Rank these automobiles based on the magnitude of the impulse needed to stop them, from largest to smallest. Rank from largest to smallest. To rank items as equivalent, overlap them. If the ranking cannot be determined, check the box below. The correct ranking cannot be determined. Part C Rank the automobiles based on the magnitude of the force needed to stop them, from largest to smallest. Rank from largest to smallest. To rank items as equivalent, overlap them. If the ranking cannot be determined, check the box below. The correct ranking cannot be determined.

Answers

Answer 1

Based on linear velocity, size of impulse, and force required to stop them, the automobiles are ranked from largest to smallest in size.

Light blue car = Purple car > Red car = Yellow car =  Blue car > Green car

What exactly is Impulse?

As fast-acting force or "impact" is referred to as "impulse," impulse may be described as "the abrupt force operating on an item for a brief period of time."

How do we solve the given question?

Force (F), Impulse (J) and linear momentum (P) are related as

P = mu

where m = mass

           u = initial velocity

J = ΔP = m (v - u)

Impulse is the change in momentum as we know.

J = F.t

Therefore, P ∝ J ∝ F

Thus, it follows that the force and impulse required to stop each automobile are precisely proportional to its linear momentum.

The Red car's linear momentum is computed as;

P = 1000 x 10 = 10, 000 kg.m/s

The Yellow car's linear momentum is computed as;

P = 2,000 x 5 = 10,000 kg.m/s

The Blue car's linear momentum is computed as;

P = 500 x 20 = 10,000 kg.m/s

The Light blue car's linear momentum is computed as;

P = 1,000 x 20 = 20,000 kgm/s

The Purple car's linear momentum is computed as;

P = 4,000 x 5 = 20,000 kg.m/s

Therefore the rankin of the automobiles will be

Light blue car = Purple car > Red car = Yellow car =  Blue car > Green car

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The complete question is;

Six automobiles are initially traveling at the indicated velocities. The automobiles have different masses and velocities. The drivers step on the brakes and all automobiles are brought to rest. Red Car: 1000kg, 10m/s Yellow Car: 2,000kg, 5m/s Blue Car: 500kg, 20m/s Light Blue Car: 1,000kg, 20m/s Green Car: 500kg, 10m/s Purple Car: 4,000kg, 5m/s Part A Rank these automobiles based on the magnitude of their momentum before the brakes are applied, from largest to smallest. Rank from largest to smallest. To rank items as equivalent, overlap them. Part B Rank these automobiles based on the magnitude of the impulse needed to stop them, from largest to smallest. Rank from largest to smallest. To rank items as equivalent, overlap them. Part C Rank the automobiles based on the magnitude of the force needed to stop them, from largest to smallest. Rank from largest to smallest. To rank items as equivalent, overlap them.


Related Questions

8. How much power is used if you use a 20 N force to push a shopping cart 3.5 m in 2 s?

Answers

The power used, given that a force of 20 N is used to push the shopping cart 3.5 m in 2 seconds is 35 W

How do i determine the power used?

First, we shall determine the work done in pushing the cart. Details below:

Force used (F) = 20 NDistance (d) = 3.5 mWork done (Wd) = ?

Wd = Fd

Wd = 20 × 3.5

Wd = 70 J

Finally, we shall determine the power used in pushing the cart. Details below:

Work done (Wd) = 70 JTime (t) = 2 secondsPower used (P) = ?

P = Wd / t

P = 70 / 2

P = 35 W

Thus, we can conclude that the power used is 35 W

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What is the net force acting on the box?
0 285 N
0 185 N
SN
0 85 N
0 65 N

Answers

Answer:

the answer would be D 65N

Explanation:

just got it correct on EDG

How much POWER is used in 30 seconds when you complete 150 Joules of work?

Answers

Answer:

Power of 5 watts is used

Explanation:

Mechanical Work and Power

Mechanical work is the amount of energy transferred by a force.

Being F the force vector and s the displacement vector, the work is calculated as:

\(W=\vec F\cdot \vec s\)

If both the force and displacement are parallel, then we can use the equivalent scalar formula:

W=F.s

Power is the amount of energy converted per unit of time. The SI unit of power is the watt, equal to one joule per second.

