Samir works at a carpet warehouse and is paid a 4% commission on his sales. In November, he sold $9455 of carpet. To the nearest dollar, how much did Samir earn in commission for November?

Answer:

\(a ^{2} \)

a^4 + a^2 + 1

a^4 + a^2 + x + 1

a^2 ( a^2 + 1) + 1 ( x + 1)

so, here clearly we can see that If wee add a^2 in place of x it would be a perfect square..

Hope it helpz~

Answer:

-7x^2-3x

Step-by-step explanation:

-x * 7x + (-x) * 3

-7xx-3x

-7x^2-3x

Thus, to determine whether Intel's stock and Southwest Airlines' stock have similar rates of return, we can use a statistical analysis of the daily rate of return for each stock over a 50-day period. However, the small sample size means that we must be cautious when interpreting the results.

To determine whether Intel's stock and Southwest Airlines' stock have similar rates of return, we can conduct a statistical analysis using the sample data collected. The sample size of 50 days is relatively small, so we must be cautious when interpreting the results.

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A and B are mutually exclusive, with P(A) is 0.7 and P(B) is 0.2, the probability of event B given event A (P(B|A)) and the probability of event B given event A (P(BIA)) are both 0.2.

To find the probability of B given A, we can use the formula:

P(B|A) = P(A and B) / P(A)

Given:

P(A) = 0.5

P(B) = 0.1

P(A and B) = 0.3

P(B|A) = 0.3 / 0.5

= 0.6

Therefore, the probability that B will occur if A occurs is 0.6.

Given:

P(A) = 0.3

P(B) = 0.4

Since A happening guarantees that B must also happen, the events A and B are not independent. In this case, we can use the formula:

P(A or B) = P(A) + P(B) - P(A and B)

P(A or B) = 0.3 + 0.4 - 0.3

= 0.4

Therefore, the probability of A or B occurring is 0.4.

Given:

P(A) = 0.7

P(B) = 0.2

Since A and B are mutually exclusive events, they cannot occur together. In this case, we have:

P(A and B) = 0

Therefore, P(B|A) = P(BIA)

= 0.

P(BIA) = P(B)

= 0.2.

So, P(BIA) < P(B) is true.

When events A and B are mutually exclusive, with P(A) = 0.7 and P(B)

= 0.2, the probability of event B given event A (P(B|A)) and the probability of event B given event A (P(BIA)) are both 0.2.

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The point where the curve has a vertical tangent line is (-1, -3).Hence, the required points are(-1/16, -1/8) for horizontal tangent and(-1, -3) for vertical tangent.

The curve is x(t) = t² + 2t, y(t) = 4t² + t. We are required to find the points where the curve has(a) horizontal tangent lines, and(b) vertical tangent lines.

(a) Horizontal Tangent Lines:The slope of the curve dy/dx is given as:dy/dx = (dy/dt) / (dx/dt)On simplifying the given expressions: dy/dx = (8t+1)/(2t+2) For the horizontal tangent line, the slope of the curve should be zero. Therefore,8t + 1 = 0 => t = -1/8.Now, substituting this value of 't' in the expression for x(t) and y(t):x(-1/8) = (-1/8)² + 2(-1/8) = -1/16y(-1/8) = 4(-1/8)² - 1/8 = -1/8Therefore, the point where the curve has a horizontal tangent line is (-1/16, -1/8).

(b) Vertical Tangent Lines: The slope of the curve dx/dy is given as: dx/dy = (dx/dt) / (dy/dt)On simplifying the given expressions: dx/dy = (2t+2)/(8t+1)For the vertical tangent line, the slope of the curve should be infinite. Therefore,2t + 2 = 0 => t = -1.Now, substituting this value of 't' in the expression for x(t) and y(t):x(-1) = (-1)² + 2(-1) = -1y(-1) = 4(-1)² - 1 = -3Therefore, the point where the curve has a vertical tangent line is (-1, -3).Hence, the required points are(-1/16, -1/8) for horizontal tangent and(-1, -3) for vertical tangent.

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Step-by-step explanation:

it's simple:

The  total distance it flies, rounded to the nearest mile is: d. 1,692 miles .

First distance= 550 miles (given)

Second distance=483 miles (given)

Now let find the third distance

Let x represent the third distance

Hence:

x/sin79 = 550/sin55

x= 659.1

Now let calculate the total distance

Total distance=550+483+659.1

Total distance= 1692.1

Total distance= 1692 miles (rounded)

Therefore the correct option is d.

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Step-by-step explanation:

you multiplie elements in order

first you multiple 2v by 4,than 2v by -v,than -q by 4 and finally -q by -v

it will be 8v+2v^2-4q+qv

Answer:

I do not know what this is

The derivative of the given function is x²eˣ + 7eˣ.

To solve this question, we use the Product Rule and the Chain Rule from the principles of Differentiation.

