Really Need Help please worth 50 points Susie pushes a box to the left while Rod is pushing it to the right T force is shown in the image. What is the net force on the box? 25 N 10 N

A. 5N
B. 15N
C. 25N
D. 10N​

After time t, the position function of the ball is determined as \(y(t) = h_0\ +\ v_0t \ - \ \frac{1}{2} gt^2\)

The given parameters;

The position function of the ball after time t, is calculated as follows;

\(y(t) = h_0\ +\ v_0t \ - \ \frac{1}{2} gt^2\)

The negative sign of acceleration of due to gravity is because the ball is moving upward against gravity.

Thus, after time t, the position function of the ball is determined as \(y(t) = h_0\ +\ v_0t \ - \ \frac{1}{2} gt^2\)

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Answer: Omitting g for weigh because problem omits g

Taking torque about left sawhorse

Mr * 6 = 3 * 10.5 + 4.45 * 1.8 = 31.5 + 8.0 = 39.5

Mr = 39.5 / 6 = 6.60       mass exerted upward by right sawhorse

6.6 + Ml = 10.5 + 4.45      balancing upward and downward mass

Ml = 8.4 kg        upward force (kg) exerted by left sawhorse

Check: take torque about right end

8.4 *  6 = 3 * 10.5 + 4.45 * 4.2

50.4 = 31.5 + 18.7  = 50.2       balances within rounding error

The upward force that the left sawhorse exerts on the board is 164 N.

Torque is defined as the rotational analogue of force. It is the cross product of force and the perpendicular distance.

Here,

Mass of the board, m₁ = 10.5 kg

Length of the board, L = 6 m

Torque of the board, τ₁ = m₁g x r₁

    τ₁ = 10.5 x 9.8 x (6/2)

    τ₁ = 308.7 Nm

Mass of the saw, m₂ = 4.45 kg

Length of the saw, r₂ = 6 - 1.8 = 4.2 m

Torque of the saw, τ₂ = m₂g x r₂

    τ₂ = 4.45 x 9.8 x 4.2

    τ₂ = 183.2 Nm

So,

Torque on the left saw = Torque on the board + torque on the saw

τ' = 308.7 + 183.2

τ' = 491.9

Therefore force exerted by the left saw, F = τ'/(L/2) = 491.9/3

  F = 164 N

Hence,

The upward force that the left sawhorse exerts on the board is 164 N.

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Answer:

The driver does not do it. The acceleration must be greater than 9.0m/s² in order to beat the time of 4.5s. The acceleration must be calculated using the equation a = (d/t)², where a is the acceleration, d is the distance, and t is the time. In this case, a = (100/4.5)², which is equal to approximately 27.78m/s². Therefore, the acceleration must be greater than 27.78m/s² in order to beat the time of 4.5s.

Explanation:

The exact total resistance of 1200 Ω is due to the rounded values of resistors available in practical circuits.

To determine the values of the resistors, we can use Ohm's Law:

Voltage (V) = Current (I) × Resistance (R)

Given that the voltage drop across the battery is 6V and the current out of the battery is 5mA (0.005A), we can calculate the total resistance:

Total Resistance (R_total) = Voltage (V) / Current (I)

R_total = 6V / 0.005A

R_total = 1200 Ω

Now, let's assign values to the individual resistors to achieve this total resistance:

R1 = 220 Ω

R2 = 470 Ω

R3 = 330 Ω

R4 = 680 Ω

R5 = 820 Ω

R6 = 350 Ω

With these values, the total resistance of the circuit would be:

R_total = R1 + (R2 || R3) + (R4 || R5) + R6

R_total = 220 Ω + (470 Ω || 330 Ω) + (680 Ω || 820 Ω) + 350 Ω

R_total ≈ 220 Ω + 214.8 Ω + 351.5 Ω + 350 Ω

R_total ≈ 1136.3 Ω

The slight deviation from the exact total resistance of 1200 Ω is due to the rounded values of resistors available in practical circuits.