The power can be calculated as:

\(\displaystyle P=\frac {W}{t}\)

Where W is the work and t is the time.

It's required to calculate the power used in t=30 seconds when W=150 Joules of work are completed. Substitute in the formula:

\(\displaystyle P=\frac {150}{30}\)

P = 5 Watt

Power of 5 watts is used

explain why the insulting layer of fleece is good at reducing the rate of energy transfr

Answers

The insulating layer of fleece is effective at reducing the rate of energy transfer due to its unique properties and structure. Fleece is made of synthetic fibers or natural fibers such as wool, which have excellent insulating properties.

One key factor is the structure of fleece. Fleece fabric consists of many small air pockets trapped within the fibers. Air is a poor conductor of heat, so these air pockets act as a barrier to prevent the transfer of thermal energy. The trapped air creates a layer of insulation that helps to slow down the transfer of heat between the body and the environment.

Furthermore, fleece has a high loft, meaning it is thick and fluffy. The loft creates additional air space and increases the insulation capacity. The thickness of the fleece allows for more air to be trapped, providing a thicker barrier for heat transfer. The fibers themselves also have natural crimps and curls, which further enhance the insulation by creating more air pockets.

Additionally, fleece is hydrophobic, meaning it repels moisture. Moisture has a higher thermal conductivity than air, so by repelling moisture, fleece maintains its insulating properties even in damp conditions. This is particularly advantageous in outdoor activities or during physical exertion when the body may produce sweat.

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What angle would you use for the greatest distance when the projectile leaves at zero height above ground g

Answers

Answer: 45 degree

Explanation:

Since Range = Ucosø × T

Where T = total time.

Range = distance covered

T = 2usinø/ 2g

If you substitute T into the range formula, you will get

R = (Ucosø×2Usinø) / 2g

But in trigonometry, 2sinøcosø = sin2ø

Substitute it into the formula

R = Usin2ø/ 2g

If ø = 45 degree

R = Usin(2 × 45)/2g

R = Usin90 / 2g

But sin 90 = 1

Therefore,

Range R = U/2g

Therefore, 45 degree angle would be use for the greatest distance when the projectile leaves at zero height above ground.

Answer:

∴ the angle for greatest distance is 90°, where Vy = 0

Explanation:

maximum height of a projected object is highest vertical position of the trajectory object which depends on the initial velocity

formula for maximum height

H= u² sin²θ/2g

if θ = 90°, then sin²90° = 1

∴ the angle for greatest distance is 90°, where Vy = 0

for horizontal distance,

the range of a projectile is the horizontal distance.

R = u² sin2θ/g

if θ = 45°, then 2θ  = 90°

∴sin 90°= 1

Acceleration is the change in speed over the time
taken. A hungry cheetah spots a gazelle and decides to
chase it. The cheetah accelerates at 10 m/s² from rest
until it reaches 20 m/s. How long did this take?

Answers

vf=vi+at

20=0+10.t

20=10t

t=2 s

What's the kinetic energy of an object that has a mass of 30 kilograms and moves with a velocity of 20 m/s?
Question 16 options:

A)

12,000 J

B)

2,940 J

C)

6,000 J

D)

5,880 J

Answers

the kinetic energy of an object that has a mass of 30 kilograms and moves with a velocity of 20 m/s is  6,000 J. Option C is correct answer.

The kinetic energy of an object that has a mass of 30 kilograms and moves with a velocity of 20 m/s can be calculated by using the formula:

K.E = 1/2 mv²

Where, K.E = Kinetic energy of the objectm = Mass of the objectv = Velocity of the object

Putting the given values in the above formula:

K.E = 1/2 mv²K.E = 1/2 × 30 kg × (20 m/s)²K.E = 1/2 × 30 × 400K.E = 6000 joules

The correct answer is C.

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What is the frequency of the fundamental note produced by a pipe
closed at one end and open at the other end if it resonates with
sound waves of frequency 100 Hz and 140 Hz but not with any wave
of frequency intermediate between these two?

