Raul quiere agregar a su artículo algunos recursos visuales, para que su tema que-
de más comprensible. ¿Cuál opción los muestra?
1. Gráficas
2. Cita textual
3. Ilustraciones
4. Tablas de datos
5. Referencias bibliográficas
B) 1, 4, 5
A) 1, 3, 4
D) 3,4,5
C) 2,3,4
chos Reservados. GOB. EDO. SEECH. MEAD​

Unit Rate is the correct answer, I know because it is the correct answer

The volume of the prism is 0.343 cubic inches.

What is Volume ?

Volume is a measure of the amount of space occupied by a three-dimensional object. It is the quantity of space that a solid object occupies in three dimensions. Volume is often expressed in cubic units, such as cubic meters, cubic centimeters, or cubic inches , depending on the system of measurement used.

To find the volume of a rectangular prism, we multiply its length, width, and height.

In this case, the length, width, and height of the prism are all 0.7 inch. Therefore, the volume of the prism is:

Volume = (length) x (width) x (height)

= (0.7 x (0.7) x (0.7)

= 0.343 cubic inches

Therefore, the volume of the prism is 0.343 cubic inches.

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Answer:

120

Step-by-step explanation:

20 times 6

Answer:

120 miles

Step-by-step explanation:

1 in. = 20 miles

6 x 20 = 120

6 in. = 120 miles

Hopefully this helps you :)

pls mark brainlest ;)

The area of ​​the balloon, rounded to the nearest square centimeter, is about 201 cm²

The distance around the boundary of a circle is called the circumference. The distance across a circle through the centre is called the diameter. The distance from the centre of a circle to any point on the boundary is called the radius.

The surface area of ​​the balloon can be estimated using the following formula:

Area ≈ 4πr²

where r is the radius of the balloon.

To find the radius of the balloon, we can use the formula for the circumference of a circle:

Circumference = 2πr

Since the circumference of the balloon is 16 cm, we can solve for r as:

16 cm = 2πr

r = 8 cm/π

Now that we know the radius of the sphere, we can use the area formula  to approximate it:

Area ≈ 4π(8/π)²

≈ 201 cm²

Therefore the  area of ​​the balloon, rounded to the nearest square centimeter, is about 201 cm²

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The area bounded by the curves y=e3x and y=e-3x for x between x=-2 and x=1 is approximately equal to 26.8153.

Given functions: y=e 3x and y=e -3x

To find the points of intersection of the graphs of the functions, equate both functions such that

e3x = e-3x

⇒ 3x = -3x

⇒ x = -3x/3

⇒ 4x/3 = 0

⇒ x = 0

So, we got the intersection point at (0, 1).

Now, we have to find the area bounded by the curves y=e3x and y=e-3x for x between x=-2 and x=1.

So, we can solve this problem by integrating the difference of both the functions.

It can be expressed as:A = ∫e3x dx - ∫e-3x dxfor x between -2 and 1Now, let's find the integral of both the functions separately:

∫e3x dx = (1/3)e3x + C1∫e-3x dx

= (-1/3)e-3x + C2

Now, substitute the limits and simplify: A = [(1/3)e3x - (-1/3)e-3x] from x = -2 to x = 1= (2/3)e3 - (2/3)e-3= (2/3)(e3 - e-3)

Therefore, the required area is (2/3)(e3 - e-3) which is approximately equal to 26.8153 (rounded off up to four decimal places).

Hence, the points of intersection of the graphs of the functions are (0, 1).

The area bounded by the curves y=e3x and y=e-3x for x between x=-2 and x=1 is approximately equal to 26.8153.

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To show that two triangles ABC and CYZ are congruent using the Side-Angle-Side (SAS) criterion: Side AB congruent to side CY, Side BC congruent to side YZ and Angle B congruent to angle Y.

To show that two triangles ABC and CYZ are congruent using the Side-Angle-Side (SAS) criterion, we would need to establish the following congruences:

These three congruences combined would satisfy the SAS criterion and establish the congruence between triangles ABC and CYZ.

By showing that the corresponding sides and angles of the two triangles are congruent, we can conclude that the triangles are identical in shape and size.

