these factors interact with each other, and the combined effect determines the overall amount of refraction that occurs.
The amount of refraction that occurs as light passes between two media depends on the following factors:
1. The angle of incidence: The angle at which the light ray approaches the interface between the two media determines the amount of refraction. According to Snell's law, the angle of refraction is related to the angle of incidence and the refractive indices of the two media.
2. The refractive indices of the media: Each medium has a characteristic refractive index, which is a measure of how much the speed of light is reduced when passing through that medium. The difference in refractive indices between the two media affects the amount of refraction. The greater the difference, the larger the angle of refraction.
3. The wavelength of the light: Different wavelengths of light experience different amounts of refraction. This phenomenon is called dispersion. For example, in a prism, different colors of light are refracted at different angles due to their different wavelengths.
4. The medium's optical properties: The optical properties of the media, such as their density and composition, can also affect the amount of refraction. For example, a denser medium will typically cause more refraction than a less dense medium.
5. The shape of the interface: The curvature of the interface between the two media can also impact the amount of refraction. For example, a lens with a curved surface will cause more bending of light than a flat surface.
To know more about refraction visit:
brainly.com/question/32684646
#SPJ11
The electromagnetic spectrum has waves of varying levels of energy. Which
wave has the least energy?
Answer:
Radio waves, I believe
Explanation:
Answer:
radio yes yup yup yup yup
Enumera las funciones del Estado
Answer:
Gobernancia. ...
Compromiso con el mercado. ...
Seguridad. ...
Infraestructura. ...
Imperio de la ley. ...
Capital humano. ...
Gestión Financiera Pública. ...
Compromiso ciudadano.
Explanation:
Light of wavelength 630 nm is incident on a long, narrow slit.
a)Determine the angular deflection of the first diffraction minimum if the slit width is 0.020 mm.
b)Determine the angular deflection of the first diffraction minimum if the slit width is 0.20 mm.
c)Determine the angular deflection of the first diffraction minimum if the slit width is 2.0 mm.
When light passes through a narrow slit, it diffracts and creates a pattern of bright and dark regions known as a diffraction pattern. The angular deflection of the first diffraction minimum, also called the first dark fringe, can be calculated using the following formula:
θ = λ / (2 * w)
where θ is the angular deflection, λ is the wavelength of light, and w is the width of the slit.
a) For a slit width of 0.020 mm and a wavelength of 630 nm (or 630 × 10^(-9) m), we can calculate the angular deflection as follows:
θ = (630 × 10^(-9) m) / (2 * 0.020 × 10^(-3) m) = 0.01575 radians
b) For a slit width of 0.20 mm, using the same wavelength, we have:
θ = (630 × 10^(-9) m) / (2 * 0.20 × 10^(-3) m) = 0.001575 radians
c) For a slit width of 2.0 mm:
θ = (630 × 10^(-9) m) / (2 * 2.0 × 10^(-3) m) = 0.0001575 radians
To convert the angular deflection to degrees, we can multiply the value by (180/π):
a) θ = 0.01575 * (180/π) ≈ 0.902 degrees
b) θ = 0.001575 * (180/π) ≈ 0.0902 degrees
c) θ = 0.0001575 * (180/π) ≈ 0.00902 degrees
Therefore, the angular deflection of the first diffraction minimum for the given slit widths is approximately 0.902 degrees, 0.0902 degrees, and 0.00902 degrees for parts (a), (b), and (c), respectively.
Learn more about Diffraction Pattern :
https://brainly.com/question/14076849
#SPJ11
What do organisms get when Glucose is broken down?
Answer:
Explanation:
chemical energy :) yay... we can live :D
Consider a small drainage ditch with cross sectional area A= 0.5 m2 and length L=15 m. The ditch is full of clean still water. At time t=0, a farmer spills mass M=60.2mg of a toxic salt into the ditch. The salt washes in uniformly across one end of the ditch. The diffusion constant within the ditch is D=0.002 m2/s. Assume that the salt is conservative and too dilute to change the density of the water within the ditch, and also that it results in biological impairment in concentrations above 0.1 mg/L=100mg/m3. An endangered salamander has been observed to lay eggs in the ditch, and a local environmental group asks you to evaluate the potential harm of the spill. What will be the concentration of salt in the ditch after it fully mixes and is diluted by the entire volume of the ditch? Please provide your answer in mg/L. After you have established the concentration of the toxic salt in the ditch, can you report back to the local environmental group ? Is the endangered salamander at risk, given that biological impairment occurs at concentrations >100mg/m3 ? a. It'll be alright.... b. The toxic salt will harm the salamander species
The toxic salt will harm the salamander species.
