Riya has pens and pencils, which together are 40 in number. If she had 5 more pencils and 5 less pens, then the number of pencils would become four times the number of pens. Find the original number of pens and pencils.

We determine the cumulative weight retained at each sieve and then calculate the cumulative percentage passing by dividing the cumulative weight passing by the total weight of the sample and multiplying by 100.

To calculate the percentage passing for each sieve size in a sieve analysis, we need to determine the cumulative percentage passing at each sieve size.

The sieve analysis provides information about the particle size distribution of an aggregate sample. It involves passing the sample through a series of sieves with different mesh sizes, and measuring the amount of material retained on each sieve.

To calculate the percentage passing, we first need to determine the cumulative weight retained at each sieve size. This is done by subtracting the weight retained on a particular sieve from the weight retained on the previous sieve.

Once we have the cumulative weight retained, we can calculate the cumulative percentage passing by dividing the cumulative weight passing by the total weight of the sample and multiplying by 100.

Here is an example:

Sieve Size (mm) | Weight Retained (g)

4.75 | 50

2.36 | 30

1.18 | 20

0.6 | 15

0.3 | 10

0.15 | 5

To calculate the cumulative percentage passing:

Calculate the cumulative weight retained:

Cumulative weight retained at sieve 4.75 mm = 50 g

Cumulative weight retained at sieve 2.36 mm = 50 g + 30 g = 80 g

Cumulative weight retained at sieve 1.18 mm = 80 g + 20 g = 100 g

Cumulative weight retained at sieve 0.6 mm = 100 g + 15 g = 115 g

Cumulative weight retained at sieve 0.3 mm = 115 g + 10 g = 125 g

Cumulative weight retained at sieve 0.15 mm = 125 g + 5 g = 130 g

Calculate the cumulative percentage passing:

Cumulative percentage passing at sieve 4.75 mm = (Total weight - Cumulative weight retained) / Total weight * 100 = (130 g - 50 g) / 130 g * 100 = 61.54%

Cumulative percentage passing at sieve 2.36 mm = (130 g - 80 g) / 130 g * 100 = 38.46%

Cumulative percentage passing at sieve 1.18 mm = (130 g - 100 g) / 130 g * 100 = 23.08%

Cumulative percentage passing at sieve 0.6 mm = (130 g - 115 g) / 130 g * 100 = 11.54%

Cumulative percentage passing at sieve 0.3 mm = (130 g - 125 g) / 130 g * 100 = 3.85%

Cumulative percentage passing at sieve 0.15 mm = (130 g - 130 g) / 130 g * 100 = 0%

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There is a 42.3% chance that the Rangers will win a majority of their seven games against the Islanders, assuming their win percentage stays the same.

We can use the binomial distribution to calculate the probability of the Rangers winning a majority of their games against the Islanders, given their win percentage of 55.1%. Let's denote the probability of the Rangers winning a single game against the Islanders as p.

Since the Rangers and Islanders play seven games against each other, the number of games the Rangers win against the Islanders follows a binomial distribution with parameters n = 7 and p = 0.551.

To find the probability that the Rangers win a majority of these seven games, we need to sum the probabilities of all possible outcomes where they win four or more games. We can use the binomial probability formula to calculate each of these individual probabilities and then sum them up:

P(Rangers win 4 or more games) = P(Rangers win 4 games) + P(Rangers win 5 games) + P(Rangers win 6 games) + P(Rangers win 7 games)

\(= (7 choose 4) * 0.551^4 * (1 - 0.551)^3 + (7 choose 5) * 0.551 ^ 5 * (1 - 0.551)^2 + (7 choose 6) * 0.551^6 * (1 - 0.551) + (7 choose 7) * 0.551^7\)

Using a binomial calculator or a spreadsheet, we can evaluate this expression and find that:

P(Rangers win a majority of their games against the Islanders) = 0.423

Therefore, there is a 42.3% chance that the Rangers will win a majority of their seven games against the Islanders, assuming their win percentage stays the same.

