reduction of nitrate to nitrite by paracoccus denitrificans is an example of anaerobic respiration.

Answer:

I think it's 21.5 *C

Explanation:

The empirical formula of the compound containing Mg and N is Mg₃N₂.

The outcome of the Mg + N2 reaction is:

Mg + N₂ → MgₓNₙ

the following are contained in 0.55g of magnesium:

Mg is represented as 0.55g x (1 mol / 24.305g) = 0.0226 moles.

Due to the product's 0.76g mass, the mass of nitrogen is as follows:

0.76g minus 0.55g equals 0.21g of nitrogen.

0.015 moles of N are equal to 0.21g x (1 mol / 14g).

The ratio of N:Mg in moles is:

0.0226 / 0.015 = 1.5. This indicates that you have 1.5 Mg atoms for every N atom. The problem's empirical formula, which is the simplest whole-number ratio of atoms in a compound, is:Mg₃N₂

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Answer:

Proton

Explanation:

Changing the number of protons in an atom changes the type of atom.

Answer:

Explanation: An acid is a substance or compound that releases hydrogen ions (H+) when in solution. In a strong acid, such as hydrochloric acid (HCl), all hydrogen ions (H+), and chloride ions (Cl-) dissociate (separate) when placed in water and these ions are no longer held together by ionic bonding.

Answer:

115 mL of a gas is at 45.8 kPa and 57.2°C. What is the volume of the gas at 99.3 kPa and 112.3°C?[5] 11. ... What is the pressure of 62.76 g of carbon dioxide (CO2) gas if it occupies a volume of 35,000 mL at standard temperature?

Explanation:

By using gas law , the volume will be 61.9 mL .

According to the gas law, the pressure of a gas generally directly proportional to its temperature at a fixed volume.

Gas law can be represented as:

\(P_{1} V_{1}/ T_{1} = P_{2} V_{2} / T_{2}\)

Calculation of volume with the aid of gas law:

It is given that, \(P_{1}\) = 45.8 kPa, \(P_{2}\) = 99.3 kPa , \(T_{1}\) = 57.2°C, \(T_{2}\) = 112.3°C, \(V_{1}\) = 115 mL .

Now, put the values of given data in gas laws equation.

(45.8kPa)(115mL)/(330K)= (99.3kPa)(\(V_{2}\))(385.3K)

\(V_{2}\) = 61.9 mL

Therefore, the volume will be 61.9 mL .

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Answer:

‑297 degrees Fahrenheit (‑183 degrees Celsius).

Explanation:

Answer:

-218°C.

Explanation:

Oxygen's melting point is -218°C. At that temperature, solid oxygen starts converting to liquid.

Answer:

For the distance range 50 to 500 km, the S-waves travel about 3.45 km/s and the P-waves around 8 km/s.

IF HELPED MARK AS BRAINLIEST

Answer:

For the distance range 50 to 500 km, the S-waves travel about 3.45 km/s and the P-waves around 8 km/s.

Answer:

I believe physical

Explanation:

If you step on the bag of chips, it would reduce them to crumbs. Wouldn't this be a physical change in the chips?

Answer:

physical change

Explanation:

when you step on a bag of chips they would be crushed so it would cause a physical change.

Answer:

The velocity of the bb when it reaches a height of 203 m can be determined using the laws of projectile motion. Since the bb is moving vertically upwards, its velocity at that height will be zero.

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Answer: v = 83.96 m/s

Assuming the acceleration due to gravity is approximately 9.8 m/s^2, we can use the principles of projectile motion and energy conservation.

Using the equation for the vertical displacement of an object in free fall:

Δy = (v₀² - v²) / (2g)

Δy = vertical displacement (203m)

v₀ = initial velocity (105 m/s)

v = final velocity (not known yet)

g = accerlation due to gravity (9.8 m/s^2)

Lets rearrange the equation to solve for the final velocity:

v = v = √(v₀² - 2gΔy)

Substituting the given values:

v = √(105² - 2 * 9.8 * 203)

v ≈ √(11025 - 3979.6)

v ≈ √(7054.4)

v ≈ 83.96 m/s

Therefore, when the BB pellet is at the height of 203m, its velocity will be approximately 83.96 m/s.

