Rhonda is looking for a campsite for the night. From her parking spot she walks north for 212 meters, then turns and walks west for 145 m what is the displacement from Rhonda's car to her campsite

The two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.

In the given case, the figure shows an exaggerated view of a rifle that has been sighted in for a 91.4-meter target. Let the muzzle speed of the bullet be v0 = 427 m/s.

Now, we are required to find the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target.

It is known that the horizontal displacement of the bullet from the gun can be given by the equation: x = v0 t cosθ ..........(i)and the vertical displacement of the bullet from the gun can be given by the equation: y = v0 t sinθ - (1/2) g t^2..........(ii).

Here, t is the time of flight of the bullet and g is the acceleration due to gravity.

As the bullet hits the target, its final vertical displacement from the gun is equal to the height of the target, i.e.,y = 91.4m.Now, we can substitute equations (i) and (ii) in place of t and y in equation (ii) to get:x tanθ - (g/2v0^2) x^2 sec^2θ = 91.4 ..........(iii)This is a quadratic equation in tanθ.

On solving this equation using the quadratic formula, we get:tanθ = [-b ± √(b^2 - 4ac)]/2aWhere,a = -gx^2/(2v0^2) = -4.9x^2/v0^2, b = x, and c = -91.4.

Rearranging the terms, we get:2a tanθ^2 + b tanθ - 91.4 = 0On substituting the given values, we get:2(-4.9x^2/v0^2) tanθ^2 + x tanθ - 91.4 = 0θ1 and θ2 are the two possible angles which can be found by solving the above quadratic equation.

Using the trigonometric identity given in the hint, we can write: sin 2θ = 2 sinθ cos θ = 2 tanθ/ (1 + tan^2θ)Now, we can substitute tanθ = (-b ± √(b^2 - 4ac))/2a in the above equation to get: sin 2θ = (-4bx ± 2x√(b^2 - 4ac))/(b^2 + 4a^2)Now, we can substitute the given values to get: sin 2θ1 = -0.999sin 2θ2 = 0.998.

Thus, we get two values of sin 2θ, one is close to -1 and the other is close to 1. As sin 2θ = -1 when 2θ = -π/2 + nπ and sin 2θ = 1 when 2θ = π/2 + nπ, where n is an integer, we get two possible values of θ for each of these two cases.

Hence, the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.

As one of these angles is so large that it is never used in target shooting, we only need to consider the other angle.

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The two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.

In the given case, the figure shows an exaggerated view of a rifle that has been sighted in for a 91.4-meter target. Let the muzzle speed of the bullet be v0 = 427 m/s.

Now, we are required to find the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target.

It is known that the horizontal displacement of the bullet from the gun can be given by the equation: x = v0 t cosθ ..........(i)and the vertical displacement of the bullet from the gun can be given by the equation: y = v0 t sinθ - (1/2) g t^2..........(ii).

Here, t is the time of flight of the bullet and g is the acceleration due to gravity.

As the bullet hits the target, its final vertical displacement from the gun is equal to the height of the target, i.e.,y = 91.4m.Now, we can substitute equations (i) and (ii) in place of t and y in equation (ii) to get:x tanθ - (g/2v0^2) x^2 sec^2θ = 91.4 ..........(iii)This is a quadratic equation in tanθ.

On solving this equation using the quadratic formula, we get:tanθ = [-b ± √(b^2 - 4ac)]/2aWhere,a = -gx^2/(2v0^2) = -4.9x^2/v0^2, b = x, and c = -91.4.

Rearranging the terms, we get:2a tanθ^2 + b tanθ - 91.4 = 0On substituting the given values, we get:2(-4.9x^2/v0^2) tanθ^2 + x tanθ - 91.4 = 0θ1 and θ2 are the two possible angles which can be found by solving the above quadratic equation.

Using the trigonometric identity given in the hint, we can write: sin 2θ = 2 sinθ cos θ = 2 tanθ/ (1 + tan^2θ)Now, we can substitute tanθ = (-b ± √(b^2 - 4ac))/2a in the above equation to get: sin 2θ = (-4bx ± 2x√(b^2 - 4ac))/(b^2 + 4a^2)Now, we can substitute the given values to get: sin 2θ1 = -0.999sin 2θ2 = 0.998.

