Scientists have studied two species of sand lizards, the Mojave fringe-toed lizard and the western zebra-tailed lizard, to understand the extent to which the different structure of the two species' toes is related to their preferred habitats-fine sand for the Mojave lizard and coarse sand for the zebra-tailed lizard. (Figure 1) shows a somewhat simplified velocity-versus-time graph for the Mojave fringe-toed lizard. Figure1 of 1 The plot shows velocity v subscript x as a function of time t. Time is measured from 0 to 250 milliseconds on the x-axis. Velocity is measured from 0 to 2.0 meters per second on the y-axis. Velocity equals 0 at zero time. Then it increases linearly to 0.8 meter per second at 50 milliseconds. Then it increases at a decreasing rate forming the curve concave down that passes 1.0 meter per second at 70 milliseconds, 1.3 meters per second at 100 milliseconds, 1.5 meters per second at 125 milliseconds, 1.65 meters per second at 150 milliseconds, 1.8 meters per second at 200 milliseconds, and 1.9 meters per second at 230 milliseconds. Part A Estimate the maximum acceleration of the lizard in both m/s2 and g's.
Answers
With the average acceleration in each interval we can find that maximum acceleration occurs in the first interval and has a value of a = 16 m / s²
Average acceleration is defined as the change in velocity of a body in a given time interval
a = \(\frac{\Delta v}{\Delta t}\)
where a is the acceleration, Δv and Δt the speed and time variations in the interval.
In the attachment we have a graph of the speed as a function of time where it is observed that the speed is reaching a maximum as time advances,
let's calculate the average acceleration for each interval
1) time between t₁ = 0 and t_f = 50 10⁻³ s for velocities v₁ = 0 and v_f = 0.8 m/s
a₁ = \(\frac{0.8 -0}{(50 - 0) 10^{-3}}\)
a₁ = 16 m / s²
2) time between t₁ = 50 10⁻³and t_f = 70 10⁻³ s for velocities v₁ = 1.0 and
v_f = 0.8 m/s
a₂ = \(\frac{1.0 - 0.8}{(70-50) \ 10^{-3}}\)
a₂ = 10 m / s²
3) time between t₁ = 70 10⁻³ s and t_f = 100 10⁻³ s for velocities v₁ = 0 and
v_f = 0.8 m/s
a₃ = \(\frac{1.3 - 1.0}{(100 -70) \ 10^{-3}}\)
a₃ = 10 m / s²
4) time t₁ = 100 10⁻³ s and t_f = 125 10⁻³ s for speeds v₁ = 1.3 m / s and
v_f = 1.5 m / s
a₄ = \(\frac{ 1.5 - 1.3}{(125-100)10^{-3}}\)
a₄ = 8 m / s²
5) time t₁ = 125 10⁻³ s and t_f = 150 10⁻³ s for speeds v₁ = 1.5 m / s and
v_f = 1.65 m / s
a₅ = \(\frac{1.65 - 1.5}{(150-125)10^{-3}}\)
a₅ = 6 m / s²
6) time t₁ = 150 10⁻³ s and t_f = 200 10⁻³ ms for speeds v₁ = 1.65 m / s and
v_f = 1.8 m / s
a₆ = \(\frac{1.8 - 1.65}{(200 -150)10^{-3}}\)
a₆ = 3 m / s²
7) time t₁ = 200 10⁻³ s and t-f = 230 10⁻³ s for speeds v₁ = 1.8 m / s and
v_f = 1.9 m / s
a₇ = \(\frac{1.9 - 1.8}{(230-200)10^{-3}}\)
a₇ = 3 m / s
In conclusion, using the concepts of average acceleration we can find that maximum acceleration occurs in the first interval and has a value of
a = 16 m / s²
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Related Questions
Two blocks, 1 and 2, are connected by a massless string that passes over a massless pulley. 1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. 2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105
. The figure illustrates the configuration.
A system of two blocks connected by a rope passing over a pulley. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle. Box M subscript 1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M sub 1 and the surface is mu subscript 1. Box M subscript 2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle. The coefficient of friction between box M sub 2 and the surface is mu subscript 2.