The percent yield of CO₂ if a reaction starts with 91.3 g C₃H₆ and produces 87.0 g CO₂ is 30.4%.

To calculate the percent yield of CO₂, you need to first determine the theoretical yield and then use the actual yield (87.0 g CO₂) to find the percent yield.

1. Balance the reaction: C₃H₆ + O₂ → 3CO₂ + 3H₂O

2. Calculate the molar mass of C₃H₆

(3C + 6H) = (3 × 12.01 + 6 × 1.01)

= 42.08 g/mol

3. Calculate the moles of C₃H₆:

(91.3 g C₃H₆) / (42.08 g/mol)

= 2.168 moles C₃H₆

4. Since the ratio between C₃H₆ and CO₂ is 1:3, moles of CO₂

= 3 * 2.168

= 6.504 moles

5. Calculate the molar mass of CO₂ (C + ₂O)

= (12.01 + 2 × 16.00)

= 44.01 g/mol

6. Calculate the theoretical yield:

(6.504 moles CO₂) × (44.01 g/mol)

= 286.2 g CO₂

7. Calculate the percent yield:

(Actual yield / Theoretical yield) × 100

= (87.0 g CO₂ / 286.2 g CO₂) × 100

= 30.4%

Thus, the percent yield of CO₂ in this reaction is 30.4%.

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(b) electronegativity decreases left to right across the periodic table

Electronegativity increases from left to right in a period across the periodic table.

Electronegativity is a relative property that defines the tendency to attract shared pair of electrons. It is a unitless parameter that is calculated by different formulae.

Pauling scale is widely used to calculate the electronegativity values of a covalent bond. e.g. F = 4.0, Cl = 3.0, etc.

⇒Electron affinity decreases from top to bottom in the periodic table.

⇒Atomic radii decrease from left to right in the periodic table.

⇒Ionization energy decreases from top to bottom in the periodic table.

Given data:H2O vapor content: 13 gramsH2O vapor capacity: 52 grams at 25 degrees Celsius 13 grams at 10∘C52 grams at 30∘CFormula used to find the dew point:$$\dfrac{13}{52}=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$$$\frac{1}{4}=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$

Where A is the constantDew Point:It is the temperature at which air becomes saturated with water vapor when the temperature drops to a point where dew, frost or ice forms. To solve this question, substitute the given data into the formula.$$13/52=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$$$13(17.27-A)=3\pi A(ln100)$$By simplifying the above expression, we get$$A^2-17.27A+64.78=0$$Using the quadratic formula, we get$$A=9.9,7.4$$

The dew point is 7.4 since it is less than 10°C.More than 100:The term "More than 100" has not been used in the question provided.

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The equilibrium hydronium ion concentration of an initially 4.5 m solution of hypoiodous acid, hoi, at 25°C (Ka = 10-10) is explained as follows:We can use the following expression to determine the hydronium ion concentration of a weak acid, which is ionized to a small extent.Ka = [H3O+][A−][HA]/[H2O]Here, HA is the weak acid, A− is its conjugate base, and [H2O] = constant.

Hypoiodous acid (HOI) is the weak acid in this case, and we can write its equation as follows:HOI + H2O ⇌ OI− + H3O+Initial concentration of HOI = 4.5 M.At equilibrium, let's suppose x M of HOI gets ionized, giving x M of OI− and x M of H3O+.Initial concentration of HOI is reduced by x to give the equilibrium concentration of HOI as (4.5−x) M.Now, we may use the Ka expression to calculate x and the hydronium ion concentration.