Thus, we get two values of sin 2θ, one is close to -1 and the other is close to 1. As sin 2θ = -1 when 2θ = -π/2 + nπ and sin 2θ = 1 when 2θ = π/2 + nπ, where n is an integer, we get two possible values of θ for each of these two cases.

Hence, the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.

As one of these angles is so large that it is never used in target shooting, we only need to consider the other angle.

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Humans emit waves at a frequency of 33.3 THz, which correspond to the infrared portion of the electromagnetic spectrum.

a) With a wavelength of 9.0 microns, the frequency of electromagnetic waves emitted by humans is roughly 33.3 THz. (terahertz).

b) These waves are part of the electromagnetic spectrum's infrared region, which is responsible for heat transfer and is widely used in technologies such as remote controls and thermal imaging cameras. Infrared waves belongs to the region of the spectrum where the wavelength is high but the frequency is low but they have shorter wavelength and longer frequency than the microwaves.

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The change of kinetic energy is -156.7 joules.

\(V1_{i}\) =15

\(V2_{i}\)= -13.5(as towards left)

V= common velocity during collision

On applying momentum conservation during the collision

\(m_{1}V1_{i} + m_{2}V2_{i} = V ( m_{1} + m_{2})\)

\(0.650 \ 15 + 0.950 \ (-13.5) = (0.625 + 0.950) \ V\)

    \(\frac{3.075}{1.6}\) =V

V= -1.92 m/s        

To kind change in kinetic energy we will subtract final and initial kinetic energy

ΔK=\(\frac{1\ (m_{1} + m_{2} ) \ V}{2} ^{2}\) - \(\frac{1\ (m_{1} ) \ V1_{i} }{2} ^{2}\)  -  \(\frac{1\ (m_{2} ) \ V2_{i} }{2} ^{2}\)

ΔK= \(\frac{1\ (0.625 + 0.950 ) \ (-13.5)}{2} ^{2}\) -  \(\frac{1\ (0.625 ) \ 15 }{2} ^{2}\)-  \(\frac{1\ (0.950 ) \ 13.5 }{2} ^{2}\)

ΔK=   = - 156.7 J

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Answer:

Your answer is -2.5m/s

Explanation:

To determine the position u of the mass at any time t, we can use the equation of motion for a mass-spring system without damping:n m * u''(t) + k * u(t) = 0

m = 2 lb / (32.2 ft/s^2) = 0.062 lb·s^2/ft

The spring constant k can be determined using Hooke's law:

k = F / x

where F is the force exerted by the mass and x is the displacement. In this case, the force F is the weight of the mass, and the displacement x is 6 in:

k = (2 lb) / (6 in) = (2 lb) / (6 in) * (1 ft/12 in) = 0.111 lb/ft

The equation of motion now becomes:

0.062 * u''(t) + 0.111 * u(t) = 0

To solve this second-order linear homogeneous differential equation, we assume a solution of the form u(t) = A * cos(ωt + φ).

Substituting this assumed solution into the equation of motion, we get:

-0.062 * A * ω^2 * cos(ωt + φ) + 0.111 * A * cos(ωt + φ) = 0

-0.062 * ω^2 + 0.111 = 0

Solving for ω, we get:

ω = sqrt(0.111 / 0.062) = 2.258 rad/s

From ω, we can determine the frequency f and period T:

f = ω / (2π) = 2.258 / (2π) ≈ 0.359 Hz

T = 1 / f ≈ 2.786 s

The amplitude A is determined by the initial conditions. When the mass is pulled down an additional 3 in (0.25 ft) and released, it reaches its maximum displacement, so A = 0.25 ft.

Therefore, the position u of the mass at any time t is given by:

u(t) = 0.25 * cos(2.258t)

To draw the graph of u(t), plot the position u on the y-axis and time t on the x-axis, using the equation u(t) = 0.25 * cos(2.258t). The graph will be a cosine wave with an amplitude of 0.25 ft.

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We will have the following:

First, we remember that:

So:

So, the change in length of the rod is approximately 4.41 mm.

Answer:

I think it is D

Explanation:

Answer:

D :D lol

Explanation:

The star is moving away from Earth at a velocity of 1.8 x 106 m/s.