Hence, the correct option is B,
To determine the concentration of the toxic salt in the ditch after it fully mixes and is diluted by the entire volume of the ditch, we can use the formula for concentration:
Concentration (C) = Mass of Salt (M) / Volume of Water (V)
Given:
Mass of Salt (M) = 60.2 mg
Volume of Water (V) = Area (A) * Length (L) = 0.5 \(m^{2}\) * 15 m = 7.5 \(m^{3}\)
Using the formula:
Concentration (C) = 60.2 mg / 7.5 \(m^{3}\)
Concentration (C) = 8.03 mg/ \(m^{3}\)
To convert from mg/ \(m^{3}\) to mg/L, we multiply by 1000:
Concentration (C) ≈ 8.03 mg/ \(m^{3}\) * 1000 = 8030 mg/L
The concentration of the toxic salt in the ditch, after it fully mixes and is diluted by the entire volume of the ditch, is approximately 8030 mg/L.
Since the concentration of the toxic salt exceeds the threshold for biological impairment, which is 100 mg/ \(m^{3}\) or 100 mg/L, the endangered salamander is at risk.
The concentration of the salt in the ditch is significantly higher than the level at which biological impairment occurs, indicating potential harm to the salamander species.
Therefore,The toxic salt will harm the salamander species.
Hence, the correct option is B,
To know more about salt here
https://brainly.com/question/29318703
#SPJ4
Find the depth of water at which an air of radius 0.003m bubble may remain in equilibrium (surface tension=0.072Nm,gravity=9.8gs²)
Answer:
h = 0.047 m
Explanation:
It is given that,
Radius of an air bubble is 0.0003 m
The surface tension of water is \(7\times 10^{-2}\ N/m\)
We need to find the depth at which an air bubble of radius 0.0003 m will remain in equilibrium in water. Let it is given by h.
Pressure due to surface tension is given by :
\(P=\dfrac{2T}{R}\) .....(1)
T is surface tension
Also, pressure due to a height is given by :
\(P=\rho gh\)
So, equation (1) becomes :
\(\rho g h=\dfrac{2T}{R}\)
So,
\(h=\dfrac{2T}{\rho gR}\)
\(h=\dfrac{2\times 7\times 10^{-2}}{10^3\times 9.8\times 0.0003}\\\\h=0.047\ m\)
So, the depth is 0.047 m.
define from which of Earth's systems are mineral resources obtained?
Sources of mineral resources are most commonly magma, sediments, or hydrothermal fluids.
Examples of mineral resources are iron, diamond, gold, silver, copper, aluminum, granite, marble, clay, salt, rare earths or fossil fuels.
What are mineral resources?
A mineral resource is a concentration of natural solid inorganic or fossilized organic matter, including metals, coal and minerals, in sufficient quantity and quality to have reasonable prospects for economic exploitation. This definition has a broader scope than mineral reserves that are likely to be economically recovered based on consideration of technical, economic, and legal concerns.
Mineral resources means minerals, naturally occurring solid inorganic substances, or naturally occurring solid fossilized organic substances (including base metals, precious metals, coal and industrial minerals), in or on the earth's crust, such Means concentrated or occurring in form and quantity and in its grade or quality. There are reasonable prospects for economic development. The location, quantity, grade, geological features and continuity of Mineral Resources are known, estimated or interpreted on the basis of specific geological evidence and knowledge.
To know more about mineral resources, visit:
https://brainly.com/question/24514288
#SPJ1
For what reasons could a theory be changed or replaced? Check all that apply.
New technology is developed that provides more information about the theory.
New experimental methods are designed to test a theory.
A new, untested hypothesis is proposed.
New information is discovered that does not support the theory.
A single experiment produces results that differ from all previous experiments.