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Answer: 7/25 or 28%

Step-by-step explanation:

28 (cherry) + 19 (strawberry) + 20 (orange) + 33 (lemon) = 100 (total)

so p(cherry), or the probability of getting cherry, is 28/100 (7/25)

that as a percent is 28%

Answer:

180$

Step-by-step explanation:

First you have to find out how many pencils the company bought each year which is 6000 since they bought 500 dozens and 75% of 500 is 375 and 20% of 0.40 is 0.08 so the cost for each dozen pencils would be 180$ (Sorry if this is wrong I'm 80% sure)

The number of more drapery pieces than upholstery pieces does Brandon have is 2.03 pieces

Number of pieces of upholstery fabric = 23 3/5 ÷ 2 5/6

= 118/5 ÷ 17/6

= 118/5 × 6/17

= 708 / 85

= 8 28/85

Number of pieces of drapery fabric = 18 1/2 ÷ 2 5/6

= 37/2 ÷ 17/6

= 37/2 × 6/17

= 222/34

= 6 18/34

= 6 9/17

How many more drapery pieces than upholstery pieces does Brandon have = 708 / 85 - 222/34

= (24072-18204) / 2890

= 5,868 / 2890

= 2.03 pieces

Therefore, the number of more drapery pieces than upholstery pieces does Brandon have is 2.03 pieces

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Answer:

The area of the rectangle is given by the formula A = lw. Substituting the given values, we get:

A = (x+14)(3x+1)

Expanding the expression, we get:

A = 3x^2 + x + 42x + 14

A = 3x^2 + 43x + 14

Therefore, the area of the rectangle is given by the polynomial expression 3x^2 + 43x + 14.

Answer:

x = -2

Step-by-step explanation:

Given equation:

8^x= 1/64

Ensure both sides of the equation are in power format by changing 1/64

1/64 = 64^-1

8^x = 64^-1

2^3(x) = 2^6(-1)

The bases will cancel out each other

3(x) = 6(-1)

3x = -6

x = -6/3

x = -2

Check

8^x = 1/64

x = -2

8^-2

= 1/8²

= 1/8*8

= 1/64

Answer:

You want to have a common denominator. Multiply 3/4 by two and get 6/8. Multiply 6 times 1 and get 6. That's 6/8 since the denominators are the same. Simplify by dividing 6/8 by two and you get 3/4.

Step-by-step explanation:

The product is 3/4 x 1/8 = 3/32.

You just combine the numerators and denominators together to multiply a fraction.

You multiply the numerators together to get the new numerator, and you multiply the denominators together to get the new denominator, to determine the product of two fractions.

Here are the facts:

3/4 x 1/8 = (3 x 1) / (4 x 8)

We get 3 when we multiply the numerators, and 32 when we multiply the denominators.

So, 3/4 times 1/8 equals 3/32.

Because there are just two components that 3 and 32 have in common, 3/32 is already in its simplest form.

Hence the product is 3/4 x 1/8 = 3/32.

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The exercise involves finding the product C = AB, where matrix A is given by [2 9] and matrix B is given by [3 6 1]. We need to perform the matrix multiplication to obtain the resulting matrix C.

Let's calculate the matrix product C = AB step by step:

Matrix A has dimensions 2x1, and matrix B has dimensions 1x3. To perform the multiplication, the number of columns in A must match the number of rows in B.

In this case, both matrices satisfy this condition, so the product C = AB is defined.

Calculating AB:

AB = [23 + 912 26 + 94 21 + 95]

[103 + 612 106 + 64 101 + 65]

Simplifying the calculations:

AB = [6 + 108 12 + 36 2 + 45]

[30 + 72 60 + 24 10 + 30]

AB = [114 48 47]

[102 84 40]

Therefore, the product C = AB is:

C = [114 48 47]

[102 84 40]

In summary, the matrix product C = AB, where A = [2 9] and B = [3 6 1], is given by:

C = [114 48 47]

[102 84 40]

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The solution to the linear system is x₁ = 0, x₂ = -5/4, and x₃ = 3/2.