The Doppler Effect describes the shift in wavelength of a wave when the source is moving in relation to the observer. The shift can be observed in sound waves, light waves, and other waves.

The Doppler Effect can be used to determine the velocity of objects moving away from an observer, as in the case of stars moving away from Earth.

The velocity of a star moving away from Earth can be determined using the equation:

v = Δλ/λ x c, Where v is the velocity of the star, Δλ is the shift in wavelength of the spectral line, λ is the wavelength of the spectral line measured in the lab on Earth, and c is the speed of light (3.00 x 108 m/s).

In this case, the shift in wavelength of the spectral line is Δλ = 500.3 nm - 500 nm = 0.3 nm.

The wavelength of the spectral line measured in the lab on Earth is λ = 500 nm.

Plugging in these values to the equation above: v = Δλ/λ x cv = (0.3 nm / 500 nm) x (3.00 x 108 m/s) = 1.8 x 106 m/s.

Therefore, velocity of star 1.8 x 106 m/s.

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Pascal's introverted nature may lead to them being more reflective and introspective, which could enhance their ability to recognize facial expressions of emotion. However, they may struggle with expressing their own emotions outwardly, as introverts tend to process emotions internally before sharing them with others.

In terms of their ability to recognize facial expressions of emotion and to express emotions, Pascal, as an introvert, may be more sensitive and observant, which could potentially make them better at recognizing facial expressions.

However, this doesn't necessarily mean they are less able to express emotions compared to their extravert friend Paulina, who might display emotions more openly and energetically. Both introverts and extraverts have unique ways of processing and expressing emotions.

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The plane travels a distance of 325 miles if the airplane travels for 2.5 hours at an average speed of 130 miles per hour. Using the distance formula (d = rt), we can calculate the distance.

To find the distance traveled by the airplane, we can use the distance formula, which is represented as d = rt. In this formula, "d" represents the distance, "r" represents the rate or speed at which the object is traveling, and "t" represents the time taken for the travel.

Given that the airplane travels for 2.5 hours at an average rate of 130 miles per hour, we can substitute these values into the formula. The rate of the airplane is 130 miles per hour, and the time taken is 2.5 hours.

Using the formula, we can calculate the distance traveled as follows:

d = rt

d = 130 mph × 2.5 hours

Multiplying the rate (130 mph) by the time (2.5 hours) gives us:

d = 325 miles

Therefore, the airplane travels a distance of 325 miles during the 2.5 hours of travel at an average rate of 130 miles per hour.

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Answer:

a = V/T

Explanation:

uh i think thats the answer let me know if im wrong

what's the answer to say

When a person focuses on an object at a very far distance from the eye, the focal length of the eye at that time is approximately infinity.

The human eye is a complex optical system that can adjust its focus to objects at different distances. The lens of the eye changes its shape to allow for accommodation, enabling the eye to focus on objects at varying distances. However, when a person looks at an object located at an extremely far distance, such as a distant mountain or star, the light rays entering the eye can be considered nearly parallel.

In this scenario, the lens of the eye becomes relatively flat and reaches its least curved state. As a result, the focal length of the eye approximates infinity. Essentially, the eye's focusing mechanism is optimized for parallel light rays, allowing the incoming light to converge at a point that is virtually at an infinite distance from the eye. This enables clear vision and sharp focus on objects situated at extremely far distances.

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Answer:

After 5minutes the temperature in the metal cup will decrease the most

Explanation:

this is because metal is a very good conductor of heat, this property also allows it to lose heat to the surrounding, while plastic and cardboard are insulators and they tend to retain the heat hence the water is warm after 5 minutes.

Answer:

to be balanced moments should be equal

4m

Explanation:

\(fd = fd \\ 600 \times 2 = 300 \times x \\ \frac{600 \times 2}{300} = x \\ 4m\)

Answer:

4m

Explanation:

fd=fd

600×2× x

300

4m ans

Answer:

objects that is at rest will remain at rest and an objects in motion will remain in motion with the same velocity unless changed by an unbalanced force.

Explanation:

A moving body must undergo a change of position.

The concept of inertia states that an object will maintain its current motion unless a force changes its speed or direction. The phrase should be understood as a shortened form of Newton's first law of motion's description of "the principle of inertia."

