SCIENCE Which best describes a difference between single-celled organisms and multicellular organisms?

A.
Single-celled organisms are simple, while multicellular organisms are complex.

B.
Single-celled organisms have many functions, while multicellular organisms have one function.

C.
Single-celled organisms can live without water, while multicellular organisms cannot live without water.

D.
Single-celled organisms can only be found in one specific environment, while multicellular organisms can be found anywhere on Earth.

Answer: The concentration of hydrogen ion in the given solution is \(2.81 \times 10^{-10}\).

Explanation:

pOH of a solution is the negative logarithm of concentration of hydroxide ions.

Hence, if \([OH^{-}]\) is \(3.5 \times 10^{-5}\) then its pOH value is calculated as follows.

\(pOH = -log [OH^{-}]\\= -log (3.5 \times 10^{-5})\\= 4.45\)

Now, the relation between pH and pOH is as follows.

pH + pOH = 14

pH + 4.45 = 14

pH = 14 - 4.45

= 9.55

And, pH is the negative logarithm of concentration of hydrogen ions. Hence, \([H^{+}]\) is calculated as follows.

\(pH = -log [H^{+}]\\9.55 = -log [H^{+}]\\H^{+} = 2.81 \times 10^{-10}\)

Thus, we can conclude that the concentration of hydrogen ion in the given solution is \(2.81 \times 10^{-10}\).

Answer:The fuel/air mixture may become too minimal

Explanation:While cruising at 9,500 feet MSL, the fuel/air mixture is properly adjusted. What will occur if a descent to 4,500 feet MSL is made without readjusting the mixture

The given statement is  "The two atoms in a water molecule are arranged asymmetrically" is true as the two hydrogen atoms are arranged asymmetrically. The correct option is a.

In the water molecule, the oxygen atom (O) and the two hydrogen atoms (H) are arranged as the asymmetrically. This will produces the dipole, the molecule with the one negatively and the one positively charged end. It will depending on the temperature, the dipoles align themselves in to the aggregates according to the charge, such as, in the formation of the ice crystal.

Water is the polar molecule, this is due to the O-H bond of the water, Oxygen is the more electronegative due to which the partial positive charge and the partial negative charge will created on the hydrogen and the oxygen, this resulting in the dipole moment. Therefore, the correct option is a.

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In a sample of ground beef, there were 18.9% protein and 21.4% fat, both expressed in mass. Therefore, 125g of ground beef has 147.5 kilocalories.

The now-defunct kinetic theory of heat served as the basis for the calorie, a unit of energy. For historical reasons, the term "calorie" has two main definitions that are often employed.

Originally, the amount of heat needed to raise the temperature of one kg of water by one degree Celsius was referred to as a large calorie, dinner calorie, dietary nutrient, and kilo calorie (or one kelvin). A minuscule calorie or tiny calorie is the term used to describe the quantity of heat needed to produce the same increase in one kilogram of water.

The needed number of calories for ground beef is m.

protein in it = .18m

fat in it =  .21m

1 gram of protein gives 4 cals .

1 gram of fat gives 9 cals .

4 x .18m  + 9 x  .21m = 350

m = 147.5kilocalories

Therefore, 125g of ground beef has 147.5 kilocalories.

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I think there are a bond??

Answer:

it is covalent

hope this helps!

add me as a friend if you can:)

Answer: OH−.

Explanation: Hydroxide, any chemical compound containing one or more groups, each comprising one atom each of oxygen and hydrogen bonded together and functioning as the negatively charged ion OH-.

\(\begin{aligned} -5x+4y &= 3\\\\ x&=2y-15 \end{aligned}\)

The first two chemical equations are reversible while the other two are irreversible.

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

The first chemical equation was put forth by Jean Beguin in 1615.By making use of chemical equations the direction of reaction ,state of reactants and products can be stated. In the chemical equations even the temperature to be maintained and catalyst can be mentioned.