We start with the augmented matrix:

[1 2 3 | 2]

[-1 2 5 | 5]

[2 1 3 | 9]

First, we eliminate the variable x₁ from the second and third equations by adding the first equation to them:

[1 2 3 | 2]

[0 4 8 | 7]

[0 -3 -3 | 5]

Next, we eliminate the variable x₂ from the third equation by adding 3/4 times the second equation to it:

[1 2 3 | 2]

[0 4 8 | 7]

[0 0 3 | 18/4]

Now, we have the system in row echelon form. We can perform backward substitution to find the values of the variables. Starting from the last equation, we have:

3x₃ = 18/4 -> x₃ = 18/4 / 3 = 3/2

Substituting this value back into the second equation, we have:

4x₂ + 8(3/2) = 7 -> 4x₂ + 12 = 7 -> x₂ = -5/4

Finally, substituting the values of x₂ and x₃ into the first equation, we have:

x₁ + 2(-5/4) + 3(3/2) = 2 -> x₁ - 5/2 + 9/2 = 2 -> x₁ = 0

Therefore, the solution to the linear system is x₁ = 0, x₂ = -5/4, and x₃ = 3/2.

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the probability of rolling two integers that differ by 2 on the first two rolls is \($\frac{3}{36}$\), since there are 3 favorable outcomes out of 36 total possible outcomes

The probability of rolling integers that differ by 2 on the first two rolls is \(\frac{3}{36}\).

There are six possible outcomes on a standard 6-sided die - 1,2,3,4,5,6.

The possible outcomes that could produce two integers that differ by 2 are (1,3), (3,5), and (5,1).

Therefore, the probability of rolling two integers that differ by 2 on the first two rolls is \(\frac{3}{36}\), since there are 3 favorable outcomes out of 36 total possible outcomes. the probability of rolling two integers that differ by 2 on the first two rolls is \(\frac{3}{36}\) since there are 3 favorable outcomes out of 36 total possible outcomes

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Answer:

We have to use a little bit of casework to solve this problem because some numbers on the die have a positive difference of 2 when paired with either of two other numbers (for example, 3 with either 1 or 5) while other numbers will only have a positive difference of 2 when paired with one particular number (for example, 2 with 4).

If the first roll is a 1, 2, 5, or 6, there is only one second roll in each case that will satisfy the given condition, so there are 4 combinations of rolls that result in two integers with a positive difference of 2 in this case. If, however, the first roll is a 3 or a 4, in each case there will be two rolls that satisfy the given condition- 1 or 5 and 2 or 6, respectively. This gives us another 4 successful combinations for a total of 8.

Since there are 6 possible outcomes when a die is rolled, there are a total of \(6\cdot6=36\) possible combinations for two rolls, which means our probability is \($\dfrac{8}{36}=\boxed{\dfrac{2}{9}}.$\)

OR

We can also solve this problem by listing all the ways in which the two rolls have a positive difference of 2:

(6,4), (5,3), (4,2), (3,1), (4,6), (3,5), (2,4), (1,3).

So, we have 8 successful outcomes out of  possibilities, which produces a probability of \(\frac{8}{36}=\frac29\)

The currently accepted basic units and symbols in the metric system are the meter (m) for length, kilogram (kg) for mass, and second (s) for time. The correct Option is b) kilogram (kg).

The centimeter (cm) and milliliter (ml) are derived units in the metric system. The cm is derived from the meter and the ml is derived from the cubic meter.

Therefore, the correct option b) kilogram (kg). The currently accepted basic unit and symbol in the metric system is kilogram (kg).

The metric system is a system of measurement that is based on the International System of Units (SI). The SI is a modern form of the metric system that is widely used around the world. The basic units and symbols in the metric system are the meter (m) for length, kilogram (kg) for mass, and second (s) for time. The centimeter (cm) and milliliter (ml) are derived units in the metric system. The kilogram (kg) is the only basic unit in the given options and is currently accepted as a basic unit in the metric system.

 The kilogram (kg) is the only basic unit and symbol in the metric system among the given options.

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The equation that best represent the situation  relating W to T would be;                             W = 700 + 35T

For a solution to be solution to a system, it must satisfy all the equations of that system, and as all points satisfying an equation are in their graphs, so solution to a system is the intersection of all its equation at single point(as we need common point, which is going to be intersection of course)(this can be one or many, or sometimes none)

We have been given that water is added in the pond at a rate of 35 liters per minute and there are total 700 liters in the pond to start.

Let W represent the amount of water in the pond (in liters) and T to be the the number of minutes that water has been added.

The equation that best represent the situation will be;

                                   W = 700 + 35T

Hence, the graph of the equation is a line with slope of 35 and y-intercept of 700 .