Answers
The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.
The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.
The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.
The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.
The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).
The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).
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What improvements were made in measuring system with the introduction of standard units?
Answers
Answer:
Standard units are commonly used units of measurement, which help us measure length, height, weight, temperature, mass and more. These units are standardised, which means that everyone gets the same understanding of the size, weight and other properties of objects and things.
Explanation:
Which type of electromagnetic radiation is used to keep food warm?
O A. Infrared radiation
O B. Visible light
O C. Gamma rays
D. X-rays
Answers
Answer:
A. infrared
Explanation:
Heat lamps used to keep foods warm are infrared on the light spectrum
describe briefly how you can a body
Answers
Answer:
what
you need to elaborate
Answer: Can you please write question clearly.
Explanation:
Describe how the basic measurements of length, volume, and mass were determined in the
metric system?
Answers
the basic measurements of length, volume, and mass are 1 meter, 1 meter³ and 1kilogram.
One 10-millionth of the distance from the North Pole to the equator would equal one meter.
A cube with sides of one meter has a volume of one meter³.
The mass of 1,000 cubic centimeters of water is very close to (and was originally intended to be exactly) one kilograms.
but today a more precise way to define is available in which:
1 meter is defined as the distance traveled by light in 1/3×10⁸ sec.
The weight of a specific platinum-iridium prototype held by the International Bureau of Weights and Measures is defined as 1 kg.
moreover these measurements are man made and are not absolute and therefore many new units of measurement can be defined as long as they are fundamentally same everywhere.
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5.) This car battery
measures at 12.6 V
with a voltmeter. If it
produces 0.53 A of current for
a vehicle's headlight when
connected, what is the
resistance of the headlight
bulb?
Answers
Answer:
R =V/ I =12.6 ÷ 0.53= 27.77 ohm
Question 12 of 25
Two identical satellites circle the Earth in orbits. The distance between the
Earth and satellite B is twice the distance between the Earth and satellite A.
What is the relationship between the gravitational force acting on satellite A
(FA) and the force on B (FB)?
Earth
OA. FB = FA
OB. Cannot be determined
OC. FB< FA
OD. Fa> FA
Satellite A
Satellite B
Answers
Answer:
F = G M m / R^2 gravitational force on satellite of mass m
Fma / Fmb = (ma / Ra^2) \ (mb / Rb^2) = (ma / mb) * (Rb / Ra)^2
Fma / Fmb = 1 * 4 = 4
The force on A is 4 times the force on B
A roller coaster starts from rest at its highest point and then descends on its (frictionless) track. Its speed is 34 m/s when it reaches ground level. What was its speed when its height was half that of its starting point? 12 m/s 24 m/s 17 m/s 28 m/s
Answers
A roller coaster begins at its highest point, where it is at rest, & then drops on its frictionless track. When it reaches the bottom, it moves at a velocity of 34 m/s & 24 m/s when it is halfway up from its starting place.
What is the potential energy whenever a roller coaster hits its greatest point?On a roller coaster, the gravitational potential is greatest at the top and lowest at the bottom. Kinetic energy (KE) is known as energy an item has due to its motion and thus is equal with one the item's mass multiplied by the object's velocity squared (mv2).
Is the descent and acceleration of a roller coaster potential or kinetic?The transformation of potential energy into kinetic energy drives the motion of a roller coaster. The potential energy of the rollercoaster ride cars increases as they are propelled to the summit of the initial hill. Potential energy is transformed into kinetic energy as the cars fall.
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Two loops of wire are arranged so that a changing current in one will induce a current in the other. If the current in the first is increasing clockwise by one amp every second, the current in the second loop will
Answers
Answer:
The current in the second loop will stay constant
Explanation:
Since the induced emf in the second coil, ε due to the changing current i₁ in the first wire loop ε = -Mdi₁/dt where M = mutual inductance of the coils and di₁/dt = rate of change of current in the first coil = + 1 A/s (positive since it is clockwise)
Now ε = i₂R where i₂ = current in second wire loop and R = resistance of second wire loop.