Answers

The frequency of the fundamental note produced by a pipe closed at one end and open at the other end is given by the formula:

f = (n * v) / (4 * L)

where:

- f is the frequency of the fundamental note

- n is the harmonic number (for the fundamental frequency, n = 1)

- v is the speed of sound in air (approximately 343 m/s at room temperature)

- L is the length of the pipe

For a pipe closed at one end and open at the other end, the fundamental frequency is the first harmonic, so n = 1.

We can use the formula to find the length of the pipe for each of the two resonant frequencies, and then solve for the frequency of the fundamental note.

For the frequency of 100 Hz:

100 Hz = (1 * 343 m/s) / (4 * L)

L = 8.575 m

For the frequency of 140 Hz:

140 Hz = (1 * 343 m/s) / (4 * L)

L = 6.125 m

The length of the pipe must be such that it resonates at both 100 Hz and 140 Hz, but not at any frequency in between. One possible length that satisfies this condition is the half-wavelength of the fundamental frequency, which is:

L = (1/2) * (v / f) = (1/2) * (343 m/s / 100 Hz) = 1.715 m

We can now use this length to find the frequency of the fundamental note:

f = (1 * 343 m/s) / (4 * 1.715 m) = 50 Hz

Therefore, the frequency of the fundamental note produced by the pipe is 50 Hz.

A truck pushes a mound of dirt 5 meters with a force of 75 newtons. How much
work has been done?

Answers

Answer:

\(375\:\mathrm{N}\)

Explanation:

Work is given by the equation \(W=F\Delta x\). Plugging in given values, we get:

\(W=75\cdot 5=\fbox{$ 375\:\mathrm{N}$}\).

1. What is the wavelength
a sound wave in air with a frequency of 50 Hz?


Answers

Wavelength is the Distance from one crest to another

camera was able to deliver 1.3 frames per second for this photo, and that the car has a length of approximately 5.3 meters. Using this information and the photo itself, approximately how fast did the car drive

Answers

The question is incomplete. Here is the complete question.

The image below was taken with a camera that can shoot anywhere between one and two frames per second. A continuous series of photos was combined  for this image, so the cars you see are in fact the same car, but photographed at differene times.

Let's assume that the camera was able to deliver 1.3 frames per second for this photo, and that the car has a length of approximately 5.3 meters. Using this information and the photo itself, approximately how fast did the car drive?

Answer: v = 6.5 m/s

Explanation: The question asks for velocity of the car. Velocity is given by:

\(v=\frac{\Delta x}{\Delta t}\)

The camera took 7 pictures of the car and knowing its length is 5.3, the car's displacement was:

Δx = 7(5.3)

Δx = 37.1 m

The camera delivers 1.3 frames per second and it was taken 7 photos, so time the car drove was:

1.3 frames = 1 s

7 frames = Δt

Δt = 5.4 s

Then, the car was driving:

\(v=\frac{37.1}{5.4}\)

v = 6.87 m/s

The car drove at, approximately, a velocity of 6.87 m/s

camera was able to deliver 1.3 frames per second for this photo, and that the car has a length of approximately

The velocity of the car will be 6.5 m/s.The rate of change of displacement is defined as speed.

What is velocity?

The change of displacement with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is

t is the time for camera deliver= 1.3 frames per second

l is the  length = 5.3 meters

The instantaneous velocity is given as;

\(\rm v = \frac{\triangle x }{\triangle t } \\\\ \rm \triangle x = 7 \times 5.3 \\\\ \rm \triangle x = 37.1 m\)

The time engaged is find as;

1.3 frames = 1 s

\(\rm \triangle t= 7 \ frames \\\\ \rm \triangle t=5.4 sec\)

Hence the velocity of the car driving;

\(\rm v= \frac{37.1}{5.4} \\\\ \rm v= 6.87 m/sec\)

Hence the velocity of the car will be  6.5 m/s.

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Motion maps for two objects, Y and Z, are shown.

A motion map. The position line is a long black arrow pointing right with x as the reference point at left. Above the line are three dots, each with a vector pointed away from x back to back in a line labeled B. Above B, there are four dots, each with a shorter vector pointing away from x in a line labeled A starting closer to x .