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Answer:

y = x - 10, y = x, y = x + 1, y = x - 37,654,356, which are just a few examples

Step-by-step explanation:

There are infinite solutions to this, but one of them is y = x - 10. Just change the y-intercept in this equation, then you can see that the lines never touch, and are parallel, which is what we want.

The domain of all six trigonometric functions is all real numbers, and the range of the sine and cosine functions is between -1 and 1, while the range of the tangent, cosecant, secant, and cotangent functions is all real numbers except for certain values where the denominator is equal to zero.

Using the properties of the unit circle, we can define the six trigonometric functions (sine, cosine, tangent, cosecant, secant, and cotangent) based on the coordinates of points on the unit circle.

The domain of all six trigonometric functions is the set of all real numbers, since the input angle can take any value in radians or degrees.

The range of the sine and cosine functions is the set of all real numbers between -1 and 1, inclusive. This is because the y-coordinate (sine) and x-coordinate (cosine) of any point on the unit circle can range from -1 to 1.

The range of the tangent, cosecant, secant, and cotangent functions is the set of all real numbers except for values where the denominator (sine, cosine) is equal to zero. For example, the range of the tangent function is all real numbers except for the values of x where cos(x) = 0, which occur at multiples of pi/2.

So, in summary, the domain of all six trigonometric functions is all real numbers, and the range of the sine and cosine functions is between -1 and 1, while the range of the tangent, cosecant, secant, and cotangent functions is all real numbers except for certain values where the denominator is equal to zero.

Using properties of the unit circle, the domain and range of the six trigonometric functions are as follows:

1. Sine (sin): Domain is all real numbers, Range is [-1, 1].
2. Cosine (cos): Domain is all real numbers, Range is [-1, 1].
3. Tangent (tan): Domain is all real numbers except odd multiples of π/2, Range is all real numbers.
4. Cosecant (csc): Domain is all real numbers except integer multiples of π, Range is (-∞, -1] and [1, ∞).
5. Secant (sec): Domain is all real numbers except odd multiples of π/2, Range is (-∞, -1] and [1, ∞).
6. Cotangent (cot): Domain is all real numbers except integer multiples of π, Range is all real numbers.

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The end behavior of a function describes how the function behaves as x approaches positive or negative infinity. To determine the end behavior of f(x) = 1 - 3x, we can look at the leading term, which is -3x.

As x becomes very large (either positive or negative), the value of -3x becomes very large in the opposite direction. That is, as x approaches positive infinity, -3x approaches negative infinity, and as x approaches negative infinity, -3x approaches positive infinity.

Since the constant term 1 does not have any effect on the end behavior, we can conclude that the function f(x) = 1 - 3x decreases without bound as x approaches positive infinity and increases without bound as x approaches negative infinity.

In other words, the end behavior of f(x) = 1 - 3x can be described as:

As x → ∞, f(x) → -∞

As x → -∞, f(x) → +∞

The table has

x values 2,3,4,5 and

f(x) as 1, 14,20, 31

The statements A is true Intermediate value theorem, B is false mean value theorem, C is true extreme value theorem and D is true.

Given that,

The table has

x values 2,3,4,5 and

f(x) as 1, 14,20, 31

The function f is continuous.

A is true, From the figure.

Intermediate value theorem is let [a,b]be a closed and bounded intervals and a function f:[a,b]→R be continuous on [a,b]. If f(a)≠f(b) then f attains every value between f(a) and f(b) at least once in the open interval (a,b).

B is false because, mean value theorem, Let a function f:[a,b]→R be such that,

1. f is continuous on[a,b] and

2. f is differentiable at every point on (a,b).

Then there exist at least a point c in (a,b) such that f'(c)=(f(b)-f(a))/b-a

In the B part, the differentiability is not given do mean value theorem can be applied.

C is true because the extreme value theorem, if a real-valued function f is continuous on the closed interval [a,b] then f attains a maximum and a minimum each at least once such that ∈ number c and d in[a,b] such that f(d)≤f(x)≤f(c)∀ a∈[a,b].

D is true.

Therefore, The statements A is true, B is false, C is true and D is true.

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The minimum οf the data is 81, the first quartile is 94, the median οf the data is 105, the third quartile is 129, and the maximum οf the data is 133.