So, i₂R = -Mdi₁/dt
i₂ = -Mdi₁/dt/R
Since di₁/dt = + 1 A/s,
i₂ = -Mdi₁/dt/R
i₂ = -M × + 1 A/s/R
i₂ = -M/R
Since M and R are constant, this implies that i₂ = constant
So, the current in the second wire loop will stay constant.
How do I find the mass in kg
Answers
To find the mass in kilograms, you need to know the object's weight in newtons and the acceleration due to gravity. The formula for finding mass is mass = weight / acceleration due to gravity. So if you have an object with a weight of 100 N and the acceleration due to gravity is 9.8 m/s^2, the mass would be 10.204 kg.
The mass of the block is 0.025 kg or 25 g, when the spring has k = 28 N/m, and compresses 0.11 m before bringing the block to rest.
When a block is dropped onto a spring with k=28 N/m, the block has a speed of 3.2 m/s just before it strikes the spring. If the spring compresses an amount of 0.11 m before bringing the block to rest, what is the mass of the block?The formula for the spring potential energy is given as follows; PE = (1/2) kx² where k is the spring constant and x is the amount of deformation of the spring. Substituting the values given;PE = (1/2) 28 (0.11)²PE = 0.16972 J. According to the law of conservation of energy, the potential energy stored in the spring at maximum compression is equal to the kinetic energy the block had before it struck the spring;KE = (1/2) mv²where m is the mass of the block and v is its velocity.Substituting the values;0.16972 = (1/2) m (3.2)²m = 0.025 kg or 25 gTherefore, the mass of the block is 0.025 kg or 25 g.For more questions on mass
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Use Kepler's third law to determine how many days it takes a spacecraft to travel in an elliptical orbit from a point 6 590 km from the Earth's center to the Moon, 385 000 km from the Earth's center.
Answers
Answer:
1.363×10^15 seconds
Explanation:
The spaceship travels an elliptical orbit from a point of 6590km from the earth center to the moon and 38500km from the earth center.
To calculate the time taken from Kepler's third Law :
T^2 = ( 4π^2/GMe ) r^3
Where Me is the mass of the earth
r is the average distance travel
G is the universal gravitational constant. = 6.67×10-11 m3 kg-1 s-2
π = 3.14
Me = mass of earth = 5.972×10^24kg
r =( r minimum + r maximum)/2 ......1
rmin = 6590km
rmax = 385000km
From equation 1
r = (6590+385000)/2
r = 391590/2
r = 195795km
From T^2 = ( 4π^2/GMe ) r^3
T^2 = (4 × 3.14^2/ 6.67×10-11 × 5.972×10^24) × 195795^3
= ( 4×9.8596/ 3.983×10^14 ) × 7.5059×10^15
= 39.4384/ 3.983×10^14 ) × 7.5059×10^15
= (9.901×10^14) × 7.5059×10^15
T^2 = 7.4321× 10^30
T =√7.4321× 10^30
T = 2.726×10^15 seconds
The time for one way trip from Earth to the moon is :
∆T = T/2
= 2.726×10^15 /2
= 1.363×10^15 secs
In one paragraph, written in your own words (at least three sentences), describe what is
meant by the wave-particle duality of electromagnetic radiation
Answers
Answer:
Light wave-particle duality simply that the light has both the characteristics of fluctuations, but also has the characteristics of particles. Scientists have found that light can propagate forward like a wave, and sometimes show the characteristics of particles. Therefore, so we call light has “wave-particle duality”.
Explanation:
The energy released when 10 g of steam is spilt on the hand is...... (Knowing that: the specific heat capacity of water to be 4200 J kg-¹ K-¹, the specific latent heat of vaporization of water to be 2.2 MJ kg¹) Assume that the temperature of the skin is 33 °C. A- 22 kJ B- 25 kJ C- 3 kJ D- 19 kJ
Answers
The energy released when 10 g of steam is spilled on the hand is approximately 25 kJ
B- 25 kJHow to find the energy releasedThe heat required to raise the temperature of 10 g of water from 33 °C to 100 °C is
Q₁ = m x c x ΔT
= 10 g * 4.2 * (100 °C - 33 °C)
= 2772 J
The heat required to vaporize 10 g of water at 100 °C is given by:
Q₂ = m x L
= 10 * 2.2
= 22,000 J
where L is the specific latent heat of vaporization of water
The total energy released
Q = Q1 + Q2
= 2772 J + 22,000 J
= 24,772 J
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A__is the best example or representation of a concept.
