biochemistry sections and achievements, biochemistry's role in studying molecular genetics of diseases, amino acid properties, chemical composition of living organisms, structure and significance of proteins, physico-chemical properties of proteins, and levels of protein structural organization.
The focus of the first topic regarding the organization of educational processes at the department is to discuss the staffing, textbooks, individual scientific work, and other aspects related to the educational process.
The topic of discussion in the second question related to the biochemical laboratory is the safety rules that need to be followed in the laboratory setting.
The main point being addressed in the topic of determining biochemistry as a science is to define and establish biochemistry as a distinct scientific discipline, discussing its objects and tasks.
The discussion of biochemistry sections, achievements, and perspectives covers various aspects such as the different branches or areas of biochemistry, notable accomplishments or advancements in the field, and the future prospects or directions of research.
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what is the probability that this student does spend more than $25 a week on gas? a. 0.2445 b. 0.7555 c. 0.6740 d. 0.8403 e. 0.4532
Using conditional probability, it is found that there is a 0.83 = 83% almost 0.8403 probability that this student does spend more than $25 a week on gas, given that he/she does commute to school each day.
Probability: -
Probability is the branch of mathematics concerning numerical descriptions of how likely an event is to occur, or how likely it is that a proposition is true. The probability of an event is a number between 0 and 1, where, roughly speaking, 0 indicates impossibility of the event and 1 indicates certainty. Since the coin is fair, the two outcomes ("heads" and "tails") are both equally probable; the probability of "heads" equals the probability of "tails"; and since no other outcomes are possible, the probability of either "heads" or "tails" is 1/2 (which could also be written as 0.5 or 50%).
Conditional Probability :
Using conditional probability, it is found that there is a 0.83 = 83% = P( A∩ B) / P(A)
In which
P(B|A) is the probability of event B happening, given that A happened.P(A∩B) is the probability of both A and B happening.P(A) is the probability of A happening.In this problem:
Event A: Commute to school each day.
Event B: Spends more than $25 a week.
80% indicated that they commute to school each day. of those that commute to school each day, hence , P(A) = 0.8
Of those, 83% spend more than $25 a week on gasoline, hence .
P(B|A) = 0.83
Thus, 0.83 = 83% probability that this student does spend more than $25 a week on gas, given that he/she does commute to school each day.
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A school playground is in the shape of a rectangle 800 feet long and 700 feet wide. If fencing costs $18 per yard, what will it cost to place fencing around the playground?
Answer:
pomogło dzięki xxxxxxxxxx
MP.7 Use Structure Sue and Jonah
chose numbers for a place-value game.
Sue chose the number one hundred
fifty-two thousand. Jonah chose five
million for his number. Who chose the
greater number? Explain.
Jonah has chosen the greater number.
Given, Sue and Jonah chose numbers for a place value game.
As a way to express numbers, a number system is a way of expressing them. It is a method of describing numbers from a particular set mathematically by consistently employing digits or other symbols. Every number is given a distinct representation, and the figures' algebraic and mathematical structures are also shown.
Sue chose the number = one hundred fifty two thousand
= 152000
= 1.52 lakhs
Jonah chose the number = five million
= 5,000,000
we know that 10 lakhs = 1 million = 1,000,000
therefore, 5 million = 5 × 10 lakhs
= 50 lakhs
50 lakhs > 1.5 lakhs
the greater number is 5 million.
Therefore , the greater number chose by Sue and Jonah is of Jonah's that is 5 million.
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sally purchased 24 pencils 1/8 of the pencils are blue 1/6 of the pencils are red how many pencils are either red or blue
A. 17
B.14
C.7
D.4
Answer:
4
Step-by-step explanation:
Because the common multiple of 6 and 8 is 24 which is the amount of pencils.
1/8 x 3 equals 24 (3 because 3 times 8 gives 24)
1/6 x 4 equals 24 (4 because 4 times 6 gives 24)