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The time it takes to heat this water in a 1-kg steel pan sitting on a 1,500-W electric stove burner that transfers 75% of its energy output to the water and the pan is 90 seconds (rounded to the nearest whole second).

We need to calculate the time taken to heat the water in a 1-kg steel pan sitting on a 1,500-W electric stove burner that transfers 75% of its energy output to the water and the pan. The given information are as follows:

Specific heat of water, cw = 4184 J/kg °C

Specific heat of steel, cs = 450 J/kg °C

Energy supplied by the electric stove burner, P = 1,500 W (75% of which is transferred to the water and the pan)

Mass of water, mw = 250 g = 0.25 kg

Mass of steel pan, ms = 1 kg

Initial temperature of water and steel pan, T1 = 10 °C

Final temperature of water and steel pan (boiling point of water), T2 = 100 °C

Heat absorbed by the steel pan = Qs = ms × cs × (T2 - T1)Heat absorbed by the water = Qw = mw × cw × (T2 - T1)

Total heat absorbed by the water and the pan = Q = Qw + Qs = (0.25 × 4184 × 90) + (1 × 450 × 90) J= 94,140 + 40,500 J= 1,34,640 J

Time taken to heat the water and the pan = t = Q/P= 1,34,640 / 1,500 s= 89.76 or 90 s

Therefore, the time it takes to heat this water in a 1-kg steel pan sitting on a 1,500-W electric stove burner that transfers 75% of its energy output to the water and the pan is 90 seconds (rounded to the nearest whole second).

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Answer:

1. V2.

2. 299K.

3. 451K

4. 0.25 x 451 = V2 x 299

Explanation:

1. The data obtained from the question include:

Initial volume (V1) = 0.25mL

Initial temperature (T1) = 26°C

Final temperature (T2) = 178°C

Final volume (V2) =.?

2. Conversion from celsius to Kelvin temperature.

T(K) = T (°C) + 273

Initial temperature (T1) = 26°C

Initial temperature (T1) = 26°C + 273 = 299K

3. Conversion from celsius to Kelvin temperature.

T(K) = T (°C) + 273

Final temperature (T2) = 178°C

Final temperature (T1) = 178°C + 273 = 451K

4. Initial volume (V1) = 0.25mL

Initial temperature (T1) = 299K

Final temperature (T2) = 451K

Final volume (V2) =.?

V1 x T2 = V2 x T1

0.25 x 451 = V2 x 299

Some assumptions from the kinetic molecular theory , one is most frequently cited to explain diffusion of a gas is the gas consist of  tiny particles moving in the random straight line motion.

The assumption of the kinetic molecular theory are :

Thus, the gas is the gas consist of  tiny particles moving in the random straight line motion explain the diffusion of a gas.

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The chemist should observe the formation of solid copper metal, a change in color of the solution, and the disappearance of the aluminium foil through this unbalanced equation.

The balanced equation for the reaction between copper (II) chloride and aluminum is:

3CuCl2 + 2Al → 2AlCl3 + 3Cu

In this reaction, aluminum replaces copper in the copper chloride solution to form aluminium chloride and copper metal.

The likely observations when the reaction stops are:

1. The solution may change color, indicating that a chemical reaction has occurred. Copper (II) chloride is blue, while aluminum chloride is colorless.

2. Solid copper metal may form and settle at the bottom of the container, indicating that a precipitation reaction has occurred.

3. The aluminum foil may appear to have dissolved or disintegrated, as it has been consumed in the reaction.

4. The reaction mixture may become warmer due to the exothermic nature of the reaction.

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Answer:

The answer is B

Explanation:

A solution that contains a relatively low concentration of solute is called dilute, and one with a relatively high concentration is called concentrated. If we add more salt to a saturated solution of salt, we see it fall to the bottom and no more seems to dissolve.

The temperature change when 720.0 g of steam at 400.0 °C absorbs 800.0 kJ of heat energy is 265 °C.