Answers
A prototype is the best example or representation of a concept, which is used as a design to shape a device.
What is a prototype?A prototype can be defined as a given design in its experimental stage which is very useful to shape the framework or idea to carry out.
Therefore, with this data, we can see that a prototype can be very useful to shape an idea or concept about a given device in particular.
Complete question:
Fill in the blank. A _____ is the best example or representation of a concept.
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A sharpshooter fires a rifle while standing with the butt of the gun against her shoulder. If the forward momentum of a bullet is the same as the backward momentum of the gun, why isn't it as dangerous to be hit by the gun as by the bullet? (Select all that apply.)
The butt distributes the recoil force over an area much larger than that of the bullet.
The rifle has a much lower speed than the bullet.
The rifle has a much smaller kinetic energy than the bullet.
The rifle has much less mass than the bullet.
The rifle has much more total momentum than the bullet.
Answers
It as dangerous to be hit by the gun as by the bullet because of the following;
(A) The butt distributes the recoil force over an area much larger than that of the bullet.
(B) The rifle has a much lower speed than the bullet.
What is principle of conservation of linear momentum?
The principle of conservation of linear momentum states that in an isolated system, the total momentum of the system is conserved.
That is the sum of the initial momentum is equal to the sum of the final momentum.
momentum of the gun = momentum of the bullet
Mu = mU
where;
M is mass of the gunu is the velocity of the gunm is mass of the bulletU is the velocity of the bulletIf the forward momentum of a bullet is the same as the backward momentum of the gun, the speed of the gun will be smaller than the speed of the bullet since the mass of the gun is bigger than mass of the bullet.
We cannot conclude on the kinetic energy, since it depends on both mass and velocity.
Finally, the butt distributes the recoil force over an area much larger than that of the bullet, since the butt has a larger surface area and will hit more surface area than the bullet.
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As a boss, knowing your employees’ personality types can help you
Answers
Answer:
identify who they are as a person
Explanation:
Help help help help please
Answers
Answer:
The sediment settled with the largest particles at the bottom and the smaller at the top.
starting from rest, a 20,000-kg aircraft being launched from an aircraft carrier goes from 0 to 90 m/s in 2 seconds. the net force acting on the aircraft is
Answers
The response to the question is that there is net force of 900,000 N operating on the airplane.
What does it mean to be a net force?A thing's net force is the sum of all the stresses it has received. The equation below provides the total number of N pressures that were applied to an item. Various forces may be applied to an object.
The overall reaction force on the airplane can be calculated using Newton's second law.
F = m × a
You can use the following formula to determine the average acceleration using time (t = 2 s), initial speed (v0 = 0 m/s), and object velocity (vf = 90 m/s):
\(a = \frac{(vf - v0) }{ t}\)
Putting in the values:
\(a = \frac{(90 m/s - 0 m/s)}{ 2 s}= 45 m/s^2\)
We can determine the net force affecting the aircraft now that you understand its acceleration:
F = m × a
\(= 20,000 kg \times 45 m/s^2 \\= 900,000 N\)
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if an object with a mass of 30kg is propelled with a force of 10 N what rate will the object accelrate at
Answers
The given scenario involves calculating the acceleration of an object propelled by a force of 10 N with a mass of 30 kg. The object will accelerate at a rate of 0.333 m/s².
The equation for calculating acceleration is:
acceleration = force / mass
where acceleration is measured in meters per second squared (m/s²), force is measured in Newtons (N), and mass is measured in kilograms (kg).