The Binomial distribution is a discrete probability distribution that describes the probability of obtaining a certain number of successes in a fixed number of independent trials, where each trial can have only two outcomes (e.g., success or failure).

The distribution is defined by two parameters: the number of trials n and the probability of success in each trial p. The distribution gives the probability of obtaining k successes in n trials, where k can range from 0 to n.

The formula for the probability mass function of the Binomial distribution is:

\(P(k) = (n choose k) * p^k * (1 - p)^n-k\)

where (n choose k) is the binomial coefficient, which gives the number of ways to choose k items from a set of n items. The formula can be used to calculate the probability of obtaining k successes in n trials, given a fixed probability of success p.

The Binomial distribution is used in many areas of statistics, including quality control, epidemiology, and finance, among others. It is also a fundamental building block for more complex statistical models, such as the Poisson distribution and the normal distribution.

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Answer:

5 3 3 2 2

Step-by-step explanation:

180

90 2

45 2 2

15 3 2 2

5 3 3 2 2

Answer:

180 = 5 × 3² × 2²

Step-by-step explanation:

Starting with 180, the prime factors are in bold

180 = 90 × 2

      = 45 × 2 × 2

      = 15 × 3 × 2 × 2

      = 5 × 3 × 3 × 2 × 2

Then

180 = 5 × 3 × 3 × 2 × 2 = 5 × 3² × 2²

the answer is :

\(-4x-2\)

how to do it:

\(3x-7x-4+2\)

\(3x-7x-2\)

\(-4x-2\)

The degree sequence of a graph is the list of degrees of its vertices arranged in non-increasing order.

For a bipartite graph $K_{m,n}$ with $m$ vertices in the first partite set and $n$ vertices in the second partite set, every vertex in the first partite set is connected to all vertices in the second partite set and vice versa. Therefore, the degree of each vertex in the first partite set is $n$ and the degree of each vertex in the second partite set is $m$.

So, the degree sequence of the bipartite graph $K_{m,n}$ is $n,n,\ldots,n$ (repeated $m$ times) followed by $m,m,\ldots,m$ (repeated $n$ times). In other words, the degree sequence consists of two blocks, each of length $m+n$, where the first block contains the degree $n$ repeated $m$ times and the second block contains the degree $m$ repeated $n$ times.

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sir........you gucci?

Answer:

3.27

Step-by-step explanation:

Answer:

3/8 of the area is shaded

Step-by-step explanation:

this can be determined by deviding the total shape into parts and determining those parts

so we see the top right 1/4 of the shape has a square that is shaded, with the triangle only covering 1/2 of this shape becuase the hypotenuse ((diagnal edge of a right triangle)) devides the square in half

beings that 1/2 of the 1/4 square is shaded, we know that in reation to the whole shape that the small shaded area is equal to 1/8 ((1/2 ÷ 1/4 = 1/8))

same can be said for the bottum shape, with the bottum half of the whole shape half covered we can determine its total shaded area in relation to the shape ((1/2 ÷ 1/2 = 1/4))

the left top shape is completely unshaded so we wont need to calculate any shadded area into the equation

with the total shape covered by 1/4 + 1/8 we can find the least common denominator between the two fractions to get a simplifide answer for the total shaded area

1/4 = 2/8
2/8 + 1/8 = 3/8

this leaves 5/8 of the shape unshaded

3/8 fraction of the square is to be shaded.

A triangle is a three-sided polygon that consists of three edges and three vertices.

In the top right 1/4 of the shape has a square that is shaded, with the triangle only covering 1/2 of this shape because the hypotenuse divides the square in half.

1/2 of the 1/4 square is shaded, we know that in relation to the whole shape that the small shaded area is equal to 1/8.

same can be said for the bottom shape, with the bottom half of the whole shape half covered we can determine its total shaded area in relation to the shape.