Object Z passes object Y after how many seconds?

2
3
4
5

Answers

Answer: it takes 3 seconds (b)

Explanation:

Answer: B. 3

Explanation:

Each black point on the map represents one second. There are three black points with vectors representing Z's movement before Y begins to move.

Motion maps for two objects, Y and Z, are shown.A motion map. The position line is a long black arrow

2. All of the following are examples of physical properties except:
A. tearing B. density C. melting point D. boiling point

Answers

All of the following are examples of physical properties except tearing.

What is Physical property?

This is used to describe the state of a physical system and is usually measurable.

Examples include:

DensityMelting point Boiling point

Tearing isn't an example of a physical property which was why option A was chosen as the most appropriate choice.

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WILL MARK BRAINLIEST FOR CORRECT ANSWERS

A rocket will accelerate...

WILL MARK BRAINLIEST FOR CORRECT ANSWERSA rocket will accelerate...

Answers

The answer the the questions:
True
False
False

Answer:

True

False

False

Explanation:

The first answer is inferred from Newton's third law of motion. As the rocket burns fuel and ejects the products downwards, a thrust is created, which acts downwards; pushing the rocket upwards.

The second answer is gotten from the same law. Pushing against the atmosphere (action) will create a reaction (this reaction is from the atmosphere; action and reaction are equal and opposite) which acts downwards. Hence the rocket doesn't move up.

Third. When the rocket is in space (vacuum), it moves at a uniform velocity since no force acts on it. This is gotten from Newton first law of motion. Here, the rocket moves into the orbit, fuelled by the force of it's thrust (when it was on the ground).

Which graph shows the change in velocity of an object in free fall?

Which graph shows the change in velocity of an object in free fall?

Answers

Answer:

The graph of the velocity of an object in free fall would look like a straight line sloping downward. As the object falls, its velocity increases at a constant rate, so the graph of its velocity versus time will be a straight line with a negative slope. This is because acceleration due to gravity is a constant -9.8 meters per second squared, so the velocity of a free-falling object will increase by 9.8 meters per second every second.

Therefore, the graph that shows the change in velocity of an object in free fall is a straight line with a negative slope. Here is an example of such a graph:

Free Fall Velocity Graph

Enzyme reaction rates Consider the illustration below. What variable might be on the horizontal axis? (Click on all that apply) Temperature pH
Activation energy Competitive inhibitor concentration Rate of reaction Noncompetitive inhibitor concentration Salt concentration

Answers

In general, a reaction is sped up by increasing temperature and slowed down by decreasing temperature. But extremely high temperatures can denature an enzyme, causing it to lose its form and cease functioning.

How is the rate of reaction affected by variations in pH or temperature?

As enzymes have a maximum temperature and pH at which their rate is maximal, temperature and pH can both raise or reduce the enzyme reaction rate. The pace of reaction for the enzyme will be slowed down by changes in temperature and pH that are not optimal.

Which of the following factors will speed up an enzyme reaction?

An enzyme's concentration increases along with the speed of an enzyme-catalyzed process. An enzyme-catalyzed process accelerates with rising temperatures at low temperatures. The protein is denatured at higher temperatures, which also causes a sharp drop in reaction rate.

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A response is typically sped up by rising temperature and slowed down by falling temperature. However, exceedingly hot temperatures can denature an enzyme, causing it to lose its shape and stop working.

Temperature and pH have the ability to increase and decrease the rate of an enzyme reaction since enzymes have a maximum temperature and pH at which they function at their highest rate. Unfavorable variations in temperature and pH will cause the enzyme's reaction to proceed more slowly. The rate of an enzyme-catalyzed process increases as the concentration of the enzyme rises. When temperatures are low, an enzyme-catalyzed reaction speeds up as they rise. At higher temperatures, the protein is denatured, which also results in a dramatic decrease in response rate.

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A heat engine does 200 J of work per cycle while exhausting 400 J of waste heat. what is the engine's thermal efficiency?