Given:
mass = 30 kg
force = 10 N
To find the acceleration, we can substitute these values into the equation:
acceleration = force / mass
acceleration = 10 N / 30 kg
acceleration = 0.333 m/s²
Therefore, the object will accelerate at a rate of 0.333 meters per second squared. This means that for every second that passes, the object's velocity will increase by 0.333 meters per second.
It's worth noting that the direction of the force is also important in determining the direction of the acceleration. If the force is applied in the same direction as the motion of the object, it will speed up, but if the force is applied in the opposite direction, it will slow down.
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is the idea that reinforcement is not necessary for learning to occur, but that it does eventually affect demonstrated
behavior
Answers
Yes the given statement that reinforcement is not necessary for learning to but that it eventually affects demonstrative behaviour is correct.
What is the meaning of reinforcement in learning?Most of the animals including humans are taught by others a basic set of guidelines that they should follow in certain situations that might happen to produce optimal solutions for a problem or the given situation. Now this method of Pre guidelines by others is known as reinforcement in learning.
What is demonstrative behaviour?Demonstrative behaviour means following certain actions to grab the attention of others or showing of yourself.
Reinforcement in learning is very important for fast growth of any human being.
For example if members of a tribe were given a task of measuring the speed of light it will take them centuries before the figure out the proper method for measuring the speed of light it happens because never thought about the basic guidelines that we know about light and its properties.
If they were to do this on their own it will take them years and years before the learn to do so.
From childhood we are taught what to do when an earthquake happens now if it were ever to happen we will follow the same guidelines to help and create the optimal solution for the problem.
But if someone who has never thought about these guidelines were to come across an earthquake he might come to the same conclusion that he should hide under the bench and look for an open ground because to him it will see him as the optimal solution.
Therefore, Yes the given statement that reinforcement is not necessary for learning to but that it eventually affects demonstrative behaviour is correct.
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Consider a double-paned window consisting of two panes of glass, each with a thickness of 0.500 cm and an area of 0.760 m2 , separated by a layer of air with a thickness of 1.65 cm . The temperature on one side of the window is 0.00 ∘C; the temperature on the other side is 23.0 ∘C. In addition, note that the thermal conductivity of glass is roughly 36 times greater than that of air. Approximate the heat transfer through this window by ignoring the glass. That is, calculate the heat flow per second through 1.65 cm of air with a temperature difference of 23.0 ∘C . (The exact result for the complete window is 24.4 J/s .)
Answers
The approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.
To approximate the heat transfer through the air layer in the double-paned window, we can assume that the glass layers have a negligible impact on the heat flow. The heat transfer can be calculated using Fourier's Law of Heat Conduction, which states that the heat flow (Q) is proportional to the temperature difference (ΔT) and inversely proportional to the thickness (L) and thermal conductivity (k) of the material.
First, we need to calculate the effective thermal conductivity of the air layer due to its thickness and the thermal conductivity ratio between air and glass. Let's denote the thermal conductivity of air as k_air and the thermal conductivity of glass as k_glass. Since glass has a thermal conductivity roughly 36 times greater than air, we have k_glass = 36 * k_air.
Next, we calculate the effective thermal conductivity of the air layer as:
k_eff = (k_air * L_air) / (L_air + k_glass)
Substituting the given values, we have:
k_eff = (k_air * 0.0165 m) / (0.0165 m + 0.005 m) = 0.01309 * k_air
Now, we can calculate the heat flow per second through the air layer using the formula:
Q = (k_eff * A * ΔT) / L_air
Substituting the given values, we get:
Q = (0.01309 * k_air * 0.760 m^2 * 23.0 K) / 0.0165 m = 24.4 J/s
Therefore, the approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.
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Which object will require the greatest amount of force to change its motion?
A. A 148 kg object moving 131 m/s
B. A 153 kg object moving 127 m/s
C. A 160 kg object moving 126 m/s
O D. A 162 kg object moving 124 m/s
Answers
Answer: D 160kg object moving 126 m/s
Explanation:
An object having a mass of 162 kg and moving with a velocity of 124 m/sec will require the greatest amount of force to change its motion. The correct option is D.
What is force?Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body.
If the object has to stop, the final velocity must be zero. If the time is constant, the amount of force only depends on the mass and the velocity at which the body is moving.