The inertia of motion is the resistance offered by the body to continue to be in the uniform motion unless an external force acts on it.

Movement is a change in a body part's position in relation to the entire body. It is one of the key characteristics shared by all living things. Examples of movement include eating, breathing, and eye blinking. Therefore, we may conclude that at least one portion of our body moves in some way every second.

Hence, a  moving body must undergo a change of position.

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In Ørsted’s observation, the current-carrying wire acted like  option B)magnet

Michael Faraday based his first invention, the C) motor, on Ørsted s observation.

The two laws that relate electricity and magnetism the other being Faraday's law of induction were originally discovered as a result of rsted's discoveries. These two rules were incorporated into Maxwell's equations, which control electromagnetic.

Note that When a magnetic compass needle was brought in close proximity to a wire carrying current, Oersted noticed that it dramatically deflected. Since of this result, he came to the conclusion that a wire can function as a magnet because moving charges in the form of a current possess a certain magnetic field.

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See correct question below

In Ørsted’s observation, the current-carrying wire acted like a

A)generator

B)magnet

C)motor

Michael Faraday based his first invention, the (______),on Ørsted s observation.

A)electromagnet

B)generator

C)motor

Answer:

9. forces: BALANCED, object will: NOT ACCELERATE

10. Forces: UNBALANCED, object will: ACCELERATE

Explanation: sorry I don't no the net force but hope this helps for know

True, most astronomical objects emit light over a broad range of wavelengths.

Astronomical objects such as stars, galaxies, and nebulae typically emit light across various wavelengths, including visible light, ultraviolet, infrared, X-rays, and gamma rays. This is due to the diverse physical processes occurring within these objects, such as nuclear fusion in stars or gas heating in nebulae.

Studying the emitted light in different wavelengths allows astronomers to gain valuable insights into the composition, temperature, and other properties of these celestial bodies. As a result, multi-wavelength observations are crucial in understanding the complexity and nature of astronomical objects.

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Answer:

100 newton

Explanation:

newton third law of motion says to every action there is an always an equal and opposite reaction so the magnitude will stay equal but opposite direction

Answer:

- 100N is the answer of this question

In the 1990s, astronomers observed distant type I supernovae and found that they were fainter than they expected based on their previous understanding of the universe.

This unexpected dimness led them to conclude that the expansion of the universe was accelerating, which in turn led to the discovery of dark energy, a mysterious force that is driving the universe's accelerated expansion.

This observation led astronomers to conclude that the universe's expansion is accelerating, not slowing down as previously thought. This acceleration is due to an unknown force, later termed "dark energy," which makes up about 68% of the universe's total energy content. The discovery of the accelerating universe was a groundbreaking result in cosmology and earned the 2011 Nobel Prize in Physics.

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One statement that is not true is that UV radiation is a type of electromagnetic radiation. It is also a type of ionizing radiation. UV radiation is actually a form of non-ionizing radiation.

UV radiation, or ultraviolet radiation, is a type of electromagnetic radiation that falls between visible light and X-rays on the electromagnetic spectrum. It is often categorized into three types: UVA, UVB, and UVC. Unlike ionizing radiation, such as X-rays and gamma rays, which have enough energy to remove tightly bound electrons from atoms or molecules, UV radiation lacks the necessary energy to ionize atoms or molecules. Instead, it primarily interacts with the outermost electrons of atoms or molecules, leading to chemical reactions and causing biological effects.

UV radiation is commonly associated with sunlight and has various effects on living organisms and materials. It can cause sunburn, premature aging of the skin, and an increased risk of skin cancer. Exposure to excessive UV radiation can also damage the eyes and impair the immune system. It is important to protect oneself from excessive UV exposure by wearing sunscreen, protective clothing, and sunglasses.

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Answer:

165.5

Explanation:

vrms × root 2= v max

Hence we get v maximum =165.5 V

Answer: The longer the lever, the greater the force on the load will be.

Explanation:

Answer:

40° (nice and warm)

Explanation:

40° is very cold (below freezing)

If the linear distance on the screen from the central fringe to the first bright fringe above it is 5.28 cm, 9.19m is the separation of the slits.