Endothermic reactions are reactions in which heat is absorbed by the reaction system from the surroundings.

Exothermic reactions are reactions in which heat is given off by the reaction system to the surroundings.

The temperature change when 720.0 g of steam at 400.0 °C absorbs 800.0 kJ of heat energy is calculated as follows:

temperature change = heat change / mass * specific heat

Specific heat of water = 4.18 J/g/°C

mass of water = 720 g

heat absorbed = 800 kJ or 800000 J

temperature change = 800000 / (4.18 * 720)

temperature change = 265 °C

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Answer:

266 Celsius

Explanation:

q=mst

t=q/ms

800.0 kj x 1000 = 800000 J

water specific heat = 4.18 or 4.184

\(t=\frac{800000J}{4.18x720C} = 265.8 C or 266 C\)

The amount of concentrated solution needed is (0.286 M)(65 mL) / C M, and the amount of water needed is 65 mL minus the volume of the concentrated solution.

To calculate the molarity of Kool Aid desired, we need to determine the number of moles of Kool Aid powder and sugar in the package. Since the molecular formula for sugar is C12H22O11, we can calculate its molar mass as follows:

Molar mass of C12H22O11 = (12 * 12.01) + (22 * 1.01) + (11 * 16.00)

= 144.12 + 22.22 + 176.00

= 342.34 g/mol

Given that the package contains 4.25 grams of Kool Aid powder, we can calculate the number of moles of Kool Aid powder using its molar mass:

Number of moles of Kool Aid powder = Mass / Molar mass

= 4.25 g / 342.34 g/mol

≈ 0.0124 mol

Similarly, for the sugar, which has a molar mass of 342.34 g/mol, we can calculate the number of moles of sugar using its mass:

Number of moles of sugar = Mass / Molar mass

= 192.00 g / 342.34 g/mol

≈ 0.5612 mol

Now, to calculate the molarity of the desired Kool Aid solution, we need to determine the volume of water. Given that 1.06 quarts is equal to 1 liter, and we have 2.00 quarts of water, we can convert it to liters as follows:

Volume of water = 2.00 quarts * (1.06 liters / 1 quart)

= 2.12 liters

To find the molarity, we use the formula:

Molarity (M) = Number of moles / Volume (in liters)

Molarity of Kool Aid desired = (0.0124 mol + 0.5612 mol) / 2.12 L

≈ 0.286 M

To prepare 65 mL of the desired molarity, we can use dilution calculations. We need to determine the volume of concentrated solution and the volume of water needed.

Let's assume the concentration of the concentrated Kool Aid solution is C M. Using the dilution formula:

(C1)(V1) = (C2)(V2)where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

Given that C1 = C M and V1 = V mL, and we want to prepare a final volume of 65 mL (V2 = 65 mL) with a final concentration of 0.286 M (C2 = 0.286 M), we can rearrange the formula to solve for the volume of the concentrated solution:

(C M)(V mL) = (0.286 M)(65 mL)

V mL = (0.286 M)(65 mL) / C M

So, the amount of concentrated solution needed is (0.286 M)(65 mL) / C M, and the amount of water needed is 65 mL minus the volume of the concentrated solution.

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Using ohms law

\(\\ \rm\longmapsto V=IR\)

\(\\ \rm\longmapsto V=3(5)\)

\(\\ \rm\longmapsto V=15V\)

Answer:

specialized if you add one more I cause I'm pretty sure there is supposed to be one more i.

Between 0 and 1500, the average reaction rate is 0.000112 M/s, or 7.14*\(10^{-5}\)Instantaneous rate is thus 7.25*\(10^{-5}\) M/s..

Resistance or antagonism to a force, action, or movement is a reactionary act, process, or occurrence. especially: a reaction to a particular treatment, circumstance, or stimulus; leaning toward a past and typically antiquated political or social system or policy. She was shocked by the information.

