Ray bought a new hoodie that was on sale for 30% off the original price. The new price of the hoodie was $34.30. What was the original price of the hoodie

Answer:

For a bake sale, addison sells 14 cupcakes for 1.50 dollars each, charli sells 12 cupcakes for 2.00 dollars each. How much money did they make together?

14(1.50)+12(2.00)

21+24= 45

They make 45 dollars together

Step-by-step explanation:

For a pack of 52 cards, two cards are drawn together, the probability that one card is clubs and one card is spades is equals to the

\(= \frac{13}{102}\)

Probability is chances of occurrence of an event. It is calculated by dividing the favourable response to the total possible outcomes. We have a pack of 52 cards. Let's consider an event E : card is one card is culb and one is spade

Total possible outcomes = 52

Two cards are drawn together from a pack. So, number of total possible outcomes for drawing two cards from a pack, n(T) = ⁵²C₂ = 1326

In a 52 cards pack, number of spades = 13

Number of clubs cards in pack = 13

Number of ways of choosing/drawing one spades card out of 13 and one one clubs out of 13 cards, n(E) = 169

Probability that one card is clubs and one card is spades on drawing two cards,

\( P(E) = \frac{ n(E)}{n(T)}\)

\(= \frac{169}{1326}\)

\(= \frac{13}{102}\)

Hence, required probability value is \(= \frac{13}{102}\).

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The possible outcomes in the sample space of this experiment are

{(h,1),,(h,2),(h,3),(h,4),(h,5),(h,6),(t,1),(t,2),(t,3),(t,4),(t,5),(t,6)}

Jo flips a coin sample space for a coin = {h, t}

and rolls a 6-sided die sample space for a die = {1,2,3,4,5,6}

at a time coin is tossed and the die is rolled

the possible outcomes in the sample space of this experiment are

{(h,1),,(h,2),(h,3),(h,4),(h,5),(h,6),(t,1),(t,2),(t,3),(t,4),(t,5),(t,6)}

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If many random samples of this size were taken and intervals constructed, 90% of them would contain the true population mean. In repeated sampling, about 90% of the constructed confidence intervals will capture the true population mean difference. The correct answer is C.

When we construct a confidence interval, it is important to understand its interpretation. In this case, the correct answer (Oc) states that if we were to take many random samples of the same size and construct confidence intervals for each sample, approximately 90% of these intervals would contain the true population mean difference.

This interpretation is based on the concept of sampling variability. Due to random sampling, different samples from the same population will yield slightly different sample means.

The confidence interval accounts for this variability by providing a range of values within which we can reasonably expect the true population mean difference to fall a certain percentage of the time.

In the given scenario, when constructing a 90% confidence interval for the paired difference, it means that 90% of the intervals we construct from repeated samples will successfully capture the true population mean difference, while 10% of the intervals may not contain the true value.

It's important to note that this interpretation does not imply a probability or chance for an individual interval to capture the true population mean. Once the interval is constructed, it either does or does not contain the true value. The confidence level refers to the long-term behavior of the intervals when repeated sampling is considered.

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Answer:

Step-by-step explanation:

interval in mathematics stands for a set of real numbers,

denoted by [a,b] where a and b are the starting and ending real numbers both inclusive respectively.

thus, interval [a,b] is the set of real numbers starting from a to b both are real numbers and are included.

Answer:

Step-by-step explanation:

875.50*6%=52.53<---tax paid

875.50+52.53=928.03<--- total paid

Answer:

928.03

Step-by-step explanation:

AC=5cm

CB=4cm

hypotenuse=5²+4²=25+16=41

hypotenuse=√41=6.40cm

Theta has a reference angle of 30° and is in Quadrant I or II.

Sin(theta) = ½

Basic angle: 30

The acute angle between the terminal arm/terminal side and the x-axis. The reference angle is always positive. In other words, the reference angle is an angle sandwiched between the terminal side and the x-axis.

Angles: 30,

180-30 = 150

Because sin is positive in quadrants 1 and 2.

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The nurse should teach the parents to administer 2.5 teaspoons of the acetaminophen liquid suspension per dose.

