A po pa brainliest
a vertical asymptote is a vertical line that the graph of the function approaches as x tends to positive or negative infinity. b. a vertical asymptote is a vertical line x
A vertical asymptote basically means of a graph on a vertical line x = a where the graph tends toward positive or negative infinity as the inputs approach a.
In a graph a vertical asymptote is a vertical line x = a where the graph tends toward positive or negative infinity as the inputs approach a. And similarly the horizontal asymptote in a graph is a horizontal line y = b where the graph approaches the line as the inputs approach ∞ or –∞.
At x = a in a graph where a is a zero for a factor in the denominator the removable discontinuity occur that is common with a factor in the numerator.
Factor the numerator and denominator.
It is set it equal to zero and solve if any factors are common to both the numerator and denominator.
This is removable discontinuity type location.
In mathematics a graph is defined as a diagrametical or a pictorial representation that helps to represents data or values in an organized manner. The points that are shown on the graph are use to mark of represent the various value or relation between two value .
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The time in minutes for each of Sam's phone calls this week are shown in the list. {9, 15, 5, 7, 9, 12, 11, 4} Which statement is true regarding the duration of his calls? A. The median is greater than 10. B. The mean is less than 8. C. The range is less than 10. D. The mode is greater than 7.
Answer: The mode is greater than 7.
Step-by-step explanation:
The time in minutes are given as 9, 15, 5, 7, 9, 12, 11, 4. We can arrange them in ascending order and this will be:
= 4, 5, 7, 9, 9, 11, 12, 15
Mean = (4 + 5 + 7 + 9 + 9 + 11 + 12 + 15) / 8 = 9
Median = 9+9/2 = 18/2 = 9
Mode = 9
Range = 15 - 4 = 11
Therefore, the true statement are:
D. The mode is greater than 7.
approximately what percentage of values in your data set is above the third quartile? group of answer choices 25% 75% 100% 0% 50%
Approximately 25% of the values in the dataset are above the third quartile.
The third quartile, also known as the upper quartile, is the value below which 75% of the data lies. Therefore, if approximately 25% of the values are above the third quartile, it implies that the remaining 75% of the values are below or equal to the third quartile.
To calculate the third quartile, we need to sort the dataset in ascending order and find the median of the upper half. Once we have the third quartile value, we can determine the percentage of values above it by counting the number of values in the dataset that are greater than the third quartile and dividing it by the total number of values.
For example, if we have a dataset with 100 values, we would find the third quartile, let's say it is 80. Then we count the number of values greater than 80, let's say there are 20. So the percentage of values above the third quartile would be (20/100) * 100 = 20%.
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Helppp pleaseee!!!!!!!
Answer:
1234567891011121314151617181920
Step-by-step explanation:
Rashid can do a piece of work in 8 days, which Tipu can finish in 12 days. If they work on alternate days with Rashid Beginning, in how many days, the work will be finished?
Answer: 9.6 days
Step-by-step explanation:
Rashid can do a piece of work in 8 days. Rashid work rate will then be:
= 1/8 owe day.
Tipu can finish in 12 days. Tipu's work rate will be: = 1/12 owe day.
Their work rate together will then be:
= 1/8 + 1/12
= 3/24 + 2/24
= 5/24
From the calculation, together they will finish the work in:
= 1 ÷ 5/24
= 1 × 24/5
= 24/5 days
= 4.8 days
Busy since they are working on alternate days, then this will be multiplied by 2 which will be:
= 4.8 × 2
= 9.6 days
Do the following using the given information: Utility function u(x1+x2) = .5ln(x1) + .25ln(x₂) .251 Marshallian demand X1 = - and x₂ = P₂ . Find the indirect utility function . Find the minimum expenditure function . Find the Hicksian demand function wwww
Hicksian demand functions are:x1** = 2P₁x₂ ; x₂** = P₂²
Utility function: u(x1+x2) = .5ln(x1) + .25ln(x₂) .The Marshallian demand functions are: x1* = - and x₂* = P₂.
The indirect utility function is found by substituting Marshallian demand functions into the utility function and solving for v(P₁, P₂, Y).u(x1*,x2*) = v(P₁,P₂,Y) ⇒ u(-, P₂) = v(P₁,P₂,Y) ⇒ .5ln(-) + .25ln(P₂) = v(P₁,P₂,Y) ⇒ v(P₁,P₂,Y) = - ∞ (as ln(-) is not defined)
Thus the indirect utility function is undefined.