The paper ought to include a synopsis of the source material, but the major emphasis should be on your opinions and justifications regarding the topics included in the actual text. This necessitates your consideration of the provided work, followed by a targeted, well-thought-out response supported by outside sources, when appropriate.

Part A:

At t = 0 s , [A] = 0.184 M

At t = 1500 s , [A] = 0.016 M

Average rate = \Delta[A] / \Deltat

= (0.016 - 0.184) / (1500 - 0)

= - 0.168 / 1500

= - 0.000112 M/s

Hence average rate = 1.12*\(10^{-4}\) M/s

Part B:

At t = 500 s , [A] = 0.069 M

At t = 1200 s , [A] = 0.019 M

Average rate = (0.019 - 0.069) / (1200 - 500)

= - 0.05 / 700

= - 7.14*\(10^{-5}\) M/s

Hence average rate = 7.14*\(10^{-5}\) M/s

Part C:

0.20 0.18 0.16 0.14 0.12 Z 0.10 0.08 0.06 0.04 0.02 0 200 400 600 800 1000 1200 1400 1600 Time (s)

Now, we have:

At t = 600s ; [A] = 0.043 M

At t = 1000s ; [A] = 0.014 M

Instantaneous rate = slope of tangent at t = 800s

= d[A] / dt

= (0.014 - 0.043) / (1000 - 600)

= - 0.029 / 400

= - 0.0000725 M/s

Hence instantaneous rate =  7.25*\(10^{-5}\) M/s

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The volume of the dry nitrogen gas at STP is 57.4 mL

From the question given above, the following data were obtained:

Initial volume (V₁) = 77 mL

Initial temperature (T₁) = 50 °C = 50 + 273 = 323 K

Initial pressure (P₁) = 763 – 92.5 = 670.5 mmHg

Final temperature (T₂) = STP = 273 K

Final pressure (P₂) = 760 mmHg

The volume of the dry nitrogen can be obtained by using the combine gas equation as follow:

\( \frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2} \\ \\ \frac{670.5 \times 77}{323} = \frac{760 \times V_2}{273} \\ \\ cross \: multiply \\ \\ 323 \times 760 \times V_2 = 670.5 \times 77 \times 273 \\ \\ divide \: both \: side \: by \: 323 \times 760 \\ \\ V_2 = \: \frac{670.5 \times 77 \times 273 }{323 \times 760} \\ \\ V_2 = 57.4 \: ml\)

Therefore, the volume of the dry nitrogen gas is 57.4 mL

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When a diprotic acid is titrated with a strong base, and the Ka1 and Ka2 are significantly different, then the pH vs. volume plot of the titration will have: two distinct equivalence points. The answer is C.

There are two distinct steps in the titration curve, the first equivalence point is the point at which the base has reacted with all of the H+ ions from the first acidic hydrogen, while the second equivalence point is the point at which the base has reacted with all of the H+ ions from the second acidic hydrogen.

The pH at the first equivalence point will be less than 7, and the pH at the second equivalence point will be greater than 7, indicating that the solution is acidic for the first equivalence point and basis for the second equivalence point.

The Ka1 and Ka2 values for diprotic acids are typically different because the first hydrogen ion is more strongly bound to the molecule than the second hydrogen ion, resulting in different dissociation constants for each hydrogen ion.

Therefore, the pH vs. volume plot of the titration of a diprotic acid with a strong base will have two distinct equivalence points if Ka1 and Ka2 are significantly different.

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Answer:

\(V_2=5.32L\)

Explanation:

Hello there!

In this case, according to the given pressure, temperature and volume, it is possible for us to calculate the final volume via the combined ideal gas law:

\(\frac{P_2V_2}{T_2}=\frac{P_1V_1}{T_1}\)

In such a way, we solve for the final volume, V2, to obtain:

\(V_2=\frac{P_1V_1T_2}{T_1P_2}\)

Then, we plug in the given data to obtain:

\(V_2=\frac{1.19atm*2.3L*380K}{326K*0.60atm}\\\\V_2=5.32L\)

Regards!