Answer:
New technology is developed that provides more information about the theory. (New technologies can lead to new results).
New experimental methods are designed to test a theory.
New information is discovered that does not support the theory.
Explanation:
A theory is an explanation of an aspect of the natural based on careful examination of facts. A theory by its definition can be repeatedly tested. A theory can be changed or replaced because of the following reasons:
a log splitter puts out 1 100W of power for every 1500 W put into it. the efficiency of the machine is what
Answer:400 is the answer 1500-1100 is 400
Explanation:
η=out/in x 100%
η=1100/1500 x 100%
η=73%
A 12 kg object has a velocity of 37.5 m/s. What is its momentum
Answer:
Solution:
Explanation:
Here, mass of body ( m)=12kg.
velocity (v)=37.5 m/s. momentum = mass× velocity = 12kg×37.5m/s =450kgm/s ans.
¿Qué es la carga eléctrica de un cuerpo?
Answer:
Las células del interior son negativas, mientras que en el exterior son positivas.
Explanation:
Que tenga un buen día :)
What was the initial speed of a car if its speed is 40 m/s after 5 seconds of accelerating at -4 m/s²?
A. 50 m/s
B. 60 m/s
C. 25 m/s
D. 20 m/s
Answer:
\(\huge\boxed{\sf V_i=60 \ m/s}\)
Explanation:
Given Data:Final speed = \(V_f\) = 40 m/s
Time = t = 5 s
Acceleration = a = -4 m/s²
Required:Initial velocity = \(V_i\) = ?
Formula:\(\displaystyle a = \frac{V_f-V_i}{t}\)
Solution:Put the givens in the above formula
\(\displaystyle -4=\frac{40 - V_i}{5} \\\\Multiply \ -5 \ to \ both \ sides\\\\-4 \times 5 = 40 - V_i\\\\-20 =40-V_i\\\\Subtract \ 40 \ to \ both \ sides\\\\-20-40=-V_i\\\\-60\ m/s=-V_i\\\\60 \ m/s = V_i\\\\V_i=60 \ m/s\\\\\rule[225]{225}{2}\)
it is important to have an appropriate level of lighting in each area of the operation. which action will provide adequate lighting?
Providing adequate lighting is crucial to ensuring a safe and productive work environment. The appropriate level of lighting in each area of operation can be achieved by using a combination of natural and artificial lighting sources.
The type and intensity of lighting required will depend on the task being performed and the area being lit. In general, bright, white light sources are preferred as they reduce eye strain and improve visibility. It is important to avoid glare and shadows that can impair visibility and cause accidents.
To ensure adequate lighting, lighting fixtures should be properly maintained and positioned to provide even illumination across the area. The use of dimmer switches and adjustable lighting can also provide flexibility in lighting levels, allowing for optimal lighting conditions for different tasks and activities. Additionally, using energy-efficient lighting sources, such as LED bulbs, can help reduce energy costs and promote sustainability. Overall, providing adequate lighting is essential for ensuring a safe and productive work environment.
Learn more about lighting here:
brainly.com/question/7520158
#SPJ11
Two people are pushing a car of mass 2000 kg. If they each push with a force of 320 N at an angle of 15° to each side of the car, calculate the acceleration of the car, assuming no resistance.
The car's acceleration while assuming no resistance. 4000 N of net force are required.
What exactly is an acceleration?Speed and direction changes in velocity with time. When a point or object moves faster or slower along a straight line, it is said to be accelerated. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting.
What exactly are velocity and acceleration?The pace at which displacement changes is known as velocity. The rate at which velocity changes is known as acceleration. Because it includes both magnitude and direction, velocity is a vector quantity. As acceleration is merely the rate at which velocity changes, acceleration is likewise a vector quantity.
To know more about Acceleration visit:
https://brainly.com/question/30660316
#SPJ1
how does thunder and lighting occurs
Answer:
Lightning is a discharge of electricity. A single stroke of lightning can heat the air around it to 30,000°C (54,000°F)! This extreme heating causes the air to expand explosively fast. The expansion creates a shock wave that turns into a booming sound wave, known as thunder.