A stem and leaf plοt is a graphical representatiοn οf a dataset that is used tο display and οrganize individual values. The plοt is made up οf twο parts: the "stem" and the "leaf." The stem is the left-hand side οf the plοt and represents the first οne οr twο digits οf the values, while the leaf is the right-hand side οf the plοt and represents the remaining digits.

This plοt shοws the distributiοn οf the data and allοws yοu tο quickly see the range οf values, the shape οf the distributiοn, and any οutliers οr gaps in the data.

The stem and leaf plot represents the following data:

Stem/Leaf                  Value

8 1 3                              813

9 0 3 4 7       903, 934, 974

10 4 7                     104, 107

11 5                                  15

12 9                               129

13                                    13

The five-number summary for the data is as follows:

The minimum of the data is 81.

The first quartile is 94.

The median of the data is 105.

The third quartile is 129.

The maximum of the data is 133.

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Answer:

minimum-81

first Q-95

median-109

third Q-127

maximum-136

Step-by-step explanation:

yurrrrr

Answer:

3

Step-by-step explanation:

{2 + [-3 (4 -2) + 8] - 1}

first, solve the parenthesis in the middle:

{2 + [-3(2) + 8] - 1}

Now, multiply -3 and 2:

{2 + [-6 + 8] - 1}

add -6 and 8

{2 + 2 - 1}

add 2+2

4-1

obviously:

4-1=3

Also, can you please give me brainliest? Thank you very much!!

The sum of a vector in W and a vector orthogonal to W is \(y = \begin{bmatrix} -3 \\ 5 \\ 2 \end{bmatrix}\)

In this problem, we are given two vectors → u 1 and → u 2 that span a subspace W, and another vector → y. Our goal is to write → y as the sum of a vector in W and a vector orthogonal to W.

To do this, we first need to find a basis for W. A basis is a set of linearly independent vectors that span the subspace. In this case, we can use → u 1 and → u 2 as a basis for W, because they are linearly independent and span the same subspace as any other pair of vectors that span W. We can write this basis as a matrix A:

A = \(\begin{bmatrix} 1 & -4 \\ 1 & 5 \\ 1 & -1 \end{bmatrix}\)

Next, we need to find the projection of → y onto W. The projection of → y onto a subspace W is the closest vector in W to → y. This vector is given by the formula:

\(projW(y) = A(A^TA)^{-1}A^Ty\)

where \(A^T\) is the transpose of A and \((A^TA)^{-1}\) is the inverse of the matrix A^TA. Using the given values, we get:

\(projW(y) = \begin{bmatrix} 1 & -4 \\ 1 & 5 \\ 1 & -1 \end{bmatrix} \left( \begin{bmatrix} 1 & 1 & 1 \\ -4 & 5 & -1 \end{bmatrix} \begin{bmatrix} 1 & -4 \\ 1 & 5 \\ 1 & -1 \end{bmatrix} \right)^{-1} \begin{bmatrix} 1 & 1 & 1 \\ -4 & 5 & -1 \end{bmatrix} \begin{bmatrix} -3 \\ 5 \\ 2 \end{bmatrix} = \begin{bmatrix} 7/3 \\ 1/3 \\ 8/3 \end{bmatrix}\)

This is the vector in W that is closest to → y. To find the vector orthogonal to W, we subtract this projection from → y:

\(z = y - projW(y) = \begin{bmatrix} -3 \\ 5 \\ 2 \end{bmatrix} - \begin{bmatrix} 7/3 \\ 1/3 \\ 8/3 \end{bmatrix} = \begin{bmatrix} -16/3 \\ 14/3 \\ -2/3 \end{bmatrix}\)

This vector → z is orthogonal to W because it is the difference between → y and its projection onto W. We can check this by verifying that → z is perpendicular to both → u 1 and → u 2:

\(z . u_1 = \begin{bmatrix} -16/3 \\ 14/3 \\ -2/3 \end{bmatrix} \cdot \begin{bmatrix} 1 \\ 1 \\ 1 \end{bmatrix} = 0\)

\(z . u_2 = \begin{bmatrix} -16/3 \\ 14/3 \\ -2/3 \end{bmatrix} \cdot \begin{bmatrix} -4 \\ 5 \\ -1 \end{bmatrix} = 0\)

The dot product of → z with → u 1 and → u 2 is zero, which means that → z is orthogonal to both vectors. Therefore, → z is orthogonal to W.