Answers

The thermal efficiency of an engine is
N=W/Q
where
W is the work done by the engine
Q is the heat absorbed by the engine to do the work

In this problem, the work done by the engine is W=200 J, while the heat exhausted is Q=400 J, so the efficiency of the machine is
N=200J/400J=0.50=50%
I hope this helps!

The engine thermal efficiency is 50%

The engine does 200 joules of work per cycle

It exhausts 400 j

The thermal efficiency can be calculated as follows

= 200/400

= 0.5 × 100

= 50 %

Hence the engine thermal efficiency is 50%

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7. Apply Concepts: suppose the dog walked at a constant speed the whole way. What
would the graph look like then? Explain.

Answers

If the dog walked at a constant speed the whole way, the graph of the dog's position versus time would be a straight line. This is because the dog's velocity (which is the derivative of position with respect to time) would be constant, and the acceleration (which is the derivative of velocity with respect to time) would be zero.

What is the speed about?

A straight line on a position-time graph indicates that the object is moving at a constant velocity. The slope of the line would be equal to the velocity of the dog.

If the graph is a horizontal line, it would indicate that the dog is at rest. If the line slopes upward, the dog is moving in the positive direction (for example, to the right in a position-time graph), and if the line slopes downward, the dog is moving in the negative direction.

In all, A constant speed means a constant velocity and the line is a straight line with a particular slope.

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7. Apply Concepts: suppose the dog walked at a constant speed the whole way. Whatwould the graph look

What are the limitations of sending information using electronic waves

Answers

Answer:

The limitations of sending information using electromagnetic waves is that when the electromagnetic waves move outward in all directions, wave transmitters need to be focused to transmit their signals to a single specified location.

State the three rules of refraction for converging lenses

Answers

The three rules of refraction for converging lenses, also known as convex lenses, are as follows:

1. The incident ray parallel to the principal axis refracts through the lens and passes through the focal point on the opposite side of the lens.

2. The incident ray passing through the focal point refracts and emerges parallel to the principal axis.

3. The incident ray passing through the center of the lens continues undeviated.

The three rules of refraction for converging lenses, also known as convex lenses, are as follows:

1. The incident ray parallel to the principal axis refracts through the lens and passes through the focal point on the opposite side of the lens.

When a ray of light traveling parallel to the principal axis (the horizontal line passing through the center of the lens) enters a converging lens, it refracts and bends toward the principal axis. After refraction, the ray passes through the focal point on the opposite side of the lens. This rule is essential in understanding the behavior of light rays in converging lenses.

2. The incident ray passing through the focal point refracts and emerges parallel to the principal axis.

When a ray of light passes through the focal point before entering the lens, it refracts and emerges parallel to the principal axis. This rule implies that light rays that enter the lens at different angles converge and meet at the focal point on the opposite side.

3. The incident ray passing through the center of the lens continues undeviated.

When a ray of light passes through the center of a lens, it continues in a straight line without deviating from its path. This rule is derived from the fact that the refractive index of the lens material is the same throughout, resulting in no change in the direction of light passing through the center of the lens.

These rules of refraction for converging lenses help in understanding how light rays interact with the lens and how the lens focuses incoming light. By applying these rules, one can predict the behavior of light rays and determine the location and characteristics of images formed by converging lenses.

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Find the velocity of the car after 6.9 s if its acceleration is 1.5 m/s² due south.

Answers

Velocity is 6.9 x 1.5 = 10.35 m/s due South

The velocity of the car after 6.9 s if its acceleration is 1.5 m/s² due south would be  10.35 meters / seconds.

What are the three equations of motion?

There are three equations of motion given by  Newton

v = u + at

S = ut + 1/2×a×t²

v² - u² = 2×a×s

Note that these equations are only valid for a uniform acceleration.

As given in the problem we have to find the velocity of the car we have to find the velocity of the car  after 6.9 s if its acceleration is 1.5 m/s² due south,

The acceleration of the car = 1.5 m/s²

The time taken by the car = 6.9 seconds

By using the first equation of the motion,

v = u + at

v = 0 + 1.5*6.9

v = 10.35 meters / seconds

Thus, the velocity of the car after 6.9 s, if its acceleration is 1.5 m/s² due south, would be  10.35 meters / seconds.