Ka = [H3O+][OI−]/[HOI]x^2/(4.5−x) = 1.0 × 10^-10Let's suppose x is small in comparison to 4.5. As a result, we can make the following assumptions:x^2/(4.5) ≈ 0.0because, x << 4.5As a result,x^2/(4.5−x) ≈ x^2/4.5Since we're solving for x, let's rearrange the equation: x^2 = 1.0 × 10^-10 × 4.5x = 1.0 × 10^-6 MThe hydronium ion concentration is x, therefore the main answer is the equilibrium hydronium ion concentration of an initially 4.5 M solution of hypoiodous acid is 1.0 × 10^-6 M.

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The number between the parentheses in a chemical formula represents the subscript of that particular group of atoms or polyatomic ion that is enclosed in the parentheses.

In chemistry, we use chemical formulas to express the number of atoms that make up a molecule or compound. Chemical formulas are a shorthand way of writing a compound’s name and its chemical structure. A chemical formula indicates the type and number of atoms that are present in a compound or molecule.

For example, the chemical formula for water is H2O, where H is the symbol for hydrogen, and O is the symbol for oxygen. This formula tells us that one molecule of water is made up of two hydrogen atoms and one oxygen atom, which are bonded together.Another example, Ca(OH)2, which represents the ionic compound calcium hydroxide. The parentheses indicate that the hydroxide (OH) group is made up of one oxygen atom and one hydrogen atom. The subscript 2 outside the parentheses tells us that there are two hydroxide groups in the molecule.

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1. The limiting reagent is sulfur trioxide, SO₃ and the excess reagent is water, H₂O

2. The mass of the excess reagent leftover is 14.92 g

3. The mass of sulfuric acid, H₂SO₄ is produced is 8.06 g

The limiting and excess reagent can be obtained as follow:

SO₃ + H₂O -> H₂SO₄

From the balanced equation above,

80 g of SO₃ reacted with 18 g of H₂O

Therefore,

6.58 g of SO₃ will react with = (6.58 × 18) / 80 = 1.48 g of H₂O

From the above calculation, we can see that only 1.48 g of H₂O out of 16.4 g is needed to react completely with 6.58 g SO₃.

Thus, the limiting reagent is SO₃ and the excess reagent is H₂O

The mass of the excess reagent leftover can be obtained as follow:

Mass of excess reagent, H₂O leftover = Mass given - mass reacted

Mass of excess reagent, H₂O leftover = 16.4 - 1.48

Mass of excess reagent, H₂O leftover = 14.92 g

The mass of H₂SO₄ produced can be obtained as illustrated below:

SO₃ + H₂O -> H₂SO₄

From the balanced equation above,

80 g of SO₃ reacted to produce 98 g of H₂SO₄

Therefore,

6.58 g of SO₃ will react to produce = (6.58 × 98) / 80 = 8.06 g of H₂SO₄

Thus, the mass of H₂SO₄ produced is 8.06 g

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Answer:

2 single, 0 double, and 1 triple

Explanation:

H-C≡C-H

Answer:

yes

Explanation:

Answer:

Alpha is the most harmful, Gamma is the least harmful.

Explanation:

From skimming over your answer I have noticed this mistake. You are correct in saying alpha is the least penetrating but incorrect in saying alpha is the least ionising. Same for Gamma.

Answer:

3846g of Carbon tetrachloride is in the chemical equation.

Explanation:

The Balanced equation is :

   CH4 + 4CL2 -> CCL4 + 4HCL

Converting grams to moles ;

  Moles of CL2 = Mass / Molar mass

  Molles of CL2 = 709.0g/70.906g/mol => 10 moles

  Moles  of CCL4 = Moles of CL2 / 4

  Moles of CCL4 = 10 moles/ 4 => 2.5 moles

Converting moles of CCL4 to grams:

 Mass of CCL4 = Moles of CCL4 x Molar mass of CCL4

 Mass of CCL4 = 2.5 moles x 153.823 g/mol => 384.5575 grams

Therefore 384.6 grams of carbon tetrachloride can be produced from reacting 709.0 grams of chlorine.