The prescribed dosage of acetaminophen is 300 mg every 4 hours as needed. The liquid suspension provides 120 mg of acetaminophen per 5 mL (1 teaspoon). To determine the number of teaspoons required for the prescribed dosage, we can set up a proportion:

120 mg / 5 mL = 300 mg / x mL

Cross-multiplying, we get:

120 mg * x mL = 5 mL * 300 mg

Simplifying, we have

120x = 1500

Dividing both sides by 120, we find:

x = 1500 / 120 = 12.5 mL

Since there are 5 mL (1 teaspoon) in each dose, we can convert 12.5 mL to teaspoons:

12.5 mL / 5 mL = 2.5 teaspoons

Therefore, the nurse should teach the parents to administer 2.5 teaspoons of the acetaminophen liquid suspension per dose to ensure the child receives the prescribed dosage of 300 mg.

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Answer:

120

Step-by-step explanation:

The number of people who owned both a cat and a dog is 73.

We need to calculate how many people owned both a cat and a dog. The number of people who owned a dog and/or a cat is:

Total = dog-only + cat-only + dog-and-cat + neither

Total = 145 + 60 + dog-and-cat + 71

Total = 276 + dog-and-cat

So, the number of people who owned both a cat and a dog (dog-and-cat) is:

dog-and-cat = Total - 276

dog-and-cat = 349 - 276

dog-and-cat = 73

However, this number is the total of those who own both. The answer to the question asks how many owned both a cat and a dog.

So:

dog-and-cat = dog-only + cat-only + dog-and-cat

dog-and-cat = 145 + 60 + dog-and-cat

73 = 145 + 60 + dog-and-cat

dog-and-cat = 73 - 205

dog-and-cat = -132

Hence, 132 people neither own a dog nor a cat. So, the number of people who owned both a cat and a dog is:

dog-and-cat = Total - (dog-only + cat-only + neither)

dog-and-cat = 349 - (145 + 60 + 71)

dog-and-cat = 349 - 276

dog-and-cat = 73

Therefore, the number of people who owned both a cat and a dog is 73.

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For a two-tailed hypothesis test about μ, we can use any of the following approaches except comparing the level of significance; to the confidence coefficient

To determine if the sample mean is substantially more than or significantly less than the population mean, a two-tailed hypothesis test is used. The area under both tails or sides of a normal distribution is what gives the two-tailed test its name.

Any of the following methods, with the exception of comparing the level of significance to the confidence coefficient, can be used for a two-tailed hypothesis test regarding. To create a confidence interval estimate for the population mean, approach (d) compares the level of significance which is a to the confidence coefficient which is 1- a. This method is employed to estimate the population parameter rather than test a hypothesis.

Complete Question:

For a two-tailed hypothesis test about μ, we can use any of the following approaches EXCEPT compare the _____ to the _____.

a.confidence interval estimate of μ; hypothesized value of μ

b.p-value; value of α

c.value of the test statistic; critical value

d.level of significance; confidence coefficient

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Answer: 25 + 12.5v ≥ 170

Step-by-step explanation:

We already have the 25 reward points; it also gives the information that she gets 12.5 points for each visit. Because we don't know the amount she has gone to the theater or will go we have to use a variable; 12.5v. When we add them, we get 25 + 12.5v. The inequality we use is ≥ because it says "at least". When this is used that means it has to be equal to or greater and that is why use that sign and get the full equation;

5 + 12.5v ≥ 170

Answer:

55

Step-by-step explanation:

A compound inequality which shows the possible lengths of the third side is: A. 4 ≤ x ≤ 9.

An inequality can be defined as a mathematical relation that compares two (2) or more integers and variables in an equation based on any of the following arguments:

For this word problem, we would model it by this compound inequality:

25 ≤ x + 9 + 12 ≤ 30

25 - 9 - 12 ≤ x

4 ≤ x.

The sum of three lengths of a fence that ranges from 25 to 30 inches would be modeled by this compound inequality:

x + 9 + 12 ≤ 30

x ≤ 30 - 9 - 12

x ≤ 9

Compound inequality = 4 ≤ x ≤ 9.

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The domain of the function \(f(x) = \sqrt{\frac{1}{3}x + 2\) is (d) x  ≥ -6

From the question, we have the following parameters that can be used in our computation:

\(f(x) = \sqrt{\frac{1}{3}x + 2\)

Set the radicand greater than or equal to 0

So, we have

1/3x + 2 ≥ 0

Next, we have

1/3x  ≥ -2

So, we have

x  ≥ -6

Hence, the domain of the function is (d) x  ≥ -6

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The height of the lamp post will be 2.7 meters long.

If two objects are having the same shape then they will be termed as similar. So in mathematics, if two figures have the same shapes, lines or angles then they are called similar.