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Researchers studying the possible effects of “heading” a soccer ball--hitting it with the head--use a force plate to measure the interaction force between a ball and a hard surface. (Figure 1) shows smoothed data of the force when a 430 g
soccer ball is fired horizontally at the force plate with a speed of 15 m/s
With what speed does the ball rebound from the plate?

Researchers studying the possible effects of heading a soccer ball--hitting it with the head--use a force

Answers

The speed of the ball rebounding from the plate is approximately 13.2 m/s.

According to the graph, the greatest force exerted by the football on the force plate during impact is around 1900 N. The ball comes to a halt on the force plate before rebounding.

The kinetic energy of the ball before impact equals the kinetic energy of the ball after the rebound, according to the law of conservation of energy.

The speed of the ball rebounding can be calculated using the formula:

(1/2)mv²= (1/2)mv_0²

where m is the mass of the ball (0.43 kg), v is the speed of the ball rebounding, and v_0 is the initial speed of the ball (15 m/s).

Solving for v, we get:

v = sqrt(v_0² - (2F/m))

where F is the maximum force exerted on the force plate (1900 N).

Plugging in the values, we get:

v = sqrt(15² - (2*1900/0.43)) ≈ 13.2 m/s

Therefore, the speed of the ball rebounding from the plate is approximately 13.2 m/s.

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A 5.0 kg block with a speed of 3.0 m/s collides with a 10
kg block that has a speed of 2.0 m/s in the same direction.After the
collision, the 10 kg block travels in the original direction with a
speed of 2.5 m/s. (a) What is the velocity of the 5.0 kg block immediately after the collision? (b) By how much does the total kinetic
energy of the system of two blocks change because of the collision? (c) Suppose, instead, that the 10 kg block ends up with a
speed of 4.0 m/s. What then is the change in the total kinetic energy? (d) Account for the result you obtained in

Answers

(a) The first block  moves at 4.0 m/s in the same direction right after colliding.

(b) the system's total kinetic energy changes by  28.75 J

(c) the system's total kinetic energy changes by -1.25 J

Given;

First block's mass, m1, is 5 kg.

u1 = 3.0 m/s is the first block's starting speed.

m2 weight of the second block is 10.0 kg.

u2 = 2.0 m/s is the second block's initial speed.

v2 = 2.5 m/s is the second block's final speed.

Immediately following the impact, the first block block's Part (A) velocity is as follows:

Apply the law of conservation of linear momentum: m1u1 + m2u2 = m1v1 + m2v2, where v1 is the speed of the first block after it collides.

(5 x 3.0) + (10 x 2.0) = 5.0v₁ + (10 x 2.5) (10 x 2.5)

35= 2.5v₁ + 25

2.5v₁ = 35-25

2.5v₁ = 10

v₁ = 10/2.5

v₁ = 4

2.5 m/s in the same direction for v1.

Change in the system's overall kinetic energy, part (B):

Final kinetic energy minus beginning kinetic energy equals the change in kinetic energy.

ΔK = (1/2m1v1^2 + 1/2m2v2^2) - (1/2m1u1^2 + 1/2m2u2^2)

ΔK is equal to (1/2 x 5 x 4^2 + 1/2 x 10 x 2.5^2) – (1/2 x 5 x 3^2 + 1/2 x 10 x 2^2).

ΔK = 71.25 J - 42.5 J

ΔK = 28.75 J

Change in part (C) of the system's total kinetic energy if the second block accelerates to 5.2 m/s

Determine the final speed of the first block using the conservation of linear momentum: m1u1 + m2u2 = m1v1 + m2v2 (5 x 3.0) + (10 x 2.0) = 5v1 + (10 x 4)

35 = 2.5v₁ + 40

2.5v₁ = -5

2.5v₁ = - 5 v₁ = - 5 / 2.5 \s v₁ = -2 m/s

Final kinetic energy minus beginning kinetic energy equals the change in kinetic energy.