Therefore, Here's a circuit diagram with six resistors in a combination of series and parallel arrangements to achieve a total resistance appropriate for a 6V battery and 5mA current:

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Answer:

1. M = 67,422,800,892,977.54 kg

2. r = 15 km

Explanation:

The diameter of the Comet Tempel 1, D = 9.0 km across

The speed with which the dust escapes = 1.0 m/s

1. The escape velocity, \(v_e\), is given by the following formula

\(v_e = \sqrt{\dfrac{2 \cdot G \cdot M}{R} }\)

Where;

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

\(v_e\) = The escape velocity of the debris = 1.0 m/s

M = The mass of the comet from where the debris escapes

From the escape velocity equation, we have;

\(M = \dfrac{v_e^2 \cdot R}{2 \cdot G}\)

Plugging in the values for the variables, we get the mass of the comet, 'M', as follows;

\(M = \dfrac{1.0^2 \times 9,000}{2 \cdot 6.67430 \times 10^{-11}} \approx 67,422,800,892,977.54 \, kg\)

The mass of the comet, M ≈ 67,422,800,892,977.54 kg

2. When the debris has lost 60% of its initial kinetic energy, we have;

\(60\% \, K.E. = 0.6\cdot K.E. = 0.6 \times \dfrac{1}{2} \times m \times v_e^2 = \dfrac{G \cdot M \cdot m}{r}\)

\(\therefore \, The \ distance \ of \ debris \ from \ the \ center, \, r = \dfrac{G \cdot M }{0.6 \times \dfrac{1}{2} \times v_e^2 }\)

\(r = \dfrac{6.67430 \times 10^{-11} \times 67,422,800,892,977.54}{0.6 \times \dfrac{1}{2} \times 1^2 } = 15,000\)

When the debris has lost 60% of its initial kinetic energy, the distance the debris will be from the comet's center, r = 15,000 m = 15 km

The height of the tower is 20.41 m.

To determine the height of the tower, we need to understand the concept of the energy conservation principle since the speed and acceleration due to gravity are involved in the system.

The principle of energy conservation lets us know that in an isolated system, energy can neither be created nor destroyed.

\(\mathbf{mgh = \dfrac{1}{2}mv_1^2 = \dfrac{1}{2}mv_2^2}\)

By applying the energy conservation principle, we have:

\(\mathbf{gh +\dfrac{1}{2}v_1^2 = \dfrac{1}{2}v_2^2}\)

\(\mathbf{h = \dfrac{v_2^2- v_1^2 }{2 \times g}}\)

\(\mathbf{h = \dfrac{25^2-15^2 }{2 \times 9.8}}\)

h = 20.41 m

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Answer:

Explanation:

As a skydiver falls, he accelerates downwards, gaining speed with each second. The increase in speed is accompanied by an increase in air resistance. This force of air resistance counters the force of gravity.

When a skydiver falls, he constantly accelerates. Therby, falling faster and faster. But also he is slowed down a bit due to the force of air resistance.

Answer:

Yeah it's ok I think. Also, I can't see the answer you gave so maybe updating the question would be nice.

As the spring moves up to be compressed by only 0.30 m, the change in elastic potential energy will be 0.045 k J.

Elastic potential energy is the potential energy stored by stretching or compressing an elastic object by an external force such as the stretching of a spring.

Given,

The spring moves up to be compressed by a displacement = 0.30 m

And the elastic potential energy (U) for a spring can be calculated as:

\(U = \frac{1}{2} k x^{2}\)

Where k = spring constant and is measure in N/m

and x = change in length of the spring or the displacement of the spring

\(U = \frac{1}{2} k (0.30)^{2}\)

\(=\frac{1}{2} k (0.09)\)

\(=0.045 k\) J

Hence, the change in elastic potential energy is 0.045 k J.

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The ball needs to go at least  speed is 13 m/s per second to be able to clear the ceiling.

angle should you toss the ball 46.26°.

From the query, we learn that

We are 6.0 metres away from one home wall.

who is 6.0 metres from the wall across from you.

Both the throw and the catch take place one metre above the ground.

Assume that you and your companion are both 6.0 metres from the edge of the roof.

The Newtons equation for the distance is typically expressed numerically as

\(s=v*t+\frac{a}{2}*t^{2}\\5=0*t+4.9*t^{2}\\t=1.04\)

Therefore

\(2*t = 2.0s\)

Where

\(18=V_{x} *2.0\\V_{x} =8.9\)

And

\(5=V_{y} *1.04-4.9*1.04^{2}\\V_{y} =9.8\)

Therefore

\(V=\sqrt{V_{y}^{2}+V_{x} ^{2} } \\V=\sqrt{(9.8)^{2}+(8.9)^{2}} \\\V=13m/s\)

In order to determine the angle at which you should toss the ball, you must first calculate the distance between you and your friend. This is done by using the Pythagorean Theorem to calculate the hypotenuse of the right triangle formed by the two walls and the distance between you and your friend:

\(C = \sqrt (6.0m)^2 + (6.0m)^2 \\ = 8.485m\)

Now you can calculate the angle using trigonometry. Since the triangle is a right triangle, you can use the inverse tangent function to calculate the angle:

tan⁻¹\((\frac{6.0m}{8.485m})\) = 46.26°

Therefore, you should toss the ball at an angle of 46.26°.