Minimum expenditure function can be derived from the Marshallian demand function and prices of goods:
Exp = P₁x1* + P₂x2* = P₁(-) + P₂P₂ = -P₁ + P₂²
Minimum expenditure function is thus:
Exp = P₁(-) + P₂²
Hicksian demand functions can be derived from the utility function and prices of goods:
H1(x1, P1, P2, U) = x1*H2(x2, P1, P2, U) = x2*
Hicksian demand functions are:
x1** = 2P₁x₂
x₂** = P₂²
If there are no restrictions on the amount of money the consumer can spend, the Hicksian demand functions for x1 and x2 coincide with Marshallian demand functions.
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Construct a polynomial function with the following properties. Third-degree, with zeros of -3,-2, and 4, and a y-intercept of -6
The constructed polynomial function is f(x) = (1/4)(x + 3)(x + 2)(x - 4), where the zeros are -3, -2, and 4, and the y-intercept is -6.
To construct a polynomial function with the given properties, we can start by considering the zeros and the y-intercept.
The zeros of the polynomial function are -3, -2, and 4. This means that when the input to the function is -3, -2, or 4, the function evaluates to zero. We can represent these zeros as factors in the polynomial function. Therefore, the factors of the polynomial will be (x + 3), (x + 2), and (x - 4).
Next, we know that the polynomial is a third-degree function, which means it will have a leading term with x raised to the power of 3.
Putting it all together, the polynomial function can be written as:
f(x) = a(x + 3)(x + 2)(x - 4)
To determine the value of "a," we can use the y-intercept. The y-intercept is the point where the function crosses the y-axis, and it occurs when x = 0. Given that the y-intercept is -6, we can substitute these values into the function:
-6 = a(0 + 3)(0 + 2)(0 - 4)
Simplifying, we have:
-6 = a(3)(2)(-4)
-6 = -24a
Dividing both sides by -24, we find:
a = 1/4
Substituting this value of "a" back into the polynomial function, we have:
f(x) = (1/4)(x + 3)(x + 2)(x - 4)
Thus, the polynomial function that satisfies the given properties is:
f(x) = (1/4)(x + 3)(x + 2)(x - 4)
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A tower is braced by a 40 ft. wire that is attached to the ground 8 feet from the base of the tower. How
tall is the tower?
Answer: ≈39 ft
Step-by-step explanation: Pythagorean theorem= √40^2-8^2 ≈39.19!
A stack of magazines is 4 2/5 inches high. Each magazine is 2/5 inch thick.
How many magazines are in the stack?
Answer:
Equation:(4 2/5)/2/5=? ; estimate: a
little more than 10 magazines; answer:
11 magazines in the stack.
Step-by-step explanation:
Leroy work selling electronics. He earns 8% commission. If Leroy sells to 3000 in electronics how much is his commission?
Answer:
240
Step-by-step explanation:
Leroy works by selling electronics
He earns 8% commission
He sells 3000 in electronics
Therefore the commission can be calculated as follows
= 3000× 8/100
= 3000×0.08
=
Hence the commission is 240
A popcorn container is the shape of an inverted cone. it is 9 inches tall, and the circular opening has a diameter of 4 inches. which equation can be used to find the volume of the container? v = one-third pi (2) squared (9) v = one-third pi (4) squared (9) v = one-third pi (4) (9) squared v = one-third pi (2) (9) squared
The expression that determines the volume of the container is \(V = \frac 13 * \pi * 2^2 * 9\)
How to determine the volume expression?The given parameters are:
Shape = ConeHeight, h = 9 inDiameter, d = 4 inThe volume of the cone is calculated using:
\(V = \frac 13 * \pi (d/2)^2h\)
So, we have:
\(V = \frac 13 * \pi (4/2)^2 * 9\)
This gives
\(V = \frac 13 * \pi * 2^2 * 9\)
Hence, the expression that determines the volume of the container is \(V = \frac 13 * \pi * 2^2 * 9\)
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Answer:
v = 1/3 pi (2) to the power of 2 (9)
Step-by-step explanation:
Person above is right, I'm taking the test now! <3
solve this equation
4f+2=6f-12
Let's try to understand how we can solve this equation
Given equation,4f+2=6f-12
Now we will take the terms on one side and constants on the other.
=> 2+12=6f-4f
=> 14=2f
=>7=f
So, the value of f would be 7. Remember that while bringing value to another side, the sign of that value changes. If it is a positive sign then it is going to be transformed into a negative one and vice versa.
4. A pizza shop has 12" pizzas with 6 slices and 16" pizzas with slices. Which pizza has bigger slices?
need help solving these please!