We can check that → y = projW(→y) + → z, which means that → y can be written as the sum of a vector in W (its projection onto W) and a vector orthogonal to W (→ z):

\(projW(y) + z = \begin{bmatrix} 7/3 \\ 1/3 \\ 8/3 \end{bmatrix} + \begin{bmatrix} -16/3 \\ 14/3 \\ -2/3 \end{bmatrix} = \begin{bmatrix} -3 \\ 5 \\ 2 \end{bmatrix} = y\)

Therefore, we have successfully written → y as the sum of a vector in W and a vector orthogonal to W.

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Answer:

---------------------

The angle formed by a tangent and secant is half the difference of the intercepted arcs:

Find the measure of ∠MLJ by substituting 4 for x in the angle measure:

Answer:

Step-by-step explanation:

where angle A is opposite to side BH, angle B is opposite to side AH, and angle H is opposite to side AB.

Problem 8:

Using the Pythagorean theorem, we have:

AB² = AH² + BH²

Dividing both sides by BH², we get:

AB²/BH² = AH²/BH² + 1

(sin A)² + (cos A)² = 1, since sin A = AH/BH and cos A = BH/AB.

Therefore, (sin A)² + (cos A)² = 1, which is the identity we wanted to prove.

Problem 9:

Using the definition of cosine, we have:

cos(90°-A) = BH/AB

Using the Pythagorean theorem, we have:

AB² = AH² + BH²

Dividing both sides by AB², we get:

AB²/AB² = AH²/AB² + BH²/AB²

1 = (sin A)² + (cos A)², since sin A = AH/AB and cos A = BH/AB.

Therefore, sin A = √(1 - (cos A)²).

Substituting cos A = BH/AB, we get:

sin A = √(1 - (BH/AB)²)

Multiplying the numerator and denominator by AB², we get:

sin A = √(AB²/AB² - BH²/AB²)

sin A = √(1 - (BH/AB)²), which is the desired result.

Therefore, sin A = cos(90°-A).

Answer:

Step-by-step explanation:

Given the function

f(x) = 2x³ -3x²+ 7

putting x=-1 to find f(-1)

f(-1) =  2(-1)³ -3(-1)²+ 7

      = -2 + 3 + 7

      = 8

putting x=1 to find f(1)

f(1) =  2(1)³ -3(1)²+ 7

      = 2 - 3 + 7

      = 6

putting x=2 to find f(2)

f(2) =  2(2)³ -3(2)²+ 7

      = 16 - 12 + 7

      = 11

Therefore,

In this question, we are given a prime number p = 227 and an element a = 2, which is primitive in Zp*. We need to perform several computations involving factorization and discrete logarithms in Zp* to the base a.

(a) First, let's compute a^32, a^40, and a^59 modulo p using the base {2, 3, 5, 7, 11}.

a^32 ≡ 2^32 (mod 227)

a^40 ≡ 2^40 (mod 227)

a^59 ≡ 2^59 (mod 227)

To compute these modular exponentiations, you can use modular exponentiation algorithms such as repeated squaring.

Next, let's factor a^156 modulo p using the factor base:

a^156 ≡ 2^156 (mod 227)

Factorizing a^156 modulo p involves expressing it as a product of prime factors from the factor base {2, 3, 5, 7, 11}. You can use prime factorization methods or tools to determine the prime factors of a^156.

(b) Using the fact that log 2 = 1, we can compute the logarithms of 3, 5, 7, and 11 based on the factorizations obtained above.

For example, if the factorization of a^156 modulo p is:

a^156 ≡ 2^a * 3^b * 5^c * 7^d * 11^e (mod 227)

Then, we have:

log 3 ≡ b (mod (p - 1))

log 5 ≡ c (mod (p - 1))

log 7 ≡ d (mod (p - 1))

log 11 ≡ e (mod (p - 1))

(c) To compute log 173, multiply 173 by the "random" value 2177 modulo p:

173 * 2177 ≡ result (mod 227)

Factorize the result over the factor base {2, 3, 5, 7, 11} as done before. Then, using the previously computed logarithms, determine the logarithm of 173.

Remember to perform all computations modulo p and use the properties of modular arithmetic for calculations in Zp*.

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