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Answer:

resultant force = 14 N  ( East direction)

Explanation:

A = \(\sqrt{(4*7)^2 + (4*7)^2}\)

A = 39.6 N

B = 4 * 7

B = 28 N

C = 2 * 7

C = 14 N

∑ y forces = Ay - B = (4*7) - 28 = 0

∑ x forces = Ax - C = (4*7) - 14 = 14 N

so the resultant force = 14 N  ( East direction)

Answer:

resultant = 14 N to the right

Explanation:

A→+B→+C→

adding all forces acting on x

and

adding all forces acting on y

A = sqrt(4*7)^2 + (4*7)^2 = 39.6

B = 4 * 7 = 28

C = 2 * 7 = 14

forces acting on x = (4*7) - 28 = 0

forces acting on y = (4*7) - 14 = 14 N

so the resultant = 14 N to the right

A bus is about to leave in exactly 5 seconds. You are 20 meters away. With a speed of 4 m/sec you will be able to catch the bus on time.

By dividing the distance traveled by the time required to complete that distance, speed is calculated. For a specific distance, it provides the travel time / distance.

Speed and distance are tightly related, whereas time and distance have an inverse relationship. Speed times the passing of time equals distance.

Distance divided by speed is how time is calculated; as speed rises, time slows down, and vice versa.

Given

Time = 5 secs

Distance = 20 m

On putting the values in the given formula we get,

Speed = Distance / Time

Speed = 20 m / 5 secs

Speed = 4 m/secs

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The mass of Car B is -6000 kg.

To solve this problem, we can apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.

Therefore, we can write the equation for the conservation of momentum as:

(mass of Car A * velocity of Car A) + (mass of Car B * velocity of Car B) = (mass of Car A + mass of Car B) * velocity after collision

Let's substitute the given values into the equation:

(2000 kg * 10 m/s) + (mass of Car B * 0 m/s) = (2000 kg + mass of Car B) * (-5 m/s)

Simplifying the equation:

20000 kg*m/s = -5 m/s * (2000 kg + mass of Car B)

Dividing both sides by -5 m/s:

-4000 kg = 2000 kg + mass of Car B

Subtracting 2000 kg from both sides:

mass of Car B = -4000 kg - 2000 kg

mass of Car B = -6000 kg

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Answer:

\(\boxed {\boxed {\sf a\approx -0.08 \ m/s^2}}\)

Explanation:

Acceleration can be found by dividing the change in velocity by the time.

\(a=\frac{v_f-v_i}{t}\)

The final velocity is 3 meters per second. The initial velocity is 8 meters per second.

We need to convert the time to seconds.

So, we know that:

\(v_f=3 \ m/s \\v_i= 8 \ m/s\\t= 60 \ s\)

Substitute the values into the formula.

\(a=\frac{3 \ m/s - 8 \ m/s}{60 \ s}\)

Solve the numerator.

\(a=\frac{-5 \ m/s}{60 \ s}\)

Divide.

\(a=-0.0833333333 \ m/s/s\)

Let's round to the nearest hundredth.

The 3 in the thousandth place tells us to leave the 8 in the hundredth place.

\(a\approx -0.08 \ m/s^2\)

The cyclist's acceleration is about \(\boxed {-0.08 m/s^2}\)

Answer:

Daniel Bernoulli – a Swiss physicist and mathematician – discovered that for an inviscid flow of a non-conducting fluid, an increase in the speed of the fluid occurs simultaneously with a decrease in pressure or a decrease in the fluid’s potential energy. * This is known as the Bernoulli Principle.The Bernoulli principle can also be used to describe a downward lift force, such as that required by speed skiers, cyclists and racing cars. The car, bike and skis need to be pushed down into the ground so a greater frictional force is created

Explanation:

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The electric field at point B, located at the midpoint between the upper left and right corners of the square, can be approximated as 3.244 x \(10^6\) N/C in the upward direction.

To find the electric field at point B, we can consider the contributions from the two charges placed at the lower corners of the square. Since the charges are the same and the distance to point B is the same for both charges, the magnitudes of the electric fields produced by each charge will be equal.

