Reaction Equations:_______CrO4-2 (aq) + _______ [Zn(OH)4]-2 (aq) --> __________

Answer: 2.04

Explanation:

Answer:

Approximately \(0.821\; \rm mol\).

Explanation:

Look up the relative atomic mass of \(\rm Ba\), \(\rm O\), and \(\rm H\) on a modern periodic table:

Calculate the formula mass of \({\rm Ba(OH)_2}\):

\(\begin{aligned}& M({\rm Ba(OH)_2}) \\ &= 137.327 + 2\times(15.999 + 1.008) \\ &\approx 171.334\; \rm g \cdot mol^{-1}\end{aligned}\).

Calculate the number of moles of \({\rm Ba(OH)_2}\) formula units in that \(235\; \rm g\) of this compound:

\(\begin{aligned}& n({\rm Ba(OH)_2}) \\ &= \frac{m({\rm Ba(OH)_2})}{M({\rm Ba(OH)_2})} \\ &= \frac{235\; \rm g}{171.334\; \rm g \cdot mol^{-1}} \approx 1.37159\; \rm mol \end{aligned}\).

Calculate the volume of a \(c({\rm Ba(OH)_2}) = 1.67\; \rm mol \cdot L^{-1}\) with approximately \(n({\rm Ba(OH)_2}) = 1.37159\; \rm mol\) of the solute:

\(\begin{aligned}& V({\rm Ba(OH)_2}) \\ &= \frac{n({\rm Ba(OH)_2})}{c({\rm Ba(OH)_2})} \\ &= \frac{1.37159\; \rm mol}{1.67\; \rm mol \cdot L^{-1}} \approx 0.821\; \rm L \end{aligned}\).

To use Charles's Law, which states that the volume of a gas is directly proportional to its temperature (in Kelvin) when pressure is held constant. The equation represents Charles's Law is V1 / T1 = V2 / T2.

Where:

V1 is the initial volume of the gas

T1 is the initial temperature of the gas (in Kelvin)

V2 is the new volume of the gas

T2 is the new temperature of the gas (in Kelvin)

In this case, we are given the initial volume (200.0 mL) and the initial temperature (75.0 °C). We need to find the new volume (V2) when the temperature is increased to 85.0 °C.

However, to use the equation, we need to convert the temperatures from Celsius to Kelvin. The Kelvin temperature scale is obtained by adding 273.15 to the Celsius temperature:

T1 = 75.0 °C + 273.15 = 348.15 K

T2 = 85.0 °C + 273.15 = 358.15 K

Now, we can substitute the known values into the equation:

(200.0 mL) / (348.15 K) = V2 / (358.15 K)

We can now solve for V2:

V2 = (200.0 mL) × (358.15 K) / (348.15 K)

Calculating the values:

V2 = 206.32 mL. Therefore, the new volume of the nitrogen gas, when warmed from 75.0 °C to 85.0 °C with constant pressure, is approximately 206.32 mL.

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Answer: are transferred

Explanation:

An ionic bond is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element or the metal and the element which accepts the electrons is known as electronegative element or non metal.

A covalent bond is formed when an element shares its valence electron with another element. This bond is formed between two non metals.

Answer:

are transferred

Explanation:

i took the test earlier

The moles would be 12 moles, 4 moles and 11.34 moles

When hydrogen gas (H2) reacts with oxygen gas (O2) to produce water (H2O), the balanced chemical equation is:

2H2 + O2 -> 2H2O

So,

For every 6 moles of H2, 12 moles of H2O will be produced

For every 2 moles of H2, 4 moles of H2O will be produced

For every 5.67 moles of H2, 11.34 moles of H2O will be produced.

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Answer:

Environmental limitations.

Explanation:

Question a

Step 1

The average atomic mass of the element is calculated as:

--------------------

Step 2

Information provided:

Isotope 1:

10.0 % abundant and 23.8 amu.

Isotope 2:

40.0 % abundant and 24.6 amu.

Isotope 3:

25.8 amu, the % abundant = 100 % - 10.0 % - 40.0 % = 50.0 %

-----------------------

Step 3

Procedure:

Average atom mass = (10.0% x 23.8 amu + 40.0% x 24.6 amu + 50.0 % x 25.8 amu)/100 = 25.12 amu

Answer: 25.12 amu

We need to add 0.43 moles of NaOH to the buffer. This is equivalent to adding 2.59 L of 6.01 M NaOH to the buffer.

To calculate the amount of 6.01 M NaOH required to raise the pH of the buffer, we first need to determine the current pH of the buffer. Using the Henderson-Hasselbalch equation, we can calculate that the pH of the buffer is 4.76. To raise the pH to 5.75, we need to add enough NaOH to increase the [OH-] concentration by a factor of 10.