1/4 = 2/8

2/8 + 1/8 = 3/8

Hence, 3/8 fraction of the square is to be shaded.

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Answer:

The steps are more or less the same, except for one new addition:

1. Divide the tens column dividend by the divisor.

2. Multiply the divisor by the quotient in the tens place column.

3. Subtract the product from the divisor.

4. Bring down the dividend in the one's column and repeat it.

Step-by-step explanation:

Step-by-step explanation:

Hi, it seems the question is not complete, therefore I'll create an example tailored to the concept of the question you are asking.

1. Cumulative property can be used to change the order of addends and the result remains the same. Therefore the law states that, if a and b are real numbers, then a + b = b + a

Think about adding two numbers, such as 7 and 2.

7 + 2 = 9

2 + 7 = 9

The results are the same.

Notice, the order in which we add does not matter.

2. Associative property, this can be used to regroup addends and the result remains the same: the law states that, if a, b and c are real numbers, then

(a + b) + c = a + (b + c).

Think about three numbers, 4, 3 and 2

(4 + 3) + 2 = 7 + 2 = 9

4 + (3 + 2) = 4 + 5 = 9

The results are the same, notice that the regrouping did not change the final result.

Answer:

Thank You This Helped Alot!

Answer:

35

Step-by-step explanation:

since ACD is a line so angle BCA+angle BCD=180

BCA+120=180

BCA=60

The total degrees of all interior angles of triangle is 180

So angle BAC+BCA+ABC=180,

BAC+60+85=180

BAC=35

The theoretical likelihood of selecting a heart is 1/16 times higher than the actual likelihood.

In the given question, we have to find the experimental probability of choosing a heart compare with the theoretical probability of choosing a heart.

We are aware that a deck's total number of cards= 52

Total number of hearts = 13

Then the theoretical probability of getting a heart = Number of cards have hearts/Total cards

Then the theoretical probability of getting a heart = 13/52

Then the theoretical probability of getting a heart = 1/4

Then the theoretical probability of getting a heart = 0.25

Cards chosen by Rochelle : Clubs 29, Spades 13, Hearts 15, Diamonds 23

Total cards  = 80

The experimental likelihood of experiencing a heart attack = Number of cards have hearts/Total cards

The experimental likelihood of experiencing a heart attack = 15/80

The experimental likelihood of experiencing a heart attack = 3/16

The experimental likelihood of experiencing a heart attack = 0.185

Since, 0.25 > 0.1875 so, Theoretical probability > Experimental probability

and,

Theoretical probability = 0.25-0.1875

Theoretical probability = 0.0625

Theoretical probability = 625/10000

Theoretical probability = 1/16

Hence, the theoretical likelihood of selecting a heart is 1/16 times higher than the actual likelihood.

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Answer:

100%= ?

287.50= 115%

1%= 287.50/115

1%= 2.5

100%= 250

therefore answer is $250

The amount on the dinner bill excluding the tip for the server would be $244.375.

In mathematics, a percentage is a number or ratio expressed as a fraction of 100.

Given is a group of friends who receives a dinner bill of $287.50 at a restaurant. The bill includes a 15% tip for the server.

The initial amount in the bill recieved = $287.5

Percentage tip for server = 15%

Amount recieved by the server = 15% of 287.5 = $43.12

Therefore, the amount before the tip = 287.5 - 43.12 = 244.375

Therefore, the amount on the dinner bill excluding the tip for the server would be $244.375.

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The inverse of the matrix M does not exist. To find the inverse of a matrix, we can use the formula: M^(-1) = 1/|M| * adj(M)

where |M| is the determinant of M and adj(M) is the adjoint of M. The adjoint of a matrix is the transpose of its cofactor matrix.

In this case, the determinant of M is 0. This means that M is not invertible and therefore M^(-1) does not exist.