According to the Product Rule,

(d/dₓ)[AB] = [A' * B] + [A*B' ]

which is read as "the derivative of the product AB is equal to the sum of the products of 'derivative of A' and B, and vice versa.

According to the Chain Rule,

(d/dₓ)Xⁿ = n* (Xⁿ⁻¹)

Now, we attempt to solve the given question term-wise.

T₁ = (d/dₓ) { x²eˣ }

   = [(x²)' * eˣ] + [x² * (eˣ)']

   = 2x*eˣ + x²eˣ

T₂ = (d/dₓ) { 2x *eˣ }

    = 2*{ [(x)' * eˣ] + [x * (eˣ)'] }

    = 2eˣ + 2x*eˣ

T₃ = (d/dₓ) { 9eˣ }

    = 9eˣ

The derivative we require is just the sum/difference of derivatives of the three terms, which we calculated as T₁, T₂, and T₃.

Therefore,

The derivative is T₁ - T₂ + T₃

= 2x*eˣ + x²eˣ - (2eˣ + 2x*eˣ) + 9eˣ

= x²eˣ + 7eˣ

So, the derivative of the function is x²eˣ + 7eˣ.

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Answer:

6

Step-by-step explanation:

Put the numbers in order and find the number in the middle

2,4,6,10,15  The number in the middle is 6.

Helping in the name of Jesus.

Answer: 6

Step-by-step explanation:

the median is the middle number to put it in an easy explanation. Since there are 5 numbers the 3rd one would be the middle one since there would be 2 numbers of the left and 2 number on the right!!!

sorry I forgot to put them in order so

2,4,6,10,15

out of those 6 is the one in the middle

The area of the triangle formed by the line with a slope of 2 and the coordinate axes, given that the distance between the origin and the line is 5, is 25 square units.

To find the area of the triangle, we first need to determine the base and height of the triangle. The base of the triangle is the distance between the two points where the line intersects the x-axis. Since the line passes through the origin (0,0), one of the intersection points is (0,0). The other point can be found by setting the y-coordinate equal to zero and solving for the x-coordinate. In this case, the second point is (5/2, 0).

The height of the triangle is the distance between the origin and the point on the line that is perpendicular to the x-axis. Since the line has a slope of 2, the equation of the line can be written as y = 2x. To find the point of intersection between the line and the perpendicular from the origin, we can solve the equation for x when y equals 5. Substituting y = 5 into the equation, we have 5 = 2x, which gives x = 5/2.

So, the height of the triangle is 5/2. Now we can calculate the area of the triangle using the formula for the area of a triangle, which is given by A = (1/2) * base * height. Plugging in the values, we get A = (1/2) * (5/2) * (5) = 25/4 = 6.25 square units.

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There are no outliers in the data since all the values are between -11 and 43.

Given data set is, 4, 9, 10, 13, 16, 17, 18, 22, 23, 38f)

Find the lower and upper quartiles.

The first step is to arrange the data in increasing order.

4, 9, 10, 13, 16, 17, 18, 22, 23, 38

The median is (16 + 17)/2 = 16.5.

This is the second quartile.

Now, the lower quartile (Q1) is the median of the first half of the data.

4, 9, 10, 13, 16

median is (9 + 10)/2 = 9.5

Therefore, Q1 = 9.5.

The upper quartile (Q3) is the median of the second half of the data.

18, 22, 23, 38 median is (22 + 23)/2 = 22.5

Therefore, Q3 = 22.5. g)

Are there any outliers in these data?

Using the interquartile range and Z-score.

To determine whether there are any outliers in the data, we use the interquartile range (IQR) and Z-score.

The formula for IQR is given by;

IQR = Q3 - Q1Substitute the values of Q1 and Q3IQR = 22.5 - 9.5IQR = 13If a value in the data is less than Q1 - 1.5 IQR or greater than Q3 + 1.5 IQR, then it is considered as an outlier.

The lower limit for outliers is;

Q1 - 1.5 IQR = 9.5 - 1.5(13) = -11

The upper limit for outliers is;

Q3 + 1.5 IQR = 22.5 + 1.5(13) = 43

We can see that there are no outliers in the data since all the values are between -11 and 43.

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Answer:

It is an arithmetic sequence. Common difference: -20

Step-by-step explanation:

First we can find out if it is an arithmetic sequence by seeing how you get from -3 to -23. Then we see to get from -3 to -23, we need to subtract -20. It's the same with -43, so the common difference is -20. And since arithmetic sequences are the only ones common differences, then this is an arithmetic sequence. I hope this helps and I hope it's not wrong, but I do not think it is.