Explanation:
ILL MARK BRAINLEST
Question 13: A food web of the Yellowstone National Park ecosystem is
provided below. If a sudden outbreak of disease severely reduced the
number of wolves in Yellowstone National Park very rapidly, what are two
changes that might happen to the local food web? Fully explain using
claim, evidence, and reasoning.
Answer:
they all will die and so will we
Explanation:
Answer:
3 animals will thrive better
Explanation:
If the number of wolves is reduced, 3 animal species usually eaten by the wolves will have a better chance of survival.
A spring has a force of 2.0N and an extension of 0.30m. What will the extension be if the force applied is 6 N.
Will mark as brainliest
Answer:
0.9 m
Explanation:
Hooke’s Law
\(\large\boxed{F = ke}\)
where:
F is the force in newtons (N).k is the 'spring constant' in newtons per metre (N/m).e is the extension in metres (m).Given values:
F = 2.0 Ne = 0.30 mSubstitute the given values into the formula to find k:
\(\implies 2.0=0.30k\)
\(\implies k=\dfrac{2.0}{0.30}\)
\(\implies k=\dfrac{20}{3}\; \sf N/m\)
To find the extension if the force applied is 6 N, substitute the found value of k and the given value of F into the formula and solve for e:
\(\implies 6=\dfrac{20}{3}e\)
\(\implies 18=20e\)
\(\implies e=\dfrac{18}{20}\)
\(\implies e=0.9\; \sf m\)
(a) If an inductor carrying a 1.80 A current stores an energy of 0.250 mJ, what is its inductance?
_____mH
(b) How much energy does the same inductor store if it carries a 3.3 A current?
_____mJ
The formula for the energy stored in an inductor is E = (1/2) × L × I^2. Given that the inductor carries a current of 1.80 A and stores an energy of 0.250 mJ,
we can calculate its inductance as follows:
E = (1/2) × L × I^2
0.250 × 10^-3 J = (1/2) × L × (1.80 A)^2
L = (0.250 × 10^-3 J) / [(1/2) × (1.80 A)^2] = 26.0 μH
Therefore, the inductor's inductance is 26.0 μH.
(b) Using the same formula as in part (a), we can calculate the energy stored in the inductor when it carries a current of 3.3 A:
E = (1/2) × L × I^2
E = (1/2) × (26.0 μH) × (3.3 A)^2
E = 0.0587 mJ
Thus, the inductor stores 0.0587 mJ of energy when it carries a current of 3.3 A.
Learn more about inductor
brainly.com/question/29632226
#SPJ4
A circular loop of wire is placed in a uniform magnetic field directed out of the page. Suddenly the magnetic field disappear . What is the direction of the induced current in the loop?
Hi there!
Counterclockwise.
If a loop of wire is placed in a magnetic field directed out of the page that disappears, that means that the magnetic flux out of the page through the loop has decreased.
The loop will try to oppose this change in the magnetic flux, so an induced current that produces an additional magnetic field out of the page will occur to make up for the decrease in the magnetic flux.
Using the magnetic right-hand rule, the current in the loop would need to be traveling in the counterclockwise direction in order for the produced magnetic field to be directed out of the page inside the loop.
If the coefficient of kinetic frictionbetween tires and dry pavement is 0.80, what is the shortestdistance in which you can stop an automobile by locking the brakeswhen traveling at 29.1{\rm m/s}(about 65{\rm mi/h})?
On wet pavement, the coefficient of kineticfriction may be only 0.25. How fast should you drive on wetpavement in order to be able to stop in the same distance as inpart A? (Note: Locking the brakes is not thesafest way to stop.)
The shortest stopping distance on dry pavement is approximately 87.6 meters, and to stop in the same distance on wet pavement, the speed should be approximately 20.2 m/s.
To determine the shortest stopping distance of an automobile, we can use the equations of motion and the concept of kinetic friction.
Given:
Coefficient of kinetic friction on dry pavement, μ_dry = 0.80
Coefficient of kinetic friction on wet pavement, μ_wet = 0.25
Initial velocity, v_initial = 29.1 m/s
a) Stopping distance on dry pavement:
To find the stopping distance on dry pavement, we need to determine the deceleration (negative acceleration) experienced by the car due to friction.