Here is why the determinant of M is 0. The determinant of a 3x3 matrix can be computed using the following formula:

|M| = a11 * a22 * a33 + a12 * a23 * a31 + a13 * a21 * a32 - a13 * a22 * a31 - a12 * a21 * a33 - a11 * a23 * a32

where a11, a12, a13, a21, a22, a23, a31, a32, and a33 are the elements of the matrix M. In this case, the elements of M are 1, 12, 2, 210, 0, and 22. Substituting these values into the formula for the determinant, we get:

```

|M| = 1 * 22 * 22 + 12 * 0 * 2 - 2 * 12 * 21 = 0

```

Therefore, the determinant of M is 0 and M is not invertible.

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Answer:

-1

Step-by-step explanation:

-4(y-2)=12

-4y+8=12

-4y=4

y= -1

Answer:

a] 2pi/3

this is the answer

The increase in price of the book is $3.60. The percentage increase in price is calculated by dividing this increase by the original price and then multiplying by 100, which gives an 18% increase.

To calculate the

percentage increase

, you first need to find out how much the price has increased. In your situation, Miko sold the book to Elsa for $23.60 when the original price of the book was $20. The increase in price, therefore, is $23.60 - $20 = $3.60. Then, the percentage increase is calculated by dividing the increase in price ($3.60) by the original price ($20) and then multiplying the result by 100. So, the calculation will be ($3.60/$20) * 100 = 18%. Hence, the percentage increase in the price of the book is 18%.

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Answer:

Step-by-step explanation:

Answer:

M = 61

nm = 31

kn = 45

L = 119

Step-by-step explanation:

its a parallelogram so everything is obvious

(a) The rate of change of P with respect to time is dP/dt = k(P^(1/3))^4.

(b) The solution of differential equation is P = (1/(1/3000 - t/9000000))^3.

(c) Whether or not this population size is cause for concern depends on various factors, such as the size of the swarm relative to the available resources in the surrounding environment etc.

(a) Let P(t) be the population of the swarm at time t. The rate of change of P with respect to time is proportional to the fourth power of the cubic root of its current population. Therefore, we have:

dP/dt = k(P^(1/3))^4

where k is a positive constant of proportionality.

(b) To solve the differential equation, we can use separation of variables:

dP/(P^(1/3))^4 = k dt

Integrating both sides, we get:

-3(P^(1/3))^(-3) / 3 = kt + C

where C is the constant of integration.

Using the initial condition that P(0) = 1000, we have:

-3(1000^(1/3))^(-3) / 3 = C

C = -1/3000

Substituting this value of C back into the equation, we get:

(P^(1/3))^(-3) = 1/3000 - kt/3

Raising both sides to the power of 3, we get:

P = (1/(1/3000 - kt/3))^3

Using the additional information that P(3) = 8000, we can solve for k:

8000 = (1/(1/3000 - 3k))^3

1/8000 = (1/3000 - 3k)

k = (1/9000000)

Substituting this value of k back into the equation, we get:

P = (1/(1/3000 - t/9000000))^3

(c) To determine if the concerns of the people of the nearby town are justified, we need to calculate the population of the swarm at t = 6 and compare it to some threshold value. Using the formula we derived in part (b), we have:

P(6) = (1/(1/3000 - 6/9000000))^3

P(6) ≈ 513,800

Whether or not this population size is cause for concern depends on various factors, such as the size of the swarm relative to the available resources in the surrounding environment and the potential impact on the local ecosystem.

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The term that describes a group of statements that executes as a single unit is a "block". A block of code is a program that is grouped together and treated as a single unit. So, the correct option is D.

In computer programming, a block is a group of statements or declarations that are enclosed within a set of curly braces ({ }). The block serves as a single unit that is executed together. Blocks are used to organize code and to apply control structures, such as loops and conditional statements, to multiple statements.

A block can contain any number of statements, which can include variable declarations, function calls, loops, conditional statements, and other constructs. The statements within a block are executed in sequence, one after another, unless a control statement is encountered that alters the normal sequence of execution.