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Your answer is B

Sun and wind are considered renewable energy, meaning that it won't polute the Earth. And as far as I know, the Sun and wind can't really run out. So it can last a very long time!

Hope this helps!

-Daisuke

Answer: D. Condensation

Explanation: because condensation happens when water vapor cools and turns into clouds

Williamson ether synthesis would give a poor yield of product as the halide is on a 2° carbon. is true about the synthesis of 1-isopropoxy-1-methylcyclopentane.

The Williamson ether synthesis is a method for the synthesis of ethers using an alcohol and an alkyl halide. The reaction proceeds through a nucleophilic substitution mechanism and the ether product is obtained with the alcohol and halide groups in the anti-Markovnikov orientation. The reactivity of the alkyl halides used in this reaction follows the order: primary > secondary >> tertiary. Therefore, the reaction of a secondary halide such as 2° carbon halide will give a poor yield of product as the reactivity of 2° carbon halide is less compared to primary halide. As a result, the reaction is less efficient and the yield of the product is lower.

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Explanation:

We have a 63.9 g sample of calcium hydroxide. First we have to convert those grams into moles. To do that we have to use the molar mass of calcium hydroxide.

Calcium hydroxide = Ca(OH)₂

molar mass of Ca = 40.08 g/mol

molar mass of O = 16.00 g/mol

molar mass of H = 1.01 g/mol

molar mass of Ca(OH)₂ = 1 * 40.08 g/mol + 2 * 16.00 g/mol + 2 * 1.01 g/mol

molar mass of Ca(OH)₂ = 74.10 g/mol

mass of Ca(OH)₂ = 63.9 g

moles of Ca(OH)₂ = 63.9 g /(74.10 g/mol)

moles of Ca(OH)₂ = 0.862 moles

In 1 molecule of Ca we have 2 atoms of O. So in 1 mol of Ca(OH)₂ we will have 2 moles of O atoms.

1 mol of Ca(OH)₂ = 2 moles of O atoms

moles of O atoms = 0.862 moles of Ca(OH)₂ * 2 moles of O /1 mol of Ca(OH)₂

moles of O atoms = 1.724 moles

One mol is similar to a dozen. When we say that we need a dozen eggs we know that we need 12 eggs. If we want a mol of eggs, we want 6.022*10^23 eggs. So one mol of something is 6.022 * 10^23 of that.

1 mol of O atoms = 6.022 * 10^23 atoms

n° of O atoms = 1.724 moles * 6.022 * 10^23 atoms/1 mol

n° of O atoms = 1.04 * 10^24 atoms

Answer: In a 63.9 g sample of Ca(OH)₂ we have 1.04 *10^24 atoms of oxygen.

Answer:

the bike is moving at a speed of 0.115810 mph

The coefficients in a balanced equation can be used as molar ratios, which can act as conversion factors to relate the reactants to the products. These conversion factors state the ratio of reactants that react but do not tell exactly how much of each substance is actually involved in the reaction.

The best proof that a chemical reaction has occurred based on the observations above is: Small, solid particles formed and fell to the bottom of the beaker.

Chemical reactions occur when the chemical composition of a substance changes.

What is the best proof that a chemical reaction has occurred based on the following observations?

Students mixed two liquids in a beaker and listed their observations. Observations Liquid 1 was colorless. Liquid 2 was colorless. The mixture of liquids 1 and 2 formed a colorless solution. Small, solid particles formed and fell to the bottom of the beaker.

When two liquids are mixed and a solid forms, that is the best indication that a chemical reaction has occurred. This indicates a precipitation reaction has occurred in which an insoluble substance forms from a solution. This chemical reaction occurs when two aqueous solutions are mixed and the resulting solution becomes a solid compound called a precipitate.  Precipitation reactions are one type of double replacement reaction that occurs in water solutions.

                                               Therefore, the best proof that a chemical reaction has occurred based on the observations above is: Small, solid particles formed and fell to the bottom of the beaker.

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