Answer:

1. Zn + HCl --> ZnCl + H2

2. when zinc reacts with hydrochloric acid, the zinc gets oxidized as chlorine is an electronegative element while the hydrochloric acid gets reduced as their is a removal of chlorine from the compound to give out hydrogen

3. it happens in our stomach as it releases hcl in the undigested food to convert it into soluble compounds and waste material for consumption by our body and excretion respectively.

The nuclear disintegration series of 238-U is the source of radon-222 in soil.

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Rocksalt Structure: No close-packed directions.

FCC Metal Structure: [111] family of close-packed directions.

BCC Metal Structure: [110] family of close-packed directions.

The rock salt structure has a face-centered cubic (FCC) arrangement of both cations and anions. In this structure, there are no close-packed directions because the ions are arranged in a simple cubic pattern. Consider the [100], [010], and [001] directions as the primary directions of the rock salt structure.

In an FCC metal structure, the close-packed directions are represented by the [111] family. The [111] direction is the densest and corresponds to the stacking of atoms along the body diagonal of the cube. The [111] family includes directions such as [111], [1-11], [11-1], [1-1-1], [-111], [-1-11], [-11-1], and [-1-1-1].

In a BCC metal structure, the close-packed directions are represented by the [110] family. The [110] direction is the densest and corresponds to the stacking of atoms along the cube edge diagonal. The [110] family includes directions such as [110], [1-10], [-110], and [-1-10].

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The most stable conformation of 3-isopropyl-1,1dimethylcyclohexane equatorial ethyl group (more stable).  The stability of ethylcyclohexane's equatorial conformer exceeds that of its axial conformer by 7.4 kJ/mol.

According to the previous section, the chair conformation with the equatorial methyl group is more stable because it reduces steric repulsion, and as a result, the equilibrium favors the more stable conformer. Strongly favoring the equatorial shape is methylcyclohexane. The methyl group is in close proximity to the axial hydrogens in the axial conformation, which has an energetically unfavorable effect known as a 1,3-diaxial interaction. The methyl group prefers the equatorial shape as a result.  The conformation of ethylcyclohexane in which the ethyl group is in the equatorial position is the most stable.

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Answer:

the energy required to do work

Answer:6969?

Explanation:

From the given information, a 4.70 ml sample of an H3PO4 solution of unknown concentration is titrated with a 1.050×10−2 M NaOH solution. It is stated that a volume of 7.32 ml of the NaOH solution was required to reach the equivalence point.

In a titration, the equivalence point is reached when the moles of the acid and the moles of the base are stoichiometrically balanced. From the volume of NaOH solution required to reach the equivalence point (7.32 ml) and the known concentration of the NaOH solution (1.050×10−2 M), the number of moles of NaOH can be calculated.

Next, using the balanced equation for the reaction between H3PO4 and NaOH, the stoichiometry can be determined. If we assume a 1:1 ratio between H3PO4 and NaOH, the number of moles of H3PO4 in the initial 4.70 ml sample can be calculated.

Finally, with the moles of H3PO4 and the volume of the sample, the concentration of the H3PO4 solution can be determined.

Note: Since the balanced equation for the reaction between H3PO4 and NaOH is not provided, the exact calculation cannot be performed without additional information.

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Answer: 80000 micrometers

hope i helped

Answer:

325 g/L,

0.9503 M

Explanation:

65 g sugar --- 0.2 L

x g              ---  1 L

x = 65/0.2 g/L = 325 g/L

Sugar(sucrose) is C12H22O11.

Molar mass (C12H22O11) = 12*12 + 1*22 + 16*11 = 342 g/mol

325 g/L * 1 mol/342 g = 0.9503 mol/L = 0.9503 M

Answer 0.6398(M) is not related to sugar (sucrose),

it should be given formula or molar mass of sugar if it is different than sucrose.