The amount of force on the object depends on the momentum of the body.
The momentum of the body is;
P = mv
Object D will require the greatest amount of force to change its motion. Because the momentum of the body for option D is the greatest.
Hence, the correct option is D.
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1. A paper pinwheel is spinning in the wind. Which statement is correct about the forces responsible for the rotation?
The components of gravity and the force of wind that point through the pivot are responsible for the rotation.
Only the perpendicular component of wind is responsible for the rotation, because gravity points downward.
Only the perpendicular component of gravity is responsible for the rotation, because wind points toward the pivot. <- MY ANSWER
The perpendicular components of gravity and the force of wind are responsible for the rotation.
2. Which statement about kinetic and static friction is accurate?
Static friction is greater than kinetic friction, but they both act opposite the applied force.
Static friction is greater than kinetic friction, and they both act in conjunction with the applied force.
Kinetic friction is greater than static friction, but they both act opposite the applied force.
Kinetic friction is greater than static friction, and they both act in conjunction with the applied force.
3. A group of engineers is preparing a satellite to land by moving it 10% closer to Earth in each rotation. Which statement is correct about the rotational inertia of the satellite?
Rotational inertia decreases proportional to the decrease in the radius of rotation.
Rotational inertia increases proportional to the decrease in the radius of rotation. <- MY ANSWER
Rotational inertia first decreases and then increases as the satellite is ready to land.
Rotational inertia does not change because it is conserved.
4. In the experimental setup shown (see image attached), a car has one end of a string attached to it. The other end of the string has a hanger on which metal discs can be added or removed. The car moves along the table, and two photogate probes sense the motion of the car. The probes send information to a computer that displays the experimental results.
Which quantity is being held constant in this experiment?
mass
force
acceleration
velocity <- MY ANSWER
Answers
Answer:
1) Only the perpendicular component of wind is responsible for the rotation, because gravity points downward.
2) static friction is greater than kinetic friction and the applied force acts oppositely
3) Inertia decreases with decreasing radius of the orbit.
4) constant is the mass of the car
Explanation:
1) In order to know which statement is correct, let's analyze the movement of the mill.
The rotation of the blades due to a force perpendicular to each one, which creates a torque that results in its rotation.
The true force does not affect the movement because it is applied at the center of mass of the mill that coincides with its axis of rotation.
Of the statements, the correct one is:
The perpendicular to the wind is responsible for the movement
2) static friction is the result of microscopic bonds between two surfaces when there is no relative motion between them
kinetic friction is the result of the unions between the two surfaces when there is a relative movement between them.
From these statements it follows that friction is contrary to motion, static friction must be greater than kinetic friction.
Of the statements the correct one is:
static friction is greater than kinetic friction and the applied force acts oppositely
3) The inertia of a particle is
I = m R²
where m is the mass of the satellite and R is the distance from the center of the Earth, decreasing with each orbit
The correct answer is:
Inertia decreases with decreasing radius of the orbit.
4) From the figure it can be seen that the motorist subjected to a constant force, for which we can apply Newton's second law
F = m a
The force equals the applied weight.
The quantity that is held constant is the mass of the car
since the applied force and therefore the acceleration can be changed by changing the applied weight.
Answer:
1. The perpendicular components of gravity and the force of wind are responsible for the rotation.
2. Static friction is greater than kinetic friction, but they both act opposite the applied force.
3. Rotational inertia decreases proportional to the decrease in the radius of rotation.
4. mass
when would a swimmer have the most potential energy due to her position
Answers
Answer: A
Explanation:
A swimmer have the most potential energy due to her position.When he is sitting on the highest diving board at the pool.
What is potential energy?The potential energy is the due to the virtue of the position and the height. The unit for the potential energy is joule.
The potential energy is found as;
\(\rm PE = mgh\)
The potential energy is mainly depending upon the height of the object.
When the swimmer is at the highest position, the height is maximum. Therefore, the potential energy is also maximum.
Hence, a swimmer have the most potential energy due to her position.When he is sitting on the highest diving board at the pool.