Answer:
kidding meee
Step-by-step explanation:
Doood you are kiding me
Helpp real quick GIVING CROWNN!!
Answer:
2g+60>92
Step-by-step explanation:
Find the area of the region that lies above the x-axis, below the curve x=t^2+4t+8,y=e^−t with 0≤t≤1. Give your answer exactly or round to four decimal places.
The area bounded region that above the x-axis, below the curve x(t) = t² + 4t + 8, \( y = e^{−t}\) with interval 0≤t≤1, is equals to the -6.27453.
The area between two curves is defined as the area that bounded in between two curves and can be calculated using integral calculus. We have two curves with the following equation, x(t) = t² + 4t + 8, \( y = e^{−t}\) with interval, 0≤ t ≤1. We will determine the area of the region that lies inbetween x-axis and curves. The formula for area under the curves is written as below, \(A = \int_{0}^{1} x(t)y'(t) dt \)
Substitute the known values in above formula, \(= \int_{0}^{1} ( t² + 4t + 8) ( - e^{-t}) dt \).
Now, integration by letting \(e^{-t}\)
as first function and (t² + 4t + 8) as second function, \(= [( t² + 4t + 8) e^{-t}]_{0}^{1} - \int_{0}^{1} (2t + 4) e^{-t} \\ \)
\(= [( 1 + 4×1 + 8) e^{-1} - ( 8e^{0})] + [ (2t + 4) e^{-t}]_{0}^{1} - \int_{0}^{1} 2 e^{-t}] \\ \)
\(= [13e^{-1} - 8] + [ (2×1 + 4) e^{-1} - 4]- \int_{0}^{1} 2 e^{-t}] \\ \)
\(= 13e^{-1} - 8 + 6e^{-1} - 4 + 2 e^{-1} - 2 \\ \)
\(= 21e^{-1} - 14 \)
= - 6.27453
Hence, required value is - 6.27453.
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factoring a quadratic in two variables with leading coefficient 1
Factoring a quadratic in two variables with a leading coefficient of 1 involves finding two binomial factors that, when multiplied, produce the quadratic expression. The factors can be determined by identifying the common factors of the quadratic terms and arranging them appropriately.
To factor a quadratic expression in two variables with a leading coefficient of 1, we need to look for common factors among the terms. The goal is to rewrite the quadratic expression as a product of two binomial factors. For example, if we have the quadratic expression x^2 + 5xy + 6y^2, we can factor it as (x + 2y)(x + 3y) by identifying the common factors and arranging them in the binomial factors.
The process of factoring a quadratic in two variables may involve trial and error, testing different combinations of factors to find the correct factorization. Additionally, factoring methods such as grouping or using the quadratic formula can also be applied depending on the specific quadratic expression.
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Answer this midpoint
A. Q
B. R
C. S
D. T
The midpoint of the line segment XY is S
Calculating MidpointThe midpoint refers to the center or middle position of a line. To obtain the midpoint here, we take the sum of the distances and divide by 2 .
XP = 2
PQ = 3
QR = 4
RS = 3
ST = 6
TY = 6
Sum of the points :
2+3+4+3+6+6 = 24
The midpoint = 24/2 = 12
The point where 12 lies on the segment is the point S
Hence, the midpoint is S
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CAN SOMONE PLZ HELP ME ON THS
Answer:
Step-by-step explanation:
Help please i dont understand this !
Answer:
see explanation
Step-by-step explanation:
You are going to plug in the x values to the equation.
f(-4)=-2(-4)-3 -> f(-4)=8-3 -> f(-4)=5
f(-2)=-2(-2)-3 -> f(-2)=4-3 -> f(-2)=1
f(2)=-2(2)-3 -> f(2)=-2-3 -> f(2)=-5
Then you are going to graph. Plot the points on the table (remember rise over run) and connect them with a straight line.