This means we need to add 10 times the amount of H+ ions in the buffer solution. From the balanced chemical equation for the ionization of acetic acid, we know that for every mole of acetic acid that ionizes, it produces one H+ ion. Therefore, we need to add 0.43 moles of NaOH to the buffer. This is equivalent to adding 2.59 L of 6.01 M NaOH to the buffer.

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The Ka of chloroacetic acid is equal to 2.1 x 10⁻². The Ka for chloroacetic acid can be determined from the measured pH of a 0.11 M solution of chloroacetic acid.

To determine the value of Ka for chloroacetic acid (CH2ClCOOH), we can use the pH of the solution and the initial concentration of the acid. The equation for the dissociation of chloroacetic acid is:

CH2ClCOOH(aq) + H₂O(l) ⇌ CH2ClCOO-(aq) + H₃O+(aq)

At equilibrium, we can assume that x is the concentration of the hydronium ion (H₃O+) and the acetate ion (CH2ClCOO-), which will be equal since the acid is monoprotic. Therefore, the concentration of CH2ClCOO- will also be x. The initial concentration of CH2ClCOOH is 0.11 M.

The equilibrium expression for Ka is given by:

Ka = [CH2ClCOO-][H₃O+]/[CH2ClCOOH]

Substituting the equilibrium concentrations, we have:

Ka = (x)(x)/(0.11 - x)

Given that the pH of the solution is 1.91, we can calculate the concentration of H₃O+ using the relationship:

pH = -log[H₃O+]

1.91 = -log[H₃O+]

[H₃O+] = 10^(-pH)

[H₃O+] = 10^(-1.91)

[H³O+] ≈ 7.94 × 10⁻² M

Since the concentration of H3O+ is equal to x, we can substitute this value into the equilibrium expression:

Ka = (7.94 × 10⁻²)(7.94 × 10⁻²)/(0.11 - 7.94 × 10⁻²)

The Ka of chloroacetic acid is equal to 2.1 x 10⁻².

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Answer:

20 km

Explanation:

he walks 10 km + another 10 km so 20 :)

Explanation:

Answer:

30

Explanation:

use the keep,change,change method.

19 + 11

19,keep, "-" change to addition, -11,change to positive

now use this

19 + 11 = (30 )

Explanation:

[Ne] 3s² 3p⁵

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Atomic number: 17

Symbol: Cl

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Argon

Answer:

a. The reactivity series is:

increasing reactivity:

(c) sodium

calcium

magnesium

aluminium

zinc

iron

hydrogen

copper

Carbon fits into the series between iron and hydrogen.

b. The method of extraction used to obtain calcium from its ore is electrolysis. This is because calcium is too reactive to be extracted by reduction with carbon.

c. The balanced equation for the extraction of zinc in the blast furnace is:

ZnO + C → Zn + CO

I hope this helps!

The region can be a curve, surface, or solid. The term region refers to a specific area of space that can be expressed as a curve, surface, or solid.

A curve is a line that follows a path through space. A surface is a two-dimensional area that can be defined by an equation or a set of coordinates.

A solid is a three-dimensional object that has a length, width, height, firm, hard, or compact substance: solid ground. having relative firmness, coherence of particles, or persistence of form, as matter that is not liquid or gaseous

Therefore, the region can be any of the three, depending on how it is defined and expressed.

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Answer:

Carbon=about 85.13%

Hydrogen=about 14.26%

Explanation:

Percent composition= (molar mass of element x amount of it)/Molar mass x100

C= 12x3/42.08 x100=about 85.13

H=6x1/42.08 =about 14.26

A) structural formula

On edge

Answer:

A

Explanation:

A man have to get their friend bond with someone they like a lot closer. Then, if the man is ready to confess his feeling, try buying his love of his life their favorite flower or favorite candy/food.

hope this help-(even though im a girl ;v;)

The concentration of total suspended solids in the stream during the spring is 45.833 mg/l.

What is total suspended solids?

Total suspended solids, or TSS for short, are waterborne particles larger than 2 microns. On the other hand, every particle less than 2 microns is referred to be a completely dissolved solid (TDS). Algae and bacteria can also be categorized as total suspended solids (TSS), however inorganic materials make up the majority of TSS.

Sand, silt, and plankton are all examples of TSS because they are all floating or "suspended" in water. The organic particles released into the water when some water sources are polluted by dead plants or animals are typically suspended solids. While some silt will sink to the bottom of a body of water, other TSS may float to the top or hang suspended somewhere in the middle. TSS has an impact on water clarity, hence the more TSS is present in a water supply, the less clear it will be.