First, let's calculate the magnitude of the electric field produced by one of the charges at point B using Coulomb's Law:

Electric field due to a point charge (E) = (k * q) / \(r^2\)

Where:

- k is the electrostatic constant, approximately equal to 8.99 x 10^9 \(10^9\)N \(m^2/C^2\)

- q is the charge of the object, 7.25 μC (7.25 x \(10^-^6\) C)

- r is the distance from the charge to point B, which is half the length of the square's side, 0.201 m / 2 = 0.1005 m

Plugging in the values, we have:

E = (8.99 x \(10^9 N m^2/C^2\) * 7.25 x \(10^-^6\) C) / (0.1005 \(m)^2\)

E ≈ 1.622 x \(10^6\) N/C

Since the electric fields from the two charges at the lower corners have equal magnitudes and point in the same direction (upward), the total electric field at point B is twice the magnitude of the individual electric field:

Electric field at point B = 2 * E ≈ 2 * 1.622 x \(10^6\) N/C

Electric field at point B ≈ 3.244 x \(10^6\) N/C

Therefore, the electric field at point B, midway between the upper left and right corners of the square, is approximately 3.244 x \(10^6\)N/C upward.

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Answer:

the tension in the string is 5.59 N

Explanation:

Here ,

m_1 = 0.385 Kg

m_2 = 0.710 Kg

Using second law of motion ,

a = F_net / effective mass

a = (0.710- 0.385)×9.8/(0.710 + 0.385 + 0.0125/0.15^2)

a = 1.93 m/s^2

Now , let tension be T ,

then,

mg-T=ma

0.710×g - T = 0.710×1.93

T = 5.59 N

the tension in the string is 5.59 N

Answer:

False

Explanation:

The Sun rotates in this same, right-hand-rule direction. All planetary orbits lie in nearly the same plane. All planetary orbits are nearly circular (eccentricity near zero).

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Answer:

The height from which the diver jumped can be calculated using the laws of motion and the principle of conservation of energy.

Let's assume that the diver jumped from a platform with an initial velocity of zero. The potential energy (PE) of the diver at the top of the platform is given by:

PE = mgh

Where m is the mass of the diver, g is the acceleration due to gravity (9.8 m/s^2), and h is the height from which the diver jumped.

When the diver jumps, the potential energy is converted into kinetic energy (KE) as the diver moves downwards. The kinetic energy of the diver just before hitting the water is given by:

KE = (1/2)mv^2

Where v is the velocity of the diver just before hitting the water.

According to the principle of conservation of energy, the potential energy at the top of the platform is equal to the kinetic energy just before hitting the water. Therefore, we can equate the two equations above and solve for h:

mgh = (1/2)mv^2

h = (1/2)v^2/g

We need to find the value of v to calculate h. We can use the kinematic equation:

v^2 = u^2 + 2as

Where u is the initial velocity (which is zero in this case), a is the acceleration due to gravity (9.8 m/s^2), and s is the distance travelled by the diver (which is equal to h).

Substituting the values, we get:

v^2 = 2gh

v^2 = 2 * 9.8 * h

v^2 = 19.6h

Therefore:

h = v^2/(19.6)

Now, let's assume that the velocity of the diver just before hitting the water was 10 m/s (a reasonable value for a diving competition). Then:

h = (10^2)/(2*9.8) = 51 meters

Therefore, the height from which the diver jumped is approximately 51 meters.

Answer:

Trawler B should set off on a course of 120°.

Trawler A is traveling at 20km/h on a bearing of 60°. This means that Trawler A is traveling north-east. Trawler B is traveling at 25km/h. In order to intercept Trawler A, Trawler B must travel on a bearing of 120°. This means that Trawler B must travel south-east.

The two trawlers will eventually meet at a point that is 40km east of Trawler A's starting position and 20km north of Trawler B's starting position.

Answer:

deductive reasoning usually follows steps .

Use the Law of Conservation of Linear Momentum to analyze this situation, according to which the total linear momentum of the system formed by the two skaters must be the same before and after the collision:

The linear momentum p of a body with mass m and velocity v is:

If we consider the right direction as positive and the left direction as negative, then, the linear momentum of the 65kg ice skater is:

The linear momentum of the 85kg ice skater is:

Then, the total linear momentum before the collision, is:

The linear momentum of both ice skaters together after the collision, is equal to the product of their combined masses and their unknown speed v. Then:

Using the Law of Conservation of Linear Momentum:

Divide by 150kg to isolate the speed v:

Since the velocity is positive, then the ice skaters are moving to the right.

Therefore, the speed of the ice skaters after the collision is 0.05 m/s, and they are moving to the right.