Using the equation of motion: v_final^2 = v_initial^2 + 2as, where v_final is the final velocity (zero in this case), a is the deceleration, and s is the stopping distance.
Rearranging the equation: s = v_initial^2 / (2a)
The deceleration can be calculated using the formula: a = μ * g, where μ is the coefficient of kinetic friction and g is the acceleration due to gravity (approximately 9.8 m/s^2).
Substituting the values, we have: a = 0.80 * 9.8 m/s^2
Now, we can calculate the stopping distance:
s_dry = v_initial^2 / (2 * a)
Substituting the given values, we get: s_dry = (29.1 m/s)^2 / (2 * 0.80 * 9.8 m/s^2)
Calculating this expression gives us a stopping distance on dry pavement of approximately 87.6 meters.
b) Stopping distance on wet pavement:
To determine the required speed on wet pavement, we want to find the velocity that will result in the same stopping distance as on dry pavement.
Using the same formula as before: s_wet = v_wet^2 / (2 * a_wet)
We can set the stopping distances on dry and wet pavement equal to each other: s_dry = s_wet
Substituting the values, we have: (29.1 m/s)^2 / (2 * 0.80 * 9.8 m/s^2) = v_wet^2 / (2 * 0.25 * 9.8 m/s^2)
Solving for v_wet, we find: v_wet ≈ 20.2 m/s
Therefore, to stop in the same distance on wet pavement as on dry pavement, the speed should be approximately 20.2 m/s.
To know more about distance click here:
https://brainly.com/question/13034462
#SPJ11
The shortest stopping distance on dry pavement is approximately 87.6 meters. To stop in the same distance on wet pavement, the speed should be approximately 20.2 m/s.
To calculate the stopping distance on dry pavement, we use the equations of motion and the concept of kinetic friction. The deceleration (negative acceleration) experienced by the car due to friction can be determined by multiplying the coefficient of kinetic friction on dry pavement, μ_dry, by the acceleration due to gravity, g. Using the equation of motion, we find the stopping distance.
To find the required speed on wet pavement to achieve the same stopping distance, we set the stopping distances on dry and wet pavement equal to each other. By rearranging the equation and substituting the coefficients of kinetic friction and acceleration due to gravity, we can solve for the speed on wet pavement.
Upon evaluation, we find that the shortest stopping distance on dry pavement is approximately 87.6 meters. In order to stop in the same distance on wet pavement, the speed should be approximately 20.2 m/s.
To know more about distance click here:
brainly.com/question/13034462
#SPJ11
the 8.00 a current through a 4.00 mh inductor is switched off in 8.33 ms. what is the emf induced (in v) opposing this?
The induced emf opposing the current is approximately -3.84 V for the 8.00 A current through a 4.00 mH inductor is switched off in 8.33 ms.
To find the induced emf in the inductor, we can use the formula:
emf = -L * (ΔI/Δt)
where:
emf = induced electromotive force (in volts)
L = inductance of the inductor (in Henrys)
ΔI = change in current (in amperes)
Δt = time taken for the current to change (in seconds)
Given the information in your question:
L = 4.00 mH = 4.00 * \(10^{-3}\) H (converting millihenry to henry)
ΔI = 8.00 A (since the current is switched off, the change is equal to the initial current)
Δt = 8.33 ms = 8.33 * \(10^{-3}\) s (converting milliseconds to seconds)
Now, we can plug these values into the formula:
emf = - (4.00 * \(10^{-3}\) H) * (8.00 A) / (8.33 * \(10^{-3}\) s)
emf = - (32 * 10^-3) / (8.33 * \(10^{-3}\))
emf ≈ -3.84 V
The induced emf opposing the current is approximately -3.84 V. The negative sign indicates that the induced emf opposes the change in current, as expected.
To learn more about electromotive force, refer:-
https://brainly.com/question/13753346
#SPJ11
The EMF induced in the inductor opposing the change in current is approximately 3.84 V.
To find the EMF induced in the inductor, we'll need to use the formula for the induced EMF in an inductor, which is:
EMF = -L × (ΔI / Δt)
Here, EMF is the induced electromotive force, L is the inductance, ΔI is the change in current, and Δt is the time interval during which the current changes.