Given that a boy who is 1. 8 meters tall stands 1 meter away from a lamppost and casts a shadow 2 meters long.

The height of the lamppost will be calculated by the law of similarity between the two triangles.

H / 1.8 = 3 / 2

H = ( 3 x 1.8 ) / 2

H = 2.7 meters

Hence, the height of the post is 2.7 meters.

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Answer:D

Step-by-step explanation:

Answer:

45°

Step-by-step explanation:

The length of the rectangle is 7.875 meters and the width of the rectangle is 5.625 meters.

Perimeter of a rectangle = 2(length + width)

27 = 2(1.4x + x)

27 = 2(2.4x)

27 = 4.8x

x = 27/4.8

x = 5.625

Therefore,

Length of the rectangle = 1.4x

= 1.4(5.625)

= 7.875 meters

Width of the rectangle = x

= 5.625 meters

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Answer:

I believe its true

Step-by-step explanation:

The expression for the students in the class is 5N + 25 + 15 = 90 or N = 10

An algebraic expression is an expression that is made up of variables and constants along with algebraic operations such as addition, subtraction, multiplication, exponent, etc.

Let the number of students in class be N.

Therefore, from the information provided, the expression for the students in the class can be written as:

5N + 25 + 15 = 90

5N + 40 = 90

5N = 90 - 40

5N = 50

N = 50/5

N = 10

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Answer:

Step-by-step explanation:

(-8 + (-3))/2= -11/2 = -5.5

(-9+(-1))/2= -10/2 = -5

(-5.5, -5): midpoint

If the original quantity is 8 and the new quantity is 2, then the correct answer is 75%.

For this question we need to subtract and multiply the numbers. We know that 2 = 25% of 8 so:

\(\boxed{8-2=6}\\\boxed{6/2=3}\)

We are going to take that 25% and multiply it with 3 to get are final answer.

\(\boxed{25*3=75}\\\boxed{So,2=75}\)

Therefore, If the original quantity is 8 and the new quantity is 2, then the correct answer is 75%.

Answer:

Step-by-step explanation:

Plot 213, −56, and −312 on the number line.

Answer: 1/4

Step-by-step explanation: Here, we have 1/3 ÷ 4/3.

Dividing by a fraction is the same

as multiplying by its reciprocal.

In other words, we can change the division sign

to multiplication and flip the second fraction.

So here, 1/3 ÷ 4/3 can be rewritten as 1/3 × 3/4.

Now we're simply multiplying fractions.

Before multiplying however, always try to cross-cancel.

Notice that we can cross-cancel 3 and 3 to 1 and 1.

So we now have 1/1 × 1/4.

Multiplying across the numerators

and denominators, we have 1/4.

Dion's study suffers from selection bias as his sample of individuals on the beach in Miami may not be representative of the entire population's affinity for warm weather.

This is because he is only sampling residents of Miami, Florida, who are on the beach.

This group may not accurately represent the entire population's affinity for warm weather, as it excludes those who may not enjoy the beach or may not have the opportunity to visit the beach.

A more representative sample would include individuals from various locations and backgrounds to better assess the affinity for warm weather across the population.

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The margin of error associated with the confidence interval is 0.02.

The 95% confidence interval for the population proportion is defined as:

p ± z(0.05 / 2) × √[p ( 1 − p )/ n]

We have,

p − z(0.05 / 2) × √[ p ( 1 − p )/ n ] = 0.73                                     ----------- ( 1 )

p + z(0.05 / 2) × √[ p ( 1 − p )/ n ] = 0.77                                    ----------- ( 2 )

Adding the above two equations,

p − z(0.05 / 2) × √[ p ( 1 − p )/ n ] + p + z(0.05 / 2) × √[ p ( 1 − p )/ n ] = 0.73 + 0.77

2p = 0.73 + 0.77

2p = 1.5

p = 0.75

Now, Subtracting the equations ( 1 ) and (2),

We get,

p − z(0.05 / 2) × √[ p ( 1 − p )/ n ] - p - z(0.05 / 2) × √[ p ( 1 − p )/ n ] = 0.73 - 0.77

−2 × z(0.05 / 2) × √[ p ( 1 − p )/ n ] = -0.44

z( 0.10 / 2) × √[ p ( 1 − p )/ n] = 0.02

The margin of error is defined by the formula:

M E = z(0.05 / 2) × √[ p ( 1 − p )/ n]

Therefore, The margin of error will be:

M E = 0.02

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