Answer:
\(\boxed{(x)}\boxed{f(x)} \\ \boxed{ - 4}\boxed{ + 5}\\ \boxed{ - 3}\boxed{ + 4}\\ \boxed{ - 2}\boxed{ + 1}\\ \boxed{ - 1}\boxed{ +0}\\ \boxed{ + 0}\boxed{ - 2}\\ \boxed{ + 1}\boxed{ - 4}\\ \boxed{ + 2}\boxed{ - 7}\)
Step-by-step explanation:
\(f(x) \: is \: same \: as \: y \to \\ i.e \: y \: is \: a \: function \: of \: x. \\ so \: .....come \: to \: think \: of \: it.... \to \\ if \: y = \: f (x) = - 2x - 3. \\ then \: if \: x = - 4 \\ what \: would \: y \: (i.e \: f(x))\: be : \: ?....... \\ lets \: use \: this \: method \: to \: solve \: the \: above \: questions \\ \\ \boxed{(x)}\boxed{f(x)} \\ \boxed{ - 4}\boxed{ + 5}\\ \boxed{ - 3}\boxed{ + 4}\\ \boxed{ - 2}\boxed{ + 1}\\ \boxed{ - 1}\boxed{ +0}\\ \boxed{ + 0}\boxed{ - 2}\\ \boxed{ + 1}\boxed{ - 4}\\ \boxed{ + 2}\boxed{ - 7} \\ .............................................................. \\ i \: think \: that \: the \: above \: value s\: are \: the \: \\ only \: possible \: answers.\)
♨Rage♨
Find the FACTORS FOR: 6.25
Answer: Factors are used with whole numbers, not decimals.
when the base-$b$ number $11011 b$ is multiplied by $b-1$, then $1001 b$ is added, what is the result (written in base $b$)?
we express the result in base $b$: $b^5 - 2b^4 + 3b^3 - 2b^2 + 2b^1 + b^0$ (written in base $b$)
To find the result when the base-$b$ number $11011_b$ is multiplied by $b-1$ and then $1001_b$ is added, we can follow these steps:
Step 1: Multiply $11011_b$ by $b-1$.
Step 2: Add $1001_b$ to the result from step 1.
Step 3: Express the final result in base $b$.
To perform the multiplication, we can expand $11011_b$ as $1 \cdot b^4 + 1 \cdot b^3 + 0 \cdot b^2 + 1 \cdot b^1 + 1 \cdot b^0$.
Now, we can distribute $b-1$ to each term:
$(1 \cdot b^4 + 1 \cdot b^3 + 0 \cdot b^2 + 1 \cdot b^1 + 1 \cdot b^0) \cdot (b-1)$
Expanding this expression, we get:
$(b^4 - b^3 + b^2 - b^1 + b^0) \cdot (b-1)$
Simplifying further, we get:
$b^5 - b^4 + b^3 - b^2 + b^1 - b^4 + b^3 - b^2 + b^1 - b^0$
Combining like terms, we have:
$b^5 - 2b^4 + 2b^3 - 2b^2 + 2b^1 - b^0$
Now, we can add $1001_b$ to this result:
$(b^5 - 2b^4 + 2b^3 - 2b^2 + 2b^1 - b^0) + (1 \cdot b^3 + 0 \cdot b^2 + 0 \cdot b^1 + 1 \cdot b^0)$
Simplifying further, we get:
$b^5 - 2b^4 + 3b^3 - 2b^2 + 2b^1 + b^0$
Finally, we express the result in base $b$:
$b^5 - 2b^4 + 3b^3 - 2b^2 + 2b^1 + b^0$ (written in base $b$)
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Find an equation for the plane containing the two (parallel) lines
v1 = (0, 1, −8) + t(6, 7, −5) and v2 = (8, −1, 0) + t(6, 7, −5).
The equation of the plane containing the two parallel lines v₁ = (0, 1, −8) t(6, 7, −5) and v₂ = (8, −1, 0) t(6, 7, −5) is 6x + 6y + 3z = 0.
What are parallel lines?
Parallel lines are coplanar infinite straight lines that do not intersect at any point in geometry. Parallel planes are planes that never meet in the same three-dimensional space. Parallel curves are those that do not touch or intersect and maintain a constant minimum distance.
To find an equation for the plane containing the two parallel lines v₁ = (0, 1, −8) t(6, 7, −5) and v₂ = (8, −1, 0) t(6, 7, −5),
We use the equation of a line: v = v₀ + tv₁
where v₀ and v₁ are points on the line and t is a real number.
Substitute the given points in for v₀ and v₁: v = (0, 1, −8) + t(6, 7, −5)
This equation of the plane is Ax + By + Cz = D, where A, B, C, and D are constants to be determined.
Equate the components:
0x + 1y - 8z = D....(1)
6x + 7y - 5z = D...(2)
Now, we subtract equation (1) from (2) and we get
6x - 0x + 7y - 1y - 5z + 8z = 0
6x + 6y + 3z = 0
Hence, the equation of the plane containing the two parallel lines v₁ = (0, 1, −8) t(6, 7, −5) and v₂ = (8, −1, 0) t(6, 7, −5) is 6x + 6y + 3z = 0.
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Simplify this expression.
20.25 – 9 + 11
о
1
4
0 18.75
0
21?
0 40.75
Answer:
\(21\frac{3}{4}\)
Step-by-step explanation:
Step 1: Add the numbers.