Given the information in your question, we have:
\(L = 4.00 mH = 0.004 H\) (converting millihenries to henries)
\(ΔI = 8.00 A\) (the current goes from 8 A to 0 A)
\(Δt = 8.33 ms = 0.00833 s\) (converting milliseconds to seconds)
Now, plug the values into the formula:
EMF =\(-0.004 H × (8.00 A / 0.00833 s)\)
EMF = \(-3.8408 V\)
Since we're looking for the magnitude of the induced EMF, we can ignore the negative sign:
EMF = 3.8408 V
to know more about EMF refer here:
https://brainly.com/question/16626131#
#SPJ11
The steering wheel of a car has a radius of 36 cm, and part of rest with an acceleration of 1.8m / s. Determine
a) The angular speed after 10s
b) The number of turns the wheel gave in 10s
Answer:
a) 50 rad/s
b) 39.8 rev
Explanation:
Given:
r = 0.36 m
v₀ = 0 m/s
a = 1.8 m/s
t = 10 s
a) Find: ω
v = at + v₀
v = (1.8 m/s) (10 s) + (0 m/s)
v = 18 m/s
ω = (18 m/s) / (0.36 m)
ω = 50 rad/s
b) Find: Δθ
Δx = v₀ t + ½ at²
Δx = (0 m/s) (10 s) + ½ (1.8 m/s) (10 s)²
Δx = 90 m
Δθ = (90 m) / (2π × 0.36 m)
Δθ = 39.8 rev
A machine that operates a ride at the fair requires 2500 J to lift a 294 N child 5.0 m. What is the efficiency of this machine?
Answer:
η = 58.8%
Explanation:
Work is defined as the force applied by the distance traveled by the body.
\(W =F*d\)
where:
W = work [J] (units of joules)
F = force = 294 [N]
d = distance = 5 [m]
\(W = 294*5\\W = 1470 [J]\\\)
Efficiency is defined as the energy required to perform an activity in relation to the energy actually added to perform some activity. This can be better understood by means of the following equation.
\(efficiency = W_{done}/W_{required}\\efficiency = 1470/2500\\efficiency = 0.588 = 58.8%\)
A single-turn current loop, carrying a current of 3.66 A, is in the shape of a right triangle with sides 50.0,101. and 113 cm. The loop is in a uniform magnetic field of magnitude 65.9mT whose direction is paraliel to the current in the 113 cm side of the loop. What is the magnitude of the magnetic force on (a) the 113 cm side, (b) the 50.0 cm side. and (c) the 101 cm side? (d) What is the magnitude of the net force on the loop?
a. The force on the 113 cm side is 0N. b. The force on the 50.0 cm side is 0.120N. c. The 101 cm side force is 0.234N . d. The magnitude of the net force on the loop is 0.354 N
The magnitude of the magnetic force on each side of the loop can be determined using the formula F = I * L * B * sin(θ), where I is the current, L is the length of the side, B is the magnetic field magnitude, and θ is the angle between the magnetic field and the side of the loop. The net force on the loop can be obtained by summing the individual forces acting on each side.
(a) To calculate the magnitude of the magnetic force on the 113 cm side, we use the formula F = I * L * B * sin(θ). The current (I) is 3.66 A, the length (L) is 113 cm, the magnetic field magnitude (B) is 65.9 mT (converted to Tesla by dividing by 1000), and the angle (θ) is 0 degrees since the magnetic field is parallel to this side. Therefore, the force on the 113 cm side is F = 3.66 * 1.13 * 0.0659 * sin(0°) = 0 N.
(b) Similarly, for the 50.0 cm side, the force can be calculated using the same formula, but the length is 50.0 cm and the angle θ is 90 degrees since the magnetic field is perpendicular to this side. Thus, the force on the 50.0 cm side is F = 3.66 * 0.5 * 0.0659 * sin(90°) = 0.120 N.
(c) For the 101 cm side, the angle θ is also 90 degrees, so the force is F = 3.66 * 1.01 * 0.0659 * sin(90°) = 0.234 N.
(d) To find the net force on the loop, we sum the individual forces: 0 + 0.120 + 0.234 = 0.354 N.
Therefore, the magnitude of the net force on the loop is 0.354 N.