The double-slit experiment is a proof in modern physics that light and matter can exhibit properties of both classically defined waves and particles. It also shows that quantum mechanical phenomena are fundamentally probabilistic.

The formula to be used here is:

Linear distance (y) = nλL / d

where n = bright fringe

          L = distance of screen from slits

          λ = wavelength

          d = distance between slits

Plugging in the values we get,

0.0528 = 5.58×\(10^{-7}\) × 8.70 / d

0.0528 = 48.546×\(10^{-7}\) / d

d = 919.431818×\(10^{-7}\)

d = 9.19m

The complete question is; Light with a wavelength of 558 nm passes through two slits and forms an interference pattern on a screen 8.70 m away. If the linear distance on the screen from the central fringe to the first bright fringe above it is 5.28 cm, what is the separation of the slits

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The change in the kinetic energy of the calcium ion's is 6.4 x 10⁻¹⁶ J.

The change in the kinetic energy of the ion's which accelerated through the given potential difference is calculated as follows;

ΔK.E = qV

where;

Substitute the given parameters in the above equation and solve for change in kinetic energy.

ΔK.E = (2e)V

ΔK.E = (2 x 1.6 x 10⁻¹⁹) x (2.0 x 10³)

ΔK.E = 6.4 x 10⁻¹⁶ J

Thus, the change in the kinetic energy of the calcium ion's is 6.4 x 10⁻¹⁶ J.

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Answer:90+80+90=360

Explanation:10x+60–50

(a) 6, 8, 14, 17, 23, there is 1 comparison and 1 swap.

(b) 17, 23, 14, 6, 8, there are 3 comparisons and 2 swaps.

(c) 23, 17, 14, 8, 6, there are 3 comparisons and 2 swaps.

To simulate the function selection sort on the given arrays, let's go through each case as follows.

(a) For the array containing the elements 6, 8, 14, 17, 23: -

Starting with the first element, we compare it with the remaining elements in the array to find the smallest element. - We find that the smallest element is 6. So, we swap it with the first element.

Now, the array becomes 6, 8, 14, 17, 23. - Next, we move to the second element (8) and compare it with the remaining elements to find the smallest element. - We find that the smallest element is 8 itself. So, there is no need to swap.

Similarly, we move to the third, fourth, and fifth elements and compare them with the remaining elements to find the smallest element. However, no swaps are needed as the remaining elements are already in sorted order.

Therefore, in this case, there are a total of 1 comparison and 1 swap.

(b) For the array containing the elements 17, 23, 14, 6, 8:

Following the same steps as before, we compare the first element (17) with the remaining elements to find the smallest element. - We find that the smallest element is 6. So, we swap it with the first element.

Now, the array becomes 6, 23, 14, 17, 8. - Continuing with the second element (23), we find that the smallest element is 8. Hence, we swap it with the second element. - The array becomes 6, 8, 14, 17, 23. - Then, we move to the third element (14) and find that the smallest element is itself.

No swaps are needed. - We continue with the fourth and fifth elements, and no swaps are required. - In this case, there are a total of 3 comparisons and 2 swaps.

(c). For the array containing the elements 23, 17, 14, 8, 6: -

Again, starting with the first element (23), we compare it with the remaining elements to find the smallest element. - We find that the smallest element is 6. So, we swap it with the first element.

Now, the array becomes 6, 17, 14, 8, 23. Moving to the second element (17), we find that the smallest element is 8. Hence, we swap it with the second element. - The array becomes 6, 8, 14, 17, 23. - For the third, fourth, and fifth elements, no swaps are needed as they are already in sorted order.

Therefore, in this case, there are a total of 3 comparisons and 2 swaps.

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There are several locations on Earth where there are complex or uncertain plate boundaries:

The boundary between the Eurasian Plate and the African Plate: This boundary runs through the middle of the Red Sea and is marked by a divergent boundary (where the plates are moving away from each other).

The boundary between the North American Plate and the Pacific Plate: This boundary is marked by a transform boundary (where the plates are moving past each other) along the west coast of North America, including the San Andreas Fault in California.

The boundary between the Nazca Plate and the South American Plate: This boundary is marked by a subduction zone along the west coast of South America, including the Andes Mountains.

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