20.25 can also be expressed as \(20\frac{1}{4}\), because \(\frac{2025}{100}\) = \(\frac{81}{4}\) = \(20\frac{1}{4}\). So if we add \(20\frac{1}{4}\) and 11, we would get \(31\frac{1}{4}\)
Step 2: Solve
\(31\frac{1}{4} -9\frac{1}{2}\)
Subtract the whole numbers\(31-9=21\)
Combine the fractionsThis means addition. Also, since our denominators are not the same value, we have to find the LCM (Least Common Denominator): What do 2 and 4 have in common that they can divide themselves by? 4. We know this because 2 divided by 4 is 2, and 4 divided by 4 is 1, so they can both divide themselves by 4.
\(\frac{5}{4}-\frac{1}{2}\)
LCM
\(\frac{5}{4}-\frac{2}{4} =\frac{3}{4}\)
Therefore, the simplified expression to this is \(21\frac{3}{4}\).
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4 = 3а - 14 how do you get the problem set up
Answer:
Step-by-step explanation: 4=3a-14 then you add 14 to both sides and to isolate 3a should it look like this 18=3a then you divide 3 and to isolate "a" and you should 6=a
hope this helped :D
Answer:
a = 6
Step-by-step explanation:
Switch the sides
\(4=3a-14\\= 3a-14=4\)
Group(right side)
\(3a-14=4\\3a-14+14=4+14\)
Simplify arithmetic
\(3a=4+14\\3a=18\)
Isolate "a"
\(3a=18\\\frac{3a}{3}=\frac{18}{3}\)
Simplify this improper fraction by splitting it into its least common multiples
\(a=\frac{6 \times 3}{1 \times 3}\)
Factor(Cancel GCF)
\(a = 6\)
Concerns, let me know, otherwise, have a great day!
What are the parts of this expression: 5 x (m – 2)
Answer:
5m - 10. Easy
Step-by-step explanation:
5m - 10
-15, ___, ___, ___, -240 find the geometric means of each sequence
The geometric mean of the sequence -15, ___, ___, ___, -240 is 30.
To find the geometric mean of a sequence, we need to find the nth root of the product of all the terms in the sequence, where n is the number of terms in the sequence. In this case, the sequence has five terms.
Let's label the missing terms as x, y, and z. The sequence becomes -15, x, y, z, -240.
The geometric mean formula is given by:
Geometric mean = (product of terms)^(1/n)
To find the missing terms, we can set up the equation as follows:
(-15) * x * y * z * (-240) = 30^5
Simplifying the equation, we have:
3600xyz = 30^5
Dividing both sides by 3600, we get:
xyz = (30^5) / 3600
Taking the fifth root of both sides, we have:
(xyz)^(1/5) = (30^5 / 3600)^(1/5)
Simplifying further, we get:
(xyz)^(1/5) = 30 / 6
Therefore, the geometric mean of the sequence -15, ___, ___, ___, -240 is 30.
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Which of the following criteria are used when deciding upon the
inclusion of a variable? Check all that apply.
Group of answer choices
A-Theory
B-t-statistic
C-Bias
D-Adjusted R^2
the criteria used when deciding upon the inclusion of a variable are A - Theory, B - t-statistic, C - Bias, and D - Adjusted R^2.
When deciding upon the inclusion of a variable, the following criteria are commonly used:
A - Theory: Theoretical justification is often considered to include a variable in a model. It involves assessing whether the variable is relevant and aligns with the underlying theory or conceptual framework.
B - t-statistic: The t-statistic is used to determine the statistical significance of a variable. A variable with a significant t-statistic suggests that it has a meaningful relationship with the dependent variable and may be included in the model.
C - Bias: Bias refers to the presence of systematic errors in the estimation of model parameters. It is important to consider the potential bias introduced by including or excluding a variable and assess whether it aligns with the research objectives.
D - Adjusted R^2: Adjusted R^2 is a measure of the goodness of fit of a regression model. It considers the trade-off between the number of variables included and the overall fit of the model. Adjusted R^2 helps in assessing whether the inclusion of a variable improves the model's explanatory power.
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√ 32 +√ 48/√ 8 +√ 12
Answer:
Please refer to the photo
I don't know which one you want
l= prt is an example of.
Answer:
intrest=principle*rate* time
Step-by-step explanation:
Base formula, written as I = Prt or I = P × r × t where rate r and time t should be in the same time units such as months or years. Time conversions that are based on day count of 365 days/year have 30.4167 days/month and 91.2501 days/quarter.