Learn more about magnetic force here
https://brainly.com/question/31700111
#SPJ11
Name the two poles of a magnet
What is meant by magnetism?
in which phase is the solution defined?
A solution is defined as the homogeneous mixture which has the same composition throughout. A solution can exist in any phase.
What is binary solution?A solution which is made up of two constituents or components is defined as the binary solution. The term solute is commonly used to refer to the constituent that dissolves and the term solvent is one in which the dissolution takes place.
There can be three physical states in which the solutions may exist, there can be three types of solutions: solid solutions, liquid solutions and gaseous solutions. There are solid solutions, liquid solutions and gaseous solutions.
Thus the solution can exist in any phase.
To know more about solution, visit;
https://brainly.com/question/11985826
#SPJ1
What force do you need to accelerate a car at 5m/s2 that has a mass of 3,000kg?
The force needed to accelerate a car at 5 m / s² that has a mass of 3,000 kg is 15 KN
F = m a
F = Force
m = Mass
a = Acceleration
m = 3000 kg
a = 5 m / s²
F = 3000 * 5
F = 15000 N
F = 15 KN
According to Newton's second law of motion, the force is equal to the rate of change of momentum of the object.
Therefore, the acceleration of the car is 15 KN
To know more about Newton's second law of motion
brainly.com/question/13447525
#SPJ1
One meter of a particular type of wire has a resistance of 30 (ohms) what length of this wire will have a resistance of 6 (ohms)
To determine the length of wire that will have a resistance of 6 Ω if a meter of wire has a resistance of 30 Ω, we can use the formula for resistance of a wire: Resistance = resistivity x length/area of cross-sectionThe resistivity is a constant for the material of the wire.
it remains constant, then we can write: Resistance of 1 meter of wire = resistivity x 1 / area of cross-sectionTherefore: resistivity = Resistance of 1 meter of wire / (1 / area of cross-section)The area of cross-section is not given in the question, so we can assume it remains constant. This means we can write: resistivity = Resistance of 1 meter of wire / 1Now, we can use this value of resistivity to find the length of wire that will have a resistance of 6 Ω. Resistance = resistivity x length/area of cross-section6 Ω = resistivity x length/area of cross-sectionresistivity = Resistance of 1 meter of wire / 1 = 30 Ω / 1 = 30 ΩmNow:6 Ω = (30 Ωm) x length/area of the cross-section area of cross-section = (30 Ωm) x length / 6 Ωarea of cross-section = 5 x lengths area of cross-section is proportional to the square of the diameter of the wire. If we assume the diameter remains constant, then we can write: area of cross-section = k x diameter²where k is a constant. Therefore:5 x length = k x diameter²Now, we can add the given information on the concept of resistivity and how it varies with temperature and the properties of the wire material. We can also discuss how the diameter of the wire affects its resistance and how different types of wire have different resistivities. Additionally, we can mention the practical applications of calculating resistance and length of wire in electrical circuits.
Learn more about length of wire here:
https://brainly.com/question/6708730
#SPJ11
Radioactive tritium (3H) labeled guanine has been used to measure the rate of biochemical processes that involve its binding or incorporation.
Given that water is the solvent for this type of experiment, what is the best site for tritium labeling?
Radioactive tritium (3H) labeled guanine is indeed used to measure the rate of biochemical processes that involve its binding or incorporation.
In this context, the best site for tritium labeling would be at the C8 position of the guanine molecule. This is because the C8 position is less likely to undergo exchange with the solvent (water) and maintains the integrity of the labeled guanine throughout the experiment. The best site for tritium labeling in this type of experiment would be the 8th position of the guanine molecule. This is because the 8th position is involved in biochemical processes such as base-pairing and is also solvent-accessible, allowing for efficient incorporation of the radioactive tritium.
Learn more about Radioactive here:
brainly.com/question/14454195
#SPJ11
A football thrown by a professional quarterback goes farther than one thrown by a 10-year old. What Newton Law is this?
Answer:
2nd law of motion
Explanation:
Answer:
Newton's 2nd Law of Motion
Explanation:
The amount of force needed to make an object change its acceleration depends on the mass of the object. In other words, the amount of force thrown by a professional quarter-back has more acceleration from his mass.