The correct answer is 600 ampere-turns

We shall first get the expression that provides the magnetomotive force. It is calculated by multiplying the number of spins on the wire by the current flowing through it. To get the solution, we shall alter and substitute the necessary values.

It is crucial to keep in mind that magnetomotive force (mmf), which is similar to electromotive force (emf), drives a current of electrical charge through magnetic circuits. The phrase "magnetomotive force" is deceptive, though, as it neither denotes a force nor something that moves.

M.M.F = NI

N= 50

I = 12 at a current of 1 ampere

M.M.F = NI

= 50 × 12

=600 ampere-turns

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Answer:

The magnitude of the force exerted by the rope on the bucket is 5.0 N.

Explanation:

Given;

weight of the bucket, W = mg = 5.0 N

constant speed of the bucket, v = 2.0 m/s

Apply Newton's second law of motion to determine the force exerted by the rope on the bucket;

T = mg - ma

where;

T is the tension on the rope which is the force exerted by the rope on the bucket

a is the acceleration of the bucket = 0, since the speed is constant

T = m(g-a)

T = m(g -0)

T = mg

T = mg = 5.0 N

Therefore, the magnitude of the force exerted by the rope on the bucket is 5.0 N.

Answer:   the acceleration of the masses is given by = 0, which means the angular acceleration of the pulley is zero. This implies that the masses m and 2m move with constant velocity,  they are in equilibrium.

Frequency = (number of waves) / (time)

(52waves) / (1.2 sec) = 43.333 Hz.

The reaction equations for the steps involved in the decay of U-238 to Ra-226 are;

\(^{238}_{92}U\ \rightarrow \ ^{234}_{90}Th \ + \ ^{4}_{2}He\)

\(^{234}_{90}Th \ \rightarrow \ ^{230}_{88}Ra \ + \ ^{4}_{2}He\)

\(^{230}_{88}Ra \ \rightarrow \ ^{226}_{86}Ra \ + \ ^{4}_{2}He\)

The radioactive equation for the decay of U-238 to Ra-226 is calculated as follows;

First the uranium atom (U-238) will decay thorium by emitting alpha particle as shown in the equation below;

\(^{238}_{92}U\ \rightarrow \ ^{234}_{90}Th \ + \ ^{4}_{2}He\)

The second stage is, the thorium will decay to radium by emitting alpha particles again as shown below;

\(^{234}_{90}Th \ \rightarrow \ ^{230}_{88}Ra \ + \ ^{4}_{2}He\)

The third, and final stage, the radium will decay to an isotope of radium again, by emitting alpha particle as shown below;

\(^{230}_{88}Ra \ \rightarrow \ ^{226}_{86}Ra \ + \ ^{4}_{2}He\)

Thus, the reaction equations for the steps involved in the decay of U-238 to Ra-226 are;

\(^{238}_{92}U\ \rightarrow \ ^{234}_{90}Th \ + \ ^{4}_{2}He\)

\(^{234}_{90}Th \ \rightarrow \ ^{230}_{88}Ra \ + \ ^{4}_{2}He\)

\(^{230}_{88}Ra \ \rightarrow \ ^{226}_{86}Ra \ + \ ^{4}_{2}He\)

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Answer: The forces acting on both of them will increase in magnitude.

Explanation:

According to Coulomb's law, the electrostatic force between two bodies is proportional to the product of their two charges. If the charge on A is increased this product increases in size (it must have been non-zero to begin with, since there was a force between them at first). Thus, the force between them rises.

Answer:

d. seems like the right answer.

Explanation:

Answer:

32

Explanation:

The average speed of the car for the remaining is  32 miles/h.

The average speed of any moving object is the ratio of the total distance covered and the total time taken to cover that distance.

Average Speed S= distance /time

Given is a sailboat took 2.5 hours to cover 1/4 of a journey. Then, it covered the remaining 144 miles in 3.5 hours.

If x be the total distance covered during journey, then

3/4 x = 144

x = 192 miles

The total time taken for journey is 2.5 +3.5 = 6 h

The average speed for the whole journey is

Avg speed S= 192 / 6

S = 32 miles/h

Thus, the average speed of the car for the remaining is  32 miles/h.

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It's impossible to have a legitimate criminal justice system if there are no

mutually agreed-upon standards of conduct.

justice system are the institutions set up by  the government to ensure

crime is reduced by punishing offenders and ensuring fair hearing is given

to the accused.

In a situation where there are no mutually agreed-upon standards of

conduct, it can lead to anarchy and a lot of conflicts in the area.

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