Step-by-step explanation:

To solve the equation:

6(sin(x))^2 + 7cos(x) - 3 = 0

We can use the identity:

sin^2(x) + cos^2(x) = 1

Rearranging the equation, we get:

6(1-cos^2(x)) + 7cos(x) - 3 = 0

Expanding and rearranging, we get:

6cos^2(x) + 7cos(x) - 9 = 0

This is now a quadratic equation in terms of cos(x).

Using the quadratic formula, we get:

cos(x) = [-7 ± √(7^2 - 4(6)(-9))]/(2(6))

cos(x) = [-7 ± 13]/12

cos(x) = 1/2 or -3/2

Now we use the inverse cosine function to find x for each solution for cos(x).

When cos(x) = 1/2, we get:

x = π/3 + 2πk or x = 5π/3 + 2πk

When cos(x) = -3/2, we get:

there are no solutions for this case.

Therefore, the general solution to the equation is:

x = π/3 + 2πk or x = 5π/3 + 2πk where k is an integer.

The statement "IRI = |Nl" is false. because The symbol "|Nl" is not well-defined and it's not clear what it represents.

On the other hand, |N| represents the set of natural numbers, which are the positive integers (1, 2, 3, ...). These two sets are not equal.

Furthermore, the diagonalization argument is used to prove that the set of real numbers is uncountable, which means that there are more real numbers than natural numbers. This argument shows that it is impossible to construct a one-to-one correspondence between the natural numbers and the real numbers, even if we restrict ourselves to the interval [0, 1]. Hence, it is not possible to prove IRI = |N| using diagonalization argument.

In order to prove that two sets are equal, we need to show that they have the same elements. So, we would need to define what "|Nl" means and then show that the elements in IRI and |Nl are the same.

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It seems your question is about the diagonalization argument and cardinality of sets. A diagonalization argument is a method used to prove that certain infinite sets have different cardinalities. Cardinality refers to the size of a set, and when comparing infinite sets, we use the term "order."

In your question, you are referring to the sets N (natural numbers), IRI (real numbers), and the interval [0, 1]. The goal is to prove that the cardinality of the set of real numbers (|IRI|) is equal to the cardinality of the set of natural numbers (|N|).

Through a diagonalization argument, we can show that the cardinality of the set of real numbers in the interval [0, 1] (|IRI [0, 1]|) is larger than the cardinality of the set of natural numbers (|N|). This implies that the two sets cannot be put into a one-to-one correspondence.

Then, in order to prove that |IRI| = |N|, we would need to find a one-to-one correspondence between the two sets. However, the diagonalization argument shows that this is not possible.

Therefore, the statement in your question is False, because we cannot prove that |IRI| = |N| by showing a one-to-one correspondence between them.

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Answer:

Step-by-step explanation:

For A: Bar graph; for B: Histogram; for C: Pie chart; and for D:  Bar graph would be appropriate graphical representations.

a. The number of sales for your online company on each of the seven days in the past week:

The best graphical display to use here would be a bar graph. This is because a bar graph is appropriate for showing the distribution of a categorical variable, and the days of the week can be considered a categorical variable. The bar graph can clearly show the number of sales for each day of the week, making it easy to compare sales across days.

b. The amounts of each of the sales on Monday of the past week:

A histogram would be the best choice for this scenario. A histogram is used to represent continuous data, and sales amounts are continuous data. The histogram can be used to show the frequency of sales amounts within a specific range, providing a clear visual representation of the distribution of sales amounts on Monday.

c. The number of items bought by each of the customers who made a purchase on Monday of the past week:

A Pareto chart would be the best choice for this scenario. A Pareto chart is used to show the relative frequency or size of problems or categories, with the largest categories displayed on the left and the smallest on the right. The Pareto chart can clearly show the number of items bought by each customer, making it easy to see which customers made the most purchases.

d. The total amount of sales during the past year for each of the customers who made a purchase on Monday of the past week:

A bar graph would be the best choice for this scenario. This is because a bar graph can clearly show the distribution of the total sales amount for each customer, making it easy to compare the total sales among customers.

"

Complete question

Which graphical display should you use? For each of the following scenarios, decide which graphical display (pie chart, bar graph, Pareto chart, stemplot, or histogram) you would use to describe the distribution of the variable. Give a reason for your choice and if there is an alternative choice that would also be reasonable, explain why your choice was better than the alternative.

a. The number of sales for your online company on each of the seven days in the past week.

b. The amounts of each of the sales on Monday of the past week.

c. The number of items bought by each of the customers who made a purchase on Monday of the past week.

d. The total amount of sales during the past year for each of the customers who made a purchase on Monday of the past week.

"

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Answer: 15

Step-by-step explanation:

slow eater lol.

in one fifth of a minute, they ate 3 pieces. so add the other four fifths, 3 + 3 + 3 + 3 + 3, and youll get 15. easier to just multiply tho, 1/5 is 3, so 5/5 would be 3(5) = 15. hope this helps

Answer:

Step-by-step explanation:

y+2+8(y+7)

y+2+8y+56

9y+58

Answer:

AB = 24

Step-by-step explanation:

BD = 5x – 26

BC = 2x + 1

AC = 43

Using the segment addition postulate, AC = AB + BC.