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i understand how something about the pod could have affected its velocity change.
yes or not yet.
EXPLAIN your answer choice.
Answers
A stronger force can cause a greater change in an object's velocity. The correct option is yes
What caused the pod to change direction?The force exerted by the thrusters caused the pod to change direction. The thrusters on the ACM pod exerted the same strength force as thrusters on other pods on other missions. If the same strength force is exerted on two objects but the objects have different masses the object with less mass will have a greater change in velocity.
Therefore pod would have had to have a lighter mass meaning a smaller amount of force would have had to be exerted onto the pod making it move in the opposite direction.
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An 8.0 Kg mass is placed at = 3 where should a 10 Kg mass be placed along the − so that the center of mass will be located ay = 4.5?
Answers
Answer:
Therefore, the 10 kg mass should be placed at x = 5.7 m along the x-axis to achieve a center of mass located at y = 4.5 m.
Explanation:
To find the position along the x-axis where a 10 kg mass should be placed such that the center of mass is located at y = 4.5, we can use the formula for the center of mass:
x_cm = (m1 * x1 + m2 * x2) / (m1 + m2)
Here, m1 and x1 represent the mass and position of the 8 kg mass, respectively. m2 is the mass of the 10 kg mass, and we need to find x2, its position.
Given:
m1 = 8 kg
x1 = 3 m
x_cm = unknown (to be found)
m2 = 10 kg
y_cm = 4.5 m
Since the center of mass is at y = 4.5, we only need to consider the y-coordinate when calculating the center of mass position along the x-axis.
To solve for x2, we can rearrange the formula as follows:
x2 = (x_cm * (m1 + m2) - m1 * x1) / m2
Substituting the given values:
x2 = (x_cm * (8 kg + 10 kg) - 8 kg * 3 m) / 10 kg
Simplifying:
x2 = (x_cm * 18 kg - 24 kg*m) / 10 kg
Now, we can set the y-coordinate of the center of mass equal to 4.5 m and solve for x_cm:
4.5 m = (8 kg * 3 m + 10 kg * x2) / (8 kg + 10 kg)
Simplifying:
4.5 m = (24 kg + 10 kg * x2) / 18 kg
Multiplying both sides by 18 kg:
81 kg*m = 24 kg + 10 kg * x2
Subtracting 24 kg from both sides:
10 kg * x2 = 81 kg*m - 24 kg
Dividing both sides by 10 kg:
x2 = (81 kg*m - 24 kg) / 10 kg
Simplifying:
x2 = 8.1 m - 2.4 m
x2 = 5.7 m
(brainlest?) ples:(
Answer:
the 10 kg mass should be placed at x = -2.4 m to achieve a center of mass at y = 4.5 m.
Explanation:
To find the position along the x-axis where the 10 kg mass should be placed so that the center of mass is located at y = 4.5, we can use the principle of the center of mass.
The center of mass of a system is given by the equation:
x_cm = (m1x1 + m2x2) / (m1 + m2),
where x_cm is the x-coordinate of the center of mass, m1 and m2 are the masses, and x1 and x2 are the positions along the x-axis.
Given:
m1 = 8 kg,
x1 = 3 m,
m2 = 10 kg,
y_cm = 4.5 m.
To solve for x2, we need to find the x-coordinate of the center of mass (x_cm) by using the y-coordinate:
y_cm = (m1y1 + m2y2) / (m1 + m2),
where y1 and y2 are the positions along the y-axis.
Rearranging the equation and substituting the given values:
4.5 = (83 + 10y2) / (8 + 10).
Simplifying the equation:
4.5 = (24 + 10*y2) / 18.
Multiplying both sides by 18:
81 = 24 + 10*y2.
Rearranging the equation:
10*y2 = 81 - 24,
10*y2 = 57.
Dividing both sides by 10:
y2 = 5.7.
Therefore, the y-coordinate of the 10 kg mass should be 5.7 m.
To find the x-coordinate of the 10 kg mass, we can use the equation for the center of mass:
x_cm = (m1x1 + m2x2) / (m1 + m2).