K = (1/2m1v12 + 1/2m2v22) - (1/2m1u12 + 1/2m2u22)

K is equal to (1/2 x 5 x 22 + 1/2 x 10 x 2.52) - (1/2 x 5 x 3 + 1/2 x 10 x 2).

ΔK = 41.25 - 42.5 J

ΔK = -1.25 J

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A spherical bowling ball of mass 7 kg and radius 0.18 m rolls down a hill that has a vertical height of 7 m. If the ball started from rest at the top, what is its angular momentum at the bottom of the hill? Use two sig figs.

Answers

Answer:

er so ue 0.984 kg study your self brhh

How do you find the parallel component of force (Fsub||) on an inclined plane? Is it equal to the y-component? I also need to find applied force.

Mass = 100 kg
Weight = 980 N
Normal Force = 965 N
Theta = 10°
Friction = 289.5 N

Please Help :) ​

Answers

Answer:

just add them all up i think i dont know

Explanation:

The following are four electrical components.
A. A component which obeys ohm's law
B. Another component which obeys ohm's law
but which has higher resistance than A
A filament lamp
C.
D. A component, other than a filament lamp,
which does not obey ohm's law.
a. For each of these components, sketch current-
voltage characteristics, plotting current on the
vertical axis, and showing both positive and
negative values. Use one set of axes for A and
B, and separate sets of axes for C and for D.
label your graphs clearly.
b.
Explain the shape of the characteristic for C
c. Name the component you have chosen for D.

Answers

For the following are four electrical components:

a. For components A and B, both of which obey Ohm's law, the current-voltage characteristics would be a straight line passing through the origin. The slope of the line for component B would be steeper than that of component A, indicating higher resistance.

b. The shape of the characteristic for component C, the filament lamp, can be explained by its construction. A filament lamp consists of a filament made of a resistive material, typically tungsten, which heats up and emits light when an electric current passes through it.

c. The component chosen for D, which does not obey Ohm's law, could be a diode. A diode is a two-terminal electronic component that allows the current to flow in only one direction.

For the following are four electrical components:

a. Sketches of current-voltage characteristics:

For components A and B, both of which obey Ohm's law, the current-voltage characteristics would be a straight line passing through the origin. The slope of the line for component B would be steeper than that of component A, indicating higher resistance.

  Current (I)

     ^

     |          B

     |         /

     |        /

     |       /

     |      /

     |     /

     |    /

     |   /

     |  /

     | /

     |/

     +------------------> Voltage (V)

     Current (I)

     ^

     |          A

     |         /

     |        /

     |       /

     |      /

     |     /

     |    /

     |   /

     |  /

     | /

     |/

     +------------------> Voltage (V)

For component C, a filament lamp, the current-voltage characteristic would be a curve that is not linear. It would exhibit a non-linear increase in current with increasing voltage. At lower voltages, the lamp would have low resistance, but as the voltage increases, the resistance of the filament also increases due to the phenomenon of thermal self-regulation. This leads to a slower increase in current at higher voltages.

For component D, a component that does not obey Ohm's law, the current-voltage characteristic could be any non-linear curve depending on the specific component chosen. Examples of components that do not obey Ohm's law include diodes and transistors.

b. The shape of the characteristic for component C, the filament lamp, can be explained by its construction. A filament lamp consists of a filament made of a resistive material, typically tungsten, which heats up and emits light when an electric current passes through it. As the voltage across the filament increases, the temperature of the filament increases as well, causing its resistance to increase. This increase in resistance results in a slower increase in current with increasing voltage, leading to the characteristic non-linear curve observed.

c. The component chosen for D, which does not obey Ohm's law, could be a diode. A diode is a two-terminal electronic component that allows the current to flow in only one direction. It exhibits a non-linear current-voltage characteristic where it conducts current only when the voltage is above a certain threshold, known as the forward voltage. Below this threshold, the diode has a high resistance and blocks current flow in the reverse direction. The characteristic curve of a diode would show negligible current flow until the forward voltage is reached, after which it exhibits a rapid increase in current with a relatively constant voltage.