Given in the question,

flow rate of stream (Q1) = 100 cfs

concentration of suspended solids (S1) = mg/l

During spring time,

concentration of TSS (S2) = 250 mg/l

flow rate of stream (Q2) = 20 cfs

The concentration of a mixture is calculated by:

\(C = \frac{Q_1 S_1 + Q_2 S_2}{Q_1 + Q_2}\)

\(C = \frac{100 \times 5 + 20 \times 250}{100+20}\)

\(C = 45.833\) mg/l

Therefore, concentration is 45.833 mg/l

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Answer:

Potassium bromide

Explanation:

Respuesta:

340 N/cm²

Explicación:

Paso 1: Información provista

Peso de la estructura (F): 8500 Newton

Area superficial (A): 25 cm²

Paso 2: Calcular la presión (P) ejercida por la estructura de concreto sobre su base

La presión es igual al cociente entre la fuerza ejercida y la superficie sobre la que se aplica.

P = F/A

P = 8500 N / 25 cm² = 340 N/cm²

Answer:

Unlike other temperature scales of the time, Celsius based his on the freezing and boiling points of water, with 0° as the boiling point and 100° as the freezing point. After he died from tuberculosis in 1744, that scale was reversed, creating the scale still used today.

Answer:

it's O2 since the oxygen has 6 valence electrons and it can make 2 covalent bonds

Filtration, drying, and weighing are the actual yield.

What is the procedure of  facilitate the measurement of the actual yield?

Filtering the precipitate, drying the precipitate, and weighing the precipitate are the processes that would make it easier to quantify the real yield of the solid.

The reaction's resultant liquid/solid mixture can be separated using the filtration method and filter paper. The solid component of the reaction's byproduct would be the residue in the filter paper, and the liquid component would be the filtrate.

After allowing the residue to dry, it can be weighed with a laboratory-grade weighing balance. The solid's weight is a representation of its actual yield.

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Answer:

0.24

Explanation:

If 10 moles of P4S3 were used, the mass of P4O6 produced would be 2838.8 grams.

To determine the number of grams of P4O6 produced from 10 moles of P4S3, we need to use the balanced chemical equation and the molar masses of the compounds involved.The balanced equation for the reaction between P4S3 and oxygen to produce P4O6 is:

P4S3 + 8 O2 → P4O6 + 6 SO2

From the balanced equation, we can see that the molar ratio between P4S3 and P4O6 is 1:1. This means that for every 1 mole of P4S3 consumed, 1 mole of P4O6 is produced.The molar mass of P4S3 is 220.25 g/mol, and the molar mass of P4O6 is 283.88 g/mol.

To calculate the mass of P4O6 produced, we can use the following equation:

Mass of P4O6 = Moles of P4O6 × Molar mass of P4O6

Since the molar ratio between P4S3 and P4O6 is 1:1, the number of moles of P4O6 produced is also 10 moles.

Mass of P4O6 = 10 moles × 283.88 g/mol = 2838.8 grams

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Answer:

6.79 atm

Explanation:

Applying Dalton's law of partial pressure:

\(P_{total} = P_{helium} + P_{oxygen}\), where \(P_{total}\) = total partial pressure of all the component gases in the mixture, \(P_{helium}\) = partial pressure of helium gas, and \(P_{oxygen}\) = partial pressure of oxygen gas.

From the illustration, \(P_{total}\) = 7.00 atm and \(P_{oxygen}\) = 0.21 atm. Hence, the partial pressure due to helium is calculated such that:

\(P_{helium}\) = \(P_{total} - P_{oxygen}\)

           = 7.00 - 0.21

              = 6.79 atm

Therefore, the partial pressure due to helium in order to maintain the pressure due to oxygen at 0.21 atm would be 6.79 atm.

Answer:

the answer is B Astroid Belt

Explanation:

When the student crushes sugar there there occurs an increase in the number of molecules or particles of sugar. This means that now more number of sugar particles (solute) are able to interact with water (solvent).

Therefore, there will be more number of collisions taking place between the solute and solvent molecules.

As a result, sugar will dissolve readily into water as there is an increase in interaction between solute and solvent particles.

Thus, we can conclude that when he crushes the sugar and then stirs it into the water then it will work as this leads to more interaction or collisions between the solute and solvent particles.

The reaction between 2-methyl-2-pentanol and sulfuric acid to yield 2-methyl-2-pentene goes via an elimination reaction

Elimination reactions are those that proceed by the removal of one or more atoms or functional groups from the reactants, resulting in the formation of a new double bond or π bond in a product. An example of an elimination reaction is the dehydration of alcohols.In this particular reaction, 2-methyl-2-pentanol (an alcohol) reacts with sulfuric acid to produce 2-methyl-2-pentene, which is an alkene.

The reaction mechanism proceeds via an elimination reaction, where the OH group and a hydrogen ion (H+) are removed from the reactant, resulting in the formation of a double bond between the adjacent carbon atoms in the product.The reaction can be represented as follows:CH3C(CH3)2CH(OH)CH3 + H2SO4 → CH3C(CH3)2C=CH2 + H2O + H2SO4In conclusion, the reaction between 2-methyl-2-pentanol and sulfuric acid to yield 2-methyl-2-pentene goes via an elimination reaction.

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