Substituting the given values:
x_cm = (83 + 10x2) / (8 + 10).
Since the center of mass is at x_cm = 0 (the origin), we can solve for x2:
0 = (83 + 10x2) / (8 + 10).
Rearranging the equation:
83 + 10x2 = 0.
24 + 10*x2 = 0.
10*x2 = -24.
Dividing both sides by 10:
x2 = -2.4.
If the ball bounces straight up and returns to the floor 3.5 seconds after for striking it what was the balls greatest above the floor
Answers
Given,
The time, T = 3.5 s
The time the ball is required to go up is half of the time the ball bounces straight up and returns to the floor. It is the same for the ball going down.
\(\begin{gathered} t=\frac{T}{2} \\ t=\frac{3.5}{2}s \end{gathered}\)\(v=u+at\)Here, u is the initial velocity, v is the final velocity and a is the acceleration due to gravity calculated as g = 9.8 m/s^2.
Rearrange the equation,
\(u=v-at\)Put t = 3.5/2,
\(\begin{gathered} u=0-(-9.81m/s^2)\times(\frac{3.5}{2}s) \\ u=17.16\text{ }\frac{m}{s} \end{gathered}\)By the equation of the motion,
\(\begin{gathered} s=ut+\frac{1}{2}at^2 \\ s=17.16\times1.75+\frac{1}{2}\times(-9.81)\times(1.75)^2 \\ s=30.03-15.02 \\ s=15\text{ m} \end{gathered}\)Thus, the maximum height of the ball is 15 m.
The decibel rules of thumb can be combined. (a) If a sound has intensity xdB, how many dB does a sound 100 times more intense have? (b) If another sound has intensity ydB, how many dB does a sound 4 times less intense have? (c) Combine what you know about (a) and (b): If a sound has intensity zdB, how many dB does a sound 25 times more intense have?
Answers
Rannie travelled by train from New York to New Jersey She travels 350 kilometers to the north. But, then the track turns back to south 125 kilometers. Calculate Radha's total displacement using displacement formula?
Answers
Answer:
225 km north
Explanation:
Displacement = 350 km north + 125 km south
= 350 km north - 125 km north
= 225 km north
Current in Electric Circuits
Circuit
Current (A)
A
2.3
B
0.6
C
0.2
D
1.8
A
46. The table shows the current in circuits
that were each connected to a 6-V dry
cell. Calculate the resistance of each cir-
cuit. Graph the current versus the resis-
tance of each circuit. Describe the shape
of the line on your graph.
Answers
Answer:
To calculate the resistance of each circuit, we can use Ohm's law:
Resistance = Voltage / Current
For Circuit A: Resistance = 6 V / 2.3 A = 2.61 Ω
For Circuit B: Resistance = 6 V / 0.6 A = 10 Ω
For Circuit C: Resistance = 6 V / 0.2 A = 30 Ω
For Circuit D: Resistance = 6 V / 1.8 A = 3.33 Ω
To graph the current versus the resistance of each circuit, we can plot the resistance on the x-axis and the current on the y-axis. The resulting graph will show a decreasing linear relationship between current and resistance, with higher resistance resulting in lower current flow. This is in accordance with Ohm's law, which states that the current in a circuit is directly proportional to the voltage and inversely proportional to the resistance.
Explanation:
The current and voltage are directly proportional to each other and the resistance is inversely proportional to the current. The relation of three quantities is given by Ohm's law.
Ohm's law is defined as the applied voltage is directly proportional to the current flow through the circuit. V = IR where R is the resistance of the circuit and it obstructs the current flow. The unit of resistance is the ohm.
From the given,
Resistance, R₁ = V/I₁ = 6 /2.3 = 2.60Ω
Resistance, R₂ = V/I₂ = 6/0.6 = 10 Ω
Resistance, R₃ = V/I₃ = 6/0.2 = 30Ω
Resistance, R₄ = V/I₄ = 6/1.8 = 3.33Ω
In current versus resistance graph shows the linearly decreasing function, as the current increases resistance decreases and vice versa. Hence, the resistance and current are inversely proportional to each other.
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