We know that BD = BC, BD = 5x-26 and BC = 2x+1.  We can set up an equation to find the value of x:

5x - 26 = 2x + 1   Subtract 2x from each side

5x - 26 - 2x = 2x + 1 - 2x

3x-26 = 1  Add 26 to each side

3x-26+26 = 1+26

3x=27  Divide both sides by 3

3x/3 = 27/3

x = 9

This means that BC = 2x + 1 = 2(9) + 1 = 18 + 1 = 19.

We know that AC = AB + BC; using our given information as well as the value of BC we just found, we have

43 = AB + 19  Subtract 19 from each side

43 - 19 = AB + 19 - 19

24 = AB

Answer:

8-10=-2

Step-by-step explanation:

8-10=-2

I did 8- 10 instead of 10-8 because that how you put it in the question. I hope this helps if not I'm truly sorry.

Answer:

The answer is

Step-by-step explanation:

The distance between two points can be found by using the formula

\(d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\ \)

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(3,-12) and (3,-8)

The distance between them is

\( |EF| = \sqrt{( {3 - 3})^{2} + ({ - 12 + 8})^{2} } \\ = \sqrt{ {0}^{2} + ({ - 4})^{2} } \\ = \sqrt{16} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \)

We have the final answer as

Hope this helps you

Answer: 4

Step-by-step explanation: 8-12=4

a) The independent variable is the number of days after the baby panda's birth (d), and the dependent variable is the weight of the baby panda (w)

b) The slope represents the rate of change in weight per day. In this context, it means that the baby panda's weight is increasing by 0.25 pounds every day.

c) The y-intercept is 1.2 lbs. In this context, it means that the baby panda weighed 1.2 pounds at birth

d) The function to model the panda's weight after d days can be written as w = 0.25d + 1.2

a) The independent variable is the number of days after the baby panda's birth (d), and the dependent variable is the weight of the baby panda (w)

b) To find the slope, we can use the formula:

Slope = (Change in y) / (Change in x)

where (Change in y) is the change in weight and (Change in x) is the change in days.

Slope = (3.2 - 1.95) / (8 - 3 )

Slope = 1.25 / 5

Slope = 0.25

The slope represents the rate of change in weight per day. In this context, it means that the baby panda's weight is increasing by 0.25 pounds every day.

c) To find the y-intercept, we can use the equation of a line:

y = mx + b

where y is the weight, x is the number of days, m is the slope, and b is the y-intercept.

Using the data given, we can substitute the values into the equation:

1.95 = 0.25* 3 + b

Solving for b, we get:

b = 1.95 - 0.25 * 3

b = 1.95 - 0.75

b = 1.2

The y-intercept is 1.2 lbs. In this context, it means that the baby panda weighed 1.2 pounds at birth (on day 0).

d) The function to model the panda's weight after d days can be written as:

w = 0.25d + 1.2

where w is the weight of the baby panda and d is the number of days after its birth.

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Answer:

$1,725,360

Step-by-step explanation:

For this, you would just multiply every number: \(employees×weekly salary×weeks\) which is \(546×790×4=1,725,360\).

Answer:

I think all u need to do is mulitply thoses numbers just use calulator

Step-by-step explanation:

hope it helped

The required requirement of the density curve is should be equal to 1 and the ordinate should not be zero.

Given that,
Two requirements of a density curve are to be determined.

A density curve is defined as a curve on a graph that represents the distribution of values in a dataset.

Here,

The two requirements of a density curve should be,

a. The area under the density curve should be equal to 1.

b. The ordinate of the curve should not be zero i.e. they should always have the vertical height.

Thus, the required requirement of the density curve is mentioned above.

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Yes, frequency distributions can be made for both categorical and quantitative data.

A frequency distribution is a table that shows how often each value occurs in a data set. It is a way of summarizing data and can be used for both categorical and quantitative data.

Categorical data is data that can be divided into categories, such as gender or eye color. A frequency distribution for categorical data would show how many times each category appears in the data set.

Quantitative data is numerical data, such as height or weight. A frequency distribution for quantitative data would show how many times each numerical value appears in the data set.

In both cases, the frequency distribution helps to summarize and visualize the data in a clear and concise way.

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Answer:

x = \(\frac{k+9}{y}\)

Step-by-step explanation:

Given

xy - 9 = k ( add 9 to both sides )

xy = k + 9 ( isolate x by dividing both sides by y )

x = \(\frac{k+9}{y}\)

Answer:

4 gal / day

Step-by-step explanation:

12 gallons / 3 days

12/3 = 4

4 gallons / 1 day