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3.) A boat is moving south at 15.0, a passenger is walking north along the boat deck at 4.0 and throws a
rock north at 3.0, what is the velocity of the rock when viewed from the boat and the shore? (2)

Answers

When viewed from the boat, the velocity of the rock will be equal to the sum of the velocity of the rock relative to the passenger (3.0 m/s north) and the velocity of the passenger relative to the boat (4.0 m/s south).

Therefore, the velocity of the rock when viewed from the boat will be:

Vrock (boat) = Vrock (passenger) + Vpassenger (boat)

Vrock (boat) = 3.0 m/s north + (-4.0 m/s south)

Vrock (boat) = -1.0 m/s south

So, when viewed from the boat, the velocity of the rock will be 1.0 m/s south.

When viewed from the shore, the velocity of the rock will be equal to the velocity of the boat relative to the shore (15.0 m/s south) plus the velocity of the rock relative to the boat (which we calculated as -1.0 m/s south).

Therefore, the velocity of the rock when viewed from the shore will be:

Vrock (shore) = Vrock (boat) + Vboat (shore)

Vrock (shore) = -1.0 m/s south + (-15.0 m/s south)

Vrock (shore) = -16.0 m/s south

So, when viewed from the shore, the velocity of the rock will be 16.0 m/s south.

A pendulum bob is released from some ini-
tial height such that the speed of the bob at
the bottom of the swing is 3.0 m/s.
The acceleration of gravity is 9.81 m/s².
What is the initial height of the bob?

Answers

A bob is the mass on the end of a pendulum found most commonly, but not exclusively, in pendulum clocks.

What is a bob on a pendulum?

A basic pendulum consists of a light, flexible, inextensible thread with a heavy but tiny item, known as a "bob," at one end. Graph: Pendulum clocks employ it. It's used to calculate the acceleration caused by gravity.

Clock pendulums are typically composed of a weight or bob attached to the bottom end of a rod, with the top linked to a pivot so it can swing, despite the fact that a pendulum's shape or any rigid item hanging on a pivot is theoretically possible.

The benefit of this design is that it places the centre of mass farthest from the pivot, nearer to the actual end of the pendulum. This reduces the length of the pendulum needed for a specific period and increases moment of inertia. 

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A thin half ring with a radius of R = 10 cm is uniformly charged with a linear density of = 1 Mikrokulon/m and located in a vacuum. Determine the force F of interaction between the half ring and a point charge q = 20 nC located at the center of curvature. (don't use chatgpt please)

Answers

Answer:

Explanation:

F = k * q * lambda * R * π * (1 - √2/2)

Substituting the given values of q, lambda, R, and k, we get:

F = (9 x 10^9 N*m^2/C^2) * (20 x 10^-9 C) * (1 x 10^-6 C/m) * (0.1 m) * π * (1 - √2/2)

F ≈ 8.58 x 10^-4 N

Therefore, the force of interaction between the half ring and the point charge is approximately 8.58 x 10^-4 N.

A comet is known to be traveling toward the earth at a speed of 255 km per second. It is observed to give light with a frequency of 642 x 1014 Hz. What frequency of light would the come be emitting if it were motionless? Express your answer to the nearest hundred trillion Hz.

A comet is known to be traveling toward the earth at a speed of 255 km per second. It is observed to

Answers

Given:

The speed of the comet, u=255 km/s=255×10³ m/s

The observed frequency, f_o=642×10¹⁴ Hz

To find:

The frequency emitted by the comet.

Explanation:

The observed frequency is given by,

\(f_o=\sqrt{\frac{c+u}{c-u}}f\)

Where c is the speed of light and f is the frequency emitted by the comet.

On substituting the known values,

\(\begin{gathered} 642\times10^{14}=\sqrt{\frac{3\times10^8+255\times10^3}{3\times10^8-255\times10^3}}\times f \\ \implies f=\frac{642\times10^{14}}{\sqrt{\frac{3\cdot10^{8}+255\cdot10^{3}}{3\cdot10^{8}-255\cdot10^{3}}}} \\ =641\times10^{14}\text{ Hz} \end{gathered}\)

Final answer:

The frequency emitted by the comet is 641×10¹⁴ Hz

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