For example, a while loop in Java consists of a block of code that is executed repeatedly while a certain condition is true:

while (condition) {

   // block of code to be executed while condition is true

}

In this example, the block of code inside the curly braces will be executed repeatedly while the condition specified in the while statement is true. The block can contain any number of statements, and these statements will be executed each time the loop iterates.

Another common use of blocks is to define functions or methods. A function or method is a block of code that can be called from other parts of the program, and can take inputs (arguments) and return outputs. For example, in Python, a function can be defined as follows:

def function(argument1, argument2):

   # block of code to be executed in the function

   return result

In this example, the block of code enclosed within the function definition is executed when the function is called. The function can take inputs (argument1 and argument2), which can be used within the function, and it can return a result using the return statement.

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Answer:

constant term = 6

Step-by-step explanation:

if you multiply the constant terms within each factor together you get the constant term of the expansion of p(x) , that is

constant term = 3 × 2 × 1 = 6

\(~~~~~~ \stackrel{\textit{\Large Anna}}{\textit{Simple Interest Earned Amount}} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$100\\ r=rate\to 4.5\%\to \frac{4.5}{100}\dotfill &0.045\\ t=years\dotfill &3 \end{cases} \\\\\\ A=100[1+(0.045)(3)]\implies A=100(1.135)\implies A=113.5 \\\\[-0.35em] ~\dotfill\)

\(~~~~~~ \stackrel{\textit{\Large Matt}}{\textit{Simple Interest Earned Amount}} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$100\\ r=rate\to 3\%\to \frac{3}{100}\dotfill &0.03\\ t=years\dotfill &3 \end{cases} \\\\\\ A=100[1+(0.03)(3)]\implies A=100(1.09)\implies A=109 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{Anna}{113.5} - \stackrel{Matt}{109}\implies 4.5\)

The range of the function f(x) = log5x is (-∞, +∞).The function f(x) = log5x represents the logarithm base 5 of x. To determine the range of this function, we need to consider the possible values that the logarithm can take.

The range of the logarithm function y = log5x consists of all real numbers. The logarithm function is defined for positive real numbers, and as x approaches 0 from the positive side, the logarithm approaches negative infinity. As x increases, the logarithm function approaches positive infinity.

The range of the function is the set of all possible output values. In this case, the range consists of all real numbers that can be obtained by evaluating the logarithm

log5(�)log 5 (x) for �>0 x>0.

Since the base of the logarithm is 5, the function log5x will take on all real values from negative infinity to positive infinity. Therefore, the range of the function f(x) = log5x is (-∞, +∞).

In other words, the function can output any real number, ranging from negative infinity to positive infinity. It does not have any restrictions on the possible values of its output.

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Answer: All real numbers

Step-by-step explanation:

Edge

Answer:

16

Step-by-step explanation:

Here,

a=4

d= t1 - t2

=6-4

=2

tn = a +(n-1)d

t7 = 4+ (7-1)2

= 4+ 6×2

= 4 + 12

= 16

Answer: Pretty sure the answer is C

Step-by-step explanation:

Answer:

kunjal brother answer is correct hope it's help you have a good day ☺☺ keep smiling be happy stay safe ☺☺

I think it is -5................

Line passing through AB is perpendicular. A pair of angles that are linear have an angle sum of 180 degrees. The lines are therefore shown to be perpendicular to one another because the angles are 90 degrees in size.

Two lines intersect to generate perpendicular lines, and the angle formed between the two lines must be 90 degrees (right angle).

Given,

Create another line perpendicular to AB passing through C on AB..

Line passing through AB is perpendicular.

Two lines are perpendicular if they cross at a point where a pair of linear congruent angles results. In a plane, a transversal is perpendicular to the other line if it is parallel to one of the two parallel lines.

A pair of angles that are linear have an angle sum of 180 degrees. The lines are therefore shown to be perpendicular to one another because the angles are 90 degrees in size. The linear pair perpendicular theorem is demonstrated by this.

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